The graph of f(x) = x3 − 7x − 6 is shown.



Based on the graph, what are all of the solutions to f(x) = x3 − 7x − 6?

x = −6
x = −2, −1
x = −2, −1, 3
x = −6, −2, −1, 3

Answers

Answer 1

In accordance with the graph of the cubic function, the roots are - 2, - 1, 3.

What are the roots of a cubic equation according to a graph?

In this question we have a graph of a cubic equation, the roots are the points of the curve that pass through the x-axis. Cubic equations have at least a real root and at most three. In accordance with the graph of the cubic equation, the roots are - 2, - 1, 3.

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The Graph Of F(x) = X3 7x 6 Is Shown.Based On The Graph, What Are All Of The Solutions To F(x) = X3 7x

Related Questions

Ned and Sam are playing a game. Ned has -3 points. Sam has -8 points. How many more points does Ned have than Sam? Please provide an equation and an answer.

Answers

Answer:

5 points

Step-by-step explanation:

Subtracting their scores, we get (-3)-(-8)=5

Solve the system of equations.
y = 2x+ 3
y=x^2+3x+3

Answers

Answer:

(0,3)

(-1,1)

Step-by-step explanation:

Hello!

Since both equations are equal to y, we can set the right-hand side of the equations equal to each other.

[tex]y = 2x + 3\\y = x^2 + 3x + 3[/tex][tex]y = y[/tex][tex]2x + 3 = x^2 + 3x + 3[/tex]

Solve for x[tex]2x + 3 = x^2 + 3x + 3[/tex][tex]0 = x^2 + x[/tex][tex]0 = x(x + 1)[/tex][tex]x = 0, x =-1[/tex]

X can either be 0 or -1. Remember, a solution to a system is not complete without a y-value. Plug in 0 and -1 for x in the first equation, and find the corresponding y-values.

[tex]y = 2(0) + 3\\y = 3[/tex]

And

[tex]y = 2(-1) + 3\\y = -2 + 3\\y = 1[/tex]

So the solutions to the system are (0,3) and (-1,1)

How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the population standard deviation is 40 . Round your answer to next whole number.

Answers

Using the z-distribution, it is found that a sample of 171 should be selected.

What is a z-distribution confidence interval?

The confidence interval is:

[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]

The margin of error is:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which:

[tex]\overline{x}[/tex] is the sample mean.z is the critical value.n is the sample size.[tex]\sigma[/tex] is the standard deviation for the population.

For this problem, the parameters are:

[tex]z = 1.96, \sigma = 40, M = 6[/tex]

Hence we solve for n to find the needed sample size.

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]6 = 1.96\frac{40}{\sqrt{n}}[/tex]

[tex]6\sqrt{n} = 40 \times 1.96[/tex]

[tex]\sqrt{n} = \frac{40 \times 1.96}{6}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2[/tex]

n = 170.7.

Rounding up, a sample of 171 should be selected.

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Please tell me fast I am on a time crunch

Answers

x< -6
Solve for the inequality x


Remove all perfect squares from inside the square roo
√28

Answers

Answer:

√2² cannot be answer yesah

SOLVE AND EXPLAIN HOW TO SOLVE

Answers

Answer:

4.13

Step-by-step explanation:

Using sine ratio where it states that sine of a measurement is equal to ratio of opposite of measurement to hypotenuse (slant side/side with slope)

From the question, our opposite is x, hypotenuse is given as 15 units and the measurement is 16°. Apply the formula:

[tex]\displaystyle{\sin 16^{\circ} = \dfrac{x}{15}}[/tex]

Move 15 to multiply sin(16°):

[tex]\displaystyle{15\sin 16^{\circ} = x}[/tex]

Go ahead and input the value in a calculator since it's not a special triangle - a measurement that can be found using hand method - after you find the value, round it to 2 decimal places:

[tex]\displaystyle{x = 4.13456033...}[/tex]

Therefore, after rounding to 2 decimal places, the answer is:

[tex]\displaystyle{x=4.13}[/tex]

Therefore, the value of x is 4.13 units.

Which of the following functions are discontinuous?

Answers

Answer:

D.  I, II, and III

Step-by-step explanation:

A discontinuous function is a function which is not continuous.  

If f(x) is not continuous at x = a, then f(x) is said to be discontinuous at this point.

To prove whether a function is discontinuous, find where it is undefined.

A rational function is undefined when the denominator is equal to zero.

Therefore, to find the values that make a rational function undefined, set the denominator to zero and solve.

Function I

Denominator:  x - 2

Set to zero:  x - 2 = 0

Solve:  x = 2

Therefore, this function is undefined when x = 2 and so the function is discontinuous.

Function II

Denominator:  4x²

Set to zero:  4x² = 0

Solve:  x = 0

Therefore, this function is undefined when x = 0 and so the function is discontinuous.

Function III

Denominator:  x² + 3x + 2

Set to zero:  x² + 3x + 2 = 0

Solve:  

⇒ x² + 3x + 2 = 0

⇒ x² + x + 2x + 2 = 0

⇒ x(x + 1) + 2(x + 1) = 0

⇒ (x + 2)(x + 1) = 0

⇒ x = -2, x = -1

Therefore, this function is undefined when x = -2 and x = -1, and so the function is discontinuous.

Therefore, all three given functions are discontinuous.

I need help with this geometry question asap!

Answers

Answer:

  (a)  Theorem 9

Step-by-step explanation:

Any of the given theorems can be used to prove lines are parallel. We need to find the one that is applicable to the given geometry.

Analysis

The marked angles are between the parallel lines (interior) and on opposite sides of the transversal (alternate).

Theorem 9 applies to congruent alternate interior angles.

at the movie theatre, child admission is $6.10 and adult admission is $9.70. On Monday , 146 tickets were sold for a total sales of $1074.20.HOw many adult tickets were sold that day ?

Answers

Answer:

51

Step-by-step explanation:

Let c be the number of child tickets sold.

Let a be the number of adult tickets sold.

From the information given from the question, we can deduce:

6.10c + 9.70a = 1074.20 - Equation 1

c + a = 146 - Equation 2

From here, we can use the substitution method in solving simultaneous equations to find a and c. We will use Equation 2 as the base.

c = 146 - a - Equation 2A

We will then substitute equation 2A into Equation 1 to find a.

6.10(146-a) + 9.70a = 1074.20

890.6 - 6.10a + 9.70a = 1074.20

890.6 + 3.6a = 1074.20

3.6a = 1074.20 - 890.6

3.6a = 183.6

a = [tex]\frac{183.6}{3.6}[/tex]

a = 51

Therefore we know that 51  adult tickets were sold that day.

After that you can substitute a into equation 2 to find c.

Seven more than 4 times a number is 43 solve in algebraic equation?

Answers

Answer:

x = 9

Step-by-step explanation:

4x + 7 = 43

4x = 36

x = 9

A random variable X has a gamma density function with parameters α= 8 and β = 2.
Without making any assumptions, derive the moment generating function of X and use to
determine the mean and variance of X.

Answers

I know you said "without making any assumptions," but this one is pretty important. Assuming you mean [tex]\alpha,\beta[/tex] are shape/rate parameters (as opposed to shape/scale), the PDF of [tex]X[/tex] is

[tex]f_X(x) = \dfrac{\beta^\alpha}{\Gamma(\alpha)} x^{\alpha - 1} e^{-\beta x} = \dfrac{2^8}{\Gamma(8)} x^7 e^{-2x}[/tex]

if [tex]x>0[/tex], and 0 otherwise.

The MGF of [tex]X[/tex] is given by

[tex]\displaystyle M_X(t) = \Bbb E\left[e^{tX}\right] = \int_{-\infty}^\infty e^{tx} f_X(x) \, dx = \frac{2^8}{\Gamma(8)} \int_0^\infty x^7 e^{(t-2) x} \, dx[/tex]

Note that the integral converges only when [tex]t<2[/tex].

Define

[tex]I_n = \displaystyle \int_0^\infty x^n e^{(t-2)x} \, dx[/tex]

Integrate by parts, with

[tex]u = x^n \implies du = nx^{n-1} \, dx[/tex]

[tex]dv = e^{(t-2)x} \, dx \implies v = \dfrac1{t-2} e^{(t-2)x}[/tex]

so that

[tex]\displaystyle I_n = uv\bigg|_{x=0}^{x\to\infty} - \int_0^\infty v\,du = -\frac n{t-2} \int_0^\infty x^{n-1} e^{(t-2)x} \, dx = -\frac n{t-2} I_{n-1}[/tex]

Note that

[tex]I_0 = \displaystyle \int_0^\infty e^{(t-2)}x \, dx = \frac1{t-2} e^{(t-2)x} \bigg|_{x=0}^{x\to\infty} = -\frac1{t-2}[/tex]

By substitution, we have

[tex]I_n = -\dfrac n{t-2} I_{n-1} = (-1)^2 \dfrac{n(n-1)}{(t-2)^2} I_{n-2} = (-1)^3 \dfrac{n(n-1)(n-2)}{(t-2)^3} I_{n-3}[/tex]

and so on, down to

[tex]I_n = (-1)^n \dfrac{n!}{(t-2)^n} I_0 = (-1)^{n+1} \dfrac{n!}{(t-2)^{n+1}}[/tex]

The integral of interest then evaluates to

[tex]\displaystyle I_7 = \int_0^\infty x^7 e^{(t-2) x} \, dx = (-1)^8 \frac{7!}{(t-2)^8} = \dfrac{\Gamma(8)}{(t-2)^8}[/tex]

so the MGF is

[tex]\displaystyle M_X(t) = \frac{2^8}{\Gamma(8)} I_7 = \dfrac{2^8}{(t-2)^8} = \left(\dfrac2{t-2}\right)^8 = \boxed{\dfrac1{\left(1-\frac t2\right)^8}}[/tex]

The first moment/expectation is given by the first derivative of [tex]M_X(t)[/tex] at [tex]t=0[/tex].

[tex]\Bbb E[X] = M_x'(0) = \dfrac{8\times\frac12}{\left(1-\frac t2\right)^9}\bigg|_{t=0} = \boxed{4}[/tex]

Variance is defined by

[tex]\Bbb V[X] = \Bbb E\left[(X - \Bbb E[X])^2\right] = \Bbb E[X^2] - \Bbb E[X]^2[/tex]

The second moment is given by the second derivative of the MGF at [tex]t=0[/tex].

[tex]\Bbb E[X^2] = M_x''(0) = \dfrac{8\times9\times\frac1{2^2}}{\left(1-\frac t2\right)^{10}} = 18[/tex]

Then the variance is

[tex]\Bbb V[X] = 18 - 4^2 = \boxed{2}[/tex]

Note that the power series expansion of the MGF is rather easy to find. Its Maclaurin series is

[tex]M_X(t) = \displaystyle \sum_{k=0}^\infty \dfrac{M_X^{(k)}(0)}{k!} t^k[/tex]

where [tex]M_X^{(k)}(0)[/tex] is the [tex]k[/tex]-derivative of the MGF evaluated at [tex]t=0[/tex]. This is also the [tex]k[/tex]-th moment of [tex]X[/tex].

Recall that for [tex]|t|<1[/tex],

[tex]\displaystyle \frac1{1-t} = \sum_{k=0}^\infty t^k[/tex]

By differentiating both sides 7 times, we get

[tex]\displaystyle \frac{7!}{(1-t)^8} = \sum_{k=0}^\infty (k+1)(k+2)\cdots(k+7) t^k \implies \displaystyle \frac1{\left(1-\frac t2\right)^8} = \sum_{k=0}^\infty \frac{(k+7)!}{k!\,7!\,2^k} t^k[/tex]

Then the [tex]k[/tex]-th moment of [tex]X[/tex] is

[tex]M_X^{(k)}(0) = \dfrac{(k+7)!}{7!\,2^k}[/tex]

and we obtain the same results as before,

[tex]\Bbb E[X] = \dfrac{(k+7)!}{7!\,2^k}\bigg|_{k=1} = 4[/tex]

[tex]\Bbb E[X^2] = \dfrac{(k+7)!}{7!\,2^k}\bigg|_{k=2} = 18[/tex]

and the same variance follows.

BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

B.) (1, -5)

Given, equation:

[tex]\sf \dfrac{(x-1)^2}{25} -\dfrac{(y+5)^2}{49} =1[/tex]

Comparing it with standard formula of hyperbola:

[tex]\sf \dfrac{(x-h)^2}{a^2} -\dfrac{(y-k)^2}{b^2} =1[/tex]

where (h, k) is center

The given equation in standard form:

[tex]\sf \dfrac{(x-1)^2}{5^2} -\dfrac{(y-(-5))^2}{7^2} =1[/tex]

Determined:

(h, k) = (1, -5)

a = 5, b = 7

So, here (1, -5) is the center of the given hyperbola.

You have a job earning $12.50 per hour, and you receive a raise so that you earn $13.25 per hour. What is the percent change in your salary?

Answers

Answer: 6 %

Step-by-step explanation: 6 % of 12.5 = 0.75. 12.5 plus 0.75 = 13.25

Describe the function over each part of its domain. State whether it is constant, increasing, or decreasing, and state the slope over each part.

Answers

The function is illustrated below based on the information.

How to describe the function?

When x <= 8000

The cost remains constant at 0.35 when x increases from 0 to 8000. The slope of the cost function over this part is 0

When 8000 < x <= 20000

The cost remains constant at 0.75 when x increases from 8000 to 20000 and the slope of the cost function over this part is 0.

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Carol and Janis decide to sew fancy masks to sell on Etsy. Carol can cut, pin, sew and pack a mask in 30 minutes. Working together they can complete a package in 16 minutes. How long does it take Janis to complete a package alone?

Answers

it would take Janis 14 minutes to complete a package alone

How to determine the value

From the information given,

Let's say that

Carol working time = x = 30 minutes

Janis working time = y

x + y = 16 minutes

Let's make 'y' the subject

30 - 16 = y

y= 14 minutes

Thus, it would take Janis 14 minutes to complete a package alone

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Identify the correct trigonometry formula to solve for x

Answers

The correct trigonometry formula to solve for x in the right angled triangle is sin(62°) = 18 / x

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

Hence:

sin(62°) = 18 / x

The correct trigonometry formula to solve for x in the right angled triangle is sin(62°) = 18 / x

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I have no clue what this question is asking nor how to answer it

Which of the following numbers are solutions of the sentence x-3< 2?

| -3
|| 0
||| 2
IV 5


II only

III only

I and III only

I, II, and III only

Or

I, II, III, and IV

Answers

Answer:

IV 5

Step-by-step explanation:

you have to solve for x:

x-3<2

x-3+3<2+3

x=5

could you put the brainlyest Icon for me? I have 1500 points, but no brainlyest, so I can't move up the ranks.

What do l do??? Need help

Answers

Answer:

you have to put the formula of perimeter

Answer:

12a. L+8m + 14m

12b. 10m+8m +14m

12c. 66

12d.420m

12e.252m

quick questions

volume= 288cm cubed

You have a $10,000, you must choose between Gamble A and Gamble B. Gamble A will cost $5,000. If you win, you will get $15,000, but if you lose, you will get nothing. On the other hand, Gamble B will cost $10,000 that will give $30,000 if you win, otherwise get nothing if lost. You are risk averse, and your preference for wealth (W) is specified by the relationship U(W)= √W. Probability of wining is 0.4 and losing is 0.7. Which gamble will you choose and why?

Answers

The answer of this is b 0.8 + 9 equal 100 because if that’s not the answer then it’s 10000- 0.7

Write an equivalent expression in simplest form for each given expression. Then, choose the answer that explains why the expressions are equivalent.
(A) 2y + 4(y + 1) = y +

First use the Property to simplify the expression in parentheses, then
combine like terms.

(B) 9y + 6 + 2(5 + y) = y +

After applying the Distributive Property, use the Properties to
combine like terms.

Answers

The equivalent expressions are 6y + 4 and 11y + 16

How to determine the equivalent expressions?

Expression (A)

We have:

2y + 4(y + 1)

Open the bracket

2y + 4y + 4

Evaluate the like terms

6y + 4

Expression (B)

We have:

9y + 6 + 2(5 + y)

Open the bracket

9y + 6 + 10 + 2y

Evaluate the like terms

11y + 16

Hence, the equivalent expressions are 6y + 4 and 11y + 16

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Let f(x) = 3x²+2, g(x) = 3x - 5. Find the following value or expression.
(fog)(x)

Answers

Answer:

  (f∘g)(x) = 27x² -90x +77

Step-by-step explanation:

The composition of functions (f∘g)(x) is interpreted to mean f(g(x)). The value is found the way any function value is found. The argument is substituted for the variable in the function definition.

Substitution

After substituting g(x) for the argument of f(x), the resulting expression can be simplified.

  [tex](f\circ g)(x) =f(g(x))=f(3x-5)\\\\=3(3x-5)^2+2=3(9x^2-30x+25)+2\\\\\boxed{(f\circ g)(x)=27x^2-90x+77}[/tex]

If 70 mL of solution contains 280 mg of drug, how many milligrams of drug are in 50 mL of solution?

Answers

280 mg = 70 Ml
280/70 = 4
50 mL x 4 = 200 mg

200 mg

Solve the logarithmic equation by writing in exponential form or by
graphing.
log (5-2x) = 0

Answers

Answer:

Hello,

Step-by-step explanation:

[tex]log(5-2x)=0\\\\\ \Longleftrightarrow\ 10^{log(5-2x)}=10^0\\\\\\\Longleftrightarrow\ 5-2x=1\\\\\Longleftrightarrow\ 2x=5-1\\\\\\\Longleftrightarrow\ x=\dfrac{4}{2}\\\\\\\Longleftrightarrow\ \boxed{x=2}\\[/tex]

the function f(t) = 5 cos(pi/4*t) + 11 represents the tide in dark sea. it has a maximum of 16 feet when time (t) is 0 and a minimum of 6 feet. the sea repeats this cycle every 8 hours. after six hours, how high is the tide?

Answers

The height of the tide after eight hours is 16 feet.

How to illustrate the function?

From the information given, the function is given as 5cos (π/4)t + 11.

In this case, the time is given as eight hours. This will be:

f(8) = 5 × cos (π/4) × 8 + 11

f(8) = 5 × cos(2π) + 11

= (5 × 0.999) + 11

= 16 feet

The height is 16 feet.

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Geometry Question!! PLEASE HELp

Answers

The difference between the distance travelled by any point on the record and it's label is; 27.57cm.

What is the difference between the distance travelled in each case?

According to the task content, it follows from observation that the quantity required is the difference between the circumference in each case and can be evaluated as follows;

Difference = π(17.78 - 9)

Difference = (22/7) × 8.78

Difference = 27.57cm.

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Suppose we want to choose 5 letters, without replacement, from 15 distinct letters.

Answers

[tex]order \: does \: not \:matter \\ sample \: space = 15 \: letters \\ no \: repetition\\ P(A) = 15C5 = 3003 \: ways[/tex]

Assume a = b and c ≠ 0
Which of the following sentences is not true?

1) a+c=b+c

2) a-c=b-c

3) ac = bc

4) a/c = b/c

5) none of these​

Answers

Answer:

None of these is not true

5) none of these is not true because all of them are actually true.

Please tell me fast on a time crunch

Answers

Answer:

x ≥ -6

Step-by-step explanation:

x - 4 ≤ 3x + 8

Add 4 to both sides.

x ≤ 3x + 12

Subtract 3x from both sides.

-2x ≤ 12

Divide both sides by -2. Remember to change the direction of the inequality sign since you are dividing by a negative number.

x ≥ -6

Answer:

[tex]x \geqslant - 6[/tex]

Step-by-step explanation:

[tex]x - 4 \leqslant 3x + 8 = = > \\ - 12 \leqslant 2x = = = > \\ x \geqslant - 6[/tex]

Hector wants to laminate the tabletop in his study room. The tabletop is the shape of an isosceles trapezoid shown here. If laminating costs $4 per square foot, what is the total cost to laminate the tabletop?

A trapezoid with a height of 4 feet and bases of 6 feet and 10 feet is shown.

$136
$128
$112
$32

Answers

The total cost to laminate the table top is $128.

What is the total cost to laminate the table top?

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides.

The first step is to determine the area of the table top.

Area of a trapezoid = 0.5  x (sum of the lengths of the parallel sides) x height

0.5 x (6 + 10) x 4 = 32 square foot

Now, multiply the area by the cost per square foot

32 x 4 = $128

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Use the equation and type the ordered-pairs. y=3^x

Answers

The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)

How to type the ordered pairs?

The equation is given as:

y = 3^x

Let x = 0, 1 and 2

y = 3^0 = 1

y = 3^1 = 3

y = 3^2 = 9

So, we have the following ordered pairs (0,1), (1,3) and (2,9)

Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)

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