The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that Earth exerts on the sun?
A. Earth pulls the sun away from itself with a force equal to the ratio of the mass of the sun to the mass of Earth.
B. Earth pulls the sun toward itself with a force equal to the ratio of the mass of the sun to the mass of Earth.
C. Earth pulls the sun away from itself with an equal force.
D. Earth pulls the sun toward itself with an equal force,
Answers
Answer:
Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth
The Earth pulls the sun toward itself with an equal force. (Option D)
According to the 3rd Newton's Law, forces existing in the universe are shown in pairs, that is to say, for all action force, there is a corresponding reaction force of equal magnitude and opposite direction. By the Newton's Law of Gravitation we understand that gravitation between the Sun and the Earth is done because of a gravitational field created by mutual interaction, in terms of their masses and distance among them. The pair of forces is not based on direct contact.
Hence, we conclude that the Earth pulls the sun toward itself with an equal force.
We kindly invite to check this question on gravitation: https://brainly.com/question/3009841
Related Questions
1: A generator produces electricity at about 21,600 V. This voltage needs to be increased to about 345,000 V via a transformer before being transmitted through the power grid. What is the ratio of windings between the secondary coil and the primary coil needed to do this
Answers
Answer:
16:1
Explanation:
From the question,
Since the voltage of the transformer is increased, then the winding in the secondary coil is greater than the winding in the primary coil
Applying transformer's equation
Vs/Vp = Ns/Np............. Equation 1
Where Vs = Secondary voltage, Vp = primary Voltage, Ns/Np = Ratio of the winding between the secondary coil to the winding in the primary coil.
Given: Vs = 345000 V, Vp = 21600 V
Substitute these values into equation 1
Ns/Np = 345000/21600
Ns/Np = 16:1
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
Answers
Complete Question
(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
The tensile strength of the nylon string is [tex]600*10^{6} \ N/m^2[/tex]
Answer:
A
T = 471.3 \ N
B
To prevent breakage the thickness of the string is increased
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
Explanation:
From the question we are told that
The diameter is [tex]d = 1.00 \ mm = 0.001 \ m[/tex]
The tensile strength of the nylon string is [tex]\sigma = 600 *10^{6} \ N/m^2[/tex]
Generally the radius is mathematically evaluated as
[tex]r= \frac{d}{2}[/tex]
=> [tex]r = \frac{0.001}{2}[/tex]
=> [tex]r = 0.0005 \ m[/tex]
The cross sectional area is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.005)^2[/tex]
=> [tex]A = 7.855*10^{-7}\ m^2[/tex]
Generally the tensile strength of nylon is mathematically represented as
[tex]\sigma = \frac{T}{ A }[/tex]
Where T is the tension on the maximum tension on the string
So
[tex]T = \sigma * A[/tex]
=> [tex]T = 600*10^{6} * 7.855*10^{-7}[/tex]
=> [tex]T = 471.3 \ N[/tex]
Form the equation above we see that
[tex]T \ \alpha \ A[/tex]
So if the tension is increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional area )
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.
Answers
Answer:
4 seconds
Explanation:
Given:
v₀ = 20 m/s
v = 0 m/s
a = -5 m/s²
Find: t
v = at + v₀
0 m/s = (-5 m/s²) t + 20 m/s
t = 4 s
Add the following vectors using head-to-tail method and verify your results using the component method.
1. Vector A has a magnitude of 4.0 cms at an angle of 30 degrees with the positive X-axis; vector B has a magnitude of 3.0 cms at 90 degrees with + X-axis; vector C has a magnitude of 5.0 cms at 120 degrees with + X-axis.
2. In addition to vectors A, B, and C in problem # 1, there is a vector D with a magnitude of 6.0 cms at an angle of 210 degrees with +X-axis.
Note: Use a graph paper to show your work for problem number 1 and 2 using the head-to-tail method.
Do the component method analysis of both of these problems using the component method of adding vectors. Show your work step by step by taking the x and y components of all the vectors; adding all the x and y components together and then finding the resultant vector magnitude and direction knowing x and y are perpendicular to each other.
Compare the results of the graphical analysis as well as the component method and find the percent error using the component method as standard result
Answers
Answer:
See attached image for the requested graphs.
Part 1 : Vector sum is about 9.4 cm long in the graph, from components: about 9.35 cm long. Percent difference = 0.5%
Part 2: Vector sum is about 7.6 cm long in the graph and from components: 7.57 cm long. Percent difference = 0.4%
Explanation:
Part 1.
The graphical addition of the three vectors A, B and C gives a vector sum of approximately 9.4 cm at an angle of about 84 degrees
The component form addition is
Ax + Bx + Cx = 3.5 + 0 + (-2.5) = 1
Ay + By + Cy = 2.0 + 3 + 4.3 = 9.3
Magnitude: [tex]\sqrt{1^2+9.3^2} \approx 9.35\,\,cm[/tex]
The percent difference is: (9.4-9.35) * 100 /9.35 = 0.5%
Part 2.
The graphical addition of the four vectors (A, B, C, and D) measures approximately 7.6 cm at an angle of about 124 degrees.
The component form addition is
Ax + Bx + Cx + Dx = 3.5 + 0 + (-2.5) + (-5.2) = -4.2
Ay + By + Cy + Dy = 2.0 + 3 + 4.3 + (-3) = 6.3
Magnitude = [tex]\sqrt{(-4.2)^2+6.3^2} \approx 7.57\,\,cm[/tex]
The percent difference is: (7.6-7.57) * 100 /7.57 = 0.4%
A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. m/s2 (b) Over what time interval does the proton reach this speed? s (c) How far does it move in this time interval? m (d) What is its kinetic energy at the end of this interval? J
Answers
Answer:
a) a = 6.31 10¹⁰ m / s² , b) t = 2.06 10⁻⁵ s , c) x = 13.39 m , d) ΔK = 1.41 10⁻¹⁵ J
Explanation:
a) Since they indicate that the speeds are non-relativistic, we can use the kinematics relations and Newton's second law
F = m a
The force in electrical is
F = qE
qE = m a
a = qE / m
we calculate
a = 1.6 10⁻¹⁹ 660 / 1.673 10⁻²⁷
a = 6.31 10¹⁰ m / s²
b) Let's use the one-dimensional kinematics relation
v = v₀ + a t
as part of rest its initial velocity is zero
v = a t
t = v / a
t = 1.30 10⁶ / 6.31 10¹⁰
t = 2.06 10⁻⁵ s
c) We use the kinematics displacement equation
x = v₀ t + ½ a t²
initial velocity is zero
x = ½ a t²
x = ½ 6.31 10¹⁰ (2.06 10⁻⁵)²
x = 1,339 10¹ m
x = 13.39 m
d) the kinetic energy is
ΔK = Kf -K₀
ΔK = ½ m v² - 0
ΔK = ½ 1.673 10⁻²⁷ (1.30 10⁶) 2
ΔK = 1.41 10⁻¹⁵ J
The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (Assume atmospheric pressure.)(a) What is the number of molecules of air inhaled with each human breath when the air temperature is 18.0°C?________molecules(b) If the molar mass of air is 28.96 g/mol, what is the mass of air molecules inhaled with each breath? (Assume the air temperature is 18.0°C.)(c) It has been calculated that all of the air in Earth's atmosphere could be collected into a sphere of diameter 1,999 km at a pressure of 1.00 atm. What is the mass of the air in Earth's atmosphere? (Assume the density of air used in this calculation was 1.225 kg/m3.)(d) If all 7 billion humans on Earth inhaled simultaneously, what percentage of the atmosphere would be inhaled during this process? (Assume the air temperature is 18.0°C everywhere on Earth.)
Answers
Answer:
Explanation:
Temperature of air = 18°C = 273 + 18 = 291 K .
volume = 500 cc = 0 .5 litre .
pressure = one atmosphere ( atm) .
From gas equation , we can calculate this volume at NTP as follows.
volume = .5 x ( 273 / 291 ) litre
= 0.469 litre .
In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules
.469 litre will contain 6.02 x 10²³ x .469 / 22.4 molecules
= 126 x 10²⁰ molecules .
b )
one mole = 6.02 x 10²³ molecules
6.02 x 10²³ molecules has weight of 28.96 grams
126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams
= .606 gram .
c )
volume of all the air in the atmosphere = volume of sphere
= 4 / 3 x π x R³
= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³
= 4.18 x 10¹⁸ m³
density of air = 1.225 kg / m³
mass of air = 1.225 x 4.18 x 10¹⁸ kg
= 5.12 x 10¹⁸ kg
d )
volume of air inhaled by 7 billion people
= . 5 x 7 x 10⁹ litre
= 3.5 x 10⁶ m³ .
Total volume of air in atmosphere = 4.18 x 10¹⁸ m³
required percentage
= 3.5 x 10⁶ x 100 / 4.18 x 10¹⁸
= .8373 x 10⁻¹⁰ % .
A container of gas at 2.7 atm pressure and 133 ∘C is compressed at constant temperature until the volume is halved. It is then further compressed at constant pressure until the volume is halved again.
a) What is the final pressure (atm)?
b) What is the final temperature (C)?
Answers
Answer:
5.4atm ,66.5°c
Explanation:
Note that we are given the initial temperature to constant,
Thus PV = constant
so volume halved means pressure doubled from P1v1= p2v2
Hence P2 = 2.7*2atm = 5.4atm
next step we keep pressure constant thenV/T = constant
so volume halved means temperature also halved from V1/T1= v2/T2
Hence
T = 133/2 = 66.5°C
If the charge remains the same but the radius of the sphere is doubled, the electric flux coming out of it will be
Answers
Answer:
Explanation:
We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .
∫ E ds = q / ε
Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so
∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .
This also represents total flux coming out of the charge q on all sides .
This is equal to q / ε where ε is a constant called permittivity which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .
If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .
It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors
1 ) charge q and
2 ) the permittivity of medium ε around .
An optical fiber made of glass with an index of refraction 1.50 that is coated with a material with index of refraction 1.30 has a critical angle of
Answers
Answer:
A critical angle of 60.1°
Explanation:
Let's say
n1 Refractive index of rarer medium
n2 Refractive index of denser medium
So using the relation
စc= Sin^ -1(n1/n2)
So
စc = Sin^-1(1.3/1.5) = 60.1°
What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser
Answers
Hello. This question is incomplete. The full question is:
You've recently read about a chemical laser that generates a 20-cm-diameter, 25.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20-cm-diameter, 100 kg,perfectly absorbing block. What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser?
Answer:
V = 0.408 m / s
Explanation:
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 25 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8) = 2,652 N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2,652 * π * (0.2 / 2) ^ 2 = 0.083N
a = F / m
a = 0.083 / 100 = 0.0002129 m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.0002129 * 108
V = 0.2144 m / s
What is the direction of the magnetic field at the location of the charge due to the current-carrying wire
Answers
Answer: please find the answer in the explanation.
Explanation:
The direction of the magnetic field at the location of the charge due to the current-carrying wire can be determined by using right hand rule.
The thumb points in the direction of current while the fingers curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight wire. The thumb is pointed in the direction of the current and the fingers then give the direction of the magnetic field lines.
A paper pinwheel is spinning in the wind. Which statement is correct about the forces responsible for the rotation?
A. The perpendicular components of gravity and the force of wind are responsible for the rotation.
B. Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
C. The components of gravity and the force of wind that point through the pivot are responsible for the rotation.
D. Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot.
Answers
Answer:
Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.
Explanation:
Where on the physical activity pyramid do sedentary activities belong?
Answers
Answer:A
Explanation:
i just did the test
Answer: A.
Explanation: Edge said it was right
Examples of sources of physical entropy for secure random number generation include:________
Answers
Answer:
Noise in the environment
Electrons emitted via the photoelectric effect
Explanation:
Physical entropy can be seen as a disorderliness that can be observed in a physical system. The noise in a physical system can be used for secure number generation because of its randomness.
Noise is known to have no defined pattern and hence, can be used to creates secure random key generations.
Electrons emitted via the photoelectric effect: Electrons are emitted in a random order whenever a beam of light is incident on a photoelectric material. These electrons emitted can be used for random key generations
Draw the velocity vectors starting at the black dots and the acceleration vectors including those equal to zero. The orientation of the vectors will be graded. The location and length of the velocity vectors will be graded. The location and length of the nonzero acceleration vectors will not be graded. To draw a zero vector click at the point of its location.
Answers
Answer:
hello your question is incomplete attached below is the remaining part and the solution
Explanation:
The accelerations at points 1,2,3 is zero and this is because the velocities at points 1,2,3 are constants. attached below is the velocity vector diagram and the acceleration vectors
A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration of the car?
Answers
Answer:
770m/s
Explanation:
caculation using one of the newton law of motion
A right triangle has a hypotenuse of 37 and a leg of 10. What is the second leg of the triangle?
Answers
Answer:
The second leg of the triangle is 35.62
Explanation:
Given that
Hypotenuse = 37
A leg = 10
Based on the above information
The second leg of the triangle is
According to the Pythagorean theorem
a^2 + b^2 = c^2
where,
a and b = legs
And, the c = hypotenuse.
Now put these values to the above formula
So,
10^2 + b^2 = 37^2
b^2 = 37^2 - 10^2
b^2 = 1269
b = sqrt(1269)
b = 35 .62
Hence, the second leg of the triangle is 35.62
The other leg is 35 mm.
PHYSICS HW HELP PLS!! explain how you got it too thank you! :)
1.) F= Gm1m2/d2 for m2
2.) R= V/I for I
3.) = xd/L for d
4.) ac= v^2/r for v
5.) A= πr^2 for r
6.) vf^2= vi^2+2ax for x
Answers
Answer:
Explanation:
Can you please place the square roots in a proper manner so I may assist you?
Rayna studied rats in a lab. She observed that all 50 rats in her sample preferred to eat brand A rat food and would eat brand B food only when brand A was not available. Can she correctly conclude that all rats prefer brand A rat food over brand B food? Why or why not?
Answers
Answer:
it is correct to conclude that rats prefer food A over food B
the standard deviation is zero
Explanation:
In the experiment performed when both meals are available, rats prefer food A and eat only B when no other is available.
Therefore it is correct to conclude that rats prefer food A over food B
This conclusion is correct because ours is significant with a population of 50 animals all have the same preference for which the standard deviation is zero
"Which gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string?"
Answers
Answer:
the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string
Explanation:
This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required
Formula of velocity
Answers
Answer:
s = d/t
Explanation:
s= speed
d = distance traveled
t = time elapsed
PLEASE HELP NEED ANSWERS NOW! Time-Distance Graph
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, some have more details available when you click on them. Drag and drop each label to the corresponding area it identifies in the image.
Answers
Answer: I added a picture of the answer
Explanation: its right
The image of answer with labeled Time-Distance Graph is attached.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
What is a Distance-Time Graph?How far an object has moved in a certain amount of time is displayed on a distance-time graph. The graph that shows the results of the distance vs time analysis is a straightforward line graph.
The Y-axis represents the distance.The X-axis is used to plot time.When the object's motion is uniform, and the graph is a straight line. we can determine the object's speed at any given moment of time from the graph. The object was in the following positions when it started and stopped:
Speed = (Final Position-Initial position)/Time
Drawing a rectangle anywhere along the straight line that regulates the object's speed will reveal the slope of the line. A horizontal line on the distance-time graph indicates that an object is at rest if it is not moving.
Learn more about speed here:
https://brainly.com/question/28224010
#SPJ5
A 5 kg object is launched from a 35 m high cliff at an angle of 30 degrees with a speed of 100 m/s. How far from the cliff does it hit the ground
Answers
Answer:
The object will hit the ground at 882.77 m from the lunch
Explanation:
we are to find the range of the motion
What is range?
It is the distance from the point of projection to the point where the object hits the ground
R=(v^2sin2θ)/g
Given data
v= 100 m/s
θ= 30 degree
g= 9.81 m/s^2
Substituting to find the R we have
R= 100^2 *sin(2*30)/9.81
R= (10000*0.866)9.81
R= 8660/9.81
R= 882.77 m
if the DIY parachute is dropped freely from the rooftop of the building of a building and reached the ground 3s later.Upon reaching the ground,What is the (a)final velocity of DYI parachutes ?(b) Height of the rooftop?
Answers
Answer:
It depends on what the parachute is made out of.
Explanation:
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency of 2 Hz, what is the speed of the wave that travels through the string to the other end?
Answers
Wave speed = (wavelength) x (frequency)
Wave speed = (0.5 m) x (2 /sec)
Wave speed = 1 m/s
a train it speed steading from 10 m/s to 20m/s in 1 minutes average speed during this time in m/s
how far does it travel while increase its speed
Answers
Explanation:
Given:
v₀ = 10 m/s
v = 20 m/s
t = 60 s
Find: v_avg and Δx
v_avg = ½ (v + v₀)
v_avg = ½ (20 m/s + 10 m/s)
v_avg = 15 m/s
Δx = v_avg t
Δx = (15 m/s) (60 s)
Δx = 900 m
A resistance of 4 ohm is offered by a conductor when a potential difference of 6 V l'd applied across it. Calculate the current through it?.
Answers
Answer:
1.5 Ampere
Explanation:
The formula is V=IR
so now we can derive out the formula which is
I =V
R
I = 6
4
I = 1.5 Ampere
Joey drives his Skidoo 13 kilometres north. He stops for lunch and then drives 10kilometres south. What distance did he cover? What was his displacement?
Answers
Answer:
Total distance covered (scalar quantity) = 23 km
Displacement (vector quantity) = 3 km north from the original starting point
Explanation:
Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km
On the other hand, his displacement was 3 km north from where he started.
what is the significant contribution of Heraclitus
Answers
Explanation:
HERACLITUS ALSO SPELLED HERADEITUS, [ BORN C.540 bce, EPHESUS, ANATOLIA [ NOW SELCUK, TURKEY] - DIED C.486 ] GREEK PHILOSOPHER REMEMBERED FOR HIS COSMOLOGY, IN WHICH FIRE FORMS THE BASIC MATERIAL PRINCIPLE OF AN ORDERLY UNIVERSE . LITTLE IS KNOWN ABOUT HIS LIFE, AND THE ONE BOOK HE APPARENTLY WROTE IS LOST.
HOPE IT HELP.....❤❤Acceleration: A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration
Answers
Answer:
1500 m/s squared
Hope this helps :)
Explanation: