Answer:
7.88 x 10²² formula units CuCl₂
Explanation:
To find the amount of formula units, you need to (1) convert grams to moles (via the molar mass) and then (2) convert moles to formula units (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (CuCl₂): 134.45 g/mol
Avogadro's Number:
6.022 x 10²³ formula units = 1 mole
17.6 g CuCl₂ 1 mole 6.022 x 10²³ formula units
-------------------- x ----------------- x ------------------------------------------ =
134.45 g 1 mole
= 7.88 x 10²² formula units CuCl₂
Select the correct answer.
A 20.0-liter flask contains a mixture of argon at 0.72 atmosphere and oxygen at 1.65 atmospheres. What is the total pressure in the flask?
A. 0.93 atm
B. 2.37 atm
C. 8.44 atm
D. 18.6 atm
Answer:
2.37 atm
Explanation:
0.72+1.65 = 2.37 atm
A soil test recommends applying 193 lbs N per acre. Using a 36-6-18 fertilizer, how much fertilizer is needed to meet the recommendation? Round your answer to nearest whole number.
The mass of 36-6-18 fertilizer fertilizer required is 536 lb.
What mass of nitrogen fertilizer is required for the acre of land?The mass of nitrogen fertilizer required for the acre of land is determined as follows:
Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.
Mass of Nitrogen required per acre = 193 lbs
Mass of fertilizer required = 193 * 100/36
Mass of fertilizer required = 536 lb of fertilizer.
In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.
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What is the generic name of this molecule? (Ph stands for phenyl)
The proper name of the compound is now 1,1 - dihydroxy-3-phenyl propene.
What is the name of the compound?Firstly we know that the parent chain is based on propane. Now we have three substituents on that parent chain. Two hydroxy moieties and one phenyl moiety.
The proper name of the compound is now 1,1 - dihydroxy-3-phenyl propene.
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Calculate the mass in grams of benzophenone required to make a solution of 2.5 mmoles
Answer:
0.46 grams (C₆H₅)₂CO
Explanation:
To find the mass of benzophenone ((C₆H₅)₂CO), you need to (1) convert mmoles to moles and then (2) convert moles to grams (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the sig figs of the given value (2.5 mmoles).
Molar Mass ((C₆H₅)₂CO): 13(12.011 g/mol) + 10(1.008 g/mol) + 15.998 g/mol
Molar Mass ((C₆H₅)₂CO): 182.221 g/mol
2.5 mmoles (C₆H₅)₂CO 1 mole 182.221 g
----------------------------------- x ------------------------ x ------------------- =
1,000 mmoles 1 mole
= 0.46 grams (C₆H₅)₂CO
A student reacted dilute nitric acid with lead(II) oxide to prepare lead(II) nitrate. The diagram shows the stages in the method used.
The highlighted apparatus are;
1) stirring rod
2) crucible
What is a chemical reaction?The term chemical reaction refers to the process by which two or more substances are combined to form a product. The product may look like or different from the reactants that were combined to produce it.
Now we can see the set up that was used as shown for the reaction of dilute nitric acid with lead(II) oxide to prepare lead(II) nitrate.
The highlighted apparatus are;
1) stirring rod
2) crucible
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34.1 mg NaCl in 117.3 mL of solution
The molarity of the solution will be 4.97 M.
What is molarity?It is the number of moles of solutes per 1 liter of solvent or solution.
Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol
117.3 mL = 117.3/1000 = 0.1173 L
Molarity of the solution = 0.5835/0.1173 = 4.97 M
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which celsius temperature is equal to 298k
Answer:
298-273 = 25°C is correct answer!
Question 9
What pressure will be exerted by 15 g of carbon dioxide gas in a 20 L container at 0 °C?
Answer:
0.382 atm
Explanation:
In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
15 grams CO₂ 1 mole
---------------------- x ------------------------ = 0.341 moles CO₂
44.007 grams
To find the pressure, you need to use the Ideal Gas Law equation.
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.
P = ? atm R = 0.08206 atm*L/mol*K
V = 20 L T = 0 °C + 273.15 = 273.15 K
n = 0.341 moles
PV = nRT
P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)
P(20 L) = 7.64016
P = 0.382 atm
A concept map for four types of intermolecular forces and a certain type of bond is shown.
No
A
No
Are molecules
with permanent
dipoles present?
Yes
Is H atom
bonded to F, O, or
Natom?
No
B
Are ions
present?
Yes
C
Yes
Are polar
molecules
present?
Yes
D
No
E
Compare the relative strength of the two forces C and D. Explain how you determined this comparison by identifying the forces.
XD
ΩΣ
Source
C
In the case the relative strength of the two forces C and D is that D represents a ion-dipole forces, which are known to be very much stronger than the force that is said to be represented by C.
What is the aim of concept map?A concept map is known to be a kind of a special type of a web diagram that is often used in the exploration of knowledge and gathering and also in sharing of information.
Note that Concept mapping is a strategy used in creating the idea of a map as it is made up of a visual depiction of ideas, theories, and others.
Note that Intermolecular forces are known to be those forces that are said to be attractive and also a kind of a repulsive forces that is seen between the molecules of a substance.
Looking at the image attached, In regards to the relative strength of the two forces C and D. The fact is that D stands for ion-dipole forces, which are known to be very much stronger than the force that is said to be represented by C.
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9. Predict the full Robinson Annulation product (including all intermediates) and 10. Show the stepwise mechanism for the following reaction.
Consider this reaction: 6 CO2 + 6 H₂O + light
C6H12O6 + 6 02
If you actually produced 30g of C6H12O6 what would be the percent yield?
Calculate the theoretical yield from having 2.38 x 10² g of H₂O, 18.6 moles of CO₂.
531.2 grams of oxygen and 608.22 grams of C6H12O6 make up the potential yield.
What is a Moles?A mole is the amount of a substance that contains precisely 6.02214076 X 1023 of the substance's fundamental components.If a material has the same mass as 12.000 g of 12C and the same number of elementary particles as atoms, it is said to have a mole of that substance.The mole can be used to determine the simplest compound formula and calculate the quantities needed for chemical reactions. Molarity, a related concept, comes in handy when discussing reactions in solutions. Molarity is the measure of how many moles of a solute are present per liter of a solution (M).Molecular quantities are those that cannot be measured in terms of grams or milligrams. This way, a mole counts the number of atoms, ions, or molecules.Determine the reaction's theoretical yield:
Given is the reaction: 6 CO2 + 6 H2O = C6H12O6 + 6 O2.
2.38 x 102 g of H2O are provided as the mass.
Given is 18.6 moles of CO2.
6 CO2 + 6 H2O → C6H12O6 + 6 O2
6 moles of H2O 1 mole of C6H12O6
1 mole of water equals 0.6 moles of C6H12O6.
18gm of H2O = 276/6 gm of C6H12O6
2.38*10^2 gm of H2O = ? gm of C6H12O6
[tex]=\frac{2.38*10^{2} *\frac{276}{6} }{18}[/tex]
[tex]=608.22gms[/tex] of C6H12O6
1 mole of C6H12O6 = 276gms
? moles of C6H12O6 = 608.22gms
= 608.22/276
= 2.2 moles of C6H12O6
6 moles of CO2 = 6 moles of O2
1 mole of CO2 = 1 mole of O2
∴ 18.6 moles of CO2 = 18.6 moles of O2
1 mole of O2 = 32gms of O2
∴18.6 moles of O2 = ? gm
= 18.6*32
= 531.2gms of O2
Hence 531.2 grams of oxygen and 608.22 grams of C6H12O6 make up the potential yield
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how many molecules of methane, CH4 are in 125 g CH4
Answer:
4.69 x 10²⁴ molecules CH₄
Explanation:
To find the amount of molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (125 g).
Molar Mass (CH₄): 16.05 g/mol
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
125 g CH₄ 1 mole 6.022 x 10²³ molecules
---------------- x --------------- x ------------------------------------- =
16.05 g 1 mole
= 4.69 x 10²⁴ molecules CH₄
What would the pH of a solution that had a hydroxide ion concentration of 4.9 x 10-5 M be?
Taking into account the definition of pH and pOH, the pH of the solution is 9.69.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
pH in this caseA solution had a hydroxide ion concentration of 4.9×10⁻⁵ M. This is [OH⁻]= 4.9×10⁻⁵ M. So, pOH is calculated as:
pOH= - log (4.9×10⁻⁵ M)
Solving;
pOH= 4.31
Replacing in the relationship established between pH and pOH, the pH can be calculated as:
pH + 4.31= 14
Solving:
pH= 14 - 4.31
pH= 9.69
In summary, the pH of the solution is 9.69.
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Suppose you experimentally calculate the value of the gas constant R
as 0.0878 L-atm/mol-K. The known value is 0.0821 L-atm/mol-K.
What is the percent error of your experimentally determined R?
Answer: 5.72%
Explanation:
Given:
Experimental value of gas constant, R = 0.0878 L.atm/mol⋅K
Known value of gas constant, R = 0.0821 L.atm/mol⋅K
This percent error is defined as the difference in percentage between a measurement's real value and its observed value.
[tex]\text { Percent Error }=\frac{\mid \text { Experimental Value }-\text { Known Value } \mid}{\text { Known Value }} * 100[/tex]
[tex]\text { Percent Error }=\frac{\mid \text {0.0878}-\text { 0.0821 } \mid}{\text { 0.0821 }} * 100[/tex]
[tex]\bf{Percent \ Error = 5.72\%}[/tex]
Balance the following reactions
a) Ca (s) + H₂O (1)→ Ca(OH)2 (aq) + H₂ (g)
b) Al2O3 (s) + C(s) + Cl₂ (g) → AICI3 (s) + CO (g)
c) FeCl3 (aq) + H₂S (g) → Fe2S3 (s) + HCI (aq)
d) CaCO3 (s) + HCI (aq) → Ca Cl₂ (aq) + CO2 (g) + H₂O (1)
Answer:
a) Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
b) Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
c) 2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
d) CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Explanation:
For an equation to be balanced, there must be an equal amount of each type of atom on both sides of the reaction. The reactants are on the left side and the products are on the right side.
a) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Ca (s) + H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 2 hydrogen, 1 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
The balanced equation:
Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 4 hydrogen, 2 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
b) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Al₂O₃ (s) + C (s) + Cl₂ (g) ---> AICI₃ (s) + CO (g)
Reactants: 2 aluminum, 3 oxygen, 1 carbon, 2 chlorine
Products: 1 aluminum, 1 oxygen, 1 carbon, 3 chlorine
The balanced equation:
Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
Reactants: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
Products: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
c) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
FeCl₃ (aq) + H₂S (g) ---> Fe₂S₃ (s) + HCI (aq)
Reactants: 1 iron, 3 chlorine, 2 hydrogen, 1 sulfur
Products: 2 iron, 1 chlorine, 1 hydrogen, 3 sulfur
The balanced equation:
2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
Reactants: 2 iron, 6 chlorine, 6 hydrogen, 3 sulfur
Products: 2 iron, 6 chlorine, 6 chlorine, 3 sulfur
d) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
CaCO₃ (s) + HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 1 hydrogen, 1 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
The balanced equation:
CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
5. Which of the following personal protective equipment is selected based on a
chemical's IDLH value?
O A. Respirator
O B. Eyewear
O C. Body suit
O D. Gloves
Respirator - It is chosen based on a chemical's IDLH value, ensuring protection against immediate life-threatening respiratory hazards.
Option (A) is correct.
The correct personal protective equipment (PPE) selected based on a chemical's IDLH (Immediately Dangerous to Life or Health) value is a respirator. IDLH value is a critical safety parameter that represents the maximum concentration of a chemical in the air above which an individual could suffer immediate or long-term health effects, such as life-threatening respiratory issues.
When a chemical's IDLH value is exceeded, it becomes essential to use appropriate respiratory protection. A respirator helps filter and remove harmful contaminants from the air, preventing inhalation and protecting the wearer's respiratory system.
Different types of respirators are available, ranging from simple dust masks to full-face air-purifying respirators or supplied-air respirators, based on the specific hazard and IDLH value of the chemical involved.
Eyewear, body suits, and gloves are essential PPE, but they are not specifically selected based on the chemical's IDLH value.
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What is indicated by the methyl-prefix?
OA. The molecule is an alkene.
OB. The molecule is a branched hydrocarbon.
O C. The molecule is saturated with hydrogen atoms.
OD. The molecule is a stereoisomer.
Answer:
B.) The molecule is a branched hydrocarbon.
Explanation:
A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.
why second ionization energy of second group elements is lower than alkali metals.
Answer:
The removal of second electron from alkaline earth metals leads to the stable octet state in M2+ ions. In case of alkali metals it is not so. Since the removal of electron leads to stability, hence it can easily removed leading to lowering of second ionization enthalpy in alkaline earth metals.
Explanation:
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A weather balloon calibrated at 0.00 °C to
have a volume of 20.0 L has what volume at
-36.2 °C assuming pressure is held
constant? Answer is in L
Answer:
17.3 L
Explanation:
With all other variables held constant, you can find the missing volume using the Charles' Law equation:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before we can solve, we need to convert Celsius to Kelvin (because we don't want negative numbers or temp. of 0).
V₁ = 20.0 L V₂ = ? L
T₁ = 0.00 °C + 273.15 = 273.15 K T₂ = -36.2 °C + 273.15 = 236.95 K
V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation
20.0 L / 273.15 K = V₂ / 236.95 K <----- Insert values
0.0732 = V₂ / 236.95 K <----- Simplify left side
17.3 L = V₂ <----- Multiply both sides by 236.95
Fill in the chart below to identify the properties of shape and volume for each type of matter. Shape Volume Solid Liquid Gas
The properties are given below:
Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volumeWhat are the properties of solids, liquids and gases?The property of solids, liquids, and gases refers to those features which are used to identify solids, liquids and gases.
Some property of solids, liquids and gases are shape and volume.
Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.
Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volume
In conclusion, solids, liquids and gases have unique properties in their shape and volume.
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PLEASE ANSWER THIS FAST... tysm
●what will happen to the texture off egg shell if you place it in.
1. Coca cola
2. orange juice
3. grape juice
4. normal water
5. a dark coloured sugary drink like sting
Answer all these correctly please
thanks
Answer:
4. the egg shell you place in normal water
How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?
A. 163.2
B. 0.28
C. 152.3
D. 0.30
0.28 moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa).
Ideal gas law :
An ideal gas is a gas in which atoms dose not exert any force on each other even after collision which walls and other atoms (inelastic collisions).
Mole definition:
The mole is the amount of compound present in a given system which has molecular mass as that of the mass of carbon12 .carbon 12
Using ideal gas law ,
PV=nRT
Given,
pressure = P = 100kPa
Volume = V = 6.8 Lit
Temperature = room temperature = T = 293 K
R= universal gas constant = 8.314
n= moles = ?
∴[tex]n = \frac{PV}{RT}[/tex]
∴ n = 100 × 6.8 / 8.314 × 293
∴n = 0.28 moles
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State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:
Mg (s) + H2SO4 (aq) ---> MgSO4 (aq) + H2 (g)
Answer:
Mg(s) = oxidized
H₂SO₄(aq) (hydrogen) = reduced
Explanation:
Oxidized substances lose electrons and see an increase in oxidation number. Reduced substances gain electrons and see a decrease in oxidation number.
Lone elements always have an oxidation number of 0. H₂SO₄ and MgSO₄ are ionic compounds that can be broken up into a cation and polyatomic anion. The anion, SO₄²⁻, has an overall oxidation number of -2. Therefore, to make the overall charge of the ionic compound neutral, the hydrogen in H₂SO₄ has an oxidation state of +1 (bc there are two hydrogens) and the magnesium in MgSO₄ has an oxidation state of +2.
Since Mg(s) is losing electrons (goes from 0 to +2), it is being oxidized. Since the hydrogen in H₂SO₄(aq) is gaining electrons (goes from +1 to 0), it is being reduced.
You need to calculate the enthalpy change (AH) of the reaction A + 2B → C.
How can the enthalpies given for the reaction steps below be combined to
give the overall change in enthalpy?
D+B
D+3B
A. AH = AH2-A H₁
B. AH=2AH₁+AH²₂
OC. AH AH ₁ +AH²₂
D. AH = A H₁-AH₂
A
C
A
AH°,
A Hº
The enthalpy change of the reaction: A + 2B → C is determined as follows: ΔH = ΔH₁ + ΔH₂; option C
What is enthalpy change?Enthalpy change refers to the change in heat content as reactant molecules combine to form products.
The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.
Thus, the enthalpy change of the reaction: A + 2B → C is determined as follows:
ΔH = ΔH₁ + ΔH₂
In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.
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27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
How to find the mass of solute ?Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]
= [tex]\frac{508.64}{100}[/tex]
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
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Calculate the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask
9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.
What is Law of Equivalent ?N₁V₁ = N₂V₂
where,
N₁ = Normality of solution with known concentration
V₁ = Volume of solution with known concentration
N₂ = Normality of solution with unknown concentration
V₂ = Volume of solution with unknown concentration
Now find the mass of solution
Mass = Density × Volume
= 1.16 × 0.32 × 1000
= 371.52 g
How to find the Normality ?Normality = [tex]\frac{\text{Weight}}{\text{Equivalent weight}}[/tex]
= [tex]\frac{371.52\ g}{36.5}[/tex]
= 10.18 equivalents
Now put the values in above formula we get
N₁V₁ = N₂V₂
1 × 100 = 10.18 × V₂
100 = 10.18 × V₂
[tex]V_{2} = \frac{100}{10.18}[/tex]
= 9.82 mL
Thus from the above conclusion we can say that 9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.
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What volume of barium chloride, BaCl2 is needed to make a 2.5 M barium
chloride solution with 0.45 mol BaCl2?
Answer:
0.18 L
Explanation:
You can find the volume using the molarity ratio:
Molarity = moles / volume (L)
You can plug the given values into the equation and simplify to find the volume.
Molarity = moles / volume <----- Molarity ratio
2.5 M = 0.45 moles / volume <----- Insert values
(2.5 M) x volume = 0.45 moles <----- Multiply both sides by volume
volume = 0.18 L <----- Divide both sides by 2.5
Balance the following reaction: NH3 + I2 --> N2I6 + H2
The balanced equation will be [tex]2NH_3 + 3I_2 -- > N_2I_6 + 3H_2[/tex]
What are balanced equations?They are chemical equations that obey the law of conservation of atoms.
In other words, they are equations in which the number of atoms before and after reactions are the same.
Thus, the balanced equation for the reaction will be [tex]2NH_3 + 3I_2 -- > N_2I_6 + 3H_2[/tex]
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Which is the number of moles of carbon dioxide produced from the complete combustion of 4.3 moles of ethanol?
The number of moles of carbon dioxide produced will be 8.6 moles.
Stoichiometri mole ratiosFirst, let's look at the balanced equation of the reaction. The complete combustion of ethanol gives carbon dioxide and water as follows:
[tex]C_2H_5OH + 3O_2 --- > 2CO_2 + 3H_2O[/tex]
We can see from the equation that the burning of 1 mole of ethanol produces 2 moles of carbon dioxide. In other words, the mole ratio is 1:2.
Thus, with 4.3 moles of ethanol, the amount, in moles, of carbon dioxide that will be produced will be:
4.3 x 2 = 8.6 moles
In other words, 8.6 moles of carbon dioxide will be produced from the complete combustion of 4.3 moles of ethanol.
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If you react 9.10g of vinyl chloride with 7.80g of oxygen, what is the theoretical yield of carbon dioxide
The theoretical yield of the CO2 produced is 4.22 g.
What is the theoretical yield of carbon dioxide?The balanced reaction equation is;
2C2H3Cl + 5O2 ------>2CO2 + 2H2O + 2HCl
Number of moles of vinyl chloride = 9.10g /62 g/mol = 0.15 moles
Number of moles of oxygen = 7.80g/32 g/mol = 0.24 moles
Now;
2 moles of C2H3Cl reacts with 5 moles of oxygen
0.15 moles of C2H3Cl reacts with 0.15 moles * 5 moles / 2 moles
= 0.375 moles
Hence oxygen is the limiting reactant;
5 moles of oxygen produces 2 moles of CO2
0.24 moles of oxygen produces 0.24 moles * 2 moles /5 moles
= 0.096 moles
Mass of CO2 produced = 0.096 moles * 44 g/mol
= 4.22 g
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