The name of Ra3N₂ is

A. The partial pressure of oxygen in atmospheric air at sea level is greater than the partial pressure of oxygen in atmospheric air at the top of Mt. Everest.

Partial pressure is the pressure exerted by a component of mixture of gases.

The depth (distance from top to bottom) of the atmosphere is greatest at sea level and decreases at higher altitudes.

With greater depth of the atmosphere, more air is pressing down from above.

Air pressure is greatest at sea level and falls with increasing altitude.

Thus, the partial pressure of oxygen in atmospheric air at sea level is greater than the partial pressure of oxygen in atmospheric air at the top of Mt. Everest.

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The total mass of the reactants equals the total mass of the products

Answer: To determine the mass of the 7.3 moles of a compound Taran also needs to know the molar mass of the compound

Explanation: Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.

Add it all together and put units of grams/mole after the number.

It gives us the molar mass of the compound taken.

Multiply it with number of moles i.e., 7.3 moles, you will get the mass of the 7.3 moles of a compound.
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Answer:

best answer is D

Explanation:

if element has even number then protons and neutrons are same but if element has odd number then we should add 1 number in number of protons to know neutrons. but this rule is not work in 4 element that element are argon, nitrogen, hydrogen and one other

If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

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Answer:

1.3 x10^-16

Explanation: answered it in your comments! :)

[tex]oxidation \: number \: of \: oxygen = \\ before \: rxn = - 2 \\ after \: rxn = - 2[/tex]

[tex]oxidation \: number \: of \: hydrogen = \\ before \: rxn = + 1 \\ after \: rxn = \\ 2x - 2 = 0 \\ x = + 1[/tex]

[tex]oxidation \: number \: of \: carbon = \\ before \: rxn = \\ x - 6 = - 2 \\ x = 4 \\ after \: rxn = \\ x - 4 = 0 \\ x = 4[/tex]

[tex]oxidation \: numbers \: remain \: constant \\ so \: none \:a re \: undergoing \: oxidation \: \\ nor \: reduction \: [/tex]

Answer:

D

Explanation:

I believe that is the answer

Explanation:

Proton is one of the subatomic particles which has a positive charge. The number of protons present will give the atomic number of the chemical element. Every element will have a unique atomic number. Thus, we can say that protons will determine the identity of an element.

Answer:

B.) 2.92

Explanation:

Tp find the mass of H₂ produced, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass), then (2) convert moles AlCl₃ to moles H₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂ to grams H₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.

Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)

Molar Mass (AlCl₃): 133.341 g/mol

2 Al + 6 HCl ---> 2 AlCl₃ + 3 H₂

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

129 g AlCl₃           1 mole              3 moles H₂             2.016 g
------------------  x  ------------------  x  ---------------------  x  ---------------  =
                            133.341 g          2 moles AlCl₃          1 mole

=  2.93 g H₂

*our answers are most likely different due to using slightly different molar masses

The element should be placed in the column for metalloids. Option A

We know that the properties of metals can be used to identify an unknown substances as a metal. We know that metals are able to react with acids to liberate the metal salt and hydrogen gas. Metals do not react with bases because they can not accept electrons.

Metalloids are generally amphoteric in nature. They can react with both the acid and the basses to form compounds. The nonmetals do not react with acid or base.

Looking at the result, we are told that the entry in the second row have the entries  nothing, nothing, nothing. If this is the outcome, then it follows that the element should be placed in the column for metalloids.

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Answer: A

Explanation:

Answer:

All except 2nd one

Explanation:

Answer:

CB. Two different compounds mixing and remaining separate is not correct!

Answer:

B) Gold

A) Number of electrons and protons.

Explanation:

Atomic Masses (from periodic table):

----> Copper (Cu): 63.546 g/mol

----> Gold (Au): 196.97 g/mol

----> Iron (Fe): 55.845 g/mol

----> Platinum (Pt): 195.08 g/mol

The atomic number represents the number of protons. Neutral atoms have the same number of protons as electrons. The mass number represents the number of protons and neutrons.

Answer:

Any base with an ability to dissolve in water are called alkalis. All alkalis are bases, however, not all bases are alkalis.

The ΔG° for the reaction in kJ/mol is -17.09.

Calculation,

The reaction is given below.

[tex]ICl(g)+Cl_{2} (g)[/tex]  → [tex]ICl_{3} (s)[/tex]

The ΔG° for [tex]ICl(g)[/tex] = -5.5  kJ/mol

The ΔG° for [tex]ICl_{3} (s)[/tex]  = -22.59  kJ/mol

The ΔG° for  [tex]Cl_{2} (g)[/tex]  = 0  kJ/mol ( change in gibb's free energy of standard state )

ΔG° for the reaction =  ΔG° (product) -  ΔG° (reactant)

ΔG°  for the reaction = -22.59  kJ/mol - ( -5.5  kJ/mol + 0  kJ/mol )

 ΔG°  for the reaction = -17.09  kJ/mol

The value of change standard gibb's free energy for the standard state ( most stable form of elements) is zero.

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The total atmospheric pressure of the final product in the flask is 18.36atm

Atmospheric pressure can be defined as the force exerted on a surface by the air above it as gravity pulls it to earth.

Furthermore, the standard atmosphere is a unit of pressure which is also defined as:

101,325 Pa =760mmHg

So therefore, the total pressure of the final product in the flask is 18.36atm

Complete question:

Gaseous iodine pentafluoride, IF₅, can be prepared by the reaction of solid iodine and gaseous fluorine:

I₂(s) + 5F₂(g) → 2IF₅(g)

A 10.00 L flask is charged with 19.0 grams of I₂ and 2.00 atm of F₂ at 25°C. The flask is heated to 100°C until one of the reagents is completely consumed. What will be the total pressure (in atm) of the final products in the flask at 100°C? (Assume ideal gas behavior)

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If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

2AgNO₃ + CaCl₂ →  2AgCl + Ca(NO₃)₂

Molecular Weight of CaCl₂ = 110.98 g/mol

Molecular Weight of AgNO₃ = 170.01 g/mol

Molecular Weight of AgCl = 143.45 g/mol

Here,

Volume of CaCl₂ = 30.0 mL = 0.03L

Volume of AgNO₃ = 38.5 mL = 0.0385 L

Now find the number of moles

Number of moles = Volume × Molarity

Number of moles of CaCl₂ = 0.03 L × 0.150

                                             = 0.00456 mol

Number of moles of AgNO₃ = 0.0385 L × 0.100

                                               = 0.00385 mol

The stoichiometric ratio of AgNO₃ to CaCl₂ is 2:1.

= [tex]\frac{0.00385}{2}[/tex]

= 0.001925 mol                      

According to Stoichiometry Mass of AgCl

[tex]= 0.0385 \times \frac{0.1}{1\ \text{mol}} \times \frac{2\ \text{mol} AgCl}{2\ \text{mol} AgNO_3} \times \frac{143.4\ g}{1\ \text{mol}}[/tex]

= 0.552 g AgCl

Thus from the above conclusion we can say that If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

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Answer:

C.) H₂O and K₂SO₄

Explanation:

This appears to be a double-displacement reaction. In these reactions, the cation of one substance is swapped with the cation of another.

So, K⁺ from KOH is swapped with the H⁺ from H₂SO₄. The new compounds should have an overall charge of 0. Therefore, it may be necessary to modify the amount of each ion (not just be 1:1).

K₂SO₄
-----> K⁺ and SO₄²⁻

-----> + 1 + 1 + (-2) = 0

H₂O

-----> H⁺ and OH⁻

-----> + 1 + (-1) = 0

Answer:

door

Explanation:

door I guess..................

Answer:

Fe(CH₂CO₂)₂, Fe₂MnO, Pb(CH₂CO₂)₄, PbMnO

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CH₂CO₂)₂

   ----> Fe²⁺ and 2 CH₂CO₂⁻

   ----> +2 + (-1) + (-1) = 0

2.) Fe₂MnO

   ----> 2 Fe²⁺ and 1 MnO⁴⁻
   ----> 2(+2) + (-4) = 0

3.) Pb(CH₂CO₂)₄
   ----> 1 Pb⁴⁺ and 4 CH₂CO₂⁻
   ----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) PbMnO

   ----> 1 Pb⁴⁺ and 1 MnO⁴⁻

   ----> +4 + (-4) = 0

Answer:

45.82 gm O2

Explanation:

From your balanced equation in the first part, you can see that 2 moles propane  need 7 moles O2

Find the number of moles of propane in 18 gm

   mole wt of propane = ~  12 * 3 + 8 *1 = 44 gm/mole

      18 gm /  44 gm/mole  =  9/22 gm/mole  propane

            we need 7/2 of this as O2 moles    7/2 * 9/22 = 1.432moles of O2

 O2   mole weight =~ 32

       1.432 moles * 32 gm/mole = 45.82 gm O2

Answer:

1) a) 1.81  × 10²³ molecules (b) 1.93  × 10²³ molecules (c) 0.66× 10²³ molecules

2) a) 0.45× 10²³ions  (b) 0.84× 10²³ions (c) 3.6 × 10²³ions

Explanation:

1) Number of molecules:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

a) 16g of H₂CO₃

Number of moles = mass/ molar mass

Number of moles = 16 g/ 62.03 g/mol

Number of moles = 0.3 mol

1 mol = 6.022 × 10²³ molecules

0.3 mol ×  6.022 × 10²³ molecules /1 mol

1.81  × 10²³ molecules

b) 20g of HNO₃

Number of moles = mass/ molar mass

Number of moles = 20 g/ 63.01 g/mol

Number of moles = 0.32 mol

1 mol = 6.022 × 10²³ molecules

0.32 mol ×  6.022 × 10²³ molecules /1 mol

1.93  × 10²³ molecules

c) 30g of C₆H₁₂O₆

Number of moles = mass/ molar mass

Number of moles = 20 g/ 180.156 g/mol

Number of moles = 0.11 mol

1 mol = 6.022 × 10²³ molecules

0.11 mol ×  6.022 × 10²³ molecules /1 mol

0.66× 10²³ molecules

2. Calculate the number of ions in the following compounds:

a) 10g of AlCl₃

Number of moles = mass/ molar mass

Number of moles = 10g/ 133.34 g/mol

Number of moles = 0.075 mol

1 mol = 6.022 × 10²³ ions

0.075 mol ×  6.022 × 10²³ ions/1 mol

0.45× 10²³ions

b) 30g of BaCl₂

Number of moles = mass/ molar mass

Number of moles = 30g/ 208.23 g/mol

Number of moles = 0.14 mol

1 mol = 6.022 × 10²³ ions

0.14 mol ×  6.022 × 10²³ ions/1 mol

0.84× 10²³ions

c) 58 g of H2SO4

Number of moles = mass/ molar mass

Number of moles = 58g/ 98.079 g/mol

Number of moles = 0.59 mol

1 mol = 6.022 × 10²³ ions

0.59 mol ×  6.022 × 10²³ ions/1 mol

3.6 × 10²³ions

Explanation:

On oxidation of aldehydes produces carboxylic acid functional group.

The product of oxidation of aldehydes depends upon whether the reaction occur in acidic medium or alkaline condition.

If oxidation of aldehydes occurs under acidic condition the product is carboxylic acid but if oxidation of aldehydes occurs under alkaline condition then reduce as well as oxidized product obtained which is known as disproportional product.

The  oxidation of aldehydes occur through potassium dichromate, potassium permanganate or many more. The oxidation of aldehydes in the presence of base is known as cannizzaro's reaction.

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Answer:

Sucrose to is the substrate of the reaction because is a simple sugar( disaccharide) which produce glucose and fructose in the presence of sucrase or when it is hydrolysed.

Answer:During an acid-base titration, an acid with a known concentration  is slowly added to a base with an unknown concentration (or vice versa). A few drops of indicator solution are added to the base. The indicator will signal, by color change, when the base has been neutralizedExplanation:

The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.

Charles's law states that, "When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion".

According to the given information:

V ∝ T

V/T = K

Where,

V is the volume of the gas,

T is the temperature of the gas (measured in kelvins), and

K is a non-zero constant.

In two different states, an initial state 1 and a final state 2, the equation is,

[tex]\frac{V 1}{T 1}=\frac{V 2}{T 2}[/tex]

Given data:

V1 = 11.2L

V2 = 13.3L

T2 = 55°C = 328K

By substituting the given data,

[tex]\begin{aligned}&\frac{11.2}{T 1}=\frac{13.3 L}{328 K} \\&T 1=\frac{11.2 L / 328 K}{13.3 L}\end{aligned}[/tex]

∴T1 = 276K = 3°C

The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.

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Based on the type of experiment that is being conducted:

This is the term that is used to refer to the variable that is used to arrive at conclusions about the dependent variable.

The experiment is trying to tell us that the temperature of a material is the function of the heat applied to it and the type of material.

This is the term that is used to refer to the variable of interest. It is what is being tested in the experiment.

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The iron atoms in the prosthetic groups of the electron transport chain proteins can easily accept and release electrons

A helper molecule, or prosthetic group, is a nonproteinaceous substance that aids in the activity of an enzyme. A particular type of cofactor molecule, or organic molecule, known as a coenzyme, aids enzymes in catalyzing chemical reactions.

a prosthetic group made comprised of a protoporphyrin ring and an iron (Fe) atom in the middle. Four pyrrole rings joined by methene bridges form a protoporphyrin ring.

Through their involvement in cellular respiration and fatty acid production, prosthetic groups support cellular activity. Holoproteins are the name for prosthetic groups that are attached to proteins. Prosthetic groups include, among others, heme, biotin, flavin, iron sulfides, copper, and ubiquinone.

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Answer:

electrical conduction

Explanation:

The freezing point of a solution is -1.16°C

Calculation,

The equation which give relation between freezing point depletion and molality is,

Δ[tex]T_{f} = K_{f} .m[/tex]      ... (i)

Moles of the solute = 22.0 g / 114.23 g/mole = 0.193 mole

Mass of the solvent in g = 148 g

Mass of the solvent in kg = 0.148 kg

Molality = 0.193 mole/ 0.148 kg = 1.3 m

Now, after putting the value of  [tex]K_{f}[/tex] and m in equation (i) we get

Δ[tex]T_{f} = K_{f} .m[/tex]  

Δ[tex]T_{f}[/tex]= 5.12°C/m×1.3 m = 6.66°C

Δ[tex]T_{f}[/tex]=  [tex]T_{f}[/tex] (solvent) - [tex]T_{f}[/tex] (solution)

[tex]T_{f}[/tex] (solution) = [tex]T_{f}[/tex] (solvent)  -Δ[tex]T_{f}[/tex]= 5.5 °C - 6.66°C = -1.16°C

The freezing point of a is -1.16°C

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Answer:

particles in liquids have greater kinetic energy than particles in solids