The number, N, of napkins used in a restaurant is N =f(C) = 2C, where C is the number of customers.
What is the dependent variable? The independent variable?

Answer:

Negative of 5 exists

It continues in the left part of a number line...

Hence the answer is false it does exist

Remove the parentheses and combine the like terms:

7 - -9 = 7+ 9 = 16

6i - -8i = 6i +8i = 14i

The answer is 16 + 14i

This question is incomplete, the complete question is;

A rocket is launched straight into the air with initial velocity 200 ft/s. Assume the launch is instantaneous. How high will it go, and how long will that take (use time increments of 0.01 seconds)? G= - 32.2 ft/s² , H₀=0 (the ground)

V(t)=V₀ + g t

H(t)= H₀ + V₀ t + ½ g t²

The rocket deploys a parachute after 9 seconds and descends at a constant rate of 20 ft/sec. How long does it take to reach the ground

Answer:

a) maximum height S is 621.12 ft and time taken to reach it is 6.21 sec.

b) The rocket deploys a parachute after 9 seconds and descends at a constant rate of 20 ft/sec,

Time taken to travel t = 24.79 sec

NOW total time taken = 27.55 sec

Step-by-step explanation:

Given that,

initial velocity u = 200 ft/s

acceleration a = 32.2 ft/s²

vertical displacement ( maximum height) S = ?

final velocity at highest point Ц = 0

NOW from the equation of motion

v² - u² = 2as

we substitute

0² - (200)² = 2 (-32.2) × s

s = 621.12 ft

time taken t = (v -u)/a = (0-200)/-32.2

t = (-200) / (-32.2)

t = 6.21 sec

distance traveled by rocket from t=6.21sec to t=9sec

Δt = (9-6.21) = 2.79sec

s = ut + 1/2at²

s = 0 + 1/2(32.2)(2.79)² = 125.32 ft

Remaining distance = 621.12 ft - 125.32 ft = 495.8 ft

Time taken to travel = t = s/v = (495.5ft) / (20 ft/sec)

t = 24.79 sec

NOW total time taken = 2.79sec + 24.79sec = 27.55 sec

Ans

8 option b.

Step-by-step explanation:

3+4/2+3

=3+2+3

=5+3

=8

Answer:

PQ = 2

Step-by-step explanation:

We know that OQ = OP + PQ. Since OQ = 16 and OP = 14, we know that 16 = 14 + PQ, therefore, PQ = 2.

Answer:

Step-by-step explanation:

x- intercept, vertex (v) and axis of symmetry, parabola form:x²+bx+c

vertex(h,k)

f(x)=x²-9  a=1,b=0 ,c=-9

h=-b/2a=0

k=f(0)=-9

vertex(0,-9) , x intercept is when f(x)=0

(x-3)(x+3)=0 either x-3=0⇒ x=3 or x+3=0 then x=-3

x=3, x=-3 (-3,0) and (3,0)

the x of symmetry is the h of the vertex=0

g(x)=x²-2x-3 a=1, b=-2,c=-3

h=-b/2a⇒-(-2)/2(1)⇒h=1

k=f(1)=1²-2(1)-3⇒k=-4

v(1,-4)

x of symmetry=h=1

(x+1)(x-3)=0

x+1=0⇒x=-1 (-1,0)

x-3=0 ⇒x=3  (3,0)

x intercept :-1,3

vertex(-3,9)

x intercept:(0,0) and (-6,0)

axis of symmetry =-3

vertex(3,-8)

axis of symmetry=3

x intercept : (5,0), (1,0)

vertex(-1/2,1)

x of symmetry=-1/2

x intercept : (0,0)(-1,0)

vertex(3,0)

x intercept (3,0)

axis of symmetry = 3

Answer:

1079

Step-by-step explanation:

Hello,

18-5 = 13

31-18=13

44-31=13

161=5+13*12

So we need to compute

[tex]\displaystyle \sum_{k=0}^{k=12} \ {(5+13k)}\\\\=\sum_{k=0}^{k=12} \ {(5)} + 13\sum_{k=1}^{k=12} \ {(k)}\\\\=13*5+13*\dfrac{12*13}{2}\\\\=65+13*13*6\\\\=65+1014\\\\=1079[/tex]

Thanks

The required sum of the arithmetic series 5+18 +31 +44 + ... 161 is 1079.

Given that,
Arithmetic series: 5+18 +31 +44 + ... 161.

The Sum of the series is to be determined.

Arithmetic progression is the series of numbers that have common differences between adjacent values

Here,
From the given series
First term A = 5, Common difference D = 13 and last term L = 161
Last term = An + (n -1)
161 = 5 + (n - 1)13
n - 1 = (161 - 5) / 13
n = 12 + 1
n = 13

Now the sum of an arithmetic series,
S = n /2 (A + L)
S = 13 / 2 (5 + 161)
S = 13 / 2 * 166
S = 13 * 83
S = 1079

Thus, the required sum of the arithmetic series 5+18 +31 +44 + ... 161 is 1079.

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Answer:

z^4-z²-20

Step-by-step explanation:

( z^2 + 4 ) ( z^2 – 5)

z^4+4z²-5z²-20

z^4-z²-20

Answer:

2513.3

Step-by-step explanation:

cylinder volume = π[tex]r^{2}[/tex]h

cylinder volume = π [tex]20^{2}[/tex](2)

cylinder volume = 2513.27

cylinder volume = 2513.3

Answer:

5

Step-by-step explanation:

Answer:

The mean of the sampling distribution  [tex]\mu_{\overline x}[/tex] is 86

The standard deviation of the sampling distribution  [tex]\sigma_x[/tex]  is 2

The mean of the sampling distribution  [tex]\mu_{\overline x}[/tex] is 71

The standard deviation of the sampling distribution  [tex]\sigma_x[/tex]  is 1

B) The distribution is approximately normal.

[tex]\mathbf{P(\overline x >73) = 0.0228}[/tex]

Therefore, the probability that the sample mean is greater than 73 = 0.0228

[tex]\mathbf{P(\overline x \leq 69) = 0.0228}[/tex]

The probability that the sample mean is less than or equal to 69 is 0.0228

[tex]\mathbf{P( 69.8 \leq \overline x \leq 72.5) = 0.8181}[/tex]

Thus, the probability that the sample mean is between 69.8 and 72 is 0.8181.

Step-by-step explanation:

We are to determine the [tex]\mu_{\overline x}[/tex] and [tex]\sigma_x[/tex] from the given parameters of a population and sample size.

Given that :

population mean [tex]\mu[/tex] = 86

population standard deviation [tex]\sigma[/tex] = 16

sample size n = 64

From the central limit theorem's knowledge, we know that as the sample distribution approximates a normal distribution, the sample size gets larger. Thus, the mean of the sampling distribution [tex]\mu_{\overline x}[/tex]  is equal to the population mean [tex]\mu[/tex]

∴

[tex]\mu_{\overline x}[/tex]  = [tex]\mu[/tex] = 86

The standard deviation of the sampling distribution can be computed by using the formula:

[tex]\sigma_{\overline x } = \dfrac{\sigma }{\sqrt{n}}[/tex]

[tex]\sigma_{\overline x } = \dfrac{16 }{\sqrt{64}}[/tex]

[tex]\sigma_{\overline x }= \dfrac{16 }{8}[/tex]

[tex]\mathbf{\sigma_{\overline x } = 2}[/tex]

∴

The mean of the sampling distribution  [tex]\mu_{\overline x}[/tex] is 86

The standard deviation of the sampling distribution  [tex]\sigma_x[/tex]  is 2

Suppose a simple random sample of size n = 36  is obtained from a population with mu = 71 and sigma = 6.

i.e

sample size n = 36

population mean [tex]\mu[/tex] = 71

standard deviation [tex]\sigma[/tex] = 6

From the central limit theorem's knowledge, we know that as the sample distribution approximates a normal distribution, the sample size gets larger. Thus, the mean of the sampling distribution [tex]\mu_{\overline x}[/tex]  is equal to the population mean [tex]\mu[/tex]

∴

[tex]\mu_{\overline x}[/tex]  = [tex]\mu[/tex] = 71

The standard deviation of this sampling distribution [tex]\sigma_{\overline x}[/tex] can be estimated as :

[tex]\sigma_{\overline x }= \dfrac{\sigma }{\sqrt{n}}[/tex]

[tex]\sigma_{\overline x }= \dfrac{6 }{\sqrt{36}}[/tex]

[tex]\sigma_{\overline x } = \dfrac{6 }{6}[/tex]

[tex]\mathbf{\sigma_{\overline x } = 1}[/tex]

∴

The mean of the sampling distribution  [tex]\mu_{\overline x}[/tex] is 71

The standard deviation of the sampling distribution  [tex]\sigma_x[/tex]  is 1

A)

The correct option from the  given question is:

B) The distribution is approximately normal.

B) What is P (xbar > 73)?

i.e

[tex]P(\overline x >73) = P \begin {pmatrix} \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{73 -71 }{\dfrac{6}{\sqrt{36}}} \end {pmatrix}[/tex]

[tex]P(\overline x >73) = P \begin {pmatrix} Z > \dfrac{73 -71 }{\dfrac{6}{\sqrt{36}}} \end {pmatrix}[/tex]

[tex]P(\overline x >73) = P \begin {pmatrix} Z > \dfrac{2 }{\dfrac{6}{6}} \end {pmatrix}[/tex]

[tex]P(\overline x >73) = P \begin {pmatrix} Z > \dfrac{2 \times 6 }{6} \end {pmatrix}[/tex]

[tex]P(\overline x >73) = P \begin {pmatrix} Z > \dfrac{12 }{6} \end {pmatrix}[/tex]

[tex]P(\overline x >73) = P \begin {pmatrix} Z > 2 \end {pmatrix}[/tex]

[tex]P(\overline x >73) = 1- P \begin {pmatrix} Z < 2 \end {pmatrix}[/tex]

Using the Excel Function ( =NORMDIST(2) )

[tex]P(\overline x >73) = 1- 0.9772[/tex]

[tex]\mathbf{P(\overline x >73) = 0.0228}[/tex]

Therefore, the probability that the sample mean is greater than 73 = 0.0228

C) What is P (xbar ≤ 69)?

i.e

[tex]P(\overline x \leq 69) = P \begin {pmatrix} \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{69 -71 }{\dfrac{6}{\sqrt{36}}} \end {pmatrix}[/tex]

[tex]P(\overline x \leq 69) = P \begin {pmatrix}Z \leq \dfrac{-2 }{\dfrac{6}{6}} \end {pmatrix}[/tex]

[tex]P(\overline x \leq 69) = P \begin {pmatrix} Z \leq \dfrac{-2 \times 6 }{6} \end {pmatrix}[/tex]

[tex]P(\overline x \leq 69) = P \begin {pmatrix} Z \leq \dfrac{-12 }{6} \end {pmatrix}[/tex]

[tex]P(\overline x \leq 69) = P \begin {pmatrix} Z \leq -2 \end {pmatrix}[/tex]

Using the EXCEL FUNCTION ( = NORMSDIST (-2) )

[tex]\mathbf{P(\overline x \leq 69) = 0.0228}[/tex]

The probability that the sample mean is less than or equal to 69 is 0.0228

NOTE: This text editor can't contain more than 5000 characters so the last part of the question is attached in the image below.

Answer:

-4 1/2

Step-by-step explanation:

1/3(-15+3/2)

1/3(-13 1/2)

1/3(-27/2)

-27/6

-4 3/6

-4 1/2

Answer:

X = -1

Y = 1

Step-by-step explanation:

The solution of the equations x = 6y - 7 and 4x + y = -3 will be (-1, 1).

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

The linear equation is given below.

x = 6y - 7           ...1

4x + y = - 3       ...2

Simplify the equation, then we have

4(6y - 7) + y = -3

24y - 28 + y = - 3

25y = 25

y = 1

The value of the variable 'x' will be calculated as,

x = 6(1) - 7

x = 6 - 7

x = - 1

The solution of the equations x = 6y - 7 and 4x + y = -3 will be (-1, 1).

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Do parentheses first:

6 +4-2 = 8

Now do brackets:

128/8 = 16

Now multiply:

16 x 8 = 128

The answer is 128

Answer:

first answer

Step-by-step explanation:

Hello, you know that

[tex]\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\cdot \dfrac{d}{c}[/tex]

So, the quotient we need to estimate is

[tex]\begin{aligned}\dfrac{x^2-36}{x+8}\cdot\dfrac{4x+32}{x^2+12x+36}&=\dfrac{x^2-6^2}{x+8}\cdot \dfrac{4(x+8)}{(x+6)^2}\\\\&=\dfrac{4(x-6)(x+6)}{(x+6)^2}\\\\&=\dfrac{4(x-6)}{x+6}\end{aligned}[/tex]

Thank you

Answer:

Sarah answered 7 multiple choice questions and 3 free response questions correctly.

Step-by-step explanation:

Given that: she has 36 points.

                   3 points each for the multiple choice question (MCQ)

                   5 points each for the free response question (FRQ)

To determine how many of each question was answered correctly. Let the number of MCQ she answered be represented by x and FRQ by y.

  3x + 5y = 36   ............ 1

Since she answered a total of 10 question, then;

  x + y = 10

 x = 10 - y  ................  2

Substitute equation 2 into 1,

3(10 - y) + 5y = 36

30 - 3y + 5y = 36

2y = 6

y = 3

Substitute the value of y in equation 2,

x = 10 - y

  = 10 - 3

  = 7

x = 7, y = 3

Therefore, Sarah answered 7 multiple choice questions and 3 free response questions.

Answer:

natural numbers - positive integers (whole numbers)

• 1

• 2

• 3

• 4

• 5

whole numbers - a number without fractions

• 10

• 11

• 12

• 13

• 14

rational numbers - a number that can be expressed as the ratio of two integers

• 1/3 or 0.3333...

• 17

• -34

• 25

• -10

integers - a whole number; a value that is not a fraction

• -5

• 49

• 68

• 439

• 35

8^15 ÷ 1/8^3 = 8^15 x 8^3=8^18

1.8014399e+16

Step-by-step explanation:

So before you can divide the numbers you have to simplify the exponents. You probably learned P(parentheses) E(exponents) M(multiply) D(divide) A(add) S(subtract.

25.36+5.09+11.45= 41.9$ intotal

Answer:

41,9

Step-by-step explanation:

25.36+5.09+11.45

Answer:

4×(x+8)=25.

use the 4 to multiply the numbers in the bracket.

which is 4x+32=25.

then collect like terms which is...

4x=25-32...

4x=-7.

x=-7/4= -1.75 or -1 whole number 3/4.

Answer:

60in^2

Step-by-step explanation:

Area of a triangle = Height x Base X 1/2

Base = 10

Other 2 sides = 13

Now, let's split the Base into 2 parts.

=> 1 part = 5 and 2 part = 5

We can find the height using Pythagorean theorem

=> Isosceles triangle

=> (1 part of the base)^2 + Height^2 = The Hypotenuse^2  = the longer side of a triangle = 13^2

=> 5^2 + Height ^2 = 13^2

=> 25 + Height^2 = 169

=> 25 - 25 + Height ^2 = 169 - 25

=> Height^2 = 144

=> Height = Square root of 144

=> Height = 12

Area = 12 x 10 x 1/2

=> 12 x 5

=> 60 in^2

So, the Area is 60 in ^2

Answer:

13 hours

Step-by-step explanation:

8:00 plus 4 is twelve ( 12 o'clock )

then you have 9hrs left.

( 4+9=13 )

Answer:

10/25

Step-by-step explanation:

2/5 = x/25

We need to multiply the bottom by 5 to get to 25

5*5 = 25

What we to the bottom, we do the the top

2/5 * 5/5 = 10/25

Answer:

10/25

Step-by-step explanation:

2/5 = x/25

cross multiply

2 • 25 = 50

5 • x = 5x

set equal to each other

5x = 50

divide both sides by 5

x = 10

Answer:

-0.66666666666

Step-by-step explanation:

1/3-5/5

Answer:

Here is your solution-

x³ times x⁷

means, x³×x⁷

Here you just have to add the powers as aⁿ×aᵐ=aⁿ⁺ᵐ

x³⁺⁷

x¹⁰

Answer:

-8/4-21x

Step-by-step explanation:

Distribute inside the parantheses

Divide -8 and 4

Add the two terms

Simplify

Answer:

x=35 hrs

1 hour =105

cross mutiply

105÷35=3

The equation that describes the situation is 35x = 105.

An equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

The equations are useful in the determination of unknown parameters.

The equations are of various types, such as Trigonometric equations, and quadratic equations.

William drove 35 miles per hour for a total of 105 miles.

The total miles William drove is 105 miles.

The speed at which he drove is 35 miles/ hour.

The total time he drove is given by x hours.

The equation has to be formed for this situation.

Speed is defined as the distance traveled with respect to time.

35 = 105 / x

35x = 105

This equation describes the given situation.

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Answer:

600/11

Step-by-step explanation:

scoops of

strawberry= x

chocolate= y

vanilla ice cream= z

X+y+z= 100

The snack bar sold 3 times as many scoops of chocolate as it did strawberry

3x= y

X= y/3

and 2 times as many scoops of

vanilla as it did chocolate

2z= y

Z= y/2

X+y+z= 100

Y/3 + y +y/2 = 100

2y + 6y + 3y = 600

11y= 600

Y= 600/11