Answer: Resolution
Explanation: The total number of pixels that can be displayed on the screen at a time is called the resolution of the screen. This resolution is normally described in the pair of numbers, such as 2560 x 1440. This means, the computer screen is 2560 pixels wide and 1440 pixels tall.
The most common type of monitor for a laptop or desktop is a
Answer:
LCD monitor
explanation
it incorporates one of the most advanced technologies available today.
________models software in terms similar to those that people use to describe real- world objects.
A) Procedural programming
B) Object-oriented programming
C) Object-oriented design
D) None of the above
Answer:
The correct answer is C - Object-oriented design.
Explanation:
Object-oriented design defines code or software as objects. These objects represent instances of a real-life situation. For example, an animal class consist of a dog, cat, lion. A dog therefore is n instance of the animal class.
Objects are described as having properties and behaviours. Properties are variables, arrays, sets, maps etc and behaviours are the functions and methods that manipulate these data.
Object-oriented programming is done based on this design.
To move a file or folder in Microsoft Windows you can click and hold down the left mouse button while moving your mouse pointer to the location you want the file or folder to be, which is also known as
Answer:
**UNSURE** Cutting and pasting*
Explanation:
Its essentially the same thing. Nowadays File Explorer will instead copy the file to the new location in certain circumstances, such as if the destination is a separate drive.
*I'm not sure if this is the type of answer you are looking for, as I'm not sure what context this is in. If you're looking for a specific term regarding that type of action in the user interface, this might not be it.
Which one of the following statements is false? A. As storage is now cheap and plentiful, modern code management systems are less concerned with optimizing storage. B. Sub-version is the best-known, open-source code management product that is based around a centralized repository. C. In the open-source software development model, many different people can work independently on the code without any knowledge of what others are doing. D. The oldest and perhaps best-known system building tool is "Ant", which was originally developed in the 1970s for Unix.
Answer:
D. The oldest and perhaps best-known system building tool is "Ant", which was originally developed in the 1970s for Unix.
Explanation:
Ant often referred to Apache Ant is a computer software tool, though popularly considered oldest, was originally first built in the year 2000 by Unix, on Java platform, which is utilized as a component of plug-in development.
Hence, given the available options, the correct answer is Option D, because, Ant originally built in the year 2000 and not the year 1970, while the other statements are definitely correct.
Which of the following would not be considered metadata for a spreadsheet file?
A) Read-only attributeB) Calculation inside the fileC) Name of the fileD) Full size
Answer:
B.
Explanation:
Metadata is a type of data that dispense details of other data. In simple terms, metadata can be defined as information of a file such as file name, attributes, etc.
In excel sheet, metadata works the same and helps to provide information about file name, author name, file size, attributes such as read-only, archieve, hidden, system, location of the file, date and time of creation, modification, or accessed, type of file, etc.
From the given options, the information that is not considered or included in metadata is calculation inside the file. Metadata in excel sheet does not include calculations inside the file. Thus option B is the correct answer
select the correct answers. What are examples of real-time applications?
My answer to the question are:online money transfer,news update,blog post.
Data_____is defined as the condition in which all of the data in the database are consistent with the real-world events and conditions.
a. ubiquity.
b. quality.
c. anomaly.
d. integrity.
Answer:
d. integrity
Explanation:
Data integrity is defined as the condition in which all of the data in the database are consistent with the real-world events and conditions.
Data integrity can be used to describe a state, a process or a function – and is often used as a proxy for “data quality”. Data with “integrity” is said to have a complete or whole structure. Data integrity is imposed within a database when it is designed and is authenticated through the ongoing use of error checking and validation routines. As a simple example, to maintain data integrity numeric columns/cells should not accept alphabetic data.
What are video games and what have they meant for society?
video games are a source of entertainment for people especially children.
it helps relieve stress for adults or grown ups.
society sees video games as a negative impact on children and that it wastes their time.
Answer:
video games are games played for fun and enjoyment they are types of video games we have shooting video games, football video games, sport video games and so much more. video games are for fun and not all video games are meant for society. video games like football should be meant for sociey ehere everyone can come together to play games like these bring people and society together.
Create a File: Demonstrate your ability to utilize a Linux command to create a text file. Create this file in the workspace directory: in. A text file showing the current month, day, and time (Title thisfile Time_File.txt.) II. Create a Directory: In this section of your project, you will demonstrate your ability to execute Linux commands to organize the Linux directory structure. a. In the workspace directory, create a new directory titledCOPY. III. Modify and Copy: Demonstrate your ability to utilize Linux commands to copy a file to a different directory and renameit. a. Copy the Time_File.txt file from the workspace directory to the COPYdirectory. b. Append the word COPY to the filename. IV. Execute the Script: Complete and execute the newly created script.
Answer: Provided in the explanation section
Explanation:
#So we Create a workspace directory
mkdir workspace
#let us browse inside the workspace
cd workspace/
#creating a Time_File.txt file
touch Time_File.txt
#confirming creation of Time_File.txt
ls
# Time_File.txt
#writing in the month day and time to Time_File.txt
date +%A%B%R >> Time_File.txt
#Let us confirm the content of Time_File.txt as month day and time
cat Time_File.txt
# ThursdayJune19:37
#making a COPY directory
mkdir COPY
#verifying creation of COPY
ls
# COPY Time_File.txt
# copying Time_File.txt to COPY
cp Time_File.txt COPY/
#check the inside COPY
cd COPY/
#verifying copying of Time_File.txt to COPY
ls
# Time_File.txt
#appending COPY to Time_File.txt name
mv Time_File.txt COPYTime_File.txt
#confirming append
ls
# COPYTime_File.txt
# Creating a NewScript.sh
touch NewScript.sh
# cocnfirming the function
ls
# COPYTime_File.txt NewScript.sh
# adding executable permission
chmod +x NewScript.sh
ls
COPYTime_File.txt NewScript.sh
# Running NewScript.sh
./NewScript.sh
# Time_File.txt
# ThursdayJune19:49
# COPY Time_File.txt
# Time_File.txt
# COPYTime_File.txt
# we repeat same as seen above using script
ls
# COPYTime_File.txt NewScript.sh workspace
Write a recursive definition of x^n, where n≥0, similar to the recursive definition of the Fibonacci numbers. How does the recursion terminate?
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
int recurs(int x, int n)//defining a method recurs that accepts two parameter
{
if(n==0)//defining if block that checks n value
{
return 1;//return value 1
}
else//defining else block
{
return x*recurs(x,n-1);//use return keyword that retun value
}
}
int main()//defining main method
{
cout<<recurs(5,3); //use print method to call recurs method
return 0;
}
Output:
125
Explanation:
In the above-given program, the integer method "recurs" is declared which accepts, two integer variables, which are "x, n", inside the method the if conditional statement is used.
In the if block, it checks the value of n is equal to "0" if this condition is true, it will return a value, that is 1. Otherwise, it will go to the else block, in this block, it will use the recursive method to print its value.Recursions are functions that execute itself from within.
The recursive definition x^n in Python, where comments are used to explain each line is as follows:
#This defines the function
def recursion(x, n):
#This returns 1, if n is 0
if(n==0):
return 1
#This calculates the power recursively, if otherwise
else:
return x*recursion(x,n-1);
The function terminates when the value of n is subtracted till 0
Read more about recursions at:
https://brainly.in/question/634885
the content of a text is its
Text content informs, describes, explains concepts and procedures to our readers
In order to place a gradient within a stroked path for type, one must convert the type using the __________
Answer:
in order to place a gradient within a stroked path for type ,one must convert the type 17316731
What AI technology is commonly used to describe Input A to Output B mappings?
Answer:
Supervised learning
Explanation:
Supervised learning is a term widely used in computer engineering that describes a form of the machine learning process, which is based on understanding a task that maps an input to an output based on illustration input A to output B pairs.
Hence, in this case, AI technology that is commonly used to describe Input A to Output B mappings is called SUPERVISED LEARNING
Which of these file types does not share info in a spreadsheet?
A) CSV
B) Excel
C) PNG
D) all have
Answer:
C) PNG
Explanation:
PNG which is an acronym for Portable Network Graphics is a form of images file format and it does not share info in a spreadsheet. The files that share info on the spreadsheet are the following:
1. Text = .txt
2. Formatted Text = .prn
3. CSV = .csv
4. Data Interchange Format = .dif
5. Symbolic Link = .slk
6. Web page = .html, .htm
7. XML Spreadsheet = .xml
Hence, in this case, the file types that do not share info in a spreadsheet is PNG
PNG does not share info in a spreadsheet
Comma-separated values (CSV) file is a text file that stores data in lines. Each record is separated by commas and is made up of fields. CSV can store data in tabular forms like spreadsheet or database.
Excel files use a Binary Interchange File Format that store data like numbers, formula and spreadsheet data.
Portable Graphics Format (PNG) is a file format that is used to store images. It does not share info in spreadsheet.
Find about more at: https://brainly.com/question/17351238
Which of the following is an example of self-directed learning?
Answer:
Self directed learning is an the strategy the students guidance from that teacher decide and students they will learn.
Explanation:
Self directed learning its a effective technique that can anyone to use the learning in a school time into a curriculum program, there are many type of characteristics:- (1) Flexibility (2) Autonomy (3) Self acceptance (4) Playfulness.
Self directed learning is to perform that allow us to the initiative own learning, students grow and improve the motivation and integrity to the learning.Self directed learning to that contain the self learning with the internet program, and apply to the skill outside of the area learning.Self directed learning to the set of goal that the business and career and the achieve of the goal.Self directed learning to contain your interests and motivate yourself and reflecting the learners.Self directed learning is to provide learn strategies and methods to achieve the better lives and behavior can translate.Self directed is the value to the teamwork and help the students and learner work in better team.Self learning is perform physical side learning and the focus on the mental side, and they we are putting in heads.Self learning is to contain the better your learning standards and to measure learning goals.Answer:
B
I got it on edge
The system board contains the logic circuitry that performs the instructions of a computer's applications.a. Trueb. False
Answer:
TRUE
Explanation:
As computer programs can be complex and difficult to write, they, A Web browser is an example of applications software. process, as well as programs, or instructions specifying the steps necessary to complete.
The statement "The system board contains the logic circuitry that performs the instructions of a computer's applications" is true.
What is a logical symbol?In Boolean algebra, the conjunction between two propositions is denoted by the logical AND symbol.
It is given that:
The statement is:
The system board contains the logic circuitry that performs the instructions of a computer's applications.
As we know,
An idealized or actual device called a logic gate implements a Boolean function, which is a logical operation on one or more binary inputs that results in a single binary output.
Because writing computer programs can be challenging and complex, An illustration of applications software is a web browser. programs or instructions that outline the steps required to perform a process
Thus, the statement "The system board contains the logic circuitry that performs the instructions of a computer's applications" is true.
Learn more about the logical symbol here:
brainly.com/question/11359207
#SPJ2
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
Answer:
Here is the JAVA program:
import java.util.Scanner; //to take input from user
public class Main{
public static void main(String[] args) { //start of main function
Scanner input = new Scanner(System.in); // creates Scanner class object
int num, integer, odd = 0, even = 0; //declare variables
System.out.print("Enter the number of integers: "); //prompts user to enter number of integers
num = input.nextInt(); //reads value of num from user
System.out.print("Enter the integers:\n"); //prompts user to enter the integers
for (int i = 0; i < num; i++) { //iterates through each input integer
integer = input.nextInt(); // reads each integer value
if (integer % 2 == 0) //if integer value is completely divisible by 2
even += integer; //adds even integers
else //if integer value is not completely divisible by 2
odd += integer; } //adds odd integers
System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers
System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers
}}
Explanation:
The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.
Suppose user wants to input 5 integers. So,
num = 5
Suppose the input integers are:
1, 2 , 3, 4, 5
for (int i = 0; i < num; i++) is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.
At first iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 1
if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:
odd += integer; this becomes:
odd = odd + integer
odd = 1
Now the value of i is incremented to 1 so i=1
At second iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 2
if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So
even += integer; this becomes:
even= even+ integer
even = 2
Now the value of i is incremented to 1 so i=2
At third iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 3
if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So
odd += integer; this becomes:
odd= odd + integer
odd= 1 + 3
odd = 4
Now the value of i is incremented to 1 so i=3
At fourth iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 4
if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So
even+= integer; this becomes:
even = even + integer
even = 2 + 4
even = 6
Now the value of i is incremented to 1 so i=4
At fifth iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 5
if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So
odd+= integer; this becomes:
odd= odd+ integer
odd= 4 + 5
odd = 9
Now the value of i is incremented to 1 so i=5
When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So
even = 6
odd = 9
Hence the output is:
Sum of Even Numbers: 6 Sum of Odd Numbers: 9
Today, trending current events are often present on websites. Which of the following early developments in audiovisual technology is most closely related to this?
Answer: Newsreels
Explanation:
Options not included however with the early audio visual technologies known, the Newsreel is the closest when it comes to displaying news and current events.
Like the name suggests, Newsreels showed news and they did this of events around the world. They were short films that captured events and then displayed them in cinemas and any other viewing locations capable of showing them.
By this means, people were able to keep up to date with events around the world without having to read newspapers. The advent of news channels killed this industry and logically so.
Answer:
B: Newsreels
Explanation:
edg2021
The text states, "...newsreels began to gain popularity. They were short movies about current events around the world, usually shown prior to the main feature in movie theaters"
Write a GUI program that calculates the average of what an employee earns in tips per hour. The program’s window should have Entry (font: Courier New) widgets that let the user enter the number of hours they worked and amount they earned in tips during they time. When a Calculate button is clicked, the program should display the average amount they got paid in tips per hour. Use the following formula: Tips per hour = amount of tips in dollars / hours.
Answer:
Explanation:
Using Code:
from tkinter import *
#object of Tk class to make GUI
root = Tk()
#creating a canvas to put labels, entries and button
canvas1 = Canvas(root, width = 300, tallness = 200)
canvas1.pack()
#label for number of hours worked
label1 = Label(root, text = "Hours : ", textual style = ('Courier', 10))
canvas1.create_window(80, 50, window = label1)
#entry for number of hours worked
entry1 = Entry(root, textual style = ('Courier', 10))
canvas1.create_window(200, 50, window = entry1)
#label for sum they earned in tips
label2 = Label(root, text = "Tips : ", textual style = ('Courier', 10))
canvas1.create_window(80, 80, window = label2)
#entry for sum they earned in tips
entry2 = Entry(root, text style = ('Courier', 10))
canvas1.create_window(200, 80, window = entry2)
#label for tips every hour
label3 = Label(root, text = "Tips Per Hour : ", textual style = ('Courier', 10))
canvas1.create_window(80, 150, window = label3)
#function to figure tips every hour
def TipsPerHour():
#getting estimation of hour
hours = int(entry1.get())
#getting estimation of tips
tips = int(entry2.get())
#calculating normal sum got paid in tips every hour
normal = tips/hours
#creating a name to show normal
label4 = Label(root, text = "$" + str(average), textual style = ('Courier', 10))
canvas1.create_window(170, 150, window = label4)
#button for compute
calculateButton = Button(root, text = "Compute", textual style = ('Courier', 10), order = TipsPerHour)
canvas1.create_window(170, 110, window = calculateButton)
#mainloop
root.mainloop()
Write a simple command-line calculator with an exception handler that deals with nonnumeric operands. Your program should display a message that informs the user of the wrong operand type before exiting. It should also ask the user to re-input the number to finish the calculation.
Answer:
Here is the JAVA program:
import java.util.InputMismatchException; // exception that is thrown when input does not match the expected type
import java.util.Scanner; //used to take input from user
public class Main {
public static void main(String[] args) { //start of main function
Scanner input = new Scanner(System.in); // creates Scanner class object
double num1=0.0; // double type operand 1
double num2=0.0; // double type operand 2
System.out.println("Please enter 2 operands"); //prompts user to enter two operands
try { //defines a chunk of code to be tested for non numeric operand error
num1 = input.nextDouble(); //reads operand 1 value
num2 = input.nextDouble(); //reads operand 2 value
} catch (InputMismatchException ex) { //code chunk executed when exception occurs in program
System.out.println("wrong operand type, re-input " + input.next() + " to finish the calculation."); //displays wrong operand type if user enters non numeric operands
System.exit(1); }//exits the program
System.out.print("Enter an operator (+, -, *, /): "); //prompts user to enter an operator
char operator = input.next().charAt(0); //reads the input operator
double result; // to store the result of the operation
switch(operator) { //decided operation on basis of input operator
case '+': // if user enters + operator
result = num1 + num2; //adds two operands
break;
case '-': // if user enters - operator
result = num1 - num2; //subtracts two operands
break;
case '*': // if user enters * operator
result = num1 * num2; //multiplies two operands
break;
case '/': // if user enters / operator
result = num1 / num2; //divided two operands
break;
default: //if user enters wrong operator
System.out.printf("wrong operator!"); //displays wrong operator
return; }
System.out.printf("%.1f %c %.1f = %.1f", num1, operator, num2, result); }} //displays the result of the operation
Explanation:
The program is well explained in the comments mentioned with each line of program. The user is prompted to enter the values of two operands num1 and num2. The try block is used to test for non numeric operand error and throws InputMismatchException when any of the input operands (num1 or num2) is non numeric. InputMismatchException is thrown by Scanner class. This informs that the token retrieved (which is the num1 or num2 operand) does not match the expected type (which is type numeric). When this error occurs in the program, catch block is used to execute a code chunk, which is the print statement in this program. The print statement informs the user of the wrong operand type before exiting. It also asks the user to re-input the number to finish the calculation and the wrong input type is also mentioned in the output that is to be re-input.
If you want the program to take the input again from user after throwing this exception then you can alter the above program by using two try catch blocks separately for the two operands:
//for operand 1 i.e. num1
System.out.println("Please enter operand 1: ");
try {
num1 = input.nextDouble();
} catch (InputMismatchException ex) {
System.out.println("wrong operand type, re-input " + input.next() + " to finish the calculation.");
num1 = input.nextDouble(); } //reads input of operand 1 again from user
//for operand 2 i.e. num2
System.out.println("Please enter operand 2: ");
try {
num2 = input.nextDouble();
} catch (InputMismatchException ex) {
System.out.println("wrong operand type, re-input " + input.next() + " to finish the calculation.");
num2 = input.nextDouble(); } //reads input of operand 1 again from user
The program and its output is attached.
E-mail is the most common distributed application that is widely used across all architectures and vendor platforms.a) trueb) false
Answer:
A. True.
Explanation:
E-mail is an acronym for electronic mail and it can be defined as an exchange or transmission of computer-based data (messages) from one user to another over a communications network system.
Also, a distributed application refers to a software program that is capable of running on several computer systems and can communicate effectively through a network.
E-mail is the most common distributed application that is widely used across all architectures and vendor platforms because it primarily operates on a client-server model, by providing users with the requested services through the Simple Mail Transfer Protocol (SMTP) using the standard port number of 25.
Which item converts a high level language program to low level machine instruction?
What three conditions must be satisfied in order to solve the critical section problem?
Answer:
Explanation:
The critical section problem revolves around trying to ensure that at most one process is executing its critical section at a given time. In order to do so, the three following conditions must be met.
First, no thread may be executing in its critical section if there is already a current thread executing in its critical section.
Second, only the specific threads that are not currently occupied executing in their critical sections are allowed to participate in deciding which process will enter its critical section next.
Third, a preset limit must exist on the number of times that other threads are allowed to enter their critical state after a thread has made a request to enter its critical state.
Write code to complete factorial_str()'s recursive case. Sample output with input: 5 5! = 5 * 4 * 3 * 2 * 1 = 120
Answer:
Here is the complete code to complete factorial_str()'s recursive case:
Just add this line to the recursive part of the code for the solution:
output_string += factorial_str(next_counter,next_value)
The above statement calls factorial_str() method recursively by passing the values of next_counter and next_value. This statement continues to execute and calls the factorial_str() recursively until the base case is reached.
Explanation:
Here is the complete code:
def factorial_str(fact_counter, fact_value): #method to find the factorial
output_string = '' #to store the output (factorial of an input number)
if fact_counter == 0: # base case 1 i.e. 0! = 1
output_string += '1' # displays 1 in the output
elif fact_counter == 1: #base case 2 i.e. 1! = 1
output_string += str(fact_counter) + ' = ' + str(fact_value) #output is 1
else: #recursive case
output_string += str(fact_counter) + ' * ' #adds 8 between each value of fact_counter
next_counter = fact_counter - 1 #decrement value of fact_counter by 1
next_value = next_counter * fact_value #multiplies each value of fact_value by next_counter value to compute the factorial
output_string += factorial_str(next_counter,next_value) #recursive call to factorial_str to compute the factorial of a number
return output_string #returns factorial
user_val = int(input()) #takes input number from user
print('{}! = '.format(user_val),end="") #prints factorial in specified format
print(factorial_str(user_val,user_val)) #calls method by passing user_val to compute the factorial of user_val
I will explain the program logic with the help of an example:
Lets say user_val = 5
This is passed to the method factorial_str()
factorial_str(fact_counter, fact_value) becomes:
factorial_str(5, 5):
factorial_str() method has two base conditions which do not hold because the fact_counter is 5 here which is neither 1 nor 0 so the program control moves to the recursive part.
output_string += str(fact_counter) + ' * ' adds an asterisk after the value of fact_counter i.e. 5 as:
5 *
next_counter = fact_counter - 1 statement decrements the value of fact_counter by 1 and stores that value in next_counter. So
next_counter = 5 - 1
next_counter = 4
next_value = next_counter * fact_value multiplies the value of next_counter by fact_value and stores result in next_value. So
next_value = 4 * 5
next_value = 20
output_string += factorial_str(next_counter,next_value) this statement calls the factorial_str() to perform the above steps again until the base condition is reached. This statement becomes:
output_string = output_string + factorial_str(next_counter,next_value)
output_string = 5 * 4 = 20
output_string = 20
Now factorial_str(next_counter,next_value) becomes:
factorial_str(4,20)
output_string += str(fact_counter) + ' * ' becomes
5 * 4 * 3
next_counter = fact_counter - 1 becomes:
4 - 1 = 3
next_counter = 3
next_value = next_counter * fact_value becomes:
3 * 20 = 60
next_value = 60
output_string = 5 * 4 * 3= 60
output_string = 60
factorial_str(next_counter,next_value) becomes:
factorial_str(3,60)
output_string += str(fact_counter) + ' * ' becomes
5 * 4 * 3 * 2
next_counter = fact_counter - 1 becomes:
3 - 1 = 2
next_counter = 2
next_value = next_counter * fact_value becomes:
2 * 60 = 120
next_value = 120
output_string += factorial_str(next_counter,next_value) becomes:
output_string = 120 + factorial_str(next_counter,next_value)
output_string = 5 * 4 * 3 * 2 = 120
factorial_str(2,120)
output_string += str(fact_counter) + ' * ' becomes
5 * 4 * 3 * 2 * 1
next_counter = fact_counter - 1 becomes:
2 - 1 = 1
next_counter = 1
next_value = next_counter * fact_value becomes:
1 * 120 = 120
next_value = 120
output_string += factorial_str(next_counter,next_value) becomes:
output_string = 120 + factorial_str(next_counter,next_value)
factorial_str(next_counter,next_value) becomes:
factorial_str(1, 120)
Now the base case 2 evaluates to true because next_counter is 1
elif fact_counter == 1
So the elif part executes which has the following statement:
output_string += str(fact_counter) + ' = ' + str(fact_value)
output_string = 5 * 4 * 3 * 2 * 1 = 120
So the output of the above program with user_val = 5 is:
5! = 5 * 4 * 3 * 2 * 1 = 120
Following are the recursive program code to calculate the factorial:
Program Explanation:
Defining a method "factorial_str" that takes two variable "f, val" in parameters.Inside the method, "s" variable as a string is defined, and use multiple conditional statements.In the if block, it checks f equal to 0, that prints value that is 1.In the elif block, it checks f equal to 1, that prints the value is 1.In the else block, it calculates the factor value and call the method recursively, and return its value.Outside the method "n" variable is declared that inputs the value by user-end, and pass the value into the method and print its value.Program:
def factorial_str(f, val):#defining a function factorial_str that takes two parameters
s = ''#defining a string variable
if f == 0:#defining if block that check f equal to 0
s += '1'#adding value in string variable
elif f == 1:#defining elif block that check f equal to 1
s += str(f) + ' = ' + str(val)#printing calculated factorial value
else:#defining else block that calculates other number factorial
s += str(f) + ' * '#defining s block that factorial
n = f - 1#defining n variable that removes 1
x = n * val#defining x variable that calculate factors
s += factorial_str(n,x)#defining s variable that calls factorial_str method recursively
return s#using return keyword that returns calculated factors value
n = int(input())#defining n variable that inputs value
print('{}! = '.format(n),end="")#using print method that prints value
print(factorial_str(n,n))#calling method factorial_str that prints value
Output:
Please find the attached file.
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Change the value in cell E4 to 375000
Answer:
Click cell E4. Type 375000, and then press ENTER. Keyboard (2)1. Press SHIFT+TAB (or use ARROW keys) to select cell E4.
Write an application that asks a user to enter an integer. Display a statement that indicates whether the integer is even or odd.
Answer:
in C++:
#include <iostream>
int main(){
int input;
std::cout<<"Enter a number: "<<std::endl;
std::cin>>input;
if(input%2==0){
std::cout<<" The number is even"<<std::endl;
}else{
std::cout<<"The number is odd"<<std::endl;
}
}
Explanation:
Getting user input as integer, and check if NUMBER÷2 have remainder=0 or no, if remainder==0 then number is even else number is odd
11. To select Access database entries, you should be in
O A. Datasheet view.
O B. Design view.
O C. Query wizard.
O D. Form Design.
Answer: A
Explanation:
Answer:
Design view
Explanation:
did it on edge
Write code to complete PrintFactorial()'s recursive case. Sample output if userVal is 5:5! = 5 * 4 * 3 * 2 * 1 = 120
Answer:
Here is the C++ program:
#include <iostream> //to use input output functions
using namespace std; //to access objects like cin cout
void PrintFactorial(int factCounter, int factValue){ // method definition
int nextCounter = 0; // initialize value of nextCounter by 0
int nextValue = 0; // initialize value of nextValue by 0
if (factCounter == 0) { //base case 1: 0! = 1
cout << "1" << endl; } //displays 1 in the output
else if (factCounter == 1) { //base case 2: 1! = 1
cout << factCounter << " = " << factValue << endl; } //displays 1 in result
else { //recursive case
cout << factCounter << " * ";
nextCounter = factCounter - 1; //decrements factCounter by 1
nextValue = nextCounter * factValue; // multiplies values of nextCounter and factValue and assigns the result to nextValue
PrintFactorial( nextCounter, nextValue); } } //recursively calls PrintFactorial method to compute the factorial
int main() { //start of main function
int userVal = 0; //initialize the userVal variable to 0
userVal = 5; //assigns 5 to the userVal variable
cout << userVal << "! = "; //prints the userVal with ! =
PrintFactorial(userVal, userVal); } //calls PrintFactorial method to compute the factorial of userVal i.e. 5
Explanation:
I will explain the logic of the program with an example.
The value of variable userVal is 5
This is passed to the method PrintFactorial()
1st step:
void PrintFactorial(int factCounter, int factValue) becomes:
PrintFactorial(5, 5)
PrintFactorial method has two base conditions which do not hold because the factCounter is 5 here which is neither 1 nor 0 so the program control moves to the recursive part.
cout << factCounter << " * ";
In recursive part, the above statement prints the value of factCounter followed by an asterisk on the output screen. So this prints:
5 *
nextCounter = factCounter - 1;
This statement decrements the value of factCounter by 1 and assigns it to nextCounter as:
nextCounter = 5 - 1;
nextCounter = 4
nextValue = nextCounter * factValue; multiplies the value of nextCounter by factValue and stores result in nextValue . So
nextValue = 4 * 5
nextValue = 20
PrintFactorial( nextCounter, nextValue); this statement calls the PrintFactorial() recursively to perform the above steps again until the base condition is reached. This statement becomes:
PrintFactorial(4,20)
2nd step:
PrintFactorial method has two base conditions which do not hold because the factCounter is 4 here which is neither 1 nor 0 so the program control moves to the recursive part.
cout << factCounter << " * ";
In recursive part, the above statement prints the value of factCounter followed by an asterisk on the output screen. So this prints:
5* 4 *
nextCounter = factCounter - 1;
This statement decrements the value of factCounter by 1 and assigns it to nextCounter as:
nextCounter = 4 - 1;
nextCounter = 3
nextValue = nextCounter * factValue; multiplies the value of nextCounter by factValue and stores result in nextValue . So
nextValue = 3 * 20
nextValue = 60
PrintFactorial( nextCounter, nextValue); This statement becomes:
PrintFactorial(3,60)
3rd step:
PrintFactorial method has two base conditions which do not hold because the factCounter is 3 here which is neither 1 nor 0 so the program control moves to the recursive part.
cout << factCounter << " * ";
In recursive part, the above statement prints the value of factCounter followed by an asterisk on the output screen. So this prints:
5* 4 * 3 *
nextCounter = factCounter - 1;
This statement decrements the value of factCounter by 1 and assigns it to nextCounter as:
nextCounter = 3 - 1;
nextCounter = 2
nextValue = nextCounter * factValue; multiplies the value of nextCounter by factValue and stores result in nextValue . So
nextValue = 2 * 60
nextValue = 120
PrintFactorial( nextCounter, nextValue); This statement becomes:
PrintFactorial(2,120)
4th step:
PrintFactorial method has two base conditions which do not hold because the factCounter is 2 here which is neither 1 nor 0 so the program control moves to the recursive part.
cout << factCounter << " * ";
In recursive part, the above statement prints the value of factCounter followed by an asterisk on the output screen. So this prints:
5* 4 * 3 * 2 *
nextCounter = factCounter - 1;
This statement decrements the value of factCounter by 1 and assigns it to nextCounter as:
nextCounter = 2 - 1;
nextCounter = 1
nextValue = nextCounter * factValue; multiplies the value of nextCounter by factValue and stores result in nextValue . So
nextValue = 1 * 120
nextValue = 120
PrintFactorial( nextCounter, nextValue); This statement becomes:
PrintFactorial(1,120)
Now the base case 2 evaluates to true because nextCounter is 1
cout << factCounter << " = " << factValue statement prints the value of factCounter i.e. 1 followed by an equal sign = followed by value of factValue i..e 120
So the output of the above program with userVal = 5 is:
5! = 5 * 4 * 3 * 2 * 1 = 120
Recursion functions are functions whose execution is controlled from within the function
The PrintFactorial()'s recursive caseThe code segment written in Python, where comments are used to explain each action is as follows:
#This defines the function
def PrintFactorial(n):
#if n is 1, this returns the value of n
if n == 1:
return n
#If otherwise
else:
#This calculates the factorial, recursively
return n*PrintFactorial(n-1)
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Identify the most common level of education for a programmer or software developer.
a bachelor's degree
a PhD
a high school diploma
a certificate
Answer:
A. a bachelor's degree
Explanation:
A keyboard would be considered____. Select 2 options.
Answer:
hardware
an input device
Explanation:
the ohter options are not applicable