Answer:
Pressure
Explanation:
One of the theories propounded by the Kinetic molecular theory, and which also provides an explanation of the several gas laws, is the statement that the gas molecules in a container, travel in straight lines and are in constant collision with themselves and the walls of the container, thus exerting force. This force is the pressure which is defined as the force per unit area.
There is no loss of energy in the collisions involving the gas molecules and that is why their movement can be described as elastic. The descriptions of the behavior of gas molecules in the Kinetic Molecular Theory, give rise to Charles law, Boyle's Law, Avogadro's Laws, Dalton's Law, and Amonton's Law.
Answer:
The pressure
Explanation:
Molecules of gases are constantly in motion, colliding with the walls of their container. This constant collision impacts force on the walls of the container, which depends on the speed with which the molecules are moving. The speed with which these molecules travel depends on the average kinetic energy of the molecules, which is proportional to the temperature.
This force when exerted per unit area is the pressure the gases exert on the walls of the container.
A wave has a frequency of 5 Hz and a wavelength of 0.5 m, what is the speed of this wave?
Answer:
2.5 m/s
Explanation:
The speed of a wave can be found using the following formula.
v= λ * f
where λ is the wavelength in meters (m) and f is the frequency of the wave in Hertz (Hz).
We know the wavelength is 0.5 m and the frequency of the wave is 5 Hz.
Therefore,
λ= 0.5 m
f = 5 Hz
v= 0.5 * 5
Multiply 0.5 by 5, or divide 5 by 2.
0.5 * 5= 2.5 or 5/2=2.5
v= 2.5
Add appropriate units. The units for wave speed are m/s (meters per second).
v= 2.5 m/s
The speed of the wave is 2.5 meters per second.
An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10 seconds. Assuming air resistance is negligeble, Calculate initial velocity and the height of the building
Answer:
Explanation:
from 2nd equation of motion
S=vi t +1/2 a(t)²
vi=2 s-at /t
vi=2*200 m- 9.8*10 /10
vi=302/10
vi=30.2 m/s
H= vi*t+1/2 a t^2
H=30.2*10+1/2 9.8*10
H=302+1/2*9.8*10
H=302+1/2(98)
H=302+98/2
H=506/2
H=253
A uniform horizontal beam with a length of 8m and weigh of 200N is attached to a wall by a pin connection ..Its far end is supported by the cable tha makes an angle of 53.0 with the beam. If 600N person stands 2m from the wall , find the tension in the cable as well as the magnitude and direction of the force exerted by the wall on the beam.
Answer:
The tension in the cable is approximately 1440.0 N
Explanation:
The length of the beam = 8 m
The weight of the beam = 200 N
The angle made by the beam support cable = 53°
The weight of the person = 600 N
The position where the person stands = 2 m
The forces acting are the weight of the cable acting at the center of the beam and the weight of the person acting at 2 m from the wall
Therefore, we have;
Sum of moments = 0, which gives;
2000 × 4 + 2 × 600 - 8 × [tex]T_y[/tex] = 0
2000 × 4 + 2 × 600 = 8 × [tex]T_y[/tex]
[tex]T_y[/tex] = 9200/8 = 1150 N
The tension in the cable, T = The component of the force in the cable
The vertical component of the tension [tex]T_y[/tex] = T×sin(53)
Therefore;
T = [tex]T_y[/tex]/(sin(53)) = 1150/(sin(53 degrees)) = 1439.96 ≈ 1440 N
The tension in the cable, T is approximately 1440 N.
V Page 1. What is the acceleration due to gravity at poles in m/s2.if it is 9.78 at the equation ->
Answer:
Chk photo
Explanation:
what do you mean by scattering of light
Answer:
Scattering of light is the phenomenon in which light rays get deviated from its straight path on striking an obstacle like dust or gas molecules, water vapours etc. Scattering of light gives rise to many spectacular phenomena such as Tyndall effect and the “red hues of sunrise and sunset”.
Which statement accurately describes dark matter?
Answer:
Dark matter is the term astronomers use to describe material in the universe that does not emit or reflect light and is, therefore, invisible.
Explanation:
Stars, nebulae, and galaxies are examples of luminous objects in the sky. However, luminous matter appears to make up only a small fraction of all the matter in the universe, perhaps only up to 10 percent.
. Calculate the momenturn of a bus of mass 2000 kg moving with a velocity of 20 m/s
We know
[tex]\boxed{\sf Momentum=Mass\times Velocity}[/tex]
[tex]\\ \sf\longmapsto Momentum=2000(20)[/tex]
[tex]\\ \sf\longmapsto Momentum=40000kgm/s[/tex]
In a simple machine the energy input is 120J if the efficiency of the machine is 80% calculate the energy output
Answer:
E_O = 96J
Explanation:
E_O = E_I*(%e/100%)
E_O = 120J*(80%/100%)
E_O = 96J
While driving on a highway, your HMMWV starts to pull to one side. You stop and check your tires – one tire is going flat. There is no spare, but the affected tire has a runflat device installed, and you are only 5 miles from the motor pool. What is your maximum allowable speed when driving with one flat tire?
Answer:
30 miles people hour (mph)
Explanation:
The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.
a body weighs 100newtons and 80newtons when submerged in water.calculate the upthrust action on the body
Answer:
20 N
Explanation:
In air, the normal force is equal to the weight.
∑F = ma
N − mg = 0
N = mg
Submerged in water, the normal force is equal to the weight minus the buoyant force:
∑F = ma
B + N − mg = 0
N = mg − B
Plugging in values:
80 N = 100 N − B
B = 20 N
What happens when a sound wave passes from oil into air? A. the sound wave slows down and bounces back B. the sound wave slows down and bends C. the sound wave speeds up and bounces back D. the sound wave speeds up and bends
Oil is optically denser than water. When sound/light goes from optically denser medium to optically rarer medium, their velocity increase and they moves away for normal.
Appropriate Answer:The sound wave speeds up and bends
[tex] \Large{ \underline{ \boxed{ \pink{ \bf{Option \: (D)}}}}}[/tex]
As, In optics we learnt that light undergoes refraction when travels from medium of different densities. Similarly, Sound also follows the law of refraction.
It is due to the change of speed of water in different mediums, This makes it speed up or down depending upon the medium and their densities.━━━━━━━━━━━━━━━━━━━━
Answer:
the sound wave slows down and bends
Explanation:
a p e x
A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. What force constant is needed to produce a period of 0.500 s for a 0.0150-kg mass
Answer:
the force constant k = 2.369 N/m
Explanation:
Given that:
A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.
with period T = 0.500 s and a mass of 0.0150 kg, Then the force constant can be calculated by using the formula:
[tex]\mathtt{T = 2 \pi \ \sqrt{\dfrac{m}{k} }}[/tex]
where;
T = time period
m = mass
k = force constant.
By making k the subject of the formula; we have:
[tex]\mathtt{T^2 = 4 \pi^2 (\dfrac{m}{k})}[/tex]
[tex]\mathtt{k =\dfrac{4 \pi ^2 \ m}{T^2}}[/tex]
replacing our given values , we have:
[tex]\mathtt{k =\dfrac{4 (3.142) ^2 \ \times 0.0150 }{0.5^2}}[/tex]
[tex]\mathtt{k =\dfrac{39.49 \ \times 0.0150 }{0.25}}[/tex]
[tex]\mathtt{k =\dfrac{0.59235 }{0.25}}[/tex]
k = 2.369 N/m
According to the information available in the question, the force constant is 2.37N/m.
Using the relation;
T = 2π√m/k
T = period = 0.500 s
m = mass in kilograms = 0.0150-kg
k = spring constant = ?
Making k the subject of the formula;
k = 4π^2m/T^2
k = 4 × (3.142)^2 × 0.0150/(0.500 )^2
k = 2.37N/m
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A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She throws the softball with a velocity of 23.5 m/s at an angle of 39.5∘ above the horizontal. When the softball leaves her hand, it is 11.5 m above the water. How far does the softball travel horizontally before it hits the water? Neglect any effects of air resistance when calculating the answer.
Answer:
66.86m
Explanation:
Velocity of ball thrown, u = 23.5 m/s
Initial height of the ball above the water, H = 11.5 m
Angle of projection, θ = 39.5°
Vertical components of veloclty = usinθ
Horizontal components of veloclty = ucosθ
The soft ball hits the water after time 't'
Considering the second equation of motion
S = ut + 1/2at^2........ 1
But since the ball went through motion under gravity ( free fall ) rather than linear motion, then equation 1 can be rewritten as:
H = ut +/- 1/2gt^2
H = - 11.5m
U = usinθ
θ = 39.5°
a = -g = -9.8m/s^2
- 11.5m = 23.5(sin39.5°)t + 1/2(-9.8)t^2
-11.5m = 23.5(0.6360)t - 4.9t^2
-11.5m = 14.946t - 4.9t^2
4.9t^2 -14.946t-11.5m = 0
Since the ball drifted horizontally
D = (Ucosθ)t
Where θ = 39.5°
U = 23.5m/s t=
Alternatively,
horizontal component of the velocity is 23.5 cos 39.5º = 18.1331 m/s
now how long does it take the ball to raise to a peak and fall to the water.
vertical component of velocity = 23.5 sin 39.5º = 14.947m/s
time to reach peak t = v/g = 11.947/9.8 = 1.5252 sec
peak reached above cliff top is
h = ½gt² = ½(9.8)(1.5252)²
= ½×22.797
= 11.3985m
now the ball has to fall 11.3985+ 11.5 = 22.8985m
time to fall from that height is
t = √(2h/g) = √(2• 22.8986/9.8) = 2.1617 sec
add up the two times to get time it is in the air, 2.1617 + 1.5252 = 3.6869
now haw far does the ball travel horizontally in that time
d = vt = 18.1331 ×3.6869= 66.856m
= 66.86m
A projectile has a range of 60 m and can reach a maximum height of 15 m. Calculate the angle at which projectile is fired? ( g = 10m/s2 )
Answer:
The angle the projectile was fired is [tex]45^o[/tex]
Explanation:
Recall the formulas for maximum height and ranges for a projectile fired with initial velocity "v" at an angle [tex]\theta[/tex]:
[tex]h = \frac{v^2\,sin^2(\theta)}{2\,g}\\R=\frac{v^2\,sin(2\,\theta)}{g}[/tex]
we can use them to solve for the angle by first isolating the value [tex]v^2[/tex] which is common in both equations:
[tex]v^2=2\,h\,g/sin^2(\theta)=2\,(15)\,g/sin^2(\theta)=30\,(g)/sin^2(\theta) \\ \\v^2=R\,g/sin(2\,\theta)=60\,(g)/sin(2\,\theta)[/tex]
and now, making those to expressions equal and using the formula for the sine of a double angle, we get:
[tex]\frac{30\,(9.8)}{sin^2(\theta)} =\frac{60\,(g)}{sin(2\,\theta)} \\30\,(g)\,sin(2\,\theta)=60\,(g)\,sin^2(\theta)\\sin(2\,\theta)=2\,sin^2(\theta)\\2\,sin(\theta)\,cos(\theta)=2\,sin(\theta)\,sin(\theta)\\cos(\theta)=sin(\theta)[/tex]
This happens when [tex]\theta=45^o[/tex]
The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one important model is missing. An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle. An image at right with a purple center outlined in black with two concentric black circles around the center, the inner circle having 2 small green balls on it and the outer circle having 8 small green balls on it. Which atomic model is missing from this set? Bohr’s model Dalton’s model Rutherford’s model Thomson’s model
Answer:
Thomson’s model
Explanation:
Thompson regarded the atom largely as a sphere of positively charged matter in which negative charges were embedded.
This came to be known as the plum pudding model of the atom because it resembles a pudding studded with currants.
This was an early model of the atom and did not survive further experimental scrutiny of the structure of the atom.
Answer:
Thompsons model
Explanation:
i got it right on the quiz
The rate of chage of displacement is called __________
Answer:
Velocity is the rate of change of displacement.
Most cars have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made of copper and is filled to its 21.1 L capacity when at 12.2°C. What volume of radiator fluid (in L) will overflow when the radiator and fluid reach a temperature of 95.0°C, given that the fluid's volume coefficient of expansion is β = 400 ✕ 10−6/°C? (Your answer will be a conservative estimate, as most car radiators have operating temperatures greater than 95.0°C).
Answer:
0.699 L of the fluid will overflow
Explanation:
We know that the change in volume ΔV = V₀β(T₂ - T₁) where V₀ = volume of radiator = 21.1 L, β = coefficient of volume expansion of fluid = 400 × 10⁻⁶/°C
and T₁ = initial temperature of radiator = 12.2°C and T₂ = final temperature of radiator = 95.0°C
Substituting these values into the equation, we have
ΔV = V₀β(T₂ - T₁)
= 21.1 L × 400 × 10⁻⁶/°C × (95.0°C - 12.2°C)
= 21.1 L × 400 × 10⁻⁶/°C × 82.8°C = 698832 × 10⁻⁶ L
= 0.698832 L
≅ 0.699 L = 0.7 L to the nearest tenth litre
So, 0.699 L of the fluid will overflow
3Three identical sheets of paper are taken, but arranged in different ways as shown. Which paper can support the most weight?
Answer:
The most thick paper can support maximum weight.
Explanation:
A paper is defined as a thin sheet of material that is prepared chemically or mechanically processing of the cellulose fibers which are derived from the grasses, wood, bamboos, trees or rags.
In the context, there are three different but identical sheets of paper that are arranged in different ways. Weights are placed over the papers. Now the most thick paper of the three provided will support most of the weight.
Paper thickness or paper weights are measured in GSM. GSM stands for grams per square meter. The thicker paper will have higher GSM.
Which element would have the lowest electronegativity? (1 point)
an element with a small number of valence electrons and a large atomic radius
an element with a small number of valence electrons and a small atomic radius
an element with a large number of valence electrons and a small atomic radius
an element with a large number of valence electrons and a large atomic radius
Answer:
an element with a small number of valence electrons and a large atomic radius
what is measurement?
Answer:
The comparison of unknown quantity with known quantity is called measurement
Answer:
the size, length or amount of something is a measurement.
Explanation:
Measurements help in daily life and are important to development, accuracy and making decisions.
what does it mean by that "length of an object is m"
A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the exact instant, a carriage moving on rails is also released to the right from the bottom of the pillar. Calculate the velocity with which the carriage should be released so that the ball falls in the carriage after the carriage has traveled a distance of 50 meters on the ground.
A. 12.20 meters/ seconds
B. 13.23 meters/ seconds
C. 14.30 meters/ seconds
D. 15.65 meters/ seconds**
E. 16.00 meters/ seconds
I believe D is right = 15.65m/s
Also ** on Plato
Answer:
D. 15.65 meters/ seconds**
Explanation:
You're correct. Use kinematic equation to find V_final.
[tex] {v}^{2} = {v 0}^{2} + 2a(xf - x0)[/tex]
Then use the following to find time.
[tex]t = (vf - v0) \div a[/tex]
Then 50m/3.2s = 15.65m/s
Part B After producing electricity in many different ways, describe what causes electricity to flow in the coil? In your response, describe the types of forces acting on the electrons and how they result in movement.
Explanation:
If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. ... A changing magnetic field through a coil of wire therefore must induce an emf in the coil which in turn causes current to flow.
Due to the flow of the current run, the coil magnetic field is produced. Magnetic fields result in magnetic force.
What is electric force?The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.
A current will be generated in a wire coil if it is put in a changing magnetic field. As a result, a changing magnetic field through a coil of wire must create an emf in the coil, causing the current to flow.
A current is induced in a coil of wire when it is put in a changing magnetic field. Something generates an electric field that drives the charges around the wire, causing the current to flow.
Hence due to the flow of the current in the coil magnetic field is produced.
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A 0.149 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.710 m/s . It has a head-on collision with a 0.308 kg glider that is moving to the left with a speed of 2.27 m/s . Suppose the collision is elastic.1. Find the magnitude of the final velocity of the 0.157kg glider.
2. Find the magnitude of the final velocity of the 0.306kg glider.
Answer:
v1 = −2.201946 m/s ( to the left)
v2 = 0.7780534 m/s ( to the right)
Explanation:
Given the following :
Mass of first glider (m1) = 0.149kg
Initial Speed of first glider (u1) = 0.710 m/s
Mass of second glider (m2) = 0.308kg
Initial Speed of second glider (u2) = 2.27m/s
For elastic collision:
m1u1 + mu2u2 = m1v1 + m2v2
Where V1 and v2 = final velocities if the body after collision.
Taking right as positive ; left as negative
u1 = 0.710m/s ; u2 = - 2.27m/s
u1 - u2 = - (v1 - v2)
0.710 - - 2.27 = - v1 + v2
v2 - v1 = 2.98 - - - - (1)
From:
m1u1 + mu2u2 = m1v1 + m2v2
(0.149 * 0.710) + ( 0.308 * - 2.27) = (0.149 * v1) + (0.308 * v2)
0.10579 + (-0.69916) = 0.149 v1 + 0.308v2
−0.59337 = 0.149 v1 + 0.308v2
Dividing both sides by 0.149
v1 + 2.067v2 = −0.59337 - - - - - (2)
From (1)
v2 = 2.98 + v1
v1 + 2.067(2.98 + v1) = −0.59337
v1 + 6.16 + 2.067v1 = −0.59337
3.067v1 = −0.59337 - 6.16
3.067v1 = −6.75337
v1 = −6.75337 / 3.067
v1 = −2.201946 m/s ( to the left)
From v2 = 2.98 + v1
v2 = 2.98 + (-2.201946)
v2 = 0.7780534 m/s ( to the right)
How many minutes does it take for light to go from the sun to the planet Uranus, a distance of 2.88x109 km? (The
velocity of light is constant in free space and is 3.00x108 m/s)
Answer:
t = 160 minutes
Explanation:
Given that,
Distance of Uranus from Sun is [tex]2.88\times 10^9\ km[/tex]
We need to find the time taken by the light to go from sun to Uranus if the velocity of light is constant in free space and it is equal to c.
So,
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{2.88\times 10^9\times 10^3\ m}{3\times 10^8}\\\\t=9600\ s[/tex]
Since, 1 minute = 60 seconds
t = 160 minutes
So, 160 minutes is taken by the light.
state three effects of malnutrition in farm animals
Answer:
Cows,Pigs,Chicken. They are always in farm
what is metel and non metel ?
Answer:
Metals (like copper and aluminium) are good conductors of heat and electricity, while nonmetals (such as phosphorus and sulfur) are insulators.
Explanation:
i don't really have one i just know
Answer:
1 of them is metel and one is not
Explanation:
The probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm. What is the wavelength of the sound waves in the patient?a) 0.54 mm b) 0.12 mm c) 0.26 mm d) 0.027 mm
Answer:
0.54mm
Explanation:
Given the following :
Wavelength (λ) of Soundwave in air = 0.12mm
Velocity of sound wave (v) = 340m/s
Calculate the frequency (f) :
v = fλ
Wavelength to metres
1000mm = 1 m
0.12mm = (0.12/1000)m
= 0.00012m
v = fλ
340 = F * 0.00012
f = 340 / 0.00012
f = 2833333.3 Hz
Wavelength of Soundwave in the patient:
Velocity of sound wave through body tissue = 1540m/s
Therefore,
Using v = fλ
λ = v / f
λ = 1540 / 2833333.3
λ = 0.0005435m
λ = (0.0005435 * 1000)mm
λ = 0.5435mm = 0.54mm
The distance between neighbouring, identical wave components, such as adjacent compressions, determines a sound's wavelength. The number of waves passing a spot in a given amount of time is known as the frequency, which is the same as the source's frequency.
What wavelength of the sound waves in the patient?Wavelength (λ) of Soundwave in air = 0.12 mm
Velocity of sound wave (v) = 340m/s
Calculate the frequency (f) :
v = fλ
Wavelength to metres
1000 mm = 1 m
0.12 mm = (0.12/1000)m
= 0.00012 m
v = fλ
340 = F × 0.00012
f = 340 / 0.00012
f = 2833333.3 Hz
Wavelength of Soundwave in the patient:
Sound waves travel through body tissue at a speed of 1540 m/s.
Therefore, Using v = fλ
λ = v / f
λ = 1540 / 2833333.3
λ = 0.0005435m
λ = (0.0005435 × 1000)mm
λ = 0.5435mm = 0.54 mm
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A car accelerate uniformly from rest at 5m/s2 . Determine it's speed after 10s
Answer:
50m/s.
Explanation:
Let's take acceleration as A and speed as S:
A = 5m/s²
S = A × 10s = 5 × 10 = 50m/s
The answer is 50m/s.
Answer:
50m/s
Explanation:
Given:
a=5m/s^2
t=10s
Required:
v=?
Formula:
a=v/t
Solution:
a=v/t
v=a*t
v=5m/s^2*10s
v=50m/s
Hope this helps ;)❤❤❤
an astronaut takes a tuning fork with her to the moon she strikes it inside the cabin the cabin is normally filled with air so the humans inside the spacecraft are comfortable she also strikes it outside the spacecraft when she gets down on the surface of the moon which of the following is true about the tuning fork?
A: it does not vibrate inside the spacecraft
B: id does not vibrate on moon surface
C: it vibrations are not transmitted inside the spacecraft
D:it's vibrations are not transmitted to the moon's atmosphere
Answer:
The correct option is;
D: Its vibrations are not transmitted to the moon's atmosphere
Explanation:
A tuning fork is used to produce sound by vibration such that the tune produced is pure
The tune, sound, produced by the tuning fork is transmitted as sound wave through the air by means of the gases of the air as a transmission medium so people at a distance that have air around them can hear the tuning fork sound
On the Moon's surface, the atmosphere is very and it is referred to technically as an exosphere, so the sound of the tuning fork has no medium through which to transmit and therefore, it is not transmitted on the Moon's atmosphere.