The peak value of an alternating current in a 1500-W device is 6.4 A. What is the rms voltage across it

Explanation:

Height is the x-axis, and gravitational potential energy is the y-axis.  As the height increases, the gravitational potential energy increases linearly.

Answer:

a. the minimum amplitude of vibration for the NO molecule A [tex]\simeq[/tex] 4.9378 pm

b. the minimum amplitude of vibration for the HCl molecule A [tex]\simeq[/tex] 10.9336 pm

Explanation:

Given that:

The effective spring constant describing the potential energy of the HBr molecule is 410 N/m

The effective spring constant describing the potential energy of the NO molecule is 1530 N/m

To calculate the minimum amplitude of vibration for the NO molecule, we use the formula:

[tex]\dfrac{1}{2}kA^2= \dfrac{1}{2}hf[/tex]

[tex]kA^2= hf[/tex]

[tex]A^2= \dfrac{hf}{k}[/tex]

[tex]A = \sqrt{\dfrac{hf}{k}}[/tex]

[tex]A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 5.63 \times 10^{13} \ s^{-1})}{1530 \ N/m}}[/tex]

[tex]A = \sqrt{\dfrac{3.730438 \times 10^{-20} \ m}{1530 }[/tex]

[tex]A = \sqrt{2.43819477 \times 10^{-23}\ m[/tex]

[tex]A =4.93780799 \times 10^{-12} \ m[/tex]

A [tex]\simeq[/tex] 4.9378 pm

The effective spring constant describing the potential energy of the HCl molecule is 480 N/m

To calculate the minimum amplitude using the  same formula above, we have:

[tex]A = \sqrt{\dfrac{hf}{k}}[/tex]

[tex]A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 8.66 \times 10^{13} \ s^{-1})}{480 \ N/m}}[/tex]

[tex]A = \sqrt{\dfrac{5.738116\times 10^{-20} \ m}{480 }[/tex]

[tex]A = \sqrt{1.19544083\times 10^{-22}\ m[/tex]

[tex]A = 1.09336217 \times 10^{-11} \ m[/tex]

[tex]A = 10.9336217 \times 10^{-12} \ m[/tex]

A [tex]\simeq[/tex] 10.9336 pm

The blue sky we observe depends upon two factors: how sunlight interacts with Earth's atmosphere, and how our eyes perceive that light.

If this helps please mark me the brainiest

how sunlight interacts with Earth's atmosphere, and how our eyes perceive that light.nation:

Answer:

Hip and knee extensors

Explanation:

These are gluteus muscles and hamstring muscles the there are the major movers for your body and are very important in pelvic alignment and lower back support during weight lifting

Answer:

The correct answer is:

The instantaneous speed is always equal to the magnitude of instantaneous velocity. (A)

Explanation:

Speed is the ratio of distance travelled to time. It is a scalar quantity.

Velocity is the rate of change of displacement with time. It is a scalar quantity, having both magnitude and direction

Instantaneous velocity is the rate of change of position for a very small time interval (at a particular point in time), while the instantaneous speed at any given time, is the magnitude of instantaneous velocity. Note that the velocity has both magnitude and direction, so at a particular point in time, the magnitude part of velocity is the same as the speed.

The formula of instantaneous velocity is: [tex]V_{i}=\lim_{\Delta t\rightarrow 0}\frac{ds}{dt}[/tex]

The formula of instantaneous speed is: [tex]Speed_{(i)}=\frac{ds}{dt}[/tex]

On the other hand, average speed does not equal the magnitude of average velocity, because velocity depends on displacement while speed depends on distance, and if an object in motion changes direction at any point in the motion, the velocity reduces because the angle of change in the direction will be considered, hence the speed will be greater than the velocity, therefore, the average speed is not the same as the magnitude of average velocity.

Answer:

independent

dependent

dependent

Answer:

Is a flame hottest when it is blue?  Is it cold today?

Explanation:

Verification questions. These are basic data collecting questions. They are useful in building knowledge.

Answer:

Explanation:

⁶₃Li will have 3 protons and 3 neutrons .

mass of proton in amu = 1.00727 amu

mass of neutron in amu = 1.00866 amu

mass of lithium nucleus in amu = 6.01512 amu

mass defect = 3 (  1.00727  + 1.00866 ) - 6.01512 amu

= .03267 amu

Binding energy = mass defect in amu x 931 Mev

= 30.41 MeV

binding energy per nucleon

no of nucleon = 3 + 3 = 6

binding energy per nucleon = 30.41 / 6 Mev

= 5.068 MeV .

The binding energy of  ⁶₃Li nucleus in MeV per nucleon is 5.26  MeV per nucleon.

We can see that Li has three protons and three neutrons. The total mass of the Li nucleus is obtained from;

3(1.007277) + 3(1.008665) = 3.023 + 3.026 = 6.049 amu

Actual mass of Li - 6 =  6.0151 amu

Mass defect = 6.049 amu - 6.0151 amu = 0.0339 amu

We can obtain the binding energy in MeV as follows;

Binding energy = 0.0339 amu × 931 = 31.56 MeV

The binding energy per nucleon in MeV per nucleon =  31.56 MeV/6

= 5.26  MeV per nucleon

Learn more: https://brainly.com/question/6284546

Body mass index, known as BMI, is not a method of calculating body fat percentage, but it is a technique used to check nutritional status and to see if a person is within normal range with respect to weight and height.. This technique is measured by the formula: BMI = Weight (Kg) / (Height (m)) ².

Ergo, the answer  is BMI!!!!!!!!!!!

Hope this helped you!

Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

             A = 0.07129 m²

b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

The correct answer is B. 1.3 m/s north

Explanation:

Velocity is a factor that describes how fast or slow the motion of a body occurs and its direction. Moreover, this can be calculated by dividing the total displacement into the time of movement, and the final result is expressed in units such as meters per second followed by the direction, for example, 152 m/s south. The process to calculate the velocity of the swimmer is shown below.

[tex]v = \frac{d}{t}[/tex]

[tex]v = \frac{28 meters}{22 seconds}[/tex]

[tex]v = 1.27 m/s[/tex]

This means the velocity of the swimmer is 1.27 m/s, which can be rounded as 1.3 m/s. Additionally, if the direction is considered it would be 1.3 m/s north because the swimmer went from the south of the pool to its north.

Answer:

the answer is B

Explanation:

confirmed

Answer:

Explanation:

We shall convert all the displacement in vector form .

i and j represents east and north respectively .

D₁ = 4 i

D₂ = 4 j

D₃ = - 5 cos 53.1 i + 5 sin 53.1 j

= -3i + 4 j

Total displacement = D₁ + D₂ + D₃

= 4i + 4 j - 3i + 4 j

= i + 8j

magnitude of displacement = √( 1² + 8² )

= 8.06 km

velocity = 8.06 / 5

= 1.61 km / h

Direction from x axis in anticlockwise direction .

Tanθ =  8 / 1 = 8

θ = 83° north of east .

Answer:

3.5s

Explanation:

Using equation of motion number 2

S= ut + 1/2 gt²

Substituting

10= 0.5+1.62t²

t= 3.5seconds

Answer:

The correct answer will be "2".

Explanation:

Answer: 1) a = 9.61m/s² pointing to west.

             2) (a) Δv = - 37.9km/s

                  (b) a = - 6.10⁷km/years

Explanation: Aceleration is the change in velocity over change in time.

1) For the plane:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

[tex]a=\frac{125}{13}[/tex]

a = 9.61m/s²

The plane is moving east, so velocity points in that direction. However, it is stopping at the time of 13s, so acceleration's direction is in the opposite direction. Therefore, acceleration points towards west.

2) Total change of velocity:

[tex]\Delta v = v_{f}-v_{i}[/tex]

[tex]\Delta v = -17.1-(+20.8)[/tex]

[tex]\Delta v= -37.9[/tex]km/s

The interval is in years, so transforming seconds in years:

v = [tex]\frac{-37.9}{3.15.10^{-7}}[/tex]

[tex]v=-12.03.10^{7}[/tex]km/years

Calculating acceleration:

[tex]a=\frac{-12.03.10^{-7}}{2.01}[/tex]

[tex]a=-6.10^{7}[/tex]

Acceleration of an asteroid is a = -6.10⁷km/years .

Answer:

Explanation:

252,000

Answer:

bobby has a greater magnitude of velocity because because when angular speed is constant linear velocity is proportional to radius of the circular path

B. They both have same magnitude of angular velocity since the angular speed of the merrygoround is constant

C. Also they both have the same tangential acceleration because the angular speed is constant and tangential is zero for both of them

D. Centripetal acceleration of Bobby is greater

E.they both have the same angular acceleration because angular Speed I constant so angular acceleration is zero for both

Answer:

(a). The gauge pressure at the bottom of tube 1 is [tex]P_{1}=\rho g h_{1}[/tex]

(b).  The speed of the fluid in the left end of the main pipe [tex]\sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}[/tex]

Explanation:

Given that,

Gauge pressure at bottom = p₁

Suppose, an arrangement with a horizontal pipe carrying fluid of density p . The fluid rises to heights h1 and h2 in the two open-ended tubes (see figure). The cross-sectional area of the pipe is A1 at the position of tube 1, and A2 at the position of tube 2.

Find the speed of the fluid in the left end of the main pipe.

(a). We need to calculate the gauge pressure at the bottom of tube 1

Using bernoulli equation

[tex]P_{1}=\rho g h_{1}[/tex]

(b). We need to calculate the speed of the fluid in the left end of the main pipe

Using bernoulli equation

Pressure for first pipe,

[tex]P_{1}=\rho gh_{1}[/tex].....(I)

Pressure for second pipe,

[tex]P_{2}=\rho gh_{2}[/tex].....(II)

From equation (I) and (II)

[tex]P_{2}-P_{1}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)[/tex]

Put the value of P₁ and P₂

[tex]\rho g h_{2}-\rho g h_{1}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)[/tex]

[tex]gh_{2}-gh_{1}=\dfrac{1}{2}(v_{1}^2-v_{2}^2)[/tex]

[tex]2g(h_{2}-h_{1})=v_{1}^2-v_{2}^2[/tex]....(III)

We know that,

The continuity equation

[tex]v_{1}A_{1}=v_{2}A_{2}[/tex]

[tex]v_{2}=v_{1}(\dfrac{A_{1}}{A_{2}})[/tex]

Put the value of v₂ in equation (III)

[tex]2g(h_{2}-h_{1})=v_{1}^2-(v_{1}(\dfrac{A_{1}}{A_{2}}))^2[/tex]

[tex]2g(h_{2}-h_{1})=v_{1}^2(1-(\dfrac{A_{1}}{A_{2}}))^2[/tex]

Here, [tex]\dfrac{A_{1}}{A_{2}}=\gamma[/tex]

So, [tex]2g(h_{2}-h_{1})=v_{1}^2(1-(\gamma)^2)[/tex]

[tex]v_{1}=\sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}[/tex]

Hence, (a). The gauge pressure at the bottom of tube 1 is [tex]P_{1}=\rho g h_{1}[/tex]

(b).  The speed of the fluid in the left end of the main pipe [tex]\sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}[/tex]

Answer:

A

Explanation:

cant be c because its asking for speed and speed doesnt have direction

Answer: a Had twice as much mass

Explanation:

The data that we have is:

"The force of gravity pulls down on your school with a total force of 400,000 newtons. "

First, remember that, by the second Newton's law that:

F = a*m

F = force

a = acceleration

m = mass

In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2

Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:

Then if the initial force is written as:

F = a*m

twice as much that force is written as:

2*F = a*x

x is a variable that represents the new mass.

We know that F = a*m

2*F = 2*a*m

2*a*m  = a*x

2*m = x

Then, if we want to have twice as much force, we should have twice as much mass.

Answer:

Explanation:

Let the magnetic field after .37 s is B

magnetic flux associated with coil = n BA , where B is magnetic field and A is area of coil and n is no of turns

= 55 x .12 x 1.75

= 11.55 Tm²

magnetic flux after .37 s

= 55 x B x .12

= 6.6 B

rate of change of flux = (66B - 11.55)  / .37 = EMF induced

(6.6B - 11.55)  / .37 = 12.7

6.6 B - 11.55 = 4.7

6.6 B = 16.25

B = 2.46 T .

Answer:

b) directional

Explanation:

The prediction that alcohol slows reaction time is Directional . This is because for alcohol to be known as one which slows reaction time means there have been various hypothesis conducted which supports this.

In this case, formulation of a null hypothesis is usually necessary which means that alcohol does not slow reaction time and another alternative hypothesis that suggests that alcohol slows reaction time.

Answer:

Explanation:

point a represents time 0 and position coordinate 30

point b represents time 10 s , and position coordinate 50 m .

time elapsed = 10 - 0 = 10 s .

displacement = 50 m - 30 m

= 20 m

average velocity = displacement / time elapsed

= 20 / 10

= 2 m /s .

In a position-time graph, the velocity of the moving object is represented by the slope, or steepness, of the graph line. If the graph line is horizontal, like the line after time = 5 seconds in Graph 2 in the Figure below, then the slope is zero and so is the velocity. The position of the object is not changing.

Explanation:

The slope of a position time graph gives the velocity of an object. It can be calculated as follows:

[tex]v=\dfrac{dx}{dt}[/tex]

Where

[tex]dx[/tex] is the change in position

[tex]dt[/tex] is the change in time

If the position vs time graph of an object is a horizontal line, it shows that the object is at rest. At this point the object is not moving.

Answer:

If the position versus time graph of an object is a horizontal line, the object is at rest.

Reference:

https://brainly.com/question/12025472

Answer:

Explanation:

Force = mass × acceleration

F = ma

Answer:

117.8 m³/s

Explanation:

given that

the diameter of the river, d = 10 m wide

Velocity of flow of water, v, = 3 m/s

To get the discharge of a river, we have to find the area of the said river first.

Area of the river, a = area of semi circle = 1/2 * area of a circle

Area = 1/2 * πr²

Area = 1/2 * 3.142 * 5²

Area = 39.275 m²

Discharge of the river therefore is

Discharge, q = A * V, where

A is area of the river, and

V is the velocity of flow of the river.

Discharge, q = 39.275 * 3

Discharge, q = 117.825

Answer:

2.42×10⁷ s

Explanation:

From the question above,

Applying,

Q = It.................... Equation 1

Where Q = quantity of charge in coulombs, I = electric current in Ampere, t = time in seconds

make t the subject of the equation

t = Q/I................ Equation 2

Given: Q = 10900 C, I = 0.450 mA = 4.5×10⁻⁴ A

Substitute these values into equation 2

t = 10900/(4.5×10⁻⁴)

t = 2.42×10⁷ s

Hence the clock runs for 2.42×10⁷ s

Complete Question  

A very long, straight solenoid with a cross-sectional area of 2.39cm2 is wound with 85.7 turns of wire per centimeter. Starting at t= 0, the current in the solenoid is increasing according to i(t)=( 0.162A/s2) t2. A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid. What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is 3.2A ?

Answer:

The value  is [tex]\epsilon =  1.83 *10^{-5} \  V[/tex]

Explanation:

From the question we are told that

    The  cross-sectional area is  [tex]A = 2.39 \ cm^2 = \frac{2.39}{10000} = 0.000239 \ m^2[/tex]

    The  number of turns is  [tex]N = 85.7 \ turns/cm = 8570 \ turns / m[/tex]

    The initial time is  t = 0s

    The  current on the solenoid  is [tex]I(t)   = (0.162 \ A/s^2) t^2[/tex]

     The number of turns of the secondary winding is  [tex]n =  5 \ turns[/tex]

Generally At I =  3.2 A

        [tex]3.2 =  (0.162 )t^2[/tex]

=>       [tex]t^2  =  19.8[/tex]

=>         [tex]t =  4.4 \  s[/tex]

Generally induced emf is mathematically represented as

        [tex]\epsilon  = A *  \mu_o *  n *  N  \frac{d(I)}{dt}[/tex]

         [tex]\epsilon  =  0.000239 *  4\pi * 10^{-7} *  8570 * 5 *  (0.162) * 2t[/tex]

          [tex]\epsilon  =  0.000239 *  4\pi * 10^{-7} *  8570 * 5 *  (0.162) * 2 *  4.4[/tex]  

        [tex]\epsilon =  1.83 *10^{-5} \  V[/tex]

Answer:

v = 6.79 m/s

Explanation:

It is given that,

Mass of a train car, m₁ = 11000 kg

Speed of train car, u₁ = 21 m/s

Mass of other train car, m₂ = 23000 kg

Initially, the other train car is at rest, u₂ = 0

It is a case based on inelastic collision as both car couples each other after the collision. The law of conservation of momentum satisied here. So,

[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]

V is the common velocity after the collisions

[tex]V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{11000\times 21}{(11000+23000)}\\\\V=6.79\ m/s[/tex]

So, the two car train will move with a common velocity of 6.79 m/s.