The velocity when function p(t)=11 is 8 .
According to the question
The position of a car at time t represented by function :
[tex]p(t)=t^{2} +2t-4[/tex]
Now,
When function p(t) = 11 , t will be
[tex]p(t)=t^{2} +2t-4[/tex]
11 = t²+2t-4
0 = t² + 2t - 15
or
t² +2t-15 = 0
t² +(5-3)t-15 = 0
t² +5t-3t-15 = 0
t(t+5)-3(t+5) = 0
(t-3)(t+5) = 0
t = 3 , -5
as t cannot be -ve as given ( t≥0)
so,
t = 3
Now,
the velocity when p(t)=11
As we know velocity = [tex]\frac{position}{time}[/tex]
therefore to get the value of velocity from function p(t)
we have to differentiate the function with respect to time
[tex]\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)[/tex]
v(t) = 2t + 2
where v(t) = velocity at that time
as t = 3 for p(t)=11
so ,
v(t) = 2t + 2
v(t) = 2*3 + 2
v(t) = 8
Hence, the velocity when function p(t)=11 is 8 .
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Which of these can happen to energy in a system? Select all that apply.
Group of answer choices
a. It can be converted.
b. It can remain constant.
c. It can be destroyed.
d. It can be created.
A. What can happen to energy in a system is that it can be converted.
What is the principle of conservation of energy?The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
The energy of a system can be converted from one form to another.
Thus, what can happen to energy in a system is that it can be converted.
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The crystal in a digital watch oscillates at a rate of 215 Hz. If the maximum displacement of one crystal face (measured from one extreme of its motion to the other) is 50 nm, what is the maximum speed of the face?
The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
Maximum speed of the face
v = fλ
where;
f is frequency of the waveλ is the wavelengthAngular speed of the waveω = 2πf
v(max) = ωA
v(max) = 2πfA
where;
A is amplitude of the wavev(max) = 2π(215)(50 x 10⁻⁹ m)
v(max) = 6.75 x 10⁻⁵ m/s
Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
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What is the voltage drop across the 10.0 ohm resistor?
The voltage drop across the 10.0 Ω resistor is c)120V
What is voltage drop in a circuit?A voltage drop is an amount the voltage lowers when crossing a component from the negative side to the positive side in a series circuit. If you positioned a multimeter across a resistor, the voltage drop would be the quantity of voltage you are reading.
Voltage drop is the reduction of electrical potential along the way of a present flowing in an electrical circuit.since, all three resistors 10Ω, 20 Ω, and 30Ω are in series combination this indicates that the voltage drop across each resistor will be the same as the total voltage drop in the circuit because in parallel combination voltage stay identical in the circuit buy current gets divided in each branchhence, the voltage drop across the 10.0 Ω resistor = 120 V
correct answer c) 120 V
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A car drives 17.9 m/s east. It
accelerates at 2.88 m/s² at a
137.7° angle. How long does it
take until the car is driving directly
north?
The time taken for the car to drive directly north is 8.52 seconds.
Time of motion of the car
v = u + at
At 137.7° anglev = u + a cosθ(t)
v = 17.9 + 2.88cos(137.7)t
v = 17.9 - 2.1t
when the car is directly north, v = 0
0 = 17.9 - 2.1t
2.1t = 17.9
t = 17.9/2.1
t = 8.52 seconds
Thus, the time taken for the car to drive directly north is 8.52 seconds.
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The photographer realizes that with the lens she is currently using, she can't fit the entire landscape she is trying to photograph into her picture. Should she switch to a lens with a longer or shorter focal length
She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.
What is focal length?
The focal length is a measure of how strongly the system converges or diverges light.
A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light.
For a standard rectilinear lens,
FOV = 2 arctan (x/2f)
FOV ∝ 1 / f
where x is the diagonal of the film.
Focal length (f) and field of view (FOV) of a lens are inversely proportional.
From the equation we can say that,
A shorter focal length gives you a wide angle of view which allows more view to fit in the frame.
Hence,
She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.
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Answer the following regarding Momentum Change and Force
1. Find the force necessary to gain a velocity of 60 m s-1 within 5 minutes, when acted on a mass of 200 kg which is initially at rest.
2. A force of 150 N acts on an object of mass 600 kg for 2 minutes, which was initially at rest. Find the velocity gained by the object at the end of the second minute.
The force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
Force of the objectF = mv/t
where;
m is mass of the object = 200 kgv is velocity of the object = 60 m/st is time of motion = 5 mins = 300 secondsF = (200 x 60)/(300)
F = 40 N
Velocity of the objectF = mv/t
Ft = mv
v = Ft/m
where;
m is mass = 600 kgF is force = 150 Nt is time = 2 mins = 120 sv = (150 x 120)/(600)
v = 30 m/s
Thus, the force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
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1. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of plutonium-239 to be a mole of “reactions” (molar mass = 239 grams).
2. Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years.
Energy use per person per year in the United States = 3.5 × 1011 joules.
Base your calculations on a current population of 310,000,000.
The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T
Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."
Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.
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You have discovered the planet Zoltron. It is 10.0 times farther from the Sun than Earth (10.0 AU). How long does it take this planet to go once around the Sun
Planet Zoltron takes 32 days to to go once around the Sun.
To find the answer, we need to know about the third law of Kepler.
What's the Kepler's third law?Kepler's third law says the square of time period is directly proportional to the cube of the radius of the orbit.Mathematically, T²∝a³What's the time period of planet Zoltron present at 10AU from sun?Let T1 , T2 are the time period of Earth and Zoltron. a1, a2 are radius of earth and Zoltron orbit respectively.As per Kepler's third law, (T1/T2)²= (a1/a2)³T2 = (a2/a1)3/2×T1= (10 AU/ 1AU)3/2 × 1day
= 32 days.
Thus, we can conclude that the planet Zoltron has time period of 2 days.
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Read the following question and answer it using complete sentences. Be sure to fully explain your answer.
What energy conversion is happening when wave power is used?
Wave power involves conversion of mechanical energy to electrical energy.
What is wave power?We know that energy conversion is part of the postulations of the first law of thermodynamics which states that energy can neither be created nor destroyed but can be transformed from one form to another.
Now, the wave power can convert the regular up and down movement of the ocean waves into a source of electricity. This implies that the energy that is taking place here is the conversion of mechanical energy to electrical energy.
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You are holding a positive charge and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east. What is the direction of the force on the charge you are holding
If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.
Reasoning:
It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.
Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.
Thus the electric force applied on the charge in my hand due to each other is,
[tex]F=\frac{kQq}{r^2}[/tex]
Here k is the Coulomb constant, and r is the distance between the charges.
It is also known that the force on a positive charge due to another positive charge is acted outwards.
Thus, the force on the charge due to the charge on the east is,
[tex]\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}[/tex]
And the force on the charge due to the charge on the north is,
[tex]\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}[/tex]
As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of [tex]45^\circ[/tex] from the north or from the north direction.
Thus the net force is acting in the north-east direction.
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A population distribution shows _______. a. the distribution of age groups within a population b. the amount of organisms in a unit area c. the total number of organisms in a population d. where and in what arrangement organisms are located Please select the best answer from the choices provided A B C D
The answer would be D where and in what arrangement organisms are located.
The large, roughly circular, dark, and somewhat younger regions on the moon are called?
The large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.
What is Maria?Lunar Maria are large, dark, basaltic plains on Earth's Moon. It was created by an ancient asteroid impacting the Moon on the far side and triggering some volcanic activity on the opposite side.
These are vast basins containing lava flows that are marked by craters, ridges, faults and straight and immersed valleys called rills. They are waterless. There are about 20 major areas of this type. Most of which include the largest located on the side of the Moon that always faces Earth.
These maria were the result of the melting and eruption of basaltic lava on the lunar surface 3.8 to 2.8 billion years ago. This type of lava was highly fluid under the Moon's weak gravitational field and spread over vast distances.
Thus, the large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.
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A crate with a mass of 44.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough floor a distance of 5.50 m.
Work done will be 825 N*m
Given:
mass of crate = 44.0 kg
horizontal force = 150 N
distance moved by crate = 5.50 m
To Find:
Work done
Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
First we want to find the work, it is given by the force applied times the distance moved, so the work is just:
W = Force x displacement
W = 150N*5.50m
W = 825 N*m
So, work done will be 825 N*m
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A thin stream of water bends toward a negatively charged rod. When a positively charged rod is placed near the stream, it will bend in the same direction, not the opposite direction. Why
Water bends in the same direction irrespective of the charge of the rod placed near it is because water is dipole- that hydrogen is positively charged and oxygen is negatively charged and thus either of the particle is attracted by the charged rod.
The reason behind it:
As a neutral substance, water has an equal number of positive and negative charges. The negatively charged electrons migrate away from the negatively charged rod and the positively charged protons move toward the rod when the negatively charged rod is placed closer to the water. Water then adheres to the rod. Protons migrate away from the positively charged rod, just as they do when it is moved closer to the water, while electrons flow in its direction. As a result, the water and rod form a relationship.
The partial +ve charge on H is drawn to the -ve charged rod when it is installed, which causes the water stream to bend in the direction of the charged rod.
The partial -ve charge on O is drawn to the +ve rod when it is installed, causing the water stream to bend in the direction of the rod.
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A tank, shaped like a cone has height 6 meters and base radius 5 meters long. It is placed so that the circular part is upward. It is full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. Assume that a cubic meter of water weighs 10 000 N , i.e. the density of water is 10000 N m 3 . How much work does it require to pump all water out of the tank
The work required to pump out the liquid is 2.35 MJ.
What is work?
Work can be defined as the scalar product of the force and the displacement.
The formula to calculate the work done W is,
[tex]W=F.d[/tex]
where F is the force and d is the displacement.
Note: It is assumed that the weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].
Break down the vertical tank into parallel disc elements whose thickness is dh and are located at a height h from the ground. The radius of the element at height h is r.
It is given that the height of the tank is 6 m and the base radius is 5 meters. Using these, the ratio of the radius r at height h to the height h by using the triangle similarity criterion is,
[tex]\frac{h}{r}=\frac{6}{5} \\ r=\frac{5h}{6}[/tex]
Using the above value of r, the volume of the element is given by,
[tex]V= \pi r^2dh\\V=\pi (\frac{5h}{6})^2dh\\V= \frac{25\pi h^2}{36} dh[/tex]
The weight of the volume element is the force required.
The weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].
So the weight F of the volume element at height h is given by,
[tex]F=10000 (\frac{25 \pi h^2}{ 36})dh\\F= 6944.44\pi h^2dh[/tex]
At the height h, the difference in the height of the top of the tank and the volume element is (6-h). So the work required to pump out the volume of liquid at height h is given by the integrating the equation,
[tex]W=6944.44\pi\int\limits^6_0 {(6h^2-h^3)} \, dx \\\\W=69.44\pi \left[ 2h^3-\frac{h^4}{4}\right]^6_0\\W=2,.35\times10^6\text{ J}[/tex]
The value of the W obtained is 2.35*10^6 J or 2.35 MJ.
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A 16.0 kg crate rests on a shelf 1.80 m above the floor in a warehouse. A forklift is used to raise the crate to a shelf 3.30 m above the warehouse floor. What is the increase in potential energy of the crate?
Group of answer choices
a. 240 J
b. 250 J
c. 230 J
d. 260 J
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
What is potential energy?It is the energy due to the position.
A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:
U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J
A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:
U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J
The increase in the potential energy is:
518 J - 283 J = 235 J ≈ 240 J
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
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Give an example of q eqluibrium in a linear motion
Answer:
What type of equilibrium? There are more types, lol.
If you want a mechanical equilibrium, then just take in consideration the uniform linear motion. The resultant of the forces is null.
A 1-oz bullet is traveling with a velocity of 1400 ft/s when it impacts and becomes embedded in a 5-lb wooden block. The block can move vertically without friction. Determine (a) the velocity of the bullet and block immediately after the impact, (b) the horizontal and vertical components of the impulse exerted by the block on the bullet.
After impact velocity = 14.968 ft/s
Weight and mass of Bullet and wooden block:
Bullet: w = 1oz = 1/16 lb m = 0.001941 lb
wooden block : W = 5lb M = 0.15528 lb
velocity of block and bullet immediately after impact:
Σmv1 + ΣImp = mv2
Resolving vertical component
( m× v₀cos30⁰) + 0 = ( m+M) v'
v' = ( m× v₀cos30⁰)/ (m+M)
v' = 14.968 ft/s
Horizontal and vertical component of the impulse exerted by block on the bullet:
Here we will apply the principle of impulse and momentum.
Horizontal component:
-mv₀ cos30⁰ + RxΔt =0
RxΔt = mv₀sin30⁰
= 0.001941 × 1400sin30⁰
RxΔt = 1.3587 lb.s
Vertical component:
-mv₀cos30⁰ + RyΔt = -mv'
RyΔt = m( v₀cos30⁰-v')
RyΔt = 0.001941(1400cos30⁰ - 14.968)
= 2.32 lb.s
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A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/s velocity. The car uniformly accelerates to the velocity 35m/s in 20 seconds, the moves at a constant speed for 5 seconds. How long will it take for the car to catch up to the truck.
Answer:
At [tex]t = (70 / 3) \; {\rm s}[/tex] (approximately [tex]23.3 \; {\rm s}[/tex].)
Explanation:
Note that the acceleration of the car between [tex]t = 0\; {\rm s}[/tex] and [tex]t = 20\; {\rm s}[/tex] ([tex]\Delta t = 20\; {\rm s}[/tex]) is constant. Initial velocity of the car was [tex]v_{0} = 0\; {\rm m\cdot s^{-1}}[/tex], whereas [tex]v_{1} = 35\; {\rm m\cdot s^{-1}}[/tex] at [tex]t = 20\; {\rm s}\![/tex]. Hence, at [tex]t = 20\; {\rm s}\!\![/tex], this car would have travelled a distance of:
[tex]\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}[/tex].
At [tex]t = 20\; {\rm s}[/tex], the truck would have travelled a distance of [tex]x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}[/tex].
In other words, at [tex]t = 20\; {\rm s}[/tex], the truck was [tex]400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}[/tex] ahead of the car. The velocity of the car is greater than that of the truck by [tex]35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}[/tex]. It would take another [tex](50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}[/tex] before the car catches up with the truck.
Hence, the car would catch up with the truck at [tex]t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}[/tex].
A lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms , what is the average electric current in the lightning?
The average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A
Why Lightning Conductors on top of a tower ?The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.
Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.
one charge = 1.6 × [tex]10^{-19}[/tex] C
Average current I = Q/t
Where
Q = charge = 1.6 × [tex]10^{-19}[/tex] Ct = time = 2ms = 2 × [tex]10^{-3}[/tex] sI = current = ?Substitute all the parameters into the formula
I = 1.6 × [tex]10^{-19}[/tex] C ÷ 2 × [tex]10^{-3}[/tex]
I = 8 × [tex]10^{-17}[/tex] A
Therefore, the average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A
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You are looking down on a 20 kg beam resting on a horizontal, frictionless surface. The beam is 2 m long and can pivot about one end. A small 0.1 kg rock slides across the surface at 400 m/s and hits the middle of the beam, embedding itself inside. What is the angular speed of the rod after the impact (in rad/s)
The angular speed of the rod after the impact is 1.49 rad/s
What is angular speed?
The rate of change of angular displacements is known as angular speed.
Angular speed is a scalar measure of the rotating object.
What is Angular momentum?
It is the property of a rotating body given by the product of the moment of inertia and the angular velocity of the rotating object.
Angular momentum is expressed as follows:
L=m*v*r
Here,
mass of beam, M =20 kg
mass of rock, m =0.1 kg
length of the beam, L =2 m
length where rock slides, l = (L / 2), l = 1 m
velocity of rock, v =400 m/s
As here the Torque on which the system is zero implies that the angular momentum is conserved.
Initial angular momentum for rock: I(ri) = m*v*r
Final angular momentum for rock: I(rf) = m*w*r^2
Final angular momentum for beam: I(bf) = 1/3 (M*L^2w)
Now, According to the conservation of momentum:
m*v*r = m*w*r^2 + 1/3 (ML^2w)
w = m*v*r / ( mr^2 + 1/3 ML^2 )
w = 0.1 *400*1 / ( (0.1 * 1) + 1/3 20* 2^2 )
w = 1.49 rad / s
The angular speed of the rod after the impact is 1.49 rad/s
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Find the location of the object at times 0,1,2,. 1,000. Save the x-coordinates of the object at each time in a 1 ×1001 row vector named a11. Save t
The x-coordinates of the object at each time in a 1 ×1001 row vector named a11 using coordinate.
Coordinates are distances or angles, represented by numbers, that uniquely perceive factors on surfaces of dimensions (second) or in space of 3 dimensions.
Coordinates are hard and fast values that help to expose the exact position of a factor within the coordinated aircraft. A coordinate aircraft is a 2nd plane that's shaped by the intersection of perpendicular traces known as the x-axis and y-axis.
clear all
close all
alpha=-0.003;
w=0.05;
A=[1-alpha,-w;w,1-alpha];
A_inv=inv(A);
x0=[1;-1];
ans1=[1];
ans2=[-1];
for i=1:1000
x0=A_inv*x0;
ans1(i+1)=x0(1);
ans2(i+1)=x0(2);
end
ans1
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When starting a foot race, a 64 kilogram sprinter exerts an average force of 693 newtons backward on the ground for 0.59 seconds. how far does he travel in meters during this time?
The distance traveled by the sprinter in meters is determined as 1.88 m.
Acceleration of the sprinterThe acceleration of the sprinter is the rate of change of velocity of the sprinter with time.
The acceleration of the sprinter is calculated as follows;
Apply Newton's second law of motion as follows;
F = ma
a = F/m
where;
F is the applied force by the sprinterm is mass of the sprintera is acceleration of the sprintera = 693 N / 64 kg
a = 10.83 m/s²
Distance traveled by the sprinterThe distance traveled by the sprinter is calculated as follows;
s = ut + ¹/₂at²
where;
u is initial velocity = 0s = ¹/₂at²
where;
t is time of motiona is accelerations = (0.5)(10.83)(0.59²)
s = 1.88 m
Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.
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Which mineral property is the least useful for identifying minerals, and why?
A fireworks shell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m. How long did the acceleration last
The acceleration lasted for 0.007s.
To find the answer, we need to know about the Newton's equation of motion.
What's the Newton's equation of motion that relates initial velocity, final velocity, acceleration, time and distance?Newton's equations are
V²-U²= 2aSV²-U²= 2aSV= U+atV= final velocity, U= initial velocity, a= acceleration, t= time and S = distance
What's the acceleration, if the fireshell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m?Here, U= 0m/s, V= 60.0 m/s, S= 0.200 m60²-0= 2a×0.2= 0.4a
a= 3600/0.4= 9000m/s²What's the time taken by the fireshell to achieve 60m/s with 9000m/s² acceleration from rest?Here, U= 0m/s, V = 60.0 m/s, a= 9000m/s²60= 0+9000tt= 60/9000= 0.007 sThus, we can conclude that the acceleration of the fireshell lasted for 0.007s.
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A 500 watt heater carries a current of 4 A. What is the voltage across the ends of the heating element
The voltage across the ends of the heating element is 125 volts.
VoltagePower = 500J/s = 500 Watts. I = 4A
V*I = 500
V = 500/I = 500/4 = 125 Volts.
The difference between two points' electric potentials, also known as electric potential difference, electric potential pressure, or electric tension, is what moves a test charge between the two points in a static electric field. The derived unit for voltage (potential difference) in the International System of Units is called volt. 166 Work per unit charge is stated in SI units as joules per coulomb, with 1 volt equaling 1 joule (of work) for 1 coulomb (of charge). The quantum Hall and Josephson effect was first used to define the volt in the old SI system in 1990. More recently, fundamental physical constants have been included to the definition of the volt in the new SI system.
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The amount of excess load that can be imposed on the wing of an airplane depends upon the:.
The amount of excess load that can be imposed on the wing of an airplane depends upon the speed of the airplane.
What is meant by wing loading?
Wing loading in aerodynamics is the ratio of the loaded weight of the aircraft and the area of each wing. It is given as:
W_L = W (weight of the aircraft) / S (gross wing area of the airplane)
The more speed an aircraft gains, the more lift is produced by each unit of wing area.
Thus, with a high value of wing loading the aircraft lands and takes-off at higher speeds with low maneuvering control. Generally, Airliners have high wing loading while smaller airplanes have lower wing loading.
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A see-saw is balanced on its
midpoint. A 22.4 kg kid sits on the left, 1.75 m from the axis. A second kid sits on the other side, 1.22 m from the axis. What is the mass of the second kid?
Answer:
W1 L1 = W2 L2 equation for balancing torques
M1 g L1 = M2 L2 g
Or M2 = M1 * 1.75 / 1.22 = 1.43 M1 = 32.1 kg
Why is it that astronomers rely upon the 21-centimeter line associated with the spin flip in hydrogen and not the more familiar hydrogen Balmer lines to gather information from the far side of the galactic plane
Hydrogen, the element that is by far the most prevalent in the universe, exhibits radio emissions with a wavelength of 21 centimetres.
This makes it practical for using radio waves to explore space objects. An object in space emits radio waves that are more noticeable the more hydrogen it has.
What is a Galactic plane ?The majority of a disk-shaped galaxy's mass is located on the galactic plane. The galactic poles are shown by directions that are perpendicular to the galactic plane.
The Galaxy is divided in half by the planetary plane (top and bottom). The celestial equator is at an angle of 63 degrees with the galactic plane, whereas the ecliptic is at an angle of 60 degrees.The poles of all three coordinate systems each point in a different sky direction.Learn more about Galactic plane here:
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A student is given a box containing ten similar plastic drinking straws, a 30 cm ruler and two set-squares. (a) Explain how the student determines an average value for the external diameter of the straws using this apparatus. Draw a diagram to illustrate your answer.
The way to perform the experiment is illustrated below.
How to perform the experiment?Place each straw tightly without deforming the roundness of the straw into the corner of the set square.
Measure the distance from the corner of the set square to where the straw touches the set square using the 30 cm ruler. This will be the radius of each straw.
Multiply this radius by 2 in order to obtain the diameter of each straw.
Sum the diameter of each of the 10 straws.
Divide this sum by 10 to obtain the average value for the diameter of a straw.
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