The probability that a graduate of the Faculty of Finance will defend the diploma “excellent” is 0.6. The probability that he will defend his diploma “perfectly” and receive an invitation to work at the bank is 0.4. Suppose a student defends a diploma. Find the probability that he will receive an invitation to work in a bank?

Answer:

196 in/cm/m²

Step-by-step explanation:

Given that the scale factor is a : b , then the area factor is a² : b² Here the scale factor is 1 : 7 , thus area scale factor is 1² : 7² = 1 : 49 That is the area of the dilated square is 49 times the original square. area of dilated square = 4 × 49 = 196 in/cm/m²

Answer:

The probability of raining if the number of days is more than 23 is 0.0668.

Step-by-step explanation:

We are given that the mean number of days to observe rain in a particular city is 20 days with a standard deviation of 2 days.

Let X = Number of days of observing rain in a particular city.

The z-score probability distribution for the normal distribution is given by;

                         Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean number of days = 20 days

           [tex]\sigma[/tex] = standard deviation = 2 days

So, X ~ Normal([tex]\mu=20, \sigma^{2} = 2^{2}[/tex])

Now, the probability of raining if the number of days is more than 23 is given by = P(X > 23 days)

        P(X > 23 days) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{23-20}{2}[/tex] ) = P(Z > 1.50) = 1 - P(Z [tex]\leq[/tex] 1.50)

                                                              = 1 - 0.9332 = 0.0668

The above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.

If you want to form a square of 7500 soldiers, the side of the square must be [tex]\sqrt{7500}\approx86.6[/tex] soliders.

But since you cannot have 0.6 solider, the general needs to find the closest perfect square to the number 7500 which is less than 7500.

That number is 7396 which when square rooted gives 86 soliders on the side.

Subtract 7396 from 7500 and get how many soliders were left out,

[tex]7500-7396=\boxed{104}[/tex]

Hope this helps :)

Answer:

  -864

Step-by-step explanation:

The determinant of a matrix product is the product of the determinants. The determinant of a transpose is the same as the determinant of the original. Hence ...

  [tex]|AB^5C^T|=(4)(-2)^5(\frac{1}{4})=-32[/tex]

The multiplication of an n×n matrix by a scalar 'a' multiplies its determinant by a^n, so the desired determinant is ...

  [tex]|3AB^5C^T|=3^3(-32) = \boxed{-864}[/tex]

Answer:

C, 39.3 in²

Step-by-step explanation:

Lets first find the area of the rectangle part of the house.

To find the area of a rectangle its base × height.

So its 6×4=24 in².

Now lets find the area of the top triangle.

Area for a triangle is (base × height)/2.

The height is 3 inches, because its 7-4. While the base is 6 inches.

(6×3)/2=9 in².

To find the area of the half circle the formula, (piR²)/2.

The radius of the circle is 2 because its half of the diamter which is 4.

(pi2²)/2=6.283 in².

Now we just need to add up the area of every part,

24+9+6.283=39.283in²

Answer:

1/8

Step-by-step explanation:

3/8-1/8-1/8=1/8

Answer:

yes

Step-by-step explanation:

every negative any positive number is an integer

Answer:

Step-by-step explanation:

No.  Integers do not have fractions in them.

-2.75 is equivalent to -275/100, which is a fraction that does not reduce to an integer

Answer:

=  -2w + 22

Step-by-step explanation:

  -3(2w - 6) + 4(w+1)

= (-3*2w -3*-6) + (4*w + 4*1)

=  -6w + 18 + 4w + 4

= -6w + 4w + 18 + 4

= -2w + 22

Answer:

t=1, u=-2, w=-2

Step-by-step explanation:

Answer:

multiplication prop of equality, (multiplying both sides by 6)

simplifying, (not distrib prop as there is no parentheses)

Addition prop of equality, (adding 18 to each side)

simplifying

x = number of 1-cent stamps

y = number of 8-cent stamps

z = number of 12-cent stamps

We have 31 stamps all together, so x+y+z = 31.

"I have 4 more 1-cent stamps than 8-cent stamps" means we have the equation x = y+8. Whatever y is, add 8 to it to get x. Solve for y to get y = x-8.

You also have "twice as many one cent stamps as 12 cent stamps", so x = 2z. Solving for z gets you z = 0.5x

-------------

x+y+z = 31

x+x-8+z = 31 ... y replaced with x-8

x+x-8+0.5x = 31 ... plug in z = 0.5x

2.5x-8 = 31

2.5x = 31+8

2.5x = 39

x = 39/2.5

x = 15.6

Your teacher made a typo somewhere because we should get a positive whole number result for x (since x is a count of how many 1-cent stamps we have).

The number of one-cent stamps is 14.

Total stamps = 31
We have three types of stamps: 1-cent stamps, 8-cent stamps, and 12-cent stamps.

The person has 4 more 1-cent stamps than 8-cent stamps.

The person has twice as many 1-cent stamps as 12-cent stamps.

We have to make equations with the given above statement.

Consider,

1-cent stamp = A

8-cent stamp = B

12-cent stamp = C

4 more 1-cent stamps than 8-cent stamps: A = 4 + B.

A = 4 + B

B = A - 4..........(1)

Twice as many 1-cent stamps as 12-cent stamps: A = 2C.

A = 2C

C = A/2...............(2)

Total number of stamps = 31

A + B + C = 31................(3)

Putting (1) and (2) in (3)

we get,

A + ( A - 4 ) + A / 2 = 31

A + A - 4 + A / 2 = 31

2A - 4 + A / 2 = 31

2A + A / 2 = 31 + 4

(4A + A) / 2 = 35

4A + A = 35 x 2

5A = 70

A = 70 / 5

A = 14

Thus the number of 1-cent stamps is 14.

Learn more about similar problems here:

https://brainly.com/question/16959755

#SPJ5

5X + 8 = 53

5X = 53 - 8

X = 45 / 5

X = 9

Answer:

X=9

Step-by-step explanation:

5X+8=53

To solve this we need to make X the subject of the equation that means X should be alone on one side of the equation. Taking the following steps

5X=53-8

5X=45

X=45/5

X=9

6 pounds of strawberries and 1 pound of blueberries

I did the quiz

By the fundamental theorem of calculus,

[tex]E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du[/tex]

So we have

[tex]E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du[/tex]

[tex]E(t)=92+(75u-3u^2)\bigg|_1^t[/tex]

[tex]E(t)=20 + 75 t - 3 t^2[/tex]

Answer:

Any value that has x less than or equal to 19 is a solution

Step-by-step explanation:

x – 5 ≤ 14

Add 5 to each side

x – 5+5 ≤ 14+5

x  ≤ 19

Any value that has x less than or equal to 19 is a solution

Answer:

[tex]\boxed{x\leq 19}[/tex]

Step-by-step explanation:

[tex]x-5\leq 14[/tex]

[tex]\sf Add \ 5 \ on \ both \ sides.[/tex]

[tex]x-5+5 \leq 14+5[/tex]

[tex]x\leq 19[/tex]

This question is incomplete.

Complete Question

Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She receives a delivery of 4 tons of wood each day. The deliveries can continue for 100 days at most, afterwards the weather is too bad to allow them. Overall, she wants to build enough ships to accommodate at least 2100 sailors. How much wood does Astrid need to accommodate 2100 sailors?

Answer:

280 tons of wood.

Step-by-step explanation:

From the above question:

To make 1 ship = we require 40 tons of wood.

1 ship = can accommodate 300 sailors.

Step 1

If :

300 sailors = 1 ship

2100 sailors = y ships

Cross Multiply

300 × y ships = 1 ship × 2100 sailors

y ships = 2100 / 300

y ships = 7

Hence, 2100 sailors can occupy 7 ships.

Step 2

We are told in the question that:

Astrid wants to build enough ships to accommodate at least 2100 sailors. How much wood does Astrid need to accommodate 2100 sailors?

If:

1 ship = 40 tons of wood

Since 7 ships can accommodate 2100 sailors,

7 ships =

7 × 40 tons of wood = 280 tons of wood.

Therefore , Astrid needs 280 tons of wood to accommodate 2100 sailors.

Answer:

7 pi cm^2 or  approximately 21.98 cm^2

Step-by-step explanation:

First find the area of the large circle

A = pi r^2

A = pi 3^2

A = 9 pi

Then find the area of the small unshaded circle

A = pi r^2

A = pi (1)^2

A = pi

There are two of these circles

pi+ pi = 2 pi

Subtract the unshaded circles from the large circle

9pi - 2 pi

7 pi

If we approximate pi as 3.14

7(3.14) =21.98 cm^2

Answer:

[tex]\boxed{\sf 7\pi \ cm^2 \ or \ 21.99 \ cm^2 }[/tex]

Step-by-step explanation:

[tex]\sf Find \ the \ area \ of \ the \ two \ smaller \ circles.[/tex]

[tex]\sf{Area \ of \ a \ circle:} \: \pi r^2[/tex]

[tex]\sf r=radius \ of \ circle[/tex]

[tex]\sf There \ are \ two \ circles, \ so \ multiply \ the \ value \ by \ 2.[/tex]

[tex](2) \pi (1)^2[/tex]

[tex]2\pi[/tex]

[tex]\sf Find \ the \ area \ of \ the \ larger \ circle.[/tex]

[tex]\sf{Area \ of \ a \ circle:} \: \pi r^2[/tex]

[tex]\sf r=radius \ of \ circle[/tex]

[tex]\pi (3)^2[/tex]

[tex]9\pi[/tex]

[tex]\sf Subtract \ the \ areas \ of \ the \ two \ circles \ from \ the \ area \ of \ the \ larger \ circle.[/tex]

[tex]9\pi -2\pi[/tex]

[tex]7\pi[/tex]

Answer:

33 Litres

Step-by-step explanation:

Answer:

B. The graph of function f is stretched horizontally by a scale factor of 3 to create the graph of function g.

Step-by-step explanation:

The rules for linear transformations are that

 g(x) = a·f(b·(x-c)) +d

stretches the graph vertically by a factor of "a" (before the shift)

compresses the graph horizontally by a factor of "b" (before the shift)

shifts it to the right by amount "c"

shifts it up by amount "d".

Your equation has b=1/3, so the graph is compressed by a factor of 1/3, which is equivalent to a stretch by a factor of 3.

The appropriate choice of description is ...

 b) the graph of g(x) is horizontally stretched by a factor of 3

Answer:

B

Step-by-step explanation:

Correct on Plato

Answer:

A  has the points plotted correctly

Step-by-step explanation:

We need to plot the data

A  has the points plotted correctly

B  has the point ( 10,5) plotted on (9,5)

C is missing (-6,-5)

D is missing (-6,-5) and has (-2,1) instead of (-2,-1)

Answer:

A.

Step-by-step explanation:

It would be very helpful to write the points individually from the data. Take the x value and place it with its corresponding y value:

(1,4) ; (2,2) ; (-2,-1) ; (-2,-6) ; (5,-4) ; (-6,-5) ; (10,5)

Now find the graph that has each of these points. You can write these down and cross them out if you find them on the graph, and once you find the graph where all of these points are crossed out, that's the correct graph.

The correct graph is A.

:Done

9514 1404 393

Answer:

  C. symmetric with respect to the origin

Step-by-step explanation:

A graph must pass the vertical line test to be called the graph of a function. No function will ever be symmetrical with respect to the x-axis, because that would mean it fails the vertical line test.

An even function is symmetrical about the y-axis. An even function has the characteristic that ...

  f(-x) = f(x) . . . . an even function

An odd function is symmetrical about the origin. An odd function has the characteristic that ...

  f(-x) = -f(x)

__

The given function is f(x) = -1/x. Then the value of f(-x) is ...

  f(-x) = -1/-x = 1/x = -f(x)

The given function is an odd function, so is symmetrical about the origin.

Answer:

Hello,

answer C

Step-by-step explanation:

[tex]\begin{array}{|c|c|c|c|}x&y&x^2&3x^2\\---&---&---&---\\1&3&1^2&3*1^2=3\\2&12&2^2&3*2^2=12\\3&27&3^2&3*3^2=27\\4&48&14^2&3*4^2=48\\5&75&5^2&3*5^2=75\\\end{array}\\\\\\\boxed{y=3x^2\ the\ function\ is\ quadratic.}[/tex]

Answer:

-1

Explanation:

Let the number be x.

Then the equation will be:

3(x+18) = 51

=> 3x + 54 = 51

=> 3x = 51 - 54

=> 3x = -3

=> x = -3/3

=> x = -1

So, the number you thought of is -1.

Answer:

The number is 3.

Step-by-step explanation:

[tex]3(14+x)=51\\42+3x=51\\3x=9\\x=3[/tex]

Answer:

0.0090483

Approximately = 0.00905

Step-by-step explanation:

z = (x - μ)/σ, where

x is the raw score = 3.74

μ is the sample mean = population mean = 4 mm

σ is the sample standard deviation

This is calculated as:

= Population standard deviation/√n

Where n = number of samples = 100

σ = 1.1/√100

σ = 1.1/10 = 0.11

z = (3.74 - 4) / 0.11

z = -2.36364

Using the z score table to determine the probability,

The probability that the average thickness of the 100 sheets is less than 3.74 mm

P(x<3.74) = 0.0090483

Approximately = 0.00905

Using the normal distribution and the central limit theorem, it is found that there is a 0.0091 = 0.91% probability that the average thickness of the 100 sheets is less than 3.74 mm.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The probability is the p-value of Z when X = 3.74, then:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{3.74 - 4}{0.11}[/tex]

[tex]Z = -2.36[/tex]

[tex]Z = -2.36[/tex] has a p-value of 0.0091.

0.0091 = 0.91% probability that the average thickness of the 100 sheets is less than 3.74 mm.

A similar problem is given at https://brainly.com/question/14228383

Answer:

see below

Step-by-step explanation:

Let r = amount of the 7% solution

y represent the amount of the 15 percent solution

.07r + .15 y = (r+y) .12

r+y = 20

y = 20-r

.07r + .15 (20-r) = (20) .12

0.07r+0.15(20-r)=2.4

.07r+ 3 - .15r = 2.4

-.08r = 2.4-3

-.08r = -.6

Divide by-.08

r =7.5 Liters of the 7%

y = 20-7.5

y = 12.5 L of 12%

Check

.07 *7.5 + .15 (12.5) =20*.12

.525+1.875=2.4

2.4=2.4

Answer:

Yes it is reasonable to conclude the mean rate charged is greater than 14%

Step-by-step explanation:

From the question we are told that

    The  population mean is  [tex]\mu = 0.14[/tex]

    The sample size is  [tex]n = 10[/tex]

    The  sample mean is  [tex]\= x = 0.1564[/tex]

     The  standard deviation is  [tex]\sigma = 0.01561[/tex]

     The level of significance is  [tex]\alpha = 0.01[/tex]

The null hypothesis is    [tex]H_o: \mu = 0.14[/tex]

The  alternative hypothesis is  [tex]H_a : \mu > 0.14[/tex]

 Generally the test statistic is mathematically represented as

              [tex]t = \frac{ \= x - \mu }{ \frac{\sigma }{\sqrt{n} } }[/tex]

substituting values

              [tex]t = \frac{ 0.1564 - 0.14 }{ \frac{0.01561 }{\sqrt{10} } }[/tex]

              [tex]t = 3.322[/tex]

Now the p-value obtained from the z-table is

        [tex]p-value = P(t > 3.322) = 0.00044687[/tex]

Since the [tex]p-value < \alpha[/tex] then we reject the null hypothesis, hence we can conclude that  the mean rate charged is greater than 14%

Answer:

the domain is all real numbers

The answer is -13.8.

Hope this helps!