the sum of a number and six is ten. find the number



​

Answer:

Center: (3, - 4)

Step-by-step explanation:

We can start to solve this problem by converting this equation into standard form. In other words, by completing the square --- (1)

Subtract " 10 " from either side of the equation x² + y² - 6x + 8y + 10 = 0

x² + y² - 6x + 8y = - 10

Step 1: Complete the square for the expression " x² - 6x "

Using the quadratic equation ax² + bx + c we know that a = 1, b = - 6, c = 0. Assume that d = b / 2a. We have...

d = - 6 / 2(1) = - 6 / 2 = - 3

Now let's assume that e = c - (b²) / 4a...

e = 0 - (-6)² / 4(1) = 0 - 36 / 4 = 0 - 9 = 9 (Substitute values d and e)

(x - 3)² - 9

Step 2: Respectively we can complete the square for the remaining expression " y² + 8y "

Here a = 1, b = 8, c = 0

d = 8 / 2(1) = 8 / 2 = 4

e = 0 - (8)² / 4(1) = 0 - 64 / 4 = 0 - 16 = - 16 (Substitute values)

(y + 4)² - 16

This leaves us with the expression " (x - 3)² - 9 + (y + 4)² - 16 = - 10. " If we simplify this a bit further it leaves us with the following circle equation. Using this we can identify the center of the circle as well --- (2)

[tex]\mathrm{Standard}\:\mathrm{Circle}\:\mathrm{Equation} : (x - 3)^2 + (y +4)^2 = 15,\\\mathrm{General}\:\mathrm{Form} : (x - h)^2 + (y +k)^2 = r^2,\\\mathrm{Properties} : \mathrm{Center} = (3, - 4), \mathrm{Radius} = \sqrt{15}[/tex]

As you can see our center here is (3, - 4)

Answer: yes.

Step-by-step explanation:

adding 10 is moving the decimal point once to the right, so yes.

move the decimal point in 0.007 once to the right (multiply it by 10) and you get 0.07

Answer:

Yes

Step-by-step explanation:

Answer: $25

Step-by-step explanation:

Answer:

There is no sufficient evidence to support  the claim that the boards are either too long or too short

Step-by-step explanation:

From the question we are told that

   The  population mean is [tex]\mu = 2599.0[/tex]

    The sample size is  [tex]n = 23[/tex]

     The  sample mean is  [tex]\= x = 2600.3 \ mm[/tex]

    The  standard deviation is  [tex]\sigma = 13.0[/tex]

     The  level of significance is  [tex]\alpha = 0.05[/tex]

The  null hypothesis  is  [tex]H_o : \mu = 2599.0[/tex]

  The  alternative  hypothesis is [tex]H_a : \mu \ne 2599.0[/tex]

Generally the test statistics is mathematically represented as

            [tex]t = \frac{ \= x - \mu }{ \frac{\sigma}{ \sqrt{n} } }[/tex]

=>          [tex]t = \frac{ 2600.3 - 2599.0 }{ \frac{13}{ \sqrt{ 23} } }[/tex]

=>            [tex]t = 0.3689[/tex]

Now from the normal distribution table  the critical value  of  [tex]\alpha[/tex] is  

    [tex]Z_{\alpha } = 1.645[/tex]

Hence from the evaluated and obtained value we see that

    [tex]t < Z_{\alpha }[/tex]

Hence we fail to reject the null hypothesis  

  Thus we can conclude that there is no sufficient evidence to support  the claim that the boards are either too long or too short

Answer:

rational, Natural, Integer, whole

Step-by-step explanation:

remember your perfect squares

the sqrt of 25 is a perfect square

sqrt of 25 is 5

5 is all except irrational

Answer:

This is false

Step-by-step explanation:

Because we have to understand that some times sample mean may be very high that is they may be practically significant but are not statistically significant because the calculated p-value is not less than alpha value which could only mean that they could occur as a result of mere chance.

The required magic square using the numbers 6, 8, 10, 13, 15, 17, 20, 22, and 24 is   | 6   |   8    | 10 |

                  | 13  | 15    | 17  |

                  | 20 | 22   | 24 |.

A magic square is a square grid of numbers, typically integers, where the numbers in each row, column, and diagonal add up to the same constant value.

Here,
To create a magic square using the numbers 6, 8, 10, 13, 15, 17, 20, 22, and 24, we can follow these steps,

Start by placing the number 15 in the center square of the grid.

Place the number 6 in one corner of the grid. We'll choose the top left corner for this example.

Place the number 24 in the opposite corner. We'll choose the bottom right corner for this example.

Place the remaining numbers in the empty squares of the grid, following these rules:

a. If a square is already occupied, move to the next square in the same direction.

b. If you reach the edge of the grid, wrap around to the other side.

c. If you reach a square that is diagonally adjacent to a previously filled square, move to the next empty square in a clockwise direction.

Using these rules, we can fill in the rest of the grid as follows:

| 6   |   8    | 10 |

| 13  | 15    | 17  |

| 20 | 22   | 24 |

Learn more about magic square here:
https://brainly.com/question/28675556

#SPJ9

Answer:

C($)= (x²/2 +11x)5.75

Step-by-step explanation:

Let's assume the height= x

The base= x+22

Area= 1/2(base*height).

Area= 1/2((x+22)(x))

Area= x²/2 +11x

Cost per ft= $5.75

Cost for painting the triangular mural C

C($)= (x²/2 +11x)5.75

Answer:

y=3/4x

it passes through (-4,-3) on its own

Answer:

Length = X + 3

Step-by-step explanation:

Examples for the length width relationship would go as follows:

Width    Length

1              4

2             5

3             6

4             7

Hope this helps!

-TheBusinessMan

Answer:

Length = x + 3

Step-by-step explanation:

Width = x

Length = 3 + Width

So, Length = 3 + x

So, if Width as a number, then Length will be 3 more than that number.

Answer:

i think it would be 18 kids in the class

Step-by-step explanation:

since for every 4 boys there are 5 girls and so it means

so for every 10 girls there would be 8 boys

Answer:

(-17+7)-13 or -17-13+7

Step-by-step explanation:

Answer:

Step-by-step explanation: -17+7=10-13=-2

Answer: 7 pt

Step-by-step explanation:

1 U.S pt is 2 cups

take 14 divided by 2

= 7

Answer:

38.2, or 38 1/2

Step-by-step explanation:

Steps for Solving Linear Equation:

4=51.75−1.25x

Swap sides so that all variable terms are on the left hand side.

51.75−1.25x=4

Subtract 51.75 from both sides.

−1.25x=4−51.75

Subtract 51.75 from 4 to get −47.75.

−1.25x=−47.75

Divide both sides by −1.25.

x=−1.25−47.75​

Expand −1.25−47.75​≈38.2 by multiplying both numerator and the denominator by 100.

x=−125−4775​

Reduce the fraction −125−4775​≈38.2 to lowest terms by extracting and canceling out −25.

x=5191​

Answer:

in my opition is 2x(-7)

Step-by-step explanation:

hope it help

distribute the [tex]7[/tex] and [tex]5[/tex]:

[tex]7(4+t)-5(t+1)=\\28+7t -5t -5[/tex](collect like-terms)

[tex]28-5 +7t-5t=\\23+2t[/tex]

[tex]23+2t[/tex] or [tex]2t+23[/tex] is your answer. hope this helps <3

Answer:

Sample  1 : independent

Sample  2 :   dependent

Step-by-step explanation:

From the question we are told that

   The  given date is  

                   Sample 1: Pre-training blood pressure of 17 people

                    Sample 2: Post-training blood pressure of 17 people

Now  Sample 1 is independent because  the Pre-training blood pressure of 17 people does not depend of Post-training blood pressure of 17 people

While  

        Sample 2  is  dependent because the Post-training blood pressure of 17 people is  dependent on the Pre-training blood pressure of 17 people

Answer:

Option (2)

Step-by-step explanation:

From the picture attached,

Angle between HB and FG = 90°

Therefore, HB and FG are perpendicular segments.

HB ⊥ FG

Similarly, angle between HB and AC = 90°

Therefore, both the segments HB and AC will be perpendicular.

HB ⊥ AC

Since FG and AC are both perpendicular to HB.

Therefore, FG║AC.

Option (2) will be the correct option.

Answer:

A square is a closed, two dimensional shape with 4 equal sides.

It is also a quadrilateral.

Step-by-step explanation:

none :)

Answer:

(5,-6)

Step-by-step explanation:

Answer: 82 sq. units .

Step-by-step explanation:

Answer:

a = 60°

Step-by-step explanation:

Formula used:

[tex] \red{\boxed {\bold {\tan \: \theta = \cot \: (90\degree - \theta)}}} [/tex]

[tex] \tan \: 30 \degree = \cot \: a \\ \cot \: (90 \degree - 30 \degree) = \cot \: a \\ cot \: 60 \degree = \cot \: a \\ 60 \degree = a \\ \huge \red{ \boxed{ a = 60 \degree}}[/tex]

Answer:

-18

Step-by-step explanation:

So we have the expression:

[tex]a-6y[/tex]

And we want to evaluate it when y=2 and a=-6.

Substitute in these values:

[tex]=(-6)-6(2)[/tex]

Multiply:

[tex]=(-6)-12[/tex]

Subtract:

[tex]=-18[/tex]

Answer:

-18

Step-by-step explanation:

We are given the expression:

[tex]a-6y[/tex]

and asked to evaluate when a= -6 and y=2.

Therefore, we must substitute -6 in for a and 2 in for y.

[tex]a-6y , a=-6, y=2[/tex]

[tex](-6)-6(2)[/tex]

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Addition, and Subtraction.

Multiply 6 and 2.

[tex](-6)-(6*2)[/tex]

[tex](-6)-(12)[/tex]

[tex](-6)-12[/tex]

Subtract 12 from -6.

[tex](-6-12)[/tex]

[tex]-18[/tex]

The expression a-6y when evaluated for a=-6 and y=2 is equal to -18.

Answer: B

Step-by-step explanation: (3, 4) is 4 units above the x-axis

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

Step-by-step explanation:

4(3-U)+U = 22+2U

12-4U+U = 22 + 2U

12-5U= 22+2U

10=3U

U = 10/3

U= 3.3