The sum of four consecutive integers is 78. What
are the 3rd and 4th integers?

Answer:

less than 1

Step-by-step explanation:

Answer:

a = [tex]\frac{b^2-d}{4c}[/tex]

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

Question 1

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = [tex]\frac{b^2-d}{4c}[/tex]

Question 2

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate x by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

Answer:

9

Step-by-step explanation:

If α and β are the zeros of ax² + bx + c = 0 , then

α + β = [tex]\frac{-b}{a}[/tex] ( sum of zeros ) and

αβ = [tex]\frac{c}{a}[/tex] ( product of zeros )

Given

x² + 5x + 8 = 0

with a = 1, b = 5, c = 8 , with zeros a and b, then

a + b = [tex]\frac{-5}{1}[/tex] = - 5

ab = [tex]\frac{8}{1}[/tex] = 8

Thus

(a + b)² = a² + 2ab + b² , that is

(- 5)² = a² + 2(8) + b²

25 = a² + 16 + b² ( subtract 16 from both sides )

9 = a² + b²

Answer:It depends, many people do count 0 as a natural number, but MOST do not.

So for most HS text book, the answer is NO, all whole numbers are not natural numbers and the reason is 0 is a whole number but not a natural number.

Answer:

false

Step-by-step explanation:

because the set of whole numbers starts from 0 whereas the set of natural numbers starts from 1 and so on

Answer:

x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Step-by-step explanation:

Solve for x:

7 x^25 = 30

Hint: | Divide by an appropriate factor to make the coefficient of x^25 equal to 1.

Divide both sides by 7:

x^25 = 30/7

Hint: | Take 25^th roots of both sides.

Taking 25^th roots gives (30/7)^(1/25) times the 25^th roots of unity:

Answer: x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Answer:

Step-by-step explanation:

time=distance/speed

=4800/48

100

Answer:

[tex]\Huge \boxed{\mathrm{100 \ seconds}}[/tex]

Step-by-step explanation:

4.8 kilometers is 4800 meters.

[tex]\sf \displaystyle time \ (s) = \frac{distance \ (m) }{speed \ (m/s)}[/tex]

[tex]\sf \displaystyle t = \frac{4800}{48}[/tex]

[tex]\sf \displaystyle t = 100[/tex]

It will take the object 100 seconds.

Answer:

Total length of the trip = 600 miles

Step-by-step explanation:

Given:

Distance travel during sleep = 65%

Distance travel during sleep = 390 miles

Find:

Total length of the trip

Computation:

Total length of the trip = Distance travel during sleep [100 / 65]

Total length of the trip = 390 [100 / 65]

Total length of the trip = 600 miles

Answer:

40 feet

Step-by-step explanation:

60x40=2400

2400/2=1200

1200/30=40

Answer:

x=-16

Step-by-step explanation:

4x– 15 = 17 - 4x+10x

4x+4x-10x = 17+15

-2x=32

-x=16

x=-16

Answer:

It's 2 (z + 3)

Answer:

[tex]\pi=\frac{v}{hr^2}[/tex]

Step-by-step explanation:

So we have:

[tex]v=\pi r^2h[/tex]

And we want to solve for π.

First, divide both sides by h:

[tex]\frac{v}{h}=\pi r^2[/tex]

Now, divide both sides again by r²:

[tex]\pi=\frac{v}{hr^2}[/tex]

And this is our answer :)

Answer:

[tex]\frac{v}{r^{2} h} = \pi[/tex]

Step-by-step explanation:

Simply divide both sides by [tex]r^{2}h[/tex] to get pi by itself.

Answer:

what

Step-by-step explanation:

The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one. The Heart Is a Muscle. It also carries away waste. Your heart is sort of like a pump, or two pumps in one.

Answer:

Please see attached picture for full solution.

Answer:

The correct option is (a).

Step-by-step explanation:

We need to find the expression that is equivalent to 1.5(6x+3y)+2x-0.05y.

Firstly opening brackets as follows :

[tex]1.5(6x+3y)+2x-0.05y=1.5\times 6x+1.5\times 3y+2x-0.05y\\\\=9x+4.5y+2x-0.05y[/tex]

Now taking x terms and y terms together

[tex]9x+4.5y+2x-0.05y=(9x+2x)+(4.5y-0.05y)\\\\=11x+4.45y[/tex]

So, 1.5(6x+3y)+2x-0.05y is equal to 11x+4.45y.

Answer:

4ux³

Step-by-step explanation:

√8ux⁵ √2ux

√8*2 u*u x⁵*x

√16u²x⁶

4ux³

Answer:

2/3 probability or 66%

Step-by-step explanation:

hope this helps!!

Answer:

17

Step-by-step explanation:

Let x = the number we have to find

From the given information, we have this equation:

(x + 5) / 2 = 11

<=> x + 5 = 11 . 2 = 22

<=> x = 22 - 5 = 17

Answer: 17

Step-by-step explanation:

I guess you would have to guess and check for this one.

17+5= 22

22/2 = 11

hope this helps

Answer:

p = - 14

Step-by-step explanation:

Using the rules of exponents

[tex]a^{m}[/tex] ÷ [tex]a^{n}[/tex] = [tex]a^{(m-n)}[/tex]

[tex](a^{m}) ^{n}[/tex] = [tex]a^{mn}[/tex]

Note 81 = 9² and 729 = 9³

Given

[tex](81)^{-4}[/tex] ÷ [tex](729)^{2-p}[/tex]

= [tex](9^{2}) ^{-4}[/tex] ÷ [tex](9^{3}) ^{2-p}[/tex]

= [tex]9^{-8}[/tex] ÷ [tex]9^{6-3p}[/tex]

= [tex]9^{-8-(6-3p)}[/tex]

= [tex]9^{-8-6+3p}[/tex]

= [tex]9^{3p-14}[/tex]

Thus

[tex]9^{3p-14}[/tex] = [tex]9^{4p}[/tex]

Since bases on both sides are equal then equate the exponents

4p = 3p - 14 ( subtract 3p from both sides )

p = - 14

Answer:

Charmaine earns $60.90 for 6h for mowing and 1h for babysitting.

Step-by-step explanation:

We must write the data problems.

Charmaine = $8.80/h mowing

Charmaine = $8.10/h babysitting

How much will Charmaine earn for 6 h mowing and 1 h babysitting?

1 h mowing ....................... $8.80

6 h mowing ....................... $x

x = 6 h mowing * $8.80

x = $52,8

To find the total earn of Charmaine, we have to gather the earns from mowing and babysitting.

$52,8 (from mowing) + $8.10 (from babysitting) = $60.90

Answer:

this is true!

Step-by-step explanation:

its true lnfao.

Answer:

Step-by-step explanation:no different

Answer:

(1, -8)

Step-by-step explanation:

5(1) - (-8) =  5 + 8

= 13.

An ordered pair is represented by (x,y). The ordered pair that makes the sentence 5x- y > 12,  true is (1,-8)

Given that:

[tex]5x - y > 12[/tex]

First, we test each option

[tex](a)\ (3,4)[/tex]

So, we have:

[tex]5 \times 3 - 4 > 12[/tex]

[tex]15 - 4 > 12[/tex]

[tex]11 > 12[/tex] ---- This is false

[tex](b)\ (4,9)[/tex]

So, we have:

[tex]5 \times 4 - 9 > 12[/tex]

[tex]20 - 9 > 12[/tex]

[tex]11> 12[/tex] --- This is false

[tex](c)\ (1,-8)[/tex]

So, we have:

[tex]5 \times 1 --8 > 12[/tex]

[tex]5 +8 > 12[/tex]

[tex]13 > 12[/tex] --- This is true

[tex](d)\ (0,-10)[/tex]

So, we have:

[tex]5 \times 0--10 > 12[/tex]

[tex]0+10>12[/tex]

[tex]10>12[/tex] ---- This is false

[tex](e)\ (-1,-17)[/tex]

So, we have:

[tex]5 \times -1 --17 > 12[/tex]

[tex]-5 +17 > 12[/tex]

[tex]12 > 12[/tex] --- This is false

Hence, the ordered pair that makes [tex]5x - y > 12[/tex], true is: [tex](c)\ (1,-8)[/tex]

Learn more about ordered pair at:

https://brainly.com/question/13688667

Answer:

12.2 cm

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )

Here A = 20.74 and b = 3.4 , thus

[tex]\frac{1}{2}[/tex] × 3.4 × h = 20.74 ( multiply both sides by 2 to clear the fraction )

3.4h = 41.48 ( divide both sides by 3.4 )

h = 12.2 cm

h = 12,2 cm

Area formula

A = b×h/2

20.74 = 3.4×h/2

41.48 = 3.4h

h = 41.48/3.4

h = 12,2 cm

Answer:

-5 times 12 is a binomial

Step-by-step explanation:

two terms = binomial

HOWEVER IF IT's -5.12 then it's a monomial because it's one term

Answer:

yes that answer is true

Answer:

volume is the correct answer

Step-by-step explanation:

TO FIND: construct 3 equation starting with x=5?

SOLUTION:

The equation is in the form of variable and constant equating.

Let the equation be x=5.

TO CREATE AN EQUATION,

FIRST WE ADD 5 BOTH SIDe,

x + 5=5+5

=x + 5=10

SECOND WE SUBRACT 5 BOTH SIDE,

x — 5=5—5

=x—5=0

THIRD WE MULTIPLY 5 BOTH SIDE,

5x=5×5

=5x=25

well u got the answer!

Answer:

We need to find the value of b to make 8b - 27 be equal to 5, so:

8b - 27 = 5

We solve the equation:

8b = 5 + 27

8b = 32

We divide both sides by 8:

b = 32/8 = 4

So now, we know that b=4, and we can verify:

8*4 - 27 = 5

32 - 27 = 5 TRUE

patrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convexpatrulater convex