Answer:
The mother (Rhoda) is 46 years old.
The daughter (Tenica) is 18 years old
Step-by-step explanation:
Let the age of the mother (Rhoda) be m
Let the age of the daughter (Tenica) be d.
The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:
m + d = 64 ... (1)
The difference in their ages is 28. This can be written as:
m – d = 28 ... (2)
From the above illustrations, the equation obtained are:
m + d = 64 ... (1)
m – d = 28 ... (2)
Solving by elimination method:
Add equation 1 and 2 together
. m + d = 64
+ m – d = 28
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
2m = 92
Divide both side by 2
m = 92/2
m = 46
Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1
m + d = 64
m = 46
46 + d = 64
Collect like terms
d = 64 – 46
d = 18
Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.
PLS HELP ME ON THIS QUESTION I WILLL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Which of the following measures is a measure of spread?
A. median
B. range
C. mode
D. mean
Answer:
B) Range
Step-by-step explanation:
Hope this will help you
Answer:
Range
Step-by-step explanation:
I hope this will help buddy
17. PLEASE HELP ME
The area of a playground is 160 yd2. The width of the playground is 6 yd longer than its length. Find the length and width of the playground.
A. length = 16 yd, width = 22 yd
B. length = 16 yd, width = 10 yd
C. length = 22 yd, width = 16 yd
D. length = 10 yd, width = 16 yd
Answer:
b
Step-by-step explanation:
16x10=160
Solve for x(in picture).
Answer:
x = 1/8
Step-by-step explanation:
[tex]\log _2\left(x\right)=-3\\\\\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c\\\\\log _2\left(x\right)=-3\quad \Rightarrow \quad \:x=2^{-3}\\\\Simplify\\\\x=\frac{1}{8}[/tex]
write in the form of p/q, 0.785 (bar on 85)
please to spam anything except answer....TOMORROW EXAM
The expression of 0.785 in the form p/q is 157/200
The ratio is defined as a way of dividing a variable by another variable.
For instance, p/q can be described as the ratio of p to q where p and q are integers.Given the decimal number 0.785, to convert to fraction, we will place divide 785 by 1000 (since the decimal is on thousandth)
0.785 = 785/1000
Express in its simplest form
785/1000 = 157/200
Hence 0.785 written in the form p/q is 157/200 where p = 157 and q = 200.
Learn more on ratio here: https://brainly.com/question/19473677
Which of the variable expressions below is a trinomial with a constant term? A. 3x5 – 2x3 B. x5 – 3x2 + 5x C. 7x6 + 2x4 – x3 + 7 D. 4x2 – 3 + x3
Answer:
Option (D)
Step-by-step explanation:
Option (A).
3x⁵ - 2x³
There are two terms with the variable 'x' in the given expression. therefore, it's a binomial with no constant term.
Option (B).
x⁵ - 3x² + 5x
This expression has three terms with variable 'x'.
Therefore, it's a trinomial without no constant term.
Option (C).
7x⁶ + 2x⁴ - x³ + 7
It's a quadrinomial having 4 terms. '7' is the constant term in the given expression.
Option (D).
4x² + x³ - 3 ≈ x³ + 4x² - 3
It's a trinomial with a constant term 3.
Therefore, Option (D) is the answer.
c(x)=2x^2-4x-3 find c(-4)
Answer:
45
Step-by-step explanation:
c(x)=2x^2-4x-3
Let x= -4
c(-4)=2(-4)^2-4(-4)-3
= 2(16) +16-3
=32+16-3
45
Answer:
45
Step-by-step explanation:
c(-4) = 2(-4)² - 4(-4) - 3
= 2(16) + 16 - 3
= 32 + 13
= 45
please help me i offered all my points and this is really important!!! The question is attached.
Answer:
25[tex]\sqrt{3}[/tex] +60
Step-by-step explanation: The first thing you need to do is realize that, this figure is a isosceles trapezoid due to the markings on each side.
So now we know both sides are 10.
We also know the the top two angles are congruent to each other and so are the bottom two angles due to the trapezoid being isosceles.
So the top two angles are 120 degrees and bottom two angles are 60 degrees.
It seems like we can't find the sides, let's try drawing two lines from each top angle all the way down to form two right triangles.
Wow, these two triangles are special right triangles in the form of
30 - 60 - 90 degrees.
shorter side = n
longer side = n[tex]\sqrt{3}[/tex]
hypotenuse = 2n
So, 2n = 10
n = 5 for the short side
The bottom base is 4[tex]\sqrt{3}[/tex] + 5 + 5 = 10 + 4[tex]\sqrt{3}[/tex]
The longer side is 5[tex]\sqrt{3}[/tex].
The area of trapezoid = (base1 + base2)/2 * height
= (4[tex]\sqrt{3}[/tex] + 10 + 4[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (10 + 8[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (5+4[tex]\sqrt{3}[/tex])*5[tex]\sqrt{3}[/tex] = 25[tex]\sqrt{3}[/tex] +60
So, 25[tex]\sqrt{3}[/tex] + 60 is our answer.
Answer:
60 +25√3
Step-by-step explanation:
In the figure of the isosceles trapezoid below, the angles at C and D are supplementary to the given angle, so are 60°. That makes triangle BDE a 30°-60°-90° right triangle, which has side length ratios ...
DE : BE : BD = 1 : √3 : 2 = 5 : 5√3 : 10
Triangle BDE can be relocated to the other end of the figure to become triangle CAD'. Then the area of concern is that of the rectangle with height 5√3 and length 5+4√3. The area is then ...
Area = lh = (5√3)(5 +4√3) = 5·5√3 +5·4·3
Area = 60 +25√3 . . . square units
_____
In the figure, 6.93 = 4√3, and 8.66 = 5√3, 16.93 = 10+4√3.
HELP ASAP WILL MARK BRAINLIEST!!!!!! Use the number line below, where RS=9y+2, ST = 4y+9 and RT = 115. a. What is the value of y? b. Find RS and ST. a. What is the value of y?
Answer: y = 7
Step-by-step explanation:
At a parking lot, the ratio of people to cars is 3 : 5. If there are 30 people, how many cars are there? *
Answer:
50 cars
Step-by-step explanation:
Let's define p as the number of people and c the number of cars.
We know that p / c = 3/5 or in other words, there are 5 cars every 3 people. If we have 30 people means that p = 30 which implies 30/c = 3/5 which implies c = 5/3 * 30 = 50.
Answer:
Step-by-step explanation:people=30=3/5
30/5=6*3=18
car=30=5/3
30/3=10
10*5=50
so there are 50 cars there
A dinner at a restaurant was advertised at $60 plus 18% tax. The total bill for this dinner was
Answer:
xjjvbbbnhzxb hai jhfVbfxkdXhxx
20 points! I would really like some help! :) (Question attached below)
Answer:
See below.
Step-by-step explanation:
(a)
To multiply two polynomials, multiply every term of the first polynomial by every term of the second polynomial. Then combine like terms.
[tex] (\dfrac{1}{2}x - \dfrac{1}{4})(5x^2 - 2x + 6) = [/tex]
[tex] = \dfrac{1}{2}x \times 5x^2 - \dfrac{1}{2}x \times 2x + \dfrac{1}{2}x \times 6 - \dfrac{1}{4} \times 5x^2 + \dfrac{1}{4} \times 2x - \dfrac{1}{4} \times 6 [/tex]
[tex]= \dfrac{5}{2}x^3 - x^2 + 3x - \dfrac{5}{4}x^2 + \dfrac{1}{2}x - \dfrac{3}{2}[/tex]
[tex] = \dfrac{5}{2}x^3 - \dfrac{9}{4}x^2 + \dfrac{7}{2}x - \dfrac{3}{2} [/tex]
(b)
No. Since the binomials are different, the product of two different binomials and the same trinomial will give different results.
PLEASE HELP QWQ AsAp with these 4 questions
Answer:
Step-by-step explanation:
I can't believe I'm doing this for 5 points, but ok!
For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:
[tex]\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right][/tex] and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):
[tex](7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)][/tex] which gives us:
392 + 36 - 192 - [48 + 504 - 112] which simplifies to
236 - 440 which is -204
On to the second one:
[tex]\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)][/tex] which gives us:
-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to
-417 - 124 which is -541, choice c.
Now for the third one:
[tex]\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)][/tex] which gives us:
[tex]-126+48-90-[-280+54-36][/tex] which simplifies to
-168 - (-262) which is 94, choice c again.
Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.
[tex]\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right][/tex] [tex]\left[\begin{array}{c}x\\y\\\end{array}\right][/tex] = [tex]\left[\begin{array}{c}-5\\-2\\\end{array}\right][/tex] and I found the inverse of the 2 x 2 matrix on the left.
Find the inverse by:
* finding the determinate
* putting the determinate under a 1
* multiply that by the "mixed up matrix (you'll see...)
First things first, the determinate:
|A| = (-4*-8) - (-6*-5) which simplifies to
|A| = 32 - 30 so
|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:
[tex]\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right][/tex] (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:
[tex]\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right][/tex] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:
[tex]\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right][/tex] and that right side multiplies out to
x = 20 - 5 which is
x = 15 and
y = -15 + 4 which is
y = -11
(It works, I checked it)
Find the interest rate if $8200 has
a final value of $11406 in 4 years.
Give your answer to 1 d.p.
r=I × 100÷pxt
8200×100÷ 11406×4
820000÷. 45624
17.97
make me brainliest .
Correct answer gets brainliest and 5 stars
Answer:
5, 12, 13
Step-by-step explanation:
Pythagoras theorem ⇒ Perpendicular² + Base² = Hypotenuse²
5² + 12² = 13²
25 + 144 = 169
Thus 5, 12, 13 is a Pythagorean triple.
Find the missing probability. P(A)=15,P(A∪B)=1225,P(A∩B)=7100 ,P(B)=?
Answer:
p(B) = 8310Step-by-step explanation:
We will use the addition rule of probability of two events to solve the question. According to the rule given two events A and B;
p(A∪B) = p(A)+p(B) - p(A∩B) where;
A∪B is the union of the two sets A and B
A∩B is the intersection between two sets A and B
Given parameters
P(A)=15
P(A∪B)=1225
P(A∩B)=7100
Required
Probability of event B i.e P(B)
Using the expression above to calculate p(B), we will have;
p(A∪B) = p(A)+p(B) - p(A∩B)
1225 = 15+p(B)-7100
p(B) = 1225-15+7100
p(B) = 8310
Hence the missing probability p(B) is 8310.
I need help on both answers. They’re different from my other problems so I’m kinda confused
On a baseball field, the pitcher's mound is 60.5 feet from home plate. During practice, a batter hits a ball 214 feet at an
angle of 36° to the right of the pitcher's mound. An outfielder catches the ball and throws it to the pitcher. Approximately
how far does the outfielder throw the ball?
9514 1404 393
Answer:
169 ft
Step-by-step explanation:
The law of cosines can be used to find the distance from the outfielder to the pitcher. It tells you for triangle ABC, the length of side c can be found from ...
c² = a² +b² -2ab·cos(C)
Here, we hve a=60.5, b=214, and C=36°. Then the desired distance is ...
c = √(60.5² +214² -2·60.5·214·cos(36°)) ≈ √28507.56 ≈ 168.84
The outfielder throws the ball about 169 feet.
I really need these answered!
Answer:
Step-by-step explanation:
#1) [tex]\arcsin \left(0.64958\right)=0.70703\dots \quad \begin{pmatrix}\mathrm{Degrees:}&40.51^{\circ \:}\end{pmatrix}[/tex]
∡C =62.49
[tex]\frac{\left(\sin \left(27^{\circ \:}\right)\right)}{3}=\frac{\sin \left(54^{\circ \:}\right)}{x}\quad :\quad x=\frac{3\left(\sqrt{5}+1\right)}{\sin \left(27^{\circ \:}\right)\cdot \:4}\quad \left(\mathrm{Decimal}:\quad x=5.34603\dots \right)[/tex]
Water flows through a pipe at a rate of 4 quarts per day. Express this rate of flow in liters per week. Round your answer to the nearest tenth.
Answer:
26.5 liters
Step-by-step explanation:
We know that 1 gallon is 4 quarts, and 1 gallon is approx. 3.78 liters. There's 7 days in a week, so 7 gallons of water is being flowed through. Multiplying 3.78 by 7, we get 26.46 liters per week. Rounding to the nearest tenth, and we get 26.5 liters.
Consider the following linear system.
-3x+7y=-16
-9x+5y=16
The y-value of the solution is:
a. -16/13
b. 4
c. 51/16
d. -4
Answer:
D) y=-4
Step-by-step explanation:
we can multiply the first equation by -3 to cancel out the x's
and then add the first equation and the second equation
9x-21y=48
-9x+5y=16
0x-16y=64
y=-64/16=-4
Based on the graph what are the solutions to ax^2 + bx+c=0 Select all that apply
A. X=-2
B. X=10
C. X=5
D. X=8
Answer:
x=-2 and x = 5
Step-by-step explanation:
The solutions to the equation are where the graph crosses the x axis
We can see that the graph crosses at x=-2 and x = 5
Answer:
x = -2
x = 5
Step-by-step explanation:
The answer is found when the graph crosses the x-axis
Hope this helps :D
Guys please help me find the answer to this
Answer:
C
Step-by-step explanation:
The colony will follow an exponential equation. y(x) = 8000*(2)^(t/210). Plug in t=630 and you will get y(x) = 64000
2(3x + 1) - (x - 5) = 42
Answer:
6x+2-1x+5=42
Step-by-step explanation:
Answer:
6x+2-x-5=42
Step-by-step explanation:
An object has a mass of 50.0 g and a volume of 10.5 cm cubed. What is the object's density? A. 60.5 g/cm cubed B. 0.21 g/cm cubed C. 4.76 g/cm cubed D. 525 g/cm cubed
Answer:
4.76 g/cm³
Step-by-step explanation:
Density formula = mass / volume
1. Set up the equation and solve
50.0 / 10.5 = 4.76
The following equation is often referred to as Euler's Formula; e^pii+1=0 Use what you know about complex numbers to show that this equation is true. In other words, show that e^pii+1=0 __ If someone could please help me understand the proof and the answer to this ill give you brainliest!! thank you
Answer:
[tex]\large \boxed{e^{i\pi}+1=0}[/tex]
Step-by-step explanation:
Hello, please consider the following.
For any x real number,
[tex]e^{ix}=cos(x)+i\cdot sin(x)\text{, right? So}\\\\e^{i\pi}=cos(\pi)+i\cdot sin(\pi)\\\\e^{i\pi}=-1+i\cdot 0=-1\\\\\text{ We add 1 to both sides of the equation.}\\\\\large \boxed{e^{i\pi}+1=0}\\[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Write 70cents to $1.80 as a fully simplified ratio by first converting to the same units, and then simplifying.
Answer:
7 : 18
Step-by-step explanation:
1. Convert to the same units (cents)
70 cents = 70 cents
$1.80 = 180 cents
2. Simplify
70 : 180 (divide both by ten)
7 : 18
7 and 18 cannot be simplified any further.
ayudenme con esta ecuacion de igualacion ¿ resuelve cada sistema de ecuacion por el metodo de igualacion?
7x + 4y = 2
x + y= 1
Answer:
[tex]{x, y} = {-\frac{2}{3}, \frac{5}{3}}[/tex]
Step-by-step explanation:
7x + 4y = 2
x + y = 1
// Solve equation [2] for the variable y
[2] y = -x + 1
// Plug this in for variable y in equation [1]
[1] 7x + 4•(-x +1) = 2
[1] 3x = -2
// Solve equation [1] for the variable x
[1] 3x = - 2
[1] x = - 2/3
// By now we know this much :
x = -2/3
y = -x+1
// Use the x value to solve for y
y = -(-2/3)+1 = 5/3
Solution :
{x,y} = {-2/3,5/3}
Andrea is comparing the prices charged by two different taxi firms.
Firm A charges £20 for a 5 mile journey and £30 for a 10 mile journey, and there is a linear relationship between the price and the length of the journey.
Firm B charges a pickup fee of £3 and then £2.40 for each mile travelled.
Find the length of the journey for which both firms would charge the same amount.
Answer: 17.5 miles
Step-by-step explanation:
P=price, L=length
Firm A:
P=2L+10
Firm B:
P=2.40L+3
2.40L+3=2L+10
L=17.5
The fare would be the same for 17.5 miles for both firms.
What are linear equations?Linear equations help in representing the relationship between variables such as x, y, and z, and are expressed in exponents of one degree. In these linear equations, we use algebra, starting from the basics such as the addition and subtraction of algebraic expressions.
Given here, Firm A charges £20 for a 5 mile journey and £30 for a 10 mile journey . let the fixed component of the fare be k and charge for travelling per mile be x then we have, 20=5x+k. . . (1)
30=10x+k. . . .(2)
solving these two equations we get x=2 and k = 10
Now let the length of the journey that both firm charge the same is equal to L and given here that firm B charges a pickup fee of £3 and then £2.40 for each mile travelled. Thus forming the equations we get
2L+10=2.40L+3
0.40L=7
L=17.5
Hence, The fare would be the same for 17.5 miles for both firms.
Learn more about linear equations here:
https://brainly.com/question/29739212
#SPJ2
Describe the transformation. A. (x,y)→(x+5,y−3) B. (x,y)→(x−3,y+5) C. (x,y)→(x+3,y−5) D. (x,y)→(x−5,y+3)
Answer:
Option(A)
Step-by-step explanation:
From the graph attached,
Quadrilateral USTR has been transformed to get the image quadrilateral U'S'T'R'.
Coordinates of point U → (-2, 6)
Coordinates of point U' → (3, 3)
Coordinates of U and U' show that quadrilateral USTR has been shifted by 5 units to the right and 3 units down.
Rule to be followed for the translation,
U(-2, 6) → U'[(-2 + 5), (6 - 3)]
U(x, y) → U'[(x + 5), (y - 3)]
Therefore, Option (A) describes the correct rule of transformation.
For what value(s) of k will the function y=6x^2-8x+k have: a) one zero b) two zeros c) no zeros *this is not multiple choice*
Answer:
Step-by-step explanation:
Hello, please consider the following.
[tex]6x^2-8x+k=0\\\\\text{We compute the discriminant.}\\\\\Delta = b^2-4ac=8^2-4*6*k=8*8-8*3*k=8*(8-3k)[/tex]
And the we know that if the discriminant is
***** [tex]\Delta[/tex] < 0, meaning 8-3k<0, meaning
[tex]\boxed{k>\dfrac{8}{3}}[/tex]
then, there is no real solution.
***** [tex]\Delta = 0[/tex], meaning
[tex]\boxed{k=\dfrac{8}{3}}[/tex]
There is 1 solution.
***** [tex]\Delta[/tex] > 0, meaning
[tex]\boxed{k<\dfrac{8}{3}}[/tex]
There are 2 solutions.
Thank you
PS: To give more details...
[tex]8-3k=0\\\\\text{Add 3k}\\\\8=3k\\\\\text{Divide by 3}\\\\k=\dfrac{8}{3}[/tex]