Through 57 revolutions the tub rotate while it is in motion.
What is angular speed?
Angular speed is defined as the rate of change of angular displacement, It is a scalar measurement of rotating object.
It is expressed as follows: ω = θ / t.
Here,
Initially tub is at rest so,
ω(i) = 0 rev/s
ω(f) = 6 rev/s
time taken, t = 8 second
Now the total number of revolutions,
N = t * ( ω(i)+ ω(f) ) / 2
N1 = 8* ( 0+6 ) / 2
N1 = 24 rev
Now, when the lid is opened it's safety switch is off due to which it is uniformly decelerated and comes to rest in 11 s
N2 = 11* ( 0+6 ) / 2
N1 = 33 rev
So,
Total number of revolutions:
N = N1 + N2
N = 24 + 33
N = 57 revolutions
Thus,
Through 57 revolutions the tub rotate while it is in motion.
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A wire coil inside a generator has 150 square loops and an area equal to 0.042 m2.
The coil rotates one-quarter turn in 1.7 ms. If a 0.86 T magnetic field surrounds the
coil, what is the maximum electromotive force induced in the coil
a. 3.2 V
b. 130 V
c. 1600 V
d. 3200 V
D. The maximum electromotive force induced in the coil is determined as 3,200 V.
Maximum electromotive force induced in the coilemf(max) = NAB/t
where;
N is number of turnsB is magnetic fieldA is area of the coilt is timeSubstitute the given parameters and solve for emf
emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)
emf(max) = 3,187.1 V
emf(max) ≈ 3,200 V
Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.
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Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him?
OA. 813 N
B. 1150 N
C. 122 N
D. 352 N
The force of friction acting on him is 122 N. The correct answer is option C
What is Friction ?Friction is a force that opposes the motion of a static or a moving object.
Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg
The given parameters are;
Mass m = 83 kgCoefficient of kinetic friction μ = 0.15Frictional force [tex]F_{r}[/tex] = ?The normal reaction N on the body = mg
N = 83 x 9.8
N = 813.4 N
The Frictional force formula is [tex]F_{r}[/tex] = μN
[tex]F_{r}[/tex] = 0.15 x 813.4
[tex]F_{r}[/tex] = 122.01 N
Therefore, the force of friction acting on him is 122 N approximately.
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Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, what is the magnitude of the force of attraction (in newtons) between the objects
Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN
Explanation: To find the answer we need to know more about the Newton's law of gravitation.
What is Newton's law of gravitation?Gravitation is the force of attraction between any two bodies.Every body in the universe attracts every other body with a force.This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.Mathematically we can expressed it as,[tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]
How to solve the problem?Here, we have given with the data's,[tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]
Thus, the force of attraction between these two bodies will be,[tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]
Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.
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An astronaut in training is seated at the end of a horizontal arm 8 meters long. How many revolutions per second must the arm make for the astronaut to experience a horizontal acceleration of 4.0g
Answer:
a = v^2 / R where a is the centripetal acceleration and R the radius
v = 2 π R N / t where (N / t) is the revolutions / sec giving distance / time
a = 4 g horizontal acceleration
4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2
(N / t)^2 = g / (π^2 * R)
N / t = 1 / π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2 = .352 / sec
A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.
What is the spring constant k?
Group of answer choices
130 N/m
33 N/m
13 N/m
330 N/m
Answer:
Approximately [tex]13\; {\rm N \cdot m^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)
Explanation:
Let [tex]F_{\text{s}}[/tex] denote the force that this spring exerts on the object. Let [tex]x[/tex] denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant [tex]k[/tex] of this spring would ensure that [tex]F_\text{s} = -k\, x[/tex].
Note that the mass of the object attached to this spring is [tex]m = 540\; {\rm g} = 0.540\; {\rm kg}[/tex]. Thus, the weight of this object would be [tex]m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}[/tex].
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, [tex]F_{\text{s}} = 5.230\; {\rm N}[/tex].
The spring in this question was stretched downward from its equilibrium by:
[tex]\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}[/tex].
(Note that [tex]x[/tex] is negative since this displacement points downwards.)
Rearrange Hooke's Law to find [tex]k[/tex] in terms of [tex]F_{\text{s}}[/tex] and [tex]x[/tex]:
[tex]\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}[/tex].
When operating an aircraft at cabin pressure altitudes above 12,500 feet msl up to and including 14,000 feet msl, supplemental oxygen shall be used during?
Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.
Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.
The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.
The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.
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A 16.9 kg monkey is swinging on a
5.32 m long vine. It starts at rest,
with the vine at a 43.0° angle.
How much PE does the monkey
have?
(Unit = J)
The potential energy of the monkey at the given position is 600.9 J.
What is potential energy?Potential energy is the energy stored in a body that depends upon the relative position of various parts of the body.
It increases with increase in the height of the object above the ground level.
Potential energy of the monkeyThe potential energy of the monkey is calculated as follows;
P.E = mgh
P.E = mg (L sin43)
where;
m is mass of the monkey, given as 16.9 kgg is acceleration due to gravity, given as 9.8 m/s²L is length of the vine given as 5.32 mSubstitute the given parameters and solve potential energy of the monkey
P.E = (16.9)(9.8)( 5.32 x sin 43)
P.E = 600.9 J
Thus, the potential energy of the monkey at the given position is 600.9 J.
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Josie ran at an average speed of 16 m/s. if her mass 10 kg, what was her kinetic energy as she crosses her finish line?
Answer: 1280 J
[tex]KE=\frac{1}{2}mv^{2} \\\\KE= \frac{1}{2} (10 kg)(16 m/s)^2\\=1280 J[/tex]
I have to be honest with you . . . It's not possible to determine the answer with only the information given in the question.
Kinetic energy = (1/2) (mass) (speed squared).
Josie's Kinetic energy as she crosses the finish line is
(1/2) (her mass) (her speed as she crosses the finish line)².
That's (5 kg) x (her speed as she crosses the finish line)² .
But read the question again.
WE DON'T know her speed as she crosses the finish line.
The question only tells us her average speed for the whole race.
We can be confident that her Average Kinetic Energy was
(5 kg) (16 m/s)² = 1,280 Joules.
But we can't tell what her kinetic energy was as she crossed the finish line, beause we don't know what her speed was at that instant.
Which of newton's three laws is the hardest to describe or explain when viewing common occurrences?
Newton's second law is the hardest to describe as it is about momentum (F = ma), and a lot of people don't know the concept of momentum.
Newton's first law of motion:- every object moves in a straight line unless acted upon by a force.
Newton's 2nd law of motion:-the acceleration of an object is directly proportional to the net force exerted and inversely proportional to the item's mass. Newton's 2nd law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Newton's 3rd law of motion:- For every action, there's an equal and opposite reaction.
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Aluminum and copper wires of equal length are found to have the same resistance. What is the ratio of their radii
Answer:
R = ρ L / A resistance of wire
ρC / ρA = [RC AC/ LC] / [RA AA/ LA} = AC / AA
Since resistance and length are the same for both wires where A is the area of the wire
ρC / ρA = rC^2 / rA^2 where r is the radius of the wire
(ρC / ρA)^1/2 = rC / rA
rC / rA = (1.72 / 2.83)^1/2
rC / rA = .780 radius of copper wire is .780 of aluminum wire
The _______________ is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.
The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.
what do you mean by center of balance and center of gravity ?
A location where an object is balanced in relation to applied forces is known as the center of balance (COB).
The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.
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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work must you do to transport an electron from the positive terminal to negative terminal
The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.
Given:
Potential difference, V = 1.2 V
Charge on an electron, e = 1.6 × 10⁻¹⁹ C
Calculation:
We know that the work done to transport an electron from the positive to the negative terminal is given as:
W.D = (Charge on electron)×(Potential difference)
= e × V
= (1.6 × 10⁻¹⁹ C)×(1.2 V)
= 1.92 × 10⁻¹⁹ J
Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.
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An engine has an input of heat energy of 10,750 J and does 2,420 J of work. Which of the following is the heat loss?
Group of answer choices
a. 13,200 J
b. 8,330 J
c. 4.44 J
c. 0.225 J
B. The heat loss by the heat engine is 8,330 J.
Heat loss by the heat engine
The heat loss by the heat engine is calculated as follows;
H = E - W
where;
H is heat lossE is input energyW is work doneH = 10,750 J - 2,420 J
H = 8,330 J
Thus, the heat loss by the heat engine is 8,330 J.
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If the strength of a magnetic field at B is three units the strength of the magnetic field at A is ____?
If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.
How strength of the magnetic field should be increased?We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.
So we can conclude that point B has three times more turns as compared to point A.
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Would it be more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 500 C or with a 1 Kg iron bar at 1000 C.
Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.
The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
What is the Specific heat of Water?q = m x C x AT
As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.
Therefore, we can conclude that water is more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 50 degrees C.Learn more about Specific heat here:
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A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration
Answer:6km/sec
Explanation: Acceleration = Change in velocity / Time
Change in velocity = 60km/h minus 30km/hr
Time = 5seconds
A block is thrown with an initial velocity of 30.0 m/s at an angle of 25.0o above the horizontal. What is the highest elevation reached by the ball in its trajectory in meter
The highest elevation reached by the ball in its trajectory is 16.4 m.
To find the answer, we need to know about the maximum height reached in a projectile.
What's the mathematical expression of the maximum height reached in a projectile motion?
The maximum height= U²× sin²(θ)/gU= initial velocity, θ= angle of projectile with horizontal and g= acceleration due to gravityWhat's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?
Here, U = 30.0 m/s and θ= 25°Maximum height= 30²× sin²(25)/9.8= 16.4m
Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.
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At a point in space an electric force acts vertically upward on an electrion, the directon of the electric field at that point is:____
Answer:
F = Q E force acting on charge Q due to field E
A positive electric field is directed from positive to negative.
An electron will be attracted to the positive terminal.
Thus if the electric force is upwards the direction of the field must be directed downwards, or
if F is positive and Q is negative E must also be negative or downwards.
(taking upwards as positive)
If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?
The speed is 42 m/s at which squid rejects the water.
The maximum horizontal range that squid can achieve is 1.25 m
What is a drag force?
Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.
Here,
mass of the water, m1 = 3.0 kg
mass of the squid, m2 = 36 kg
initial speed, v2 = 3.5 m/s
(a)
According to the conservation of momentum:
m1*v1 = m2*v2
3 * v1 = 36 * 3.5
v1 = 42 m/s
It is the speed at which the squid rejects the water.
(b)
The maximum range:
R(max) = (v2) ^2 / g
where,
g=9.8 m/s^2 and launch angle is 45°
R(max) = 3.5^2 / 9.8
R(max) = 1.25 m
Hence,
The speed is 42 m/s at which squid rejects the water.
The maximum horizontal range that squid can achieve is 1.25 m
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Your question is incomplete, but most probably the full question was:
We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.
a. At what speed does the squid eject the water?
b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?
The diagram below shows a pendulum at two different positions in its path. The pendulum started from rest in position 1.
Pendulum with two different positions. Position 1 is higher and to the left compared to position 2
Which best describes the energy change as the pendulum moves from position 1 to position 2?
Group of answer choices
a. The total energy is decreasing.
b. The kinetic energy is increasing.
c. The thermal energy is decreasing.
d. The potential energy is increasing.
From position 1 to position 2, the kinetic energy is increasing.
Kinetic of a pendulum in simple harmonic motion
The kinetic energy of a pendulum undergoing simple harmonic motion decreases as the displacement of the pendulum increases and increases as the displacement of the pendulum decreases.
From position 1 to position 2, the kinetic energy is increasing while the potential energy is decreasing.
Thus, from position 1 to position 2, the kinetic energy is increasing.
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The technique called adaptive optics uses dynamic mirror motion to enhance the performance of the new generation of spaced-based telescopes. True False
The mentioned statement is true.
What is adaptive optics(AO)?
Adaptive optics (AO) is a technique that enhances optical systems' performance by minimizing the impact of incoming wavefront aberrations and deforming a mirror to account for the distortion. It is employed in microscopy, optical manufacturing, and retinal imaging systems to lessen optical aberrations and in astronomical telescopes and infrared communication devices to eliminate the impacts of environmental turbulence. Using a technology that adjusts flaws, including a flexible reflector or a liquid crystal array, adaptive optics(AO) measures the abnormalities in a wavefront and adjusts them.How can adaptive optics(AO) enhance a telescope's capabilities?
To counteract the impacts of disturbance, it quickly modifies the telescope mirror's shape.A moderately luminous target star that is adjacent to the target being studied is necessary for adaptive optics. With the use of the deformable mirror, the blurring brought on by the nearby atmosphere is measured using this reference star.Therefore, it is concluded that the mentioned statement is true.
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A train is traveling at 30.0 m/sm/s relative to the ground in still air. The frequency of the note emitted by the train whistle is 262 HzHz. The speed of sound in air should be taken as 344 m/sm/s .
frequency fapproach is heard by a passenger = 302.05 Hz
frequency frecede is heard by a passenger = 228.37433 Hz
Given :
speed of train to the ground = 30.0 m/s
frequency emitted by the train whistle = 262 Hz
speed of sound in air = 344 m/s
To Find :
(A) frequency fapproach (B) frequency frecede
Solution :
The frequency of approach is given by
f' = f v + v(relative)
v - v(air)
= 262x 344 + 18
344 - 30
f' = 302.05 Hz
The frequency of approach is 302.05 Hz
The frequency of recede is given by
f' = f v - v(relative)
v + v(air)
= 262 x 344 - 18
344 + 30
The frequency of recede is 228.37433 Hz
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What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects an electron with 7.74 × 10−20 j kinetic energy?
The threshold frequency for sodium metal is
5.49 x 10^14 s-1
Given:
photon with frequency = 6.66 × 10^14 s−1
kinetic energy = 7.74 × 10−20 j
To Find:
threshold frequency
Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation
We know, relation between threshold frequency, kinetic energy and frequency s given by :
K.E = hv - hvo
Here h is plank's constant and vo, is threshold frequency.
Putting all these value in above equation we get:
7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34
vo = 5.49 x 10^14 s^-1
Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1
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A 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s 2. What is the tension in the string
The tension in the string is 36 N.
To find the answer, we need to know about pseudo acceleration.
What's pseudo acceleration?When an object is placed on a vehicle, it experiences a pseudo acceleration in the opposite direction of the motion of the vehicle. Magnitude of the pseudo acceleration is same as that of the acceleration of vehicle.What's the pseudo acceleration of a mass suspended in a lift that's moving downward with an acceleration of 2.6 m/s²?Here, the acceleration of the lift is 2.6m/s², so the mass suspended by a string inside it will feel a pseudo acceleration of 2.6m/s² upward.So the effective acceleration of the mass = acceleration due to gravity - pseudo acceleration = 9.8 - 2.6 = 7.2 m/s²What's the tension of the string suspending the mass?Tension of the string= mass × effective acceleration
= 5 × 7.2 = 36 N
Thus, we can conclude that the tension in the string is 36 N.
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A microwave is a(n) _____ that is directed from one microwave station tower to another
The high-frequency radio signal is the answer.
Radiofrequency (RF) radios are in the wavelength band of 100 to 10 meters and extend from 3 MHz to 30 MHz. Much of the HF bandwidth is allocated to mobile and fixed voice communications services that require transmission bandwidth of less than 12 kHz. International (Shortwave) Broadcast
Radio Frequency (HF) is an ITU term for the range of high-frequency electromagnetic waves (radio waves) from 3 to 30 MHz (MHz). It is also known as the decameter band or decameter wave because it has wavelengths in the range of 1 to 10 decameter (tens to hundreds of meters).
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(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters
For the different wires the values given are
For Wire A, Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B, Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]
So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]
Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]
HeatThe type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.
(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters
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Excessive use of fossil fuels causes an energy crisis
yes, it causes an energy crisis. Burning Fossil Fuels
When we burn oil, coal, and gas, we don't just meet our energy needs, we move the current global warming crisis as well.
Fossil fuels produce large amounts of carbon dioxide when burned. Carbon emissions trap heat in the air and lead to climate change.
What are the major causes of energy crisis?
Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government efforts like tax hikes, nationalization of energy companies, and rule of the energy sector, shift supply and demand of energy away from its economic stability.
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A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is the period if the amplitude of the motion is increased to 2a?.
Time period is T if increasing the amplitude to 2A
What is Time period?
The length of time during which an activity occurs or a condition remains.
The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
Formula of Time period, T:
[tex]T = 2\pi \sqrt{\frac{M}{k} }[/tex]
Where,
k is the spring constant
mass of system = M
Amplitude = A
Time period = T
Here,
The amplitude is doubled = 2A
Since from the formula we can say that, The Time period is not dependent on amplitude.
Increasing the amplitude implies increase in the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period.
So the restoring force cancels the effect of the increase in amplitude.
Hence,
Time period is T if increasing the amplitude to 2A
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Are the acceleration and force vectors related? does the simulation show this relation?
The direction of the force vector and acceleration are identical (downwards) during the motion. The simulation also indicates the same relation.
Newton's 2nd regulation, F = ma is a vector equation. It says that the net force (a vector) acting on a mass m (a range of) causes an acceleration (a vector) of the object within the same path as the net force.
A simple mathematical relationship exists between the mass of an item (m), the net force at the item (f) and its acceleration (a). The acceleration of an object is without delay proportional to the net force and indirectly proportional to the item's mass (a = f/m).
For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.
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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for:_____.
A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for 800 secs.
Newtons 3 law whilst one object exerts pressure on any other object, the second object exerts a force on the first item this is identical in significance, but opposite in course; for each movement, there is an identical, but opposite response; referred to as the law of action-reaction.
You can use the equal formulation d = rt because of this distance equals the price instance's time. To solve for speed or rate use the components for pace, s = d/t this means that pace equals distance divided by way of time. To clear up for time use the components for time, t = d/s this means that time equals distance divided by way of velocity.
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