There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. Find the smallest integer in the sequence.

Answer:

  y = 3x -7

Step-by-step explanation:

The 2-point form of the equation of a line is useful for this.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (-1 -(-4))/(2 -1)(x -1) -4

  y = 3(x -1) -4

  y = 3x -7

Answer:

6:1

Step-by-step explanation:

48:( 4+4 )

= 48:8

= 6:1

Answer:

Step-by-step explanation:

Using the formula for calculating the standard error of the mean to get the standard deviation. The standard error of the mean is expressed as;

SE = S/√n where;

S is the standard deviation

n is the sample size

Given SE = 25 months and n = 1, on substituting this parameters into the formula, we will have;

25 = S/√1

25 = S/1

cross multiply

S = 25*1

S = 25 months

Hence the standard deviation based on the sample is 25 months

Answer:

Midpoint is (-6,-34)

Step-by-step explanation:

(6+(-18))/2. (-41+(-27))/2

-12/2. (-68)/2

-6. , - 34

Distance =(6--18)^2 +(-14--27)^2

23^2. +13^2

529 +169

= 698

So u will find the square root of 698

The ans u get is the distance

Answer:

X = 6

Step-by-step explanation:

Subtract 1 x from both sides so the equation will be 3x = 18.  Then divide 3x by 3 and 18 by 3 to get 6

Answer: [tex]x=6[/tex]

Subtract x from both sides

[tex]4x-x=x+18-x\\3x=18[/tex]

Divide both sides by 3

[tex]3x=3=18/3\\x=6[/tex]

Answer:

The answer is 615 inches

Step-by-step explanation:

The formula for solving the area of a circle is :

A= 1/4 π d^2

So since we only know the diameter the formula would be:

A= 1/4 of 3.14 x 28^2

Hope this helped :)

Answer:

domain (-inf, +inf)

range [-30, +inf)

y-int = -30

x-int = -10, 3

Step-by-step explanation:

Answer:

The eight in the first number is ten times larger than the eight in the second number.

Answer:

  x ≠ 5

Step-by-step explanation:

For the two points to represent a function, the value of x cannot be repeated. The only restriction on the values of x and y is that x is not 5. (x can be anything but 5.)

Answer:

The value of x can be

✔ any real number except 5

.

The value of y can be

✔ any real number

Step-by-step explanation:

i got it correct on edguinty

Answer:

x=23, y=14

Step-by-step explanation:

The triangles are indeed simular

Answer:

53°, 127°, 127°

Step-by-step explanation:

Two intersecting lines form two pairs of angles:

So if one of the angles is measured 53°, then the other angles are:

Answer:

B) 14

Step-by-step explanation:

We can plug in the values of m and p into the equation:

1/2 m + 3p = 1/2 (16) + 3 (2) = 8 + 6 = 14.

Answer:

z = -5

y = 1

x = 4

Step-by-step explanation:

2z = -10 ➡ z = -5

4y -(-5) = 9 ➡ 4y = 4 and y = 1

2x + 3 + (-5) = 6 ➡ 2x = 8 and x = 4

Prime factorization of 100 is 2 * 2 * 5 * 5

100 as a product of prime factors will be 2 ×2×5×5 .

Given,

Number = 100

Now,

To write 100 as prime factor product ,

Take LCM of 100

LCM 100 = 2 ×2×5×5

Thus the factors obtained in the LCM is prime factors only .

So we can write 100 as the product of prime factors:

100 = 2 ×2×5×5

Know more about prime factors,

https://brainly.com/question/29763746

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Answer:

a. (0,0), (2,0), (4,0)

b. (0,0)

Step-by-step explanation:

To find the x-intercept points, you set the equation equal to 0.

0=x³-6x²+8x                                [factor out an x]

0=x(x²-6x+8)                                [factor (x²-6x+8)]

0=x(x-2)(x-4)                               [set each factor equal to 0]

x=0

x-2=0                                           [add both sides by 2]

x=2

x-4=0                                            [add both sides by 4]

x=4

Now, we know our x-intercept points: (0,0), (2,0), (4,0).

To find the y-intercept points, we know that it is located on the y-axis, meaning x=0. We plug in 0 for x, and we will know our y-intercept point.

y=(0)³-6(0)²+8(0)                         [multiply]

y=0

The y-intercept point is (0,0).

Answer:

10

Step-by-step explanation:

Given that:

There are a total of 5 members on a student council.

2 of these members will serve in Spring Formal Committee.

To find:

How many possible spring formal committees can be there ?

Solution:

If the observe this problem closely, we are actually asked nothing but the number of ways to select 2 members out of 5.

This is a simple selection problem in which we have to find the number of ways to select [tex]r[/tex] objects out of [tex]n[/tex].

The number of ways = [tex]_nC_r =\frac {n!}{r!(n-r)!}[/tex]

Here,

[tex]n = 5\\r=2[/tex]

Hence, the required number of ways are:

[tex]_5C_2 =\frac {5!}{2!(5-2)!}\\\Rightarrow \dfrac {5!}{2!3!} = \dfrac {5\times 4\times 3!}{2!3!}\\\Rightarrow \dfrac {5\times 4}{2} = \dfrac{20}{2}\\\Rightarrow \bold{10}[/tex]

So, the number of possible spring formal committees are 10.

Answer:

11.4

Step-by-step explanation:

You find the square root

Answer:

$288

Step-by-step explanation:

Answer: 24%

Step-by-step explanation:

There are a total of  2610 graduates and if that is the divided by the total which is  10730   you will get 0.2432   which is about 24%

Answer:

24%

Step-by-step explanation:

I checked it on the test to make sure, I have acellus too.

Answer:

75%

Step-by-step explanation:

Answer:

6/8

Step-by-step explanation:

An easy way to do this is to draw a giant rectangle. when you do you simply want to stay a line going straight across in the middle. draw 3/4 ontop and 6/8 on the bottom. or another fraction that's close to it. then shade in 3/4 and the same with 6/8. if the shading is the same length, that's how you know it's equivalent

Answer:

GE = 11 cm.

Step-by-step explanation:

The figure provided is attached below.

The information given is:

CD = 11.5

DE = 5.3

BC = 8

AH = 11

Perimeter = 73.8

BC = FG = EF

HA = GH

AB = GE

The perimeter of any figure is the sum of all its sides.

The perimeter of the figure provided is:

Perimeter = AB + BC + CD + DE + EF + FG + GH + HA

Perimeter = AB + BC + CD + DE + BC + BC + HA + HA

         [tex]73.8=AB+8+11.5+5.3+8+8+11+11[/tex]

         [tex]73.8=AB+62.8[/tex]

         [tex]AB=11[/tex]

The value of side AB is 11 cm.

Then the value of GE is also 11 cm.

Answer:

[tex]f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})[/tex]

Step-by-step explanation:

Let be [tex]f(x,y) = \log_{4}(2\cdot x^{2}-20\cdot x +12\cdot y)[/tex], this expression is simplified by algebraic and trascendental means. As first step, the second order polynomial is simplified. Its roots are determined by the Quadratic Formula, that is to say:

[tex]r_{1,2} = \frac{20\pm \sqrt{(-20)^{2}-4\cdot (2)\cdot (12\cdot y)}}{2\cdot (2)}[/tex]

[tex]r_{1,2} = 5\pm \sqrt{25-6\cdot y}[/tex]

The polynomial in factorized form is:

[tex](x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})[/tex]

The function can be rewritten and simplified as follows:

[tex]f(x,y) = \log_{4} [(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})][/tex]

[tex]f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})[/tex]

Answer:

Lulu's money = £81

Ruby's money= £108

Emma's money= £72

Step-by-step explanation:

Let

Lulu's money = x

Ruby's money= y

Emma's money= z

x+y+z= 261

Lulu spent 2/3 of her money Ruby spent 1/2 of her money and Emma spent 3/4 of her money.

2/3x = 1/2y= 3/4z

2/3x= 1/2y

4/3x= y

2/3x= 3/4z

8/9x= z

x+y+z= 261

x+4/3x+8/9x= 261

9x+12x+8x= 2349

29x= 2349

X= 81

4/3x= y

4/3(81) =y

108= y

8/9x= z

8/9(81)= z

72= z

Answer:

Step-by-step explanation:

Each of them had different amount of money. Lulu spent 2/3 of her money Ruby spent 1/2 of her money and Emma spent 3/4 of her money.

1 answer

·

Top answer:

Answer:Lulu= £81Ruby=£108Emma=£ 72

Answer:

[tex]x<1[/tex]

Step-by-step explanation:

So we have the inequality:

[tex]1+7x+5x<13[/tex]

First, combine like terms:

[tex]1+12x<13[/tex]

Subtract 1 from both sides:

[tex]12x<12[/tex]

Divide both sides by 12:

[tex]x<1[/tex]

And that's our answer :)

Answer:

Step-by-step explanation:

12x + 1 < 13

12x < 12

x < 1

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter:  p = (51+37+20):2 = 54 m

Area of triangle:

[tex]A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2[/tex]

Rate:  ₹ 3 per m².

Cost:  ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm  ⇒  2b = 6 cm   ⇒  b = 3 cm

p = 11:2 = 5.5

[tex]A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2[/tex]

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

[tex]A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2[/tex]

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm  ⇒ 8x = 32 cm   ⇒  x = 4 cm  ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

[tex]A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2[/tex]

Answer:

(−∞,−7/2)∪(−7/2,3)∪(3,∞)

Step-by-step explanation:

(x-3)

----------------

2x^2 +x -21

First factor the denominator

(x-3)

----------------

( 2x +7) (x-3)

The domain is restricted when the denominator goes to zero

2x+7 =0    x-3 =0

2x = -7     x-3=0

x = -7/2    x =3

This two points are not in the domain

(−∞,−7/2)∪(−7/2,3)∪(3,∞)

Answer:

Linear

Step-by-step explanation:

Answer:

the answer is Linear

Step-by-step explanation:

Answer:

($3.75)n ≤ $20

Step-by-step explanation:

Represent this number by n.  Then the total purchase price can be represented by ($3.75)n ≤ $20, which is appropriate because Cooper can't spend more than $20.

The desired inequality is ($3.75)n ≤ $20.  If a solution is desired, divide both sides by $3/75):

        $20

n ≤ ______ = 5 1/3.

      $3.75

Cooper can purchase up to 5 whole packs of paper and have a bit of money left over.

Answer:

[tex]=\left(\frac{15}{2},\:\frac{5}{2}\right)[/tex]

Step-by-step explanation:

[tex]\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(6,\:4\right),\:\left(x_2,\:y_2\right)=\left(9,\:1\right)\\\\=\left(\frac{9+6}{2},\:\frac{1+4}{2}\right)\\\\=(\frac{15}{2} , \frac{5}{2} )\\\\[/tex]