This is rlly easy but Im to lazy to do it- I mark brainliest.

This Is Rlly Easy But Im To Lazy To Do It- I Mark Brainliest.

Answers

Answer 1

Answers:

A.   6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78  seats in total

  B.  6 Large taxis =  $498 + 9 Small taxis = $450     498+450= $948

   

    C.  5 Large taxis and 10 Small taxis

Step-by-step explanation:

A.   6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78  seats in total

If I did 8 small taxis the total number of seats would be 74, so I did one small taxi more to make it fair. There would be seats for everyone but 3 seats extra

  B.  6 Large taxis =  $498 + 9 Small taxis = $450     498+450=948

   

    C.  5 Large taxis and 10 Small taxis

While the more small taxis there are, the more cheaper it is for Max but the less seats there would be for 75 people, So I did 1 more small taxi and 1 less large taxi.

The total number of seats now is 75 seats which is perfect amount for 75 people

So the total cheaper cost would $915 while still maintaining a fair amount of seats which is 75


Related Questions

Please help me with these questions

Answers

Answer:

Step-by-step explanation: you sjxhbtdtbd

Let Y be a random variable. In a​ population, mu Subscript Upper Y Baseline equals 65μY=65 and sigma Subscript Upper Y Superscript 2 Baseline equals 49σ2Y=49. Use the central limit theorem to answer the following questions. ​ (Note​: any intermediate results should be rounded to four decimal​ places)
In a random sample of size n​ = 69​, find Pr(Y <68) =
In a random sample of size n​ = 124​, find Pr (68< Y <69)=
In a random sample of size n​ = 196​, find Pr (Y >66)=

Answers

Answer:

a. [tex]\mathbf{P(\overline x < 68) = 0.9998}[/tex]

b. [tex]\mathbf{P(68 < \overline x < 69 ) =0}[/tex]

c. [tex]\mathbf{P ( \overline x > 66 ) =0.02275}[/tex]

Step-by-step explanation:

Given that ;

Let Y be a random variable In a​ population, where:

mean [tex]\mu_y[/tex] = 65

[tex]\sigma^2_y[/tex] = 49

standard deviation σ  = [tex]\sqrt{49}[/tex] = 7

The objective is to determine the following :

In a random sample of size n​ = 69​, find Pr(Y <68) =

Using the Central limit theorem

[tex]P(\overline x < 68) = \begin {pmatrix} \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{68 - \mu }{\dfrac{\sigma}{\sqrt{n}}} } \end {pmatrix}[/tex]

[tex]P(\overline x < 68) = \begin {pmatrix}Z < \dfrac{68 - 65 }{\dfrac{7}{\sqrt{69}}} } \end {pmatrix}[/tex]

[tex]P(\overline x < 68) = \begin {pmatrix}Z < \dfrac{3 }{\dfrac{7}{8.3066}} } \end {pmatrix}[/tex]

[tex]P(\overline x < 68) = (Z < 3.5599 )[/tex]

From the z tables:

[tex]\mathbf{P(\overline x < 68) = 0.9998}[/tex]

In a random sample of size n​ = 124​, find Pr (68< Y <69)=

[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{68- \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{ 69 - \mu}{\dfrac{\sigma}{\sqrt{n}}} \end {pmatrix}[/tex]

[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{68- 65}{\dfrac{7}{\sqrt{124}}} < Z < \dfrac{ 69 - 65}{\dfrac{7}{\sqrt{124}}} \end {pmatrix}[/tex]

[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{3}{\dfrac{7}{11.1355}} < Z < \dfrac{ 4}{\dfrac{7}{11.1355}} \end {pmatrix}[/tex]

[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} 4.7724 < Z < 6.3631 \end {pmatrix}[/tex]

[tex]P(68 < \overline x < 69 ) = P( Z < 6.3631 ) - P ( Z < 4.7724 )[/tex]

From z tables

[tex]P(68 < \overline x < 69 ) = 0.9999 - 0.9999[/tex]

[tex]\mathbf{P(68 < \overline x < 69 ) =0}[/tex]

In a random sample of size n​ = 196​, find Pr (Y >66)=

[tex]P ( \overline x > 66 ) = P ( \dfrac{\overline x -\mu }{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{66 -\mu }{\dfrac{\sigma}{\sqrt{n}}})[/tex]

[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{66 - 65 }{\dfrac{7}{\sqrt{196}}})[/tex]

[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{1 }{\dfrac{7}{14}})[/tex]

[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{14 }{7})[/tex]

[tex]P ( \overline x > 66 ) = P ( Z>2)[/tex]

[tex]P ( \overline x > 66 ) = 1 - P ( Z<2)[/tex]

from z tables

[tex]P ( \overline x > 66 ) = 1 - 0.9773[/tex]

[tex]\mathbf{P ( \overline x > 66 ) =0.02275}[/tex]

A ladder leans against the side of a house. The angle of elevation of the ladder is 65, and the top of the ladder is 13 from the ground. Find the length of the ladder. Round your answer to the nearest tenth.

Answers

Answer:

SOHCAHTOA.

we have to use SOH(Sin) here because the theta is 65° and the opposite is 13 while the hypotenuse is x.

which is Sin 65°=13/x.

xSin65°=13.

0.906307787x=13.

x=13/0.9063=14.34403619~14.

let f (x) =- 3x and g (x) = 2x - 1 Find the following f (x) + g (x) Pleas show steps

Answers

Answer:

See below.

Step-by-step explanation:

So we have the two functions:

[tex]f(x)=-3x\text{ and } g(x)=2x-1[/tex]

And we want to find f(x) + g(x).

So, substitute:

[tex]f(x)+g(x)\\=(-3x)+(2x-1)[/tex]

Combine like terms:

[tex]=(-3x+2x)+(-1)[/tex]

Simplify:

[tex]=-x-1[/tex]

So:

[tex]f(x)+g(x)=-x-1[/tex]

Name the 5 ways/methods/techniques we can use to find a limit.

Answers

Answer:

you have four techniques to choose from: plugging in the x value, factoring, rationalizing the numerator, and finding the lowest common denominator.

hope that helps : )

Andre says that x is 7 becuase he can move the two 1s with the x to the other side. True or false


I will mark you brainiest

Answers

Answer:

False!

Step-by-step explanation:It is not possible.

Answer:

False

Step-by-step explanation: there is no possible way

plz brainliest

Matteo makes raspberry punch. The table shows how many parts ginger ale and raspberry juice to use for a batch. Raspberry Punch Parts Ginger Ale 2 Parts Raspberry Juice 3 Matteo decides to add one part of raspberry juice. What is the new ratio of ginger ale to raspberry juice? 2 parts ginger ale to 3 parts raspberry juice 2 parts ginger ale to 4 parts raspberry juice 3 parts ginger ale to 3 parts raspberry juice 3 parts ginger ale to 4 parts raspberry juice

Answers

Answer:

Answer: There is 1 1/2 times more juice than ginger ale; there is 2/3 as much ginger ale as there is punch.

Step-by-step explanation:

Answer:

Answer A:

Step-by-step explanation:

2 parts ginger ale to 3 parts raspberry juice.

a painter chargers $12 an hour while his son charges $6 an hour. if the father and son worked the same amount of time together on a job, how many hours did each of them work if their combined charge for their labor was 108

Answers

Answer: 6 hours

Step-by-step explanation:

Let x= the number of hours they've worked

12x+6x=108

Combine like terms

18x=108

Divide 18 on both sides

18/18 x=108/18

x=6

Hope this helps!! :)

Please let me know if you have any question

both the father and son worked for 6 hours each.

Let's denote the number of hours that both the father and son worked as "h".

The father charges $12 per hour, so his earnings for h hours of work would be 12h dollars.

The son charges $6 per hour, so his earnings for h hours of work would be 6h dollars.

Since their combined charge for labor was $108, we can set up the equation:

12h + 6h = 108

Combining like terms:

18h = 108

To solve for h, we divide both sides of the equation by 18:

h = 108 / 18

h = 6

Therefore, both the father and son worked for 6 hours each.

Learn more about work here

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i need help with number 4

Answers

Answer:

x = 9, AR = 25 , AM = 40

Step-by-step explanation:

Since AM = AR + RM and AM also = 7x-23

7x - 23 = (2x + 7) + 15

7x - 23 = 2x + 22

    +23          +23

7x = 2x + 45

-2x   -2x

5x = 45

x = 9

Now plug x = 9 into 2x + 7 to find AR

AR = 2x + 7

     = 2 (9) + 7

     = 18 + 7

AR  = 25

Now to find AM plug x = 9 into 7x - 23

AM = 7x - 23

      = 7 (9) - 23

      = 63 - 23

AM = 40

To double check, we already know that RM = 15, so add AR + RM to find AM

AM = 25 + 15

AM = 40

Answer:

9 = x

AR = 25

AM =  40

Step-by-step explanation:

AR + RM = AM

2x+7 +15 = 7x - 23

Combine like terms

2x+22 = 7x -23

Subtract 2x from each side

2x+22 -2x = 7x-2x -23

22 = 5x - 23

Add 23 to each side

22+23 = 5x-23+23

45 = 5x

Divide each side by 5

45/5 = 5x/5

9 = x

AR = 2x+7 = 2*9 +7 = 18+7 = 25

AM = 7x-23 = 7*9 -23 = 63-23 = 40

A lake has a surface area of 16.0 square miles and an average depth of 51.0 feet. what is it's volume in liters

Answers

Answer:

Volume of the lake = 6.44 × 10¹¹ Litres

Step-by-step explanation:

First, let us unify the units of measurement in the problem by converting the depth from feet to miles

1 mile = 5280 feet

1 foot = 1/5280 miles

∴ 51.0 Feet = 51.0 × (1/5280) miles

= 0.009659 miles

Next, let us calculate the volume of the lake.

Volume = surface area × depth

surface area = 16.0 (mi)²

depth = 0.009659 mi

volume = 16.0 × 0.009659 = 0.15454 (mi)³

Next, since we are asked to report the volume in litres, let us convert from cubic miles to litres

1 cubic mile = 4.168 × 10¹² litres

∴ 0.15454 cubic miles = 4.168 × 10¹² × 0.15454

= 6.44 × 10¹¹ Litres

∴ Volume of the lake = 6.44 × 10¹¹ Litres

The volume of the lake is 6.46×10¹¹ liters.

To get the volume of the lake in liters, we need to calculate the volume in square miles and then convert it to liters.

Formula:

V = Ah................... Equation 1

Where:

V = Volume of the lakeA = Surface area of the lakeh = height of the lake.

From the question,

Given:

A = 16.0 square milesh = 51.0 feet = (51×0.00019) feet = 0.00969 miles

Substitute these values into equation 1

V = 16(0.00969)V = 0.15504 milesV = (0.15504×4.168×10¹²) litersV = 6.46×10¹¹ liters

Hence, the volume of the lake is  6.46×10¹¹ liters

Learn more about volume here: https://brainly.com/question/12410983

A triangle has vertices at F (8, 3), G (3, 5), and H (1, 7). What are the coordinates of each vertex if the triangle is rotated 180° about the origin counterclockwise?

Question 1 options:

F ¢(8, 3), G¢(-3, 5), H ¢(-1, -7)


F ¢(8, -3), G ¢(3, -5), H ¢(1, -7)


F ¢(-8, 3), G¢(-3, 5), H ¢(-1, 7)


F ¢(-8, -3), G ¢(-3, -5), H ¢(-1, -7)

Answers

Answer: F (-8, -3), G (-3, -5) and H (-1, -7)

Step-by-step explanation:

A rotation of 180° around the origin is equivalent to a reflection over the x-axis, and then another reflection over the y-axis.

Then, if we have a point (x, y) and we do a rotation of 180°, the point will transform into (-x, -y)

Then if at the start the vertices of the triangle are:

F (8, 3), G (3, 5), and H (1, 7).

After a rotation of 180°, the vertices will be:

F (-8, -3), G (-3, -5) and H (-1, -7)

The correct option is the last one.

Plz Help!!!!!!!!!
15. Men need to intake between 2200 and 2800 calories daily. Women need 600 fewer calories than this. Write and solve an inequality to discover how many calories women should be taking in per day.

A. 2200 x < 2800
B. 2200 > x < 2800
C. 600 < x < 1200
D. 1600 < x < 2800
E. 1600 < x < 2200
F. 2800 < x < 3200

Answers

Answer:

A

Step-by-step explanation:

help with math homework?​

Answers

Answer:

The range of the curve is [tex][-9,9][/tex].

Step-by-step explanation:

The domain of the curve corresponds to the values on horizontal axis (x-Axis), where the range of curve corresponds to the values on vertical axis (y-Axis). In addition, the curve is continuous in [tex](-5, 8)[/tex], so that images exists within interval.

The range of the curve is [tex][-9,9][/tex].

Please help me thank you so much. Just not sure of my answers

Answers

Answer:

An interesting experiment is given. We need to address various questions based on our knowledge of calculus.

Step 2

Part (a)

Time taken for the radius to grow to 2 cm = t1 = r/0.5 = 2/0.5 = 4 hours

Time taken for the radius to become 0 = t2 and the same can be obtained by solving:

r = 2 - √t2 = 0

Hence, t2 = 22 = 4 hours

Hence, the time duration of the entire experiment (from the introduction of the bacteria until its disappearance) = t1 + t2 = 4 + 4 = 8 hours

Step 3

Part (b)

r(t) = 0.5t for 0 ≤ t ≤ 4

and

r(t) = 2 - √(t - 4) for t > 2

Step-by-step explanation:

What is the number in standard form? 5.708 • 10^-8 Drag the answer into the box to match the number. 100 POINTS!!! HELP ME!!!

Answers

Answer:

.00000005708 is your answer. If it's asking you to solve the problem, 49.08

Answer:

[tex]\Huge \boxed{0.00000005708}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

[tex]5.708 \cdot 10^{-8}[/tex]

Solving for exponent and evaluating:

[tex]\displaystyle 5.708 \cdot \frac{1}{10^8 }[/tex]

[tex]\displaystyle \frac{5.708}{10^8 }[/tex]

[tex]\Rightarrow \ \displaystyle \frac{5.708}{100000000}[/tex]

The decimal place moves 8 units to the left side.

[tex]\Rightarrow \ 0.00000005708[/tex]

[tex]\rule[225]{225}{2}[/tex]

Use Stokes' Theorem to evaluate

C
F � dr
where F(x, y, z) = x2yi + 1/3x3j + xyk and C is the curve of intersection of the hyperbolic paraboloid z = y2 ? x2
and the cylinder x2 + y2 = 1 oriented counterclockwise as viewed from above.
Find parametric equations for C,Let x and y be in terms of t where
0 ? t ? 2?

Answers

Answer:

[tex]\int_C F . dr = \pi[/tex]

[tex]C : x = cost , y = sin t, z = sin^2 t - cos^2 t , 0 \leq t \leq 2 \pi[/tex]

Step-by-step explanation:

Given that:

[tex]F(x,y,z) = x^2yi + \dfrac{1}{3}x^3j +xyk[/tex]

Here C is the curve of intersection of the hyperbolic parabolic [tex]z = y^2 - x^2[/tex] and the cylinder [tex]x^2 +y^2 =1[/tex]

Using Stokes' Theorem

[tex]\int_C F . dr =\int \int \limits_s \ curl \ F. \ds[/tex]

From above ;

S = the region under the surface [tex]z = y^2 -x^2[/tex] and above the circle [tex]x^2+y^2 =1[/tex]

Suppose, we consider [tex]f(x,y,z) =z-y^2+x^2[/tex]

therefore, S will be the level curve of f(x,y,z) = 0

Recall that:

[tex]\bigtriangledown f (x,y,z)[/tex] is always normal to the surface S at the point (x,y,z).

This implies that the unit vector [tex]n = \dfrac{\bigtriangledown f}{|| \bigtriangledown ||}[/tex]

So [tex]\bigtriangledown f = <2x, -2y,1 >[/tex]

Also, [tex]|| \bigtriangledown f ||= \sqrt{4x^2+4y^2+1}[/tex]

Similarly ;

[tex]curl \ F = \begin {vmatrix} \begin{array} {ccc}{\dfrac{\partial }{\partial x} }&{\dfrac{\partial }{\partial y} }& {\dfrac{\partial }{\partial z} }\\ \\ x^2y& \dfrac{1}{3}x^3&xy \end {array} \end{vmatrix}[/tex]

[tex]curl \ F = \langle x ,-y,0 \rangle[/tex]

Then:

[tex]\int \int_s curl \ F .ds = \int \int_s curl \ F .nds[/tex]

[tex]\int \int_s curl \ F .ds = \iint_D curl \ F \dfrac{\bigtriangledown f}{ || \bigtriangledown f||} \sqrt{ (\dfrac{\partial z}{\partial x }^2) + \dfrac{\partial z}{\partial x }^2)+1 } \ dA[/tex]

[tex]\int \int_s curl \ F .ds = \iint_D \dfrac{\langle x,-y,0 \rangle * \langle 2x,-2y,1 \rangle }{\sqrt{4x^2 +4y^2 +1 }} \times \sqrt{4x^2 +4y^2 +1 }\ dA[/tex]

[tex]\int \int_s curl \ F .ds = \iint_D (2x^2 + 2y^2) \ dA[/tex]

[tex]\int \int_s curl \ F .ds = 2 \iint_D (x^2 + y^2) \ dA[/tex]

[tex]\int \int_s curl \ F .ds = 2 \int \limits ^{2 \pi} _{0} \int \limits ^1_0r^2.r \ dr \ d\theta[/tex]

converting the integral to polar coordinates

This implies that:

[tex]\int \int_s curl \ F .ds = 2 \int \limits ^{2 \pi} _{0} \int \limits ^1_0r^2.r \ dr \ d\theta[/tex]

⇒ [tex]\int_C F . dr = 2(\theta) ^{2 \pi} _{0} \begin {pmatrix} \dfrac{r^4}{4}^ \end {pmatrix}^1_0[/tex]

[tex]\int_C F . dr = 2(2 \pi) (\dfrac{1}{4})[/tex]

[tex]\int_C F . dr =(4 \pi) (\dfrac{1}{4})[/tex]

[tex]\int_C F . dr = \pi[/tex]

Therefore, the value of [tex]\int_C F . dr = \pi[/tex]

The parametric equations for the curve of intersection of the hyperbolic paraboloid can be expressed as the equations of the plane and cylinder in parametric form . i.e

[tex]z = y^2 - x^2 \ such \ that:\ x=x , y=y , z = y^2 - x^2[/tex]

[tex]x^2 +y^2 =1 \ such \ that \ : x = cos \ t , y= sin \ t, z = z, 0 \leq t \leq 2 \pi[/tex]

Set them equal now,

the Parametric equation of [tex]C : x = cost , y = sin t, z = sin^2 t - cos^2 t , 0 \leq t \leq 2 \pi[/tex]

What is the solution Set to 2a+6=2a+5+1

Answers

Answer:

6=6

True for all a

Step-by-step explanation:

[tex]2a+6=2a+5+1\\\mathrm{Subtract\:}2a\mathrm{\:from\:both\:sides}\\\mathrm{Simplify}\\6=5+1\\\mathrm{Simplify\:}5+1:\quad 6\\\\6 = 6[/tex]

Answer:

infinite solutions

Step-by-step explanation:

2a+6=2a+5+1

Combine like terms

2a+6 = 2a+6

Subtract 2a from each side

6 =6

Since this is always true, we have infinite solutions

A polygon is shown:

The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input whole numbers only, such as 8.)

Answers

Answer:

10 square units

Step-by-step explanation:

 which expression is equivalent to 6^3 x 6 1/4?

1. 6 11/4

2. 6 13/4

3. 6 3/4

4. 6

Answers

Answer:

number 3 I think I'm not sure

the cube of the sum of 4 and 9 times x divided by the product of 5 times x and the difference of x and 1​

Answers

Answer:

Step-by-step explanation:

(4 + 9x)^3 represents "the cube of the sum of 4 and 9 times x"

and if we divide by "the product of 5 times x and the difference of x and 1," we get

    (4 + 9x)^3

-----------------------

       5x(x - 1)

What exactly do you need to know, or to do?

A family is planning a three-week vacation for which they will drive across the country. They have a van that gets 12 miles per gallon, and they have a sedan that gets 36 miles per gallon. How much more will they pay for gasoline if they take the van? (Assume that the family will drive 2500 miles and that gas costs $2.50 a gallon. Round your answers to the nearest cent.)

Answers

Answer:

The family will pay 34722 cents more if they take the van

Step-by-step explanation:

Given

Van = 12 miles per gallon

Sedan = 36 miles per gallon

Distance = 2500 miles

Gas = $2.50 per gallon

First, we need to determine the number of gallons that'll be used by both vehicles

This  is done by dividing total distance by number of miles per gallon

[tex]Van = \frac{2500}{12} \ gallon[/tex]

[tex]Sedan = \frac{2500}{36}\ gallon[/tex]

Next, is to multiply this by the cost of gas per gallon;

This gives the total spendable amount on both vehicles

[tex]Van = \frac{2500}{12} * \$2.50[/tex]

[tex]Van = \frac{\$6250}{12}[/tex]

[tex]Van = \$520.833[/tex]

[tex]Sedan = \frac{2500}{36}* \$2.50[/tex]

[tex]Sedan = \frac{\$6250}{36}[/tex]

[tex]Sedan = \$173.611[/tex]

Next is to get the difference between these amounts

[tex]Difference = \$520.833 - \$173.611[/tex]

[tex]Difference = \$347.222[/tex]

Multiply by 100 to convert to cents

[tex]Difference = 347.222 * 100 cents[/tex]

[tex]Difference = 34722.2 \ cents[/tex]

[tex]Difference = 34722\ cents[/tex] (Approximated)

Hence;

The family will pay 34722 cents more if they take the van

Solve the equation 6x + 2x - 5= 19

Answers

Answer:

x = 3

Step-by-step explanation:

6x + 2x - 5= 19

8x -5 = 19

8x = 24

x = 3

Answer:

x = 3

Step-by-step explanation:

6x + 2x - 5 = 19

Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, combine like terms:

(6x + 2x) - 5 = 19

(8x) - 5 = 19

Next, isolate the variable, x. First, add 5 to both sides:

8x - 5 (+5) = 19 (+5)

8x = 19 + 5

8x = 24

Next, divide 8 from both sides:

(8x)/8 = (24)/8

x = 24/8

x = 3

3 is your answer for x.

~

F/5 = -8. F=? please solve! I'm stuck!

Answers

Answer:

-40

Step-by-step explanation:

F/5 = -8                 ⇒ multiply both sides by 5F = - 8*5F = -40                  ⇒ answer

The value of a 4 in the one thousands place is what FRACTION of the value of a 4 in the ten thousands place?

Answers

Answer:

1/10 = 0.1

Step-by-step explanation:

The value of a 4 in the one thousands place = 4000

the value of a 4 in the ten thousands

= 40000

In fraction,The value of a 4 in the one thousands place to the value of a 4 in the ten thousands place

= 4000/40000

= 4/40

= 1/10

= 0.1

I need help ASAP and I need to show my work

Answers

Answer:

Hey there!

Total students: 7+9+5+3+12=36

Students that like math: 7

7/36=19.4% of students like math.

Let me know if this helps :)

Answer:

19% (Math)

Step-by-step explanation:

7 divide by total number of students (36) X100% =19%

17. x^2 + 2x + 1
O A. This polynomial could be factored by finding the GCF, then by grouping or using the perfect squares method.
O B. This polynomial could be factored by using the difference of squares method, perfect squares method, or grouping.
C. This polynomial could be factored only by using the perfect squares method.
O D. This polynomial could be factored only by using the difference of squares method.
E. This polynomial could be factored by using grouping or the perfect squares methods.
O F. This polynomial cannot be factored by any of the methods used in this lesson.

Answers

Answer:

E. This polynomial could be factored by using grouping or the perfect squares methods.

Step-by-step explanation:

x^2 + 2x + 1

There is no greatest common factor

This is a perfect square

a^2 + 2ab+ b^2 = ( x+1)^2

We can factor this  by grouping

x^2 + 2x + 1

(x^2 +x) + (x+1)

x( x+1)  + x+1

Factor out x+1

( x+1)  ( x+1)

This is not the difference of squares since there is no subtraction

For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation can be used to solve for Carey’s hourly rate, c? One-half c plus 1 equals 6 One-half c minus 1 equals 6 One-half c plus 6 equals 1 One-half c minus 6 equals 1

Answers

Answer:

The equation used to solve Carey's hourly rate is:

1 + (c/2) = 6

Step-by-step explanation:

Answer:

The equation used to solve Carey's hourly rate is:

1 + (c/2) = 6

Step-by-step explanation:

edg2020

Find the answer to zero point 73 repeating times square root of 147 end square root and select the correct answer below. Also, is the product of a nonzero rational number and an irrational number classified as rational or irrational? start fraction 80 over 99 end fraction square root of three end square root comma rational start fraction 511 over 99 end fraction square root of three end square root comma irrational 511 over 33, rational start fraction 73 over 99 end fraction plus seven square root of three end square root comma irrational

Answers

Answer:

[tex]\frac{511\,\,\sqrt{3} }{99}[/tex]  which is an irrational number

Step-by-step explanation:

Recall that the repeating decimal 0.7373737373... can be written in fraction form as: [tex]\frac{73}{99}[/tex]

Now, let's write the number 147 which is inside the square root in factor form to find if it has some perfect square factors:

[tex]147=7^2\,3[/tex]

Then, 7 will be able to go outside the root when we compute the final product requested:

[tex]\frac{73}{99} \,*\,7\,\sqrt{3} =\frac{511\,\,\sqrt{3} }{99}[/tex]

This is an irrational number due to the fact that it is the product of a rational number (quotient between 511 and 99) times the irrational number [tex]\sqrt{3}[/tex]

what is the next greatest number of tens 384

Answers

Answer:

9

step by step explanation :

390

Hope this helps :)

384 the next greatest number of tens is 390.

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

The operator that performs the arithmetic operation is called the arithmetic operator.

Operators which let do a basic mathematical calculation

Note that the tens place is two moves to the right of the decimal point (if it exists).

To determine the greatest number to the nearest ten (nearest 10),

we use the place of the whole number to determine whether the tens place rounds up or stays the same.

The tens place (8) then look at the digit to the right (4):

⇒ 384

The digit to the right (4) is 4 or below. So, we replace it with a 0 (zero) to get 390 as the answer.

So, 384 the next greatest number of tens is 390.

Learn more about Arithmetic operations here:

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Tell which angles are congruent to the given angle measure.

Answers

Answer:

2, 5, & 6

Step-by-step explanation:

2, because it’s the opposite angle.

5, because it’s parallel.

6, because it’s opposite to 5.

2, 5, & 6 all equal 100°.

1, 3, 4, & 7 all equal 80°.

The angles formed that are congruent to angle measure of 100 degrees when transversal t intersects parallel lines m and n are:

<2, <5, and <6.

Angle measuring 100 degrees is the given angle measure formed at the point of intersection between line m and transversal t.

Thus, angles that are congruent to 100 degrees will be equal in measure to 100 degrees.

The following are angles congruent to 100 degrees.

<2 is congruent to 100 degrees (vertically opposite angles are congruent).

<5 is congruent to 100 degrees (corresponding angles are congruent).

<6 is congruent to 100 degrees (alternate exterior angles are congruent).

Therefore, the angles formed that are congruent to angle measure of 100 degrees when transversal t intersects parallel lines m and n are:

<2, <5, and <6.

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