Answer:
Hey there!
True. You use individuals rules, pieces of evidence, and experimentally found ideas that can be combined to form a general mathematical statement.
Let me know if this helps :)
2. The cost of 5 pen is Rs 1200, find the cost of 1 pen.
Step-by-step explanation:
cost of 5 pen is Rs 1200,
cost of 1 pen is 1200/5 = Rs 240
Answer:
Rs 240
Step-by-step explanation:
1200÷5=240
15. (x - 3)
If f(x) = 2x2 – 5, find the following.
16.fly-2)
17. f(a+h)-f(a)
Answer:
16. f(y-2) = 2(y-2)²-5
= 2(y²-4y+4)-5
= 2y²-8y+8-5
= 2y²-8y+3
17. f(a+h)-f(a) = 2(a+h)²-5-(2a²-5)
= 2(a²+2ah+h²)-5-2a²+5
= 2a²+4ah+h²-2a²
= h²+4ah
which was the last palindromic date?
Answer:
The previous palindrome date in all formats came 909 years ago on 11/11/1111. The next will come in 101 years on 12/12/2121 and after that there will not be another until 03/03/3030.
It depends how you format the date. If you do mm/dd/yyyy format
mm = month
dd = day
yyyy = year
then the last palindromic date was September 10th, 2019 since this would be written as 9/10/2019 in the mm/dd/yyyy format
Taking out the slash symbols, we have the number 9102019 which is the same when we reverse the digits.
The answer will be different if you have the date format as dd/mm/yyyy
2. Place the following values in scientific notation:
2020000 m
C. 0.003020 km
9901000 m/s
d. 0.001100 mm
Answer: a. [tex]2.02\times10^6\ m[/tex]
b. [tex]9.901\times10^6\ m/s[/tex]
c. [tex]3.02\times10 ^{-3}\ km[/tex]
d. [tex]1.1\times10^{-3}\ mm[/tex]
Step-by-step explanation:
Scientific notation is a technique to express a very big or a very small number in the product of a decimal form of number ( between 1 and 10) and powers of 10.
a. [tex]2,020,000 m\ = 2.02\times1,000,000=2.02\times10^6\ m[/tex]
b. [tex]9,901,000\ m/s =9.901\times1000000=9.901\times10^6\ m/s[/tex]
c. [tex]0.003020\ km=\dfrac{3020}{1000000}[/tex]
[tex]=3.02\times10 ^{-3}\ km[/tex]
d. [tex]0.001100\ mm=\dfrac{1100}{1000000}=\dfrac{11}{10000}[/tex]
[tex]1.1\times10^{-3}\ mm[/tex]
Need help with this as soon as possible.
-4x^2-28x-68
hope this helped!
Step-by-step explanation:
Hello, there!!!
The answer is: -4x^2-28x-68.
See explanation in picture.
Hope it helps...
Find the area of the region enclosed by the curves x=3y^2, x=0, and y=2
Answer:
8
Step-by-step explanation:
Hello,
[tex]x=3y^2<=>y=\sqrt{\dfrac{x}{3}} \ \ for \ x\geq 0[/tex]
And for y = 2, x = 3 * 2 * 2 = 12 so first, let's compute
[tex]\displaystyle \int\limits^{12}_0 {\sqrt{\dfrac{x}{3}}} \, dx =\dfrac{1}{\sqrt{3}} \int\limits^{12}_0 {\sqrt{x}} \, dx\\\\=\dfrac{1}{\sqrt{3}} \left[ \dfrac{2}{3}x^{3/2}\right]_0^{12}\\\\=\dfrac{1}{\sqrt{3}} *\dfrac{2}{3}*12*\sqrt{12}\\\\=\dfrac{2*12*2*\sqrt{3}}{3*\sqrt{3}}\\\\=2*4*2=16[/tex]
The area which is asked is 12*2 - 16 = 24 - 16 = 8
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Using integrals, it is found that the area of the region enclosed by the curves in the interval is of 27 units squared.
In this problem:
The curve is [tex]x = 3y^2[/tex], hence the integral is relative to y.The lower limit is when x = 0, hence [tex]0 = 3y^2 \rightarrow y = 0[/tex].The upper limit is when y = 2.Then, the integral for the area is:
[tex]A = \int_{0}^{2} 3y^2 dy[/tex]
[tex]A = y^3|_{y = 0}^{y = 3}[/tex]
[tex]A = 3^3 - 0^3[/tex]
[tex]A = 27[/tex]
The area of the region enclosed by the curves in the interval is of 27 units squared.
You can learn more about the use of integrals to calculate an area at https://brainly.com/question/15127807
Lauren bought 4 bags of popcorn for $3.00. What is the unit rate per bag of popcorn."?
Answer:
$0.75
Step-by-step explanation:
Given that
Number of bags of popcorn bought = 4
Total money spent = $3.00
To find:
Unit rate per bag of popcorn = ?
i.e. price of one bag of popcorn is to be find out.
Solution:
We can use ratio here to find the rate of one bag of popcorn.
4 bags bought at $3
4 bags : $3
Let us divide both the sides with 4.
[tex]\frac{4}4[/tex] bags : $ [tex]\frac{3}4[/tex]
OR
1 bag bought at $ 0.75
We can alternatively use unitary method.
4 bags are bought at $ 3
1 bag is bought at $ [tex]\frac{3}{4}[/tex]
1 bag is bought at $0.75.
So, unit rate per bag of popcorn is $0.75.
14. Twice the sum of a number and eight
Answer: 2(x + 8) is the expression.
Use distributive property to simplify,
2x+16
I didn't know which answer you wanted so....
Answer:
2(x + 8)
Step-by-step explanation:
Hello!
Twice the sum means we multiply by 2
2
the sum of a number and eight is x + 8
2 * x + 8
Since we have to twice the sum we put x + 8 in parenthesis to show to do that first
2(x + 8)
Hope this Helps!
How many times greater is
6.6 x 10^10
than
3 x 10^7
2.2
22
1000
2200
Answer:
2,200
Step-by-step explanation:
6.6 x 10^10
= 66,000,000,000
3 x 10^7
= 30,000,000
66,000,000,000 ÷ 30,000,000
2,200
Answer:
2200.
Step-by-step explanation:
6.6 / 3 * 10^10/10^7
= 2.2 * 10^3
= 2200
I need help please anyone ?????!!!
answer:
2 on the picture is the amplitude
Question: The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find the length of the remaining side?
Answer:
The hypotenuse is the longest side in a triangle.
a^2=b^2+c^2.
14^2=9^2+c^2.
c^2=196-81.
c^2=115.
c=√115.
c=10.72~11cm
A researcher wishes to see if the average weights of newborn male infants are higher than the
average weights of newborn female infants. She selects a random sample of 12 male infants and
finds the mean weight is 7.70 pounds. She selects a random sample of 9 female infants and finds
that the mean Leight is 7.80 pounds. Assume that the variables are normally distributed and the
population standard deviation is 0.5 for each group.
Using alpha=0.05 to test if the mean weight of the males is higher than the mean weight of the
females, the pvalue of the test is:
Answer:
The p-value is [tex]p-value = 0.62578[/tex]
Step-by-step explanation:
From the question we are told that
The sample size of male infant is [tex]n_1 = 12[/tex]
The sample size of female infant is [tex]n_2= 9[/tex]
The sample mean of male infant is [tex]\= x_1 = 7.70 \ lb[/tex]
The sample mean of female infant is [tex]\= x_2 = 7.80 \ lb[/tex]
The population standard deviation is [tex]\sigma = 0.5[/tex]
The significance level is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu_ 1 = \mu_2[/tex]
The alternative hypothesis is [tex]H_1 : \mu_1 > \mu_2[/tex]
The test statistics is mathematically represented as
[tex]t =\frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma }{n_1} } + \frac{\sigma }{n_2} } }[/tex]
=> [tex]t = \frac{7.70 -7.80}{\sqrt{\frac{0.5 }{12} } + \frac{0.5 }{9} } }[/tex]
=> [tex]t = -0.3207[/tex]
From the z-table the p-value is obtained, the value is
[tex]p-value = P(Z > -0.3207) = 0.62578[/tex]
[tex]p-value = 0.62578[/tex]
The area of a rectangular garden if 6045 ft2. If the length of the garden is 93 feet, what is its width?
Answer:
65 ft
Step-by-step explanation:
The area of a rectangle is
A = lw
6045 = 93*w
Divide each side by 93
6045/93 = 93w/93
65 =w
Answer:
[tex]\huge \boxed{\mathrm{65 \ feet}}[/tex]
Step-by-step explanation:
The area of a rectangle formula is given as,
[tex]\mathrm{area = length \times width}[/tex]
The area and length are given.
[tex]6045=93 \times w[/tex]
Solve for w.
Divide both sides by 93.
[tex]65=w[/tex]
The width of the rectangular garden is 65 feet.
evaluate the expression
The most frequently occuring value in a set is called the
Answer:
Step-by-step explanation:
The mode is the correct answer
Consider the following. C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
b Evaluate
Integral of (x+2y^1/2)ds
Answer:
a.
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b.
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
Step-by-step explanation:
Given that:
C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),
Then:
[tex]C_1 = (0,0) \\ \\ C_2 = (1,0) \\ \\ C_3 = (0,1)[/tex]
Also:
[tex]\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }[/tex]
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b Evaluate :
Integral of (x+2y^1/2)ds
[tex]\mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int \limits ^1_{0} \ (t + 0) \sqrt{1} } \\ \\ \mathtt{ \int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\ \mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits 2- t + 2\sqrt{t-1} \ \sqrt{1+1} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} \int \limits^2_1 2- t + 2\sqrt{t-1} \ dt }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2) \end {pmatrix} ^2_1}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ \sqrt{2} }{6} \ (11 )}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ 11 \sqrt{2} }{6}}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 0+2 \sqrt{3-t} \ \sqrt{0+1} }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 2 \sqrt{3-t} \ dt}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits^3_2 \begin {pmatrix} \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}[/tex]
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
The illustration below shows the graph of y as a function of x.
Complete the following sentences based on the graph of the function.
The y-intercept of the graph is the function value y=_____
The smallest positive x-intercept of the graph is located at x=_____
The greatest value of y is y=____ and it occurs when x=____
For x between x and x= 2 π the function value y___ 0
Answer:
below
Step-by-step explanation:
that is the solution above
9. There are 50 pupils in a class. Out of this
number, 1/10 speak French only and 4/5 of the remainder speak both French and
English. If the rest speak English only,
i) find the number of students who speak
Answer:
Step-by-step explanation:
50 : 10 = 5 speaks French only
50 -5= 45 the remainder
4/5 * 45= 36 speaks French and English
45 - 36= 9 speaks English only
The number of students who speak:
i) French only = 5 students,
ii) both French and English = 36 students,
iii) English only = 9 students.
Step 1: Find the number of students who speak French only.
Step 2: Find the remainder (students who speak both French and English) after subtracting the French-only speakers.
Step 3: Find the number of students who speak both French and English.
Step 4: Find the number of students who speak English only.
Let's calculate it step by step:
Step 1: Find the number of students who speak French only.
1/10 of 50 pupils speak French only:
French-only speakers = (1/10) * 50 = 5 students.
Step 2: Find the remainder (students who speak both French and English) after subtracting the French-only speakers.
Remaining students = Total students - French-only speakers
Remaining students = 50 - 5 = 45 students.
Step 3: Find the number of students who speak both French and English.
4/5 of the remaining students speak both French and English:
Both French and English speakers = (4/5) * 45 = 36 students.
Step 4: Find the number of students who speak English only.
To find the English-only speakers, subtract the total number of French-only speakers and both French and English speakers from the total number of students:
English-only speakers = Total students - (French-only speakers + Both French and English speakers)
English-only speakers = 50 - (5 + 36) = 50 - 41 = 9 students.
To know more about French:
https://brainly.com/question/34246494
#SPJ2
Complete question is:
There are 50 pupils in a class. Out of this number, 1/10 speak French only and 4/5 of the remainder speak both French and English. If the rest speak English only, find the number of students who speak
i) French only,
ii) both French and English,
iii) English only,
If (5x+3):(7x+3)=3:4, find the value of x.
[tex]\\ \sf\longmapsto \dfrac{5x+3}{7x+3}=\dfrac{3}{4}[/tex]
[tex]\\ \sf\longmapsto 4(5x+3)=3(7x+3)[/tex]
[tex]\\ \sf\longmapsto 20x+12=21x+9[/tex]
[tex]\\ \sf\longmapsto 12-9=21x-20x[/tex]
[tex]\\ \sf\longmapsto x=3[/tex]
[tex]\large\rm \longrightarrow \: {\purple{ \frac{(5x + 3)}{(7x + 3)} \: = \: \frac{3}{4} }} \\ [/tex]
⇛ Now , Cross Multiplying
[tex]\large\rm \longrightarrow \: {\blue{ 4 \: (5x + 3) \: = \: 3 \: (7x + 3)}}[/tex]
[tex]\large\rm \longrightarrow \: {\red{ 20x \: + \: 3 \: = \: 21 \: + \: 3}}[/tex]
[tex]\large\rm \longrightarrow \: {\orange{ 12 \: - \: 9 \: = \: 21x \: - \: 20x }}[/tex]
[tex]\large\rm \longrightarrow \:{\green{ 3 \: = \: x}}[/tex]
⇛ Hence , the value of x is 3
Using only the confidence interval approach, at LaTeX: \alpha α = 0.05, the conclusion about the LaTeX: \beta β1 hypothesis test is:
Answer:
Reject the null hypothesis because the value of null is outside the interval.
Step-by-step explanation:
Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value Test statistics is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. In the given case p-value is less than critical value then we should reject the null hypothesis.
An arithmetic sequence has this recursive formula: (a^1 =8, a^n= a^n-1 -6
A.a^n=8+(n-6)(-1)
B.a^n=8+(n-1)(-6)
C.
Answer:
[tex]a_n = 8 + (n - 1) (-6)[/tex]
Step-by-step explanation:
Given
[tex]a_1 = 8[/tex]
Recursive: [tex]a_{n} = a_{n-1} - 6[/tex]
Required
Determine the formula
Substitute 2 for n to determine [tex]a_2[/tex]
[tex]a_{2} = a_{2-1} - 6[/tex]
[tex]a_{2} = a_{1} - 6[/tex]
Substitute [tex]a_1 = 8[/tex]
[tex]a_2 = 8 - 6[/tex]
[tex]a_2 = 2[/tex]
Next is to determine the common difference, d;
[tex]d = a_2 - a_1[/tex]
[tex]d = 2 - 8[/tex]
[tex]d = -6[/tex]
The nth term of an arithmetic sequence is calculated as
[tex]a_n = a_1 + (n - 1)d[/tex]
Substitute [tex]a_1 = 8[/tex] and [tex]d = -6[/tex]
[tex]a_n = a_1 + (n - 1)d[/tex]
[tex]a_n = 8 + (n - 1) (-6)[/tex]
Hence, the nth term of the sequence can be calculated using[tex]a_n = 8 + (n - 1) (-6)[/tex]
What are the odds IN FAVOR of picking a red marble from a bag of 10 green marbles, 10 yellow marbles, and 5 red marbles?
Answer:
there is a 20% chance of getting a red marble
Step-by-step explanation:
Answer:
there is a 1/5 percent chance or 20%
Step-by-step explanation:
Hope this helps!
Convert the following equation
into standard form.
y = 7 - 7x
[?]x + y = []
Answer:
[tex]y = 7 - 7x \\ y + 7x = 7 \\ 7x + y = 7[/tex]
Answer:
7x + y = 7
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Given
y = 7 - 7x ( add 7x to both sides )
7x + y = 7 ← in standard form
Evaluate [x + 1/y]^m × [x-1/y]^n /[y+1/x]^m [y-1/x]^n
9514 1404 393
Answer:
(x/y)^(m+n)
Step-by-step explanation:
[tex]\displaystyle\frac{\left(x+\frac{1}{y}\right)^m\left(x-\frac{1}{y}\right)^n}{\left(y+\frac{1}{x}\right)^m\left(y-\frac{1}{x}\right)^n}=\left(\frac{x}{y}\right)^m\left(\frac{x}{y}\right)^n\\\\=\boxed{\left(\frac{x}{y}\right)^{m+n}}[/tex]
What would happen if addition were not associative?
Select all that apply.
A. The sum of 0 and a number would not always result in that number
B. The basic addition facts would not be true.
C. Addends could not be arranged in groups that sum to 10s to make column addition easier.
D. Addends could only be added in order from left to right.
Answer:
B, C, and D........................
The equation of the line L is 2y-x=10.Find the coordinates of the point where L intersects the y-axis
Equation:- 2y-x=10
For L to intersects Y axis then X cordinate must be zero
so put value of X as zero (0)
2y=10
So Y cordinate is equal to 5
Cordinate:- (0,5)
The scores for all the Algebra 1 students at Miller High on a test are normally distributed with a mean of 82 and a standard deviation of 7. What percent of students made scores above 89?
Answer:
15.7% of students made above an 89.
Step-by-step explanation:
If the data is normally distributed, the standard deviation is 7, and the mean is 82, then about 68.2% of students made between 75 and 89. 13.6% made between 90 and 96, and 2.1% made over 96. 13.6+2.1=15.7%
Simplify the expression 3-8x3-4
Answer:
−8x3−1
Step-by-step explanation:
let's simplify step-by-step.
3−8x3−4
=3+−8x3+−4
Combine Like Terms:
=3+−8x3+−4
=(−8x3)+(3+−4)
=−8x3+−1
Answer:
-1 - (2x^3)^3
Step-by-step explanation:
The equation is:
=> 3 - 8x^3 - 4
=> -1 - 8x^3
=> -1 - (2x^3)^3
Find the inverse of the following function.
Answer:
The inverse is 1/64 x^2 = y x ≥ 0
Step-by-step explanation:
f(x) = 8 sqrt(x)
y = 8 sqrt(x)
Exchange x and y
x = 8 sqrt (y)
Solve for y
Divide each side by 8
1/8 x = sqrt(y)
Square each side
(1/8 x)^2 = (sqrt(y))^2
1/64 x^2 = y
The inverse is 1/64 x^2 = y x ≥ 0
since x ≥0 in the original function
Answer:
[tex]\Huge \boxed{\mathrm{D}}[/tex]
Step-by-step explanation:
[tex]f(x)=8\sqrt{x}[/tex]
[tex]\sf Replace \ with \ y.[/tex]
[tex]y=8\sqrt{x}[/tex]
[tex]\sf Switch \ the \ variables.[/tex]
[tex]x= 8\sqrt{y}[/tex]
[tex]\sf Divide \ both \ sides \ of \ the \ equation \ by \ 8.[/tex]
[tex]\displaystyle \frac{x}{8} =\sqrt{y}[/tex]
[tex]\sf Square \ both \ sides \ of \ the \ equation.[/tex]
[tex]\displaystyle (\frac{x}{8} )^2 =y[/tex]
[tex]\displaystyle \frac{x^2 }{64} =y[/tex]
[tex]\displaystyle f^{-1}(x)=\frac{1}{64} x^2[/tex]
Eliminate the parameter for the following set of parametric equations: x= t^2 + 2 y= 4t^2
Answer:
Solution : y = 4x - 8
Step-by-step explanation:
The first thing we want to do is isolate t², rather than t. Why? As you can see when we substitute t² into the second equation, it will be easier than substituting t, as t is present in the form t². So, let's isolate t² in the first equation --- ( 1 )
x = t² + 2,
t² = x - 2
Now let's substitute this value of t² in the second equation --- ( 2 )
y = 4t²,
y = 4(x - 2),
y = 4x - 8 ~ And hence our solution is option c.