Two boys, John and Peter, are running a 100-meter race. In the first race that they run John beats Peter by 5 meters. To make things fair, the next time they race John stands 5 meters behind the starting line. If they run at the same speed as the first race, who will win the second race

Answer:

the answer might be 13.5

Answer:

(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units

The standard equation for the circle is (x - 1 ) ^2 + (y + 3)^2 = 2 ^2

A circle is a closed curve that is drawn from a fixed point called the center in which all points on the curve are the same distance from the center of the center. The equation of a circle with center (h, k) and radius r is given by:

(x-h)^2 + (y-k)^2 = r^2

This is the standard form of the equation. So if we know the coordinates of the center of the circle and also its radius, we can easily find its equation.

Consider any point P(x, y) on the circle. Let "a" be the radius of the circle which is equal to OP.

We know that the distance between the point (x, y) and the origin (0,0) can be found using the distance formula which is equal to -

√[x^2+y^2]= a

Therefore the equation of a circle with center as origin is,

x^2+y^2= a^2

Where "a" is the radius of the circle.

An alternative method

Let's derive another way. Assume that (x,y) is a point on the circle and the center of the circle is at the origin (0,0). Now, if we draw a perpendicular from the point (x,y) to the x-axis, we get a right triangle, where the radius of the circle is the hypotenuse. The base of the triangle is the distance along the x-axis and the height is the distance along the y-axis. Applying the Pythagorean theorem here, we therefore obtain:

x^2+y^2 = radius^2

We need to find the standard equation for the circle with center (1,-3) that passes through the point (2,2)

Standard equation for circle is

(x-h)^2 + (y-k)^2 = r^2................(1)

Here h = 1 , k = -3 and r = 2

put this value of h, k and r in equation (1), we get

(x - 1 ) ^2 + (y + 3)^2 = 2^2

Hence the standard equation of the circle is

(x - 1 ) ^2 + (y + 3)^2 = 2 ^2

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Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

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The approximate length of side AB is 14.0. The correct option is B. 14.0 units

From the question, we are to determine the measure of side AB

First, we will determine the measure of angle A

A + B + C = 180° (Sum of angles in a triangle)

A + 65° + 35° = 180°

A = 180° - 65° - 35°

A = 80°

Now, using the law of sines

c/sinC = a/sinA

c = AB

a = BC =  24

Thus,

c/sin35° = 24/sin80°

c = (24×sin35°)/sin80°

c = 13.978

c ≈ 14.0

∴ AB = 14.0

Hence, the approximate length of side AB is 14.0. The correct option is B. 14.0 units

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New mean is 2.53% larger than the original mean.

What is mean?

Mean is nothing but the average of the given set of values. It denotes the equal distribution of values for a given data set.

We can find the percentage larger is the mean of the new list in comparison with the original as shown below:

Given, set of number 55, 70, 81, 83, 88, 91

Median= (81+83)/2

= 164/2

= 82

Mean = (55+70+81+83+88+91)/6

= 468/6

= 78

New value which is added = 82*1.12

= 91.84

New Mean = (55+70+81+83+88+91+91.84)/7

= 559.84/7

= 79.97

Increase in mean = 79.97-78

=1.97

increase percentage (1.97/78) *100

= 2.53%

Hence, new mean is 2.53% larger than the original mean.

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Answer: [tex]y+5=-2(x+4)[/tex]

Step-by-step explanation:

See attached image.

The graph of the circle equation is graph (d)

The equation is given as:

x^2 + y^2 - 4x + 9y -7 = 0

Rewrite as:

x^2 - 4x + y^2 + 9y = 7

Express (x^2 - 4x) and (y^2 + 9y) as perfect squares.

So, we have:

(x - 2)^2 + (y + 3)^2 = 7 + 4 +  20.25

Evaluate the sum

(x - 2)^2 + (y + 3)^2 = 31.25

A circle equation is represented as:

(x - h)^2 + (y - k)^2 = r^2

Where

Center = (h, k)

Radius = r

So, we have:

(h, k) = (2, -3)

r^2 = 31.25

r = 5.5

The circle that has a center of (2, -3) and a radius of 5.5 is graph d

Hence, the graph of the circle equation is graph (d)

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Answer:

16 gallons of gas

Step-by-step explanation:

Two ways to answer this

1:

Find how many miles per gallon the car can go. Then, divide the amount the car needs to go with the miles per gallon. This gets you the gallons of gas needed to go the amount. In this case, 161 ÷ 7 = 23. 368 ÷ 23 = 16.

2:

Make a proportion. [tex]\frac{161}{7} = \frac{368}{x}[/tex]. Solve for x. 161 and 7 cancel out to get 23. [tex]\frac{23}{1} = \frac{368}{x}[/tex]. Now you can either divide 368 and 23 and multiply the quotient by 1 to get x, or you can cross multiply to get an equation you can solve. In the first case, 368 ÷ 23=16. 1*16=16. x=16. In the second case, 23x=368. Divide both sides by 23 and you get x = 16.

The angle m∠MLP in the rhombus is 56 degrees.

A rhombus has all its sides equal to each other.  The diagonals of a rhombus are angle bisectors.

Therefore,

m∠MLP = m∠MLO / 2

m∠MLO = 112°

m∠MLP = 112 / 2

Therefore,

m∠MLP = 56 degrees.

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Answer:

B. 56

Step-by-step explanation:

trust

Using the mean concept, the average collection for a student in this school was of $16.13.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

The number of students is given as follows:

82 + 74 + 96 + 99 = 351.

The sum is:

82 x 26.75 + 74 x 12.25 + 96 x 15.50 + 99 x 10.85 = $5662.15

Hence the mean is:

M = $5662.15/351 = $16.13.

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The formula for the velocity, v is √2E/m

Kinetic energy is half the mass multiplied by the square of the speed of the object

It is written thus;

Kinetic energy = 1/ 2 × m × v²

To solve for 'v' mean that we should make 'v' the subject of formula

E = 1/ 2 mv²

E = [tex]\frac{mv^2}{2}[/tex]

cross multiply

[tex]2E = mv^2[/tex]

To make 'v' the subject, we have

[tex]v = \sqrt{\frac{2E}{m} }[/tex]

Thus, the formula for the velocity, v is √2E/m

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If the function is

[tex]y = 4 e^x \cos(3x)[/tex]

then we have derivatives

[tex]Dy = 4 e^x \cos(3x) - 12 e^x \sin(3x)[/tex]

[tex]D^2y = -32 e^x \cos(3x) - 24 e^x \sin(3x)[/tex]

Now consider the linear ODE

[tex]aD^2y + bDy + cy = 0[/tex]

Substituting [tex]y[/tex] and its derivatives reduces the equation to

[tex](-32a + 4b + 4c) \cos(3x) + (-24a - 12b) \sin(3x) = 0[/tex]

Now,

[tex]-24a - 12b = 0 \implies b = -2a[/tex]

[tex]-32a + 4b + 4c = 0 \implies c = 10a[/tex]

Then the minimal ODE with the given solution is

[tex]aD^2y -2a Dy + 10ay = 0[/tex]

or

[tex]\boxed{D^2y  -2 Dy + 10y = 0}[/tex]

Answer:

482.84u², 42.5cm², 51.5ft²

Step-by-step explanation:

1) A = 2(1 + √2)a²

A = 2(1 + √2)(80 / 8)²

A = 482.84units²

2) Square = 5²

Square = 25

T1 = 3 x 5 / 2

T1 = 7.5

T2 = 4 x 5 / 2

T2 = 10

Total = 10 + 7.5 + 25

Total = 42.5cm²

3) Rect = 4(8 + 3)

Rect = 44

T1 = 2 x 3 / 2

T1 = 3

T2 = 3 x 3 / 2

T2 = 4.5

Total = 3 + 4.5 + 44

Total = 51.5ft²

Probability is 17.5% that 3 of them entered a profession closely related to their college

According to the statement

we have given that survey of 300 college graduates, 46% reported that they entered a profession closely and

We know that  For each college graduate, there are only two possible outcomes. Either they have entered a profession closely related to their college major, or they have not. The probability of a college graduate having entered a profession closely related to their college major is independent of other college graduates, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

This is P(X = 3) when n = 8. and the value of p is 0.46 put the value in the binomial formula then the outcome of answer will 17.5%

So, Probability is 17.5% that 3 of them entered a profession closely related to their college

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Answer:

The answer would be 36cm².

Step-by-step explanation:

⇒ Two prisms are similar.

⇒ Scale factor = 3:8

⇒ The ratio of the surface area is 9:64.

⇒ So S₁ : S₂ = 9:64

⇒ S₁ : 256 = 9:64

⇒ S₁ = 36cm²

This would mean that the answer is 36 centimeters ² (squared).

Answer:

[tex]2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}[/tex]

If the terms are multiplied by constants, take them outside the integral:

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x[/tex]

Multiply by the conjugate of 1 - sin(6x) :

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:[/tex]

[tex]\implies \sin^2 (6x) + \cos^2 (6x)=1[/tex]

[tex]\implies \cos^2 (6x)=1- \sin^2 (6x)[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

Expand:

[tex]\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}[/tex]

Simplify:

[tex]\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}[/tex]

[tex]\implies 2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

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Substitute [tex]y=6x[/tex] and [tex]dy=6\,dx[/tex] to transform the integral to

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = 2 \int \frac{dy}{1 - \sin(y)}[/tex]

Now substitute [tex]t=\tan\left(\frac y2\right)[/tex] and [tex]dt=\frac12 \sec^2\left(\frac y2\right) \, dy[/tex] to transform this to

[tex]\displaystyle 2 \int \frac{dy}{1 - \sin(y)} = 2 \int \frac1{1-\frac{2t}{1+t^2}}\cdot\frac{2\,dt}{1+t^2} = 4 \int \frac{dt}{(t-1)^2}[/tex]

Finally, substitute [tex]s = t-1[/tex] and [tex]ds=dt[/tex] to get

[tex]\displaystyle 4 \int \frac{dt}{(t-1)^2} = 4 \int \frac{ds}{s^2} = -\dfrac4s + C[/tex]

Now recover the antiderivative in terms of [tex]x[/tex].

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = -\frac4s + C \\\\ ~~~~~~~~ = -\frac4{t-1} + C \\\\ ~~~~~~~~ = -\frac4{\tan\left(\frac y2\right) - 1} + C \\\\ ~~~~~~~~ = \boxed{-\frac4{\tan(3x) - 1} + C}[/tex]

The explanation regarding the vector is illustrated below.

It should be noted that vector A with components a, b, c, can be written as (a, b, c) or in terms of unit vectors as ai + bj + ck.

In this case, the letters I, j, and k are the standard symbols for the unit vectors in the x, y, and z directions.

Therefore, if A = (3,4,5( you can write A = 3i + 4j + 5k.

If B = (1, 1, 1), you can write B = I + j + k.

Then A - B is the vector whose component are the difference in each components.

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Answer: 1

Step-by-step explanation: Any number raised to zero is always 1.

The height of the rectangular cereal box is 40 cm.

Volume of a rectangular prism = lwh

where

Therefore,

10000 = 25 × 10 × h

10000 = 250h

h = 10000 / 250

h = 40 cm

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Answer: 24

Step-by-step explanation:

1. Number Them

Elf and Dwarf = 1

Hobbit = 2

Wizard = 3

Man = 4

* Elf and Dwarf are put together so that they are always sitting together

2. Multiply

1 x 2 x 3 x 4 = 24

===================================================

Explanation:

If it increases by 5%, then we use the multiplier 1.05

Think of it like saying 100% + 5% = 1 + 0.05 = 1.05

Similarly, an increase of 20% means we involve 1.20

Combine those multipliers to get: 1.05*1.20 = 1.26

This is a net increase of 26%

Interestingly, we get fairly close to 25% which is what many students might go for (since 5 + 20 = 25). This is a beginner's trap.

----------------

An example:

Let's say the temperature is 20 degrees Celsius (68 degrees Fahrenheit)

An increase of 5% means it moves to 1.05*20 = 21 degrees C

A 20% increase means we go to 1.20*21 = 25.2 degrees C

The shortcut would be to do a 26% increase to get 1.26*20 = 25.2 to help confirm we have the correct combined increase.

The best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

A class can be defined as a user-defined blueprint (prototype) or template that is typically used by software programmers to create objects and define the data types, categories, and methods that should be associated with these objects.

In object-oriented programming (OOP) language, a class that is written or created to implement an interface in a software would most likely implement all of that interface's method declarations without any coding error.

In this scenario, the best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

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Complete Question:

A car dealership needs a program to store information about the cars for sale. For each car, they want to keep track of the following information: number of doors (2 or 4), whether the car has air conditioning, and its average number of miles per gallon. Which of the following is the best design?

(A) Use four unrelated classes: Car, Doors, AirConditioning, and MilesPerGallon.

(B) Use a class Car with three subclasses: Doors, AirConditioning, and MilesPerGallon.

(C) Use a class Car, with fields: numDoors, hasAir, and milesPerGallon.

(D) Use a class Car, with subclasses of Doors, AirConditioning, and MilesPerGallon.

(E) Use classes: Doors, AirConditioning, and MilesPerGallon, each with a subclass Car.

Answer:

0.1363636... = 3/22

Step-by-step explanation:

Let x = 0.1363636...

           100x = 13.6363636...

  (-)            x =   0.1363636...

------------------------------------------

              99x = 13.5

x = 13.5/99

x = 135/990

x = 27/198

x = 9/66

x = 3/22

0.1363636... = 3/22

0.1363636... is not equal to 1/33.

1/33 = 0.030303...

If the radius of the circular table is 5 cm then the length of the trim required is 31.4 cm.

Given that the radius of the circular table is 5 cm.

What is the length of trim needed to decorate along the outside trim?

Circumference is the length of arc of the circle.It is also known as the perimeter of the  circle.

Circumference of the circle=2πr in which r is the radius of the circle.

It is given that the trim is placed and decorated along the outside edge, so the perimeter of the circle must equal to the length of trim needed.

Length of trim needed to decorate the circular table=2πr

=2*π*5

=10π

=10*3.14

=31.4 cm.

Hence the length of the trim needed to decorate along the table is 31.4 cm.

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Answer:

15

Step-by-step explanation:

First side is 20

Second side is 20 * (3/2), as it is 1 and 1 half times longer than the first

Second side is 30(as calculated above)

65-20-30 = 15

Answer:

3x+2=2190

3x=2190-2

3x=2188

x=2188÷3

x=729

Since the standard deviation for the population is known, the z-distribution is used as the sampling distribution basis for this hypothesis test.

In this problem, the standard deviation for the population is known, hence the z-distribution is used.

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