Answer:
2j²/5
Step-by-step explanation:
We know that j has to be squared so j², and to find 2/5's of that number we need to multiply it by 2/5.
j²×(2/5)
Now to simplify it we can multiply the j² to the numerator.
2j²/5
Please help me check my work. Question: A square field has an area of 479 ft². What is the approximate length of a side of the field? Give your answer to the nearest foot. My answer: 22. This is because the square root of 479 is 21.88606862823929. So the answer would be about 22.
yeah this is just about right
-9(2+3x) distributive property
Answer: -18 - 27x, or -27x - 18
1. Solution Steps
[tex]-9(2+3x)[/tex]
Use the distributive property to multiply −9 by 2+3x.
[tex]-18-27x[/tex]
Expand
[tex]-27x-18[/tex]
2. Solution Steps
[tex]-9(2+3x)[/tex]
Use the distributive property to multiply −9 by 2+3x.
[tex]-18-27x[/tex]
Which of the following is the set of all real number x such that x-2 < x-4?
If you subtract x from both sides, then you go from
x-2 < x-4
to
-2 < -4
which is a false statement. The value -2 is not smaller than -4. It's the other way around. I recommend looking at a number line to compare the two values.
This means that x-2 < x-4 is never true regardless of what x value you pick. So there are no solutions.
Spackle paint supply had a beginning inventory of 10 cans of paint at 25 per can. They purchased 20 at 30 per can. They had an ending inventory valued 500. How much paint in dollars was used for the month
Answer:
The total number of paints used for the month = $350
Step-by-step explanation:
Given that:
Spackle paint had a beginning inventory of 10 can of paint at $25 per can =
10× $25 = $250
They purchased 20 at $30 per can.
The amount of the 20 purchased can = 20 × $30 = $600
The total inventory for this supply = $600 + $250
= $850
They had an ending inventory valued 500.
∴
The total number of paints used for the month = total inventory - ending inventory
The total number of paints used for the month = $850 - $500
The total number of paints used for the month = $350
E={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16} A={x:x is a multiple of 3} B={x:x is a factor of 24} C={x:x is an odd number} (i) Find (a) n(B),
B={1,2,3,4,6,8,12,24}
n(B)=8
Answer:
[tex] \boxed{ \huge{ \bold{ \boxed{ \sf{3 \: , \: 6 \: , \: 12}}}}}[/tex]
Step-by-step explanation:
Given,
E = { 1 , 2 , 3 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 }
Here, E is the universal set.
A = { x : x is a multiple of 3 }
Here, we have to list the multiples of 3 less than 16
A = { 3 , 6 , 9 , 12 , 15 }
B = { x : x is a factor of 24 }
Here, we have to list the factors of 24 less than 16 }
Factor of 24 means the numbers that can divide 24 easily.
Factor of 24 includes :
B = { 1 , 2 , 3 , 4 , 6 , 8 , 12 }
C = { x : x is an odd number }
Here, we have to list the odd numbers which are less than 16
C = { 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 }
Finding A ∩ B
Here, We have to find the common elements that are present in both A and B
{ 3 , 6 , 9 , 12 , 15 } ∩ { 1 , 2 , 3 , 4 , 6 , 8 , 12 }
= { 3 , 6 , 12 }
Hope I helped!
Best regards!!
For all integer values of x and constant k, if (x+6)(x+k)=x^2+14x+48, what is the value of k?
Answer:
8
Step-by-step explanation:
The product of terms on the left of the equal sign is ...
(x+6)(x+k) = x^2 +(6+k)x +6k
So, you have two clues to the value of k. The coefficient of x must match, and the constant must match.
6+k = 14 ⇒ k = 8
6k = 48 ⇒ k = 8
The value of k is 8.
12 14 22 14 18 23 42 13 9 19 22 14
what is the mean
Answer: 18.5
Step-by-step explanation:
The way to find the mean of a data set is to add up all the values and then divide by the number of data points.
First add up all of the values. 12+14+22+14+18+23+42+13+9+19+22+14=222.
Now count how many data points there are. There are 12 data points.
Finally, divide the sum you got by the number of data points. 222/12=18.5
Example of a function and why?
Answer:
f(x) = x + 2
Step-by-step explanation:
If we graph x + 2, we can see that it passes the Vertical Line Test. Each x-value only has 1 y-value.
If one bus takes 15 minutes to refill diesel in the tank than 4 buses will take how many minutes to refill
Answer:
1-->15 min
4-->x min
Step-by-step explanation:
x=15×4=60
4 buses will take 60 min to refill
In hours, 60min÷60=1 hour
Answer:
Step-by-step explanation:
x=15×4=60
4 buses will take 60 min to refill
In hours, 60min÷60=1 hour
I’m mainly looking for help with #15 for this one please
Answer:
[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}=1[/tex]
[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]
[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]
Step-by-step explanation:
So we want to left and right hand limits of the function:
[tex]f(x)=\sin{\frac{\pi}{\floor[x]}[/tex]
as x approaches 3.
Note that the [x] means the floor function a.k.a the greatest integer function. In other words, the value of the function will be the greatest integer less than or equal to x.
1) Left
So we have the limit:
[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}[/tex]
Note that since we're coming from the left, the values are 2.9, 2.99, and 2.999...
As I mentioned previously, the floor function outputs the greatest integer less than or equal to x.
With 2.9, 2.99, and 2.999, the greatest integer less than or equal to x is 2.
Therefore:
[tex]=\sin{\frac{\pi}{2}[/tex]
Simplify:
[tex]=1[/tex]
So:
[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}=1[/tex]
2) Right:
[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}[/tex]
Since we're coming from the right this time, the values are going to be 3.01, 3.001, 3.001.
And, the greatest integer less than or equal to 3.01, 3.001, and 3.001... is 3.
Therefore:
[tex]=\sin{\frac{\pi}{3}[/tex]
Simplify:
[tex]=\frac{\sqrt3}{2}[/tex]
So:
[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]
At 3:
So we have:
[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}[/tex]
The greatest integer of 3 is just 3. So:
[tex]=\sin{\frac{\pi}{3}\\[/tex]
Simplify:
[tex]=\frac{\sqrt3}{2}[/tex]
So:
[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]
4b+4<4(5-3b) how do u break this down to get the right answer
4b+4<20-12b
16b<16
b<1 olur.
İYİ DERSLER!
Answer:
See answer in the image below.
1/4 (12x - 20) = -70
Divide each term in the bracket by 4:
=
3
x
−
2
Explanation:
Multiplying by
1
4
is the same as dividing by 4. - You are finding a quarter of something.
To find a quarter of the bracket, divide each coefficient by 4.
You will get two unlike terms so you will not be able to simplify them.
This is the reason why you cannot simplify inside the original bracket either.
Step-by-step explanation:
A new car costs $8000 at full price. With a sales tax of 5.75%, how much will the car cost in total?
Answer:
$8460
Step-by-step explanation:
So for this problem we will use the base price of $8000 and add the additional cost of the 5.75% to find the total cost for the car.
So, to find the 5.75%, we simply multiply 8000 by .0575 to get 460.
So 8000 + 460 = 8460.
Thus, the total price of the car would be $8460.
Cheers.
Answer: $8,460
Step-by-step explanation: If you multiply the cost of the car by the sales tax you get your answer. Hope this helps!
given:x+2<-5. choose the solution set.
Step-by-step explanation:
x+2<−5
Step 1: Subtract 2 from both sides.
x+2−2<−5−2
x<−7
Answer:
x<−7
Find the number of possible outcomes. Seven books need to be placed
on a shelf. You randomly arrange the books on the shelf from left to right.
Which input value produces the same output value for the two functions on the graph? x = −1 x = 0 x = 3 x = 4
Answer:
D. x=4 did the test on edge
Step-by-step explanation:
What is the numerical value of 123.45
123.45 = 12345 × 10−^2
Answer:
12345([tex]10^{-2}[/tex])
Step-by-step explanation:
To do this you would just multiply 123.45 by 100 so you have no decimals and you would get 12345 and then since is goes up by 100 you would get [tex]10^{-2}[/tex] because you would take 2 decimal places from that so you would get
12345([tex]10^{-2}[/tex]) as your answer
Which of the following is the correct formula for distance?(1 point) d=(x2−x1)+(y2−y1)−−−−−−−−−−−−−−−−−√, where d is the distance between points (x1,y1) and (x2,y2). d=(x2+x1)2+(y2+y1)2−−−−−−−−−−−−−−−−−−√, where d is the distance between points (x1,y1) and (x2,y2). d=(x2−x1)2+(y2−y1)2, where d is the distance between points (x1,y1) and (x2,y2). d=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√, where d is the distance between points (x1,y1) and
Answer:
[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
please answer please!!!! Will mark brainliest for complete answer. -the first photo is to calculate the area. Just question number 7 a and b i). And question number 8.
+3х2+3x2
What is that answer simplified?
Can you please help me so I can get a better understanding? h(n)=3n, Find h(6)
Answer:
18
Step-by-step explanation:
So we have the function:
[tex]h(n)=3n[/tex]
And we want to find h(6).
To do so, simply substitute 6 for n. In other words:
[tex]h(n)=3n\\h(6)=3(6)[/tex]
Multiply:
[tex]h(6)=18[/tex]
So, our answer is 18 :)
Answer:
h(6) = 18
Step-by-step explanation:
To evaluate h(6), substitute n = 6 into h(n) , that is
h(6) = 3(6) = 18
Simplify: 3x2 - 4x - 5x2 + 8x A) -2x2 - 12x B) -2x2 + 4x C) -2x2 + 12x D) 8x2 - 12x
Answer:
3x^2-4x-5x^2+8x.
which is collect like terms.
3x^2-5x^2-4x+8x.
-2x^2+4x.
The answer is option B
Express the following fraction into a decimal
- 5/9
Answer:
5/9 = 0.5
Step-by-step explanation:
hope it helps leme know if u hab doubts
Without simplifying, select all the expressions that represent a rational number. Group of answer choices LaTeX: 4\frac{2}{3}\times\frac{8}{\sqrt{3}} 4 2 3 × 8 3 4 2 3 × 8 3 4 2 3 × 8 3 LaTeX: 4\frac{2}{3}+\frac{\sqrt{3}}{9} 4 2 3 + 3 9 4 2 3 + 3 9 4 2 3 + 3 9 LaTeX: 4\frac{2}{3}-\frac{\sqrt{4}}{8} 4 2 3 − 4 8 4 2 3 − 4 8 4 2 3 − 4 8 LaTeX: 4\frac{2}{3}\times\frac{\sqrt{3}}{9} 4 2 3 × 3 9 4 2 3 × 3 9 4 2 3 × 3 9 LaTeX: 4\frac{2}{3}\div\frac{\sqrt{4}}{8} 4 2 3 ÷ 4 8 4 2 3 ÷ 4 8 4 2 3 ÷ 4 8
Answer:
Well the real answer is 1st 2nd and 5th
Step-by-step explanation:
Just took the quiz
Of you add 7 to 3 times the no. you will get 31 . What are the two no.
Answer:
8
Step-by-step explanation:
4m-3/4= -9+4m/8 helppp
Answer:
m=− 33/14 =−2.357
Step-by-step explanation:
if you search up you question the first thing will come up is an answer from tiger algebra is may not be you question but click on it is will take to to this search bar area clear it and put you question in it then it will give your answer and step by step explanation
Huda evaluated the expression below. Negative 3 (8 minus 5) squared minus (negative 7) = negative 3 (3) squared minus (negative 7) = negative 3 (9) minus (negative 7) = 27 minus (negative 7) = 34. What was Huda's error? Huda evaluated (3) squared incorrectly. Huda found the product of –3 and 9 as positive. Huda subtracted –7 from 27 incorrectly. Huda did not follow the order of operations.
Answer:
Huda found the product of –3 and 9 as positive.
Step-by-step explanation:
Given the expression and result below :
Huda evaluated the expression below. Negative 3 (8 minus 5) squared minus (negative 7) = negative 3 (3) squared minus (negative 7) = negative 3 (9) minus (negative 7) = 27 minus (negative 7) = 34
-3(8 - 5)² - (-7) =
Step 1:
- 3(3)² - (-7)
Step 2:
-3(9) - (-7)
Step 3:
27 - (-7) = 34 (error in the third step)
-3(9) = - 27
Hence,
-27 - (-7) = - 27 + 7 = - 20
Answer:
its B on edge
Step-by-step explanation:
I just took the test
20 POINTS !!!
Find the distance between the points (3,-4) and (5, 4)
Answer:
[tex]d=2\sqrt{17}\approx8.2462[/tex]
Step-by-step explanation:
To find the distance between two points, use the distance formula.
The distance formula is:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]
Let (3,-4) be x₁ and y₁ and let (5,4) be x₂ and y₂. Therefore:
[tex]d=\sqrt{(5-3)^2+(4--4)^2[/tex]
Simplify:
[tex]d=\sqrt{(2)^2+(8)^2[/tex]
Square:
[tex]d=\sqrt{4+64}[/tex]
Add:
[tex]d=\sqrt{68}[/tex]
Simplify:
[tex]d=\sqrt{4\cdot17}=\sqrt4\cdot\sqrt{17}[/tex]
Simplify:
[tex]d=2\sqrt{17}\approx8.2462[/tex]
Answer:
[tex]\boxed{2\sqrt{17}}[/tex]
Step-by-step explanation:
To find the distance between two points, we use the distance formula. The distance formula is:
[tex]\boxed{d=\sqrt{(x_{2}-x_{1})^{2}+({y_{2}-y_{1})^{2}}}}[/tex]
Therefore, we can label our coordinate pairs and solve for d.
Because we are given two coordinate pairs, we will follow the standard naming system for coordinate pairs. This is [tex](x_{1}, y_{1}) \text \: {and} \: (x_{2}, y_{2})[/tex]. Therefore, we can implement the distance formula and solve.
[tex]\sqrt{(5-3)^{2}+(4-(-4))^{2}}\\\\\sqrt{(2)^{2}+(8)^{2}}\\\\\sqrt{4 + 64} \\\\\sqrt{68} \\\\\boxed{2\sqrt{17} }[/tex]
need help with these questions
Answer:
for question no 4
answer is 53
for question no 5
answer is -10
PLSSS HELP Which triangles are similar to triangle A?
Answer:
ΔB
Step-by-step explanation:
ΔA's angles are: 58º, 54º, and 68º
68º is found by 180 - (58 + 54)
ΔB's angles are: 54º, 68º, and 58º
58º is found by 180 - (68 + 54)
ΔA and ΔB have the same angles, therefore they are similar triangles
Answer:
triangle b
Step-by-step explanation:
i measured