The magnitude of the resultant with respect to one of the vectors is [tex]10 \sqrt{3} \mathrm{~N}[/tex].
The resultant of two force is given by [tex]$F=\sqrt{A^2+B^2+2 A B \cos \theta}$[/tex] where, [tex]$A \& B$[/tex] are two vectors & [tex]$\theta$[/tex] is the angle between them.
Magnitude or resultant is [tex]$\sqrt{2 \times 10^2+2 \times 100 \cos 60^{\circ}}=10 \sqrt{3} \mathrm{~N}$[/tex].
A force is an influence in physics that can modify the velocity of an object. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an object 'has in it.' Another object applies a force to another. The concept of a force is not limited to living or nonliving things.
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you launch a projectile horizontally from a height of 0.85 m. the projectile travels a horizontal distance 1.8 m. with what speed (m/s) did you launch the projectile?
Speed (m/s) required to launch the projectile is 5.94m/s.
What constitutes speed?Speed is defined as the product of distance and the amount of time it took to cover that distance.
Equations,
Vx = Vxo
x = Vx × t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt² / 2
yo - y = gt²/ 2
time to get to the ground,
0.85 = g t² / 2
t² = 0.85m × 2 / 9.81 m/s²
t² =0.1732 s²
t = 0.416s.
initial velocity,
Vxo = x / t = 1.8m/ 0.416s =4.32m/s
speed before it strikes the ground,
Vy = g*t = 9.81 m/s × 0.416 = 4.08m/s
V² = Vy² + Vx² = (4.32 m/s)² + (4.08 m/s)² = 35.3064m²/s²
V = [tex]\sqrt{35.3064}[/tex]= 5.94m/s.
Speed required to launch the projectile is 5.94m/s.
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a rollercoaster cart with a total mass of 1,000kg is at the top of a hill moving at 2ms. assuming no friction and neglecting air resistance, what is the speed of the cart when it reaches the bottom of the hill, 30m below?
Using the supposition that there is no friction and disregarding air resistance, the speed of the cart at the bottom of the hill is 24.6ms.
What kind of forces does friction produce?Small bumps collide with one another as surfaces move over one another. Friction acts as a resisting force on the surface's motion. Friction can be reduced by lubricants.
What exactly are the rules of friction?The friction caused by a moving item is inversely propotional and runs perpendicular to it. The type of surface the thing is in touch with determines the amount of friction it experiences. As long as there is a point of contact, friction remains independent of a area of contact.
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calculate the height (in m) of a cliff if it takes 2.21 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.01 m/s. (enter a number.) (b) how long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (enter a number.)
The height of the cliff is 6.22 meters and the time taken by the rock to hit the ground if thrown with same speed is 0.81 seconds.
The time taken by the rock to hit the ground when it is thrown up from the the cliff with an initial velocity of 8.01 m/s.
(a) From the equation of motion,
H = ut+1/2at²
H is the height of the cliff,
u is the the initial velocity,
t is the time taken by the rock,
g is the acceleration due to gravity.
Putting values,
H = (8.01)(2.21) + 1/2(-9.8)(2.21)²
H = -6.22m.
The height of the cliff is 6.22 m.
(b) If the rock is thrown down with the same speed,
Then the time taken by it to reach the ground is,
t = u/g
Putting values,
t = 8.01/9.8
t = 0.81 seconds.
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Help Please! would really appreciate it! THANK YOU!
The time taken for the orange to return is 0.96 s.
How long does it take to return?We know that if an object is thrown up or down that we have to look at the equations of kinematics under gravity so as to be able to obtain the velocity of the object or the time taken.
Now;
v = u - gt
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time taken.
Thus;
v = 0 m/s at the maximum height so;
u = gt
t = u/g
t = 4.73/9.8 m/s^2
t = 0.48 s
In order to go up and return;
2( 0.48 s) = 0.96 s
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a service elevator takes a load of garbage, mass 20.7 kg, from a floor of a skyscraper under construction down to ground level, accelerating downward at a rate of 1.7 m/s2. find the magnitude of the force (in n) the garbage exerts on the floor of the service elevator.
The magnitude of the force that the garbage exert on the floor of the service elevator is equal to 238.05 Newtons.
The mass of the garbage in the elevator is 20.7 kg. The elevator is accelerated downward at a rate of 1.7 m/s².
The acceleration due to gravity is g.
As the elevator accelerator downward then the total net acceleration of the elevator in the download direction is
A = (1.7 + 9.8) m/s².
A = 11.5 m/s².
The force that the garbage exert on the floor of the service elevator will be equal to the product of the mass of the garbage and the net acceleration with which the elevator is going downward,
F = 20.7 × 11.5
F = 238.05 N.
So, the force exerted by the garbage on the floor is 238.09 Newton.
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for a double slit experiment, what is the smallest separation (in nm) between two slits that will produce a second-order maximum for 652 nm visible light?
The smallest separation in terms of nm between two slits that will produce a second-order maximum for 652 nm visible light is 1.30 um
Since the relationship between wavelength and angle for minima and maxima in Young's double slit experiment is:
For constructive interference
d sinθ = n
for Destructive interference
d sinθ = (n+1/2)λ, where λ is the wavelength, n is the order of maxima and minima, Since here n = 2
So the separation, λ = 652 nm , and θ = 90
so, d sin90 = 2*652*10⁻⁹
=> d= 2*652*10⁻⁹/ sin90
= 1.30 X10⁻⁶
= 1.30 цm
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a piece of wood from a nearby construction site floats near the shore of a lake. it floats in very calm water with half of its volume just above the surface. what is the density of this piece of wood? the density of water is 1000 kg/m3 .
A piece of wood from a nearby construction site floats near the shore of a lake. it floats in very calm water with half of its volume just above the surface. The density of this piece of wood will be 500 kg/[tex]m^{3}[/tex]
The floatation principle states that when an object floats in a liquid, the buoyant force acting on the object is equal to the object's weight.
since ,
buoyant force = rho * g * V
= 1000 * g * (V/2) equation 1
objects weight = mg equation 2
equating equation 1 and equation 2
500 * g * V = mg
mass = 500 V
density = mass / volume = 500 V / V
= 500 kg/[tex]m^{3}[/tex]
The density of this piece of wood will be 500 kg/[tex]m^{3}[/tex]
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in a double-slit experiment, the slit separation d is 2.00 times the slit width w. how many bright interference fringes are in the central diffraction envelope
The number of bright interference fringes in the central diffraction envelope is 3.
To determine the number of bright interference, we need to understand the equation of first minima in the diffraction pattern, and the equation of angular locations of the double slit interference pattern.
For the equation of first minima in the diffraction pattern is:
[tex]W[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
For the equation of angular locations of the double slit interference pattern is:
[tex]d[/tex]·[tex]Sin[/tex]θ = [tex]m_{2}[/tex]·λ..... (1)
Here, W is single slit width while d is slit separation
Next, we need to determine the number of bright interference fringes in the central diffraction envelope.
For the first minima, [tex]m_{1} = 1[/tex], then rewrite the equation (1) as follows.
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]1[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = λ..... (2)
Then, from the equations (1) and (2)
[tex]=m_{2}=\frac{d}{w} \\=m_{2}=\frac{2w}{w}\\=m_{2}=2[/tex]
Therefore, there are 3 bright fingers, 1 at the centre and 2 in each side.
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suppose radius of earth known to 3595 miles with tolerance of - 0.1 miles what effect does this have on calculation of surface area
The effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %
SA = 4 π r²
SA = Surface area of a sphere
r = Radius
Actual surface area,
r = 3595 mi
SA = 4 * 3.14 * 3595²
SA = 162325754 mi²
Surface area with tolerance,
r = 3595 - 0.1
r = 3594.9 mi
SA = 4 * 3.14 * 3594.9²
SA = 162316723.5 mi²
% error = ( Actual value - Error value ) / Actual value
% error = ( 162325754 - 162316723.5 ) / 162325754
% error = 9030.5 / 162325754
% error = 5.56 * [tex]10^{-5}[/tex]
% error = 0.00556 %
Therefore, the effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %
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Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with speed 8 m/s. what was the initial speed of car a?
The initial speed of car A is 15.18 m/s.
Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.
p=p'
pa+pb = pa'+pb'
(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
ma = mass of object A (kg) = 1,783 kgmb = mass of object B (kg) = 1,600 kgva = speed of object A before collides (m/s)va' = speed of object A after collides (m/s) = 8 m/svb = speed of object B before collides (m/s) = 0 m/svb' = speed of object B after collides (m/s) = 8 m/sp = momentum before collision (Ns)p' = momentum after collision (Ns)(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)
(1,783×va) + 0 = 14,264+12,800
(1,783×va) = 27,064
[tex]va \:=\: \frac{27,064}{1.783}[/tex]
va = 15.18 m/s
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A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall. a) Will the ball pass over the wall? b) If not, where will it hit the wall and with what velocity?
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
It is the amount of change in velocity per unit time. The velocity change can be calculated using the formula: velocity change = final velocity - initial velocity. This is the time when: The rate of change in velocity is expressed in
Given
A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall.
We have to determine
a) Will the ball pass over the wall?
b) If not, where will it hit the wall and with what velocity?
From the given information
Initial velocity v =20m/s
Initial velocity along x direction vx = vcos300
= 20 cos300
= 20 x 0.866
= 17.32m/s
Initial velocity along y direction vy = v sin300
= 20 sin300
= 20 x 0.5
= 10m/s
Displacement along +ve x = 40m
Time required to travel t = x/vx
= 40/17.32
= 2.31seconds
At this time displacement of the ball along the y direction
Sy = vyt – 1/2gdt2
= 10x2.31 – ½ x 9.81 x (2.31)2
= 23.10 – 26.17
= - 3.07m
Since displacement is in a negative value, it will hit the wall and will not pass over the wall
The ball will hit at d distance from the ground
H = (10 – 3.07)
= 6.93m
Final velocity along +ve y = v’y = vy –gt
= 10 – 9.81 x 2.31
= 10 – 22.66
=-12.66m/s
velocity along +ve x = v’y = vx
= 17.32m/s
So-net velocity of the ball v’= √((v^' x)^2+(v^' y)^2 )
= √(〖(17.32)〗^2+〖(-12.66)〗^2 )
= 21.45m/s
Therefore
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
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An inclined plane make an angle of 30 degree with the horizontal. Find the contant force applied parallel to the plane required to caue a 15kg box to lide up the plane with anm acceleration of 1. 2m/^2 and down thge incline with an acceleration o1. 2m/^2. Neglect friction force
The constant force applied parallel to the plane required to cause a 15kg box to line up is 127.31 N.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass =15 kg
Normal force = mgCos30°
parallel force = mgsin30°
acceleration required = 1.2 m/s²
Contact force = 15 × 9.8 × √3/2
= 127.31 N
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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How can gravity's role in tectonic plate motion be described? question 6 options: earth's magnetic field reverses ridge push and slab pull circulating material in the mantle earth's internal heating
Gravity's role in the tectonic plate motion can be described on the basis of ridge push and slab pull of tectonic plates.
What are ridge push and slab pull?Ridge push refers to gravitational sliding. It is a driving force for plate motion in plate tectonics, occurring at mid-ocean ridges as the result of the rigid lithosphere sliding down the hot and raised asthenosphere below mid-ocean ridges.
Slab pull is a pulling force that is exerted by a cold and dense oceanic plate plunging into the mantle. The term for the process of a tectonic plate descending into the mantle is subduction. Subduction may emerge due to gravity.
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a heat exchanger has an effective area of 2500 cm2 and cools 1 kg/min of blood from 37 degrees celsius to 30 degrees celsius with a lmtd of 5.4 degrees. what is the overall heat transfer coefficient of the exchanger if the specific heat capacity of blood is 4177 j/kg-c.
The answer is 361 W/m2-C.
This approach is most commonly used when the building manager or engineer is trying to determine the heat transfer coefficient and outflow fluid temperature and already knows the heat exchanger size and inflow temperature. Subtract the end temperature from the start temperature to get the difference.
You can calculate the efficiency of anything by dividing the energy input and energy output by 100%. We usually use this equation to express energy as heat or electricity. For relatively low-pressure equipment, if the design pressure on the low side is more than two-thirds of the design pressure on the high side a full pipe rupture is not a realistic scenario.
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a multimeter is used for? select one: a. frequency testing of coaxial cable b. general electrical measurements c. testing the bandwidth of all types of cables d. testing continuity of fiber optic cable
A multimeter is used for general electrical measurements. So, the correct option is (b)
What is a multimeter?A multimeter is an electronic measuring device that combines multiple measurement functions into one device. A typical multimeter include features such as the ability to measure voltage, current, and resistance.
Most multimeters have the ability to test circuit continuity. This makes it easier to find faults such as bad cables. It also helps to see if two points in the circuit are connected.
The typical multimeter can measure voltage, resistance, and current. In this case, the device is also called a Volt-Ohm Milliammeter (VOM), since it has the functions of a voltmeter, an ammeter, and an ohmmeter. Some of them even offer measurements of additional properties such as temperature and capacitance.
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a wooden bucket filled with water has a mass of 56 kg and is attached to a rope that is wound around a cylinder with a radius of 0.060 m. a crank with a turning radius of 0.35 m is attached to the end of the cylinder. what minimum force directed perpendicularly to the crank handle is required to raise the bucket? the acceleration of gravity is 9.81 m/s 2 . answer in units of n.
The acceleration of gravity is 9.81 m/s 2 . answer in units of n. The minimum force required was 93.20N.
What is force?
Force is a quantitative representation of an interaction that creates a change in the motion of an item. In reaction to a force, an item may accelerate, slow down, or change direction. In other words, force is any action that tends to maintain or alter the motion of a body or distort it.
Total mass=56Kg
tied radius=0.060m
turning radius=0.35m
g=9.81m/s2
T=0.35F
where F is the force that we want
W=mg
=68Kg
W(0.060)=T=0.35F
0.060/0.35=0.171
F=0.171W
0.171(56)=9.576Kg
=93.20N
So here by the force required is=93.20N
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To open a box, you apply 50 N of force to a crowbar. the crowbar applies 450 N of force to the lid of the chest. What is the mechanical advantage of the crowbar?
Answer: The mechanical advantage of the crowbar 9
Answer:
9
Explanation:
50N-load
450N-effort
m.a=load÷effort
450÷50=9
What about the Model of Static Electricity makes it mechanistic?
The material that is attracted to the electron which is negatively charged and the material from which the electron was lost is considered as positively charged that makes the Mechanism of Static Electricity.
What is Model of Static Electricity?Static Buildup apparatus. The static build up is the phenomenon in which electric charges are traded between the surfaces of two objects that come into contact with each other. In this procedure, one object static takes on a positive charge and the other a negative charge. The material that interested the electron is negatively charged and the material from which the electron was lost is positively charged. This is the appliance for the Generation of Static Electricity. Static electricity is the result of a disparity between negative and positive charges in an object.
So we can conclude that Static electricity is an variance of electric charges within or on the surface of a material or between materials.
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the x, y, and z components of a magnetic field are bx = 0.088 t, by = 0.13 t, and b, = 0.15 t. a 37-cm wire is oriented along the z axis and carries a current of 3.4 a. what is the magnitude of the magnetic force that acts on this wire?
The magnitude of the magnetic force that acts on this wire is 0.2298 N.
The Magnetic Fields is an American band founded and led with the aid of Stephin Merritt. Merritt is the organization's number-one songwriter, producer, and vocalist, as well as a frequent multi-instrumentalist. A magnetic subject is the vicinity around a magnet, magnetic item or an electric powered price wherein magnetic pressure is exerted.” Huh? allow's put it this way.
The magnetic field is the location around a magnet wherein the effect of magnetism is felt. We use the magnetic field as a device to describe how the magnetic pressure is distributed within the space around and within something magnetic in nature.
Calculation:-
Magnetic field B = 0.13 i +0.13 j +0.17 k
length L = 25 k cm =0.25 km
current i = 5 A
the magnetic force acts on the wire F = i ( L X B )
F = 5 [ 0.25 k X ( 0.13 i + 0.13 j + 0.17 k ) ]
= 5 [ (0.25 *0.13) (kXi) + (0.25 *0.13) ( k X j ) + ( 0.25 *0.17 ) ( k X k ) ]
= 5 [ -0.0325 j - 0.0325 I + 0 ]
= -0.1625 I -0.1625 j
magnitude of F = sqrt [ (-0.1625)^2 + (-0.1625)^ 2 ]
= 0.2298 N
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two sounds waves are traveling through an opera house. one wave was produced by a soprano, while a baritone produced the other. which sound wave travels faster?
The speed of each wave is identical. The only factor that affects how fast sound travels is the property of the medium.
What is sound wave?An example of an energy type that propagates through a medium using adiabatic loading and unloading is acoustic waves. Acoustic pressure, particle velocity, particle displacement, and acoustic intensity are crucial parameters for defining acoustic waves. Because the air molecules oscillate back and forth as the sound travels, we refer to sound as a wave. The way the air behaves is similar to a compression or longitudinal wave on a spring.
A sound wave is a pressure wave, which can be conceptualized as variations in pressure over time. Transverse waves include sound waves. The tines of a tuning fork must transfer air from the fork to one's ear in order for one to hear the sound of the fork.
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Hydropower is the production of electrical energy through the use of
A. gravitational force
B. stored energy
C. water flowing upwards
D. water resistance
Answer:
gravitational force .. .. .
Explanation:
hope it helps^o^Evidence card 2: Repelling magnets it was harder to push the magnets together as they got closer together.
What affects the amount of potential energy stored in the magnetic field when a magnet is moved against a magnetic force?
The thing that affects the amount of potential energy stored in the magnetic field when a magnet is moved against a magnetic force is by the strength of the magnet as well as the distance that another magnet or magnetic object is said to be from it.
What aspects of magnetic potential energy affect it?Potential energy between two magnets will depend on their orientation as well as their proximity to one another and their distance from one another. If the opposing poles are kept apart, the potential energy will increase with increasing distance and decrease with increasing proximity.
More energy is transferred to the magnetic field when an object is moved against a stronger magnetic force. Near magnets, magnetic forces are stronger.
Therefore, The power of the magnet and the separation from other magnets or magnetic objects have an impact on how much potential energy is held in the magnetic field.
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It is typical for people in hypnotic trances to temporarily __________. a. begin speaking languages they do not know b. lose track of their immediate surroundings c. become aware of past lives and buried memories d. feel completely paralyzed and unable to act please select the best answer from the choices provided a b c d
It is typical for people in hypnotic trances to temporarily begin speaking languages they do not know .
Option a is correct
Who are people when they are hypnotized?Although hypnosis is frequently described as a sleep-like condition, it is actually better described as a state of sharpened focus, increased suggestibility, and vivid fantasies. People who are hypnotized frequently appear tired and disoriented, yet they are actually hyperaware.
What transpires while a person is tranced?Our brain waves must slow down in order to enter a trance. Throughout the course of the day, people alternate between several brain wave states. Different stages of the brain wave include sleeping, daydreaming, and being fully alert and focused.
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if you use a horizontal force of 30 n to slide a 12 kg wooden crate across a floos at a constant velocity, what is the coefficient of kinetic friction betweem the crate and the floor?
To use the kinetic friction force formula.
What is kinetic coefficient friction?
The proportion of contacting surfaces' kinetic friction forces to normal forces is known as the coefficient of kinetic friction.
What is acceleration?
Any process that causes a change in velocity is referred to as an acceleration. Since velocity depends on both speed and direction, you can only accelerate by changing either one or both.
Fn = 12kg* 9.81 m/s^2 = 117.7 N
since there is no acceleration, friction must equal the horizontal force
30N = 117.7*μ
μ = .255
Therefore, the coefficient of kinetic friction between the crate and the floor is 255.
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the only force acting on a 3.5 kg canister that is moving in an xy plane has a magnitude of 7.2 n. the canister initially has a velocity of 3.2 m/s in the positive x direction, and some time later has a velocity of 4.5 m/s in the positive y direction. how much work is done on the canister by the 7.2 n force during this time?
Answer:
17.5175J
Explanation:
By the work-kinetic energy theorem,
[tex]W=\frac{1}{2} m{v_{f} }^{2} -\frac{1}{2} m{v_{i} }^{2}[/tex]
where [tex]v_{i}[/tex] is initial velocity and [tex]v_{f}[/tex] is final velocity. Note that their directions make no impact on the problem.
We can simplify this to:
[tex]W=\frac{1}{2} m({v_{f} }^{2} -{v_{i} }^{2})[/tex]
Now sub in our values:
[tex]W=\frac{1}{2} (3.5)({4.5 }^{2} -{3.2 }^{2})[/tex]
W= (1.75)(20.25-10.24)=17.5175J
This is the third time I’m asking, please, On a wet road, is a higher coefficient of friction on the tires safer or a lower one and pls explain I don’t get it
Answer:
higher is safer
Explanation:
because it is a wet slippery surface, you would need more friction on the tires, to get more traction in the slippery wet road, if you had low friction you would not move anywhere and or could swerve off somewhere
a car company wants to ensure its newest model can stop in 50 m when traveling at 30 m/s (which is about 108 km/h). if we assume constant deceleration, find the value of deceleration that accomplishes this
A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.
How to calculate deceleration ?While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.
We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.
The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.
velocity of car = 30 m/s
car need to stop in 50m
Deceleration a = v^2 – u^2 / 2s
= 0^2 - 50^2 / 2*30
= 11.56
Deceleration of the care = 11.56 ms−2
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A quantity of 100g of ice at 0c and 50g steam at 100 c are added to a container that has 150 g water at 30c. Determine the final temperature in the container. Ignore the container itself in your calculations.
Answer:90g for 70km
Explanation:
you place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizontally at a speed of vv. you then repeat the exact same procedure (pulling the elastic band back the same distance) with a smaller pebble. the smaller pebble leaves the slingshot with a speed of 5v5v. how does the mass of the larger pebble compare to that of the smaller pebble?
The smaller pebble leaves the slingshot with a speed of 500 m/s.The mass of the larger pebble 25 times more mass compare to that of the smaller pebble.
In Both the cases work done by the elastic band is same i.e
WLarger = WSmaller
(1/2)MLargerVLarger2 = (1/2)MSmallerVSmaller2
MLarger/MSmaller = (VSmaller/VLarger)2
MLarger/MSmaller =(500/100)2 =25
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Michael uses his bike to apply 456 N to himself and the bike by pedaling as he approaches a 1.4 m tall ramp which is 3.0 m away. He starts from rest to accomplish this feat. How fast will he be moving just before he hits the ramp? (Mike and the bike have a combined mass of 136 kg)
*WORK OUT AND USE UNITS*
The speed of Mike and his bike before hitting the ramp is 4.48 m/s.
What is the acceleration of Michael and his bike?The acceleration of Michael and his bike is determined by applying Newton's second law of motion as follows.
According this law, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
a = F/m
where;
a is the acceleration of Michaelm is mass of Michaela = (456) / (136)
a = 3.35 m/s²
The speed of Mike and his bike before hitting the ramp is calculated as follows;
v² = u² + 2as
where;
u is the initial speed of Mike = 0a is acceleration of Mikev is the final velocity of Mikes is the distance travelled by Mikev² = 0 + 2(3.35)(3)
v² = 20.1
v = √20.1
v = 4.48 m/s
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