A system's Center of Mass won't change if no external forces are applied to it, which means no forces from sources outside the system.
What is center of mass?In a uniform gravity field, the phrases "center of mass" and "center of gravity" are interchangeable to refer to the particular place in an item or system that can be used to describe how the system reacts to outside forces and torques. The idea of the center of mass is to calculate the average mass by dividing it by the distance from a fixed location.
Because no external force actuated on the system or any of its components, C.M. velocity is zero (0) for this problem. Although it is true that the two people exerted pressures on themselves, these forces were internal (i.e., produced by system components themselves) and as a result, the system Center of Mass was unaffected.
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a bus travels with an average velocity of 60km how long does it take to cover a distance of 500km
Solution: given that; velocity (v)=60km/hr, distance (d)=500km, time (t)=? From velocity=distance/time....... :. 60=500/t, cross-multiply..... 60t=500, divide both sides by 60...... 60t/60=500/60, t=500/60, t=8.33~. Therefore the bus took 8hours, 33 minutes to cover the distance of 500km.
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2. There is a bell at the top of a tower that is 45m high. The bell weighs 190N.
The bell has
energy. Calculate it:
Answer:
4,275
Explanation:
formula:1/2mv square
1/2×190×45=4,275
What was the force of gravity on the ball when it was at the highest point in its flight?
an airplane has a mass of 26900 kg and takes off under the influence of a constant net force of 38700 n. what is the net force that acts on the plane's 106 kg pilot?
The net force that acts on the plane's 106 kg pilot is 151.58N.
What is a net force?The net force acting on an object is the result of all pushing and pulling forces acting on the object collectively (the sum). If there is an imbalance in the pushing and pulling forces acting on an object, the object will accelerate in the direction of the net force.
All forces acting on an object are added together to form the "net force." If the object is not moving, then this net force must be equal to zero, according to Newton's First Law.
acceleration a = F/m
a = 38700/ 26900
a = 1.43m/s²
F = ma
F = 106×1.43
F = 151.58N.
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The pressure of the gas is 112 kPa when its temperature is 35 °C.
The gas is heated to 340°C using some different apparatus.
Calculate the pressure of the gas when its temperature is 340 °C.
Assume the gas has a constant volume.
Pressure =
kPa
Answer:
Pressure = 223 kPa
Explanation:
Given:
p₁ = 112 kPa = 112 000 Pa
t₁ = 35°C; T₁ = 273 + 35 = 308 Pa
t₂ = 340°C; T₂ = 273 + 35 = 613 Pa
V - const
___________
p₂ - ?
Charles' law:
p₁ / T₁ = p₂ / T₂
The pressure:
p₂ = p₁·T₂ / T₁
p₂ = 112 000·613 / 308 ≈ 223 000 Pa or p₂ = 223 kPa
water flows from the pipe shown in the figure with a speed of 8.0 m/s what is the water pressure as it exits into the air? what is the height h of the standing column of water?
The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.
The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.
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A weightlifter lifts a 32 kg barbell a distance of 0.1 m in 0.83 s. How much power is demonstrated by the lift?
Answer:
Explanation:
Work:
A = m·g·h = 32·9.8·0.1 = 31.36 L
Power:
N = A / t = 31.36 / 0.83 ≈ 38 W
A 1.5 kg ball is dropped so that is is traveling at a velocity of -27 m/s when it hits the ground. If the ball rebounds upward with the same speed, what is the change in momentum of the ball?
Answer:
The change in momentum of the ball = 81 kg·m/s
Explanation:
Given:
m = 1.5 kg
V₁ = - 27 m/s
V₂ = + 27 m/s
____________
Δp - ?
The change in momentum of the ball:
Δp = m·ΔV
Δp = m· (V₂ - V₁) = 1.5·(27 - (-27)) = 1.5·(27 + 27) = 81 kg·m/s
using your spectroscope, you observe a light source and see several strong, distinct lines. is this source continuous or discrete? given a line with a wavelength corresponding to 500 nm, calculate the energy of the emitted light.
With the aid of your spectroscope and E = (h*c)/wavelength, you can determine the energy of the emitted light to be 3.97 x 10-19.
What does a mean in terms of wavelength?mathematical representation The movement v (in the x direction), frequency f, and wavelength of traveling sinusoidal waves are frequently expressed mathematically as follows: where y is the value of the wave at any place x and time t, and A is the wave's amplitude.
What is the wavelength measurement unit?The symbol for the wavelength in the SI is typically m, or one metre. The multiples or fractions of something like a meter are also employed for measuring wavelength. Notably, when wavelengths are a significant attribute, exponential powers of 10 are employed. Shorter wavelengths are given as negative exponentials.
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1 5kg cat is lifted 2 m into the air.how much gpe does it gain?
Answer:
Potential Energy= mgh = (5)(9.8)(2)= 98.xii. a fan rotating with an initial angular velocity of 1200 rev/min is switched off. in 2 seconds, the angular velocity decreases to 300 rev/min. assuming the angular acceleration is constant, how many revolutions does the blade undergo during this time?
The blade goes through 25 evolutions throughout this period.
What does angular velocity mean?Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies. The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.
Formula using,
Ф = (ω+ω')t/2
Where Ф = amount of revolution the blade undergo,
Given: ω = 1200 rev/min,
ω' = 300 rev/min,
t = 2 seconds = (2/60) min = 1/30 min
Substitute into equation 1
Ф = (1200+300)(1/30)/2
Ф = 1500/(30×2)
Ф = 1500/60
Ф = 25revolutions.
The blade goes through 25 evolutions throughout this period.
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A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material. Coaxial cabling is the primary type of cabling used by the cable television industry and is also widely used for computer networks such as Ethernet, on account of its superior ability to transmit large volumes of electrical signal with minimum distortion. Like all other kinds of cables, however, coaxial cables also have some self-inductance that has undesirable effects, such as producing some distortion and heating
Coaxial cable may experience unpleasant interference from electrical wires. Therefore, even if the cables are divided by wood or other building materials, keep coax wires at least 6 inches away from electrical cables.
Explain about the Coaxial cables?A form of copper cable known as coaxial cable is designed to prevent signal interference by using a metal shield and other parts. It is generally utilized by cable TV providers to link their satellite antenna facilities to client residences and establishments.
The same coaxial cable network that delivers cable television and internet to your house is used for both services. First, your internet service provider sends a data signal to your modem via the coaxial cable, also known as coax, inside your home.
You will need a coaxial cable connected to your TV if you want to watch live TV through a provider like Free view or Free sat.
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a rock is dropped from a 100-m-high cliff. how long does it take to fall (a) the first 50 m and (b) the second 50 m?
(a) For the first 50 m:
h1 = 0.5 x a x t12
50 m = 0.5 x 9.8 m/s2 x t12
t1 = 3.19 s
Time to fall first 50 m = 3.19 s
(b) For the full 100 m:
h2 = 0.5 x a x t22
100 m = 0.5 x 9.8 m/s2 x t22
t2 = 4.52 s
Time to fall second 50 m = t2 - t1 = 1.33 s
Dropped rocks and other objects gain speed rapidly as they fall. Velocity defines the direction in which a body or object is moving. Velocity is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance.
If our planet loses gravity for even 5 seconds it means the end of life on Earth as we know it. Gravity pulls objects together. The greater the mass of an object, the stronger its gravitational pull. Any submarine you choose for skydiving should be designed with movement in mind. If the weather is cool on the day of skydiving, you should choose pants that cover the entire leg. We recommend wearing sweatpants or sweatpants.
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Which of the following describes a way that neighborhoods help children build new relationships?
OA neighborhood holds a winter festival with activities for children and families.
O Families of the neighborhood walk around the block on differing weeknights.
O Lawn crews ensure that the neighborhood is properly maintained each week.
O Members of the community form a Neighborhood Watch team.
The neighborhood can help children build new relationships by holding a winter festival with activities for children and families.
In today's world, where everyone is quite busy in their own world, children have academic pressure and many more.
They tend to detach themselves from people, and hence many relationships ruin.
Building relationship helps the children grow and makes them more sociable. It boots their intelligence and makes them aware of the importance of having a relationship and building bonds with people.
The neighborhood holds a winter festival with activities for children and families is a great way to build new relationships.
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derive from one of the laws of motion the relation between the momentum produced in a body and the force applied on the body
Answer:
The fact that change in moment is equal to force times duration can be derived from Newton's Second Law of Motion (assuming that the net force on the object is constant.)
Explanation:
Let [tex]m[/tex] denote the mass of an object. Let [tex]\Delta v[/tex] denote the change in the velocity of this object. The change in momentum of this object will be [tex]\Delta p = m\, \Delta v[/tex].
Let [tex]F_{\text{net}}[/tex] denote the net force (resultant force) on the object. Let [tex]a[/tex] denote the acceleration of this object. By the law of motion, [tex]F_{\text{net}} = m\, a[/tex], or equivalently, [tex]a = (F_{\text{net}} / m)[/tex].
Assume that this net force is constant and is exerted on this object over a period of [tex]\Delta t[/tex]. With an acceleration of [tex]a = (F_{\text{net}} / m)[/tex], the velocity of this object would have changed by:
[tex]\begin{aligned}\Delta v &= a\, \Delta t \\ &= \left(\frac{F_{\text{net}}}{m}\right)\, (\Delta t) \\ &= \frac{F_{\text{net}}\, \Delta t}{m}\end{aligned}[/tex].
Multiply both sides of this equation by the mass [tex]m[/tex] of the object to obtain:
[tex]m\, \Delta v = F_{\text{net}}\, \Delta t[/tex].
Note that [tex]m\, \Delta v[/tex] is equal to the change in momentum ([tex]\Delta p = m\, \Delta v[/tex].) Therefore, if the net force [tex]F_{\text{net}}[/tex] on the object is constant, the change in the momentum [tex]\Delta p[/tex] over time period [tex]\Delta t[/tex] will be equal to [tex]F_{\text{net}}\, \Delta t[/tex] (net impulse on the object.)
when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about:
When an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
Luminosity and apparent brightness are about brightness, but from a different point of view. The difference between luminosity and apparent brightness is that luminosity tells us exactly how bright a star really is while apparent brightness only tells us its brightness seen from Earth.
L / Lsun = ( d / dsun )² = b / bsun
L = Luminosity of a star
Lsun = Luminosity of sun
d = Distance of star
dsun = Distance of sun
b = Brightness of star
bsun = Brightness of sun
Therefore, when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
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an automobile of mass 1500kg moving at 25.0m/s collides with a truck of mass 4500kg at rest. this time, the car and the truck bounce off each other completely elastically. what is the final velocity of the car (in m/s) after the collision? call the initial direction of the automobile positive.
the final velocity of the car (in m/s) after the collision is 6.25 m/s
12.5 m/s is moving in the initial direction of the car
1. A car of mass 1500 kg moving at a speed of 25.0 m/s collides with a truck of mass 4500 kg at rest. the bumpers of both vehicles lock on impact.
A. Compare the force exerted by the car on the truck with the force exerted by the truck on the car during the collision. Is one force greater than the other, or are they equal in magnitude?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
b. What is the final speed of the car and the truck just after the collision? show your calculations.
v=m1u1+m2u2/m1+m2=1500*25+0/1500+4500=6.25 m/s
2. the same collision as in the above question occurs, but this time the car and truck bounce off each other completely elastically.
C. Compare the force exerted by the car on the truck with the force exerted by the truck on the car in the collision. is one force greater than the other or are they equal?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
d. what is the final speed of the car and truck just after the collision?
view the calculation
v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2=[1500-4500/6000]*25+[9000/6000]*0=-12.5 m/s
a negative sign means the car is moving backwards at 12.5 m/s
v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1=[4500-1500/6000]*0+[3000/6000]25=12.5 m/s
moves in the original direction of the car
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a 650-n billboard worker stands on a 4.00-m scaffold weighing 600 n and supported by vertical ropes at each end. how far would the worker stand from one of the supporting ropes to produce a tension of 660 n in that rope?
Answer:
1.785 m
Explanation:
Without the worker the scaffolding produces 300N tension in each rope
if worker is in the middle, each rope will support 1/2 of worker's weight (325 N) for a total of 625 N <==== so worker will be pretty close to middle for tension of 660 N
Need 360 N in addition to 300N board
360 * x = 290 ( 4-x)
x = 1.785 meters from an end
Well ....that is kinda the 'intuitive approach'.....maybe this way will be more clear:
The moments around one end have to be = 0 or the plank will move
from the left end moments:
600 ( 2.000) + 650 ( x) = 660 (4.000)
x = 2.215 m from left end or 1.785 m from R end (that has the 660 N tension)
explain how the energy/velocity of water/wind controls the size of the particles in clastic/detrital) rocks
In fast-moving water only coarse material settles out and fine material is carried away. In slow-moving water only fine material, which can settle out.
What is the velocity of water?The velocity of water is the rate at which water moves.A technique that can quickly clear your drains is high-velocity water jetting. This procedure forces water through your pipes at a very high velocity, which aids in dissolving and removing any material that has built up in your drains.The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).The volume and speed of the water affect the flow. It is significant because of how it affects the stream's ecosystems, living things, and water quality. Large, fast-moving rivers can be exposed to pollution releases and experience minimal effectsTo learn more about velocity of water refer to:
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a 58 kg sprinter, starting from rest, runs a 60 m long race in 7.8 s with a constant acceleration. how much work does the sprinter do during the first 2.5 s of the race?
Work done by the sprinter in first 2.5 s will be 702.699 J.
Work done is the product of force and distance covered.
Mathematically, W = Force * DistanceMass of the sprinter = 58 kg
Distance covered by the sprinter = s = 60 m
Total time taken by the sprinter = t = 7.8 s
According to the Equations of motion S = ut + [tex]\frac{1}{2}at^{2}[/tex]u = initial velocity = 0
a = constant acceleration
60 = [tex]\frac{1}{2}a7.8^{2}[/tex]
60.84 a = 60 * 2
a = 1.97 [tex]m/s^{2}[/tex]
For a = 1.97 [tex]m/s^{2}[/tex] and t = 2.5 s
d = [tex]\frac{1}{2}at^{2}[/tex]
Here also u is '0' because the distance is being measured from the starting point.
d = [tex]\frac{1}{2} *1.97*(2.5)^{2}[/tex]
d = 6.15 m
Work done by the sprinter = F * d
Force = mass * acceleration
F = 58 * 1.97
F = 114.26 N
distance for first 2.5 sec is 6.15 m
Therefore Work done = 6.15 * 114.26
W = 702.699 J
Work done by the sprinter is 702.699 J.
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how much work is done when a 125 g tomato is lifted 13.6 m ? express your answer with the appropriate units.
Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .
What do you understand by work done?The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.
Work can be calculated by multiplying force with distance in the direction of force , and can be written as :
W = F × d
Given m= 125g = 0.125 kg
h= 13.6 m
W= P E
= m *g *h
= 0.125 * 9.8 * 13.6
Work done = 16.66 J
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what is the length between two poles if the hanging cable is 80m long, poles are 50m tall, and the distance between the hanging cable and ground is 10m?
The distance between the poles is 46 m.
Given information indicates that the two towers are 50 meters tall and that the cable is 80 meters long. The midpoint of the cable, designated as h, is 10 meters above the ground.
Let the height be y and the distance from the midpoint to either tower be x. therefore by catenary equation, we get,
y=hcos(x/h)
=>50=10cos(x/10)
Therefore 5=cosx/10
By the tabulated value from the hyperbolic cosine function, we get the value of
cos⁻¹(5)=x/10
=>2.3=x/10
=>x=23
Therefore the distance between the poles is 2x = 2 x 23 = 46 m.
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a. When rock on Earth's surface is broken into
smaller pieces, forming loose material
When rock on Earth's surface is broken into smaller pieces, forming loose material is called Weathering.
Physical weathering and chemical weathering are the two basic types of weathering. On this page, we discuss mechanical weathering (and more).
Rocks naturally fracture at a number of different levels. The borders between mineral grains can be a source of weakness in the rock. Sedimentary rocks are frequently stratified, and the layers are occasionally not tightly bonded together. As larger, more massive rocks are exposed by erosion, joints (cracks with no relative motion across them, merely spreading) may form in the rocks. These rock fissures become wider due to physical deterioration. Of course, biological weathering refers to weathering caused by living creatures.
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a string is under a tension of 760.0 n. a 1.7 m length of the string has a mass of 4.8 grams. what is the speed of a transverse wave of wavelength 0.50 m in this string? what is the frequency of the wave?
The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.
Explain about the frequency of wave?
The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.
Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.
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9. if suddenly, the sun were to quantum tunnel to a different dimension and stop applying a force on the planets, in what kind of path would the planets move? explain.
The planets move on linear motion without acceleration. Motion in one spatial dimension is described as linear motion, often known as uniform motion or rectilinear motion.
Explain about the Linear motion?Moving in a straight line is the motion that an object naturally exhibits. A forceless item will move in a straight line indefinitely, according to Newton's First Law of Motion.
An object is said to be moving linearly when it has a tendency to move in a straight line. Rectilinear motion is another name for linear motion. Many of the things we do every day, like walking, bowling, playing on a slide, etc., exhibit linear motion in reality.
Both the ultimate displacement and the velocity are positive, indicating that they are moving in the same direction. The link between displacement, average velocity, and time is described by the equation x = x0+(average v)t.
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what is the heaviest the book he can hold vertically before it slips out of his fingers? the coefficient of static friction between his fingers and the book cover is 0.88
Mass of the heaviest book is 0.733 kg.
Heaviest book has weight
= (6 + 6) * 0.6 N
= 7.2 N
If m = mass of the heaviest book in kg
m = 7.2/9.81 kg
= 0.733 kg.
Children often bring a well-established "life-view" of friction with them because of their experiences with slippery surfaces like frozen ponds (low friction) and "gripping" surfaces like deep pile carpets (high friction) and the effects they have on movement. This way of existence needs to be expanded and understood in the perspective of science.
The force that modifies movement as a result of surface/surface interaction is known scientifically as friction (all changes of movement require the action of a force). When using diagrams to portray forces in action, the direction of the frictional force should be depicted as being opposed to that of the movement.
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a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket if the thrust of the rockets is 150n
The drag force acting on the rocket is 80N.
Give an explanation of drag force?The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.
The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.
The drag force acting on the rocket F = ma
Given,
m = 4kg, a = 20ftm/s²
Substituting m and a values in the above formula,
The drag force acting on the rocket F = 4×20
The drag force acting on the rocket F = 80N.
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A 30.0 kg object is falling in air and experiences a force due to air resistance of 50.0 N. What is the net force acting on the object?
Answer:
250N
Explanation:
weight of object - air resistance= net force
weight=mg
=30×10
=300N
air resistance =50
300-50=250
A 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. On the axes below, sketch a graph of the vertical component of the ball's velocity as a function of time for the first 3 s of motion.
The graph of the vertical component of the ball's velocity is in the attachment
What is speed?Speed is the distance moved per unit time.
What is velocity?Velocity is the total displacement per unit time of an object.
How to sketch a graph of the vertical component of the ball's velocity as a function of time for the first 3 s of motion?Since a 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. To determine the vertical component of velocity,we use the equation of motion
v = u - gt where
v = final vertical component of velocity, u = initial vertical component of velocity = u'sinФ where u' = initial launch speed = 20m/s and Ф = angle above horizontal = 37°, g = acceleration due to gravity = 9.8 m/s² and t = timeSo, substituting the values of the variables into the equation, we have
v = u - gt
v = u'sinФ - gt
v = (20 m/s)sin37° - (9.8 m/s²)t
v = (20 m/s) × 0.6018 - (9.8 m/s²)t
v = 12.04 m/s - (9.8 m/s²)t
So, for the first 3 seconds, we have
for t = 0 s
v = 12.04 m/s - (9.8 m/s²) × 0 s
v = 12.04 m/s - 0 m/s
v = 12.04 m/s
for t = 1 s
v = 12.04 m/s - (9.8 m/s²) × 1 s
v = 12.04 m/s - 9.8 m/s
v = 2.24 m/s
for t = 2 s
v = 12.04 m/s - (9.8 m/s²) × 2 s
v = 12.04 m/s - 19.6 m/s
v = -7.56 m/s
for t = 3 s
v = 12.04 m/s - (9.8 m/s²) × 3 s
v = 12.04 m/s - 29.4 m/s
v = -17.36 m/s
So, we plot the graph of the vertical component of the ball's velocity using the equation v = 12.04 m/s - (9.8 m/s²)t
Find the graph in the attachment
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monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35 mm. find the wavelength of the light.
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
How to find Wavelength of the light?When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
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