Two points are plotted on a number line: -11.2 and 3.3. What is
the distance between these two points?

| - 4 | = 4

Thus :

f ( | - 4 | ) = f ( 4 )

f ( 4 ) = ( 4 )^2 - 2(4) + 4

f ( 4 ) = 16 - 8 + 4

f ( 4 ) = 16 + 4 - 8

f ( 4 ) = 20 - 8

f ( 4 ) = 12

Answer:

(x + 3i) * (x - 3i) = x^2 + 3xi - 3xi - 9(i^2) = x^2 + 9

Step-by-step explanation:

Answer:

b=a/2

c=a/2

b=c

a=2b and a=2c

Answer:

It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.

Instead of [tex]\frac{KN}{K'N'}[/tex], it should be [tex]\frac{K'N'}{KN}[/tex]. That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.

Hope this helps!

Answer:

[tex]y+6=-\frac{1}{2} (x-3)[/tex]

Step-by-step explanation:

Since point-slope form is  [tex]y-y1=m(x-x1)[/tex], you have to plug in the values given to you to create the equation. The "y1" is the "y" coordinate given to us, while the x1 is the x coordinate given to us. So, you have to plug in the x and y coordinates, 3 and -6, into the equation. Since two negatives cancel out to be a positive, y--6= y+6. The "m" stands for the slope, so -1/2 is inserted into the equation, giving us  [tex]y+6=-\frac{1}{2} (x-3)[/tex].

Answer:

i [tex]\to[/tex] a

    [tex]n = 96040000[/tex]

i [tex]\to[/tex] b

    [tex]n_1 =24010000[/tex]

i [tex]\to[/tex] c

    [tex]n_2 =41602500[/tex]

ii[tex]\to[/tex]a

     [tex]E = 58.16[/tex]

ii[tex]\to[/tex]b

    [tex]291.84 < \mu < 408.16[/tex]\

ii[tex]\to[/tex]c

    There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

     The sample size is [tex]n = 8[/tex]

      The sample mean is  [tex]\= x = \$ 350[/tex]    

      The sample standard deviation is  [tex]\$ 100[/tex]

Considering question i

    i [tex]\to[/tex] a

         At   [tex]E = 0.02[/tex]  

given that the confidence level is 95%  =  0.95

         the level of significance would be  [tex]\alpha =1-0.95 = 0.05[/tex]

The critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

        [tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]

So  the sample size is mathematically evaluated as

            [tex]n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2[/tex]

=>        [tex]n =[ \frac{ 1.96 * 100}{ 0.02} ]^2[/tex]

=>         [tex]n = 96040000[/tex]

 i [tex]\to[/tex] b

  At  [tex]E_1 = 0.04[/tex]    and  confidence level  = 95%  =>  [tex]\alpha_1 = 0.05[/tex]   =>  [tex]Z_{\frac{\alpha_1 }{2} } = 1.96[/tex]

             [tex]n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2[/tex]

=>           [tex]n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2[/tex]

=>           [tex]n_1 =24010000[/tex]

 i [tex]\to[/tex] c

       At   [tex]E_2 = 0.04[/tex]     confidence level  = 99%  =>    [tex]\alpha_2 = 0.01[/tex]

The critical value of  [tex]\frac{\alpha_2 }{2}[/tex] from the normal distribution table is  

        [tex]Z_{\frac{ \alpha_2 }{2} } = 2.58[/tex]

=>    [tex]n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2[/tex]

=>    [tex]n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2[/tex]

=>    [tex]n_2 =41602500[/tex]

Considering ii

Given that the level of significance is  [tex]\alpha = 0.10[/tex]

Then the critical value  of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

           [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

Generally the margin of error is mathematically represented as

          [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]E = 1.645 * \frac{100 }{\sqrt{8} }[/tex]

         [tex]E = 58.16[/tex]

Generally the 90% confidence interval is mathematically evaluated as

         [tex]\= x - E < \mu < \= x + E[/tex]

=>      [tex]350 - 58.16 < \mu < 350 + 58.16[/tex]

=>     [tex]291.84 < \mu < 408.16[/tex]

So the interpretation is that there is 90% confidence that the mean  fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

Answer:

angleABC=isosceles triangle

angleB=(180-50)÷2=65

angle B=angleX(alternative angle)

angleB=65degree

Answer:

3 s'mores

Step-by-step explanation:

If we center our attention on how many marshmallows you need per s'more which is 2 and you only have 7 you can only make 3 with one marshmallow remaining.

Answer:

x=3

Step-by-step explanation:

● -3 (-4x+4) = 15 + 3x

Multiply -3 by (-4x+4) first

● (-3) × (-4x) + (-3)×(4) = 15 + 3x

● 12 x - 12 = 15 +3x

Add 12 to both sides

● 12x - 12 + 12 = 15 + 3x +12

● 12 x = 27 + 3x

Substract 3x from both sides

● 12x -3x = 27 + 3x - 3x

● 9x = 27

Dividr both sides by 9

● 9x/9 = 27/9

● x = 3

Answer: The car is traveling at 73.63638 Mph

Step-by-step explanation:

1 yard per second is the same as 3 feet per second.

there are 5280ft per mile

So, at 36 yards per second, the car is traveling at 108/5280th (0.02045455) of a mile per second

0.02045455 * 60 (seconds) * 60 (minutes) = 73.63638 Mph

Answer:

To solve for a, you will need to get that variable alone on one side. First you will multiply each side by variable b. This will give you the equation pb = 3a + 4. Next you subtract 4 from each side. This puts it at pb - 4 = 3a. After that you’ll divide both sides by 3 and get a alone. This gives you (pb - 4)/3 = a or, if you switch it around, a = (pb - 4)/3. This is the simplest form when solving for a in this equation.

Answer:

Hello,

All my sentences will be written in mathematical language.

Step-by-step explanation:

[tex]p=\dfrac{3a+4}{b} \\\\p*b=3a+4 \ :\ \forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\p*b-4=3a \ :\forall\ x,y,z\in\mathbb{R} :x=y\Longleftrightarrow\ x+z=y+z\\\\\dfrac{p*b-4}{3} =a \ :\forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\a=\dfrac{p*b-4}{3} \ :\forall\ x,y\in\mathbb{R}:x=y\Longleftrightarrow\ y=x[/tex]

Answer:

[tex]x^6 - \frac{7x^5}{5} - 3x^3 + C[/tex]

Answer:

Cube C

Step-by-step explanation:

[tex]{ \sf{because \: it \: is \: identical}}[/tex]

Answer:

hi

Step-by-step explanation:

hji

hopefully this answer can help you to answer the next question

It sounds like R is the region (in polar coordinates)

R = {(r, θ) : 2 ≤ r ≤ 3 and 0 ≤ θ ≤ π/2}

Then the integral is

[tex]\displaystyle \iint_R\frac{\mathrm dx\,\mathrm dy}{\sqrt{x^2+y^2}} = \int_0^{\pi/2}\int_2^3 \frac{r\,\mathrm dr\,\mathrm d\theta}{\sqrt{r^2}} \\\\ = \int_0^{\pi/2}\int_2^3 \mathrm dr\,\mathrm d\theta \\\\ = \frac\pi2\int_2^3 \mathrm dr \\\\ = \frac\pi2r\bigg|_2^3 = \frac\pi2 (3-2) = \boxed{\frac\pi2}[/tex]

Answer:

9-x^2

Step-by-step explanation:

The difference of means subtracting. the first number is 9 and the second is x^2, so you get 9-x^2

Answer:

1/3

Step-by-step explanation:

there are twelve marbles total. there are 4 blue marbles.

4/12 = 1/3

The value of g + 100 is 150.

Given that,

The average of g and 100 is 75.

And we have to determine the value of g + 100.

So that means

The arithmetic mean of g and 100 is 75.

So, mathematically it should be

[tex]\frac{g + 100}{2} = 75\\\\[/tex]

So, g + 100 = 150

Therefore we can conclude that the value of g + 100 is 150

Learn more about the mean here: brainly.com/question/11230531

perimeter of triangle: P = l+w+h

9+12+10= 31in.

area of triangle: A=b×h÷2

21 + 21 = 42in^2

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

20x⁵⁰

Step-by-step explanation:

With the equation √400x¹⁰⁰

we need to take the square root away separately

√400 = √20*20 = 20

Then with x¹⁰⁰

√x¹⁰⁰ = √x⁵⁰*x⁵⁰ = x⁵⁰

So √400x¹⁰⁰ = 20x⁵⁰

hope this helps

Answer:

It's 28 3/4

Step-by-step explanation:

Answer:

Answer is 19.5

Step-by-step explanation:

27-9+(12-5)÷4

27-9+6÷4   [BOD MAS Rule]

27-9+1.5

28.5-9

19.5

Answer: A. The sampling follows a normal distribution.

              B. Between 25.14 and 30.86

              C. About 95% will contain the true mean and about 5% won't

Step-by-step explanation: A. The sampling is normally distributed because:

B. For a 95% confidence interval: α/2 = 0.025

Since n = 210, use z-score = 1.96

To calculate the interval:

mean ± [tex]z.\frac{s}{\sqrt{n} }[/tex]

Replacing for the values given:

28 ± [tex]1.96.\frac{21}{\sqrt{210} }[/tex]

28 ± [tex]1.96*1.45[/tex]

28 ± 2.84

lower limit: 28 - 2.84 = 25.14

upper limit: 28 + 2.84 = 30.86

Confidence Interval is between 25.14 and 30.86.

C. Confidence Interval at a certain percentage is an interval of values that contains the true mean with a percentage of confidence. In the case of number of times per day students text, 95% of the interval will contain the true mean, while 5% will not contain it.

Answer: about 40.54°

Step by step explanation:

7^2 =  5^2 + 10^2  - 2(5)(10)cos(B)

cos(B)  = (7^2 - 5^2 - 10^2) / (-2(5)(10) )

B = cos-1 [ (7^2 - 5^2 - 10^2) / (-2(5)(10) ]  =  cos-1 (.76) = about 40.54°

Answer:

√32

Step-by-step explanation:

Answer:

C = 4

Step-by-step explanation:

solution:

f(x) can be differentiated on (0,16)

By mean value theorem

= f(16) = 4

= f(0) = 0

= f(b) - f(a)/b - a

= f(4) - f(0)/ f(16) - f(0)

= f'(c) = 1/2√C

= 1/2√C = 4/16

= 1/2√C = 1/4

= 4 = 2√C

= √C = 4/2

we make c the subject of the formula and also eliminate the square root

= √C = 2

= C = 2²

= C = 4

Answer:

[tex]L + \frac{5}{8} = 1[/tex]

Step-by-step explanation:

Given

A cup of coffee

Kelly drank 5/8 of the coffee

Required

Determine how much is left

Start by representing the amount of coffee left with L

Because the amount of coffee Kelly drank is in fraction (5/8), the total cup of coffee will equate to 1;

Hence, the addition equation as requested in the question to represent the scenario is

[tex]L + \frac{5}{8} = 1[/tex]

Answer:

O (-4,1)

I hope I helped you^_^