Two tiny, spherical water drops, with identical charges of -6.19 × 10-16 C, have a center-to-center separation of 1.22 cm. (a) What is the magnitude of the electrostatic force acting between them? (b) How many excess electrons are on each drop, giving it its charge imbalance?

Answer:

Explanation:

What is average speed?

It is the total distance traveled divided by the time taken to cover the total distance traveled

Given that the various distances are

20 miles and 10 miles

the total distance traveled is 20+10= 30 miles

the average speed is expressed as

average speed= total distance/time taken

average speed= 30/1

average speed= 30 miles/hour

The average velocity is a vector quantity

the velocity is the average displacement divided by time taken

[tex]displacement= \sqrt{1^2+2^2} \\\\displacement= \sqrt{1+4} \\\\displacement=2.24 miles[/tex]

average velocity= displacement / time

average velocity= 2.24 /1

average velocity= 2.24 miles/hour

Answer:

Copernicus rediscovered Aristarchus’s heliocentric model

Explanation:

Answer:

Explanation:

A. Using

Sinစ= y/ L = 0.013/2.7= 0.00481

စ=0.28°

B.here we use

Alpha= πsinစa/lambda

= π x (0.0351)sin(0.28)/588E-9m

= 9.1*10^-2rad

C.we use

I(စ)/Im= (sin alpha/alpha) ²

So

{= (sin0.091/0.091)²

= 3*10^-4

The star is approximately 45° above the celestial equator.  (A)

"Declination" on the celestial coordinate system is equivalent to latitude on the terrestrial one.

Answer:

0.2396

Explanation:

Given that

Mass of the hollow sphere, m = 15 kg

Inner radius, r = 12 cm = 0.12 m

Outer radius, R = 18 cm = 0.18 m

Volume of a sphere is expressed as

V = 4/3.π.R³

Density ρ = mass / volume, therefore

Mass = ρ * v

Mass of the hollow sphere is given as

Mass of the outer sphere - mass of the inner sphere

M = ρV(o) - ρV(i)

V(o) = 4/3 * 3.142 * 0.18³

V(o) = 0.0244

V(i) = 4/3 * 3.142 * 0.12³

V(i) = 0.00724

15 = ρ (0.0244 - 0.00724)

15 = ρ (0.01716)

ρ = 15 / 0.01716

ρ = 874 kg/m³

moment of inertia about its centroidal axis is

I = 2/5 ρVR²

I(h) = I(o) - I(i)

I(h) = (2/5 * 874 * 0.0244 * 0.18²) - (2/5 * 874 * 0.00724 * 0.12²)

I(h) = 0.276 - 0.0364

I(h) = 0.2396

Answer:

5730 guppies

Explanation:

1 liter= 38.2 guppies

150 liters= 150×38.2

On planet Q the standard unit of volume is called guppi. Space travelers from Earth have determined that one liter = 38.2 guppies. Guppies in 150 liters is 5730 guppies.

Volume, which is measured in cubic units, is the 3-dimensional space occupied by matter or encircled by a surface. The cubic meter (m³), a derived unit, is the SI unit of volume. A addition new nickname for the cubic (dm³) is a liter (L).

Given that in the question on planet Q the standard unit of volume is called guppi, the conversion of different volume unit,

1 liter = 38.2 guppies, so

150 litre =  5730 guppies

Guppies in the given 150 liters of volume is 5730 guppies.

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Answer:

1.548K

Explanation:

Given that f= 160.23GHz

c= 3E8m/s

b= 2.898*10^-3mk

So using

(Lambda)m x T= b

So T = b/ lambda

But wavelength ( lambda) = c/f

So T = bf/c

= 2.898E-3x 160.23E9/3E8

=1.548K

The feature that characterizes simple columnar epithelium of the digestive tract is the presence of dense microvilli.

Simple columnar epithelium is a type of tissue that lines the digestive tract, including the stomach and intestines. It is composed of a single layer of column-shaped cells that are tightly packed together. One distinguishing feature of this epithelium is the presence of dense microvilli on the apical surface of the cells. Microvilli are tiny finger-like projections that increase the surface area of the cells, facilitating absorption and secretion processes. These dense microvilli help in the absorption of nutrients and the secretion of digestive enzymes, allowing for efficient digestion and absorption of nutrients in the digestive tract. The microvilli significantly increase the surface area available for these functions, enabling more efficient nutrient absorption. Therefore, the correct answer is (d) dense microvilli.

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Answer:

d' = 0.86 mm

Explanation:

First we need to find the area of low power field:

A = πd²/4

where,

A = Area = ?

d = diameter = 1.5 mm

Therefore, using the value of diameter, we get:

A = π(1.5 mm)²/4

A = 1.767 mm²

Now, the new object occupies 1/3rd of this area:

A' = (1/3)A

πd'²/4 = (1/3)A

d'² = (4/3π) A

d'² = (4/3π)(1.767 mm²)

d' = √(0.75 mm²)

d' = 0.86 mm

Answer:

0N

Explanation:

When trying to figure out opposing forces, you have to add them together,

10 + -10 = 0,

so your answer is 0N

Answer:the answer is 0 N

Answer:

The options are

A) isochoric.

B) isothermal.

C) adiabatic.

D) isobaric.

The answer is C. Adiabatic

Adiabatic process involves zero loss or gain of heat in a system. This is usually depicted as Q= 0.

An ideal gas being compressed in a well-insulated chamber using a well-insulated piston involves the use of adiabatic process. The insulated chamber and piston helps to prevent heat loss or gain of heat. This is because insulators are poor conductors of heat and electricity.

The process of compressing an ideal gas in a well-insulated chamber using a well-insulated piston is known as adiabatic process.

When an ideal gas in compressed adiabatically, the heat lost is zero and the work is done it which causes increase its temperature.

Q = 0

The well-insulated chamber and piston helps to prevent heat loss by conduction and convection. The results in a zero heat lost to the surroundings.

Thus, we can conclude that the process of compressing an ideal gas in a well-insulated chamber using a well-insulated piston is known as adiabatic process.

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Answer:

when an x-ray passes trough matter, it undergoes a process called attenuation

Answer:

-30=5(x+1) is -7

Explanation:

distribute flip subtract 5 from both sides divide both sides by 5

Given :

Number of operations move through a pocket calculator during a full day's operation , [tex]n=1.34 \times 10^{20}[/tex] .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

[tex]e^-=-1.6\times 10^{-19}\ coulombs[/tex]

So , charge on n electron is :

[tex]C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C[/tex]

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

Answer:

9.3

Explanatin:

Answer:

4.5

Explanation:

Answer:

B) We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

C) Volume of Prism = 78 cm³

Explanation:

PART C:

Since, the volume of prism s given by the following formula:

Volume of Prism = (Area of Base of Prism)(Height of Prism)

Therefore,

Height of Prism = 6.6 cm

Area of Base of Prism = Length x Width

Area of Base of Prism = 5.6 cm x 2.1 cm

Area of Base of Prism = 11.76 cm²

Hence, the equation gives:

Volume of Prism = (11.76 cm²)(6.6 cm)

Volume of Prism = 77.616 cm³

Since, the initial values had 2 significant figures, so rounding off to two significant figures:

Volume of Prism = 78 cm²

PART B:

We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

Answer:

[tex]I=0.54\ kg-m^2[/tex]

Explanation:

Given that,

Mass of a uniform rod, m = 12 kg

Length of the rod, l = 0.3 m

The moment of inertia rotating about an axis perpendicular to the rod and passing through the center of the rod is given by :

[tex]I=\dfrac{ml^2}{2}\\\\I=\dfrac{12\times (0.3)^2}{2}\\\\I=0.54\ kg-m^2[/tex]

So, the moment of inertia of the rod is [tex]0.54\ kg-m^2[/tex]

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

So

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

The ranking of the objects according to their angular acceleration is option 4 hoop, disk, sphere.

Since

Hoop, disk, sphere contain Same mass and radius

So here

Initial angular velocity, = 0

The Force on each be F

And Time = t

Radius of each = r

Now

I1 = m r² /2

= 0.5 mr² his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere should be

I3 = (2/5) mr²

= 0.4 mr²

Now

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

here,

ωf is inversely proportional to moment of inertia.

Now

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

Therefore, the fourth option is correct.

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Answer:

The magnitude of impulse the floor applies to the ball is 3.05 kg.m/s.

Explanation:

Given;

mass of the rubber ball, m = 0.25 kg

height of drop, h₁ = 2 m

height of rebounds, h₂ = 1.8 m

Determine the initial velocity of the ball as it moves downwards;

[tex]v_i = \sqrt{2gh}\\\\ v_i = \sqrt{2*9.8*2}\\\\v_i = 6.26 \ m/s[/tex]this initial velocity is acting downwards = - 6.26 m/s

Determine the final velocity of the ball as it rebounds

[tex]v_f = \sqrt{2gh} \\\\v_f = \sqrt{2*9.8*1.8}\\\\ v_f = 5.94 \ m/s[/tex]this final velocity is acting upwards = 5.94 m/s

Impulse is given by;

J = mΔv

[tex]J = m(v_f-v_i)[/tex]

J = 0.25(5.94 - (6.26))

J = 0.25(5.94 + 6.26)

J = 3.05 kgm/s

Therefore, the magnitude of impulse the floor applies to the ball is 3.05 kg.m/s.

Answer: (b) Approximately 32 years .

Explanation:

Moves = 2n-1 .

It takes (224-1) are the minimum number of moves required to move 24 disks, which is 16777216.

Now each move takes 1 minute, therefore total time in (mintes) = 16777216 .

Now in one year we have 525600 minutes.

Therefore time in years = 16777216/525600 = 31.920121765601217656012176560122 = 32 years (approx)

Answer:

We know that the second equation of motion is

S= ut + 1/2a²

And S is displacement and u is initial velocity

So in the case of Haley lets take downwards as positive Y-axis

S = 2h and

initial velocity = v

a = g (acceleration due to gravity = 9.8)

Substituting

2h = vt + 1/2gt²

And for Joe we take ownwards as positive Y-axis

S = h and

initial velocity = 0 (since the ball is dropped from rest)

a = g

h = 0x t + 1/2gt2²

t2= √ 2h/g

Now since both balls reach ground at same time: t1=t2

So

putting value of t2 in Hayley's equation:

2h= v(√2h/g) + 1/2 g( √2h/g)²

So v= √gh/2

Complete Question

A  voltaic cell is  constructed with two [tex]Zn^{2+}[/tex][tex]- Zn[/tex] electrodes. The  two cell compartment have  [tex][Zn^{2+}] =  1.6 \ M[/tex] and  [tex][Zn^{2+}] =  2.00*10^{-2} \  M[/tex] respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is   [tex]E =  0.06 V[/tex]

Explanation:

Generally from the question we are told that

   The  concentration of [tex][Zn^{2+}][/tex] at the cathode is  [tex][Zn^{2+}]_a =  1.6 \ M[/tex]

    The  concentration of [tex][Zn^{2+}][/tex] at the anode is [tex][Zn^{2+}]_c =  2.00*10^{-2} \  M[/tex]

Generally the the cell emf for the concentration is mathematically represented as

     [tex]E =  E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}[/tex]

Generally the [tex]E^o[/tex]is the standard emf of a cell, the value is  0 V

So

      [tex]E =  0  -  \frac{0.0591}{2}  * log[\frac{ 2.00*10^{-2}}{1.6} ][/tex]

=>      [tex]E =  0.06 V[/tex]

Answer:

this occurs because the energy of the constituents is greater than the energy of the material formed and this excess is what we can appreciate in the form of ligh

Explanation:

When the light stick breaks, it allows substances to mix, produced by a chemical reaction, which releases light into the environment.

The energy released is the energy energy of the excess when the transformation takes place, this occurs because the energy of the constituents is greater than the energy of the material formed and this excess is what we can appreciate in the form of light,

Answer:

12.5 m/s

Explanation:

If the avg speed is 10 m/s we assume that the speed is constant and not fluctuating

If VT (Velocity*Time) is equal to speed at the end of the 4 seconds of accel. it is the top speed at the finish line

since the speed is 0 at the beginning of races, we will use V0= 0 m/s

So the avg velocity for those 4 seconds is (VT+V0) /2 = or 1/2 VT (for 40% of the race)

The avg velocity for the last 6 seconds is, of course, VT (for 60% of the race

hence

(1/2VT)(.4) + VT(.6) = 10 m/s

VT = 10/.8 = 12.5 m/s

Answer:

It depends on the materials of the medium in involved

Answer:

Explanation:

over a million times

Answer:

Explanation:

We shall represent all the displacement in terms of vector . We shall consider east as i , and north as j . south of west direction will be represented by - i - j .

displacement of 1.9 km due east

D₁ = 1.9 i

vector representing south of west = - i - j

unit vector = - i - j / √ 2

7.2 km south of west = 7.2 ( - i - j ) / √ 2

D₂ = - 5.09 ( i + j )

Total displacement

= D₁ + D₂

= 1.9 i  - 5.09 ( I + J )

D = - 3.19 i - 5.09 j .

magnitude of D = √ ( 3.19² + 5.09² )

= 6 km .

Direction of D

Tanθ = 5.09 / 3.19 = 1.59

θ = 58°

So direction will be 58° south of west .

To reach the starting point , he shall have to go in opposite direction .

So he shall have to go in the direction of north of east at angle 58° by a displacement of 6 km .

Answer:

243.83 Hz

Explanation:

Given the following :

Recall :

When source is stationary and observe is in motion:

Moving away from the source :

Observed frequency f₀ = f(v-v₀/v)

Moving towards the source :

f₀ = f(v+v₀/v)

Hence ;

v₀ = 12.1 m/s ; f of trumpeter = 262 Hz ; speed of sound (v) = 337m/s

f(v+v₀/v) = 262(v-v₀/v)

f = 262(v-v₀/v) / (v+v₀/v)

f = 262(v-v₀/v) * (v / v+v₀)

f = 262 (v-v₀ / v+v₀)

f = 262 ((337 - 12.1) / (337 + 12.1))

f = 262 (324.9 / 349.1)

f = 262 (0.93067888857)

f = 243.83

f = 244Hz

Answer:

213 nA

2.13 mA

851e^-t μA

Explanation:

We have a pretty straightforward question here.

Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as

V = IR, since we need I, we can write that

I = V/R

a) at V = 1 mV

I = (1 * 10^-3) / 4.7 * 10^3

I = 2.13 * 10^-7 A or 213 nA

b) at V = 10 V

I = 10 / 4.7 * 10^3

I = 0.00213 A or 2.13 mA

c) at V = 4e^-t

I = 4e^-t / 4.7 * 10^3

I = 0.000851e^-t A or 851e^-t μA