Any object which have less density than the mercury will float in it and which have higher density will sink on it. Here, gold has higher density than mercury. Thus it will sink on mercury.
What is density?Density of a substance is the measure of its mass per volume. Thus it says about how much denser the substance is in a specific volume. The ratio of density of an object to the density of water is called specific gravity.
The density of mercury is 13.4 g/ml. Any object which is less dense than mercury will float on its surface whereas, objects which have higher density than mercury will sink on it.
The density of gold is 79.3 g/ml. All other given metals iron, lead and copper have a density less than that of mercury. Hence the substance which sink on mercury is gold. Option Dis correct.
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Determine the molecular formula for a molecule with 3.61 x 10^24 atoms of Carbon per mole of the compound, if it has the following compositions: 39.6% Carbon, 7.75% Hydrogen, and the remaining from Oxygen.
I have already figured out the empirical formula: C3H7O3
The empirical formula of compound is C₃H₇O₃. The molecular formula is 1, 2, 3, tri hydroxyl propane.
What is molecular formula ?
The molecular formula is an equation that specifies how many atoms of each element there are in a single compound's molecule. It displays the precise amount of atoms present in a molecule.
Propane, for instance, has the chemical formula C4H10. The given compound has a formula of 4 carbon atoms and 10 hydrogen atoms.
The empirical formula of compound is C₃H₇O₃.
Then, ( 12 × 3 ) + ( 1 × 7 ) + ( 16 × 3 )
= 36 + 7 + 48
= 91
( 39.6 ) + ( 7.75 ) = 47.35
91 - 47.35
= 43.65
Thus, molecular formula of given compound is 1, 2, 3, tri hydroxyl propane.
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How many molecules are in 12.80 moles of strontium bydroxide?
77.094*[tex]10^{23}[/tex] molecules are in 12.80 moles of strontium bydroxide.
What does Sr OH 2's formula go by?The chemical strontium hydroxide has a molecular weight of 121.6324 g/mol and the molecular formula Sr(OH)2. It appears in the form of an anhydrate with prismatic, colorless crystals that are liquescent.
What fraction of atoms and molecules makes up NaOH?The building By counting the number of components (and their corresponding quantities) listed in the chemical formula, one can easily determine that each molecule of the compound NaOH contains three atoms.
By mole concept-
1moleof strontium bydroxide =6.023*[tex]10^{23}[/tex] molecules of strontium bydroxide.
so,
12.80 moles of strontium bydroxide =12.80*6.023*[tex]10^{23}[/tex]
No of molecule =77.094*[tex]10^{23}[/tex] molecule
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What is the strength of the final solution of a 20% solution is diluted twice 1:5, then 1:2?
The final solution has a strength of 2%.
Let the initial volume of solution = x unit^3
The solution is initially by 20%
Amount of solute = x*20/100
= x/5 unit^3
Now,
We first diluted by 1:5
1 part of initial solution is diluted with 4 parts of diluent
For 'x' unit^3 solution,
Diluent added = 4x unit^3
Total volume of solution becomes = x+4x
= 5x unit^3
Now,
We diluted by 1:2
1 part of solution is diluted with 1 part of diluent
5x unit^3 of solution is diluted with 5x unit^3 of diluent
Final solution = 5x + 5x = 10x unit^3
Final strength = (Amount of Solute/Final solution)*100%
= (x/5/10x)*100%
= x/50x*100%
= 2%
The final strength of final solution is 2%
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Aqueous copper (II) nitrate, Cu(NO3)2 reacts with aqueous potassium carbonate, K2CO3 forming solid copper (II) carbonate, Cu(CO3).
Answer:
Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)
Explanation:
I interpret your question is how to balance the above reaction, right?
Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)
Cu: 2
NO3: 2
K: 2
CO3: 2
What is the density of an object that has a mass of 6.2 g and a volume of 4.4 mL ?
Density=mass/volume
d=6.2/4.4
d=1.40 grams/cm³
15. A 100 g sample of each of the following metals is heated from 35°C to 45°C. Which metal absorbs
the greatest amount of heat energy?
Metal
4
magnesium
e. copper
copper
magnesium
mercury
silver
lead
b. lead
c. silver
Specific Heat Capacity
0.385 J/(g-°C)
1.02 J/(g-°C)
0.138 J/g °C)
0.237 J/(g-°C)
0.129 J/(g-°C)
d. mercury
Answer:
b
Explanation:
erhqjh
A chemist prepares a solution of mercury(I) chloride ( Hg2Cl2) by measuring out 0.000406 umol of mercury(I) chloride into a 200. mL volumetric flask and filling the flask to mark with water.
calculate the concentration in mmol/L of the chemist's mercury(I) chloride solution. Round your answer to 3 significant digits.
The concentration in mmol/L of the chemist's mercury(I) chloride solution. is 2.03 × 10^-8 M
We are given;
Number of moles of mercury (i) chloride as 0.000406 μmol
Volume is 200 mL
We are required to calculate the concentration of the solution.
We need to know that;
Concentration is also known as molarity is given by;
Molarity = Number of moles ÷ Volume
Number of moles = 4.06 × 10^-10 Moles
Volume = 0.02 L
Therefore;
Concentration = 4.06 × 10^-10 Moles ÷ 0.02L
= 2.03 × 10^-8 M
Thus, the molarity of the solution is 2.03× 10^-8 M.
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Calculate the mass of 45.0 L of Cl₂ at
87.0° C and 950. mm Hg.
Use the Ideal Gas Law formula and here are values for R:
8.134 (L* kPa)/(mol *K)
0.0821 (atm* L)/(mol * K)
62.364 (L * mmHg)/(mol *K)
The mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 950 mm Hg (1 mm Hg = 0.00131579 atm) = 1.25 atm
The formula used to calculate moles is as follows.
∴PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows:
∴ PV = nRT
=> 1.25 atm × 45.0 L = n × 0.0821 L atm/mol K × 360K
=> n = 1.25 atm × 45.0 L / n × 0.0821 L atm/mol K × 360K
=> n = 56.25 / 29.556 mol
=> n = 1.90 mol
Moles is the mass of a substance divided by its molar mass. So, the mass of Cl₂ (molar mass = 70.906 g/mol) is calculated as follows:
∴ Moles = mass / molar mass
=> 1.90 mol = mass / 70.906 g/mol
=> mass = 134.7214 g
Thus, we can conclude that the mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
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Answer:
Don't follow this!
Explanation:
Your chemistry teacher knows that you are cheating and using this as your own work.
-From said teacher!
An object is placed in 20 mL of water. This water rose to a level of 26 mL. The object has a mass of 18 g. What is the density of the object.
An object is placed in 20 mL of water. This water rose to a level of 26 mL. The object has a mass of 18 g. the density of the object is 3 g/mL.
given the data as follows :
mass of object = 18 g
volume of object = final volume - initial volume
volume of object = 26 mL - 20 mL
= 6 mL
the density expression is given as:
Density = mass / volume
Density = 18 g / 6 mL
Density = 3 g/mL
Thus, An object is placed in 20 mL of water. This water rose to a level of 26 mL. The object has a mass of 18 g. the density of the object is 3 g/mL
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how many signals will be expected in the 1H NMR spectrum of the following compound?
In this compound, there would be five proton NMR signals,
What is the proton NMR spectrum?We know that the acronym NMR means nuclear magnetic resonance. It has to do with the kind of spectrum in which the kind of chemical environment where the proton is found would impact the spectrum that is observed in the compound.
The first thing that we need to look at and find out in the image is to be able to find out the number of chemical environments that we have in the compound as we can see it in the image.
By studying the compound closely, we can see that there are four different proton chemical environments that we can be able to see and map out from the compound and it is these chemical environments that tell us the number of signals to expect.
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What mass of carbon dioxide is produced from the complete combustion of 6.70x10-3 g of
methane?
The full burning of 6.70x10-3 g of methane results in the production of 2.95872 mass of carbon dioxide.
Combustion is what kind of reaction?Burning is sometimes referred to as combustion. A fuel is heated and interacts with oxygen in a combustion reaction. The three elements of fuel, heat, and oxygen required for combustion are summarized by the fire triangle.
What is the purpose of combustion?Chemical processes that occur during combustion are frequently quite exothermic. The energy of chemical molecules generated during this reactive process is used by combustion systems to power vehicles, produce electricity, or heat a variety of uses.
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Have two sides that mirror each other along one plane through the central axis.
Have two sides that mirror each other along one plane through the central axis called as symmetrical
The line of centroids or central axis is defined as the line that passes through the centroids along the beam and the cross section are then defined as the beam section which are perpendicular to the central axis and that two side are mirror images of each other and place a mirror on the fold then image of one side of the picture will fall exactly on the other side of the picture and that are called as symmetrical means same
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11.How much water must be added to 15 mL of sodium chloride solution 23.4% to dilute the concentration to 0.06 mmol/mL? (MW NaCl = 58.44)
The volume of water that must be added to 15 mL of sodium chloride solution 23.4% to dilute the concentration to 0.06 mmol/mL is 999985 mL.
What is the concentration of 23.4% sodium chloride solution in mol/L?The concentration of 23.4% sodium chloride solution in mol/L is calculated as follows:
23.4% solution = 23.4 g/100 mL solution
23.4 g/100 mL = 234 g/L
Molarity = mass concentration / molar massmolar mass of NaCl = 58.5
Molarity of the NaCl solution = 234 / 58.5
Molarity = 4 mol/L
Using the dilution formula:
C₁V₁ = C₂V₂
where;
C₁ is the initial concentration = 4 mol/L or 4000 mmol/L
V₁ is the initial volume = 15 mL
C₂ is the final concentration = 0.06 mmol/L
V₂ is final volume = ?
V₂ = 4000 * 15 / 0.06
V₂ = 1000000 mL
Hence, the volume of water to be added will be:
1000000 - 15 = 999985 mL
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0.499 g of NaOH (MM = 40.00 g/mol) is dissolved in 150.00 mL of water, what is the theoretical molarity of NaOH?
Answer:
0.0833 M NaOH
Explanation:
To calculate the molarity, you need to
(1) convert grams NaOH to moles (using the molar mass)
(2) convert mL to liters
(3) calculate the molarity
It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs like the given value with the smallest amount of sig figs (0.499 = 3 sig figs).
0.499 g NaOH 1 mole
-------------------------- x ------------------ = 0.0125 moles NaOH
40.00 g
150.00 mL H₂O 1 L
--------------------------- x ------------------ = 0.15000 L H₂O
1,000 mL
Molarity = moles / volume
Molarity = 0.0125 moles NaOH / 0.15000 L H₂O
Molarity = 0.0833 M
35.0 L of an ideal gas at 268 K and 5.16 atm are heated to 343 K with a new pressure of 7.65 atm. What is the new volume (in L)?
From the calculations, the new volume of the gas is 30.2 L.
What is the new volume?We know that we can be able to obtain the parameters that ahs to do with the gas by use of any of the equations of the laws that relate to an ideal gas.
Given that the;
Initial volume [tex]V_{1}[/tex] = 35.0 L
Initial temperature [tex]T_{1}[/tex] = 268 K
Initial pressure [tex]P_{1}[/tex] = 5.16 atm
Final temperature [tex]T_{2}[/tex] = 343 K
Final pressure [tex]P_{2}[/tex] = 7.65 atm
Final volume [tex]V_{2}[/tex] = ??
Then we have to use the general gas equation;
[tex]P_{1}[/tex] [tex]V_{1}[/tex]/ [tex]T_{1}[/tex]= [tex]P_{2}[/tex] [tex]V_{2}[/tex]/ [tex]T_{2}[/tex]
[tex]V_{2}[/tex] = 5.16 * 35.0 * 343/7.65 * 268
[tex]V_{2}[/tex] = 61945.8/2050.2
[tex]V_{2}[/tex] = 30.2 L
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20 POINTS PLEASE HELP
NADP, nicotinamide adenine dinucleotide phosphate forms NADPH by combining with the H+ ion and two electrons. Thus, option C is correct.
What is NADP ?NADP, nicotinamide adenine dinucleotide phosphate is a reducing agent in electron transport chains of metabolic processes in living things. NADPH is the reduced form of NADP.
In biochemical reactions such as glycolysis, photosynthesis etc, NADP plays a significant role as a reducing agent. NADP and NADPH together are called the redox couple and they maintain cellular redox homeostasis.
Hydrogenation of molecules is called reduction and thus the NADP+ reduces to its NADPH by combining with a two electrons and H+. Hence option C is correct.
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What is the oxidation number of an element
To what volume should you dilute 35 mL of a 12 M stock HCl solution to obtain a 0.500 M
HCl solution?
Volume should you dilute 35 mL of a 12 M stock HCl solution to obtain a 0.500 M is 840 mL,
Given that :
Molarity of the solution M1 = 12 M
volume of the solution V1 = 35 mL
Molarity of the solution after the dilution M2 = 0.500 M
volume of the solution after the dilution V2 = ?
the dilution law states that :
M1 V1 = M2 V2
12 × 35 = 0.500 × V2
V2 = 840 mL
Thus, Volume should you dilute 35 mL of a 12 M stock HCl solution to obtain a 0.500 M is 840 mL.
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Outline process of preparing 0.1 M silver nitrate solution given deionized water,clean and dry volumetric flask(100ml) and silver nitrate crystals
1.6987 grams the silver nitrate crystals is weighed, 100 mL of water is measured, and the weighed silver nitrate is dissolved in the measured amount of water.
Solution preparationWe are to prepare a 0.1 M silver nitrate solution given the following:
Crystals of silver nitrateClean and dry volumetric flaskDeionized waterWeighing balanceFirst, we need to make some calculations to make the amount of silver nitrate and water that will be used.
0.1 M means 0.1 mol silver nitrate crystal in 1 L of water. However, we only have a 100 mL volumetric flask. We need to know the mol amount that will be equivalent to 100 mL of water.
0.1 mol = 1000 mL
100 mL = 100 x 0.1/1000
= 0.01 mol
Mole = mass/molar mass
Molar mass of silver nitrate = 169.87 g/mol
0.01 mol silver nitrate = 0.01 x 169.87
= 1.6987 grams
Thus, 1.6987 grams of silver nitrate would be weighed.
The following steps would be taken to prepare the solution:
Weigh out 1.6987 grams of the silver nitrate crystals.Measure out 100 mL of the deionized water using the volumetric flask.Dissolve the weighed silver nitrate into the measured waterWhat you will have is 100 mL of 0.1 M silver nitrate solution.
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Write the balanced NET ionic equation for the
reaction when AICIs and NaOH are mixed in
aqueous solution. If no reaction occurs, simply write
only NR. Be sure to include the proper phases for all
species within the reaction.
The balanced NET ionic equation is
Al(OH)3 ----> Al3+(aq) + 3OH(aq) (s)
When AICI and NaOH are combined in an aqueous solution, the following balanced NET ionic equation describes the reaction:
Al(OH)3 -----> Al3+(aq) + 3OH(aq) (s)
An exchange reaction occurs when AICI and NaOH are combined.
Al(OH)3(s) + 3NaCl(aq) -----> AlCl3(aq) + 3NaOH(aq) (1)
In this reaction, the ions Al+3 and Na+ exchange Cl- and OH- ions.
The total ionic equation must first be written in order to create the NET ionic equation:
AI(OH)3(s) + 3Na+(aq) + 3Cl(aq) + Al3+(aq) + 3Cl(aq) + 3Na+(aq) + 3OH (aq) (2)
Since the Al(OH), precipitates, we are unable to describe it as an ion because the aqueous solution does not allow for its dissociation.
The following is the net ionic equation for reaction
Al3+(aq) plus 3OH-(aq) leads to Al(OH)3(s)
The net ionic equation excludes all repeating ions from reactants and products. We eliminated the Na+ and Cl- ions from the net ionic equation because of this
The balanced net ionic equation is as follows:
Al(OH)3 ----> Al3+(aq) + 3OH(aq) (s)
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Which of the following is a true statement about cellular respiration? (4 points) a Cellular respiration occurs only in plant cells. b Cellular respiration occurs only in animal cells. c Cellular respiration occurs in both plant and animal cells. d Cellular respiration occurs in some plant cells and some animal cells.
Answer:
cellular respiration occurs both in plant and animal cells.
Explanation:
Cellular respiration definitely occurs in animals, it is how we break down glucose to get ATP. Plants first use photosynthesis to produce glucose and then need a way to produce ATP, being cellular respiration.
how without making any quantitative measurements could you determine if a piece of plastic has a density greater or less than 1 g/cm
To determine if the piece of plastic has a density greater or less than 1 g/cm³, the piece of plastic is placed in water, if it sinks, it has a greater density, but if it floats, it has a lesser density.
What is an appropriate method to determine if a piece of plastic has a density greater or less than 1 g/cm³?The density of a substance measure how compact the substance is.
For fluids such as water, objects that are denser than water will sink in water. However, if the density is less than that of water, it will float in water.
The density of water is 1 g/cm³.
Hence, objects that have densities greater than 1 g/cm³ will sink in water, whereas objects that have densities less than 1 g/cm³ will float in water.
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How is the water cycle affected when the sun comes out?
A. Rain Freezes
B. Rain becomes sweet
C. Nothing Happens
D. Rain evaporates
Answer:
option d rain evoporates
Answer:
D. Rain Evaporates
Explanation:
Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds. Clouds move over the globe and drop rain and snow.
A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 64.1°C and the pressure remains constant, what will the new volume be, in mL?
Answer:
Explanation:
I forgot
PLEASE HELP
Can someone explain the step?
Calculate the mass (in grams) needed to prepare 0.505 liters of a 0.314 M CH,;O, solution.
You do not need to enter a unit with your answer.
The concentration terms are molality, normality and mole fraction. Molarity can be used to find out the ionic strength of any solution. Therefore, the mass of CH[tex]_2[/tex]O is 4.80g.
What is molarity?Molarity can be calculated by dividing number of moles of solute by volume of solution in liter. Molarity is affected by temperature. Its unit is mole/liter. It measure the concentration of any solute in a solution.
Mathematically,
Molarity= number of moles of solute÷ Volume of solution in liter
number of moles of solute =given mass÷ Molar mass of solute
number of moles of solute =mass÷30.03 g/mol
Molarity=0.314 M
Volume of solution=0.505 liters
Substituting all the given values, we get
0.314 M= {mass÷30.03 g/mol}÷ 0.505 liters
mass÷30.03 g/mol=0.15
mass =4.80g
Therefore, the mass of CH[tex]_2[/tex]O is 4.80g.
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For the reaction N2(g) + 3H2(g) ↔ 2NH3(g), the equilibrium constant, K, = 9.83 x 10-2 at a certain temperature and pressure.
While the reaction was proceeding at this temperature and pressure the concentrations of the reactants and products were measured and found to be
[N2] = 0.910 mol/L
[H2] = 0.300 mol/L
[NH3] = 0.0081 mol/L
a. Was the reaction at equilibrium? Explain. (4 marks)
b. If the reaction was not at equilibrium, in which direction was it proceeding? Explain
The reaction is not at equilibrium and it is in the forward direction.
a.
Given,
[N₂] = 0.910 mol / L
[H₂] = 0.3 mol / L
[NH₃] = 0.0081 mol / L
K = 9.83 x 10⁻²
The balanced chemical equation for the given reaction is,
N₂(g) + 3H₂(g) ⇄ 2NH₃(g)
The formula of equilibrium constant is given by,
K = [NH₃]² / [N₂] [H₂]²
9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]
⇒9.83 x 10⁻² = (0.00006561) / (0.0819)
⇒9.83 x 10⁻² = 0.0008010989
⇒0.00983 = 0.0008010989
LHS ≠ RHS
Hence, the reaction is not at equilibrium.
b.
The reaction is in forward direction.
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If you want to distinguish between alkanes and alkenes using chemical reactions, which test: the combustion or the bromine is the better one? Explain your answer. Question 2: what you can use to wash the cloth contaminated by oil?
1) We could use the bromine water test to tell the difference between the alkane and the alkene
2) We can use a detergent to wash a cloth that is contaminated by oil.
What is an alkane?The term alkane has to do with a hydrocarbon that is composed of only a straight chain compound there are no multiple bonds in the alkane molecule and this is the difference between the alkane and the alkene. The alkene is composed of double bonds. The alkene compounds are able to decolorize bromine water while the alkanes can not.
If you have a contaminated cloth, you can be able to wash it by the use of a detergent because it is able to lift off the grease or oil by the use of the hydrophobic tail of the detergent.
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Evaluate the following summaries and choose the one that best describes metals, nonmetals, and metalloids.
A)
Metals are liquids, good conductors, and melt at low temperatures. Nonmetals are solid, poor conductors, and low in density. Metalloids are very heavy, shiny, good conductors, and have very high densities.
B)
Metals are generally very shiny, good conductors, high in density, and melt at high temperatures. Nonmetals are generally dull, poor conductors, low in density, and melt at low temperatures. Metalloids exhibit properties of both metals and nonmetals, make fair conductors, and can appear as shiny or dull.
C)
Metals are usually very shiny, high in density, and poor conductors. Nonmetals are great conductors, dull, and very dense. Metalloids are the heaviest of all elements, solid, and melt at low temperatures.
D)
Metals are usually dull, low in density, and melt at low temperatures. Nonmetals are usually very shiny, high in density, and good conductors of electricity. Metalloids are generally very shiny, solid, and melt at very high temperatures.
The correct summary of the properties is; Metals are generally very shiny, good conductors, high in density, and melt at high temperatures. Nonmetals are generally dull, poor conductors, low in density, and melt at low temperatures. Metalloids exhibit properties of both metals and nonmetals, make fair conductors, and can appear as shiny or dull.
What are the classifications of materials?Materials are of course composed of matter and mater is composed of atoms of elements. There are three main classes of the elements that we have in the periodic table. The classes of the elements are known as;
1) Metals
2) Non metals
3) Metalloids
Metals do conduct electricity while the non metals just do not conduct electricity. The metalloids would acts as conductors of electricity under certain circumstances.
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True or false
Inertia and distance combine to keep Earth in orbit around the Sun and the Moon in orbit around Earth.
The statement " Inertia and distance combine to keep Earth in orbit around the Sun and the Moon in orbit around Earth " is false.
Why Inertia and distance does not combine to keep Earth in orbit around the Sun and the Moon in orbit around Earth?According to Sir Isaac Newton, he proposed and concluded in his investigation that the earth is being kept in its orbit around the Sun and the Moon in orbit around Earth by means of gravity and inertia. This is not done through inertia and distance.
In conclusion, it can be deduced from the explanation given above that inertia and gravity combine to keep the earth in orbit around the Sun and the Moon in orbit around Earth.
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What volume of 0.180 M KOH is needed to react completely with 15.1 mL of 0.190 M H2SO4
The volume of 0.180 M KOH that would be needed to completely react with 15.1 mL of 0.190 M [tex]H_2SO_4[/tex] will be 31.88 mL
Stoichiometric problemThe equation of the reaction involving KOH and [tex]H_2SO_4[/tex] is as follows:
[tex]2KOH + H_2SO_4 --- > K_2SO_4 + 2H_2O[/tex]
The equation is already balanced and the mole ratio of KOH and [tex]H_2SO_4[/tex] is 2:1.
But 15.1 mL of 0.190 M [tex]H_2SO_4[/tex] is available.
Recall that:
mole = molarity x volume
Mole of 15.1 mL of 0.190 M [tex]H_2SO_4[/tex] = 0.190 x 15.1/1000
= 0.002869 mol
From the 2:1 mole ratio, the equivalent mol of KOH would then be:
0.002869 x 2 = 0.005738 mol
Since, mole = molarity x volume. Then, volume = mole/molarity
So, the volume of 0.005738 mol of 0.180 M KOH would be:
volume = 0.005738/0.180
= 0.03188 liters
Converting 0.03188 liters to mL:
0.03188 x 1000 = 31.88 mL
Thus, the volume of 0.180 M KOH needed to react completely with 15.1 mL of 0.190 M H2SO4 would be 31.88 mL.
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