Answer:
A slider Crank Mechanism creates linear and rotary motion
Explanation:
In the desert air, sound travels at 358 meters per second (m/s). In the polar air, sound travels at 330 meters per
second (m/s). What can you conclude from this information?
A - The speed of sound is constant.
B - Sound waves travel fastest in a vacuum.
C-The temperature of the air affects the speed of sound.
D-Sound waves travel at the same speed everywhere on Earth.
Please provide your answer below using CER
1. Claim: What is your choice for the correct answer?
2. Evidence: What evidence did you observe from the test-like question that made you decide on your answer?
3. Reasoning: Provide an elaboration on your evidence, possible prior knowledge about your claim.
Answer:
The correct option is;
C. The temperature of the air affects the speed of sound
Explanation:
The information given are;
The speed with which sound travels in the desert air = 358 m/s
The speed with which sound travels in the polar air = 330 m/s
The major difference between the desert air and the polar air is that the temperature of the desert air is hotter than the temperature of the air in the polar region. Therefore the speed of sound is affected by the air temperature.
The equation that gives the relationship of the speed of sound in air, [tex]v_{air}[/tex], to temperature is presented as follows;
[tex]v_{air} = 331\frac{m}{s} \times \sqrt{\dfrac{T_K}{273 K} } = 331\frac{m}{s} \times \sqrt{1 + \dfrac{T_{^{\circ}C}}{273 ^{\circ} C} }[/tex]
Which shows that the speed of sound in air, [tex]v_{air}[/tex], rises as the temperature of the air rises.
Where;
[tex]T_{^{\circ}C}[/tex] = The temperature of the air in degrees Celsius
[tex]T_K[/tex] = The temperature of the air in degrees Kelvin.
Polymetrics can help a person maintain cardiorespitory fitness T or F
Answer:
True
Explanation:
The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.
In space, rockets move by shooting air backwards. What moves faster the air or the ship?
Answer:
Its being pushed.
Explanation:
There is no air but its being pushed by the flames coming from the rocket.
The level of toluene (a flammable hydrocarbon) in a storage tank may fluctuate between 10 and 400 cm from the top of the tank. since it is impossible to see inside the tank, an open-end manometer with water or mercury as the manometer fluid is to be used to determine the toluene level. one leg of the manometer is attached to the tank 500 cm from the top. a nitrogen blanket at atmospheric pressure is maintained over the tank contents. felder, richard m.; rousseau, ronald w.; bullard, lisa g.. elementary principles of chemical processes, 4th edition (page 81). wiley. kindle edition.
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
When water is used the reading is [tex] R = 2281.6 \ cm [/tex]
When mercury is used the reading is [tex] R = 23.83 \ cm [/tex]
The best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
Explanation:
From the question we are told that
The length of the leg of the manometer to the top of the tank is d = 500cm
The toluene level where in the tank where the height of the manometer fluid level in the open arm is equal to the height where the manometer is connected to the tank is h =150 cm
The manometer reading is R
Generally at the point where the height of the open arm is equal to the height of the of the point connected to the tank ,
The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal
i.e [tex]P_1 = P_2[/tex]
Here [tex]P_1[/tex] is the pressure of the manometer at the point corresponding to the base of the tank and this is mathematically represented as
[tex] P_{atm} + P_1 = P_{atm} + P_t[/tex]
Here [tex]P_t[/tex] is the pressure due to the toluene level in the tank and in the arm of the manometer connected to the tank and this is mathematically represented as
[tex]P_t = \rho_t * g * h_i[/tex]
Here
[tex]\rho_t [/tex] is the density of toluene with value [tex]\rho_t = 867 kg/m^3 [/tex]
[tex]h_i[/tex] is the height of the connected arm above the point equivalent to the base of the tank , this mathematically represented as
[tex]h_i = d - h + R[/tex]
and [tex] P_2 [/tex] is the the pressure at the open arm of the manometer at the point equivalent to the base of the base of the tank and this is mathematically represented as
[tex] P_2 = \rho_f * g * h_f [/tex]
Here
[tex]\rho_f[/tex] is the density of the fluid in use , if it is water the density is
[tex]\rho_w = 1000 \ kg /m^3 [/tex]
and if it is mercury the density is
[tex]\rho_m = 13600 \ kg /m^3 [/tex]
[tex]h_f[/tex] is the height of the fluid in the open arm of the manometer from the point equivalent to the base of the tank which is equivalent the manometer reading R
So when the fluid is water we have
[tex] P_{atm} + \rho_t* g *(d - h + R) = P_{atm} + \rho_f * g * h_f[/tex]
=> [tex] \rho_t* (d - h + R) = \rho_w * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 1000 * R [/tex]
=> [tex] R = 2281.6 \ cm [/tex]
So when the fluid is mercury we have
[tex] \rho_t* (d - h + R) = \rho_m * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 13600 * R [/tex]
=> [tex] R = 23.83 \ cm [/tex]
The difference in the mercury reading for mercury due to the fact that they have different densities as we have seen in this calculation
So the best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
HELP ME PLEASE. i need to turn this in by tomorrow, also pls use the words above^ thank you i’ll mark u the brainliest.
Answer:
the corrdct answer is core
A runner is jogging in a straight line at a steady vr= 7.3 km/hr. When the runner is L= 2.1 km from the finish line, a bird begins flying straight from the runner to the finish line at vb= 29.2 km/hr (4 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to the runner After this first encounter, the bird then turns around and flies from the runner back to the finish line, turns around again and flies back to the runner. The bird repeats the back and forth trips until the runner reaches the finish line. How far does the bird travel from the beginning (including the distance traveled to the first encounter
Answer:
Explanation:
Time taken by jogger to travel the distance to finishing line = 2.1 / 7.3
= .28767 hr
Bird will keep flying for this time period
distance covered by bird = speed x time
= 29.2 x .28767 km
= 8.4 km .
Distance Versus Displacement: Which one will always be the shortest out of the 2?
Answer:
The "distance" is the answer to the question,
Explanation:
A cannonball with a mass of 50 kilograms and a golf ball with a mass of 0. 8 kilograms are dropped in a vacuum from a height of 10 meters. Compare the acceleration of each object as they fall.
It's gonna take a huge amount of time and effort, and we're gonna spend a huge amount of money, to build a vacuum chamber big enough to do this experiment.
So when we're finally ready to try it, the cannonball and golf ball will make a kind of cute experiment, but let's make it really interesting. Let's ALSO try it with a feather, an apple, a watermelon, a tennis ball, a basketball, a coffeepot, a chair, an old computer, a set of dishes, a trombone, a bicycle, a math book, a TV set, a gallon of milk, a skateboard, a shotgun, a concrete block, a car, a waterbed, a schoolbus, a battleship, your dog, and my wife !
Drop every single one of them from a height of 10 meters.
Every single one of them accelerates at 9.8 m/s² as it falls, takes 1.429 seconds to reach the floor, and hits the floor at a speed of 14 m/s. The feather, the schoolbus, and my wife stay together all the way down.
The only way this doesn't happen is if ...
-- you do this experiment in some other place that's not Earth, or
-- you throw one of the objects and you don't just drop it, or
-- the vacuum chamber has a leak and some air gets into it.
Because that's how gravity works.
a soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff What is the time of flight of the soccer ball?
The time of flight of the soccer ball is 2 seconds.
Given the following data:
Initial speed = 8 m/sDisplacement = 16 meters.To find the time of flight of the soccer ball;
Mathematically, the time of flight for a horizontal displacement is given by the formula;
[tex]Time \;of \;flight = \frac{Displacement}{Initial \; velocity}[/tex]
Substituting the values into the formula, we have;
[tex]Time \;of \;flight = \frac{16}{8}[/tex]
Time of flight = 2 seconds.
Therefore, the time of flight of the soccer ball is 2 seconds.
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Describe effect of artificial selection on the process of evolution
Answer: The process is called artificial selection because people (instead of nature) select which organisms get to reproduce.
Explanation: This is evolution through artificial selection and the characteristics to reproduce, causing the evolution of farm stock.
Using only one management style with all people is the most effective leadership technique for any organization.
Answer:
False
Explanation:
More than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.
What is Leadership technique?Leadership styles are defined as those adopted by company leaders to increase efficiency, satisfaction, growth and advancement in all positions in the organization. It requires a different style in different situations and each leader needs to know when to show a special behavior.
These strategies define every leader's personal leadership style. Some effective leadership Techniques are as follows:
Understanding the objectives clearlyGet to know the teamAlways be a learnerListen.Learn to delegate.Thus, more than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.
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Muscles covert chemicals energy int
Answer:
Mechanical energy
Explanation:
Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.
How many significant figures? 53,598 m/sec
Answer:
This has 5 significant figures.
When a light ray enters water, its velocity is _________.
Answer:
UR ANSWER IS WAVELENGTH
An object dropped from rest and falls a distance of 80 m.
What is the objects displacement
Answer:
Δx = -80m
Explanation:
The object's displacement is -80m because it landed 80m below where it started.
What affect does doubling the net force have on the acceleration of the object (when
the mass of the object stays the same)? Identify a set of two trials that support your answer to question 1
===========================================================
Explanation:
Consider a mass of 10 kg, so m = 10
Let's say we apply a net force of 20 newtons, so F = 20
The acceleration 'a' is...
F = ma
20 = 10a
20/10 = a
2 = a
a = 2
The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.
---------------
Now let's double the net force on the object
F = 20 goes to F = 40
m = 10 stays the same
F = ma
40 = 10a
10a = 40
a = 40/10
a = 4
The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.
---------------
In summary, if you double the net force applied to the object, then the acceleration doubles as well.
Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.
So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.
We don't know anything about the "trials". This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.
We also don't know anything about "question 1".
Explain and reason why the the moon rotates around the earth every lunar cycle
Pls explain ASAP
Best answer will be marked as BRAINLIEST✨
HURRY PLEASE!!
The particles of solids are packed together tightly, so sound waves travel faster through solids than through liquids or gases. How do light waves differ from sound waves?
A. Light waves require a medium and travel fastest through liquids
B. Light waves require a medium, but travel fastest through a vacuum
C. Light waves do not require a medium, but travel fastest through solids
D.
Light waves do not require a medium and travel fastest when in a vacuum
Answer:
Hope it help you
Stayhomestaysafe
Plz mark my answer brainliest✍️✍️
Explanation:
Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.
Option b
REAL NAME - SHRESTH DUBEY
what happens to the wave length and frequency of a wave as it crosses a different medium and speeds
Answer: SEE EXPLANATION!
Explanation:
When waves travel from one medium to another the frequency never changes. As waves travel into the denser medium, they slow down and wavelength decreases. Part of the wave travels faster for longer causing the wave to turn. The wave is slower but the wavelength is shorter meaning frequency remains the same.
I hope this helps you!
How long would it take to swim across a lake that is 350 meters, if you swam at 9 m/sec
Answer:
[tex]\boxed {\tt t\approx 38.89 \ s}[/tex]
Explanation:
Time can be found by dividing the distance by the speed.
[tex]t=\frac{d}{s}[/tex]
The distance is 350 meters.
The speed is 9 meters per second.
[tex]d= 350 \ m \\s= 9 \ m/s[/tex]
Substitute the values into the formula.
[tex]t=\frac{350 \ m}{9 \ m/s}[/tex]
Divide. Note that the meters or "m" will cancel each other out and the seconds or "s" will move to the numerator.
[tex]t=\frac{350 }{9 \ s}[/tex]
[tex]t=\frac{350 \ s}{9}[/tex]
[tex]t=38.8888889 \ s[/tex]
Round to the nearest hundredth. The 8 in the thousandth place tells us to round the 8 to a 9.
[tex]t \approx38.89 \ s[/tex]
It will take about 38.89 seconds to swim 350 meters at 9 meters per second.
MathPhys Pls PLS PLS PLS HELP ME!!!!
Which of these statements describes the relationship between mass and weight?
(1 Point)
Mass is always greater than weight.
Mass of an object changes based on location, weight stays constant.
Mass of an object is constant, weight changes based on location.
Mass and weight are the same measurement.
Answer:
Usually, the relationship between mass and weight on Earth is highly proportional; objects that are a hundred times more massive than a one-liter bottle of soda almost always weigh a hundred times more—approximately 1,000 newtons, which is the weight one would expect on Earth from an object with a mass slightly greater ...
what happens all by itself because the nucleus is unstable
The data table shows how the amplitude of a mechanical wave varies with
the energy it carries. Analyze the data to identify the mathematical
relationship between amplitude and energy. Use your equation to find the
energy if the amplitude is 6 units.
Amplitude
Energy
1 unit
2 units
2 units
8 units
3 units
18 units
4 units
32 units
Answer:
162
Explanation:
When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units. Therefore, option C is correct.
What do you mean by an amplitude ?The term amplitude is defined as the maximum distance moved by a point on a vibrating body or wave calculated from its equilibrium position.
We have given,
first amplitude, A = 1, corresponding energy = 2
second amplitude, A = 2, corresponding energy = 8
The energy of a string at a given amplitude is calculated as follows;
E ∝ A²
Energy varies as the square of the change in amplitude.
If amplitude of one has energy of two
Amplitude of 2 (double of 1)
= ( 2 x 2 ) = 4 x 2
= 8 4 times the energy at amplitude of 1.
Then for 8 units of amplitude change
8 x 8 = 64 x 2
= 128
Thus, When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units, option C is correct.
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Your question is incomplete, most probably your question was
The data table shows how the amplitude of a mechanical wave varies with the energy it carries. Analyze the data to identify the mathematical relationship between amplitude and energy. Use your equation to find the energy if the amplitude is 8 units.
Amplitude
1
2
3
4
energy
2
8
18
32
A.66 units
B. 108 units
C. 128 units
D. 88 units
A car moved 40 km north and 90 km south. What is the displacement of the car?
A. 50 km south
B. 50 km north
C. 10 km east
Answer:
A. 50 km south
Explanation:
hope this helps!
how many apples are in 29 trees if each tree has 45 apples?
Answer:
1305 I think but not sure
Given 1 inch ≡ 2.54 cm and 1 foot ≡
12 inches, how many square centimeters are
in 3.22 ft2
?
Answer:
2991.47 [cm^2]
Explanation:
To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:
[tex]3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}][/tex]
Acceleration is the rate of change in the speed of an object. To determine the rate of acceleration, you use the formula below. The units for acceleration are meters per second per second or m/s2.
Explanation:
Acceleration is the rate of change in the speed of an object. If initial and final speed are v₁ and v₂. It changes speed in time t. Its formula is given by :
[tex]a=\dfrac{v_2-v_1}{t}[/tex]
The problem is "A skater increases her velocity from 2.0 m/s to 10.0 m/s in 3.0 seconds. What is the skater’s acceleration? "
In this problem,
v₁ = 2 , v₂ = 10 m/s and t = 3 s
Acceleration of the object,
[tex]a=\dfrac{10-2}{3}\\\\a=2.67\ m/s^2[/tex]
So, the acceleration of the skater is [tex]2.67\ m/s^2[/tex].
what caused earths continents to drift apart?
Answer:
bada bop boop pow
Explanation:
a student pushes a book with a force of 5 N to the east.which statement
describes the reaction force?
Answer:
5N westward, acting on the student
Explanation:
Answer: 5N westward, acting on the student
Explanation:
A book with a mass of 1kg is dropped from a height of 3m . What is the potential energy of th book when it reaches the floor?
Answer:
30 J
Explanation:
height = 3 m
mass = 1kg
acceleration due to gravity = 10m/s²
Potential Energy = mass× gravity × height
= 1kg ×10m/s²× 3m
= 30 J