What happens when contact angle is 90?

Answers

Answer 1

The magnitude of the torque will increase as the angle between the force and the line of action of the torque approaches 90 degrees.

Torque, a unit of rotational force exerted on an object, is calculated by multiplying the force by the distance from the axis of rotation to the point of application of the force. The sine of the angle formed between the force and the torque's line of action and the torque are also proportional.

The torque is zero when there is a 0 degree angle between the force and the torque's line of action because the force is acting in the same direction as the torque's line of action.

As the angle increases, the torque increases and reaches its maximum value when the angle is 90 degrees, at this point the sine of the angle is 1, so the torque is at its maximum value.

The given question is incomplete. The complete question is 'What happens to torque when the contact angle is 90°?'

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Related Questions

when are eclipse seasons? group of answer choices when the nodes of the moon's orbit are nearly aligned with the sun when earth and the sun are aligned with one another in the summer and winter during an eclipse in the spring and fall

Answers

Eclipse seasons occur when the nodes of the Moon's orbit are nearly aligned with the Sun. This alignment is known as a syzygy.

What is eclipse season?

During a syzygy, there can be a solar eclipse (when the Moon blocks the Sun's light from reaching Earth) or a lunar eclipse (when the Earth blocks the Sun's light from reaching the Moon).Eclipse seasons happen twice a year, approximately six months apart. During each eclipse season, there is typically at least one solar eclipse and one lunar eclipse.Eclipse seasons happen twice a year, approximately six months apart.During each eclipse season, there is typically at least one solar eclipse and one lunar eclipse.Eclipse seasons occur when the nodes of the Moon's orbit are nearly aligned with the Sun, known as a syzygy.During a syzygy, there can be a solar eclipse (when the Moon blocks the Sun's light from reaching Earth) or a lunar eclipse (when the Earth blocks the Sun's light from reaching the Moon).

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the rear window in a car is approximately a rectangle, 2.4 m wide and 0.70 m high. the inside rearview mirror is 0.60 m from the driver's eyes, and 2.10 m from the rear window. part a what is the minimum length for the rearview mirror if the driver is to be able to see the entire width and height of the rear window in the mirror without moving her head?

Answers

The minimum length for the rearview mirror is 3.2 m.

To determine this, we need to use the Pythagorean Theorem. First, we need to calculate the hypotenuse, or the distance from the driver's eyes to the bottom corner of the rear window. To do this, we need to find the sum of the two known distances, 0.60 m and 2.10 m, which equals 2.70 m.

0.60 m +  2.10 m = 2.70 m.

Next, we need to calculate the length of the side opposite the known angle. To do this, we will use the side opposite angle formula for the Pythagorean Theorem, which is

a^2 + b^2 = c^2.

In this case, a is 2.4 m, b is 0.70 m and c is 2.70 m.

We can then solve for a, which results in

a = sqrt(c^2 - b^2)

a = 3.2 m.

Therefore, the minimum length for the rearview mirror is 3.2 m.

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5.0 kg particle with a velocity of 3.0 m/s collides with a 10 kg particle that has a velocity of 2.0 m/s in the same direction. after the collision, the 10 kg particle is observed to be traveling in the original direction with a speed of 4.0 m/s. (a) calculate the velocity of the 5.0 kg particle immediately after the collision. (b) by how much does the total kinetic energy of the system of two particles change because of the collision? (c) how might you account for your answer in b)?

Answers

The velocity of the 5kg particle immediately after collision is -1m/s, the total kinetic energy of the system of the two particles change by -40 joules and the additional kinetic energy can be gained by using some external material.

Kinetic energy is the energy stored in the object by virtue of its motion and its unit is Joule. Momentum is defined as the product of mass and velocity of the particle. To calculate the velocity of the particle after collision, we first equate the values in the formula of conservation of momentum which is given as:

[tex]m1v1 + m2v2 = M1V1 +M2V2[/tex] ...(1)

m1, v1 = mass and velocity of object of mass 5kg (before collision)

m2, v2 = mass and velocity of object of mass 10kg (before collision)

M1, V1 = mass and velocity of object of mass 5kg (after collision)

M2, V2 = mass and velocity of object of mass 10kg (after collision)

Putting values in equation 1, we get:

5(3) + 10(2) = 5(V1) + 10(4)

5V1 = -5, ∴ V1 = -1 m/s

To calculate change in kinetic energy, we equate as follows:

[tex]Ki - Kf = 1/2(m1v1^2) + 1/2(m2v2^2) - 1/2(M1V1^2) - 1/2(M2V2^2)[/tex] ...(2)

Putting values in equation (2), we get:

Ki -Kf =  1/2(5×3^2) + 1/2(10×2^2)  1/2(5×1^2) + 1/2(10×4^2)

Change in K.E. = -40Joules

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What is the direction of the acceleration from t = 10 s to t = 15 s? Please identify your E, R, and C as such.

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The direction of the acceleration from t = 10 s to t = 15 s is opposite to the direction of velocity.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Both effects contribute to the acceleration for all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction.

As velocity linearly decreases, the direction of the acceleration from t = 10 s to t = 15 s is opposite to the direction of velocity.

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A 7 kg bicycle moving at 11 m/s strikes a stationary 2000 kg car. The bicycle bounces backwards at 3 m/s. What is the velocity of the car after impact?

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A 7 kg bicycle moving at 11 m/s strikes a stationary 2000 kg car, the velocity of the car after impact is 0.03m/s.

What kinds of collisions are there?

Collisions can occur in two ways: Momentum is conserved during inelastic collisions, while momentum and kinetic energy are both preserved during elastic collisions.

In a collision, two forces with opposite directions and equal magnitudes act on each object, accelerating them simultaneously. Each object experiences the same acceleration in collisions between objects of equal mass.

Momentum before collision = momentum after collision

MbVb = (Mb+Mc)V

7×11 = (7+2000)×V

77 = 2007×V

V = 77/2007

V = 0.03m/s.

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the sun, moon, and stars choose one or more: a. appear to move each day because earth rotates. b. rise north or south of east and set north or south of west, depending on their location on the celestial sphere. c. appear in the same location in the sky everywhere on earth because earth is in the center of the celestial sphere. d. change their relative positions over time.

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The correct statement about the sun, moon, and stars are the option A, B, and D. Those are: (a) appear to move each day because the Earth rotates, (b) rise north or south of east and set north or south of west, depending on their location on the celestial sphere, and (d) change their relative positions over time

What are the effects of the Earth's rotation?

The rotation of Earth within its own axis, and also changes in the orientation of the rotation axis in space. One rotation of the Earth is in 24 hours. This condition affect the Sun and the Moon, as follow:

- As the Earth rotates from west to east, the Sun appears to rise in the east and set in the west. (option b is correct)

- Just one part of the Earth that faces the Sun is alight and thus experiences day; the part of the Earth that does not face the Sun experiences night.

→ So, the Sun, Moon, and Stars seem to change their relative positions over time (option d is correct) and appear to move each day because the Earth rotates (option a is correct)

→  Therefore, the Sun, Moon, and Stars are not appear in the same location in the sky (option c is incorrect)

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While someone is skateboarding, the wheels of the skateboard are in contact with the ground. The skateboarder _[blank 1]_ on the ground to move the skateboard forward, but if the skateboarder doesn’t, _[blank 2]_ causes the skateboard to slow down and eventually stop

Answers

The skateboard's wheels make contact with the ground while someone is skating. To advance the skateboard, the skateboarder applies force to the ground. The propelling force is what's known as this force.

What will happen if a skateboard hits the ground?If the skateboarder doesn't use this propelling power, the skateboard will eventually slow down and stop due to friction between the wheels and the surface. The force that prevents movement between two in contact surfaces is known as friction.The force of friction depends on the nature of the surfaces in contact and the normal force that presses them together.Friction between the wheels and the ground acts in the opposite direction to the motion of the skateboard.As the Skateboarder coasts, the friction force between the wheels and the ground will cause the wheels to slow down, which in turn causes the entire skateboard to slow down.Eventually, the friction force will become so great that the wheels will stop moving, and the Skateboard will come to a stop.To keep the skateboard moving, the Skateboarder must continuously apply a propulsion force to overcome the friction force.

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Answer:blank 1 pushes, blank 2 friction

Explanation:

two positive point charges having equal charge values are surrounded by water and the distance between them is 0.642 m. if the magnitude of the total electric force on one of them is 342 n, what must be the charge of one of these particles in coulombs?

Answers

The charge of both  of these particles is 14 µC.

The electric force between two point charges is given by Coulomb's Law, which states that the force (F) between two point charges is proportional to the product of the charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. The proportionality constant is the Coulomb's constant (k). F = kq1q2/r^2.

When two charges are surrounded by water, the water molecules exert a force on the charges due to their polar nature. This force is called dielectric constant. The dielectric constant of water is around 80, which means that it can reduce the electric field strength by 80 times, making it weaker than it would be in a vacuum.

So, when considering the dielectric effect of water, the force on one of the charges would be 342 N / 80 = 4.28 N. This means that the charge would be 4.28 N * (0.642 m)^2 / k = 14 µC .

The dielectric constant of water can have a significant effect on the force between charges and should be considered when calculating the electric field strength or charge values in an aqueous solution.

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a 2.2 kg object is whirled in a vertical circle whose radius is 1.0 m. if the time of one revolution is 0.97 s, what is the tension in the string (assume uniform speed)

Answers

The tension in the string at the top is calculated to be 71 N and at the bottom of the string is calculated to be 1.1 × 10⁻² N.

F cent = F g + F t

where, F cent is centripetal force

F g is the gravitational force

The tension force is denoted by F t

F t = F cent - F g = (4π² R m)/T² - m g

where,

R is the radius

m is the mass

T is the time taken for one revolution

g is the acceleration due to gravity

On substituting the values,

F t = (4 × 3.14²×1)/0.97² - 2.2× 9.8 = 70.7259 N ≈ 71 N

At the bottom of the string is,

F cent = -F g + F t

F t = F cent + F g = (4 π² R m)/T² + m g = (4 × 3.14²×1)/0.97² + (2.2× 9.8) =  113.8899 N = 1.1 × 10⁻² N

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What is the formula to find cross product of two vectors?

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If there are two product A and B then the formula for cross product is,  A × B = ABsinθ.

The direction of the cross product of the two vector will always be perpendicular to the plane projected by other two vectors. If there are two product such that,

A = a₁i + a₂j + a₃k

B = b₁i + b₂j + b₃k

Then the magnitude of their cross product(C) can also be determined by the matrix method, and this will be, C = (a₂b₃-a₃b₂)i - (a₁b₃-a₃b₁)j + (a₁b₂-a₂b₁)k

It must be noted that A × B ≠ B ×A.

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when a capacitor that operates at 1,000 volts or less is removed from an energized circuit, the charge on the capacitor shall be drained to ? .

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When a capacitor operating at 1,000 volt is removed from a circuit, the charge on the capacitor should be drained to a safe voltage level of 0 volts.

A capacitor stores electrical energy in an electric field between two conductive plates. When a capacitor that operates at 1,000 volts or less is removed from an energized circuit, it should be discharged to a safe voltage level, typically 0 volts.

The discharging is done to prevent electrical shock as well as damage to the capacitor or equipment. Discharging the capacitor can be done by connecting a resistor across its terminals for a certain period of time or by using a specialized tool called a capacitor discharge tool. It's important to follow proper safety procedures when working with capacitors and high voltage circuits.

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The charge q4 is now replaced by charge q5 which has the same magnitude, but opposite sign from q4 (i. E. , q5 = 0. 1 μC). What is the new value for the potential energy of the system?

Answers

The new value for the potential energy of the system is U = 2.54J. Potential energy is the power that an item may store due to its position in relation to other things, internal tensions or other circumstances.

(4): As a result, q; = 1.2 uC

Assume that 91 = 1.5 UC and q = 2 JC. Then, a = 1.4 cm and d2 = 2 cm and 0.02 m, respectively.

U = k - 9143 9195 9345 Va' + d 2a (1.5x10-)(2x10*) (1.5x10-)(1.2x10-) (2x10-) (1.2x10-#) is the system's potential energy.

U=(9x109) \s(0.014) +(0.02) \sV(0.014) +(0.02) (0.02)

2 x0.014 \s,  U = 2.54 J

This represents the system's potential energy's new value.The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of common forms of potential energy. The joule, denoted by the letter J, is the energy unit in the International System of Units (SI).

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chapter 5 - problem 26. two charges lie along the x-axis. is it true that the net electric field always vanishes at some point (other than infinity) along the x-axis?

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Two charges line up along the x-axis. the net electric field is always zero at some point along the x-axis. The above statement is incorrect

No, not necessarily. If two charges have the same magnitude but opposite signs, there is no point at which the net electric field vanishes (the equilibrium point). If the two charges have opposite signs, the equilibrium point (if any) is not between the charges, but closer to the lesser charge. Along the line connecting the charges, there is a point at which the electric field is zero on the "far" side of the positive charge (away from the negative charge). In general, for charges of opposite signs, the zero point of the magnetic field is "outside" the smaller charge.

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which types of electromagnetic radiation might a doctor use to treat patients?

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High-energy particles or waves, such as x-rays, gamma rays, electron beams, or protons, are used in radiation therapy to kill or harm cancer cells.

The three main EMF applications in medicine are magnetic resonance imaging (MRI), radiofrequency ablation (RFA), which is used in cardiology and tumor therapy, and localized dielectric heating (short wave diathermy), which is used in physiotherapy.

The features inside that area of the body, such as bones, tissues, and organs, are visible on a digital image or film as a result of medical imaging treatments that transmit x-ray beams, a type of ionizing radiation, to that area.

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Elvira throws a meatball at the wall. When the meatball hits the wall, it makes a sound. The kinetic energy of the meatball is transferred into the surroundings through what?.

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Through sound waves, the meatball's kinetic energy is dissipated into the environment.

Are sound waves a type of wave?

Lengthwise waves are what sound waves are. Any given medium will experience compressions and rarefactions as longitudinal waves pass through it. When particles move closely together during compression, high pressure zones are created.

A vibrating object or medium causes its constituent particles to begin to move. Sound waves are the name given to this particle movement. This kind of mechanical wave exists.

The meatball's kinetic energy causes vibrations in the wall and the surrounding air when it strikes the wall. The kinetic energy is converted to sound energy through these vibrations until the energy runs out.

As a result, sound waves dissipate the meatball's kinetic energy into the environment.

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Microwaves are very efficient at heating water

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Microwaves are very efficient at heating water the reason is The microwave's heat waves are focused on the liquid (or food), not on heating the air or container around it.

How can water be heated most effectively?

Due to their high efficiencies and significant cost savings, heat pump water heaters transfer heat from one location to another instead of producing heat directly to supply hot water. Solar water heaters provide hot water by utilising the sun's heat while also reducing energy costs.

However, a microwave would typically be a little more effective at heating water than a gas stove's flame and should consume a little less energy. The cause is that the heat waves from the microwave are directed at the liquid (or food), not at the air or container it is in.

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A man standing in front of a vertical cliff fires a gun. He hears the echo after 3 seconds. On moving closed to the cliff by 82 m he fires again. This time he hears the evho after 2.5 seconds. Calculate the distance of the cliff from the initial position of the man and the velocity of sound

Answers

The distance of the cliff from the initial position of the man is 492 m and the velocity of the sound waves is 328m/s.

What is Velocity of sound?

The velocity of sound through a given material is the distance which the sound energy will propagate in that particular material in a given time period, and it is a function of material density, acoustic impedance, and temperature of material.

Let the distance of the cliff from the initial position of the man be d m.

So, the distance traveled by sound in 3 sec = 2d m

So, speed of sound, S = Time/ Distance

​S = 2d/ 3 .....(i)

On moving closer to the cliff by a distance of 82 m, the distance = 2(d - 82) m

So,

S = d/ t

S = 2(d−82.5)/ 2.5

S = 2d−2×82.5/ 2.5 .....(ii)

Therefore form equation (i) and (ii) we get,

2d/ 3 = 2d - 2 × 82/ 2.5

5d = 6d - 492

d = 492m

Thus, it is the distance of the cliff from the initial position of the man.

Now, S = 2 × 492/ 3

S = 328 m/s

Therefore, the velocity of sound is 328m/s.

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Consider two points in an electric field. The potential at point 1, V1, is 23 V. The potential at point 2, V2, is 185 V. An electron at rest at point 1 is accelerated by the electric field to point 2. A. Write an equation for the change of electric potential energy ΔU of the electron. B. Find the numerical value of the change of the electric potential energy in electron volts (eV). C. Express v2, the speed of the electron at point 2. In terms of ΔU, and the mass of the electron me. D. Find the numerical value of v2 in m/s

Answers

The electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

U1 = kqQ / r

Where U1 is the change in electrical potential energy and k is a constant,

• Charge = Q

• r = separation from the charge point

V = kQ / r, therefore U1 = V1 q.

U₁ = 23q

U2 = V2q is the electrical potential energy at position P2.

U2 = 185 x q

The following equation represents the change in electric potential energy:

ΔU = U₂- U1

(b)

Solving the equation, we have:

ΔU = 185 - 23

ΔU = 162 eV

Since the charge in the change in potential difference is positive, the work produced by the electric force when the proton is in motion is negative.

i.e.

ΔUE = q(162)

ΔUE (-e) (162) V

ΔUE = -162 eV

where;

• ΔUE denotes the work done by the electric force.

Recall that:

• 1 electron volt = 1.66 x 10-19 Joules

ΔUE = -162 x 1.66 x 10-19 J

ΔUE = -2.68 x 10-17 J

This leads us to the conclusion that the electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

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assuming a typical efficiency for energy use by the body, if a 75 kg person were to use the energy in this candy bar to climb stairs, how high could she go?

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The person can go high up to 685.71 m. The principle of energy conservation is applied in this question. First , use the term of efficiency to estimate the available energy. Finally, use energy conservation to calculate the person's height.

What is potential energy?

The following formula can be used to calculate an object's potential energy.

            PE = mgh

Here, m denotes mass, g denotes gravitational acceleration, and h denotes body height.

Step 1:

The average efficiency of energy utilised by the body is 25%. As a result, climbing the stairs consumes 25% of the person's entire energy. The following formula is used to determine available energy:

           E' = E(25/100)

In the above equation, replace E with 480 Cal.

           E' = (480 Cal) (25/100) ((4.2 * 10^3 J)/1 Cal)

               = 504 * 10^3 J

Step 2:

The body's initial energy is the energy needed to execute the task. The following is the initial energy:

            TE = E'

Substitute 504 * 10^3 J in the above equation.

            TE = 504 * 10^3 J

The available energy is used to complete the task of climbing the steps. As a result, the starting energy equals the end energy.

Replace mgh with TE in the above expression and find the height h.

           mgh = 504 * 10^3 J

            h = (504 * 10^3 J)/mg

Substitute 75 kg for m and 9.8 m/s^2 for g in the above expression.

            h = (504 * 10^3 J)/(75 kg)*(9.8m/s^2)

               = 685.71 m.

Thus, the height covered by the person is 685.71 m.

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Name the unit of energy used to express energy of atomic and subatomic particles.​

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An atomic mass unit (amu) is one-twelfth of the mass of an unbound carbon-12 atom, and it is used to express the mass of atomic and subatomic particles.

What is unit of atomic energy?The joule is the International System of Units' unit of energy. Understanding the relationship between the binding energy and the mass defect in Albert Einstein's Theory of Relativity equation clarifies the conversion of amu to joules. The mass defect in the equation refers to the "vanishing" mass of protons and neutrons that is converted to energy and used to hold the nucleus together.The electronvolt is a unit of energy used in atomic physics, particle physics, and high energy physics (eV). One eV equals 1.60217663410^-19 J.

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1) You suddenly find yourself in a zombie apocalypse and there is, of all things, a zombie cafeteria
lady chasing you! Thinking quickly, you run in a zig zag pattern. Explain how your knowledge of
Newton's Law of Inertia may just save your life!

Answers

Ummm well if I just yk get something and turn around and hit it that will knock it down then just hit it’s head a few times it’ll die

Any vector can be written as a unit vector multiplied by the magnitude of the vector (a positive scalar). Write each of the following vectors as the magnitude of the vector times the appropriate unit vector. Input the magnitude to the left (in the parenthesis) and the unit vector to the right.

Answers

The following vectors are calculated by multiplying the vector's magnitude by the relevant unit vector:

The vector [tex]$\vec{A}$[/tex] would be [tex]$- < \mathbf{0 . 7 0 8}, \mathbf{0}, \mathbf{- 0 . 7 0 8} > * 4.66 * 10^{-3}$[/tex]

The vector, [tex]$\vec{B}=\left\langle 0,-1,0 > ^* 676\right.$[/tex]

The vector, [tex]\vec{C}=\left\langle 0.707,0,-0.707 > * 4.47 * 10^2\right.[/tex]

As per the data provided in the above question are a bellow,

The basic vector looks like this:

[tex]$$\vec{A}=(\mathrm{a}, \mathrm{b}, \mathrm{c}) \ldots . .1$$[/tex]

the magnitude [tex]$|\vec{A}|$[/tex] can be obtained as :

[tex]$$|\vec{A}|=\sqrt{a^2+b^2+c^2} \ldots . .2$$[/tex]

This could be the unit vector:

[tex]$$\hat{u}_A=\frac{\vec{A}}{|\vec{A}|_{\ldots \ldots .3}}$$[/tex]

a) (0.00330, 0 , -0.00330)

Thus,

=(0.00330, 0 , -0.00330)

Using equation two to calculate this magnitude:

[tex]$$|\vec{A}|=\sqrt{0.00330^2+0^2+(-0.00330)^2}=4.66 * 10^{-3}$$[/tex]

This could be the unit vector:

[tex]\hat{u}_A & =\frac{\vec{A}}{|\vec{A}|} \\\hat{u}_A & =\left\langle\frac{0.00330}{4.66 * 10^{-3}}, \frac{0}{4.66 * 10^{-3}}, \frac{-0.00330}{4.66 * 10^{-3}} > \right. \\\hat{u}_A & = < 708,0,-708 >[/tex]

Thus, the vector [tex]$\vec{A}$[/tex] would be [tex]$- < \mathbf{0 . 7 0 8}, \mathbf{0}, \mathbf{- 0 . 7 0 8} > * 4.66 * 10^{-3}$[/tex]

B)(0 , -676, 0)

Solving similar problems to A),

The vector,

[tex]$|\vec{B}|=\sqrt{0^2+-676^2+0^2}=676$[/tex]

This could be the unit vector:

[tex]& \hat{u}_B=\frac{\vec{B}}{|\vec{B}|} \\& \hat{u}_B=\left\langle\frac{0}{676}, \frac{-676}{676}, \frac{0}{676}\right\rangle[/tex]

And the vector,

[tex]$\vec{B}=\left\langle 0,-1,0 > ^* 676\right.$[/tex]

C) (0.00316 , 0 , -0.00316)

When we attempt the third vector, we will obtain magnitude:

[tex]$$|\vec{C}|=\sqrt{0.00316^2+0^2+(-0.00316)^2}=* 4.47 * 10^{-3}$$[/tex]

Then,

[tex]& \hat{u}_C=\frac{\vec{C}}{|\vec{C}|} \\& \hat{u}_C=\left\langle\frac{0.00316}{4.47 * 10^2}, \frac{0}{4.47 * 10^2}, \frac{0.00316}{4.47 * 10^2}\right\rangle[/tex]

And the vector,

[tex]\vec{C}=\left\langle 0.707,0,-0.707 > * 4.47 * 10^2\right.[/tex]

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a rubber ball with a mass of 0.5 kg and a speed of 9.0 m/s collides perpendicularly with a wall and bounces off with a speed of 11 m/s in the opposite direction. what is the magnitude of the impulse acting on the rubber ball?

Answers

The magnitude of the impulse acting on the rubber ball is 1.5 kg m/s.

What is magnitude?

Magnitude is a measure of the size of a physical quantity, usually expressed as a numerical value and often used to compare the relative sizes of different objects or phenomena. It is typically used to measure the intensity, size, or strength of something. Magnitude is a concept applicable to many different physical quantities, such as light, sound, energy, speed, and force.

This is calculated by taking the difference between the initial and final momentum of the ball, which is (0.5 kg × 11 m/s) - (0.5 kg × 9.0 m/s) = 1.5 kg m/s.

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I have two charges of +4 x 10-5 C. If they are 0. 5 m apart, what is the electric force between them?

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Coulomb's law, states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, can be used to compute the electric force.

The equation is: F = k * (q1 * q2) / r^2

where F is the electric force, k is Coulomb's constant (9 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between them. So, in this case, the electric force between the two charges of +4 x 10^-5 C would be:

F = (9 x 10^9 N * m^2 / C^2) * ((+4 x 10^-5 C) * (+4 x 10^-5 C)) / (0.5 m)^2

F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.5 m)^2

F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.25 m^2)

F = 36 x 10^9 N. So the force between the two charges is 36 x 10^9 N.

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Select the ways in which you can induce current in a wire. Multiple answers are correct. Select all that apply.

A. Move the wire through a magnetic field.

B. Connect the wire to a voltage source.

C. Coiling the wire around a permanent magnet.

D. Leave the wire out in the sun.

Answers

Answer:

С.Coiling the wire around a permanent magnet.

Which term is most applicable to a discussion of angular momentum in the context of black holes?.

Answers

"The most applicable term to a discussion of angular momentum in the context of black holes is Spin."

Angular Momentum is defined as the property of any rotating object which is given by the product of the moment of inertia of an object and the angular velocity of the rotating object. Angular momentum is a vector quantity and it has both the magnitude and direction. The Earth's rotation and revolution are two instances of angular momentum.

When astronomers claim to have calculated a black hole's spin, they actually mean to have calculated its angular momentum. This is the total angular momentum of all the materials on the Universe that ever crossed the event horizon and got trapped inside it.

The given question is incomplete. The complete question contains options. they are 'A: Photon B: Curvature C: Spin D: Time'

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suppose an object starts out electrically neutral. through some process, 11 electrons are removed from the object. what is the electric charge of the object afterward?

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If 11 electrons are removed from the electrically neutral object, the electric charge of the object afterwards has the same net charge as the 11 protons.

Given that,

11 electrons are removed from the electrically neutral object

By taking out one or more electrons, neutral atoms can be transformed into positively charged ions. For instance, a neutral sodium atom has 11 protons and 11 electrons. This atom's electron is removed, resulting in a positively charged Na+ ion with a net charge of +1.

An electrically neutral object contains the same number of protons and electrons. As a result, if 11 electrons are taken out of the object, there will be 11 more protons than there are electrons.

Thus, the object has the same net charge as 11 protons.

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An enclosed gas has a volume of 1.64L at 1.22atm pressure and a temperature of 50°C . A fellow classmate calculates that the volume of the gas at 2.44atm and a temperature of 100°C remains the same because the pressure and temperature are both doubled, which have opposing effects on the volume. Evaluate your classmate's response. Are they correct? If not, calculate the correct volume of the gas at 2.44atm and 100°C.

Answers

They are not correct. The correct volume of the gas at 2.44 atm and 100 °C is 0.95 L

How do I determine the correct volume of the gas?

To know if your classmates are correct or not, we shall determine volume.

We can calculate the volume of the gas by using the combined gas equation as shown below:

Initial volume (V₁) = 1.64 LInitial pressure (P₁) = 1.22 atmInitial temperature (T₁) = 50 °C = 50 + 273 = 323 KNew pressure (P₂) = 2.44 atm New temperature (T₂) = 100 °C = 100 + 273 = 373 KNew volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

(1.22 × 1.64) / 323 = (2.44 × V₂) / 373

Cross multiply

323 × 2.44 × V₂ = 1.22 × 1.64 × 373

Divide both side by (323 × 2.44)

V₂ = (1.22 × 1.64 × 373) / (323 × 2.44)

V₂ = 0.95 L

We can see from the above calculation that the volume of gas at 2.44 atm and 100 °C is 0.95 L.

Thus, your classmates are not correct.

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how do modern scientists measure and calculate the speed at which the continents are moving

Answers

In todays modern word modern scientists measure and calculate the speed at which the continents are moving using the Global Positioning System (GPS).

What do you mean by the term  Global Positioning System (GPS)?A satellite-based radio navigation system which is owned by the US government and run by the US Space Force is termed as the Global Positioning System, or Navstar GPS.It Has the following specifications:Satellites in orbit: 32 (31 operational)Coverage: GlobalCost: $12 billion; (initial constellation); $750 million per year; (operating cost)Total satellites: 24First launch: February 22, 1978; 44 years agoOperator(s): US Space ForceOrbital height: 20,180 km (12,540 mi)

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Water is being sprayed from a nozzle at the end of a garden hose of diameter 2. 5 cm. If the nozzle has an opening of diameter 1. 0 cm, and if the water leaves the nozzle at a speed of 14 m/s, what is the speed of the water inside the hose?.

Answers

The speed of the water inside a garden hose is 12.6 m.

If the nozzle has an opening of diameter 1.0 cm and the water is leaving the nozzle at a speed of 14 m/s, then the speed of the water inside the hose can be calculated.

To find the speed of the water inside the hose, the Bernoulli equation can be used. The Bernoulli equation states that for an ideal, inviscid flow:

P1/ρ + (V1^2)/2 + gz1 = P2/ρ + (V2^2)/2 + gz2

The speed of the water inside the hose is Where P1 and P2 are the pressures at 1 and 2, V1 and V2 are the velocities at 1 and 2, g is the acceleration due to gravity, and z1 and z2 are the heights at 1 and 2.

The pressure inside the hose will remain constant, so the Bernoulli equation can be simplified to:

(V1^2)/2 = (V2^2)/2

The velocity of the water inside the hose can then be calculated by rearranging the equation:

V2 = √(V1^2 - 2g (z1 - z2))

Therefore, the speed of the water inside the hose can be calculated by substituting in the known values for V1, g, z1, and z2.

Using the given values, the speed of the water inside the hose is calculated to be 12.6 m/s.

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