Answer:
0.000000047
Step-by-step explanation:
Please help me figure out the 3 answers for each letters. PLEASE will be marked as brainliest if correct:))
Answer:
Step-by-step explanation:
Our interval is 180 to 270 so that's quadrant III. In quadrant 3, both x and y are negative. If we set up our right triangle in this quadrant and label it accordingly with the values given for tangent theta, we find that the missing length is the hypotenuse. Solve for that using Pythagorean's Theorem. Doing that gives us that the hypotenuse is [tex]\sqrt{61}[/tex]. Now we can solve for your other identities. First,
[tex]cos(2\theta)=2cos^2\theta-1[/tex] (There are 3 identities for cos(2θ) and regardless of which one you pick, the answer will be the same every time...promise!)
Filling in now:
[tex]cos(2\theta)=2(\frac{-5}{\sqrt{61} })^2-1[/tex] and simplified a bit:
[tex]cos(2\theta)=2(\frac{25}{61})-1[/tex] and a bit more:
[tex]cos(2\theta)=\frac{50}{61}-\frac{61}{61}[/tex] giving us, finally:
[tex]cos(2\theta)=-\frac{11}{61}[/tex]
Now for b. We have an identity for the half angle of sin:
[tex]sin(\frac{\theta}{2})=[/tex] ±[tex]\sqrt{\frac{1-cos\theta}{2} }[/tex] and filling in:
[tex]sin(\frac{\theta}{2})=[/tex] ±[tex]\sqrt{\frac{1-(-\frac{5}{\sqrt{61} } )}{2} }[/tex] which simplifies a bit to:
[tex]sin(\frac{\theta}{2})=[/tex] ±[tex]\sqrt{\frac{1+\frac{5}{\sqrt{61} } }{2} }[/tex] and a bit more to:
[tex]sin(\frac{\theta}{2})=[/tex] ±[tex]\sqrt{\frac{\sqrt{61}+5 }{2\sqrt{61} } }[/tex] I'm not sure if this is the form you need it in, but this is the answer, as convoluted and crazy as it may look.
As for the cosine half-angle, the identity is the same, except there's a + sign in the numerator of the identity instead of a -, giving us the solution:
[tex]cos(\frac{\theta}{2})=[/tex] ±[tex]\sqrt{\frac{\sqrt{61}-5 }{2\sqrt{61} } }[/tex]
Express the following in scientific notation: 0.0000079
Answer:
7.9 * 10 ^-6
Step-by-step explanation:
Move the decimal 6 places to the left so there is one number before the decimal
0.0000079
7.9
The exponent is -6 ( negative because we moved it to the left)
7.9 * 10 ^-6
Answer:
Hey there!
7.9 × 10-6 is your answer.
Hope this helps :)
Points A, B, and C are collinear. Point B is between A and C. Solve for x. Find x if BC = 2x+10, AC = x+21, and AB = 11.
the answer choices:
*0 *-4 *-11 *-1
Answer:
x = 0
Step-by-step explanation:
Since the points are collinear , then
AB + BC = AC , that is
11 + 2x + 10 = x + 21
2x + 21 = x + 21 ( subtract x from both sides )
x + 21 = 21 ( subtract 21 from both sides )
x = 0
Can u guys answer question 2 pls
Answer:
"2.93BAR
LET X=2.93BAR
10X=29.393BAR
100X=293.93BAR
NOW WE WILL SUBTRACT THE FIRST EQUATION FROM THIRD EQUATION
100X=293.93BAR
X= 2.93BAR
99X=291.00BAR
IT CAN ALSO BE WRITTEN LIKE
X=291/99"
This was an answer from the same question someone else asked.
This answer was given by grvbundela008p3f6id
Step-by-step explanation:
Select the correct answer.
Simplify the following expression.
(3x^2 - 11x - 4) – (x – 2) (2x + 3)
Answer choices
5x^2 - 12x - 10
x^2 - 10x + 2
x^2 + 10x - 2
x^2 – 12x – 10
Answer:
x^2 -10x+2
Step-by-step explanation:
(3x^2 - 11x - 4) – (x – 2) (2x + 3)
FOIL
(3x^2 - 11x - 4) – (2x^2-4x+3x-6)
Combine like terms
(3x^2 - 11x - 4) – (2x^2 -x-6)
Distribute the minus sign
3x^2 - 11x - 4 – 2x^2 +x+6
Combine like terms
x^2 -10x+2
which is the solution set of 18 - 3n + 2 = n + 20 - 4n Ф 0 all reals
Answer:
all reals
Step-by-step explanation:
Simplified, you have ...
20 -3n = 20 -3n
The equation is a tautology, true for all values of n.
The solution set is "all reals."
The following expression is a polynomial: 4x + 5y True False
Answer: False. This expression is a monomial!
Answer:
false
Step-by-step explanation:
it is molonomial
simplify the following
Answer:
1) 11[tex]\sqrt{3}[/tex]
2) 2[tex]\sqrt{2}[/tex]
3) [tex]20\sqrt{3} + 15\sqrt{2}[/tex]
4) [tex]53 + 12\sqrt{10}[/tex]
5) -2
6) [tex]7\sqrt{2} - 5\sqrt{3}[/tex]
Step-by-step explanation:
1) 2[tex]\sqrt{12}[/tex] + 3[tex]\sqrt{48}[/tex] - [tex]\sqrt{75}[/tex]
=(2 × 2[tex]\sqrt{3}[/tex] )+ (3 × 4[tex]\sqrt{3}[/tex]) - 5[tex]\sqrt{3}[/tex]
= 4[tex]\sqrt{3}[/tex] + 12[tex]\sqrt{3}[/tex] - 5[tex]\sqrt{3}[/tex]
= 11[tex]\sqrt{3}[/tex]
2) 4[tex]\sqrt{8}[/tex] -2[tex]\sqrt{98}[/tex] + [tex]\sqrt{128}[/tex]
= (4 × 2[tex]\sqrt{2}[/tex]) - (2 × 7[tex]\sqrt{2}[/tex]) + 8[tex]\sqrt{2}[/tex]
= 8[tex]\sqrt{2}[/tex] - 14[tex]\sqrt{2}[/tex] +8[tex]\sqrt{2}[/tex]
= 2[tex]\sqrt{2}[/tex]
3) 5[tex]\sqrt{12\\}[/tex] - 3[tex]\sqrt{18} + 4 \sqrt{72} +2\sqrt{75}[/tex]
= 5× [tex]2\sqrt{3}[/tex] - 3×[tex]3\sqrt{2}[/tex] + 4×[tex]6\sqrt{2}[/tex] + 2×[tex]5\sqrt{3}[/tex]
= [tex]10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}[/tex]
= [tex]20\sqrt{3} + 15\sqrt{2}[/tex]
4) [tex](2\sqrt{2} + 3\sqrt{5} )^{2}[/tex]
= [tex]8 + 12\sqrt{10} + 45[/tex]
= [tex]53 + 12\sqrt{10}[/tex]
5) [tex](1+\sqrt{3} ) (1-\sqrt{3} )[/tex]
= [tex]1 - 3[/tex]
= -2
6) [tex](2\sqrt{6} -1) (\sqrt{3} -\sqrt{2} )[/tex]
= [tex]2\sqrt{18}-2\sqrt{12} -\sqrt{3} +\sqrt{2}[/tex]
= 2×[tex]3\sqrt{2}[/tex] - 2×[tex]2\sqrt{3}[/tex] - [tex]\sqrt{3} + \sqrt{2}[/tex]
= [tex]6\sqrt{2} - 4\sqrt{3} -\sqrt{3} +\sqrt{2}[/tex]
= [tex]7\sqrt{2} - 5\sqrt{3}[/tex]
Hope the working out is clear and will help you. :)
Step-by-step explanation:
please I solved the question in the diagram above
antara berikut yang manakah faktor perdana bagi 28 A.1 B.4 C.2 D.28
Answer:
C.2
Step-by-step explanation:
Faktor perdana adalah faktor numbor² bagi sesuatu nombor yang juga merupakan nombor perdana.
Faktor nombor 28 adalah 1 ,2, 4 , 7 ,14 dan 28.
Dalam list nombor perdana ini hanya 2 dan 7 merupakan nombor perdana. Maka , jawapan soalan ini adalah 2.
Estimate the correlation coefficient that would best describe the data below.
0.4
-0.4
0.9
-0.9
Answer:
Step-by-step explanation:
Draw a line through the data points with about half of the points on one side of the line and the other half on the other side. You'll see that there is a slight positive rise in the graph as we move from left to right, but the correlation is weak. Thus, 0.4 is the correct correlation coefficient in this case.
The correlation coefficient that would best describe the data give in the table is 0.4 which is a weak positive correlation.
CorrelationWhat is correlation?The statistical concept of correlation describes how closely two variables move in tandem with one another.
Types of correlation:(1) Positive correlation:The two variables are considered to have a positive correlation if they move in the same direction.When there is a complete positive correlation, the correlation coefficient is 1.(2) Negative correlation:We say there is a negative correlation between the variables when the 'y' variable tends to decrease as the 'x' variable increases.(3) No correlation:We claim there is no correlation between the two variables when there is no obvious connection between them.Description for the graph:As the graph is scattered in such a way that,if we draw a line from the centre, we can observe that as 'x' increases 'y' also increases so the relation is positive correlation.
But it is seen in the graph that these points are scattered, so this relation is weak. For positive weak correlation the value should be less than 0.5.
Therefore, the given graph shows positive weak correlation with value 0.4.
To know more about statistics, here
https://brainly.com/question/23724696
#SPJ2
Write down inequalities,that are satisfied by these sets of integers between -10 and 10
1,2,3,4,5,6,7,8,9,10
-3,-4,-5,-6,-7,-8,-9,-10
9,10
-10
Answer:
Below
Step-by-step explanation:
Notice that x is between 10 and -10 but takes only the values that are integers.
The inequalities:
● we can write an inequality that includes all these values.
● -10 《 x 《 10
This is a possible inequality
Multiply both sides by 2 and you will get a new one:
● -20 《 2x 《 20
You can multiply it by any number to generate a new inequality.
Or you can add or substract any number.
Wrapping a Package It takes 70 inches of ribbon to make a bow and wrap the ribbon
round a box. The bow takes 32 inches of ribbon. The width of the box is 14 inches. What
the height of the box?
-14 in. -
First subtract the amount the bow takes from the total:
70 - 32 = 38 inches
The width is 14 on top and bottom so subtract 14 x 2 = 28 from 38:
38-28 = 10
Divide 10 by the 2 sides:
10/2 = 5
The height is 5 inches.
A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 40 dumpster loads of waste removed. In week 10, there were 30 dumpster loads removed. Assume that the reduction in the amount of waste each week is linear. Write an equation in function form to show the amount of trash removed each week. A f(x) = −2x + 40. B f(x) = 2x + 40 C f(x) = −2x + 50 D f(x) = 2x + 50
Answer:
The answer is A f(x) = -2x + 40
Step-by-step explanation:
it has a negative 2 because the dumps are decreasing by 2 every week and x is the amount of weeks and + 40 because that is the amount you started with.
simplify (b^4)^3 because the nun of the answers answer my question
Answer:
b^12
Step-by-step explanation:
(b^4)^3
We know that x^y^z = x^(y*z)
b^4^3 = b^*4*3) = b^12
PLS HELP ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST!!
Mary wants to get spray foam insulation in her attic space. Shown here is a diagram of her attic - is the spray foam costs $3.15 per cubic meter, how much will it cost Mary to get her whole attic done?
Answer:
v = (base x height x length)/2
(7 x 10 x 13)/2 = 455 x 3.15 = 1433.25$
hope that answers your question
Find the midpoint between two points on a number line if one of the points is at -7, and the other point is at 12.
A. 9.5
B. 5
C. -2
D. 2.5
Answer:
D
Step-by-step explanation:
The midpoint is the average of the 2 endpoints, that is
midpoint = [tex]\frac{-7+12}{2}[/tex] = [tex]\frac{5}{2}[/tex] = 2.5 → D
A class has 25 students in it. 4 students drop the class. What is a reasonable estimate for the percentage of students that dropped?
Answer:
16% drop
Step-by-step explanation:
4/25 drop
Multiply by 4/4
16/100
16% drop
Answer:
16%
Step-by-step explanation:
SInce 4 students left the class, and there are 25 students, let's make it a fraction.
4/25.
As it is asking for a percentage though we could simply convert our fraction to a percentage.
Simply divide the numerator (4) by the denominator (25).
This gives us 0.16.
Which is 16%.
What is happening to this graph when the x-values are between - 1 and 1?
A. It is decreasing.
B. It is constant
C. It is increasing
Answer:
A. It’s decreasing
Step-by-step explanation:
Hey there!
Well on the graph at points -1 and 1 we can tell the line is going down,
meaning the line is decreasing.
Hope this helps :)
Answer:it is increasing
Step-by-step explanation:
A girl who normally gets A's didn't do the first assignment given on the first day of school and now has 0%. How many 95% grades will she need to achieve an average of 90% overall? The points for each assignment are based on what she scores.
Answer:
19 of 95% grades
Step-by-step explanation:
90= (0+95(x-1))/x
90x=0+95(x-1)
90x=95(x-1)
90x=95x-95
90x-95x=-95
-5x=-95
x=-95/-5
x=19
find the distance between the pair of points (2, -5) and (3, -7)
Step-by-step explanation:
Using distance formula:
√(- 7 - (-5))² + (3 - 2)²
√(- 7 + 5)³ + 1²
√(-2)² + 1
√4+1
√5
lf y 1/4 · when x=5, find y when x=7. given that y varies directly with x.
y=
Answer:
y= 0.35
Step-by-step explanation:
y 1/4
when x=5,
find y=? when x=7.
given that y varies directly with x.
y = kx
Where k is the constant of proportionality
k= y/x
k= (1/4)÷ 5
k= 0.05
y= kx
y= (0.05)(7)
y= 0.35
I Hope this will helpful...
trigonometry help got one right need help with another
Answer:
B. [tex] \frac{HI}{GI} [/tex]
Step-by-step explanation:
The trigonometric ratio formula for tangent of any angle in a right triangle is given as:
tan(θ) = [tex] \frac{opposite}{adjacent} [/tex]
Note: it is the length of the side opposite to the θ, and the length of the side adjacent to θ.
Thus, in the right triangle given, ∆GHI,
θ = <G
The length of side the opposite <G = HI
The length of the side adjacent to <G = GI
Therefore, the equivalent of tan(<G) = [tex] \frac{HI}{GI} [/tex]
Name the quadrants in which of the following points (3, 0) (-9,-3) lie.
Answer:
(3,0) lie between quadrants I and II. (-9, -3) lie in quadrant III
how many are 5 raised to 4 ???
Answer:
625
Step-by-step explanation:
5⁴ = 5x5x5x5 = 625
If the amount of VAT paid for an item at 13% was Rs 390, at what price was the item sold?
Answer:
Step-by-step explanation:
Let the price of the item = Rs x
13% of x = 390
[tex]\frac{13}{100}*x=390\\\\\\x = 390*\frac{100}{13}\\\\\\[/tex]
x = Rs. 3000
please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44)=87m+m 5. Solve for k: ck+5k=a
Answer:
d = 55.5
x = 1
c = 11
m = [tex]\frac{1}{122}[/tex]
k = [tex]\frac{a}{(c + 5)}[/tex]
Step-by-step explanation:
Sorry, the formatting is slightly hard to understand, but I think this is what you meant.
Q1.
[tex]\frac{1}{6}[/tex]d - 8 = [tex]\frac{5}{8}[/tex] x 2
Step 1. Simplify.
[tex]\frac{5}{8}[/tex] x 2 = [tex]\frac{5}{8}[/tex] x [tex]\frac{2}{1}[/tex] = [tex]\frac{10}{8}[/tex]
Step 2. Cancel out the negative 8.
[tex]\frac{1}{6}[/tex]d - 8 = [tex]\frac{10}{8}[/tex]
+ 8 to both sides (do the opposite: [tex]\frac{1}{6}[/tex]d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)
[tex]\frac{1}{6}[/tex]d = [tex]\frac{10}{8}[/tex] + 8
Step 3. Simplify.
[tex]\frac{10}{8}[/tex] + 8 = [tex]\frac{10}{8}[/tex] + [tex]\frac{8}{1}[/tex] = [tex]\frac{10}{8}[/tex] + [tex]\frac{64}{8}[/tex] = [tex]\frac{74}{8}[/tex] = [tex]\frac{37}{4}[/tex]
Step 4. Cancel out the [tex]\frac{1}{6}[/tex].
[tex]\frac{1}{6}[/tex]d = [tex]\frac{37}{4}[/tex]
÷ [tex]\frac{1}{6}[/tex] from both sides (do the opposite: d is multiplied by [tex]\frac{1}{6}[/tex] right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)
÷ [tex]\frac{1}{6}[/tex] = x 6
So....
x 6 to both sides
d = [tex]\frac{37}{4}[/tex] x 6 = [tex]\frac{37}{4}[/tex] x [tex]\frac{6}{1}[/tex] = [tex]\frac{222}{4}[/tex] = [tex]\frac{111}{2}[/tex] = 55.5
Step 5. Write down your answer.
d = 55.5
Q2.
3x - 4 + 5x = 10 - 2x × 3
Step 1. Simplify
3x - 4 + 5x = 3x + 5x - 4 = 8x - 4
10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x
Step 2. Cancel out the negative 6x
8x - 4 = 10 - 6x
+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)
14x - 4 = 10
Step 3. Cancel out the negative 4
14x - 4 = 10
+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)
14x = 14
Step 4. Divide by 14
14x = 14
÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])
x = 1
Step 5. Write down your answer.
x = 1
Q3.
7(c - 3) = 14 × 4
Step 1. Expand the brackets
7(c - 3) = (7 x c) - (7 x 3) = 7c - 21
Step 2. Simplify
14 x 4 = 56
Step 3. Cancel out the negative 21
7c - 21 = 56
+ 21
7c = 56 + 21
7c = 77
Step 4. Cancel out the ×7
7c = 77
÷ 7
c = 77 ÷ 7
c = 11
Step 5. Write down your answer.
c = 11
Q4.
11([tex]\frac{m}{22}[/tex] + [tex]\frac{3}{44}[/tex]) = 87m + m × 5
Step 1. Expand the brackets
11([tex]\frac{m}{22}[/tex] + [tex]\frac{3}{44}[/tex]) = (11 x [tex]\frac{m}{22}[/tex]) + (11 x [tex]\frac{3}{44}[/tex]) = ([tex]\frac{11}{1}[/tex] x [tex]\frac{m}{22}[/tex]) + ([tex]\frac{11}{1}[/tex] x [tex]\frac{3}{44}[/tex]) = [tex]\frac{11m}{22}[/tex] + [tex]\frac{33}{44}[/tex] = [tex]\frac{m}{2}[/tex] + [tex]\frac{3}{4}[/tex]
Step 2. Simplify.
87m + m x 5 = 87m + 5m = 92m
Step 3. Cancel out the add [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] + [tex]\frac{3}{4}[/tex] = 92m
- [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = 92m - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{92m}{1}[/tex] - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m}{4}[/tex] - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m - 3}{4}[/tex]
Step 4. Cancel out the ÷ 4
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m - 3}{4}[/tex]
x 4
2m = 368m - 3
Step 5. Cancel out the 368m
2m = 368m - 3
- 368m
-366m = - 3
Step 6. Cancel out the × -366
-366m = -3
÷ -366
m = [tex]\frac{-3}{-366}[/tex]
m = [tex]\frac{1}{122}[/tex]
Step 7. Write down your answer.
m = [tex]\frac{1}{122}[/tex]
Q5.
ck + 5k = a
Step 1. Factorise
ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)
Step 2. Cancel out the × (c + 5)
k(c + 5) = a
÷ (c + 5)
k = a ÷ (c + 5)
k = [tex]\frac{a}{(c + 5)}[/tex]
Pls Answer A and B. You don’t need to explain. Thank you!!
During the hours from 9:00 PM on Friday to 9:00 pm on Sunday, Kristin spent 1/3 of her time sleeping, 1/8 of her time raking leaves, 1/12 of her time reading a book, 1/16 of her time working on her science project, 1/24 of her time riding in the car, and 1/48 of her time watching television. How many hours in this time period remained for all other activities?
Answer:
16 hrs of Sleep
6 hrs of Raking Leaves
4 hrs reading
3 hrs science project
2 hrs riding car
1 hr watching tv
Step-by-step explanation:
Its division on all of them, 9:00 PM on Friday to 9:00 PM on Sunday, would be 2 days, there being 24 hrs on one day, and since its 2 days, its 48, then you divide 48 by the denominator, and there you should get your timed answer.
For example, for the 1/3, you'll divide the denominator (the bottom number, in this case 3) by 48, since that's the whole amount, and the 3 is the amount of time they spent out of that whole. The division is written 48 ÷ 3 = 16
Hope this helped a bit :)
Ten tiles numbered 1 through 10 are turned face down. One tile is turned up at random, and a die is rolled and the number is square. What is the probability, written as a percent, that the product of the numbers on the tile and the die will be a perfect cube?
Answer:
18.33333333%. Please mark as brainliest if I’m Correct. :)
Step-by-step explanation:
50 points! I would appreciate an explanation, I actually want to know how to do this. Thanks! :P
Answer:
1.
(a) The Domain is the set of inputs of the function.
Considering that the function takes a period of 3 weeks (21 days), the domain is [0, 21], once we can't evaluate what happens after the 21st day.
[tex]\text{Domain is } [0, 21][/tex]
Otherwise, it could be [tex][0, \infty)[/tex]
Note: We include 0 and 21.
Once the greatest balance was $400, it will not exceed $400, either it doesn't show negative values.
[tex]\text{Range is } [0, 400][/tex]
Note: We include 0 and 400.
(b)
Once the greatest balance was $400, when x=0, it seems that the y-value is half of $400, therefore, approximately $200. It also represents the initial value, the amount of money when she opened the account.
(c)
[tex]f(x)=B(d)[/tex]
[tex]B(12)=0[/tex]
(d)
It is in segment 4.
The balance equal to zero means that the y-value of the graph is zero, therefore in the x-axis.