Answer: Efficiency signifies a peak level of performance that uses the least amount of inputs to achieve the highest amount of output.
Explanation: It minimizes the waste of resources such as physical materials, energy, and time while accomplishing the desired output.
Answer:
The efficiency of a simple machine is defined as the ratio of useful work done by the machine ( output work) to the total work out into the machine ( input work).
Explanation:
EfficiencyIf a machine overcomes a load ' L ' and the distance travelled by the load is 'Ld' , the work done by the load is L× LD. It is also called output work or useful work.
Therefore, [tex] \boxed{Output \: work \: = L \: \times \: Ld}[/tex]
Likewise, The effort applied to overcome the load is 'E' and the distance covered by effort is 'Ed' , the work done by effort is E × Ed. It is also called input work.
Therefore, [tex] \boxed{Input \: work = E \times Ed}[/tex]
The efficiency of a simple machine is defined as the ratio of output work to the input work .
Therefore, [tex] \boxed{Efficiency ( η)= \frac{outpt \: work}{input \: work} \times 100\%}[/tex]
Efficiency is expressed in percentage. It is a ratio of two works. A machine is never 100% efficient. It is because no machine is friction free and due to friction, some of the input energy is wastes in the form of heat energy.
[tex] \mathrm{Hope \: I \: helped!}[/tex]
[tex] \mathrm{Best \: regards!}[/tex]
A disk-shaped dough is initially spinning at 2 rotations per second (1 rotation = 360°). As time goes on, it slowly deforms, and is now spinning at a different angular speed. The dough changed radius from 16 cm to 17 cm, and its mass remained constant throughout. What is its final angular speed in degrees/s?
Answer:
10.44° per sec
Explanation:
Initial angular speed N = 2 rotations per minute
converting to rad/s ω = 2πN/60 = (2 x 3.142 x 2)/60 = 0.21 rad/s
the initial radius of the disk = 16 cm = 0.16 m
final radius = 17 cm = 0.17 m
Angular momentum = [tex]I[/tex]ω
where [tex]I[/tex] = rotational inertia = mass x [tex]radius^{2}[/tex]
ω = angular speed
For the initial case
[tex]I[/tex] = m x [tex]0.16^{2}[/tex] = 0.0256m
Angular momentum = 0.0256m x 0.21 = 0.0054m
For second case
[tex]I[/tex] = m x [tex]0.17^{2}[/tex] = 0.0289m
Angular momentum = 0.0289m x ω = 0.0289mω
For conservation of rotational momentum, initial angular momentum must be equal to the final angular momentum
0.0054m = 0.0289mω
m cancels out, we have
0.0054 = 0.0289ω
ω = 0.187 rad/s
converting back to rpm, we have
N = 0.187/2π = 0.029 rotations per sec
0.029 x 360 = 10.44° per sec
A 1 kg object accelerated at a constant rate of 5m/s? Estimate the net force needed to accelerate the object
Answer:
5 N.
Explanation:
Data obtained from the question include the following:
Mass (m) of object = 1 kg
Acceleration (a) = 5 m/s²
Force (F) =?
Force is simple defined as the product of mass and acceleration. Mathematically, it is expressed as:
Force (F) = mass (m) x acceleration (a)
F = ma
With the above formula, we can obtain the net force needed to accelerate the object as follow:
Mass (m) of object = 1 kg
Acceleration (a) = 5 m/s²
Force (F) =?
F = ma
F = 1 x 5
F = 5 N.
Therefore, the net force needed to accelerate the object is 5 N.
FASTTT I BEG U An astronaut weighs 900 N on earth. On the moon he weighs 150 N. Calculate the moons’ gravitational strength. (Take g = 10 N/kg).
mass of an object is always constant
weight is a force, [tex]W=mg[/tex] where $g$ is acceleration due to gravity.
Weight on earth is , $900=m\cdot 10 \implies m=90$ kg
weight on moon is $150=90\times g_{\text{moon}} \implies g=\frac{5}{3}$
You are the driver of the car in the photos above. You Are traveling at 30 mph when suddenly the car goes from its position in the first photo to the position in the second photo. What is happening
Answer:
the car uses teleportation, to zip to one side of the photo, to the other
Explanation:
A cricket ball is dropped from a height of 30 m. Calculate the speed of the ball when it hits the ground
Answer:
0m/s
Explanation:
When the ball hits the ground, it then moves with uniform motion and when an object is in uniform motion, the speed is 0m/s