Answer:
An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to remove.
Explanation:
Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 , a width of 2.1 , and a height of 6.6 Part B answer: 11.76cm^2
Answer:
The volume of the rectangular prism is 77.616 cm³
Explanation:
Here is the remaining part of the question:
Part B:
What value should you use as the area of the base when calculating the answer to Part C.
Part C:
Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 cm , a width of 2.1 cm , and a height of 6.6 cm Part B answer: 11.76 cm^2
Explanation:
The volume of a rectangular prism is given by:
V = l×w×h
Where V is the volume of the rectangular prism
l is the length of the rectangular prism
and w is the width of the rectangular prism
Recall that the Area (A) of the base of the rectangular prism can be calculated by using
A = l × w
Hence, the volume of the rectangular prism can also be calculated by substituting this into the equation to give
V = A × h
From the question, the correct answer from part B for the area of the base is 11.76 cm^2; and the height (h) is 6.6 cm
Hence, the volume of the rectangular prism is
V = A × h
V = 11.76 cm² × 6.6 cm
V = 77.616 cm³
density is a ___ that ____ the ____ of an object to its ______
Answer:
density is a PROPERTY that DESCRIBES the MASS of an object to its VOLUME.
Explanation:
solve
10N x 1m = 10)
Answer:
=10 joules
when multiplying with newtons ( the unit of force)
by a perimeter, it will becone joules, but the specific amount depends on how many newtons and metres there are
A 0.100 M solution of an acid, HA, has a pH = 2.00. What is the value of the ionization constant, Ka for this acid?
Answer:
[tex]Ka=1.11x10^{-3}[/tex]
Explanation:
Hello,
In this case, since the ionization of the given HA acid is:
[tex]HA\rightleftharpoons H^++A^-[/tex]
The equilibrium expression is:
[tex]Ka=\frac{[H^+][A^-]}{[HA]}[/tex]
Whereas the concentration of hydrogen ions is compute from the pH=
[tex][H^+]=10^{-pH}=10^{-2.00}=0.01M[/tex]
Which also equals the concentration of [tex]A^-[/tex] and the in general the ionization extent, therefore, the acid ionization constant, Ka, turns out:
[tex]Ka=\frac{0.01*0.01}{0.1-0.01}\\ \\Ka=1.11x10^{-3}[/tex]
Regards.
bronze is a mixture of copper and tin. Would all bronze have the same melting point? Explain.
Answer:
its also a mixture of gold.
Explanation:
if jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy
Answer:
If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy,work is being done. Work is said to be done when it transforms energy from one form to another or from one place to another.
Explanation:
the quantity of 3.00 cm ^ 3 is the same _ mL
Answer:
3 mL
Explanation:
1 cubic centimeter (cm³) is equal to 1 milliliter (mL).
We want to find out how many milliliters 3 cm³ is equal to.
Since 1 cm³ is equal to 1 mL, 3 cm³ is equal to 3 mL.
The quantity of 3.00 cm³ is the same as 3 milliliters (mL).
Answer:
27 or [tex]3.00^{3}[/tex] (they're the same)
Explanation:
Write 3.00^3 out: [tex]3.00^{3}[/tex] [tex]3.00^{3}[/tex] = 3.00 × 3.00 × 3.00 = 27Convert 27 cm to mL: 27 × 1 = 27Therefore, 27 cm is the same as 27 mL.
which of the following structures can differentiate plant and animal cells
Explanation:
plant cells are rigid in shape
animal cells are flexible in shape
animal cell are flexible because of their movement around
plant cells are rigid cause they stay without walking around
Science always begins with what?
Step 7- Communicate. Present/share your results. Replicate.
Step 1- Question.
Step 2-Research.
Step 3-Hypothesis.
Step 4-Experiment.
Step 5-Observations.
Step 6-Results/Conclusion.
Classify each of the following as either a physical change or a chemical change.
(a) Dissolving sugar in water
(b) Crushing rock salt
(c) Burning sulfur
(d) Digesting a chili dog
Answer:
(a) Dissolving sugar in water ⇒ physical change
(b) Crushing rock salt ⇒ physical change
(c) Burning sulfur ⇒ chemical change
(d) Digesting a chili dog ⇒ chemical change
Explanation:
Physical changes are those in which the substance does not alter its composition. They only involve changes of states of matter and the chemical substance is stil the same after the change occurs. By other hand, chemical changes are those in which new subtances are formed. So, the subtance is not the same after the change.
(a) Dissolving sugar in water ⇒ physical change; because we obtain a solution of sugar in water (sugar is stil sugar).
(b) Crushing rock salt ⇒ physical change; because we obtain crushed salt, but the chemical composition of the salt is not altered.
(c) Burning sulfur ⇒ chemical change; because sulfur is oxidized (chemical reaction) and new compounds are formed, for example sulfur dioxide.
(d) Digesting a chili dog ⇒ chemical change; because the digestion process is produced by the action of hydrocloric acid, and new compounds are formed.
Which is most closely associated with the Lewis dot diagrams for molecules that contain atoms of elements from the boron family, Group 13 (Group IIIA)
The question is incomplete, the complete question is;
Which is most closely associated with the Lewis dot diagrams for molecules that contain atoms of elements from the boron family, Group 13 (Group IIIA)?
a. elements shown as 3+ ions
b. expanded octets of electrons
c. incomplete octets of electrons
d. odd number of valence electrons
e. kernel electrons promoted to the valance shell
Answer:
incomplete octets of electrons
Explanation:
A Lewis dot structure is a representation of a molecule based on the number of valence electrons on its valence shell. These electrons are shown as dots hence Lewis structures are also called dot electron structures.
For elements of group 13, they mostly form dimeric compounds due to the fact that their compounds possess an incomplete octet of electrons. This is common to group 13 elements, hence the answer above.
You have 87.0mL of a 0.500M stock solution that must be diluted to 0.100M. What is the final volume g
Answer:
435 mL
Explanation:
Step 1: Given data
Initial volume (V₁): 87.0 mLInitial concentration (C₁): 0.500 MFinal volume (V₂): ?Final concentration (C₂): 0.100 MStep 2: Calculate the final volume of the solution
We want to prepare a diluted solution from a concentrated one. We can calculate the final volume of the solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₂ = C₁ × V₁ / C₂
V₂ = 0.500 M × 87.0 mL / 0.100 M
V₂ = 435 mL
Look at this picture and please help
Answer : The kinetic energy will be 24 J.
Explanation : Given,
Mass of marble = 3 kg
Velocity of a marble = 4 m/s
Formula used to calculate the kinetic energy is:
[tex]K.E=\frac{mv^2}{2}[/tex]
where,
K.E = kinetic energy
m = mass
v = velocity
Now putting all the given values in this formula, we get:
[tex]K.E=\frac{3kg\times (4m/s)^2}{2}[/tex]
[tex]K.E=24kg.m^2/s^2=24J[/tex] [tex](1J=1kg.m^2/s^2)[/tex]
Therefore, the kinetic energy will be 24 J.
Which of the following properties are intensive, and which are extensive? Malleability intensive or extensive Length intensive or extensive Hardness intensive or extensive Volume intensive or extensive
Answer:
Malleability is intensive
Length is extensive
Hardness is intensive
Volume is extensive
Explanation:
Extensive properties change when u change the size of an object and intensive properties don’t
Also I just took the quiz
A physical property refer to the properties of an object that can be measured and observed without changing (altering) the chemical composition of the object.
In Chemistry, there are two (2) main types of physical property and these include:
I. Extensive property: this is a property that changes when the size of an object changes. Some examples of an extensive property are:
Length.Volume.II. Intensive property: it is a property that remains the same regardless of the change in the size of an object, Some examples of an intensive property are:
Malleability.Hardness.Find more information: https://brainly.com/question/23529643
A unimolecular elementary step involves only a single reactant that breaks apart.a) trueb) false
Answer:
True
Explanation:
The correct option is; True.
Unimolecular elementary steps in a reaction requires only one reactants, they are usually decomposition reactions. They take the general form;
A --> B + C
What is the pH of a buffer made from 0.130 mol of HCNO (Ka = 3.5 × 10⁻⁴) and 0.410 mol of NaCNO in 2.0 L of solution?
Answer:
[tex]pH=3.95[/tex]
Explanation:
Hello,
In this case, by using the Henderson-Hasselbach equation we can compute the pH as follows:
[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]
Whereas the concentration of the acid (HCNO) and the base (NaCNO) are computed by considering the given volume:
[tex][base]=\frac{0.410mol}{2.0L}=0.205M[/tex]
[tex][acid]=\frac{0.130mol}{2.0L}=0.065M[/tex]
Therefore, the pH turns out:
[tex]pH=-log(3.5x10^{-4})+log(\frac{0.205M}{0.065M} )\\\\pH=3.95[/tex]
Regards.
Explain why NaBH4 is less reactive than LiAlH4 (Hint: write the structure of each ion, (BH4) - and (AlH4) - , with their formal charges
Answer:
See explanation
Explanation:
The ability of a hydride to act as a reducing agent depends on the electro negativity of the central atom in the complex hydride anion.
If we compare the electronegativities of Boron and Aluminum, Boron is more electronegative than aluminum. The more electronegative the central atom is, the lesser the electron density on the hydride and the lesser its ability to act as a reducing agent.
For the reason stated above, LiAlH4, having aluminium of low electro negativity as its central atom is a better reducing agent than NaBH4.
the observation has to be made up and i can’t think of anything or a hypothesis who can help!
Answer:the answer is hypothesis
Explanation: that’s the answer
An eccentric chemistry professor (not mentioning any names) stops in every day and orders 200ml of Sumatran coffee at precisely 65.0°C. You then need to add enough milk at 7.00°C to drop the temperature of the coffee, initially at 85.0°C, to the ordered temperature. Calculate the amount of milk (in ml) you must add to reach this temperature. In order to simplify the calculations, you will start by assuming that milk and coffee have the specific heat and density as if water. In the following parts, you will remove these simplifications. Solve now this problem assuming the density is 1.000 g/ml for milk and coffee and their specific heat capacity is 4.184 J/(g ºC). How much milk will you add?
Answer:
68.97g of milk must be added
Explanation:
To solve this problem we need to use the equation:
Q = C*m*ΔT -Coffee cup calorimeter equation-
This equation relates mass and change in temperature with heat of solution, Q.
The energy that decreases in the milk is the same that increases in the milk. That is:
Q(milk) = Q(tea)
Using the equation:
4.184J/molK* Mass milk * (65.0°C - 7.00°C) = 4.184J /molK * 200g (Tea) * (85.0°C - 65.0°C)
Mass milk * 58.0°C = 200g * 20.0°C
Mass milk = 4000g°C / 58.0°C
Mass milk =
68.97g of milk must be added-5°F to kelvins nearest whole number
Answer: 252
Explanation:
# turn F to C
C=(F-32)5/9
C=(-5-32)5/9
C=-37 × (5/9)
C= -21
# turn C to K
K=C+273
K=(-21)+273
K=252
Answer:
253 Kelvins
Explanation:
We want to convert -5°F to Kelvins.
First, we must convert -5°F to Celsius. The formula is:
°C= (°F - 32) * 5/9
Plug -5 in for °F.
°C= (-5-32) * 5/9
Solve inside the parentheses first. Subtract 32 from -5.
°C= (-37) * 5/9
Multiply -37 and 5/9.
°C= -20.5555556
-5° F is equal to -20.5555556° C.
Next, convert Celsius to Kelvins. The formula is:
K= °C + 273.15
Plug -20.5555556 in for °C.
K= -20.5555556 + 273.15
Add -20.5555556 and 273.15.
K= 252.594444
Round to the nearest whole number. The 5 in the tenth place tells us to round 252 to 253.
K ≈ 253
-5°F is equal to about 253 Kelvins.
What is the engine piston displacement in liters of an engine whose displacement is listed as 490 in^3?
Answer:
490 in^3 = 8.03 L
Explanation:
Given:
The engine displacement = 490 in^3
= 490 in³
To determine the engine piston displacement in liters L;
(NOTE: Both in^3 (in³) and L are units of volume). Hence, to find the engine piston displacement in liters (L), we will convert in^3 to liters (L)
First, we will convert in³ to cm³
Since 1 in = 2.54 cm
∴ 1 in³ = 16.387 cm³
If 1 in³ = 16.387 cm³
Then 490 in³ = (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³
∴ 490 in³ = 8029.63 cm³
Now will convert cm³ to dm³
(NOTE: 1 L = 1 dm³)
1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm
∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³
If 1 cm³ = 1 × 10⁻³ dm³
Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³
≅ 8.03 dm³
∴ 8029.63 cm³ = 8.03 dm³
Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³
Since 1L = 1 dm³
∴ 8.03 dm³ = 8.03 L
Hence, 490 in³ = 8.03 L
An engine piston displacement of 490 in³ is equivalent to 8.03 L.
The engine piston displacement is 490 in³ and we want to convert it to liters. Since both of them are units of volume, we will need one or more conversion factors.
What is a conversion factor?A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
Step 1: Convert 490 in³ to cm.We will use the conversion factor 1 in = 2.54 cm.
490 in³ × (2.54 cm/1 in)³ = 8.03 × 10³ cm³
Step 2: Convert 8.03 × 10³ cm³ to L.We will use the conversion factor 1 L = 1000 cm³.
8.03 × 10³ cm³ × (1 L/1000 cm³) = 8.03 L
An engine piston displacement of 490 in³ is equivalent to 8.03 L.
Learn more about conversion factors here: https://brainly.com/question/24513742
If the eyepiece of your scope has a power of 10, and the selected objective lens has a power of 20,what is the total
magnification?
20x
200x
O O
Ο Ο
0 30x
300x
Answer:
200x
Explanation:
The total magnification of a microscope depends on the power of the eyepiece and that of the objective lens. It is obtained by multiplying the two factors together.
The total magnification of a microscope can be mathematically expressed as:
Total Magnification = ocular/eyepiece magnification x objective magnification
In the illustration, eyepiece magnification = 10 and objective magnification = 20. Hence,
Total Magnification = 10 x 20 = 200x
The magnification power of the microscope has been 200X. Thus, option B is correct.
A microscope has been the instrument used for the analysis of the magnified image of micro-sized or small objects.
The microscope has been consisted of the objective lens and eyepiece that adjusts the level of magnification of the microscope.
The magnification of the microscope has been the product of the power of the eyepiece and objective lens.
Magnification power = Objective lens power [tex]\times[/tex] Eyepiece power
The given power of objective lens = 20
The power of the eyepiece = 10
Magnification power = 20 × 10
Magnification power = 200X.
The magnification power of the microscope has been 200X. Thus, option B is correct.
For more information about magnification power, refer to the link:
https://brainly.com/question/14668612
Calculate the density of a rock if it has a mass of 498g and a volume of 11.9 mL.
Answer:
Density = 41.8 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]Density = \frac{mass}{volume} [/tex]From the question
mass = 498 g
volume = 11.9 mL
Substitute the values into the above formula and solve for the Density
That's
[tex]Density = \frac{498}{11.9} \\ = 41.8487[/tex]We have the final answer as
Density = 41.8 g/mLHope this helps you
Olivia noticed that the pH of her garden soil decreased after it rained. Did her garden soil become more acidic or less acidic
Answer:
It is becoming more acidic.
Explanation:
The pH scale is a way to express the concentration of hydrogen ions. This scale goes from 0 to 14 and it is adimensional.
If the pH < 7, the solution is acid.If the pH = 7, the solution is neutral.If the pH > 7, the solution is basic.The lower the pH, the more acidic the solution. Since the pH of the garden soil of Olivia is decreasing, it is becoming more acidic.
You start with 420 mg of isotope which has half life of 20 days. How many mg will be left after 40 days
Answer:
105 mg
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 420 mg
Half life (t½) =20 days
Time (t) = 40 days
Amount remaining (N) =..?
Next, we shall determine the rate constant K, for the disintegration.
This can be obtained as follow:
Half life (t½) =20 days
Rate constant (K) =?
K = 0.693/ t½
K = 0.693/20
K = 0.03465 /day
Finally, we shall determine the amount remaining after 40 days as follow:
Original amount (N₀) = 420 mg
Rate constant (K) = 0.03465 /day
Time (t) = 40 days
Amount remaining (N) =..?
Log(N₀/N) = kt/2.3
Log (420/N) = (0.03465 x 40)/2.3
Log (420/N) = 1.386/2.3
Log (420/N) = 0.6026
420/N = antilog (0.6026)
420/N = 4
Cross multiply
420 = N x 4
Divide both side by 4
N = 420/4
N = 105 mg
Therefore, the amount remaining after 40 days is 105 mg.
I need help rearranging the following formulas to solve for the requested variable please
Answer :
Part (e): [tex]C_2=\frac{C_1\times P_2}{P_1}[/tex]
Part (f): [tex]P_2=\frac{C_2\times P_1}{C_1}[/tex]
Part (g): [tex]\text{Volume}=\frac{\text{Mass}}{\text{Density}}[/tex]
Explanation :
Part (e):
The given expression is:
[tex]\frac{C_1}{P_1}=\frac{C_2}{P_2}[/tex]
Now rearranging the the terms, we get:
[tex]C_2=\frac{C_1\times P_2}{P_1}[/tex]
Part (f):
The given expression is:
[tex]\frac{C_1}{P_1}=\frac{C_2}{P_2}[/tex]
Now rearranging the the terms, we get:
[tex]P_2=\frac{C_2\times P_1}{C_1}[/tex]
Part (g):
The given expression is:
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}[/tex]
Now rearranging the the terms, we get:
[tex]\text{Volume}=\frac{\text{Mass}}{\text{Density}}[/tex]
Zn + HCl → H2 +ZnCl2 type of reaction?
Answer:
The answer to your question is "Displacement " reaction. Here in the reach Zn +HCl ⇒ZnCl2 + H2 zinc replaces the hydrogen to make the zinc chloride and hydrogen gas is produced as the result and liberated.
What must happen to uranium before it can be used as a fuel source?
Answer:
Uranium must be purified before it is used as a fuel source
Explanation:
The purer the uranium sample, the more the concentration of uranium in the fuel is.
Whenever uranium is extracted from nature, it contains a lot of impurities. Only a few special nuclear reactors can utilize uranium in this raw state. most of the others have to get uranium to become about 3% pure before they begin using it.
To do this, uranium has to be passed through a series of chemical reactions all with the aim of extracting the other compounds that may be present in the fuel.
Which of the following molecules can form hydrogen bonds? Group of answer choices NH3 NaH HI BH3 CH4
Answer:
NH₃
Explanation:
The hydrogen bond is a specially strong type of dipole-dipole interaction. For a hydrogen bond to occur, a molecule must have a hydrogen atom and a very electronegative atom, such as nitrogen, oxygen or fluorine. The hydrogen atom has a positive charge density while the heteroatom has a negative charge density.
Which of the following molecules can form hydrogen bonds?
NH₃ YES
NaH NO
HI NO
BH₃ NO
CH₄ NO
Suggest what the effect of using growth hormone on meat cattle might be
It might affect the health of consumer of that meat. Hope it helps