Let side be a
Area=111units^2We know
[tex]\\ \sf\longmapsto Area=(side)^2[/tex]
[tex]\\ \sf\longmapsto a^2=111[/tex]
[tex]\\ \sf\longmapsto a=\sqrt{111}[/tex]
[tex]\\ \sf\longmapsto a=10.3units[/tex]
Quadrilateral RSTV is dilated with respect to the origin by a scale factor of 1.5 to produce quadrilateral R'S'T'V' . Vertex R is located at (6, -9). Which ordered pair represents R' after the dilation?
Answer:
(9, -13.5)
Step-by-step explanation:
It's given in the question that a quadrilateral RSTV is dilated with a scale factor of 1.5 with respect to the origin to form R'S'T'V'.
Rule for dilation is,
(x, y) → (kx, ky)
where 'k' is the scale factor.
If vertex R of the quadrilateral is (6, -9),
By the given rule of dilation,
R(6, 9) → R'[(1.5 × 6), -(1.5 × 9)]
→ R'(9, -13.5)
Therefore, Option given in bottom right (9, -13.5) will be the answer.
how do you calculate the population mean
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal places.) f(x) = x2 − 8, x1 = 2
Answer:
The first and second iteration of Newton's Method are 3 and [tex]\frac{11}{6}[/tex].
Step-by-step explanation:
The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form [tex]f(x) = 0[/tex] based on the following formula:
[tex]x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}[/tex]
Where:
[tex]x_{i}[/tex] - i-th Approximation, dimensionless.
[tex]x_{i+1}[/tex] - (i+1)-th Approximation, dimensionless.
[tex]f(x_{i})[/tex] - Function evaluated at i-th Approximation, dimensionless.
[tex]f'(x_{i})[/tex] - First derivative evaluated at (i+1)-th Approximation, dimensionless.
Let be [tex]f(x) = x^{2}-8[/tex] and [tex]f'(x) = 2\cdot x[/tex], the resultant expression is:
[tex]x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}[/tex]
First iteration: ([tex]x_{1} = 2[/tex])
[tex]x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}[/tex]
[tex]x_{2} = 2 + \frac{4}{4}[/tex]
[tex]x_{2} = 3[/tex]
Second iteration: ([tex]x_{2} = 3[/tex])
[tex]x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}[/tex]
[tex]x_{3} = 2 - \frac{1}{6}[/tex]
[tex]x_{3} = \frac{11}{6}[/tex]
Here is some information about the goals scored in some hockey games. Each game has four quarters. Please give the answer asap with full explanation and working out.
Answer:
8 home games and 10 away games
Step-by-step explanation:
Total home goals
= 8+5+9+8
= 30
Number of home games
= 30/3.75
= 8
Total away game goals
= 7+8+4+5
= 24
Number of away games
= 24/2.4
= 10
Answer:
i think it is 8 home and 10 away matches
Step-by-step explanation:
write each equation explicitly in terms of x. then indicate whether the equation is a function.
y^2-x^2+1=50
Answer:
Hello,
Step-by-step explanation:
[tex]y^2-x^2+1=50\\y^2=x^2+49\\2\ functions \ :\\\\y=\sqrt{x^2+49} \\\\or\\\\y=-\sqrt{x^2+49} \\[/tex]
Using function concepts, it is found that:
The explicit equation in terms of x is given by: [tex]y = \pm \sqrt{x^2 + 49}[/tex]The equation is not a function, as there are multiple outputs for a single input.----------------------
The expression is given by:
[tex]y^2 - x^2 + 1 = 50[/tex]
In terms of x, the equation is given by:
[tex]y^2 = 50 + x^2 - 1[/tex]
[tex]y^2 = x^2 + 49[/tex]
[tex]y = \pm \sqrt{x^2 + 49}[/tex]
----------------------
An equation is a function if for each value of the input, there is only one output.Testing the input x = 0:
[tex]y = \pm \sqrt{0^2 + 49}[/tex]
[tex]y = \pm \sqrt{49}[/tex]
[tex]y = \pm 7[/tex]
Two output values for one input, thus, it is not a function.
A similar problem is given at https://brainly.com/question/24603090
5 times 3 times 2
show work
Answer:
30
Step-by-step explanation:
5x3=p
px2 = a
5x3 = 15 x 2 = 30
Answer:
5 times 3 times 2=30
Step-by-step explanation:
5×3=15×2=30
Which of the following sets are equal to {x|x < 9 and x> 2}
{3,4,5,6,7,8}
{2,3,4,5,6,7,8,9}
{}
{2,3,4,5,6,7}
Answer:
{3, 4, 5, 6, 7, 8}Step-by-step explanation:
{x|x < 9 and x > 2}= {3, 4, 5, 6, 7, 8}[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals) if the temperature function is given by
T(x, y)= 100/1+x^2+2y^2
Answer:
Step-by-step explanation:
Given that:
[tex]T(x,y) = \dfrac{100}{1+x^2+y^2}[/tex]
This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c
here c is the constant.
[tex]c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)[/tex]
By cross multiply
[tex]c({1+x^2+2y^2}) = 100[/tex]
[tex]1+x^2+2y^2 = \dfrac{100}{c}[/tex]
[tex]x^2+2y^2 = \dfrac{100}{c} - 1 \ \ -- (2)[/tex]
From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.
Now,
[tex]\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1[/tex]
This is the equation for the family of the eclipses centred at (0,0) is :
[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1[/tex]
[tex]a^2 = \dfrac{100}{c} -1 \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}[/tex]
Therefore; the level of the curves are all the eclipses with the major axis:
[tex]a = \sqrt{\dfrac{100 }{c}-1}[/tex] and a minor axis [tex]b = \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}[/tex] which satisfies the values for which 0< c < 100.
The sketch of the level curves can be see in the attached image below.
About 60% of U.S full-time college students drank alcohol within a one-month period. You randomly select six U.S. full-time college students. Find the probability that the number of U.S. full-time college students who drank alcohol within a one-month period is exactly two.
Answer:
13.82%
Step-by-step explanation:
Here we have proportion of U.S. full time college students= p = 0.60, Random sample = n = 6
Here we apply Binomial distribution .
p ( X =x ) = nCx * px * ( 1 -p) n-x
a) Exactly two.
P ( x = 2 ) = 6C2 * 0.602 * ( 1 -0.60) 6-2
= 0.1382
If 2/3 of the girls in class have brown eyes and 1/4 of the girls have blue eyes what fraction of the girls in class have neither blue or brown
Please Help! The point (8, -2) satisfies the equation of which line? (1) y+2=2(x+8) (2) y-2=2(x-8) (3) y+2=2(x-8) (4) y-2=2(x+8)
Answer:
(3) y+2=2(x-8)
Step-by-step explanation:
Substitute the point into the equation and see if it is true
(8,-2)
(1) y+2=2(x+8)
-2+2 = 2(8+8)
0 = 2(16)
False
(2) y-2=2(x-8)
-2-2 = 2(8-8)
-4 =2 (0)
False
(3) y+2=2(x-8)
-2+2 = 2( 8-8)
0 = 2(0)
True
(4) y-2=2(x+8)
-2-2 = 2(8+8)
-4 = 2(16)
False
Answer:
[tex]\boxed{y+2=2(x-8) }[/tex]
Step-by-step explanation:
[tex]x=8[/tex]
[tex]y=-2[/tex]
[tex]\sf Check \ the \ third \ option.[/tex]
[tex]-2+2=2(8-8)[/tex]
[tex]\sf Both \ sides \ must \ be \ equal.[/tex]
[tex]0=2(0)[/tex]
[tex]0=0[/tex]
PLEASE HELP! You do not have to answer all questions but can someone explain to me on where I am even suppose to begin? I don't even know how to answer a single one of these questions.
Step-by-step explanation:
For problems 1 through 15, evaluate the function at the given x value.
1. f(5) = 2(5) − 1 = 9
2. f(3) = 3² − 3(3) − 1 = -1
3. f(0) = 2(0) + 5 = 5
So on and so forth.
Then, match each answer with the corresponding letter.
The answer to #1 was 9. 9 corresponds to the letter A.
The answer to #2 was -1. -1 corresponds to the letter C.
The answer to #3 was 5. 5 corresponds to the letter P.
Finally, write each letter with its corresponding problem number.
So everywhere you see a 1, write A.
Everywhere you see a 2, write C.
Everywhere you see a 3, write P.
Continue until every blank has a letter and the problem is solved.
Answer:
For problems 1 through 15, evaluate the function at the given x value.
1. f(5) = 2(5) − 1 = 9
2. f(3) = 3² − 3(3) − 1 = -1
3. f(0) = 2(0) + 5 = 5
So on and so forth.
Step-by-step explanation:
A speedboat moves at a rate of 25 km/hr in still water. How long will it take
someone to ride the boat 87 km downstream if the river's current moves at a rate of
4 km/hr?
Answer:
3 hours
Step-by-step explanation:
Downstream, the speeds add up:
25 + 4 = 29 km/hIt will take:
87/29= 3 hrsTo ride 87 km.
What is the intersection of the lines given by 2y=-x+3 and -y=5x+1? Enter the answer as an ordered pair.
Answer:
(-5/9, 16/9)
Step-by-step explanation:
2y = -x + 3
-y = 5x + 1
To find the intersection, you need to substitute the y-value from the second equation into the first equation. Rearrange the second equation so that it is equal to y.
-y = 5x + 1
-1(-y) = -1(5x + 1)
y = -5x - 1
Substitute this equation into the y-value of the first equation.
2y = -x + 3
2(-5x - 1) = -x + 3
-10x - 2 = -x + 3
(-10x - 2) + 2 = (-x + 3) + 2
-10x = -x + 5
(-10x) + x = (-x + 5) + x
-9x = 5
(-9x)/(-9) = (5)/(-9)
x = -5/9
Plug this x value into one of the equations and solve for y.
2y = -x + 3
2y = -(-5/9) + 3
2y = 5/9 + 3
2y = 32/9
(2y)/2 = (32/9)/2
y = 32/18 = 16/9
The ordered pair is (-5/9, 16/9).
(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on this interval. Average slope: By the Mean Value Theorem, we know there exists at least one value c in the open interval (−4,9) such that f′(c) is equal to this mean slope. List all values c that work. If there are none, enter none . Values of c:
Answer: c = 4.97 and c = -1.97
Step-by-step explanation: Mean Value Theorem states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:
[tex]f'(c) = \frac{f(b)-f(a)}{b-a}[/tex]
So, for the function f(x) = [tex]2x^{3}-9x^{2}-60x+1[/tex] on interval [-4,9]
[tex]f'(x) = 6x^{2}-18x-60[/tex]
f(-4) = [tex]2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1[/tex]
f(-4) = 113
f(9) = [tex]2.(9)^{3}-9.(9)^{2}-60.(9)+1[/tex]
f(9) = 100
Calculating average:
[tex]6c^{2}-18c-60 = \frac{100-113}{9-(-4)}[/tex]
[tex]6c^{2}-18c-60 = -1[/tex]
[tex]6c^{2}-18c-59 = 0[/tex]
Resolving through Bhaskara:
c = [tex]\frac{18+\sqrt{1740} }{12}[/tex]
c = [tex]\frac{18+41.71 }{12}[/tex] = 4.97
c = [tex]\frac{18-41.71 }{12}[/tex] = -1.97
Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97
Find the greatest rational number r such that the ratios 8/15 ÷ r and 18/35 ÷ r are whole numbers?
The answer is "[tex]\bold{\frac{2}{105}}[/tex]", and the further calculation can be defined as follows:
When the "r" is the greatest common divisor for the two fractions.
So, we will use Euclid's algorithm:
[tex]\to \bold{(\frac{8}{15}) -(\frac{188}{35})}\\\\\to \bold{(\frac{8}{15} -\frac{188}{35})}\\\\\to \bold{(\frac{56-54}{105})}\\\\\to \bold{(\frac{2}{105})}\\\\[/tex]
this is [tex]\bold{(\frac{8}{15}) \ \ mod \ \ (\frac{18}{35})}[/tex]
we can conclude that the GCD for [tex]\bold{\frac{54}{105}}[/tex], when divided by [tex]\bold{\frac{2}{105}}[/tex], will be the remainder is 0. Rational numbers go from [tex]\bold{\frac{2}{105}}[/tex] with the latter being the highest.
So, the final answer is "[tex]\bold{\frac{2}{105}}[/tex]".
Learn more:
greatest rational number:brainly.com/question/16660879
Time-series data are often graphically depicted how?
A. Bar chart.
B. Histogram.
C. Line chart.
D. All of these choices are true.
Answer:
C. Line chart
Step-by-step explanation:
Answer:
B. Histogram
Step-by-step explanation:
Histogram uses time.
A vehicle purchased for $20700 depreciates at a constant rate of 5% . Determine the approximate value of the vehicle 10 years after purchase.
Answer:
I believe it is 12,393.86
The ratio of frogs to toads was 3 to 7. If there were 1280 frogs and toads in all, how many were frogs?
Answer:
348 frogs
Step-by-step explanation:
ratio = 3:7
total of ratio = 10
frogs = 3/10 × 1280 = 348 frogs
Answer:
let the ratio be 3x and 7x.
3x+7x=1280
10x=1280
x=128
Now
frogs =3x=3*128=384
toads =7x=7*128=896
I need help please, m bda =
And m bca =
Step-by-step explanation:
Exterior angle BOA = 250°
Interior angle BOA = 360°- 250° = 110°
Now,
(A) BDA = interior angle BOA / 2 = 55°( Property of circles)
(B) From the figure, we observe that AOBC is a cyclic quadrilateral (i.e. sum of opposite angles is 180°).
Therefore, BCA + BOA = 180°
BCA = 180° - 110° = 70°
Answer the questions attached about the given sequence: -33, -27, -21, -15, ...
Answer:
see below
Step-by-step explanation:
-33, -27, -21, -15,....
-33 +6 = -27
-27+6 = -21
-21+6 = -15
This is an arithmetic sequence
The common difference is +6
explicit formula
an=a1+(n-1)d where n is the term number and d is the common difference
an = -33 + ( n-1) 6
an = -33 +6n -6
an = -39+6n
recursive formula
an+1 = an +6
10th term
n =10
a10 = -39+6*10
= -39+60
=21
sum formula
see image
The sum will diverge since we are adding infinite numbers
Twice the difference of a number and 9 is 3. Use the variable b for the unknown number.
Answer:
b = 10.5
Step-by-step explanation:
2(b-9) = 3
then:
2*b + 2*-9 = 3
2b - 18 = 3
2b = 3 + 18
2b = 21
b = 21/2
b = 10.5
check:
2(10.5 - 9) = 3
2*1.5 = 3
In the morning, Sophie goes to the church then goes to the school. In the afternoon she goes to school to home. The map shows the distance between school and home as 5 cm. If every 4 cm on the scale drawing equals 8 kilometers, how far apart are the school and home?
Answer:
10 km
Step-by-step explanation:
Distance = 5 cm
4 cm = 8 km
In km, how far apart is school and home?
Cross Multiply
[tex]\frac{4cm}{8km}[/tex] · [tex]\frac{5cm}{1}[/tex]
Cancel centimeters
[tex]\frac{40(km)(cm)}{4cm}[/tex]
Divide
= [tex]\frac{40km}{4}[/tex]
= 10 km
Solve the equation for x. √x+5-3=4
Answer:
x=4
Step-by-step explanation:
To solve for x, we must get x by itself on one side of the equation.
[tex]\sqrt{x} +5-3=4[/tex]
First, we can combine like terms on the left side. Subtract 3 from 5.
[tex]\sqrt{x} +(5-3)=4[/tex]
[tex]\sqrt{x} +2=4[/tex]
2 is being added on to the square root of x. The inverse of addition is subtraction. Subtract 2 from both sides of the equation.
[tex]\sqrt{x} +2-2=4-2[/tex]
[tex]\sqrt{x} = 4-2[/tex]
[tex]\sqrt{x} =2[/tex]
The square root of x is being taken. The inverse of a square root is a square. Square both sides of the equation.
[tex](\sqrt{x} )^{2} =2^2[/tex]
[tex]x=2^2[/tex]
Evaluate the exponent.
2^2= 2*2 =4
[tex]x=4[/tex]
Let's check our solution. Plug 4 in for x and solve.
[tex]\sqrt{x} +5-3=4[/tex]
[tex]\sqrt{4} +5-3=4[/tex]
[tex]2+5-3=4[/tex]
[tex]7-3=4[/tex]
[tex]4=4[/tex]
Our solution checks out, so we know x=4 is correct.
A fair die is tossed once, what is the probability of obtaining neither 5 nor 2?
Answer:
4/6 or 66.666...%
Step-by-step explanation:
If you want to find the probability of obtaining neither a 5 nor a 2 you find how many times they occur and add them together in this case 5 occurs once and 2 also occurs once out of 6 numbers so 1/6 + 1/6 equals 2/6, you now know that 4/6 of them won't be a 5 nor a 2 and because it is a fair die the likelihood of it falling on a number is the same for all sides so the answer is 4/6 or 66.67%.
Need Help
Please Show Work
Answer:
-36
Step-by-step explanation:
3*12=36
she is going down (negative) so, it is -36
not sure if this is what you are asking for, if not try this
0-12-12-12=-36
Help me and I will for real give u brainleist
should be 2 3 andd 5
think of the - (- as a plus sign (this is what i was always taught) to add them so it would in turn be (-5) + 12 which equals 7 and choice 3 and 5 also equal this
a family spent $93 at a carnival.
*they spent $18 on tickets and $30 on food. they spent the rest of the money on games.
which equation can be used to to find "g", the amount of money used on games.
Answer: 93-(18+30)=g
93-48=g
45=g
Step-by-step explanation: yup
The answer is 93-18-30-g=0 or 18+30+g=93
what is 38.4 cm + 38.4 cm ???
Answer:
76.8 cm
Step-by-step explanation:
Answer:
76.8 cm
Step-by-step explanation:
38.4 cm + 38.4 cm = 76.8 cm
Find the sum of the even numbers between 199 to 1999
[tex]S_n=\dfrac{n(a_1+a_n)}{2}\\a_1=200\\a_n=1998\\n=?\\\\a_n=a_1+(n-1)d\\d=2\\1998=200+(n-1)\cdot2\\2n-2=1798\\2n=1800\\n=900\\\\S_{900}=\dfrac{900\cdot(200+1998)}{2}=450\cdot 2198=989100[/tex]
The Sum is 989100.
what is sum of Even numbers?The sum of even numbers formula is determined by using the formula to find the arithmetic progression. The sum of even numbers goes on until infinity. The sum of even numbers formula can also be evaluated using the sum of natural numbers formula. We need to obtain the formula for 2 + 4+ 6+ 8+ 10 +...... 2n.
The sum of even numbers = 2(1 + 2+ 3+ .....n). This implies 2(sum of n natural numbers) = 2[n(n+1)]/2 = n(n+1)
Given:
a1 = 200
an= 1998
So, using formula
S= n(a1 + an)/2
now,
d=2
an= a1+(n-1)d
1998= 200 + (n-1) 2
1998-200= (n-1)2
1798/2=n-1
n= 900
S900= 900( 200 + 1998)/2
=450*2198
= 989100
Hence, the sum is 989100.
Learn more about this concept here:
https://brainly.com/question/18837188
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