(1) A positive charge +3 C is separated from another positive charge of +5 C by a distance of 7m. What is the magnitude of the electric force between the two charges?
(a.) 1.9 × 10 to the 10th power N (b.) 2.8 × 10 to the 9th power N (c.) 2.1 N (d.) 0.31 N
(2) A molecule has 223 electrons and 218 protons. what is the net charge on the molecule ? (a.) 5 × 10 the the - 19th power C (b.) - 5 × 10 to the - 19th power C (c.) 8 × 10 to the - 19h power C (d.) -8 × 10 to the - 19th power C
(3) A negative charge of 2 × 10 to the negative 4 C and a positive charge of 8 × 10 to the negative 4 C are separated by a distance of 0.3 m. what is the magnitude of the force between the charges? (a.) 4800 N (b.) 1.78 × 10 to the - 6th power N (c.) 16000 N (d.) 0.001 N
(4) Which one of these statements is true of a neutral or charged object?
(a.) A neutral object does not have any charged particles in it.
(b.) A neutral object does not have any protons or electrons in it.
(c.) A neutral object has equal numbers of protons and electrons.
(d.) The protons and electrons in a neutral object do not have any charge.
THEY ARE ALL SEPARATE QUESTIONS
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1. The magnitude of the electric force between the two charges is 2.8×10⁹ N (Option B)
2. The net charge on the molecule is -8×10⁻¹⁹ C (Option D)
3. The magnitude of the force between the charges is 16000 N (Option C)
4. The correct statement is: A neutral object has equal numbers of protons and electrons. (Option C)
1. How to determine the forceCharge 1 (q₁) = +3 CCharge 2 (q₂) = +5 CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 7 mForce (F) =?F = Kq₁q₂ / r²
F = (9×10⁹ × 3 × 5) / (7)²
F = 2.8×10⁹ N
2. How to determine the net charge on the moleculeElectron = 223 electronsProton = 218 protonsNet Charge =?Charge = Proton - Electron
Charge = 218 - 223
Charge = -5 electrons
But
1 electron = 1.6×10⁻¹⁹ C
Thus,
Net Charge = -5 × 1.6×10⁻¹⁹ C
Net Charge = -8×10⁻¹⁹ C
3. How to determine the forceCharge 1 (q₁) = 2×10⁻⁴ CCharge 2 (q₂) = 8×10⁻⁴ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.3 mForce (F) =?F = Kq₁q₂ / r²
F = (9×10⁹ × 2×10⁻⁴ × 8×10⁻⁴) / (0.3)²
F = 16000 N
4. What is a neutral object?A neutral object is an object having equal numbers of protons and electrons. For example, an object with 4 protons and 4 electrons is said to be neutral as illustrated below
Electron = 4 electronsProton = 4 protonsNet Charge =?Charge = Proton - Electron
Charge = 4 - 4
Charge = 0 (neutral)
Thus, the correct statement about neutral object, given in the question is: A neutral object has equal numbers of protons and electrons (Option C)
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A block and tackle machine is used to raise 300 kg grand piano a vertical distance of 12.5 m. If the efficiency of the block and tackle machine is 0.80, how much work must the piano movers do in lifting the piano ? a. 45938 J b. 36750 J c. 29400 J d. 4688 J
The amount of work done by the piano mover in lifting the piano 45938 J (Option A)
What is efficiency?This can be defined as the capacity to achieve a given task with little or no waste. Mathematically, it can be expressed as
Efficiency = (output / input) × 100
How to determine the work inputMass (m) = 300 KgDistance (s) = 12.5 mEfficiency = 0.80Acceleration due to gravity (g) = 9.8 m/s²Output = mgs = 300 × 9.8 × 12.5 = 36750 JInput = ?Efficiency = output / input
Input = Output / efficiency
Input = 36750 / 0.8
Input = 45938 J
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A crowbar with the length of 200 cm is used to lift the load of 600 Newton . If the distance between fulcrum and load is 0.75 . Calculate Effort , Mechanical advantage and Velocity ratio
Answer:
a. Effort = 960 Newton
b. Mechanical advantage (M.A) = 0.625
c. Velocity ratio (V.R) = 1.67
Explanation:
Given the following data;
Load = 600 N
Length of crowbar = 200 cm
Length of load arm = 0.75 m
Conversion:
100 cm = 1 m
X cm = 0.75 m
Cross-multiplying, we have;
X = 0.75 * 100 = 75 cm
First of all, we would find the effort arm;
Effort arm = length of crow bar - length of load arm
Effort arm = 200 - 75
Effort arm = 125 cm
Next, we would determine the mechanical advantage (M.A) of the crow bar;
Substituting the values into the formula, we have;
M.A = 0.625
To find the effort of the crow bar;
Making "effort" the subject of formula, we have;
Effort = 960 Newton
Lastly, we would determine the velocity ratio (V.R);
V.R = 1.67
Answer:a. Effort = 960 Newton
b. Mechanical advantage (M.A) = 0.625
c. Velocity ratio (V.R) = 1.67
Explanation:
Why would an object have a much lower maximum speed falling through water than falling through air?
Answer:
Explanation:
when objects move through a fluid such as air or water the fluid exerts a frictional force on the moving object. the frictional force from fluid is called a drag force friction drag force causes objects to slow down as they move through a fluid such as air or water.