What is the freezing point of a solution made from 22.0 g of octane (c8h18) dissolved in 148.0 g of benzene? (for benzene, freezing point = 5.50°c; kf = 5.12°c/m)

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × [tex]10^{7}[/tex]

Universal gas constant (R) = 8.314 J/K• mol

Temperature = 25° C = 25 °C + 273 = 300 K

Formula used:

ΔG° = -RT㏑Kf

By putting the valur of R,T, Kf we get the value of ΔG°

ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × [tex]10^{7}[/tex]

ΔG° = -2494.2㏑ 1.7 × [tex]10^{7}[/tex] = -18034.18 J/mol

So, change in standard Gibbs's free energy is -18034.18 J/mol

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The "molecule a" referred to ATP in the equation.

So, option A is correct one.

The equation is given as,

[tex]C_{6} H_{12} O_{6}+ 6O_{2}[/tex] → [tex]6CO_{2}+ 6H_{2}O + ATP[/tex]

The above equation indicates the respiration activities in the plants.

The aerobic respiration takes place in the Mitochondria and which requires oxygen and glucose and produces carbon dioxide , water and energy.

The energy is in the form of  ATP. The pull form of ATP is adenosine triphosphate. The ATP is also called energy carrier because it found in the cells of the all living organism and this molecule carries energy.

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They must also possess a fixed crystalline structure (spatial arrangement of atoms and ions).

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Answer:

See attached image.

Explanation:

See attached image.

Remember to use the units in deciding steps to take.  Find the moles needed or delivered by using:

Molarity x Volume = moles  [(moles/L)*(L) = moles]

Molarity, M, is dedined as 1 mole/liter.  When working with a unit such as 6M, rewite it as 6 moles/liter, and then use unit conversions to guide how to find the solution, so to speak.

The vapor pressure of pure B is 1.77atm

Given:-

Vapor pressure of Pure A = 0.700atm

Mole of A = 0.650mole

Mole of B = 0.250mole

Dalton's law of partial pressures states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressures of all of the constituent gases.

So, Ptotal =  [tex]P_A + P_B[/tex]

According to Raoult's law, a solvent's partial vapor pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapor pressure times the mole fraction present in the solution.

So, Ptotal =  [tex]X_AP_A + X_BP_B[/tex]

Ptotal = 1atm

1atm = (0.650/0.650+0.250 X 0.700atm) + 0.250/0.650+0.250 X [tex]P_B[/tex]

1atm = 0.722 X 0.700atm + 0.278 X [tex]P_B[/tex]

1atm = 0.506atm + 0.278 X [tex]P_B[/tex]

1atm - 0.506atm =  0.278 X [tex]P_B[/tex]

0.494atm = 0.278 X [tex]P_B[/tex]

[tex]P_B[/tex] =  0.494atm / 0.278

[tex]P_B[/tex] = 1.77atm

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According to the Planck-Einstein relation, the energy of a photon emitted with a wavelength of 448 nm is 4.44 × 10⁻¹⁹ J.

A photon is a particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.

A photon is emitted with a wavelength (λ) of 448 nm. Given the speed of light (c) is 3.00 × 10⁸ m/s, we can calculate the frequency (ν) of the photon using the following expression.

ν = c/λ

ν = (3.00 × 10⁸ m/s ) / (4.48 × 10⁻⁷ m) = 6.70 × 10¹⁴ s⁻¹

We will use the Planck-Einstein relation, being Planck's constant h = 6.63 × 10⁻³⁴ J.s.

E = h × ν

E = (6.63 × 10⁻³⁴ J.s) × (6.70 × 10¹⁴ s⁻¹) = 4.44 × 10⁻¹⁹ J

According to the Planck-Einstein relation, the energy of a photon emitted with a wavelength of 448 nm is 4.44 × 10⁻¹⁹ J.

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Yes. Unsaturated hydrocarbon are more reactive than saturated hydrocarbons because it contains double bonds which can break and compounds can react with hydrogen.

Due to the double and triple bonds between carbon atoms in unsaturated hydrocarbons, which are weaker than the single bonds in saturated hydrocarbons due to the presence of weaker pi bonds, these unsaturated hydrocarbons are more reactive than single bonded carbon compounds and react more quickly when used in reactions.

For example, unsaturated hydrocarbons are used to make paint, lubricants, and insecticides, among other industrial products. They are utilised in numerous chemical reactions because they are reactive.

Therefore, Unsaturated hydrocarbon are more reactive than saturated hydrocarbons.

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The percent yield of the calcium hydroxide is 84.5%.

Stoichiometry enables us to obtain the mass of a substance form the equation of the reaction.

The equation of the reaction is;

CaCO3 + 2HCl -----> CaCl2 + CO2 + H2O

Number of moles of X = 40.0 grams/100 g/mol = 0.4 moles

Number of moles of HCl = 850/1000 * 1 M = 0.85 moles

If 1 mole of CaCO3 reacts with 2 moles of HCl

0.4 moles of  CaCO3 reacts with  0.4 moles  * 2 moles/1 mole

= 0.8 moles of HCl

Hence X is the limiting reactant.

The reaction is 1:1 then the amount of CO2  produced is 0.4 moles

Mass of CO2 = 0.4 CO2 * 44 g/mol = 17.6 g

2) The reaction equation is; 2NaOH + CaCO3 --->  Ca(OH)2 + Na2CO3

Number of moles of X = 25.0 grams/100 g/mol =  0.25 moles

Number of moles of NaOH= 40/1000 L * 2 M = 0.08 moles

If 1 mole of X reacts with 2 moles of NaOH

0.25 moles  reacts with   0.25 moles   * 2 moles /1 mole

= 0.5 moles

NaOH is the limiting reactant

2 moles of NaOH produces 1 mole of CO2

0.08 moles of NaOH produces 0.08 moles * 1 mole/2 moles

= 0.04 moles of CO2

Theoretical yield of CO2 =  0.04 moles of CO2 * 74 g/mol = 2.96  g

Percent yield = 2.5 g/ 2.96  g * 100

= 84.5%

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Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.

Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.

Thus;

Ca(CH3COO)2(aq)  ----> Ca^2+(aq) + 2CH3COO^-(aq)

It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

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Answer:

.577 atm

Explanation:

P1 V1  = P2 V2

RE-ARRANGE TO     P2 = P1 V1 / V2

Sub in the given values

  P2 = 1.15 * .414 / .825 = .577 atm

Answer:

False

Explanation:

Attractive forces between molecules in a solid are weaker than bonds between atoms in a molecule.

It takes much more energy to break intramolecular bonds (bonds within molecules) than it does to break intermolecular bonds (bonds between molecules). As a result, it is more difficult to break apart one molecule of a solid than it is to break the solid or separate the molecules from one another.

The 0.25 volume in liters of 1.0 M [tex]K_{2}CO_{3}[/tex] solution is required to provide 0.5 moles of [tex]K[/tex](aq).

Calculation,

The Potassium carbonate dissolves as follows:

[tex]K_{2}CO_{3}(s)[/tex] → [tex]2K(aq) +[/tex][tex]CO_{3}^{-2} (aq)[/tex]

The mole ratio is 1: 2

It means, the 1 mole [tex]K_{2}CO_{3}[/tex] required to form 2 mole of [tex]K[/tex](aq).

To provide 0.5 mole of [tex]K[/tex](aq) = 1 mole ×0.5 mole /2 mole required by [tex]K_{2}CO_{3}[/tex].

To provide 0.5 mole of [tex]K[/tex](aq) ,0.25 mole required by [tex]K_{2}CO_{3}[/tex].

The morality of  [tex]K_{2}CO_{3}[/tex] = 1 M = number of moles / volume in lit

The morality of  [tex]K_{2}CO_{3}[/tex] =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

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18.26 g of Al can be recovered.

The equation that follows is:

2Al₂O₃ → 2Al + 3O₂

The atomic mass of Al = 27 g

The molecular mass of Al₂O₃ = 102 g

From the stoichiometric equation, 102g of Al₂O₃ yields 54 g of Al

Therefore,

34.5 g of Al₂O₃ will give = [tex]\frac{54 (34.5)}{102}[/tex]

                                        = 18.26 g

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Imidazole's cyclic structure is aromatic and the lone pair present at the N₁ atom available for donation. hence, according to question N₁ is the most basic atom in the structure.

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Answer:

C) ZnCl2(s) + H2(g)

Explanation:

On reaction between Zn and HCl, Zn is more reactive than Hydrogen thus displacing it from HCl making a bond with two atoms of chlorine and releases hydrogen gas.

The equation of reaction

Zn(s) + HCl(aq) => ZnCl2(s) + H2(g).

Therefore, the required products are ZnCl2(aq) and H2(g).

A homogenous mixture has uniformly dispersed components while a heterogeneous mixture does not.

First of all, both homogenous and heterogenous mixtures consist of 2 or more non-reacting chemical components.

In homogenous mixtures, the chemical components are uniformly dispersed throughout the entire mixture.

In heterogeneous mixtures, the reverse is the case. The components are not uniformly dispersed. They are skewed to a particular side.

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Radiopaque refers to a White or light appearance of a structure on a processed radiograph. Radiolucent refers to a Dark appearance of a structure on a processed radiograph.

Materials that prevent electromagnetic radiation from passing through are referred to as radiodense or radiopaque, whereas materials that permit radiation to pass more readily are referred to as radiolucent. In contrast to radiolucent volumes, which appear significantly darker on radiographs, radiopaque volumes of material seem white.

It is the relative inability of radio waves and X-rays to flow through a certain substance. Radiodensity (or radiopacity) is opacity to the radio wave and X-ray portion of the electromagnetic spectrum.

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Answer:

according to the law,the pressure would increase if volume has been decreased.

Explanation:

the reason is that,pressure and volume are inversely proportional,if volume has been decreased that means the pressure would increase because decreased volume would create a sort of compacted situation for particles either of a liquid or gas,decreasing volume would bring these particle together, closer to each other because of decreased  and since the volume has decreased they dont have enough space,they would end up getting closer to each other most likely to collide, which drastically increase pressure .

Answer:

B. the amount of atoms you contain

According to the available literature, standard nanoparticle (NP) production processes make it especially challenging to reach the catalytically important and highly complicated intermetallic -brass crystal structure.

We present a straightforward and logical method for obtaining this phase in M-Zn (M = Pd, Cu, Ni) systems as silica-supported single-phase nanocrystals. This hybrid technique begins with the synthesis of supported M/SiO2 using typical methods (dry impregnation and strong electrostatic adsorption), followed by several hours of heating to high temperatures in the presence of a stoichiometric quantity of metallic Zn in an evacuated closed system.

Pd-Zn is by far the most common in catalytic applications and produces the smallest particle size (8 nm). We investigated the effect of various synthesis parameters on phase purity and particle size distribution in the case of synthesized -brass Pd-Zn/SiO2 supported catalysts and provided general guidelines for synthesis optimization.

Pd/SiO2 is transformed to -brass Pd-Zn/SiO2, resulting in a precipitous drop in CO adsorption and a 25 kJ/mol increase in the ethylene hydrogenation barrier, indicating that the catalytic active sites are significantly modified as a result of alloying. We anticipate that these catalysts will find use in a variety of Pd-catalyzed chemistries.

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The example that shows the correct way to set up the calculation will be the second example.

Mathematically:

  Number of moles = mass/molar mass

In this case, mass = 23.4 g and molar mass = 110.98 g/mol

Number of moles = 23.4/110.98 = 0.21 moles

Thus, the second example is the correct way.

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The oxidation-reduction reaction from the reactions above is

ZnS(s) + 2O2(g) ------ ZnSO4(s)

Oxidation-reduction or redox reaction is the type of chemical reaction in which oxidation states of substrate changes

So therefore, the oxidation-reduction reaction from the reactions above is

ZnS(s) + 2O2(g) ------ ZnSO4(s)

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For the mentioned reaction, the balanced chemical equation is:

KBr (aq) + AgNO3 (s) → KNO3 (aq) + AgBr(s)

The number written in front of the ion, atoms, and molecules in a chemical reaction so that each of the elements on both the sides of reactants and products of the equation gets balanced is known as the stoichiometric coefficient.

From the mentioned balanced equation, the stoichiometric coefficient before KBr is 1, AgNO3 is 1, KNO3 is 1, as well as before AgBr is also 1. Thus, it is clear that 1 mole of potassium bromide reacts with 1 mole of silver nitrate to produce 1 mole of potassium nitrate and 1 mole of silver bromide.

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Taking into account the Avogadro's Law, 0.600 moles occupies 1.200 L.

Avogadro's Law is a gas law that relates the volume and amount of gas at constant pressure and temperature.

Avogadro's law states that volume is directly proportional to the amount of gas: increasing the amount of gas will increase the volume, while decreasing the amount of gas will decrease the volume.

Mathematically, this law states that the ratio between the volume and the amount of gas is constant:

[tex]\frac{V}{n} =k[/tex]

Assuming that there is a certain amount of gas n1 that occupies a volume V1 at the beginning of the experiment, by varying the amount of gas to a new value n2, then the volume will change to V2, and the following is true:

[tex]\frac{V1}{n1} =\frac{V2}{n2}[/tex]

In this case, you know:

Replacing in Avogadro's Law:

[tex]\frac{0.800 L}{0.400 moles} =\frac{1.200 L}{n2}[/tex]

Solving:

[tex]n2x\frac{0.800 L}{0.400 moles} =1.200 L[/tex]

[tex]n2=\frac{1.200 L}{\frac{0.800 L}{0.400 moles} }[/tex]

n2= 0.600 moles

Finally, 0.600 moles occupies 1.200 L.

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A reasonable explanation for the disappearance of these fish is the high acidity affecting fish metabolism.

pH is a very important parameter to consider, as it has a direct effect on the metabolism and physiological processes of fish and other aquatic organisms. The pH tolerance range for fish is between 4.0 and 9.0, while the ideal index is between 6.5 and 8.0

With this information, we can conclude that The various fish species differ in terms of the best pH. The pH range between 6.5 – 9.0 is generally recommended for freshwater species. For marine species, the most recommended PH range is between 7.8-8.4.

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Functional groups include hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Regardless of the other atoms in a molecule, functional groups are particular groupings of atoms within molecules that have their own distinctive capabilities.

The prefixes di, tri, and tetra are applied when there are several substituents. Function-specific groups contain identifying suffixes. For instance, the parent chain name of alcohols has the suffix "ol" and a number indicating the location of the hydroxyl group. One is used to identify ketones.

If a compound has multiple functional groups, the highest priority functional group will be considered the "parent structure" and will define the "parent name"; the remaining functional groups will be considered the "substituents." The name of the parent structure is denoted by the "suffix," and the substituent is denoted by the "prefix."

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Answer:

pH = 13.41

Explanation:

You can calculate the pH using the following formula:

pH + pOH = 14

You can plug the given pOH into the equation and simplify to find the pH.

pH + pOH = 14

pH + 0.59 = 14

pH = 13.41

Answer:

positive

Explanation: