What is the frequency of the function f (x). f (x) = -2sin x/4 +3

Answer:

In question 20

B) the triangles are not similar

Step-by-step explanation:

u can see that 1 triangle length is 14 and other 49 and one triangle breath is 8 and other 28 so how they are same

Answer:

IN question 19

what is your question I can't understand

Using the corresponding angles postulate:

m∠3 = 150°

m∠5 = 150°

According to the corresponding angles postulate, corresponding angles, ∠3 and ∠5 are congruent to each other.

Thus, we would have the following equation:

m∠3 = m∠5

Plug in the values

50x - 100 = 25x + 25

50x - 25x = 100 + 25

25x = 125

x = 125/25

x = 5

m∠3 = 50x − 100 = 50(5) − 100 = 150°

m∠5 = 25x + 25 = 25(5) + 25 = 150°

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Part 1

[tex]f(a)=4-7a+16a^2[/tex]

Part 2

[tex]f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2[/tex]

Part 3

[tex]\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7[/tex]

Answer:

c

Step-by-step explanation:

Aight, let's hop to it:

So we got

[tex] \frac{5x}{45} = \frac{20}{36} = = > \\ \frac{x}{9} = \frac{5}{9} = = > \\ x = 5[/tex]

and boom

By trigonometric solution of triangles we conclude that the actor is staying at the balcony of the second floor.

This problem presents an application of trigonometric resolution of triangles to find the floor where the actor is in terms of the height of the building. Based on the picture seen in the image, we find that all known dimensions of the triangle , three angles and a side, are:

A = 140°, B = 30°, C = 10°, p = 6 m    

First, we must find the length of side AP by law of sines:

b / sin 30° = 6 / sin 10°

b = 6 × sin 30° / sin 10°

b ≈ 17.276 m

Second, the height of the building is found by trigonometric functions:

h = (17.276 m) · sin 40°

h ≈ 11.105 m

Therefore, the floor where the actor stays is:

3.8 + 3 · n = 11.105

3 · n = 7.305

n = 2.435

n = 2

By trigonometric solution of triangles we conclude that the actor is staying at the balcony of the second floor.

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Answer: x>2

Step-by-step explanation:

[tex]8(x-1) > 12-2x\\\\8x-8 > 12-2x\\\\10x-8 > 12\\\\10x > 20\\\\x > 2[/tex]

A patient should be given 8 and a half tablets and Approx. 8 days should the patient stay on the medication.

Given:

To find:

Solution:

If each tablet contains 7 mg and the doctor orders 60 mg of Benadryl.

Then the patient should be given 60/7 tablets i.e., 8 and a half tablets.

If the patient is only to take 1 tablet per day, then approx 8 days the patient we stay on the medication.

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From the calculation, the growth rate is 0.88.

To find the relative growth rate

P1 = Poe^rt

P2 = Poe^rt

Thus;

1920 = Poe^4r ------ (1)

1966080 =Poe^12r -------(2)

P2/P1 gives;

1966080/1920 = Poe^12r/Poe^4r

1024 = e^12r/e^4r

1024 =e^8r

1024 = (e^r)^8

2^10 = (e^r)^8

e^r = 2^1.25

e^r = 2.38

r = ln(2.38)

r = 0.88

The initial size of the culture is;

1920 = Poe^(0.88 * 4)

Po = 1920/e^(0.88 * 4)

Po = 57

The  expression for the exact number of bacteria after t hours is

P(t) = 57e^0.08t

The growth (in bacteria per hour) after 9.5 hours is

P(t) = 57e^(0.88 * 9.5)

P(t) = 243544

For the number to reach 72,000;

72,000 =  57e^0.88t

72,000/57 = e^0.88t

ln 126 = ln[e^0.88t]

4.8 = 0.88t

t = 4.8/0.88

t = 5.5 hours

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Answer: -5=x

Step-by-step explanation:

kmbtvonpvnp4tnv

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: scale \: \: factor = \cfrac{new \: \: measure}{original \: measure} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = \dfrac{6}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = 3[/tex]

so, correct choice is D

Answer:

connect the points (0, 3) and (4, 2)

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

An equation is an expression that shows the relationship between two or more variables and numbers.

A ball is thrown upward from the top of a building 15 meters high, at a velocity of 2.8m/sec. Hence:

s = -4.9t² + 2.8t + 15

The maximum height is at s'(t) = 0, hence:

-9.8t + 2.8 = 0

t = 0.295 s

s = -4.9(0.295)² + 2.8(0.295) + 15 = 15.4 m

The object reaches ground when s = 0, hence:

0 = -4.9t² + 2.8t + 15

t = 2.06 seconds

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

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Answer:

H = 12cm

b

I hope I was able to help

we conclude that 900 cubes enter in the given box.

We need to find the volumes of both figures.

The blocks are cubes of 2cm by 2cm by 2cm, then the volume of each block is:

[tex]V = (2cm)^3 = 8cm^3[/tex]

The box has dimensions of 10cm by 12cm by 60cm, then the volume is:

[tex]V = 10cm*12cm*60cm = 7,200 cm^3[/tex]

The number of cubes that enter in the box is N such that:

[tex]N*8cm^3 = 7,200cm^3[/tex]

Solving for N, we get:

[tex]N = 7200cm^3/8cm^3 = 900[/tex]

In this way, we conclude that 900 cubes enter in the given box.

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Answer: About 830 dollars

Step-by-step explanation: find 15% off on 897 then find 7.5 percent of 897, then add them together.

The vertex form of the equation is y = 3(x + 2)^2 - 5

The equation is given as:

y = 3x^2 + 12x + 7

Set to 0

3x^2 + 12x + 7 = 0

Subtract 7 from both sides

3x^2 + 12x = -7

Divide through by 3

x^2 + 4x = -7/3

-------------------------------------------------------------------

Take the coefficient of x

k = 4

Divide by 2

k/2 = 2

Square both sides

(k/2)^2 = 4

-------------------------------------------------------------------

So, we add 4 to both sides of x^2 + 4x = -7/3

x^2 + 4x + 4 = -7/3 + 4

Express as perfect square

(x + 2)^2 = -7/3 + 4

Multiply through by 3

3(x + 2)^2 = -7 + 12

Evaluate

3(x + 2)^2 = 5

Subtract 5 from both sides

3(x + 2)^2 - 5 = 0

Rewrite as

y = 3(x + 2)^2 - 5

Hence, the vertex form of the equation is y = 3(x + 2)^2 - 5

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The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

The function is given as:

f(x) = 3x^6 + 4x^3 -2x^2 + 4

The leading coefficient of the function is:

p = 3

The constant term is

q = 4

Take the factors of the above terms

p = 1 and 3

q = 1, 2 and 4

The possible zeros are then calculated as:

[tex]\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}[/tex]

So, we have:

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}[/tex]

Expand

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}[/tex]

Solve

[tex]\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

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See below for how the domain and the range are calculated

Function, y = -x^4 + 4

The function is given as:

y = -x^4 + 4

See attachment for the graph

From the attached graph, we have:

Function, y = 2x^3 - 1

The function is given as:

y = 2x^3 - 1

See attachment for the graph

From the attached graph, we have:

Function, y = ∛(2x + 8)

The function is given as:

y = ∛(2x + 8)

See attachment for the graph

From the attached graph, we have:

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Answer:

1

Step-by-step explanation:

This is a U shaped graph, so the shape is a parabola

Eccentricity of any parabola is 1.

Answer:

Step-by-step explanation:

Just for some extra confrontation indeed the correct answer is 1.

Answer:

>>   [tex]6\frac{5}{18}[/tex]

Step-by-step explanation:

1) Add the whole numbers first.

[tex]5+\frac{5}{6} +\frac{4}{9}[/tex]

2) Find the Least Common Denominator (LCD) of [tex]\frac{5}{6} ,\frac{4}{9}[/tex] . In other words, find the Least Common Multiple (LCM) of [tex]6,9[/tex].

Method 1: By Listing Multiples

1. List the multiples of each number.

Multiples of 6 : 6, 12, 18, ...

Multiples of 9 : 9, 18, ...

2. Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 18

3. Make the denominators the same as the LCD.

[tex]5+\frac{5\times 3}{6\times 3}+\frac{4\times 2}{9\times 2}[/tex]

4. Simplify. Denominators are now the same.

[tex]5+\frac{15}{18}+\frac{8}{18}[/tex]

5.  Join the denominators.

[tex]5+\frac{15+8}{18}[/tex]

6. Simplify.

[tex]5+\frac{23}{18}[/tex]

7. Convert [tex]\frac{23}{18}[/tex] to mixed fraction.

[tex]5+1\frac{5}{18}[/tex]

8. Simplify.

[tex]6\frac{5}{18}[/tex]

Decimal Form: 6.277778

Cheers.

The addition of 3 5/6 + 2 4/9  is 113/18

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

3 5/6 + 2 4/9

Now, writing it into normal fraction

3 5/6 + 2 4/9

= 23/ 6 + 22/9

= 23/6 x 3/3 + 22/9 x 2/2

= 69/ 18 + 44/18

= 113/18

Hence, the addition is 113/18

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Answer:

A.

Step-by-step explanation:

1) according to the given graph, the real roots are: -1 and 4, it means the given expression can be evaluated using (x+1)(x-4)=x²-3x-4.

2) if to divide the given expression by (x²-3x-4), then

x⁴-7x³+23x²-29x-60=(x²-3x-4)(x²-4x-15), where

3) x=-1;4 - real roots, and

[tex]x=2^+_-i\sqrt{11} \ -nonreal \ roots.[/tex]

Answer:

(2, -11)

Step-by-step explanation:

(x + 3, y + 2) = (5, -9)

x + 3 = 5

y + 2 = -9

x = 2

y = -11

Answer:

Step-by-step explanation:

8x + 2(x - 7) = 7x + 3x - 14

8x + 2x - 14 = 7x + 3x - 14                 Distributive property.

10x - 14 = 10x - 14                              Combine the like terms.

-14 = -14                                             Subtraction.

0 = 0                                                  Addition.

Since the statement 0 = 0 is true regardless of the value of x, there is infinitely many solutions.

By using the concept of linear progression and some algebraic handling, we conclude that Joe will earn an amount of $ 31 700 in the 14th year.

According to the statement, we have a case of linear progression as income increases at same rate in time. Linear progressions are described by this formula:

c' = c + r · t     (1)

Where:

First, we calculate the increase rate:

r = (29 600 - 22 600)/10

r = 700

Now we proceed to find when Joe will earn an annual income of $ 31 700:

31 700 = 22 600  + 700 · t

t = 13

By using the concept of linear progression and some algebraic handling, we conclude that Joe will earn an amount of $ 31 700 in the 14th year.

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The solution set of the inequalities y ≤ x² – 3 and y > –x² + 2 is the darker region shown in the graph.

An equation is an expression that shows the relationship between two or more variables and numbers.

Inequality is an expression that shows the non equal comparison of two or more numbers and variables

The solution set of the inequalities y ≤ x² – 3 and y > –x² + 2 is the darker region shown in the graph.

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The graphs of f(x) and g(x) are transformed function from the function y = x^2 and the solution of the set of inequalities is (±1.581, -0.5)

The complete question is in the attached image (the first graph)

From the graph, we have:

f(x) = x^2 - 3 and g(x) = -x^2 + 2

To derive y ≤  x^2 - 3, we simply change the equality sign in the function f(x) to less than or equal to.

To derive y > -x^2 + 2, we simply change the equality sign in the function g(x) to greater than

The inequalities of the graphs become

y ≤ x^2 - 3 and y > -x^2 + 2

From the graph of the above inequalities (see attachment 2), we can see that the curves of the inequalities intersect at (±1.581, -0.5)

Hence, the solution of the set of inequalities is (±1.581, -0.5)

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