What is the length of the apothem of the regular pentagon shown below? Round to one decimal place

What Is The Length Of The Apothem Of The Regular Pentagon Shown Below? Round To One Decimal Place

Answers

Answer 1

Answer:

A

Step-by-step explanation:

Draw a diagonal line connecting the centre to a vertex at the bottom. This makes a triangle. It is a regular pentagon so the base of that triangle is 7.6 / 2, which is 3.8. You also know that the angle from the apothem to the base is 90 degrees. You also know that you could split the centre angle into 5 triangles. 360 / 5 = 72 and we have half of it so it is 36 degrees.

Let's see what we have so far:

The base of the triangle is 3.8

The angle at the bottom is 90

The angle at the top is 36

We now have the tan and the opposite and we need the adjacent so rearrange for adjacent.

This gives you adjacent = opposite / tan(angle)

adjacent = 3.8 / tan(36)

adjacent = 5.2m


Related Questions

Christine is putting money into a savings account. She starts with $650 in the savings account, and each week she adds $60. Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Christine has been adding money. Write an equation relating S to W. Then use this equation to find the total amount of money in the savings account after 11 weeks.

Answers

Total amount of money in the savings account after 11 weeks is $1310.

Total money in the account =

 Initial Money + Money added per week x Number of weeks

Given:

Initial Money = $650

Money added per week = $60

Total money in the account = S

Number of weeks = W

Substituting it in the above equation we get,

S = $650 + $60xW                                          (General Equation)

Total amount of money in the savings account after 11 weeks

S = $650 + $60x11

S = $650 + $660

S = $1310

Thus total amount of money in the savings account after 11 weeks is $1310.

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This table reflects the result of a survey conducted in a town to find out the number of cars of a particular color.

Which of the following ranges would be appropriate to use in order to represent the numerical data on the vertical axis of a Bar Graph?

A. 10 to 20
B. 20 to 100
C. 0 to 50
D. 0 to 30

Answers

the range that would be the most appropriate to represent the numerical data on the vertical axis is B. 20 to 100.

what range would be most appropriate?

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

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The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

Bar graph :

Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data

The range that would be the most approximately to represent the numerical data on the vertical axis is B. 20 to 100.

because

it is not possible to have zero number of cars that have a particular color,

in That way, we can eliminate options C and D .

in option A the range is too small which is not possible.

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

A sample of a radioactive isotope had an initial mass of 440 mg in the year 1990 and decays exponentially over time. A measurement in the year 1998 found that the sample's mass had decayed to 40 mg. What would be the expected mass of the sample in the year 2001, to the nearest whole number?

Answers

Using an exponential function, the expected mass of the sample in the year 2001 would be of 16 mg.

What is the exponential function for the amount of a substance?

The function is:

[tex]A(t) = A(0)e^{-kt}[/tex].

In which:

A(0) is the initial amount.k is the decay rate.

The information given is as follows:

A(0) = 440, A(8) = 40.

Hence:

[tex]A(t) = A(0)e^{-kt}[/tex].

[tex]40 = 440e^{-8k}[/tex].

[tex]e^{-8k} = 0.09090909[/tex]

[tex]\ln{e^{-8k}} = \ln{0.09090909}[/tex]

[tex]-8k = \ln{0.09090909}[/tex]

[tex]k = -\frac{\ln{0.09090909}{8}[/tex]

k = 0.29973691

Then the function is:

[tex]A(t) = 440e^{-0.29973691t}[/tex]

2001 is 11 years after 1990, hence the amount is:

[tex]A(11) = 440e^{-0.29973691 \times 11} = 16[/tex]

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Linda is training to be an assistant at the local animal shelter. To become an assistant she needs to complete 48 h of training. Linda keeps a graph of the number of hours of training left to be completed. What is the rate of change of the number of hours remaining with respect to the number of days? Remember to include units.

Answers

The equation between the number of days remaining and number of hours is given as y= -5x+50.

How to illustrate the equation?

Let y be the number of days remaining and x be the no.of hours.

From the graph the slope of the line is given by m.

m=(y2 - y1)/(x2 - x1)

m=(30 - 40)/(4 - 2)

m= -10/2 = -5.

The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.

Therefore the equation between the no.of days remaining and no.of hours is given by

y=mx +c.

y=-5x+c

Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,

50= -5(0)+c

c=50.

Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.

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Grocer Edwards graphs the relationship between the
diameter and heights of different cans in his store. The
graph is below.
Height (cm)
18-
D
16+
14+
12+
10+
8+
6+
4+
2+
2
Choose 1 answer:
4

6
8
A

10 12
What is the meaning of point A?

Diameter (cm)

14 16 18
A can with an 10 cm diameter has an 18 cm height.
A can with an 18 cm diameter has an 11 cm height.
A can with an 11 cm diameter has an 18 cm height.
A can with an 18 cm diameter has an 10 cm height.

Answers

Considering the given graph, the meaning of point A is given by:

A can with an 11 cm diameter has an 18 cm height.

What does the graph gives?

The graph gives the height of the can as a function of the diameter. Both measures are in cm. Then, the axis are given as follows:

The x-axis is the diameter.The y-axis is the height.

Point A has coordinates (11,18), that is, x = 11, y = 18, hence the interpretation is:

A can with an 11 cm diameter has an 18 cm height.

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Answer:

A

Step-by-step explanation:

just took the quiz and can confirm the other guy is valid :D

Which choice is a term in this expression -3x - 7(x+4)

Answers

-3x is a term in the expression -3x - 7(x+4)

How to determine the term?

The expression is given as:

-3x - 7(x+4)

Considering the following expression

Ax + B(x  - b)

The terms in the expressions are Ax and B(x  - b)

This means that -3x is a term in the expression -3x - 7(x+4)

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In 2016, Alberta had about 4.2 million people.
Assuming they follow the same population
growth rate, it is predicted they will have 6.65
million people in 20 years. At what rate is the
province's population growing?

Answers

The province's population is growing at the rate of  58.34 %

Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. The calculation for ROC is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.

Given:

Initial Population = 4.2 million

Population after 20 years = 6.65 million

Change in population = 6.65 - 4.2 = 2.45 million

Rate at which the province's population growing is

= [tex]\frac{Change in population}{Inital Population}[/tex] x100 %

= [tex]\frac{2.45}{4.2}\\[/tex] x 100%

= 58.34 %

Thus the province's population is growing at the rate of  58.34 %

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The length of a rectangle is two more than double the width. If the perimeter is 100 inches, find the
dimensions.

Answers

Answer:

width = 34 inches

length = 16 inches

Step-by-step explanation:

Given:

1.)The length of a rectangle is two more than double the width

2.)The perimeter is 100 inches

Let's analyze the first part,

The length is 2 more than double the width so if we let x represent the length the width would be 2x + 2

Now the second part,

the perimeter is calculated by the following formula:

2*(w+l)

(w: width, l: length)

2*(x+2x+2) first do inside the parenthesis by adding like terms

x+2x+2 = 3x + 2 now multiply both terms with 2

2*(3x+2) = 6x + 4 this is the perimeter of the rectangle, now write another equation using this

6x + 4 = 100 subtract 4 from both sides

6x = 96 divide both sides by 6

x = 16 this the length and the width would be

2x + 2 = 2*16 + 2 = 34

Compare the monthly payments and total loan costs for the following pairs of loan options. Assume that both loans are fixed rate and have the same closing costs. You need a $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5%. Find the monthly payment for each option. The monthly payment for option 1 is S The monthly payment for option 2 is S (Do not round until the final answer Then round to the nearest cent as needed) Find the total amount paid for each option The total payment for option 1 is S The total payment for option 2 is S (Use the answers from the previous step to find this answer Round to the nearest cent as needed) Compare the two options Which appears to be the better option? OA Option 2 will always be the better option B. Option 1 is the better option, but only if the borrower plans to stay in the same home for the entire term of the loan OC. Option 1 will always be the better option OD. Option 2 is the better option, but only if the borrower can afford the higher monthly payments over the entire term of the loan 0​

Answers

The monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be better option.

Given that for $200,000 loan Option 1 is a 30-year loan at an APR of 10% Option 2 is a 15-year loan at an APR of 9.5%.

A concept that implies that the future value of money will be lower than its present value due to several factors such as inflation is known as TVM(time of value money).

Monthly Payments

Option 1

Loan Amount = $200,000

Number of payments = 30×12 = 360

Monthly interest rate = 10%/12 = 0.008333333

Monthly payment = Loan amount (1+ monthly interest rate)ⁿ×monthly interest rate/[(1+monthly interest rate)ⁿ- 1]

Monthly payment=200,000×(1+0.008333333)³⁶⁰×(0.008333333)/[(1+0.008333333)³⁶⁰-1]

Monthly payment=33062.328/18.83739

Monthly payment=$1755.144

Option 2

Loan Amount = $200,000

Number of payments = 15 x 12=180

Monthly interest rate = 9.5%/12=0.00792

Monthly payment = 200,000(1+0.00792)¹⁸⁰(0.00792)/[(1+0.00792)¹⁸⁰-1]

Monthly payment=6553.096/3.137

Monthly payment=$2088.97

Total Payments

Option 1

As we've found out the monthly payments, we now need to multiply it by the number of months.

$1755.144×360 = $631851.84

Option 2

$2088.97×180 = $376014.6

Conclusion

Option 2 will always be the better option economically as it saves $255837.24 ($631851.84 - $376014.6) in total payments.

Hence, For $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5% is the monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be the better option.

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A sports center offers party packages. They advertise a flat rate of $325 for the first 10 guests. They charge $15 per person for each additional guest. A formula for the cost of the party is:

C = 325 + 15p
where p is the number of guests more than 10. (For example, if 12 people come to the party, p = 2.) Suppose you want to have a huge birthday celebration this year. However, you have budgeted $600 for your party. How many guests can you invite if you decide to have your party at this sports center?

Answers

Using the given linear equation, we conclude that you can invite a maximum number of 21 guests.

How many guests can you invite if you decide to have your party at this sports center?

Here the function is:

C(p) = 325 + 15*p

Where p is the number of guests minus 10, now we know that your budget is $600, then the maximum value of guests allowed is such that:

C(p) = 600 = 325 + 15*p

Now we can solve this equation for p:

600 - 325 = 15*p

275 = 15*p

175/15 = p = 11.67

Then the maximum whole number that p can take is p = 11

This means that the maximum number of guest that you can have is:

Guests = 10 + p = 10 + 11 = 21.

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look at the picture

Answers

Answer:

C

Step-by-step explanation:

x²-9x<-8

x²-9x+(-9/2)²<-8+(-9/2)²

(x-9/2)²<-8+81/4

(x-9/2)²<(-32+81)/4

(x-9/2)²<49/4

|x-9/2|<7/2

-7/2<x-9/2<7/2

add 9/2

9/2-7/2<x-9/2+9/2<7/2+9/2

2/2<x<16/2

1<x<8

A bank charges 12% simple interest p.a. on a cash loans for R10 000,must repay the loan over 4 years.

Calculate the interest which is gonna be paid to the loan?

Answers

Answer:

$4800

Step-by-step explanation:

Let's use the simple interest formula, P(1+rt), to find the final amount of the loan

10000(1+.12*4) = 14800, the final amount

14800 - 10000 = 4800 total in interest

-275+156-(-293)-157 = 17


ME PUEDEN DAR EL PROCEDIMIENTO

PLIS

Answers

The procedure for solving -275+156-(-293)-157 = 17 is to follow bodmas operation

Evaluation

-275+156-(-293)-157 = 17

Using BODMAS

b - bracketo - offd - divisionm - multiplicationa - additions - subtraction

-275+156-(-293)-157 = 17

= -275 + 156 + 293 - 157

= 17

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Consider the function f denoted by:
[tex]f(x) = ln(x) [/tex]
Find the nth derivative of f(x) denoted by:
[tex]f {}^{(n)} (x ) [/tex]
Irrelevant answers will be reported immediately.

Answers

Step-by-step explanation:

Let take the first derivative

[tex] \frac{d}{dx} ln(x)) = x {}^{ - 1} [/tex]

The second derivative

[tex] - {x}^{ - 2} [/tex]

The third derivative

[tex]2 {x}^{ - 3} [/tex]

The fourth derivative

[tex] - 6 {x}^{ - 4} [/tex]

The fifth derivative

[tex]24 {x}^{ - 5} [/tex]

Let create a pattern,

The values always have x in it so

our nth derivative will have x in it.

The nth derivative matches the negative nth power so the nth derivative so far is

[tex] {x}^{ - n} [/tex]

Next, lok at the constants. They follow a pattern of 1,2,6,24,120). This is a factorial pattern because

1!=1

2!=2

3!=6

4!=24

5!=120 and so on. Notice how the nth derivative has the constant of the factorial of the precessor

so our constant are

[tex](n - 1)[/tex]

So far, our nth derivative is

[tex](n - 1)!x {}^{ - n} [/tex]

Finally, notice for the odd derivatives we are Positve and for the even ones, we are negative, this means we are raised -1^(n-1)

[tex] - 1 {}^{n -1} (n - 1) ! {x}^{-n} [/tex]

That is our nth derivative

simplify (4a) × (3b)​

Answers

Answer:

Step-by-step explanation:

hello :

(4a) × (3b)​ =12ab

For which interval is the function constant? (−4,0) begin ordered pair negative 4 comma 0 end ordered pair (4,∞) left parenthesis 4 comma infinity right parenthesis (0,4) begin ordered pair 0 comma 4 end ordered pair (−∞,−4)

Answers

Answer: (-4, 0)

Step-by-step explanation: I just took the quiz and got it correct!

The function is constant on the intervals: (-4, 0), (4, ∞), and (0, 4). Within these intervals, the function's output remains the same for all values of x in each interval.

To determine the interval in which the function is constant, we need to examine the given ordered pairs (x, y) and check if the function's output (y-values) remains the same within that interval.

Let's analyze each interval:

1. (-4, 0): This interval represents all x-values greater than -4 and less than 0. In this interval, the function takes the value 0 for all x-values in the interval. Therefore, the function is constant (equal to 0) within this interval.

2. (4, ∞): This interval represents all x-values greater than 4. In this interval, the function's output is given as "∞" (infinity) for all x-values in the interval. The function is constant (equal to infinity) within this interval.

3. (0, 4): This interval represents all x-values greater than 0 and less than 4. In this interval, the function takes the value 4 for all x-values in the interval. Therefore, the function is constant (equal to 4) within this interval.

4. (-∞, -4): This interval represents all x-values less than -4. In this interval, the function's output is not specified or may not be constant. The information provided does not give us the exact function to determine the output for all x-values in this interval.

The function is constant on the intervals: (-4, 0), (4, ∞), and (0, 4). Within these intervals, the function's output remains the same for all values of x in each interval. However, we don't have enough information to determine if the function is constant on the interval (-∞, -4).

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According to the general equation for conditional probability, if P(AB) = and P(B) = 2, what is P(A/B)? 12 O A. 3/ О в. 4 O c. 2/ C. 5 O D. 9

Answers

Using conditional probability, it is found that:

[tex]P(A|B^\prime) = \frac{1}{3}[/tex]

What is Conditional Probability?

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

P(B|A) is the probability of event B happening, given that A happened.[tex]P(A \cap B)[/tex] is the probability of both A and B happening.P(A) is the probability of A happening.

For this problem, we are given that:

[tex]P(B^\prime) = 1 - P(B) = 1 - \frac{1}{3} = \frac{2}{3}[/tex].[tex]P(A \cap B^\prime) = \frac{2}{9}[/tex]

Then:

[tex]P(A|B^\prime) = \frac{P(A \cap B^\prime)}{P(B^\prime)}[/tex]

[tex]P(A|B^\prime) = \frac{\frac{2}{9}}{\frac{2}{3}}[/tex]

[tex]P(A|B^\prime) = \frac{1}{3}[/tex]

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Proofs and congruent triangles 2 forgot to put images last time 50 points ( serious answer or 1 star and report ) ( YOU NEED TO CHECK MY ANSWERS PLEASE )

Answers

Answer:

Step-by-step explanation:

Q3 asks for reasons of statements in a theorem proof.

1 Given is correct

2 Definition of right angle is correct

3 should be sum of interior angles in a triangle

4 is substitution

5 subtracting 90degree from left and right hand side

6 is definition of complementary

Given AABC shown on the coordinate plane below.
AA"B"C" = Ro 90⁰(T(-4,3)(ABC))
Draw AA"B"C" if
You may use different colors for the separate transformations. Indicate your final answer.
Feel free to use the Dynamic Geometry Tool to complete the transformations.
02
PENCIL

Answers

The triangle ABC is shifted upwards by 3 units and towards the left by 4 units. After translation again it is rotated 90° counterclockwise. All these transformations are shown in the graph below.

What are transformation rules?

The following are the basic transformation rules:

Translation: (x, y) → (x + a, y + b) or (x, y) → (x - a, y - b)Reflection over x-axis: (x, y) → (x, -y)Reflection over y-axis: (x, y) → (-x, y)Rotation 90°(counterclockwise): (x, y) → (-y, x)Rotation 180°: (x, y) → (-x, -y)

Calculation:

A triangle ABC is given in the graph with vertices as

A(-1, 2), B(1, 4), and C(4, -1)

The transformation to be applied is A"B"C" = Ro 90°(T(-4,3)(ABC))

Where -

T(-4, 3) represents the translation of 3 units upwards and 4 units towards the left

R0 90° represents the rotation of 90° (counterclockwise) of the translated triangle.

Step 1: applying translation (-4, 3):

The new vertices of the triangle ABC translated by (-4, 3) units are represented by A'B'C'. They are:

A' - (-1 - 4, 2 + 3) = (-5, 5)

B' - (1 - 4, 4 + 3) = (-3, 7)

C' - (4 - 4, -1 + 3) = (0, 2)

These are shown in the graph below.

Step 2: applying rotation 90° (counterclockwise): (x', y') → (-y, x)

Now the new triangle formed after the translation is ΔA'B'C'

So, on applying rotation, the vertices are changed to,

A'(-5, 5) → A"(-5, -5)

B'(-3, 7) → B"(-7, -3)

C'(0, 2) → C"(-2, 0)

These are shown in the graph below.

Therefore, Δ ABC → Δ A'B'C' (by T(-4, 3)) → Δ A"B"C" (by Ro 90°) i.e.,

Δ A"B"C" = Ro 90°(T(-4, 3) ABC).

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The magnitude, M, of an earthquake is represented by the equation M=2/3logE/E0 where E is the amount of energy released by the earthquake in joules and E0=10^4.4 is the assigned minimal measure released by an earthquake. Which shows a valid step in the process of calculating the magnitude of an earthquake releasing 2.5 • 10^15 joules of energy?

2.5•10^15 = 2/3logE/10^4.4
10^4.4=2/3logE/2.5•10^15
M=2/3log(9.95•10^9)
M=2/3log(2.55•10^10)
M=2/3log(9.95•10^10)

Answers

The magnitude of an earthquake releasing 2.5 * 10¹⁵ Joules of energy is 7.33

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that:

M = (2/3) * log (E/E₀)

Where M is the magnitude, E is the amount of energy and E₀ = 10^4..4

For E = 2.5 * 10¹⁵:

M = (2/3) * log (2.5 * 10¹⁵/10^4.4)

M = 7.33

The magnitude of an earthquake releasing 2.5 * 10¹⁵ Joules of energy is 7.33

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What is the domain and range of the quadratic function given by the equation /(x) = 2(x-4)] - 2

Answers

The domain of the function is the set of all real numbers and the range of the function is the set of all values greater than -2

How to determine the domain and the range?

The function is given as:

f(x) = 2(x -4)^2 - 2

A quadratic function can take any real number as its input.

So, the domain of the function is the set of all real numbers

The vertex of the above function is:

Vertex = (4, -2)

And the leading coefficient is:

a = 2

The y value of the vertex is;

y = -2

Because the value of a is positive, then the vertex is a minimum.

This means that the range of the function is the set of all values greater than -2

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The hospital in patient admission rate for employees of the ramsey

Answers

The computation shows that the the hospital in-patient admission rate for the employees of the Prendergast Corporation is 104.5 admissions per 1000 employees.

How to calculate the value?

The in-patient admission rate for Ramsey Manufacturing company = 100 admissions per 1000 employees.

It is given that the in-patient rate of Prendergast will be 10% higher than Ramsey's.

So, in-patient rate of Prendergast:

= 100 + 10% of 100

= 110 admissions

Now, it is also given that out of total in-patients, 5% are for tonsillectomies (which are not in-patient).

So, in-patient admission rate for Prendergast:

= 110 - 5% of 110

= 110 - 5.5

= 104.5 admissions per 1000 employees

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Complete question:

The hospital in-patient admission rate for employees of the Ramsey Manufacturing Company is 100 admissions per 1000 employees per year.

The Prendergast Corporation has older employees and is told that its hospital in-patient admission rate will be 10% higher than Ramsey’s. At the same time, however, all tonsillectomies will be done in the hospital’s outpatient department instead of requiring the patient to be admitted as an in-patient. Given that 5% of all in-patient admissions are for tonsillectomies, what is the hospital in-patient admission rate for the employees of the Prendergast Corporation?

A. 110.0 B. 115.0 C. 109.5 D. 100.0 E. 104.5 F. 117.0

solve asap please!!!

Answers

ANSWER: 39.7%

Explanation:
1. Determine your chain's density first.
Mass / volume equals density.

volume equals water displaced ml = 20 ml
- 15 ml = 5 ml where volume = Volume of Final Level of Water - Initial Level of Water
Mass = 66.7 g

Density is equal to 66.7g/5 ml, or 13.34 g/ml.


2. Next, calculate the chain's density as the weighted average of its component densities.

Divided by the mass of the chain, the formula is: mass of gold, density of gold, mass of other metals, density of other metals.

If x is the weight of gold, then 66.7 - x is the weight of the other metals:

19.3 - 2 + 9.7 . (66.7
66.7
= 13.34
19.32 + 635.66 - 9.72
= 889.778
9.62
254.118
2 = 26.47
Then, there are 26.47 grams of gold in 66.7
grams of chain, which yields a percentage of:
(26.47 / 66.7) × 100 = 39.7%

Sand will be placed under a circular pool with a diameter of 20 feet. The sand depth should be 2 inches. How many cubic feet of sand are needed?

Answers

you need 628 square feet of sand.

How many cubic feets of sand are needed?

Here we need to find the volume of the sand needed.

The volume filled with sand will be a cylinder of diameter of 20ft, and a height of 2 inches.

First, the radius is half of the diameter, then:

R = 20ft/2 =10ft

Remember that:

1ft= 12in

Then:

R = 10ft = 10*(12 in) = 120 in

And remember that the volume of a cylinder of radius R and height H is:

[tex]V = pi*R^2*H[/tex]

Where pi = 3.14

Then we have:

[tex]V = 3.14*(120 in)^2*2in = 90,432 in^2[/tex]

To get that in feets, we need to divide by 12 squared, then:

[tex]90,432 in^2 = 90,432ft^2/(12^2) = 628 ft^2[/tex]

So you need 628 square feet of sand.

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Complete this activity.

If the first element of the following pairs of numbers is a measure of hours and the second element is a measure of distance in miles, write an equation for D.

B = {(t, D ): (1, 50), (2, 100), (3, 150), . . .}

D =

t /2
50 t
50/ t

Answers

Answer:

D = 50t

Step-by-step explanation:

we see, with every additional hour the distance increases by 50.

that means in general that the number of hours are multiplied by 50 to get the distance.

in other words, this just calculates for a vehicle going constantly 50 miles per hour the distance it is traveling.

if A and B are events with P(A) = 0.2, P(B) = 0.8, P(A and B) = 0.07, find P(A or B)

Answers

Answer:  0.93

Work Shown:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.2 + 0.8 - 0.07

P(A or B) = 0.93

Which function is graphed? ​

Answers

Answer: A

Step-by-step explanation:

The parabola has an open hole at x=3 and the line has a closed hole at x=3, so there should be [tex]x < 3[/tex] for the parabola and [tex]x \geq 3[/tex] for the line.

This eliminates all the options except for A.

Please Please Please help with this math problem

Answers

The revenue as a function of x is equal to -x²/20 + 920x.The profit as a function of x is equal to -x²/20 + 840x - 6000.The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.The price to be charged to maximize profit is $500.

How to express the revenue as a function of x?

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

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Determine what type of model best fits the given situation:

Answers

Answer:

B. quadratic function graph

A ball is thrown from an initial height of 5 feet with an initial upward velocity of 31 ft/s. The ball's height (in feet) after t seconds is given by the following.
h=5+31t-16t^2

Find all values of t for which the ball's height is 19 feet.
t= _ seconds
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Answers

Solving a quadratic function, it is found that the ball has a height of 19 feet at t = 0.72 seconds and t = 1.22 seconds.

What is a quadratic function?

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex][tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]

In which:

[tex]\Delta = b^2 - 4ac[/tex]

In this problem, the function is:

h(t) = -16t² + 31t + 5

The height is of 19 feet when h(t) = 19, hence:

19 = -16t² + 31t + 5

16t² - 31t + 14 = 0.

Then:

[tex]\Delta = (-31)^2 - 4(16)(14) = 65[/tex][tex]x_1 = \frac{31 + \sqrt{65}}{32} = 1.22[/tex][tex]x_2 = \frac{31 - \sqrt{65}}{32} = 0.72[/tex]

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