What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of static friction between tires and road is 0.70?
2. Is this result independent of the mass of the car?

Answers

Answer 1

Answer:

78.6m/s

Explanation:

We know that frictional force also contributes to the centripetal force that keeps the car in circular motion in the turn

And is given as

F= mv²/r

But the frictional force is

F= ugm

= = 0.7*1200*9.8= 8232N

To find maximum velocity v we say

V= √F x r/m

= √ 8232* 90 /1200

= 78.6m/s

2. Yes it is independent of mass of car

Answer 2

Answer:

The value is [tex]v = 24.85 \ m/s[/tex]

Yes

Explanation:

From the question we are told that

  The mass of the car is  [tex]m= 1200 \ kg[/tex]

    The  radius  is [tex]r = 90 \ m[/tex]

    The coefficient of static friction is  [tex]\mu_s = 0.70[/tex]

Generally at maximum speed the centripetal force acting on the car is equal to the friction force on the car

So

    [tex]F_c = F_f[/tex]

        [tex]\frac{m v^2}{r} = \mu_s * m * g[/tex]

=>   [tex]v = \sqrt{\mu_s * g * r }[/tex]

=>   [tex]v = \sqrt{ 0.70 * 9.8 * 90 }[/tex]

=>    [tex]v = 24.85 \ m/s[/tex]

Yes the value is independent of the mass because from the equation above we see that v is independent of mass


Related Questions

A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth (Cable is going from the cage to ground). If the total mass of the balloon and the cage is 200 kg and the radius of the balloon is 5 m, how much tension (at least), the cable could be able to support in order to keep the balloon from breaking away. (Density of air is approximately 1.225 kg/m3 .)

Answers

Answer:

The tension is  [tex]T = 4326.7 \ N[/tex]

Explanation:

From the question we are told that

   The  total mass is  [tex]m = 200 \ kg[/tex]

    The  radius is [tex]r = 5 \ m[/tex]

     The  density of air is  [tex]\rho_a = 1.225 \ kg/m^3[/tex]

Generally the upward  force acting on the balloon is mathematically represented as

        [tex]F_N = T + mg[/tex]

=>     [tex](\rho_a * V * g ) = T + mg[/tex]

=>   [tex]T = (\rho_a * V * g ) - mg[/tex]

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      [tex]V = \frac{4}{3} * \pi r^3[/tex]

=>   [tex]V = \frac{4}{3} * 3.142 *(5)^3[/tex]

=>   [tex]V = 523.67\ m^3[/tex]

So

    [tex]T = (1.225 * 523.67* 9.8 ) - 200 * 9.8[/tex]

   [tex]T = 4326.7 \ N[/tex]

Why does pressure increases with depth?​

Answers

Answer:

Explanation:

This is due to an increase in hydrostatic pressure, the force per unit area exerted by a liquid on an object. The deeper you go under the sea, the greater the pressure of the water pushing down on you. For every 33 feet (10.06 meters) you go down, the pressure increases by one atmosphere .

2.
Which of the following is NOT a symptom of strong emotions?
A. Impulsiveness
B. Hostility
C. Blindness
D. Distraction

Answers

Answer:

blindness

Explanation:

got it right

Blindness is not a symptom of strong emotions in this scenario and is denoted as option C.

What is Emotion?

These are mental states brought on by neurophysiological changes and examples include sad, happy etc.

Blindness is a physical condition which involves impairment of the eyes which is why it was chosen.

Read more about Emotion here https://brainly.com/question/4692301

#SPJ2

whos on the 1 dollar bills

Answers

Answer:

George Washington

Explanation:

The image of the famous first President of the United States-George Washington (from  1789 to 1797) is found on every $1 bill. George Washington's image began to be found on the $1 bill in 1869.

. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional analysis, find the dimensionality of B.

Answers

Answer:

The dimensionality of B is length per cubic time.

Explanation:

Units for displacement and time are length [tex][L][/tex] and time [tex][T][/tex], respectively. Then, formula can be tested for dimensional analysis as follows:

[tex][L] = B\cdot [T]^{3}[/tex]

Now, let is clear [tex]B[/tex] to determine its units:

[tex]B = \frac{[L]}{[T]^{3}}[/tex]

The dimensionality of B is length per cubic time.

Consider two di˙erent streams of air, both with a relative humidity of 65%. Stream A has a temperature of 15◦C, and stream B has a temperature of 25◦C. The mass flow rate of dry air is the same in both streams. Which stream has a higher mass flow rate of water

Answers

Answer:

stream B.

Explanation:

Stream B has higher mass flow rate of water due to higher temperature i.e. 25◦C as compared to stream A which has a lower temperature i. e. 15◦C because temperature affect the viscosity of liquid. Higher temperature make liquid or water thinner which means lower viscosity. This thinning of liquid make easier the flow of water in the pipes or other medium with the increase in temperature.

A poundal is the force required to accelerate a mass of 1 lbm at a rate of 1 ft/s2 , and a slug is the mass of an object that will accelerate at a rate of 1 ft/s2 when subjected to a force of 1 lbf. (a) Calculate the mass in slugs and the weight in poundals of a 135 lbm woman (i) on earth and (ii) on the moon, where the acceleration of gravity is one-sixth of its value on earth. (b) A force of 405 poundals is exerted on a 35.0-slug object. At what rate (m/s2 ) does the object accelerate?

Answers

Answer:

We are given that

The

Mass of person = 135lbm

Weight of person on earth will be

= mass x gravity constant

= 135lbm x 32.174 ft/s2

=4343.49 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 4343.49 poundal

Again we are given that

Mass of person = 135 lbm

But here remember Mass remains the same

So

Weight of person on moon will be

mass x gravity constant on moon

= 135 lbm x 32.174 ft/s2 x 1/6

= 723.9 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 723.9poundal

But we know that

1 ft slug / lbf-s2 = 32.174 ft lbm/ lbf-s2

So

1 slug = 32.174 lbm

So then the Mass of person

= 135lbm x 1slug/32.174 lbm

=4.2slugs

So finally

Weight = 405 poundals is same as

405 lbm-ft/s2

So

Mass = 35 slug x 32.174 lbm/slug = 1126.09 lbm

Acceleration rate = weight /mass

= (405 lbm-ft/s2) / (1126.09 lbm)

= 0.3597ft/s2 x 0.305m/ft

= 1.179 m/s²

We use sponge when we have fever.Which phenomenon best describe the above statement in physics?​

Answers

Answer: heat loss by conduction

Explanation:

As the thermal energy from our body is flowing to the sponge, our body is losing heat.

A 1200 kg racing car accelerates from rest at a constant rate and covers a distance of 450 m in 15 s. What is the car's acceleration

Answers

Answer:

2 m/s²

Explanation:

Given that

mass of the car, m = 1200 kg

Initial velocity of the car, u = 0 m/s

Distance covered, s = 450 m

Time taken, t = 15 s

Final velocity of the car, v = s/t = 30 m/s

there are four equations of motion. In this question, we will be attempting to solve it using the first equation of motion to solve this question

v = u + at, where

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v = u + at

30 = 0 + 15a

30 = 15a

a = 30/15

a = 2 m/s

Which parenting style is thought to produce children who grow up to be emotionally withdrawn,

distant, and lacking in curiosity?

Answers

Answer:

Uninvolved (provide little guidance , nuturing and attention) that causes to grow up to be emotionally withdrawn, distant and lacking in curiosity.

Explanation:

If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.

Answers

This question is incomplete

Complete Question

Three equal point charges are held in place as shown in the figure below

If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.

A) F1=2F2

B) F1=3F2

C) F1=4F2

D) F1=9F2

Answer:

D) F1=9F2

Explanation:

We are told in the question that there are three equal point charges.

q, Q1, Q2 ,

q = Q1 = Q2

From the diagram we see the distance between the points d

q to Q1 = d

Q1 to Q2 = nd

Assuming n = 2

= 2 × d = 2d

Sum of the two distances = d + 2d = 3d

F1 is the force on q due to Q1 and

F2 is the force on q due to Q2,

Since we have 3 equal point charges and a total sum of distance which is 3d

Hence,

F1 = 9F2

A continuous line of charge lies along the x axis, extending from x = +x0 to positive infinity. The line carries positive charge with a uniform linear charge density λ0. (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: λ0, x0, and ke.) E = (b) What is the direction of the electric field at the origin? +x −x +y −y +z −z

Answers

Answer:

 E = k λ₀ / x₀, the field is in thenegative direction of the x axis (-x)

Explanation:

In this problem the electric field of a line of charge is requested, the expression for the electric field is

          E = k ∫ dq / r²

where k is the Coulomb constant that you are worth 9 10⁹ N m²/C², that the charge and r the distance to the point of interest, in this case it is the origin (x = 0)

let's use the definite linear density

        λ₀ = dq / dx

        dq = λ₀ dx

we replace and integrate

       E = k λ₀ ∫ dx / x²

       E = k λ₀ ( -1 / x)

we evaluate the integral from the lower limit of load x = x₀ to the upper limit x = ∞

       E = - k λ₀ (1 /∞ - 1 / x₀)

       E = k λ₀ / x₀

     

as the field is positive the direction is away from the charges, so it is in the negative direction of the x axis (-x)

Given that average speed is distance traveled divided by time, determine the values of mm and nn when the time it takes a beam of light to get from the Sun to the Earth (in ss) is written in scientific notation. Note: the speed of light is approximately 3.0××108 m/sm/s.

Answers

Complete Question

Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of light to get from the Sun to the Earth (in s) is written in scientific notation. Note: the speed of light is approximately 3.0×108 m/s.

Answer:

The  values of  m and  n is    5 and  2  

Explanation:

From the question we are told that

   The  speed of light is [tex]v  =  3.0 *10^{8} \  m/s[/tex]

   

Generally the distance between the sun and the earth has a constant value

      [tex]d =  1.5*10^{11} \  m[/tex]

So the time  taken is mathematically evaluated as

        [tex]t =  \frac{1.5*10^{11}}{3.0*10^{8}}[/tex]

         [tex]t =  5.0 *10^{2}[/tex]

Generally scientific notation is represented as

        [tex]m* 10^n[/tex]

So comparing the standard representation of scientific notation and the value obtained we see that

     m =  5  and  n=  2  

g a long, straight wire carries a current an electron Is it necessary to include the effects of gravity?

Answers

Answer:

The force is [tex]3.2\times10^{-20}\ N[/tex]

Explanation:

Given that,

A long, straight wire carries a current.

Suppose, a long, straight wire carries a current 0.86 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.50 cm from the wire and traveling at speed of [tex]6\times10^{4}\ m/s[/tex] directly toward the wire. What are the magnitude of the force that the magnetic field of the current exerts on the electron?

We need to calculate the magnetic field

Using formula of magnetic field

[tex]B=\dfrac{\mu_{0}I}{4\pi r}[/tex]

Where, I = current

r = distance

Put the value into the formula

[tex]B=\dfrac{4\pi\times10^{-7}\times0.86}{2\pi\times4.5\times10^{-2}}[/tex]

[tex]B=0.0000038\ T[/tex]

[tex]B=3.8\times10^{-6}\ T[/tex]

We need to calculate the force

Using formula of force

[tex]F=qvB\sin\theta[/tex]

Here, [tex]\theta=90^{\circ}[/tex]

Where, q = charge of electron

v = velocity of electron

B = magnetic field

Put the value into the formula

[tex]F=1.6\times10^{-19}\times6\times10^{4}\times3.8\times10^{-6}\sin90[/tex]

[tex]F= 3.2\times10^{-20}\ N[/tex]

Hence, The force is [tex]3.2\times10^{-20}\ N[/tex]

Examine the scenario. A circuit is arranged so that 20 A of current is flowing through it. The battery is replaced with another battery with ¼ the original voltage. Which choice correctly describes the effect on the current? The current reduces to ¼ of the original current because a smaller voltage indicates that there is less energy to move the charge. As voltage decreases in a circuit, current also decreases. The current decreases to ½ of the original amount because a smaller voltage indicates that the flow of charge is being restricted, but only by half. As voltage decreases, current will decrease also, but by a smaller amount. The current increases to 4 times the amount because a smaller voltage indicates that there is less to restrict the flow of charge. As voltage decreases in a circuit, current increases The current stays the same because a smaller voltage means there is less energy for each charge, but more charges are moving through the circuit. Current and voltage do not affect each other.

Answers

Answer:

The current reduces to ¼ of the original current because a smaller voltage indicates that there is less energy to move the charge. As voltage decreases in a circuit, current also decreases.  

Explanation:

The height of a helicopter above the ground is given by h = 2.80t3, where h is in meters and t is in seconds. At t = 2.45 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

Answers

Answer:

1.45

Explanation:

A Nichrome wire 50 cm long and 0.27 mm in diameter is connected to a 1.5 V flashlight battery. What is the electric field inside the wire

Answers

Answer:

E=3V/m

Explanation:

The electric field here is simply the voltage running through the wire divided by its length. (Meaning E is independent of the diameter of the wire.)

Short work is in the attachment.

Which of the following best describes what an electron configuration is?
A) An electron configuration is the mathematical symbol used to describe the first three principle energy levels in which electrons are found within an atom.
B) An electron configuration is the system used to name each principle energy level and the sublevels in which electrons are found within an atom.
C) An electron configuration is used to name the sublevels in which electrons are found within an atom.
D) An electron configuration describes how the principle energy level and sublevels in which protons and neutrons are found affect the electrons within an atom.

Answers

Answer:

An electron configuration is used to name the sublevels in which electrons are found within an atom

Explanation:

An electron configuration is used to name the sublevels in which electrons are found within an atom for example for the atom carbon has 6electrons so its configuration is 1s²2s²2p²

With the 1s 2s and 2p showing the various energy sublevels

Concerning the concepts and fundamentals of the atomic model, an electron configuration is used to name the sublevels in which electrons are found within an atom. Hence, option (C) is correct.

What is electronic configuration?

The arrangement of electrons in specific energy levels around the atomic nucleus of an atom is known as the electron configuration of an atom.

As per the atomic shell model, "The electrons occupy the various energy levels from the first shell nearest to the nucleus, upto the farthest shell from the nucleus.

Consequently, an electron configuration is used to name the sublevels in which electrons are found within an atom. For example for the atom carbon has 6 electrons so its configuration is 1s²2s²2p². With the 1s 2s and 2p showing the various energy sublevels.

Thus, we can conclude that an electron configuration is used to name the sublevels in which electrons are found within an atom.

Learn more about the electronic configuration here:

https://brainly.com/question/14989344

A solid sphere of radius R has a uniform charge density and total charge Q. Find the total energy of the sphere U in terms of

Answers

Answer:

[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]

Explanation:

From the information given;

The surface area of a sphere = [tex]4 \pi r ^2[/tex]

If the sphere is from the collection of spherical shells of infinitesimal thickness = dr

Then,

the volume of the  thickness and the sphere is;

V = [tex]4 \pi r ^2 \ dr[/tex]

Using Gauss Law

[tex]V(r) = \dfrac{k_cq(r)}{r}[/tex]

here,

q(r) =charge built up contained in radius r

since we are talking about collections of spherical shells, to work required for the next spherical shell r +dr is

[tex]-dW= dU = V(r) dq = \dfrac{k_c \ q(r)}{r} \ dq[/tex]

where;

[tex]q (r) = \dfrac{4}{3} \pi r^3 \rho[/tex]

dq which is the charge contained in the  next shell of charge

here dq = volume of the shell multiply by the density

[tex]dq = 4 \pi r^2 \ dr \ \rho[/tex]

equating it all together

[tex]dU = \dfrac{k_c \frac{4}{3} \pi r^3 \rho}{r} 4 \pi r^2 \ dr \ \rho = \dfrac{16 \pi^2 \ k_c \ \rho^2}{3} \ r^4 \ dr[/tex]

Integration the work required from the initial radius r to the final radius R, we get;

[tex]U = \int^R_0 \ dU[/tex]

[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} r^4 \ dr[/tex]

[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} [\dfrac{r^5}{5}]^R_0[/tex]

[tex]U = \dfrac{16 \pi^2 k_c \rho^2}{15} \ R^5[/tex]

Recall that:

the total charge on a sphere, i.e [tex]Q_{total} = \dfrac{4}{3} \pi R^3 \rho[/tex]

Then :

[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]

in a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by a multiple of

Answers

Answer:

The path difference will be zero.

Explanation:

Given that,

In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.

Suppose, we find the multiple of wavelength

In young's double slit experiment,

We need to calculate the multiple of wavelength

Using formula of path difference

[tex]\Delta x=d\sin\theta[/tex]....(I)

[tex]d\sin\theta=m\lambda[/tex]

Where, m = fringe number

[tex]\lambda[/tex] = wavelength

For center of a bright fringe ,

m = 0

Put the value into the formula

[tex]d\sin\theta=0\times\lambda[/tex]

[tex]d\sin\theta=0[/tex]

Put the value in equation (I)

[tex]\Delta x=0[/tex]

Hence, The path difference will be zero.

What is the speed of an electron that has been accelerated to the point at which its total energy is 10.5 times its rest mass

Answers

Answer:

0.995*c= 2.98*10^8m/s

Explanation:

Using

E= mc²

10.5 mc² = mc²/√1-v²/c²

So

1-v²/c²=( 1/10.5)²

V= √1-0.009c

V= 0.995 x 3E8m/s

= 2.98*10^8m/s

What are the definitions of momentum, angular momentum, and kinetic energy for a single particle? What are the dimensions of these quantities?

Answers

Answer:

Explanation:

Momentum is defined as a physical quantity that takes into cognisance the product of mass of a body and its velocity. It's unit is kgm/s

Momentum = mv

Angular Momentum is defined as the quantity of rotation of a body that measures the product of its moment of inertia with respect to its angular velocity. Because it deals with rotation is what differs it from ordinary momentum. It's unit is kgm²/s

Angular Momentum = mvr

Kinetic Energy is defined as the energy a body posses as a result of it being in motion. The unit of Kinetic Energy is J

Kinetic Energy = ½mv²

The dimensions of these quantities are

Momentum => MLT^−1

Angular Momentum => ML²T^−1

Kinetic Energy => ML²T^-2

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A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns through an angle of 80 radians. Assuming the wheel started from rest, how long had it been in motion at the start of the 4.0-s interval?
a. 3 s.
b. 6 s.
c. 9 s.
d. 12 s.

Answers

Answer:

a. 3 s.

Explanation:

Given;

angular acceleration of the wheel, α = 4 rad/s²

time of wheel rotation, t = 4 s

angle of rotation, θ = 80 radians

Apply the kinematic equation below,

[tex]\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s[/tex]

Given initial angular velocity, ω₀ = 0

Apply the kinematic equation below;

[tex]\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s[/tex]

Therefore, the wheel had been in motion for 3 seconds.

a. 3 s.

If you walk at a constant speed of 4.5 m/s, how many km can you walk in half an hour? how do you solve this?

Answers

Its 8.1 km
So you multiply 4.5 times 60 to find the distance for a minute then you multiply this number by 30 to find the distance in meters for half an hour.
Finally you convert the meters by dividing it by 1000

which surface has more friction
A. an ice rink
B. a grassy field
C. a paved road​

Answers

Answer:

The answer is C. a paved road

Explanation:

Generally, roads are meant to have very rough surfaces to allow for friction between car tyres hence the motion of vehicles.

What is a paved surface?

Paved roads are roads that are covered with a firm surface suitable for travel, like paving stones or concrete or asphalts.

Another good example of a paved road is a  small paved courtyard, covered with a hard layer of concrete/cement.

The other two examples sited in this problem are glossy materials with very low surface friction, that is their surfaces are very smooth.

4. What is being carried from particle to particle in water wave?

Answers

In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

tbh google

Your question has been heard loud and clear.

Energy propogates through different media in different ways.

Through a medium like water , energy is carried(propogated) from particle to particle in water waves.

Thank you.

A trucker drives with an average velocity of 27 m/s toward the east on a perfectly
straight highway.What will the trucker's displacement be after 2.0 h?

Answers

Answer:

The displacement of the driver is 194400m in the east direction

Explanation:

In physics, the displacement of a body is the distance the body travels in a specified direction.

We are told that the trucker is driving east on a perfectly straight highway. From this, we know that his direction is East. The thing left will be to find the distance travelled within 2 hours.

We can convert the time (2 hours) to seconds by multiplying it by 3600

2 hours = 7200 seconds

The distance travelled will be obtained by a product of truck's speed and the time travelled.

distance = 27m/s X 7200 s = 194400m

Therefore the displacement of the driver is 194400m in the east direction

Using Newton's Second Law, can you explain why one of the major advancements in spaceflight was the development of strong ceramic (clay)
materials to build their rockets out of instead of heavy metals?

Answers

Answer:

high density can withstand high acceleration and applied forces

Heavy metals are toxic to humans,

the clay is quite abundant and in general it is not toxic

Explanation:

The selection of materials for the construction of rockets takes into account many aspects, the technical resistance to the demands of space travel, but also the abundance of the material. Heavy metals have two very serious problems. The first one, some of them are a little scarce in nature, but the most serious problem is that almost all of them are toxic to humans, for example: lead and mercury.

On the other hand, the clay is quite abundant and in general it is not toxic to living beings.

If we use Newton's second law

          F = m a

let's use the concept of density

         rho = m / V

        m = rho V

let's substitute

         F = rho V a

From this expression we see that a material with high density can withstand high acceleration and applied forces, such as those existing in spacecraft clearance and re-entry to Earth.

Unfortunately with this law there is no criterion to select a material unless its density is high, in addition to this criterion low toxicity criteria for human beings are used,

What is the Kinetic Energy of a pie with a mass of 5 kg travelling at a velocity of 9m/s towards your face ?

Answers

Answer:

K = 202.5 J

Explanation:

Given that,

Mass of pie is 5 kg

Velocity of pie is 9 m/s

We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :

[tex]K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5\times (9)^2\\\\K=202.5\ J[/tex]

So, the kinetic energy of the pie is 202.5 J.

Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 2.8 s .

Answers

Answer:

2.15 mV

Explanation:

The complete question is

You have a coil of wire with 17 turns each of 1.5 cm radius. You place the plane of the coil perpendicular to a 0.50-TB?  field produced by the poles of an electromagnet.

Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 1.9 s .

Radius of the coil = 1.5 cm = 0.015 m

number of turns = 17

Initial magnetic field [tex]B_{1}[/tex] = 0.50 T

Final magnetic field [tex]B_{2}[/tex] = 0 T

time taken dt = 1.9 s

Area pf the coil = π[tex]r^{2}[/tex] = 3.142 x [tex]0.015^{2}[/tex] = 7.1 x 10^-4 m^2

magnetic flux = BA

initial flux = [tex]B_{1}[/tex]A = 0.5 x 7.1 x 10^-4 = 3.55 x 10^-4 Wb

Final flux = [tex]B_{2}[/tex]A = 0 x 7.1 x 10^-4 = 0 Wb

change in flux dФ = 3.55 x 10^-4  -  0 = 3.55 x 10^-4 Wb

Induced EMF E = NdФ/dt = (17 x 3.55 x 10^-4)/2.8 = 2.15 x 10^-3 V

==> 2.15 mV

Other Questions
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