Answer:
The summary including its circumstances in question is outlined in the illustrating segment below.
Explanation:
An astronomer seems to be an astronomical specialist who performs his information about the research problem or area elsewhere in Earth's view.A few other moons include "backward" orbits (particularly in comparison to the movement or rotation of another planet), or are favorably committed to the equator of their continent.A jet makes a landing traveling due east with a speed of 115 m/s. If the jet comes to rest in 13.0 s, what is the magnitude of its average acceleration
Answer:
8.846 m/s²
Explanation:
From the question,
The magnitude of the average acceleration is given as,
a = (v-u)/t.................. Equation 1
Where a = acceleration of the jet, v = final velocity of the jet, u = initial velocity of the jet, t = time taken for the jet to come to rest.
Given: v = 115 m/s, u = 0 m/s( from rest), t = 13.0 s
Substitute these values into equation 1
a = (115-0)/13.0
a = 115/13
a = 8.846 m/s²
Hence the magnitude of the average acceleration of the jet is 8.846 m/s²
Answer:
The value is [tex]a = 8.85 \ m/s^2[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 115\ m/s[/tex]
The time taken is t = 13.0
The initial speed is [tex]u = 0 \ m/s[/tex]
Generally the magnitude of the average acceleration is mathematically represented as
[tex]a = \frac{v-u}{ t}[/tex]
=> [tex]a = \frac{ 115 -0}{ 13}[/tex]
=> [tex]a = 8.85 \ m/s^2[/tex]
1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a
straight line at 20 m/s. What is the total speed of the insect as seen by a person standing
side of the road?
A person runs around a 400 m track. What is this person’s distance? What is this person’s displacement?
Explanation:
The distance is the length of the path, or 400 m.
The displacement is the difference between the final position and the initial position. Since the track is a circle and the end back where they started, the displacement is 0 m.
If a person runs around a 400 m track,then the distance covered by the person would be 400 meters, while the displacement covered by the person would be zero meters.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
Displacement describes this shift in location.
As given in the problem If a person runs around a 400 m track, then we have to find the distance and the displacement covered by him,
The distance is 400 meters, which is how long the path is.
The distance between the end location and the starting position is known as displacement. The displacement is 0 m since the track is round and ends where it began.
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Industrial espionage is the use of spying techniques to find out key information that is of economic value.
a) true
b) false
Answer:
The given statement is "True".
Explanation:
Industrial spying or espionage seems to be the surreptitious but sometimes unconstitutional method of trying to investigate competition in the market to gain a competitive advantage throughout the commercial enterprise. The investigation's goal may be a closely guarded secret including a patented product design or formulation, or growth strategy details.What is a true statement about models in science? A. Models change to accommodate new discoveries. B. Models are only used by scientists. C. Models never change. D. Models are only used by engineers.
Answer:
Models change to accommodate new discoveries
Explanation:
Owing to the dynamism of science, scientific models also change to accommodate new ideas and discoveries. Science is not a static body of knowledge. Research consistently brings new information to the fore. This propels a change in certain scientific models to accommodate the new discoveries and present a more accurate representation of phenomena in nature.
Hence, scientific models change to accommodate new discoveries.
Answer: Models change to accommodate new discoveries.
Explanation: I took the test
what is systematic error ?
Explanation:
Systematic error (also called systematic bias) is consistent, repeatable error associated with faulty equipment or a flawed experiment design. These errors are usually caused by measuring instruments that are incorrectly calibrated or are used incorrectly.
Most scientific experiments are what type experiment, mostly because it is simpler and easier to test single variables? a) Natural experiment. b) Controlled experiment. c) Forced experiment. d) Redundant experiment.
Answer:
The correct answer is : option B. controlled experiments.
Explanation:
A scientific experiment which deals with a single variable at a time and compared the independent variable to a controlled variable after measuring the change in dependent variable.
It is a very simple and easy test for single variable. In these experiments subjects are divided in two groups one one, with independent variable and other variable.
Thus, the correct answer is : option B. controlled experiments.
Explain how your weight can change even though your mass remains the same.
Answer:
See explanation below
Explanation:
Recall that Weight is a Force that results from the action of a gravitational field on our body mass. Therefore if one changes locations to places where the acceleration of gravity is different, our weight can change although the mass of our body stays the same.
For example, going to a high mountain, where the acceleration of gravity is a little smaller than at sea level, will produce such change. Also, going to another planet with different gravitational field, or going to the Moon (where the acceleration of gravity is about 1/6 of that on Earth which therefore will reduce our weight without reducing our mass)
Since weight is calculated with the equation:
Q=mg
the weight can also change when the gravitational acceleration (g) changes.
g can change at example when you travel to a different planet or (slightly) when gaining attitude on Earth (e.g. when climbing a mountain or flying on a plane you get lighter).
A 145 lb diver stands at the end of a rigid 7 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board
Answer:
Torque = 1015 ft.lb
Explanation:
Torque is defined as the turning effect of force. It is the force that can cause an object to rotate and gain some angular acceleration. Torque is basically an angular analog of force. The method to calculate torque is simple. Take the perpendicular distance from the line of action of force to the axis of rotation. Multiply this distance with the magnitude of force. The magnitude of this product gives the torque. Therefore,
Torque = (Force)(Perpendicular Distance)
Since, the diver is standing at the end of diving board.
Therefore,
Perpendicular Distance = 7 ft
Force = 145 lb
Therefore,
Torque = (145 lb)(7 ft)
Torque = 1015 ft.lb
what is achmedis principle
Answer:
Archimedes principle states that when a body is partially/wholly/completely immersed in fluid (liquid or gas),it experiences an upthrust which is equal to the weight of the fluid displaced....
The term 'Zero Age Main Sequence' refers to the time when a new star stops contracting and hydrogen fusion starts.A. TrueB. False
Answer:
True
Explanation:
When a star has reached the main sequence stage, hydrogen is converted into helium by nuclear fusion, . Also, the gravity and pressure are balanced because the star does not radiate more heat than it generates. A star usually spends most of its lifetime at this stage.
The Zero Age Main Sequence is the period during the main sequence when a star stops contracting, and begin to fuse hydrogen in its core.
Powerful sports cars can go from zero to 25 m/s (about 60 mph) in 6 seconds. What is the magnitude of the acceleration, including units
Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;
[tex]a = \frac{v-u}{t}\\\\a = \frac{25-0}{6}\\\\a = 4.2 \ m/s^2[/tex]
Therefore, the magnitude of the acceleration is 4.2 m/s²
The magnitude of the acceleration is 4.2 m/s²
The calculation is as follows:Given that
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Now the magnitude should be
[tex]= (25 - 0) \div 6[/tex]
= 4.2 m/s²
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Sabiendo que la velocidad de la luz en el Cuarzo es de 194.166.099 m/s y de 203.525.090 m/s en la glicerina: a) Hallar los índices de refracción absolutos en la glicerina y en el cuarzo. b) Hallar el índice de refracción relativo del agua respecto al diamante.
Answer:
a) glycerin n = 1.5440 , quartz n = 1.4730
b) n₂₁ = 0.550
Explanation:
The refractive index is
n = c / v
where c is the speed of light in a vacuum and v the speed of light in the material medium
Let's use this expression to find the indexes of refraction
a) glycerin of v= 194166099 m / s
n = 2,998 10 8/194166099
n = 1.5440
quartz v = 203525090 m / s
n = 2,998 108/203525090
n = 1.4730
b) the relative refractive index is the relationship between the absolute refractive indices of two materials
diamond n₁ = 2.417
water n₂ = 1.33
the relative refractive index
n₂₁ = n_water / n_diamond
n₂₁ = 1.33 / 2.417
n₂₁ = 0.550
What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F
Answer:
1.5F
Explanation:
Using
E= F/q
Where F= force
E= electric field
q=charge
F= Eq
So if qis tripled and E is halved we have
F= (E/2)3q
F= 1.5Eq=>> 1.5F
A lens that is "optically perfect" is still limited by diffraction effects. Suppose a lens has a diameter of 150 mm and a focal length of 620 mm. A. Find the angular width (that is, the angle from the bottom to the top) of the central maximum in the diffraction pattern formed by this lens when illuminated with 520 nm light.B. What is the linear width (diameter) of the central maximum at the focal distance of the lens?
Answer:
a
w = 8.46 *10^{-6} \ rad
b
D =5.24 *10^{-6}
Explanation:
From the question we are told that
The diameter of the lens is [tex]d = 150 \ mm = 150*10^{-3} \ m[/tex]
The focal length is [tex]f = 620 mm = 620 *10^{-3} \ m[/tex]
The wavelength is [tex]\lambda = 520 \ nm = 520 *10^{-9} \ m[/tex]
Generally the angular width is mathematically represented as
[tex]w = 2 \theta[/tex]
Here [tex]\theta[/tex] is the angular radius of the central maxima which is mathematically represented as
[tex]\theta = \frac{1.22* \lambda }{ d}[/tex]
=> [tex]\theta = \frac{1.22 * 520 *10^{-9}}{ 150 *10^{-3}}[/tex]
=> [tex]4.23 *10^{-6} \ rad[/tex]
Hence
[tex]w = 2 * 4.23 *10^{-6}[/tex]
=> [tex]w = 8.46 *10^{-6} \ rad[/tex]
Generally linear diameter is mathematically represented as
[tex]D = 2 * R[/tex]
Where [tex]R[/tex] is the linear radius which is mathematically represented as
[tex]R = \frac{1.22 * f * \lambda }{ d}[/tex]
=> [tex]R= \frac{1.22 * 620 *10^{-3} * 520 *10^{-9}}{150 *10^{-3}}[/tex]
=> [tex]R = 2.62*10^{-6} \ m[/tex]
Thus
[tex]D = 2 * 2.62 *10^{-6}[/tex]
[tex]D =5.24 *10^{-6}[/tex]
what are the x and y components of the vector that has a magnitude of 4N and a direction of 30 degrees
Answer:
We are given
vector as 4N and direction 30°
So since X-component is
adjacent /hypotenuse which is cosine we have
= 4 cos 30 = 3.46 N
And Y-component which is opposite/hypotenuse we have
= 4 sin 30 = 2N
The simplest branched-chain hydrocarbon is
A ethane
B ethene
C propane
D butane
Answer:
Butane
Explanation:
Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, car D is ahead of car C and is speeding up while car C is slowing down. During the interval At, it is observed that car C gains on car D (i.e., the distance between the cars decreases). Explain how this is possible, and give a specific example of such a case.
Answer:
possibly because the car is running out of gas
Explanation:
Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? a. Nina experiences a force equal to f/2. b. Nina experiences a force equal to f^2. c. Nina experiences a force equal to 2f. d. Nina experiences a force equal to f.
Answer:
A
Explanation:
• Nina experiences a force equal to f.
Answer:
Nina experiences a force equal to f
Explanation:
got to get that 2nd answer slot correct too before an abusive expert verifier with an alt comes in and purposely verifies the wrong answer
Two tuning forks having frequencies of 460 and 464 Hz are struck simultaneously. What average frequency will you hear, and what will the beat frequency be
Answer:
462Hz, 4Hz
Explanation:
The average frequency heard would be 462 Hz because that is the average between the two and we do not hear one note more than another so the average is 462 Hz. (460+464)/2 = 462Hz. The beat frequency is basically the difference between frequencies, so our beat frequency is 464-460=4Hz.
Hope this helped!
An electron is located on the x ‑axis at x0=−2.05×10−6 m . Find the magnitude and direction of the electric field at x=2.77×10−6 m on the x ‑axis due to this electron.
Answer:
The value is [tex]E = 62 \ N/C[/tex]
Explanation:
From the question we are told that
The initial position of the electron [tex]x_o = -2.05*10^{-6} \ m[/tex]
The position that is considered [tex]x= 2.77*10^{-6} \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = k * \frac{q}{r^2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^9 \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
r is the distance covered which is mathematically represented as
[tex]r = x- x_o[/tex]
[tex]r = 2.77*10^{-6} -(-2.05*10^{-6})[/tex]
[tex]r = 4.82 *10^{-5}[/tex]
So
[tex]E = \frac{9*10^9 * 1.60*10^{-19}}{ (4.82 *10^{-6})}[/tex]
[tex]E = 62 \ N/C[/tex]
Answer:
Direction: Negative x-direction
Explanation:
The question tells you that both lie on the ‑axis, and the data indicate that the electron is in the negative ‑direction from the field point ( 0< ). Because the field produced by a negative source charge points toward the source, the field in this case points in the negative ‑direction.
While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.
Answer:
His displacement is 260 – 169 = 91 km
His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km
Explanation:
A 400 N steel ball is suspended by a light rope from
the ceiling. The tension in the rope is
Answer:
As force = tension in string so tension in string is 400N
Explanation:
Tension in the rope is "400 N".
Tension is the force developed inside a flexible material or medium, such as a cable, wire, or rope. This force depends upon the externally applied load. In the case of equilibrium, the tension in a rope or string is equal to the load applied to the rope or string, externally.
Since the steel ball and the rope system is in equilibrium in our case. Therefore, the tension in the rope must be equal to the load (weight) of the steel ball:
Tension = Weight of Steel Ball
Tension = 400 N
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The attached picture shows the tension on a steel ball hung by a rope.
A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Write your answer as a decimal.
Complete Question
A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.
Answer:
The value is [tex]x = 14.6 \ MHz[/tex]
Explanation:
From the question we are told that
The frequency is [tex]f = 14603 \ kHz = 14603 *1000 = 14603000 \ Hz[/tex]
Generally
[tex]1 Hz \to 1.0 *10^{-6} \ MHz[/tex]
[tex]14603000 \ Hz \to x MHz[/tex]
=> [tex]x = \frac{14603000 * 1.0*10^{-6}}{1 }[/tex]
=> [tex]x = 14.6 \ MHz[/tex]
Describe the motion of an object:
a. for which the direction of the acceleration is the same as the direction of motion of the object.
b. for which the direction of the acceleration is opposite to the direction of motion of the object.
c. for which the change in velocity is zero.
d. for which the initial velocity is zero but the acceleration is not zero.
Answer:
A. Here object is moving with increasing velocity
B. Here the object is moving with decreasing velocity that is it is decelerating
C. Here the initial and final velocity are the same so the object moves at constant velocity
D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained
Answer:
Answer:
A. Here object is moving with increasing velocity
B. Here the object is moving with decreasing velocity that is it is decelerating
C. Here the initial and final velocity are the same so the object moves at constant velocity
D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained
Explanation:
what is force magnifier for class 6
Answer:
I think it will helps you dude!! :)
Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.
Answer:
Explanation:
K.E=1/2 mv²
m=1160 kg
v=19.0 m/s
so k.e=1/2*1160*(19.0)²
K.E=1/2*1160*361
K.E=1/2*418760
K.E=209380=2.0*10^5 j
Which of Jafar's statements are correct regarding distance and displacement?
Answer:The distance and magnitude of displacement are sometimes equal." Jafar is correct. The distance traveled and the magnitude of displacement are equal if and only if the path is a straight line in one direction.
Explanation:
Why do scientists need creativity? What is gravity? Why are two objects with mass drawn to each other? List the two things that affect gravitational force. How are mass and weight different? Why does weight change depending on location? Explain in your own words the law of universal gravitation. Why does gravitational force vary between objects? How do we know how much gravitational force objects have? How does distance affect gravity? answer them all
Answer:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other.
the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
mass and distance.
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
A person can weigh differently at various place on Earth because of the fluctuations in Earth's gravity.
We call the gravitational force attractive because it always tries to pull masses together, it never pushes them apart. In fact, every object, including you, is pulling on every other object in the entire universe!
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force
Its weight is determined by the degree to which gravitational force acts on it.
the force of gravity the masses exert on each other. increases, the force of gravity decreases
The mass of the objects and their separation from one another determine the gravitational force's strength. The gravitational pull of masses on one another.
What affect gravitational force?Mass is a measure of the quantity of substance in a material, whereas weight measures how the force of gravity acts upon a mass.
Because of variations in Earth's gravity, a person's weight might vary depending on where they are on the planet.
The gravitational force is referred to as attractive because it continually tries to pull masses together rather than push them apart. In truth, you and everything else in the universe are being pulled in different directions.
Therefore, Greater gravitational forces will pull more massive objects toward one another because gravitational force is directly proportional to the mass of both interacting objects.
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You drop a ball from a height of 1.7 m, and it bounces back to a height of 1.2 m.
Part A) What fraction of its initial energy is lost during the bounce? Express your answer using two significant figures.
Part B) What is the ball's speed just before the bounce? Express your answer to two significant figures and include the appropriate units.
Part C) What is the ball's speed just after the bounce? Express your answer to two significant figures and include the appropriate units.
Part D) Where did the energy go?
1. The energy "lost" was changed primarily into chemical energy.
2. The energy "lost" was changed primarily into acoustic energy.
3. The energy "lost" was changed primarily into thermal energy due to friction.
4. The energy "lost" was changed primarily into heat energy.
Answer:
A) ΔEm = 0.29, B) v₁ = 5.8 m/s, c) v₂= 4.9 m / s D) the correct answer from 4
Explanation:
For this exercise we will use conservation of energy, taking care of how to choose our system
A) For this case we take two instants
starting point. When the ball goes out
Em₀ = U = m g y₁
Final point. When the ball reaches its maximum height
[tex]Em_{f}[/tex] = U = m g y₂
In this case we see that there is a loss of mechanical energy at the moment of rebound, therefore the fraction of energy lost is
ΔEm = Em_{f} / Em₀
ΔEm = mg y₂ / mg y₁
ΔEm = y₂ / y₁
ΔEm = 1.2 / 1.7
the lost part of energy
ΔEm = 1 -0.706
ΔEm = 0.29
B) the velocity just before the bounce
starting point. When the ball is released
Em₀ = U = m g y₁
final punot. Just wide of the bounce
Em_{f} = K = ½ m v₁²
As it has not yet rebounded, it has no energy loss, therefore the mechanical energy is conserved
Em₀ = Em_{f}
m g y₁ = ½ m v₁²
v₁ = √ 2 g y₁
let's calculate
v₁ =√ (2 9.8 1.7)
v₁ = 5.77 m / s
v₁ = 5.8 m/s
C) the velocity just after the bounce
starting point, after bounce
Em₀ = K = ½ m v₂²
final point. Maximum height after bounce
Em_{f} = U = m g y₂
as it already bounced, the energy is conserved in this interval
Em₀ = Em_{f}
½ m v₂² = m g y₂
v₂ = √ (2 g y₂)
v₂ = √ (2 9.8 1.2)
v₂ = 4.85 m / s
v₂= 4.9 m / s
D) during the time that the bounce lasts, there is a strong change in energy, part of it is transformed into thermal energy, due to several processes: friction, change in the potential energy of the molecules of the ball, change in the internal energy of the balls. molecules.
Therefore we cannot specify a single process, consequently the correct answer from 4