What is true about sides opposite congruent
angles within a triangle?

Answer:

C .6 inches

Step-by-step explanation:

I'm not sure of my answer

Answer:

Not worth 40 points. Poster is a liar.

R=15 --> 30/2 , H=320

Anyways, because you lied, I won't show my work.

Volume= 72,000pi or 226194.6711

Answer:

[tex]x[/tex] =[tex]\frac{-2}{3}[/tex]   or   [tex]x[/tex] = -1

Step-by-step explanation:

quadratic formula⇒ -b ±[tex]\sqrt{b^{2} -4ac}[/tex] / 2a

15[tex]x[/tex]² + 22[tex]x[/tex] = -8

15[tex]x[/tex]² + 22[tex]x[/tex] +8 = 0

taking a=15, b=22 & c=8;

[tex]x[/tex] = (-22 ± [tex]\sqrt{ - 22^{2} 4 × 15 × 8}[/tex])/ 2 x 15 ⇒ (Pls note that the A~s are multiplications.. unable to insert symbols in equations)

  = (-22 ± [tex]\sqrt{484 - 480}[/tex]) / 30

  = (-22 ± [tex]\sqrt{4}[/tex]) / 30

  = (-22 ± 2) / 30

[tex]x[/tex] = [tex]\frac{-22 + 2}{30}[/tex]  or  [tex]x[/tex] =[tex]\frac{-22 - 2}{30}[/tex]

[tex]x[/tex] = -[tex]\frac{-20}{30}[/tex]    or [tex]x[/tex] = [tex]\frac{-30}{30}[/tex]

[tex]x[/tex] =[tex]\frac{-2}{3}[/tex] or [tex]x[/tex] = -1

Answer :

⠀

Explanation :

[tex]\longrightarrow \sf \qquad {x}^{2} + 10x - 39 = 0[/tex]

⠀

We have to find the two numbers a and b such that,

[tex]\longrightarrow \sf \qquad a + b = 10[/tex]

[tex]\longrightarrow \sf \qquad a b = 39[/tex]

⠀

Obviously, the two numbers are 3 and 13.

[tex]\longrightarrow \sf \qquad {x}^{2} - 3x + 13x - 39 = 0[/tex]

[tex]\longrightarrow \sf \qquad {x}(x - 3)+ 13(x - 3) = 0[/tex]

[tex]\longrightarrow \sf \qquad ({x}+ 13)(x - 3) = 0[/tex]

⠀

Whether, the value of x :

[tex]\longrightarrow \sf \qquad {x}+ 13 = 0[/tex]

[tex]\longrightarrow \pmb{\bf \qquad {x} = - 13}[/tex]

⠀

Whether, the value of x :

[tex]\longrightarrow \sf \qquad {x} - 3 = 0[/tex]

[tex]{\longrightarrow { \pmb{\bf \qquad {x} = 3}}}[/tex]

⠀

We are given with the equation x² + 10x - 39 = 0 and need to find x, so let's start ;

[tex]{:\implies \quad \sf x^{2}+10x-39=0}[/tex]

By using splitting the middle term method, Rewrite as ;

[tex]{:\implies \quad \sf x^{2}+13x-3x-39=0}[/tex]

[tex]{:\implies \quad \sf x(x+13)-3(x+13)=0}[/tex]

[tex]{:\implies \quad \sf (x+13)(x-3)=0}[/tex]

So, here either (x + 13) = 0 or (x - 3) = 0, when you equate both of them with 0, you will get x = -13 and x = 3

Hence, The required answer is -13 and 3

Answer:

9 square units

Step-by-step explanation:

Create a rectangle around the polygon of the dimensions:

4 spaces wide, 4 spaces tall

The area of the rectangle is 4 * 4 = 16.

Subtract the non shaded triangles which aren't taken up by the polygon:

There are two 1 by 3 triangles, one 2 by 1 triangle, and one 2 by 3 triangle.

The total sum of these areas is:

2 * [(1 * 3) / 2] + [(2 * 1) / 2] + [(2 * 3) / 2]

= 3 + 1 + 3

= 7

So, the area of the polygon is 16 - 7 = 9 square units.

Answer:

9 sq units

Step-by-step explanation:

entered it in rsm its correct

[tex] \sf \dashrightarrow \: - \frac{2}{5} - ( - \frac{3}{10} ) - ( - \frac{4}{7} )[/tex]

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to +

[tex] \sf \dashrightarrow \: - \frac{2}{5} + \frac{3}{10} + \frac{4}{7} [/tex]

Calculate the LCM of denominators

[tex] \sf\frac{ - 28 + 21 + 40}{70} [/tex]

Calculate the difference

[tex] \bf \underline{ \underline \frac{33}{70} }[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-2}{5}-\left(-\dfrac{3}{10}\right)-\left(-\dfrac{4}{7}\right)[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-2}{5}+\dfrac{3}{10}+\dfrac{4}{7}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-28+21+40}{70}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-7+40}{70}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{33}{70}[/tex]

Answer:

Approximately [tex]35.2[/tex] points.

Step-by-step explanation:

Let random variables [tex]X_{1},\, \dots,\, X_{30}[/tex] denote the score of those [tex]30[/tex] test-takers. These random variables are independently and identically distributed. In other words, the scores follow the same distribution and are independent from one other.

While the exact distribution of each score is unknown, the mean and variance of this distribution are given: [tex]\mu = 1083[/tex] and [tex]\sigma = 193[/tex].

By the Central Limit Theorem, the mean (average) [tex]\overline{X}_{n}[/tex] of a sufficiently large number of such observations would follow a normal distribution. The mean of that distribution would be [tex]\mu[/tex] (same as the mean of the observations) while the variance [tex]{\rm Var}(\overline{X}_{n})[/tex] would be [tex](\sigma^{2} / n)[/tex].

Take the square root of variance to find the value of the corresponding standard deviation:

[tex]\begin{aligned}& \sqrt{{\rm Var}(\overline{X}_{n})} \\ =\; & \sqrt{\frac{\sigma^{2}}{n}} \\ =\; & \sqrt{\frac{193^{2}}{30}}\\ \approx\; & 35.2\end{aligned}[/tex].

Answer:

x = 8/3

Step-by-step explanation:

1. Subtract 7 from both sides.

-3x + 7 = -1

-7 -7

-------------------

-3x = -8

2. Divide both sides by -3

-3x = -8

---- ----

-3 -3

x = 8/3

Step-by-step explanation:

To find a, the leading coeffiecent of the quadratic is a.

So a is 2.

To find b, we must use the formula

[tex] - \frac{b}{2a} [/tex]

[tex] \frac{ - ( - 3)}{2(2)} = \frac{3}{4} [/tex]

So b=3/4.

To find c, plug in 3/4 into the function,

which we get

[tex]2( \frac{9}{16} ) - 3( \frac{3}{4} ) + 21[/tex]

[tex] \frac{9}{8} - \frac{9}{4} + 21 = \frac{9}{8} - \frac{18}{8} + 21 = - \frac{9}{8} + 21 = 19.875[/tex]

So c=19.875

Hey there!

12: 1, 2, 3, 4, 6, & 12

30: 1, 2, 3, 5, 6, 10, 15, & 30

75: 1, 3, 5, 15, 25, & 75

LIKE TERMS: 1 and 3

GCF: 3

Therefore, your answer is: 3

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

The area of the garden enclosed by the fencing is

A(x, y) = xy

and is constrained by its perimeter,

P = x + 2y = 200

Solve for x in the constraint equation:

x = 200 - 2y

Substitute this into the area function to get a function of one variable:

A(200 - 2y, y) = A(y) = 200y - 2y²

Differentiate A with respect to y :

dA/dy = 200 - 4y

Find the critical points of A :

200 - 4y = 0   ⇒   4y = 200   ⇒   y = 50

Compute the second derivative of A:

d²A/dy² = -4 < 0

Since the second derivative is always negative, the critical point is a local maximum.

If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.

Answer:

those weights sure are mean

Step-by-step explanation:

they say their mean so their mean

Considering the discrete distribution, it is found that the desired measures are given as follows:

a) 0.86.

b) 0.57.

c) 0.45.

d) 0.14.

e) 0.43.

f) 3.02.

g) 1.31.

According to the table, it is given by:

P(X = 1) = 0.14.

P(X = 2) = 0.29.

P(X = 3) = 0.12.

P(X = 4) = 0.31.

P(X = 5) = 0.14.

Item a:

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - P(X = 1) = 1 - 0.14 = 0.86[/tex]

Item b:

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - P(X = 1) - P(X = 2) = 1 - 0.14 - 0.29 = 0.57[/tex]

Item c:

P(X > 3) = P(X = 4) + P(X = 5) = 0.31 + 0.14 = 0.45.

Item d:

P(X < 2) = P(X = 1) = 0.14.

Item e:

[tex]P(X \leq 2) = P(X = 1) + P(X = 2) = 0.14 + 0.29 = 0.43[/tex].

Item f:

The mean is given by the sum of each outcome multiplied by it's respective probability, hence:

E(X) = 0.14(1) + 0.29(2) + 0.12(3) + 0.31(4) + 0.14(5) = 3.02.

Item g:

The standard deviation is given by the square root of the sum of the difference squared of each observation and the mean, multiplied by it's respective probabilities, hence:

[tex]\sqrt{V(X)} = \sqrt{0.14(1-3.02)^2 + 0.29(2-3.02)^2 + 0.12(3-3.02)^2 + ... + 0.14(5-3.02)^2} = 1.31[/tex]

More can be learned about discrete probability distributions at https://brainly.com/question/24855677

Answer:

Bobby has 45 beads

Step-by-step explanation:

Let x be the number of beads Bobby has.

Then, (x + 30) is the number of beads Alvin has.

Then, 3 (x + 30) is the number of beads Cathy has.

3 (x + 30) + (x + 30) + x = 345

3x + 90 + x + 30 + x = 345

5x + 120 = 345

5x = 225

x = 45

Therefore, Bobby has 45 beads.

Answer:

  150 in³

Step-by-step explanation:

We want to find half the volume of a rectangular pyramid. The volume of the whole pyramid is given by the formula ...

  V = 1//3LWH

  V = 1/3(5 in)(15 in)(12 in) = 300 in³

Then the volume of the half that is not filled with marbles is ...

  1/2V = 1/2(300 in³) = 150 in³

150 cubic inches of marbles are needed to finish filling the container.

Answer:

11,200

Step-by-step explanation:

You can look up "Meters to Centimeters" and that should help you in the future

Answer:

11,200

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

First, if you asked to divide a fraction then the fraction on the right will be inversed

[tex] - 3 \div ( - \frac{2}{5} ) = - 3 \times - \frac{5}{2} [/tex]

then from here, you multiply the fraction

[tex] = \frac{15}{2} [/tex]

or

[tex]7 \frac{1}{2} [/tex]

pls give brainliest

Answer:

Step-by-step explanation:

sorry I tried but it is hard

#1

100+200+300..10000

Now

[tex]\\ \rm\Rrightarrow S_{100}=\dfrac{100}{2}(100+10000)=50(10100)=505000[/tex]

#2

[tex]\\ \rm\Rrightarrow x^2+(x+1)^2=21[/tex]

[tex]\\ \rm\Rrightarrow x^2+x^2+2x+1=21[/tex]

[tex]\\ \rm\Rrightarrow 2x^2+2x=20[/tex]

[tex]\\ \rm\Rrightarrow x^2+x-10=0[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-1\pm\sqrt{1-40}}{2}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-1\pm\sqrt{-39}}{2}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-1\pm \sqrt{39}i}{2}[/tex]

Answer:

a starting value of -1/2 so its starts at -1/2 so lets see which ones start at that

not a

not b

yes c

this isn't a function

and no change so

not a

not b

yes c

yes d(not a function)

c

Hope This Helps!!!

[tex] \rightarrow4 \times \frac{3}{5} = 12 \times \frac{1}{5} \\ [/tex]

[tex] \rightarrow \frac{12}{5} = \frac{12}{5} \\ [/tex]

[tex] \rightarrow \: lhs \: = \: rhs[/tex]

Hence , 4 x 3/5 =12 ×1/5

Let's see

We know

So

Hence verified

Answer:

Given:

[tex] \: [/tex]

To Find:

[tex] \: [/tex]

Solution:

Let,

So,

length will be 2b + 3

[tex] \: [/tex]

As, we know:

[tex] \bigstar \quad {\underline{ \boxed{ \green{Perimeter = 2 ( length + breadth ) }}}} \quad \bigstar[/tex]

➝ 2[(2b + 3) + b)] = 252

➝ 2( 3b + 3 ) = 252

➝ 6b + 6 = 252

➝ b + 1 = 42

➝ b = 41

[tex] \: [/tex]

Now putting the value of b in second equation:

➝ l = 2(41) + 3 = 85

[tex] \: [/tex]

Hence,

[tex] \: [/tex]

Check:

2( l+b ) = 252

➝ 2( 85 + 41 )

➝ 2( 126 )

➝ 252

[tex] \: \: \: \: \: \: { \sf{ \mathbb{ \pink{Formula's \: for \: Perimeter}}}}[/tex]

★ Triangle = Sum of all sides

★ Square = 4 × Side

★ Rectangle = 2( l + b )

★ Circle = 2πr

Answer:

85%

Step-by-step explanation:

Johny answered [tex]\frac{17}{20}[/tex] questions correctly. To change this into percent, just multiply both the numerator and denominator by the number that makes the denominator equal 100. In this case, 5 would make 20 equal 100, so we multiply both the top and bottom by 5.

[tex]\frac{17}{20} *\frac{5}{5}=\frac{85}{100}[/tex]

Your numerator will be your percentage if the denominator is 100.

Answer:

You are so dum i can answer it in less than 5 seconds.

Step-by-step explanation:

Answer:

Step-by-step explanation:

P(E') = 1 - P(E)

       [tex]= 1-\dfrac{5}{13}\\\\\\=\dfrac{13}{13}-\dfrac{5}{13}\\\\\\=\dfrac{8}{15}[/tex]

P(E') -> complement of the event.

Answer:

Ocupa los miles.

Step-by-step explanation:

400,000

30,000

2,000

70

9

Probability of getting the keychain = 1/2

Probability of getting red hat = 1/3

Probability of getting black sweatshirt = 1/2

Probability of all 3 = 1/2 x 1/3 x 1/2 = 1/12

Answer: A. 1/12

Answer: a

Step-by-step explanation: i did it