what measure do seismologists use to calculate the distance from a seismic receiving station to the epicenter of an earthquake? group of answer choices the time interval between the first p wave and the last surface wave the magnitude of the ground acceleration of surface wave passing a receiving station the time elapsed between the first p wave arrivals from the first and last aftershocks the time interval between the arrivals of the first p and s waves the amplitude of the strongest s wave

Your power usage when pulling the box is 125 Watts. It takes 20 seconds to move a box 10 meter's along a rough surface when applying a continuous 250 n force.

Given: force = 250 N; distance = 10 m; speed = distance/time (10/20); speed = 0.5 m/s

W = work completed, where W = 250*10 = 2500 Joules.

Your labour of 2500 J by pulling the box

Thermal energy produced—considering that the box's surface and interior are both made of wood. Therefore, the kinematic friction coefficient is 0.3.

The thermal energy is therefore 75 N

thermal energy = 75*10 = 750 Joules, or thermal energy = force*d

force = mu

 force= 0.3*250.

So pulling the Box produces 750 Joules of thermal power.

Power exerted = force* v

= 250*0.5

=125 Watts

so, The power exerted by you while pulling box is 125 Watts.

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The minimum speed at which a car can leave the road at the top is 47.47 m/s

Following are the calculations for the minimal speed at which a vehicle can veer off the road;

The hill has a radius of 230 m

Fc = Fn

[tex]\frac{mv^{2} }{r} = mg \\\frac{v^{2} }{r} =g\\v^{2} =rg \\v=\sqrt{rg}[/tex]

where;

The curving road's radius is 230 meters, and

the acceleration caused by gravity is 9.8 meters per second.

[tex]v = \sqrt{230* 9.8}[/tex]

r = 47.47

As a result, 47.47 m/s is the lowest speed at which a vehicle can exit the road at the top.

Find the approximate centripetal acceleration caused by gravity, g, in meters per second squared, and the radius of the vertical circular motion, r, in meters. Step 2: Using the formula vmin=rg v min = r g, get the object's minimum speed (the speed at the top of the circle).

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Car A's frequency is determined to be 398.4 Hz.

The frequency heard by car A is calculated using the following equation.

f = fs(v - v₀) / (v - vs)

where;

v is the speed of sound = 343 m/s

v₀ is the speed car B = 19.2 m/s

vs is the speed of car A = 22 m/s

fs is the frequency of car A = 395 Hz

f is the frequency of car B = ?

f = 395(343 - 19.2) / (343 - 22)

The frequency will be calculated as below,

f = 395(1.0087)

f = 398.4 Hz

Therefore, car A's frequency is determined to be 398.4 Hz.

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Answer:

In a unit government, all the powers of government are moved around in the central government where in turn in a federal government, the powers of government are divided between the center and the units.

Explanation:

I hope this helps.

magnetic field caused by the combination of wires to cancel out, the current will flow in a direction . The current will therefore move in the other direction,. The outside wire is experiencing a 15.83 A current.

The electric current formula, I=V/R, can be used to determine how much current is flowing. The "current equation," as it is commonly known, is derived from Ohm's Law. The variable "I" denotes current, "V" denotes voltage, and "R" denotes resistance.

Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. A positive terminal receives normal current, which then travels to a negative terminal.

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The layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere. its can't a go to higher layers because it would be  affected by density.

The troposphere servesv as the lowest layer of Earth's atmosphere however it has the mass (about 75-80%) of the atmosphere  and most of  tthe types of clouds  can be seen in the troposphere, then the weather occurs within this layer.

It should be noted that the troposphere has the highest density, as well as the greatest air pressure,  however the water vapor, and a temperature range from 62,  layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere.

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Answer:

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What is the condition for a force to do work on a body ?

Question

What is the condition for a force to do work on a body ?

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Solution

The condition of force to do some work is that the force should be along the direction of displacement.

work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.

Work Done = Force x Distance x Cos theta

For work to be done, the force must be applied and must not be zero.

The body on which the force is applied must move in one direction or the other and hence the S must not be zero.

The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.

Answer:

5 g

Explanation:

500 mg x 10 = 5000 mg

5000 x 10^-3 g = 5 g

Hello..!

To solve the problem and calculate the number of pills in the package, we will use the conversion factor.

The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.

Find out that 1 gram has a total of 1000 mg.

Problem:

How many g are in a carton containing 10 tablets of 500 mg each?

According to the previous text we can say that the conversion factor would be:

[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]

Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:

[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]

We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:

[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]

We conclude that one box contains 5 grams of tablet, option 1.

[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

Answer:

To find the displacement when the velocity is changing, a velocity-time graph is needed. Normally, velocity is plotted on the y-axis (the vertical axis) and time is plotted on the x-axis (the horizontal axis). The area under the line on a velocity-time graph is equal to the displacement of the object.

Explanation:

I hope this helps

Based on the value of the mass of the tool and the force of gravity on that planet, the gravitational acceleration of the planet is 7.8 m/s².

The mass and force of gravity acting on a body are related by the formula given below:

Force of gravity = mass * gravitational acceleration

The mass of a body is constant but the force of gravity acting on a body or the weight of the body varies depending on the value of the gravitational acceleration.

Considering the given values:

Mass of tool = 2.5 kg

Force of gravity acting on the tool = 19.5

gravitational acceleration = 19.5 / 2.5

gravitational acceleration = 7.8 m/s²

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A single collision results in a loss of 42% of the object's kinetic energy.

Kinetic energy is equal to 0.5 x mass x v2.

kinetic energy coming in = 0.5 x m x v2

v/u = Coefficient of restitution

0.76 = v/u

v = 0.76u

Kinetic energy expended = 0.5 x m x 0.76²

Kinetic energy expended = 0.5 x m x 0.5776

Kinetic energy expended = 0.5776 (0.5 x m x )

The kinetic energy that is coming in is 0.5 x m x x2.

kinetic energy expended = 0.5776 x (incoming kinetic energy)

The entering kinetic energy is equal to 57.76% of the exiting kinetic energy, as can be seen from the above.

A loss of energy of 100 - 57.76 = 42.24%

Therefore, a single collision results in a loss of 42.24% of the object's kinetic energy.

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The answers include the following:

Thus is referred to as the physical property of matter that causes it to experience a force when placed in an electromagnetic field. We should also note that like poles repel and unlike poles attract.

When the styrofoam is rubbed, it becomes negatively charged which when placed in contact with another neutral charge will result in the repulsion. In the case in which the unrubbed side of the styrofoam is placed near a neutral charge there will also be repulsion.

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The speed of light in miles per second (mi/s) is 186,000 mi/s.

The distance travelled by light in a year is known as light-year. This distance travelled by light in a year depends on the speed of light.

The speed of light in a year is given as 982,080,000 ft/s. The unit of this speed of light in feet per seconds can be converted into miles per second.

The speed of light in miles per second (mi/s) is calculated by using the following conversion factor.

1 mile = 5280 feet

982,080,000 ft/s = 982,080,000 ft/s x 1 mile/5280 ft

982,080,000 ft/s = 186,000 miles/s

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The power that firefighter needed to reach the top of the building in 55s is equal to  463.3 Watts.

Power can be described as the rate of doing work and is also defined as the work done in unit time. The S.I. unit of power is Joule/second or Watt (W). The mathematical expression for power is mentioned below.

Power = work/ time

P = W/ t

Given, the height of the building, h = 20 m

The total mass of the firefighter and backpack, m =  85 + 45 = 130 Kg

The time taken to reach the top, t = 55 sec

The power that will be needed can be determined as:

[tex]{\displaystyle {P = \frac{m\times g\times h}{t}[/tex]

[tex]{\displaystyle {P = \frac{130\times 9.8\times 20}{55}[/tex]

P = 463.3 Watt

Therefore, with the power of 463.3 Watts, a firefighter will reach the top in 55s.

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4.1510^-3 tesla the magnitude of the magnetic field required to make the electrons hit the top of the screen

v=0.7×10^8m/s

q=1.6×10^-19 C

B= ?

Voltage= 15,00 V

r= 20cm= 0.2 m

r=mVqB

B=mv/qr

B=4.1510^-3 tesla

To observe magnetic forces, one can utilize a magnetic field, an electric current, a changing electric field, or a vector field surrounding a magnet. Magnetic compass needles and other permanent magnets point in the general direction of magnetic fields resembling those on Earth. Electrically charged particles move in a helical or circular pattern in magnetic fields. Electric motors operate on this force, which is applied to electric currents in wires in a magnetic field.

Magnetic fields can be visualized as continuous lines of force or magnetic flux that travel from south to north magnetic poles. The lines' density reveals the magnetic field's strength. One or more of a magnet's poles are

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Answer:

See below

Explanation:

Vertical component of the kick-off velocity is  8.4 sin21° = 3.01 m/s

Find the time-point where vertical velocity = 0   the ball is in the air for twice this long  ( as it still has to fall back down to the ground)

vf = vo + at

0  = 3.01 m/s   - 9.81 t     shows t = .307   twice this is .614 sec  

  ( what a sorry kick !)

Among the given options the vehicle that has the most kinetic energy is a 900-kg car traveling 80 km/h

KE = 1 / 2 m v²

KE = Kinetic energy

m = Mass

v = Velocity

For A,

m = 1100 kg

v = 60 km / h

KE = 1 / 2 * 1100 * 60²

KE = 1980000 J

KE = 1980 KJ

For B,

m = 2000 kg

v = 50 km / h

KE = 1 / 2 * 2000 * 50²

KE = 2500000 J

KE = 2500 KJ

For C,

m = 900 kg

v = 80 km / h

KE = 1 / 2 * 900 * 80²

KE = 2880000 J

KE = 2880 KJ

For D,

m = 300 kg

v = 100 km / h

KE = 1 / 2 * 300 * 100²

KE = 1500000 J

KE = 1500 KJ

KEc > KEb > KEa > KEd

Therefore, the 900-kg car traveling 80 km/h has the most kinetic energy

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If there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force,the net force of an object is 0N and acceleration is 6N.

When compared to displacement and velocity, acceleration is like the wrathful, flaming dragon of motion variables. People may be terrified of it, it might be harmful, and if it's enormous, it draws your attention. When you're in a fast-turning corner in a car or go-kart or when you're in a plane during takeoff, you can feel your own acceleration.

Since velocity depends on both speed and direction, you can only accelerate by changing either one or the other, if not both. The object will be moving faster if the acceleration is pointing in the same direction as the velocity. Additionally, the item will slow down if the acceleration is pointing in the opposite direction from the direction of the velocity.

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The car speeds remains constant.

Using the following equation for momentum:

Pi=Pf

(c=car and r=rock)
              McVc + MrVr = McV'c + MrV'r

Initially
                         Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc

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Answer:

Explanation:

Given:

φ₁ = 350 V  -  potential of point A

φ₂ = 130 V - potential of point B

A = 4.7·10⁻⁴ J - Work of the electric field

______________________

Q - ?    

The magnitude of the electric charge:

Q = J / Δφ

Potential difference:

Δφ = φ₁ - φ₂ = 350 - 130 = 120 V

Then:

Q = J / Δφ = 4.7·10⁻⁴ / 120 ≈ 3.9·10⁻⁶  C  or  Q

Q = 3.9 mkC  

The distance travelled by the plane across the runway is determined as 1,620 m.

The distance travelled by the plane across the runway is calculated by applying the following equation.

v² = u² + 2as

where;

The initial velocity of the plane, u = 0, since it started from rest.

v² = 0 + 2as

s = v²/2a

The given parameters;

s = (72²)/(2 x 1.6)

s = 1,620 m

Thus, the distance travelled by the plane along or across the runway depends on the final velocity of the plane and the acceleration of the plane.

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The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person

Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.

Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.

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By using  Rayleigh criterion principle, we can calculate the Fundamental resolution limit would be 20.33 x [tex]10^{-9}[/tex] radians

The Rayleigh criterion for the diffraction limit to resolution states that two images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other.

According to the Rayleigh criterion principle, we have

Ф = 1.22 λ/D

where Ф is the resolution limit in radians

λ = wavelength of the light

D = diameter of the lens or the telescope

putting  the appropriate values, we get

Ф  = 1.22 x 500 x [tex]10^{-9}[/tex] / 30

Ф   = 20.33 x [tex]10^{-9}[/tex] radians

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The following formula can be used to determine an object's density if it is spherical.

ρ = 3/4 x π x r³

Here, r denotes the spherical object's radius.

and is a constant in mathematics with the value 22/7.

Assume that the object's initial diameter is d.

As a result, it will have a radius of = d/2 = 0.50d.

Let's enter this value and calculate density as 1.

ρ₁ = 3/4 x π x (r)³

ρ₁ = 1/2 x 22/7 x (0.5d)³

The object is currently being compressed so that its diameter is reduced to a fourth of what it was.

The object's new diameter would be d/2 = 0.50d.

The new radius would be 0.50d/2 = 0.25d as a result.

Find the new density 2 now.

ρ₂ = 1/2 x 22/7 x (0.25d)³

Compare numbers 1 and 2 now.

3/4 x 22/7 x (0.25d)3 divided by 3/4 x 22/7 x (0.5d)3 equals 2/1.

1/2 and 22/7 can be canceled here.

ρ₂/ρ₁ = (0.25d)³ / (0.5d)³

d is terminated.

ρ₂/ρ₁ = 0.125

ρ₂ = 0.125 ρ₁

The original density is 1, and the revised density is 2.

Since its new density would be 0.125 times that of its original, we can conclude that.

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The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J

Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.

Elastic potential energy = Kinetic energy

Kinetic energy = 110 J

Elastic potential energy = 1 / 2 k x²

Kinetic energy = 1 / 2 m v²

k = Spring constant

x = Displacement

m = Mass

v = Velocity

If friction is ignored,

1 / 2 k x² = 1 / 2 m v²

v / x = √ ( k / m )

Therefore, the maximum elastic potential energy store of the ball is 110 J

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Answer: That is not a question.

Explanation: It is a random jumble of letters. It also has no question mark.

Saturn radiates even more excess energy than Jupiter Helium rain gives off heat as it differentiates toward Saturn's center. Option B.

Its density is so low that it floats on water. Like Jupiter, Saturn emits almost twice as much energy as it receives from the Sun. This is because it has its own internal heat source driven by the slow gravitational collapse that began with the planet's formation. The Jupiter planet draws heat from the Sun and from within.

Jupiter produces a lot of internal heat and emits thermal radiation to release this heat. In fact, Jupiter produces so much internal heat that it emits almost twice as much energy as it receives from the Sun. Hydrogen exists in a liquid metallic state around the central rocky core and surrounds the inner half of the planet. Compared to Jupiter, Saturn's mass and volume consist of this conductive metallic liquid which may partly explain why Saturn's magnetic field is much weaker.

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Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

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In the absence of air resistance, the only force acting on both objects would be gravity. Both objects would experience the same 9.8 m/s² acceleration toward the ground.

Since the initial conditions of both projectiles are identical, the velocities of both projectiles will be the same at all times. Therefore, both projectiles will attain a zero vertical velocity at the same time, and it is at this point that they simultaneously reach their respective maximum heights.

The maximum heights will not be the same, and they will differ by precisely the amount of height difference between the launch points.

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It will take 11 seconds for a car to travel 330 m at a speed of 30.0 m/s

By going through the formula of calculating the speed of the vehicle

that is, S=D/T

We get the equation T=D/S.........(i)

Where T stands for Time

D stands for Distance

S stands for Speed

Now, as per the given question

Distance(D)= 330 meters

Speed(S)= 30.0 meters per second

Time(T)= ?

Putting the values in equation (i),

                      T=330 meters/30 meters per second

                      T = 11 seconds.

Therefore, A car moving at a speed of 30.0 meters per second will traverse 330 meters in 11 seconds.

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