Answer:In physics, energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.[note 1] Energy is a conserved quantity; the law of conservation of energy states that energy can be converted in form, but not created or destroyed. The SI unit of energy is the joule, which is the energy transferred to an object by the work of moving it a distance of 1 metre against a force of 1 newton.
Common forms of energy include the kinetic energy of a moving object, the potential energy stored by an object's position in a force field (gravitational, electric or magnetic), the elastic energy stored by stretching solid objects, the chemical energy released when a fuel burns, the radiant energy carried by light, and the thermal energy due to an object's temperature.
Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.
Living organisms require energy to stay alive, such as the energy humans get from food. Human civilization requires energy to function, which it gets from energy resources such as fossil fuels, nuclear fuel, or renewable energy. The processes of Earth's climate and ecosystem are driven by the radiant energy Earth receives from the sun and the geothermal energy contained within the earth.
Explanation:
Some forms of energy (that an object or system can have as a measurable property)
Type of energy Description
Mechanical the sum of macroscopic translational and rotational kinetic and potential energies
Electric potential energy due to or stored in electric fields
Magnetic potential energy due to or stored in magnetic fields
Gravitational potential energy due to or stored in gravitational fields
Chemical potential energy due to chemical bonds
Ionization potential energy that binds an electron to its atom or molecule
Nuclear potential energy that binds nucleons to form the atomic nucleus (and nuclear reactions)
Chromodynamic potential energy that binds quarks to form hadrons
Elastic potential energy due to the deformation of a material (or its container) exhibiting a restorative force
Mechanical wave kinetic and potential energy in an elastic material due to a propagated deformational wave
Sound wave kinetic and potential energy in a fluid due to a sound propagated wave (a particular form of mechanical wave)
Radiant potential energy stored in the fields of propagated by electromagnetic radiation, including light
Rest potential energy due to an object's rest mass
Thermal kinetic energy of the microscopic motion of particles, a form of disordered equivalent of mechanical energy
Main articles: History of energy and timeline of thermodynamics, statistical mechanics, and random processes
A wire is 24.5 m long at 4.00°C and is 1.40 cm longer at 34.0°C. Find the wire's coefficient of linear expansion (in (°C)−1)
Answer:
1.9×10⁻⁵ °C⁻¹
Explanation:
Coefficient of linear expansion: This can be defined as as increase in length of a material, per unit length per degree rise in temperature, The S.I unit is (K⁻¹).
From the question above,
α = ΔL/L(T₂-T₁)................... Equation 1
Where α = coefficient of linear expansion, ΔL = Change in length, L = original length, T₁ = Initial Temperature, T₂ = Final temperature.
Given: ΔL = 1.4 cm = 0.014 m, L = 24.5 m, T₁ = 4.00°C, T₂ = 34°C
Substitute these values into equation 1
α = 0.014/[24.5(34-4)]
α = 0.014/735
α = 1.9×10⁻⁵ °C⁻¹
Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 20 cm. The two liquids do not mix. What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.
Answer:
Difference in height = 7.5 cm
Explanation:
We are given;.
Height of ethyl alcohol;h2 = 20 cm = 0.2 m
Density of glycerin: ρ1 = 1260 kg/m³
Density of ethyl alcohol; ρ2 = 790 kg/m³
To get the difference in height, the pressure at the top of the open end must be equal to the pressure at the point where the liquids do not mix since both points will be at different levels after the pouring.
Thus;
P1 = P2
Formula for pressure is; P = ρgh
Thus;
ρ1 × g × h1 = ρ2 × g × h2
g will cancel out to give;
ρ1 × h1 = ρ2× h2
Making h1 the subject, we have;
h1 = (ρ2× h2)/ρ1
h1 = (790 × 0.2)/1260
h1 = 0.125 m
Difference in height will be;
Δh = h2 - h1
Δh = 0.2 - 0.125
Δh = 0.075 m = 7.5 cm
The difference in height between the top surface of the glycerin and the top surface of the alcohol as per Pascal's law is 7.5 cm.
What is Pascal's law?As per Pascal's law, "The pressure at any point of the vessel filled with incompressible liquid is same".
Given data -
The height of both section is, h2 = 20 cm = 0.20 m.
The density of glycerine is, [tex]\rho_{1} = 1260 \;\rm kg/m^{3}[/tex].
The density of alcohol is, [tex]\rho_{2} = 790 \;\rm kg/m^{3}[/tex].
The pressure at the top of the open end must be equal to the pressure at the point where the liquids do not mix since both points will be at different levels after the pouring. Therefore,
P1 = P2
The formula for pressure is;
P = ρgh
Thus;
ρ1 × g × h1 = ρ2 × g × h2
ρ1 × h1 = ρ2× h2
h1 = (ρ2× h2)/ρ1
h1 = (790 × 0.2)/1260
h1 = 0.125 m
Difference in height will be;
Δh = h2 - h1
Δh = 0.2 - 0.125
Δh = 0.075 m
Δh = 7.5 cm
Thus, we can conclude that the difference in height between the top surface of the glycerin and the top surface of the alcohol is 7.5 cm.
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A 0.450-kg ice puck, moving east with a speed of 5.34 m/s , has a head-on collision with a 0.990-kg puck initially at rest. Assume that the collision is perfectly elastic.1. What is the speed of the 0.450-kg puck after the collision?2. What is the direction of the velocity of the 0.450-kg puck after the collision?3. What ise the speed of the 0.990-kg puck after the collision?4. What is the direction of the velocity of the 0.990-kg puck after the collision?
(1) -2.0025m/s.
(2) It moves west.
(3) 3.3375m/s.
(4) It moves east.
Explanation:
Assuming the collision occurred in an isolated system. This means that total momentum of the system of pucks is conserved. Since no external forces are acting on these pucks, the momentum of the pucks before collision is equal to the momentum of the pucks after collision. i.e
(p₁)₀ + (p₂)₀ = (p₁)₁ + (p₂)₁ -------------(i)
Where;
(p₁)₀ = momentum of the 0.45kg puck before collision
(p₂)₀ = momentum of the 0.990kg puck before collision
(p₁)₁ = momentum of the 0.45kg puck after collision
(p₂)₁ = momentum of the 0.990kg puck after collision
But;
(p₁)₀ = m₁ u₁
[m₁ = mass of the 0.45kg, u₁ = speed of the 0.45kg before collision]
(p₂)₀ = m₂u₂
[m₂ = mass of the 0.990kg, u₂ = speed of the 0.990kg before collision]
(p₁)₁ = m₁v₁
[m₁ = mass of the 0.45kg, v₁ = speed of the 0.45kg after collision]
(p₂)₁ = m₂v₂
[m₂ = mass of the 0.990kg, v₂ = speed of the 0.990kg after collision]
Equation (i) then becomes;
m₁ u₁ + m₂u₂ = m₁v₁ + m₂v₂ ----------------(ii)
From the question:
m₁ = 0.450kg
u₁ = +5.34m/s [Taking east direction as positive]
m₂ = 0.990kg
u₂ = 0m/s [since the second puck is initially at rest]
Substitute these values into equation (ii)
(0.450 x 5.34) + (0.990 x 0) = 0.45 v₁ + 0.990 v₂
2.403 + 0 = 0.45 v₁ + 0.990 v₂
2.403 = 0.45 v₁ + 0.990 v₂ ------------------(iii)
Also, since the collision is perfectly elastic, it means that the kinetic energy is conserved. i.e the total kinetic energy before collision is equal to the total kinetic energy after collision.
=> [tex]\frac{1}{2}[/tex]m₁ u²₁ + [tex]\frac{1}{2}[/tex]m₂u²₂ = [tex]\frac{1}{2}[/tex]m₁v²₁ + [tex]\frac{1}{2}[/tex]m₂v²₂
Substitute the necessary values into the above equation:
[[tex]\frac{1}{2}[/tex] x 0.45 x 5.34²] + [0] = [[tex]\frac{1}{2}[/tex] x 0.45 x v²₁] + [[tex]\frac{1}{2}[/tex] x 0.990 x v²₂]
[6.41601] = [0.225 x v²₁] + [0.495 x v²₂] ------------------(iv)
Now let's solve equations (iii) and (iv) simultaneously
2.403 = 0.45 v₁ + 0.990 v₂
6.41601 = 0.225 x v²₁ + 0.495 x v²₂
let
v₁ = x
v₂ = y
2.403 = 0.45 x + 0.990 y ------------(5)
6.41601 = 0.225 x² + 0.495 y² -------------(6)
From equation (5), make x subject of the formula
2.403 = 0.45x + 0.990y
0.45x = 2.403 - 0.990y [divide through by 0.45]
x = 5.34 - 2.2y ----------------(m)
Substitute x into equation (6)
6.41601 = 0.225 (5.34 - 2.2y)² + 0.495 y² [expand bracket]
6.41601 = 0.225 [28.5156 - 23.496y + 4.84y²] + 0.495 y² [remove bracket]
6.41601 = 6.41601 - 5.2866y + 1.089y² + 0.495 y²
1.584y² - 5.2866y = 0
y(1.584y - 5.2866) = 0
y = 0 or 1.584y - 5.2866 = 0
y = 0 or 1.584y = 5.2866
y = 0 or y = 3.3375
Since y = v₂ cannot be zero because the puck will definitely move after collision, the second value of y = 3.3375 is considered.
Substitute this value into equation (m)
x = 5.34 - 2.2y
x = 5.34 - 2.2(3.3375)
x = 5.34 - 7.3425
x = -2.0025
Therefore,
x = v₁ = -2.0025m/s
y = v₂ = 3.3375m/s
(1) From the analyses above, the speed of the 0.450kg puck after collision is -2.0025m/s.
(2) Since the speed is negative, it shows that the 0.45kg puck moves opposite the direction at which it was moving before collision. It moves west.
(3) The speed of the 0.990kg puck after collision is 3.3375m/s.
(4) Since the speed is positive, it shows that the 0.990kg puck moves east. Remember that east has been taking as the positive direction.
In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?
Answer:
m = 312.5
Explanation:
Given that,
The focal length of the objecive lens, [tex]f_o=1\ cm[/tex]
The focal length of eye piece, [tex]f_e=2\ cm[/tex]
length of the tube, L = 25 cm
We need to find the magnitude of the overall magnification of the microscope. It is given by the formula as follows :
[tex]m=\dfrac{L}{f_o}\times \dfrac{D}{f_e}[/tex]
D = 25 cm
So,
[tex]m=\dfrac{25}{1}\times \dfrac{25}{2}\\\\m=312.5[/tex]
So, the overall magnification of the microscope is 312.5.
Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Earth is at x
Answer:
The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.
Explanation:
Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon ([tex]m_{E}[/tex], [tex]m_{M}[/tex]) are [tex]5.972\times 10^{24}\,kg[/tex] and [tex]7.349\times 10^{22}\,kg[/tex], respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:
[tex]\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}[/tex]
If [tex]x_{E} = 0\,km[/tex] and [tex]x_{M} = 384,403\,km[/tex], then:
[tex]\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}[/tex]
[tex]\bar x = 4.673\,km[/tex]
The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.
A mass of 2.5 kg of saturated water vapor at 100 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate the work done by the steam during this process. Use steam tables.
Answer:
the work done by the steam during this process = 119.575 kJ
Explanation:
From the information given:
At state 1
Let obtain the specific volume of the saturated vapor from the Saturated water- Pressure table A-5 at the pressure of 100 kPa
[tex]v_1 = v_{g \ 100 \ kPa)[/tex]
[tex]v_1 = 1.6941 \ m^3 /kg[/tex]
where [tex]v_1[/tex] is the specific volume of the saturated vapor at state 1.
At state 2:
From the tables A-6 of Superheated water at the pressure of 100 kPa or 0.1 MPa and at the temperature of 200°C, the specific volume [tex]v_2 = 2.1724 \ m^3 /kg[/tex]
where [tex]v_2[/tex] is the specific volume of the superheated water at state 2.
The workdone by the steam during the process can be expressed by the formula:
[tex]W = P(V_2 -V_1)[/tex]
[tex]W = mP(v_2-v_1)[/tex]
where;
m = mass of the saturated water vapor
P = pressure of the saturated water vapor
[tex]V_2 =[/tex] volume of the superheated water at state 2
[tex]V_1 =[/tex] volume of the saturated water at state 1
Replacing our values ;
W = 2.5 (100) ( 2.1724 -1.6941)
W = 250(0.4783 )
W = 119.575 kPa.m³ [tex]\times \dfrac{1 \ kJ}{1 \ kPa.m^3}[/tex]
W = 119.575 kJ
∴
the work done by the steam during this process = 119.575 kJ
The pendulum consists of two slender rods AB and OC which have a mass of 3 kg/m. The thin plate has a mass of 12 kg/m2 . a) Determine the location ӯ of the center of mass G of the pendulum, then calculate the mass moment of inertia of the pendulum about z axis passing through G. b) Calculate the mass moment of inertia about z axis passing the rotation center O.
Answer:
The answer is below
Explanation:
a) The location ӯ of the center of mass G of the pendulum is given as:
[tex]y=\frac{0+(\pi*(0.3\ m) ^2*12kg/m^2*1.8\ m-\pi*(0.1\ m) ^2*12kg/m^2*1.8\ m)+0.75\ m*1.5\ m *3\ kg/m}{(\pi*(0.3\ m) ^2*12kg/m^2-\pi*(0.1\ m) ^2*12kg/m^2)+3\ kg/m^2*0.8\ m+3\ kg/m^2*1.5\ m} \\\\y=0.88\ m[/tex]
b) the mass moment of inertia about z axis passing the rotation center O is:
[tex]I_G=\frac{1}{12}*3(0.8)(0.8)^2+ 3(0.8)(0.888)^2-\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8-\\0.888)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8-0.888)^2+\frac{1}{12}*3(1.5)(1.5)^2+\\3(1.5)(0.888-0.75)^2\\\\I_G=13.4\ kgm^2[/tex]
c) The mass moment of inertia about z axis passing the rotation center O is:
[tex]I_o=\frac{1}{12}*3(0.8)(0.8)^2+ \frac{1}{3}* 3(1.5)(1.5)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8)^2-\\\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8)^2\\\\I_o=13.4\ kgm^2[/tex]
What is the largest wavelength that will give constructive interference at an observation point 141 m from one source and 355 m from the other source
Answer:
Explanation:
For constructive interference of two coherent light waves at a point , the condition is as follows
path difference = n x wavelength where n is any integer like 1 , 2 , 3 , .... etc .
Given in the question , path difference of light from the two sources
= 355 - 141 = 214 m
So applying the formula above ,
214 = n x wavelength
wavelength = 214 / n
For largest value of wavelength , n should be smallest . The smallest value of n is 1 .
so ,
largest wavelength possible for constructive interference
= 214 / 1
= 214 m .
How many valence electrons does each Cholrine atom have?
Answer:
7 valence electrons is right answer
Explanation:
2 elections in first shell and 5 electrons in second shell which total makes seven electrons.
hope it helped you:)
You throw a 20-N rock vertically into the air from ground level. You observe that when it is a height 14.8m above the ground, it is traveling at a speed of 25.0 m/s upward.
A) Use the work-energy theorem to find its speed just as it left the ground. What is it?
B) Use the work-energy theorem to find its maximum height. What is it?
Answer:
(A) The speed just as it left the ground is 30.25 m/s
(B) The maximum height of the rock is 46.69 m
Explanation:
Given;
weight of rock, w = mg = 20 N
speed of the rock at 14.8 m, u = 25 m/s
(a) Apply work energy theorem to find its speed just as it left the ground
work = Δ kinetic energy
F x d = ¹/₂mv² - ¹/₂mu²
mg x d = ¹/₂m(v² - u²)
g x d = ¹/₂(v² - u²)
gd = ¹/₂(v² - u²)
2gd = v² - u²
v² = 2gd + u²
v² = 2(9.8)(14.8) + (25)²
v² = 915.05
v = √915.05
v = 30.25 m/s
B) Use the work-energy theorem to find its maximum height
the initial velocity of the rock = 30.25 m/s
at maximum height, the final velocity = 0
- mg x H = ¹/₂mv² - ¹/₂mu²
- mg x H = ¹/₂m(0) - ¹/₂mu²
- mg x H = - ¹/₂mu²
2g x H = u²
H = u² / 2g
H = (30.25)² / 2(9.8)
H = 46.69 m
Mass and Weight: What is the mass of an object that experiences a gravitational force of 685 N near Earth's surface where g
Answer:
m = 69.9 kg
Explanation:
The mass and the weight of an object are two different quantities. Mass is basically the amount of matter that is present in a body. It remains same everywhere in the universe and measured in kilograms.
Weight is basically a force. It is the force by which earth attracts everything towards itself. The weight of an object changes from planet to planet, with the change in value of the gravitational acceleration (g).
Therefore, the relation between mass and weight of an object is given by the following formula:
W = mg
m = W/g
where,
m = mass = ?
W = Weight = 685 N
g = 9.8 m/s²
Therefore,
m = (685 N)/(9.8 m/s²)
m = 69.9 kg
The mass of an object that experience a gravitational force of 685N near the earth is approximately 69.90 kg
The mass and weight are 2 different quantities.
The mass of a substance is the amount of matter present in it. Mass is measured in kilograms
The Weight is the measurement of gravitational pull of planet towards the object. Therefore, weight is a force and measured in Newton.
Mathematically, the weight can be express as follows
W = mg
where
m = mass
g = acceleration due to gravity = 9.8 m/s²
Therefore,
685 = 9.8 × m
m = 685 / 9.8
m = 69.8979591837
m = 69.90 kg
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For small angles, does the pendulum's period of oscillation depend on initial angular displacement from equilibrium? Explain.
Answer:
No, the pendulum's period of oscillation does not depend on initial angular displacement.
Explanation:
Given that,
For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.
We know that,
The time period of pendulum is defined as
[tex]T=2\pi\sqrt{\dfrac{l}{g}}[/tex]
Where, l = length of pendulum
g = acceleration due to gravity
So, The time period of pendulum depends on the length of pendulum and acceleration due to gravity.
It does not depend on the initial angular displacement.
Hence, No, the pendulum's period of oscillation does not depend on initial angular displacement.
Danielle exerts a 14.0 N force to compress a spring by a distance of 8.00 cm. What is the spring constant of this spring
Answer:
175 N/m
Explanation:
Given:
Force = F= 14.0 N
Distance = x = 8.00 cm = 0.08 m
To find:
spring constant
Solution:
spring constant is calculated by using Hooke's law:
k = F/x
Putting the values in above formula:
k = 14.0 / 0.08
k = 175 N/m
Sapphire has an index of refraction of 1.77. The critical angle for sapphire in air with an index of refraction of 1.0 is _____ degrees.
Answer:
The critical angle is 34 degree.
Explanation:
Given the index refraction = 1.77
We have to find the critical angle of sapphire when the air has the index of refraction of 1.0.
Use the below formula to find the angle.
sin(θ)c = 1 / n
sin(θ) c = 1 / 1.77
(θ) c = Sin^-1 (0.565)
= 34.4 degree
= 34 degrees.
Thus, the critical angle is 34 degree.
What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F
Answer:
F' = (3/2)F
Explanation:
the formula for the electric field strength is given as follows:
E = F/q
where,
E = Electric Field Strength
F = Force due to the electric field
q = magnitude of charge experiencing the force
Therefore,
F = E q ---------------- equation (1)
Now, if we half the electric field strength and make the magnitude of charge triple its initial value. Then the force will become:
F' = (E/2)(3 q)
F' = (3/2)(E q)
using equation (1)
F' = (3/2)F
When the charge of the particle is tripled, and magnetic field strength is halved, the force increases by factor of 1.5 (1.5 F)
The force experienced by a particle placed in magnetic field is given as;
F = qvB
where;
q is the charge of the particlev is the velocity of the particleB is the magnetic field strengthWhen the charge of the particle is tripled, q₂ = 3q and magnetic field strength is halved, B₂ = 0.5B.
The magnetic force of the particle is determined as;
[tex]F = qvB\\\\ v = \frac{F}{qB} \\\\ \frac{F_1}{q_1B}_1 = \frac{F_2}{q_2B_2}\\\\ F_2 = \frac{F_1 q_2B_2}{q_1 B_1} \\\\ F_2 = \frac{F \times 3q_1\times 0.5B_1}{q_1B_1} \\\\ F_2 = 1.5 F[/tex]
Thus, when the charge of the particle is tripled, and magnetic field strength is halved, the force increases by factor of 1.5 (1.5 F).
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Question 5 of 10
Which statement describes a characteristic of a question that can be
answered through scientific inquiry?
O A. It is constructed in such a way that possible answers can be
tested.
B. It must be related to something that benefits society.
O c. It can be answered using an ethical argument.
D. It can be answered by collecting votes from scientists.
Answer:
A
Explanation:
Ansthe answer is A
Explanation:
It is constructed in such a way that possible answers can be
tested.
A point source emits electromagnetic energy at a rate of 100 W. The intensity 10 m from the source is
Answer:
[tex]I=0.0795\ W/m^2[/tex]
Explanation:
Given that,
Power of electromagnetic energy, P = 100 W
We need to find the intensity at a distance of 10 m from the source. Intensity is equal to the power per unit area. So,
[tex]I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{100}{4\pi (10)^2}\\\\I=0.0795\ W/m^2[/tex]
So, the intensity at a distance of 10 m is [tex]0.0795\ W/m^2[/tex]
A virus has a diameter of 5.2×10−8m. What is the most appropriate prefix for reporting the diameter of the virus?
Answer:
5.2 centimicro meter or 5.2 cμm
Explanation:
Prefixes allow scientists report numbers logically depending on the order of the magnitude of the numbers. For example to represent 4 x 10⁻³m, it is more handy to say : 4 millimetre, where milli- is the prefix for 10⁻³.
Common prefixes are:
deci = 10⁻¹ deca = 10¹
centi = 10⁻² hecto = 10²
milli = 10⁻³ kilo = 10³
micro = 10⁻⁶ mega = 10⁶
nano = 10⁻⁹ giga = 10⁹
pico = 10⁻¹² terra = 10¹²
femto = 10⁻¹⁵ peta = 10¹⁵
Now, let's represent the given diameter: 5.2 x 10⁻⁸ m
Since the 10⁻⁸ prefix is not common (or maybe doesn't even exist), the way around this is to break it into bits such as:
10⁻⁸ = 10⁻² x 10⁻⁶ [10⁻² = centi, 10⁻⁶ = micro ]
10⁻⁸ = centimicro
Therefore, 5.2 x 10⁻⁸ m becomes 5.2 centimicro meter.
The symbol is 5.2 cμm
Where c = centi, μ = micro.
Which is not an example of an external force acting on an object? (1 point)
• a meteor traveling unhindered through space
O a hockey puck striking the back of the net and coming to rest
O a billiard ball bouncing off the rail of a pool table
O a batter hitting a baseball
Answer:
A. a meteor traveling unhindered through space
Explanation:
"For the lowest harmonic of pipe with two open ends, how much of a wavelength fits into the pipe’s length?"
Answer:
0.5 lambda(wavelength)
Explanation:
We know that
The first harmonic for both side open ended pipe is
L= 1/2lambda
So L = 0.5*wavelength
A split highway has a number of lanes for traffic. For traffic going in one direction, the radius for the inside of the curve is half the radius for the outside. One car, car A, travels on the inside while another car, car B, travels at equal speed on the outside of the curve. Which statement about resultant accelerations of the cars is correct
Answer:
The correct one is that the force on B is half of the force on A
Explanation:
Because radius for the inside of the curve is half the radius for the outside and Car A travels on the inside while car B, travels at equal speed on the outside of the curve. Thus force on B will be half on A
A ball is thrown straight up in the air. For which situations are both the instantaneous velocity and the acceleration zero? (Select all that apply.)
Answer:
Therefore, the situation in which both the instantaneous velocity and acceleration become zero, is the situation when the ball reaches the highest point of its motion.
Explanation:
When a ball is thrown upward under the free fall action of gravity, it starts to loose its Kinetic Energy as it moves upward. As the ball moves in upward direction, its kinetic energy gradually converts into its potential energy. As a result the speed of the ball starts to decrease as it moves up. Therefore, at the highest point during its motion, the velocity of ball becomes zero and it stops at the highest point for a moment, and then it starts to fall back down, under the influence of gravitational force.
Therefore, the situation in which both the instantaneous velocity and acceleration become zero, is the situation when the ball reaches the highest point of its motion.
g A person walks 70 m west, then turns and walks 30 m east. Find the average speed and velocity if the time for the total trip is 45 seconds.
Answer:
Average speed = 2.22m/s
Velocity = 0.89 m/s west
Explanation:
(i) Since speed is a scalar quantity, the direction of movement by the person is irrelevant. Therefore,
Average speed = total distance traveled / time taken
Where;
Total distance = 70m + 30m = 100m
Time taken = 45 seconds
Average speed = 100 / 45 = 2.22m/s
(ii) However, velocity is a vector quantity and so the direction of movement by the person is of utmost importance. Therefore,
Velocity = displacement / time taken
Where;
displacement = -70m + 30m [West direction is taken as negative and east is taken as positive]
displacement = -40m [The negative sign just means that the net displacement is in the direction of the West].
Thus, displacement can be written as 40m west.
Therefore,
Velocity = 40 / 45 = 0.89m/s west
Which explanation is based on scientific evidence?
A. Observations made using microscopes reveal that all known
organisms are composed of tiny structures called cells.
B. Magnets have hidden powers that can have health effects.
C. Performing good deeds for other people will make a person happy.
D. illnesses are caused by bad smells in the air.
All known species are made up of small structures called cells, according to observations obtained using a microscope; this theory is supported by empirical data..Option A is corect.
What is the investigation?An investigation is defined as a thorough search or inspection. The investigative process is a series of tasks or procedures that include obtaining evidence, analyzing the material, and developing and validating theories.
Respectfully recognize any information or points of view that contradict your contention. You have to demonstrate to the reader in the refutation why your position is superior to the opposing notion.
Observations made using microscopes reveal that all known organisms are composed of tiny structures called cells the explanation is based on scientific evidence.
Hence option A is corect.
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two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignoring friction, how fast is the wagon moving 3.50 s later?
Answer:
AFter 3.5 s, the wagon is moving at: [tex]4.62\,\,\frac{m}{s}[/tex]
Explanation:
Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):
Net force = 250 N + 178 N = 428 N
Therefore, the acceleration from Newton's 2nd Law is:
[tex]F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}[/tex]
So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:
[tex]v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}[/tex]
defenition of takes place in body cells
Answer:
the nucleus-containing central part of a neuron exclusive of its axons and dendrites that is the major structural element of the gray matter of the brain and spinal cord, the ganglia, and the retina. — called also perikaryon, soma.
Answer:
Your body cells use the oxygen you breathe to get energy from the food you eat. This process is called cellular respiration. During cellular respiration the cell uses oxygen to break down sugar. The opposite takes place in the cells where the blood releases oxygen and picks up carbon dioxide.
A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. It takes him 260 s to make this trip.what is his speed. express answer in 2 significant figures
Answer:
0.7 m/s
Explanation:
The following data were obtained from the question:
Distance travalled (d) = 190 m
Time (t) = 260 secs
Speed (S) =..?
Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed = Distance (d) /time(t)
S = d/t
With the above formula, we can calculate the speed of the security guard as follow:
Distance travalled (d) = 190 m
Time (t) = 260 secs
Speed (S) =..?
S = d/t
S = 190/260
S = 0.7 m/s
Therefore, the speed of the security guard is 0.7 m/s
A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. The speed of the security guard is approximately 0.73 m/s.
Given:
Distance (d) = 190 m
Time (t) = 260 s
To calculate the speed of the security guard, we can use the formula:
Speed = Distance / Time
Speed = 190 / 260 = 0.73 m/s
Therefore, A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. The speed of the security guard is approximately 0.73 m/s (rounded to two significant figures).
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Pls help answer 7 and 8
Answer:
science is the knowledge gained through observations and experimentations
Characteristics
consistency
observability
predictability
testability
tentativeness
components of nature are soil,atmosphere and radiation
What is its inside radius, in centimeters, if it holds 360 g of coffee when filled to a depth of 8.5 cm
Answer:
1.14*10^-3m
Explanation:
We know that
Volume= mass/ density
But
Area x depth= mass/density
πr²*depth= mass/density
r²=m/πdp
So
r= √0.35/3.142*0.085*1000
r= 1.14*10^-3m
When a piano tuner strikes both the A on the piano and a 440 Hz tuning fork, he hears a beat every 2 seconds. The frequency of the piano's A is
Answer:
The frequency is [tex]f = 439.5 \ Hz[/tex]
Explanation:
From the question we are told that
The frequency of the tuning fork is [tex]f_t = 440 \ Hz[/tex]
The beat period is [tex]T = 2 \ s[/tex]
Generally the beat frequency is mathematically represented as
[tex]f_b = \frac{1}{T}[/tex]
[tex]f_b = \frac{1}{2}[/tex]
[tex]f_b = 0.5 \ Hz[/tex]
The beat frequency is also represented mathematically as
[tex]f_b = f_t - f[/tex]
Where [tex]f[/tex] is the frequency of the piano
So
[tex]f = 440 - 0.5[/tex]
[tex]f = 439.5 \ Hz[/tex]