Mass of the given volleyball was 0.32 kg.
What is delivered impulse?Impulse is a measure of instantaneous change. The total momentum of an object is determined from the total change in object mass and object velocity.
Since momentum is equal to the delivered impulse,
J = m (v- u)
Where,
J = impulse delivered (-9.3kg m/s)
u = Initial speed of the ball (4.2 m/s)
v = Final speed of the ball (-24 m/s)
m = mass of the object
-9.3 = m (-24 - 4.2)
-9.3 = m × -28.2
m = 9.3 ÷ 28.2
m = 0.32 kg
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mountain goats can easily scale slopes angled at from horizontal. what are the normal force and the static friction force acting on a mountain goat that weighs 900 n and is standing on such a slope?
Using these formulas, determine the normal and static friction forces acting on the mountain goat.
What is normal force?
The normal force is the pressure that surfaces apply to stop solid objects from piercing one another. The normal force is a force in contact. Two surfaces cannot exert a normal force on one another if they are not in contact.
What exactly is static friction force?
An object experiences static friction when a force is applied to it; as a result, the object resists the applied force and stays at rest until static friction is removed. In kinetic friction, the frictional force opposes an object's motion.
Given:
The 60° angle from horizontal
900 N is the weight of the mountain goat.
To calculate the normal force, the weight perpendicular to the tilt must be resolved. As a result, we can write:
N = W CosΘ
= 900 N(Cos 60°)
= 900 N(0.5) (0.5)
= 450 N
The forces acting in conjunction with the inclination must all be added to determine the static friction force. We document:
F = W sinΘ
= 900 N(sin 60°)
= 900 N(0.8660254038) (0.8660254038)
= 779.42 N
Therefore, the normal force is 450 N, and the static friction force is 779.42 N.
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3. (a) calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 n. (b) what is the work done on the elevator car by the gravitational force in this process? (c) what is the total work done on the elevator car?
(a) Work done on the car by its cable will be 5.92 * [tex]10^{5}[/tex] J.
(b) Work done on the car by the gravitational force will be -5.92 * [tex]10^{5}[/tex] J.
(c) Total work done on the car will be 0 J.
Work done is the product of force and displacement.
Mathematically, Work-done = W = Force * DistanceMass of the car = m = 1500 kg
Distance lifted by the cable = d = 40 m
Frictional force experienced by the car = Fs = 100 N
(a) According to the Newton's second law of motion
F = Fcable - mg - Fs = ma
Fcable = mg + Fs
Work done by the same force = W1
W1 = Fcable * d
W1 = (mg + Fs) * d
W1 = (1500*9.8 + 100) * 40
W1 = 592600
W1 = 5.92 * [tex]10^{5}[/tex] J
(b) Work done by the gravitational force = W2 = mg * d
W2 = 1500*(-9.8)*40
Since the acceleration is acting downwards 'g' will be considered with a negative sign.
W2 = -5.88 * [tex]10^{5}[/tex] J
(c) The total work done on the lift is the work done by the net force exerted on the car during this process:
W3 = Fnet * d
Fnet = -5.88 * [tex]10^{5}[/tex] J + 5.92 * [tex]10^{5}[/tex] J
Fnet = 0
W3 = 0 * 40
W3 = 0 J
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what is the fundamental resolution limit (diffraction limit) for a telescope with a mirror that is 30 meters in diameter at a wavelength of 500 nanometers (green light)? give your answer in degrees or radians.
By using Rayleigh criterion principle, we can calculate the Fundamental resolution limit would be 20.33 x [tex]10^{-9}[/tex] radians
The Rayleigh criterion for the diffraction limit to resolution states that two images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other.
According to the Rayleigh criterion principle, we have
Ф = 1.22 λ/D
where Ф is the resolution limit in radians
λ = wavelength of the light
D = diameter of the lens or the telescope
putting the appropriate values, we get
Ф = 1.22 x 500 x [tex]10^{-9}[/tex] / 30
Ф = 20.33 x [tex]10^{-9}[/tex] radians
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a 70kg skater from side to side on a curved ramp they start at a height of 5m
at the boot on of the ramp they have the speed of 9.5m/s
on the opposite side of the ramp they only reach a maximum height of 4cm
describe the energy stores and transfers that take place as the skater moves form side to side on the ramp
The velocity of the skater will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase. The kinetic energy will converted into potential energy as he moves towards the maximum height.
What is law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
As the skater move from side to side on the curved ramp, his kinetic energy will be converted into potential energy.
Mathematically, it be written as;
K.E = P.E
¹/₂mv² = mgh
where;
m is the mass of the skaterv is the speed of the skater at the lowest pointh is the maximum height attainedg is acceleration due to gravityAs the skater moves from the highest point with zero velocity, he will have maximum potential energy which decreases as he moves towards the center of the ramp. The velocity will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase.
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later the car is traveling along a long straight road when it passes over a hill. the hill has a radius of 230 m. what is the minimum speed the car must have in order to become airborne as it crests the hill?
The minimum speed at which a car can leave the road at the top is 47.47 m/s
What is the minimum speed?Following are the calculations for the minimal speed at which a vehicle can veer off the road;
The hill has a radius of 230 m
Fc = Fn
[tex]\frac{mv^{2} }{r} = mg \\\frac{v^{2} }{r} =g\\v^{2} =rg \\v=\sqrt{rg}[/tex]
where;
The curving road's radius is 230 meters, and
the acceleration caused by gravity is 9.8 meters per second.
[tex]v = \sqrt{230* 9.8}[/tex]
r = 47.47
As a result, 47.47 m/s is the lowest speed at which a vehicle can exit the road at the top.
Find the approximate centripetal acceleration caused by gravity, g, in meters per second squared, and the radius of the vertical circular motion, r, in meters. Step 2: Using the formula vmin=rg v min = r g, get the object's minimum speed (the speed at the top of the circle).
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how much work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed vv to a speed 2v2v?
Using the concepts of work, we got that we need to work three times of the previous work to accelerate the object from a speed v to a speed 2v.
We know that to change the velocity of any object we need to do some work on it.
When an object having some mass m moving with velocity v, then the kinetic energy stored in that object is given by(KE₁) =(1/2)mv².
Now, When an object having some mass m moving with velocity 2v,then the kinetic energy stored in that object is given by(KE₂) =(1/2)m(2v)².
New kinetic energy is =4[(1/2)mv²] or 4KE₁
So, net work to accelerate the object is =KE₂-KE₁
W=4KE₁-KE₁=3KE₁.
Hence, the amount of work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed v to a speed 2v is 3 times the energy stored on a object.
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you pull a box with a constant force of 250 n. the box moves 10 m along a straight path on a rough surface at a constant speed. how much thermal energy is generated in the system of the box and the rough surface?
The thermal energy of the box which is pulled with a force of 250 N to a distance of 10 meters is 2500 J
The force to pull the box = 250 N
The box is moved to a distance of 10 meters
The thermal energy can be found using the formula,
W = F x d
where W is the thermal energy
F is the Force
d is the distance moved
Let us substitute the known values in the above equation, we get
W = 250 x 10
= 2500 J
Therefore, the thermal energy of the box is 2500 J
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What does water's high specific heat capacity explain about water?
A) why water bonds with other molecules
B) why water is often used as a solvent
C) why water is unable to absorb energy
D) why water is liquid at room temperature
Water's high specific heat capacity explains why why water bonds with other molecules.
The correct answer choice is option a.
Why water bonds with other moleculesWater has the ability to easily attract other molecules simply because of the fact its hydrogen and oxygen components is made up of positive and negative ions respectively.
Technically, the bonds in hydrogen possess a form of electrostatic force which makes it very possible for water to bond with other molecules with its high specific heat capacity.
So therefore, we can now confirm and deduce that from the simple note given above that the hydrogen bonds presence in water molecule makes it easy for water to combine with other molecules.
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It takes 6 people pulling with a force of 500. N each to begin moving the opposing team which was pulling with a combined force of 2500. N during a match of tug-of -war. If the total mass of both teams was 2000. kg, what was the force due to static friction? HELP ME .
From the calculations, we have the coefficient of friction as 0.026.
What is the coefficient of static friction?We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.
Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 N
Now we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 N
Then;
Coefficient of friction = Net force/ Normal reaction
= 500 N/(2000 * 9.8) N
= 0.026
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a funny car accelerates from rest through a measured track distance in time t with the engine operating at a constant power p. if the track crew can increase the engine power by a differential amount dp, what is the change in the time required for the run? (use any variable or symbol stated above as necessary.)
dT = -T^4/(2mD^2)dP
P = W/T = FD/T = (m a)D/T
dP = -maD/T^2 dT
dT = -T^2/(maD)dP
V = aT
D = 1/2 a T^2
a = 2D/T^2
dT = -T^4/(2mD^2)dP
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forces and newton’s laws 3.1 Essential Questions How are force and motion related?
According to Newton's law of motion, the direction of motion of an object depends on the direction of the applied force.
What is Newton's first law of motion?
Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force and it will move in the direction of the applied force.
The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object. The more massive an object is, the more inertia the object will possess and vice versa.
Also, the Newton's second law of motion states that the force acting on an object is directly proportional to the product of mass and acceleration of the object.
Mathematically, Newton's second law of motion is given as;
F = ma
F = mv/t
Ft = mv
This law (Newton's second law of motion) is also states that the force applied on an object directly proportional to the rate of change of momentum of the object.
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an engineer cuts a 1.0-m-long, 0.33-mm-diameter piece of wire, connects it across a 1.5 v battery, and finds that the current in the wire is 8.0 a. of what material is the wire made?
The resistivity rho of the piece of the wire will be 1.60 × 10⁻⁸ Ωm. So, the material is copper wire.
Copper is the electrical conductor in many categories of electrical wiring. Copper wire is used in power generation, power transmission, power distribution for telecommunications, electronics circuitry, and countless types of electrical equipment.
The resistivity of a material is the resistance of a wire of that material of unit length and unit area of cross-section. Its S.I. unit is ohm-metre.
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ssm a warehouse worker exerts a constant horizontal force of magnitude 85 n on a 40 kg box that is initially at rest on the horizontal floor of the warehouse. when the box has moved a distance of 1.4 m, its speed is 1.0 m/s. what is the coefficient of kinetic friction between the box and the floor?
The coefficient of the kinetic friction between the box and the floor is μk 0.21.
Friction is the force resisting the relative motion of strong surfaces, fluid layers, and fabric elements sliding against every different. There are several sorts of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.
Calculation:-
Given,
mass = 40 Kg
Applied force F = 85 N
initial velocity u = 0 (rest)
distance moved = 1.4 meter
Final velocity = 1 m/s
coefficient of kinetic friction =?
Normal force = N = mg = 400 N
v² = u² +2as
a = v²/2s
= 1/2×1.4
= 0.36 m/s²
F = μkN
μk = F/N
= 85/400
0.21
Friction is a shape of touch pressure. It exists between the surfaces which are in touch. The frictional force relies upon on the person of the surface in contact. The rougher the floor, the greater the friction is involved. The frictional force is proportional to the urgent pressure, this is the weight of the body. it's far impartial of the place of the touch.
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what effect does the amplitude setting on the function generator have on oscope display of the voltage in the small coil?
As the amplitude increases from the wave generator, the Voltages passing through the inductor will be higher. and consequently, the current passing through the inductor will also be higher Remember that when a voltage is applied across the inductor, the current is driven in the inductor due to the applied voltage.
When the applied voltage is sinusoidal it creates a sinusoidal current in the inductor with the same frequency as the applied voltage. As this current increases, it creates an induced potential difference proportional to the rate of change of current, and hence there is a sinusoidal induced voltage in the Inductor.
The function generator's amplitude control changes the voltage difference between the output signal's high and low voltage. Its direct current offset control changes the signal's average voltage with regard to the ground. A function generator is equipment to generate input functions for your circuit. It can generate sinewaves, square waves, triangular waves, modulated signals, and so on. An oscilloscope is equipment to display the signals in the circuit.
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A rocket is burning fuel at the rate of 300g/s and electing all the gas. In one direction of the rate of 500m/s what is maximum weight the rocket burn have if it going to move Vertically upward.
Correct option is D)
Overall momentum of the system is conserved.
Therefore, change in momentum of the rocket will be equal to that of the fuel.
Change in momentum of the fuel will be
Δmv=60000
Hence, change in momentum of the rocket will also be:
△P=60000
Thrust force F=
△t
△p
F=60000 N
30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? a 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? 2.07 m 1.93 m 2.12 m 2.20 m 1.98 m
The length of the beam on which the the two boys are lying is 1.01 m.
The mass of one kid is 30 kg and the mass of the beam is 20kg, the beam is balanced at a distance of 1.10 m from the 30 kg boy when a 40kg boy was sitting at the other end of the beam.
If the beam is balanced at 1.10 m from the 30kg boy it means that there lies the center of mass of the system.
So, let us assume the length of the beam to be X meters and the assume the center of mass to be at center.
So,
0 = M₁X₁ + M₂X₂/M₁+M₂
M₁ is 30kg and X₁ is 1.10m.
M₂ is 40kg and the X₂ is (X-1.10)m.
Putting values,
0 = 30 x 1.1 + 40 x (X-1.1)
(1.1 - X)40 = 3.3
X = 1.01 m.
So, the length of the Beam is 1.01 m.
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You land on an unexplored foreign planet, and have with you a 2.5 tool. You determine that the force of gravity acting on the tool
is 19.5. What is the gravitational acceleration of the planet?
Based on the value of the mass of the tool and the force of gravity on that planet, the gravitational acceleration of the planet is 7.8 m/s².
What is the gravitational acceleration of that planet?The mass and force of gravity acting on a body are related by the formula given below:
Force of gravity = mass * gravitational acceleration
The mass of a body is constant but the force of gravity acting on a body or the weight of the body varies depending on the value of the gravitational acceleration.
Considering the given values:
Mass of tool = 2.5 kg
Force of gravity acting on the tool = 19.5
gravitational acceleration = force of gravity / massgravitational acceleration = 19.5 / 2.5
gravitational acceleration = 7.8 m/s²
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if a radiograph is done using an 80 inch ffd and 12 mas and a second image is done using a 40 inch ffd, what is the new mas that should be used?
The new mas that needs to be applied reduces mAs 1 devided by 4 , which is 3.
How do you locate fresh mAs?Milliamperage and time are multiplied to get the unit mAs (mA). A typical technique setting for imaging a hurt hand, for instance, may be 60 kVp, 100 mA, and 1/100 of a second (0.01). In this case, 100 milliamperes times 0.01 secondes = one milliampere (or 1 milliampere-second).Usually, the word "más" is used as an adverb to denote "more" or "most." Más, which means "more," can also be used as an adjective or pronoun. The term mais, which is a literary word that means "but," is not the same as the word más.To learn more about unit mAs (mA) refer to:
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a projectile is fired into a region of no air resistance the horizontal component of velocity remains constant because projectiles
A) is not acted on by any horizontal force
B) is affected by gravity
C) has no vertical component of velocity
A projectile is fired into a region of no air resistance the horizontal component of velocity remains constant because projectiles
A) is not acted on by any horizontal force
Velocity remain constant until unless any net external force acts on the object . While in a projectile motion , there is a gravitational force which act in downward direction . And there is no horizontal force , hence horizontal velocity remain unchanged . Velocity remains constant because projectiles
A) is not acted on by any horizontal force
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Question 8
The scientist mixed a substance A into water. After mixing the substance the scientist
saw that most of the substance did not dissolve making the solution supersaturated.
The scientist wrote a conclusion on his experiment and noted that he put to much solute
in his solvent. Which of the following substances should the scientist use less of next
time substance A or water?
O Water
3 pts
O Substance A
O Solution
Answer:
It is likely water
Explanation:
Due to an average medium PH level it doesn't dissolve much.
two identical, parallel-plate capacitors are connected to identical batteries and allowed to charge fully. a dielectric is placed between the plates of one of the capacitors while still connected to the battery and allowed to reach a steady state. discuss whether the capacitance, charge, and electric potential of the capacitor with the dielectric are greater than, less than, or equal to the capacitor without the dielectric.
Capacitance, charge and electric potential will be greater than the capacitor without the dielectric.
Capacitance is the a property of an electric conductor or set of conductors that is measured by the amount of separate electric charge that can be stored on it per unit change in electric potential.
The value of capacitance for the parallel plate is C = (3∈0AK)/d
Since two identical, parallel-plate capacitors are connected
therefore the value of capacitance for both the plate is C
Ceq. = (C1*C2) / C1 + C2 = C*C / C+C = C2
When the battery remains connected, the potential difference [V] remains constant
Q=CV
∴Cafter>Cbefore [C increased]
∴Qafter>QBefore [Q increased]
Potential difference and charge across the capacitor before the dielectric:
Qbefore = [tex]\frac{CV}{2}[/tex]
Vbefore = Vafter = V
Potential difference and charge on the capacitor after inserting the dielectric:
Qafter = Ceq*V = [tex]\frac{kCV}{k+1}[/tex]
Vafter = Q*After / KC = [tex]\frac{\frac{kCV}{k+1}}{kc}[/tex]
Vafter= [tex]\frac{V}{k+1}[/tex] [K>1]
[Hence V decreases]
Vbefore > Vafter
Also, E = [tex]\frac{V}{d}[/tex]
therefore [E]before > [E]after [E decreases]
Energy stored in the capacitor:-
U=[tex]\frac{1}{2} CV^{2}[/tex]
As V= constant
Cafter > Cbefore .
Hence Uafter > Ubefore
Thus, the electrostatic potential increases.
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according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is?
According to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs
To identify individual conductors in a telecommunications twisted pair cable the 25-pair color code is used. These colours are marked on the conductor's insulation. The primary colours are white, red, black, yellow and violet. The secondary colours are blue, orange, green, brown and slate.
The primary colours are called as tip which is positive and the secondary colours are called as ring which is negative. In the pair only one colour from each group should be used. So the possible combinations are 25 pairs.
Therefore, according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs
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If a car, with an initial velocity of 15 m/s, accelerates at a rate of 5 m/s^2 for 4 seconds, what will its final velocity be?
Answer:
35 m/s
Explanation:
vf = vo + at
vf = 15 + 5(4) = 35 m/s
surface waves are caused primarily by what? question 6 options: frictional forces between wind and the ocean surface frictional forces at the level of the thermocline layer primarily gravitational forces of the moon large aquatic organisms breaching the ocean surface
Frictional forces between wind and the ocean surface are the primary cause of surface waves. This is the first option.
How are surface waves formed?The most common cause of waves is wind. Surface waves, also known as wind-driven waves, are formed by the frictional forces between wind and surface water. The continual disturbance creates a wave crest as wind blows across the surface of the ocean or a lake. Surface waves are found globally across the open ocean and along the coast.
There is also a type of waves called tidal waves. Tidal waves are caused by the gravitational pull of the Sun and Moon on Earth.
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Sound cannot travel without medium write on the basis of the following points (materials required) (procedure) (conclusion
Explanation:
Because it is a mechanical wave and it need material medium to travel through it.
A 900 kg coaster car is 13 m high traveling at 28 m/s at point C. If point E is 10 m high, how fast will the car be traveling assuming no frictional forces?
The velocity of the car at point E which is 10 m is determined as 24.2 m/s.
What is the final velocity of the coaster?The final velocity of the coaster car is calculated by applying the principle of conservation of energy.
total kinetic energy of the coaster = total potential energy of the coaster
K.E = P.E
-¹/₂mv₁² + ¹/₂mv₂² = -mgh
-v₁² + v₂² = -2gh
v₂² = v₁² - 2gh
where;
m is the mass of the coasterv₁ is the initial velocity of the coasterv₂ is the final velocity of the coasterh is the height of travel of the coaterg is acceleration due to gravityThe given parameters include;
initial velocity of the coaster = 28 m/sheight of travel = 10 mv₂² = v₁² - 2gh
v₂² = (28²) - (2 x 9.8 x 10)
v₂² = 588
v₂ = √588
v₂ = 24.2 m/s
Thus, the final velocity of the coaster car at the given height will be smaller than the initial velocity due to effect of gravity.
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NEED HELP ASAP
What is the acceleration due to gravity on the surface of the planet Pluto if its mass is 1.2 x 10 22 kg and radius is 1.14 x 10 6 m?
9.8 m/s2
6.4 m/s2
0.62 m/s2
0.34 m/s2
The acceleration due to gravity on the surface of planet Pluto is 0.62 m/s²
How to determine the acceleration due to gravityFrom the Newton's law of universal gravity, the acceleration due to gravity is given by:
g = GM / R²
Where
g is acceleration due to gravity M is the mass G is the gravitational constantR is the radius.With the above formula, we can obtain the acceleration due to gravity. Details below
Mass of planet (M) = 1.2×10²² KgRadius (R) = 1.14×10⁶ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Acceleration due to gravity (g) =?g = GM / R²
g = (6.67×10¯¹¹ × 1.2×10²²) / (1.14×10⁶)²
g = 0.62 m/s²
Thus, the acceleration due to gravity is 0.62 m/s²
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Joe is using a crowbar to remove a tree stump. He applies 2066 J of work to the crowbar. The output work of the crowbar is 1240 J. What is the efficiency of the crowbar?
Joe is using crowbar to remove tree stump. When output and input work is given then the efficiency can be calculated as 60%.
How is efficiency defined ?Efficiency can be defined as how good a device is at transferring input energy to useful output energy . The efficiency of a device is the proportion of the energy supplied that is transferred for useful work. The efficiency is calculated as a decimal or a percentage.
Given output work as 1240 J
input work as 2066 J
Then efficiency can be calculated by using the formula :
Efficiency= (output work/ input work) * 100%
=( 1240/2066) * 100%
Efficiency = 60%
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two polarizers are oriented to each other by an angle of 75 degrees. polarized light with a polarization angle 25 degrees from the axis of the polarizer is incident on the first polarizer. how much of the light incident on the first polarizer (what percentage) makes it through the second?
82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
We can use Snell's law to find out how much of the light makes it through the second polarizer.
Snell's law gives us:
sin(θ1)×sin(θ2)=n1×n2
Solving for n1, we get:
n1=(sinθ1cosθ2)/(sinθ1sinθ2)
We know that θ1 and θ2 are each 75 degrees, so we can put this into our equation:
n1=(0.5)(0.5)/(0.25)(0.75)=0.8333
This means that 82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
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the system produces 80,176 watts, what is the energy worth per day? assume electricity costs of $0.08 per kwh
Electricity costs of the system at $0.08 per kwh for a day is $153.9
What is power?Power refers to the rate of work. It is work done per unit of time. The SI unit for power is the watt (W), which is the joule per second (J/s).
Power = Work / time
P = W / t
One kilowatt hour is said to be one thousand watts sustained for one hour i.e. KWh = (Watts × Hours) ÷ 1,000
For the given case,
Power = 80,176 watts
Rate = $0.08 per kwh
kWh = (watts × hrs) ÷ 1,000
kWh = (80,176 × 24)
= 1924.224 kWh
Total cost of the day is = 1924.224 × 0.08
= $ 153.9
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