When the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r? X equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a 6 42 57 105

Answer:

-5/8

Step-by-step explanation:

(2,4) (-6.9)

m= y2-y1/x2-x1

= 9-4/-6-2

=5/-8

=-5/8

Answer:

A) 5.4 cm

Step-by-step explanation:

Length of mid segment = (sum of parallel sides )/2

Sum of parallel sides = PQ + SR = 9 + SR

[tex]\frac{9+SR}{2}=MN\\\\\frac{9+SR}{2}=7.2 cm\\9 +SR = 7.2*2\\\\9 + SR = 14.4\\ SR = 14.4 -9 \\SR = 5.4 cm[/tex]

Answer:

180

Step-by-step explanation:

1) 600 % 100 = 6 (to get 1% of 600)

2) 6 x 5 = 30 (to get 5% pf 600)

3) 30 x 6 =180 (to get the amount of profit per the 6 years)

please give brainliest if this helps

Answer:

x = 2

Step-by-step explanation:

If x is a prime number, then x + 1 is not a prime number.

A counterexample is x = 2.

x = 2

2 is prime

x + 1 = 2 + 1 = 3

3 is also prime

Answer:

5c² + 4c - 4

Step-by-step explanation:

Subtract the shaded area from the area of the outer rectangle, that is

(2c + 3)(3c - 2) - (c + 2)(c - 1) ← expand both pairs of factors using FOIL

= 6c² + 5c - 6 - (c² + c - 2) ← distribute parenthesis by - 1

= 6c² + 5c - 6 - c² - c + 2 ← collect like terms

= 5c² + 4c - 4

Answer:

x=2

Step-by-step explanation:

We can use the Pythagorean theorem since this makes a right triangle

a^2+b^2 = c^2

The radius is 1.5

1.5^2 + x^2 = (1+1.5)^2

1.5^2 +x^2 = 2.5^2

2.25+x^2=6.25

Subtract 2.25 from each side

x^2 = 4

Taking the square root of each side

x= 2

Answer:A

Step-by-step explanation:Took quiz

Answer:

1/3

Step-by-step explanation:

The left side of FA is 6 units.

The left side of FB is 2 units.

From 6 to 2, you divide by 3.

Same for the top,

FA is 9 units, while FB is 3 units.

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

48 in.

Step-by-step explanation:

square

P = 4s

4s = 48 in.

s = 12 in.

triangle

s = 12 in. + 4 in.

s = 16 in.

P = 3s = 3(16 in.)

P = 48 in.

Answer:

not enough info

Step-by-step explanation:

Answer:

x ∠ -10

Step-by-step explanation:

Answer:

[tex]x>-10[/tex]

Step-by-step explanation:

[tex]\frac{x}{-2} -3>2[/tex]

[tex]\frac{x}{-2} > 5[/tex]

[tex]x=-2[/tex] × [tex]5[/tex]

[tex]x>-10[/tex]

Step-by-step explanation:

Claim: There's 14 Goats and 9 Chickens!!

Data:

Working with the Provided Information.

Let the Number of goats be x

let the Number of Chickens be y

x + y = 23..... (i)

Since the goat Possesses Two Pair of Legs... Which is a Total of 4 Legs... We say Let its Contribution be 4x.

The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y

4x + 2y = 74 .....(ii)

BRINGING BOTH EQUATIONS TOGETHER.

x + y = 23

4x + 2y = 74

From Eqn i

x= 23 - y

Substitute into eqn ii

4(23 - y ) + 2y = 74

92 - 4y + 2y = 74

92 - 2y = 74

2y = 92 - 74

2y = 18

y= 9.

Substitute y into any of the eqns to get x

x + y = 23

x + 9=23

x = 23 - 9

x = 14

This simply proves that there are 14 Goats and 9 Chickens!!!.

HAVE A GREAT DAY!

Answer:

answer is 1

Step-by-step explanation:

y∝x

y=kx

15=3k

divide 3 both sides

k=5

so y=5x

when y is 5

5=5×x

divide 5 both sides

x=1

Answer:

143.4 mi²

Step-by-step explanation:

Top: 8x6=48

Bottom: 3x8=24

Sides: 3x8=24 and 24

Trapezoids sides: (6+3)/2*2.6=4.5*2.6=11.7 and 11.7

TOTAL: 48+24+24+24+11.7+11.7= 143.4 mi²

Answer:

3x and 9y and -31 is the correct answer if you are bloviating.

Step-by-step explanation:

bloviate the factors of x and y.

Answer:

A Yes

Step-by-step explanation:

the ratio is 2:1

Answer:

A. yes

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

62.5 = 10(b)^2

62.5÷10 = b^2

6.25 = b^2

square root 6.25 and b^2

the answer is 2.5

Answer: 14 units^2

Step-by-step explanation: 2 times 3 is 6, 2 times 4 is 8, 6+8=14.

Answer: -1/2

Step-by-step explanation:

[tex]\\\displaystyle \lim_{x \to 3} \ \dfrac{\dfrac{1}{x+5}-\dfrac{1}{8}}{\sqrt{x+1}-2} \\\\\\\displaystyle =\lim_{x \to 3} \dfrac{\dfrac{3-x}{8} }{\sqrt{x+1}-2} \\\\\\\displaystyle =\lim_{x \to 3} \dfrac{(\sqrt{x+1}+2)*\dfrac{3-x}{8} }{(\sqrt{x+1}-2)*(\sqrt{x+1}+2)} \\\\\\\displaystyle =\lim_{x \to 3} \dfrac{(\sqrt{x+1}+2)*({3-x)} }{8*(x+1-4)} \\\\\\\displaystyle =\lim_{x \to 3} \dfrac{(\sqrt{x+1}+2)*({3-x)} }{8*(x-3)} \\\\\\\displaystyle =\lim_{x \to 3} -\dfrac{ (\sqrt{x+1}+2)} {8} \\\\[/tex]

[tex]=-\dfrac{1}{2}[/tex]

Answer:

A.

Step-by-step explanation:

All of those graphs represent functions. You are able to tell because they all pass the vertical line test. The vertical line test is conducted by drawing a line that goes vertically and intercepts any point of the line in question. If the function crosses the vertical line twice, it is not a function. If it only intercepts once, it is a function. In this case, every graph is a function because they would intercept a vertical line once.  

Answer: Choice B

[tex](6\sqrt{5}+5)i[/tex]

==========================================================

Work Shown:

[tex]\sqrt{-5}+\sqrt{-25}+\sqrt{-125}\\\\\sqrt{-1*5}+\sqrt{-1*25}+\sqrt{-1*25*5}\\\\\sqrt{-1}*\sqrt{5}+\sqrt{-1}*\sqrt{25}+\sqrt{-1}*\sqrt{25}*\sqrt{5}\\\\i*\sqrt{5}+i*5+i*5*\sqrt{5}\\\\i*\sqrt{5}+5i+5i*\sqrt{5}\\\\(i\sqrt{5}+5i*\sqrt{5})+5i\\\\(\sqrt{5}+5\sqrt{5})i+5i\\\\(6\sqrt{5})i+5i\\\\(6\sqrt{5}+5)i\\\\[/tex]

This points us to answer choice B

Answer:

x=22.5°

Step-by-step explanation:

(cos²x-sin²x)-sin4x+sin²2x=0

or, (cos2x)²-sin4x+sin²2x=0

or, cos²2x+sin²2x-sin4x=0

or, 1-sin4x=0

or, sin4x=1

or, 4x=90°

or, x=90°/4

or, x=22.5°

Answer:

Sample because it's only the first ten games of the season not of all the games in the season

Step-by-step explanation:

Answer:

Sample but the power of a study is its ability to detect an effect when there is one to be detected. ... A sample size that is too small increases the likelihood of a Type II error skewing the results, which decreases the power of the study.

Within accompaniment order to be a population then it would need to be justifiable to be comparable to a larger cross section same teams different players that could be at the end of the season, and a population that shows cross section of change, such as the inevitable and include distractions that occur in sports as season starts and progresses till end. Examples of this would include ie) playing with man down etc. or against a team with man down or during penalties etc..

It only becomes a population when it defines all home games only being used as a population as this would show less distraction for each team. Which would be unlikely event in first 10 games, just like it would be unfair to not show the differences for away games within a population.

The higher proportion showing the whole season, thereafter would show population as things change too fast in seasonal events.

Answer:

see below

Step-by-step explanation:

75%   of what number is 150

75          150

----- =  ---------

100       x

75*2 = 150

So multiply the left by 2/2

75*2          150

----- =  ---------

100*2       x

150

------

200

Answer:

The last question

Step-by-step explanation:

I took the test

Answer:

( x-7) (x+3)

Step-by-step explanation:

X^2- 4x- 21

What two numbers multiply to -21 and add to -4

-7 * 3 = -21

-7+3 = -4

( x-7) (x+3)

Answer:

B

Step-by-step explanation:

we have a formula of volume:

V= 4/3*pi*R^3 = 4/3*3.14*(18/2)^3 = 3052.08

Answer:

Hey there!

1/2 can also be written as 8/16.

Thus, starting from 0, count 8 tick marks, and place a point there.

3/16 is just 3/16.

Thus, starting from the 8th tick mark (where you left off in the first part) count three more tick marks to the 11th tick mark.

This shows us that 8/16+3/16=11/16.

Hope this helps :)

Answer:

so 1/2+3/16 is 11/16

Step-by-step explanation:

count the lines until u get to 11 and thts where u put the point.

hope this helps.have a good day

Answer:

$4.84

Step-by-step explanation:

Given that

For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25

For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70

For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60

For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05

For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50

For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40

So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.

So actual charges after increase of 10%

[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]

Answer:

B

Step-by-step explanation:

The triangle RUS is similar to RST. 9/sqrt(90)=y/(3+x) and y^2=x^2+81. Solving all this will give x=27 and y=9*sqrt(10)

Value of x is 27 and value of y is [tex]9\sqrt{10}[/tex].

The angle addition postulate in geometry states that if we place two or more angles side by side such that they share a common vertex and a common arm between each pair of angles, then the sum of those angles will be equal to the total sum of the resulting angle.

X-value:

<RST = [tex]90^{0}[/tex]

[tex]tan( < RSU)= \frac{\overline R \overline U}{\overline S \overline U}[/tex]

[tex]tan( < RSU) = \frac{3}{9}[/tex]

[tex]< RSU = 18.435^{0}[/tex]

Angle addition postulate:

<RST = <RSU + <TSU

[tex]90^{0} =18.435^{0} + < TSU[/tex]

[tex]< TSU =71.565^{0}[/tex]

[tex]tan( < TSU) = \frac{\overline T \overline U }{\overline S \overline U}[/tex]

[tex]tan(71.565^{0})=\frac{x}{9}[/tex]

[tex]x=27[/tex]

Y-value:

<RST = [tex]90^{0}[/tex]

[tex]tan( < RSU)= \frac{\overline R \overline U}{\overline S \overline U}[/tex]

[tex]tan( < RSU) = \frac{3}{9}[/tex]

[tex]< RSU = 18.435^{0}[/tex]

Angle addition postulate:

<RST = <RSU + <TSU

[tex]90^{0} =18.435^{0} + < TSU[/tex]

[tex]< TSU =71.565^{0}[/tex]

[tex]cos( < TSU) = \frac{\overline S \overline U }{\overline S \overline T}[/tex]

[tex]cos(71.565^{0})=\frac{9}{y}[/tex]

[tex]y=9\sqrt{10}[/tex]

Value of x is 27 and value of y is [tex]9\sqrt{10}[/tex].

Find out more information about angle addition postulate here

brainly.com/question/14957499

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Answer:

2-point shots: 31

3-point shots: 6

Step-by-step explanation:

In order to solve this system of equations, we can use the method of elimination. We can start by multiplying the equation x + y = 37 by 2 in order to get the x terms to cancel out in the next step(They can do that because we are making them the same value, 2x). So, we get:

2(x + y) = 2(37)

2x + 2y = 74

Now, we can subtract the equation 2x + 2y = 74 from the equation 2x + 3y = 80 in order to make a one-variable equation:

2x + 3y = 80

-(2x + 2y) = -(74)

y = 6

We can plug in the value of y in one of the equations to find x:

x + (6) = 37

x = 31

Since x stands for the amount of 2-point shots and y for the 3-point shots, we can say:

2-point shots: 31

3-point shots: 6

Answer:

31 and 6

Step-by-step explanation:

The 2 equations modelling the situation are

x + y = 37 → (1)

2x + 3y = 80 → (2)

Multiplying (1) by - 2 and adding the result to (2) will eliminate x

- 2x - 2y = - 74 → (3)

Add (2) and (3) term by term to eliminate x

0 + y = 6

y = 6

Substitute y = 6 into (1) and solve for x

x + 6 = 37 ( subtract 6 from both sides )

x = 31

Then 2- point shots = 31 , 3- point shots = 6

Answer:

Below

Step-by-step explanation:

● 11 + 4(x+ 2y + 4)

● 11 + 4x + 8y + 16

● 27 + 4x + 8y