Which conversion factors are used to multiply to 12 m/s to get kilometers per minute?

Select each correct answer.

1min60 s
1 min over 60 s

60 s1 min
60 s over 1 min

1000 m1 km
1000 m over 1 km

1 km1000 m

PLEASE HELP

Answer:

x=6

Step-by-step explanation:

-2x-6=-18

     +6. +6

-2x=-12

/-2. /-2

x=6

Hopes this helps please mark brainliest

The Kilometer that Alan was left to walk is given as c six and twenty five thirty thirds kilometers

In order to solve for the solution, we would have to write out the expressions in mathematical forms first

eight and two thirds kilometers = [tex]8\frac{2}{3}[/tex]

This is is the time that Alan is said to travel for him to get to school

The expression one and ten elevenths is written mathematically as [tex]1\frac{10}{11}[/tex]

This is the kilometer that he spent running.

We are to find the time that was used to walk to school.

To get this we have to subtract the kilometer that he ran from the total kilometer that he traveled.

[tex]8\frac{2}{3} - 1\frac{10}{11}[/tex]

we have to express as a mixed fraction then we would subtract

26/3 - 21/11

= 286 - 63 / 33

= 223/33

= 6.75

= 6 25/33

Hence the solution is C.

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A statement that two numbers or expressions are equal is an equation.

An equation is a mathematical expression that states that two expressions are equal. An equation's solution is the value that, when substituted for the variable, makes the equation true. To accomplish our goal, we employ two equality principles: the addition principle and the multiplication principle.

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

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The representation of the composite function (fg)(x) is (fg)(x) = 10x

From the question, we have the following function definitions

f(x) = √2x

g(x) = √50x

The function to calculate is given as (fg)x

This can be calculated using

(fg)(x) = f(x) * g(x)

Substitute √2x for f(x) and √50x for g(x) in the above equation

So, we have

(fg)(x) = √2x  * √50x

Evaluate the products

(fg)(x) = √100x²

Evaluate the exponents

(fg)(x) = 10x

Hence, the possible equation is (fg)(x) = 10x

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The expected number of people between 165 and 175 is 41.

The expected number of people taller than 168 is 39.

Given that the mean and standard deviation of people's heights (measured in centimeters) are 170 and 5 respectively. The heights of 60 people are revealed.

μ = 170

σ = 5

n = 60

(a) The probability would you expect to be between 165 and 175 cm tall;

P( 165 < x < 175 ) = P( (165 - 170)/5 < z < (175 - 170)/5 )

                            = P( -1 < z < 1 )

                            = P( z < 1) - P( z < -1 )

                            = 0.8413 - 0.1587

                            = 0.6826

Expected number of people between 165 and 175 = n * p

                                                                                    = 60 * 0.6826

                                                                                    = 40.956

                                                                                    ≅ 41

(b) The probability would you expect to be taller than 167 cm;

P( x >  167 ) = P( z > (167 - 170)/5 )

                   = P( z > -0.6 )

                   = 0.7257

Expected number of people taller than 168 = n * p

                                                                        = 60 * 0.7257

                                                                        = 43.542

                                                                        ≅ 39

Hence,

The expected number of people between 165 and 175 is 41.

The expected number of people taller than 168 is 39.

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0.05093 is the probability that exactly 13 students will take up application development in the coming year .

Describe probability using an example?

Average rate (number) of students who chose to study Application Development (λ)= 18

Poisson random variable(number of students taking up Application Development in the coming year)(x)=13

Poisson distribution = P(X = x) = e^−λ (λ)^x/ x!

Here, probability of 13 students choosing application development next year= P(X=13)

               =   ^(−18 ) 18^13/  13!

P(X=13) = 0.0509286= 0.05093

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The statement that is true is All rational numbers can be written as the quotient of Integers

Any number that can be written as a fraction and has an integer as both the numerator and the denominator is referred to as rational number.

In a rational number, the denominator cannot be zero.

Integer refers to whole numbers. They are generally of two types the positive integers and the negative integers

Quotients refers to the end product of division example 2 ÷ 1 = 2/1

2/1 is the quotient, both 2 and 1 are integers

All decimals are rational - A counter example to this is √2

It has decimal and not a rational number because it cannot be represented as a fraction

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The statement that is true is All rational numbers can be written as the quotient of Integers

What are rational numbers ?

Any number that can be written as a fraction and has an integer as both the numerator and the denominator is referred to as rational number.

In a rational number, the denominator cannot be zero.

Integer refers to whole numbers. They are generally of two types the positive integers and the negative integers

Quotients refers to the end product of division example 2 ÷ 1 = 2/1

2/1 is the quotient, both 2 and 1 are integers

All decimals are rational - A counter example to this is √2

It has decimal and not a rational number because it cannot be represented as a fraction

The rate of change of the surface area of the balloon is 32cm²/sec

We know that volume of the sphere is,

V = 4/3πr³

Given,

dV / dt = +200

r = 5cm

d(SA) / dt = ?

dV / dt = 4πr² dr/dt

80 = 4π (25) dr/dt

dr / dt = 0.8 / π

SA = 4πr²

d(SA) / dt = 8πr dr / dt

d(SA) / dt = 8π × 5 × 0.8 / π

d(SA) / dt = 32cm²/sec

Hence the rate of change of the surface area is 32cm²/sec

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The sample is a subset of the whole population selected to be questioned for the purposes of prediction or gauging opinion .

A sample is a collection of people, things, or things used in research that is taken for analysis from a larger population. To enable us to extrapolate the research sample's findings to the entire population, the sample must be representative of the population.

We must utilize inferential statistics to discover a population's characteristics by directly observing only a subset (or sample of the population) in order to derive conclusions about populations from samples.

Since it is frequently impractical and hardly ever possible, we acquire a sample of the population.

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The dimension for the enclosure that is most economical to construct will be length=11.13 feet and width=27.85 feet.

The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a shape or planar lamina.

A=l*b

=310

b=310/l

total cost=(8b+4l+16l)

=8b+20l

=8*310/l+20l

t=2480/l+20l

t'=20-2480/l²

t'=0

20l²=2480

l²=124

l=11.13 feet

b=310/11.13

b=27.85 feet

The enclosure's length and width, which add up to 11.13 feet and 27.85 feet respectively, will be the most cost-effective dimensions to build.

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By apply the law of cosine, the shortest length of wire needed is 180 feet.

In order to determine the shortest length of wire needed, we would apply the law of cosine because a mental image of the scenario described produces a right-angled triangle.

In Trigonometry, law of cosine (cos) is given by this mathematical expression:

C² = A² + D² - 2(A)(D)cosD

Note: Angle D = 90° + 32° = 122°

Substituting the given parameters into the formula, we have;

C² = 55² + 145² - 2(55)(145)cos122°

C² = 3,025 + 21,025 - 2(7,975)(-0.5299)

C² = 24,050 - (-8,451.905)

C² = 24,050 + 8,451.905

C² = 32,501.905

C = √32,501.905

C = 180.28 ≈ 180 feet.

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Answer: 105 (altough im not entirely sure sry...)

Step-by-step explanation:

I believe since it is "fg" then only the g gets the 7 (g(7)) and the f is just f(1)

This is quite difficult so you this may not be correct

I hope

[tex]\huge\begin{array}{ccc}BT=21\\DC=10.2\end{array}[/tex]

If BT is the midsegment of ΔMAH and DC is the midsegment of ΔBTH, then MA, BT and DC are parallel.

Therefore the segments form the proportion:

[tex]\dfrac{HM}{MA}=\dfrac{HB}{BT}=\dfrac{HD}{DC}[/tex]

BT is the midsegment of ΔMAH, therefore

[tex]HB=\dfrac{1}{2}HM[/tex]

DC is the midsegment of ΔBTH, therefore

[tex]HD=\dfrac{1}{2}HB=\dfrac{1}{2}\cdot\dfrac{1}{2}HM=\dfrac{1}{4}HM[/tex]

[tex]\dfrac{HM}{42}=\dfrac{\frac{1}{2}HM}{BT}[/tex]

cross multiply

[tex]HM\cdot BT=42\cdot\dfrac{1}{2}HM[/tex]

divide both sides by HM

[tex]\boxed{BT=21}[/tex]

[tex]\dfrac{HM}{42}=\dfrac{\frac{1}{4}HM}{DC}[/tex]

cross multiply

[tex]HM\cdot DC=42\cdot\dfrac{1}{4}HM[/tex]

divide both sides by HM

[tex]\boxed{DC=10.5}[/tex]

The constant of variation is 13.

The value of y when x is 15 is 195.

Direct variation is when two values move in the same direction. If one variable increases, the other variable increases.

The equation that represents direct variation is:

y = kx

Where:

91 = 7k

k = 91 / 7

k = 13

The value of y when x = 15

y = 13 x 15

y = 195

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The dependent variable depends on a particular situation. The independent variable does depends on the result of an experiment. The controlled variable is a variable whose value is constant.

What is dependent variable?

The variable being measured or tested in an experiment is known as the dependent variable. The results of the participants' tests, for instance, since that is what is being measured, would be the dependent variable in a study looking at how tutoring affects test scores.

What is independent variable?

This isn't the same as an experiment's independent variable, which is a variable that can stand on its own. Tutoring would be the independent variable in the aforementioned case. The dependent variable (test results), however, may alter depending on the independent variable (tutoring).

What is controlled variable?

Anything kept constant or constrained in a research study is referred to as a control variable. Despite not being relevant to the study's objectives, this variable is controlled because it might have an impact on the results.

Numbers called parameters are used to define the characteristics of entire populations. Statistics are numerical representations of sample characteristics. One population parameter is the average income in the United States.

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There are 200 dogs Roscoe groom if he worked for 40 hours.

What is working time?

A person's working time is the time they are engaged in paid work. Personal housework, childcare, and pet care are examples of unpaid work that is not included in the definition of the working week.

In most cases, when someone inquires about your working hours, you should first provide the start time before providing the time you leave for home.

From the given graph we can see that for each three hours the number of dogs are increased by 15.

So, for each one hour the number of dogs increased by 5.

For 18 hours the the number of dogs are 90.

After 18 hours to complete 40 hours we need 22 hours.

So, for 22 hours the number of dogs are

22 x 5 = 110.

Therefore, the total number of dogs worked for 40 hours are,

90 + 110 = 220.

Hence, there are 200 dogs Roscoe groom if he worked for 40 hours.

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a) Amount of sugar in the tank initially is 0.

b) The amount of sugar in the tank after t minutes is 13.6(1 - [tex]e^{\frac{4t}{1360} }[/tex]).

c) The concentration of sugar in the solution in the tank after 60 minutes is 3.672.

a) Assign the sugar content of the tank for time t to the symbol A(t). Starting with only clean water, the tank

A(0) = 0

b) Sugar flows in at a rate of

(0.02 kg/L) × (2 L/min) = 0.04 kg/min

and flows out at a rate of

(A(t) ÷ 1360 kg/L) × (2 L/min) = (2A(t) ÷ 1360) kg/min

so that the net rate of change of A(t) is governed by the ODE,

dA(t) ÷ dt = (4 ÷ 100) - (2A(t) ÷ 1360)

A'(t) + (2A(t) ÷ 1360) = 2 ÷ 100

Multiply both sides by the integrating factor [tex]e^{\frac{4t}{1360} }[/tex] to condense the left side into the derivative of a product:

[tex]e^{\frac{4t}{1360} }[/tex] A'(t) + (2 [tex]e^{\frac{4t}{1360} }[/tex] A(t) ÷ 1360) = 4 [tex]e^{\frac{4t}{1360} }[/tex] ÷ 100

( [tex]e^{\frac{4t}{1360} }[/tex] A(t))' = 4 [tex]e^{\frac{4t}{1360} }[/tex] ÷ 100

Integrate both sides:

[tex]e^{\frac{4t}{1360} }[/tex] A(t) = ∫ 4 [tex]e^{\frac{4t}{1360} }[/tex] ÷ 100

[tex]e^{\frac{4t}{1360} }[/tex] A(t) = 13.6 [tex]e^{\frac{4t}{1360} }[/tex] + C

Solve A(t);

A(t) = 13.6 + C [tex]e^{\frac{4t}{1360} }[/tex]

A(0) = 0, substitute the value

0 = 13.6 + C [tex]e^{\frac{4t}{1360} }[/tex]

C = -13.6

so that the amount of sugar at any time t is,

A(t) =  13.6 - 13.6[tex]e^{\frac{4t}{1360} }[/tex]

A(t) = 13.6(1 - [tex]e^{\frac{4t}{1360} }[/tex])

c) As t → 60, the exponential term converges to 0 and is left with

[tex]\lim_{t \to \(60}[/tex] A(t) = 13.6 × (1 - 0.73)

[tex]\lim_{t \to \(60}[/tex] A(t) = 3.672 kgs of sugar.

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The number of real roots found are-

1. (x-4)(x+3)^2(x-1)^3=0 ; 6 real roots.

2. X^2(x^3-1)=0 ; 3 real roots.

3. X(x+3)(x-6)^2=0 ; 4 real roots.

4. 3x(x^3-1)^2=0 ; 3 real roots.

5. (x^3-8)(x^4+1)=0​ ; 1 real roots.

Consider the given cases-

1. (x-4)(x+3)^2(x-1)^3=0,

Put each equals zero.

x – 4 = 0 or (x + 3)^2 = 0 or (x – 1)^3 = 0,

Thus,

x = 4

x = –3 twice

x = 1 thrice

All are real numbers, thus given polynomial has 6 real roots.

2. x^2(x^3-1)=0

Put each equals zero.

x² = 0

x³ – 1 = x³ – 1³ = (x – 1)(x² + x + 1) = 0

The quadratic expressions has 2 imaginary roots.

Use the discriminant formula to find-

D = b² – 4ac = 1² – 4(1)(1) = 1 – 4 = –3 < 0.

Thus, roots that are not real.

So, the real roots of this polynomial : 0(twice) and 1.

Hence, thus given polynomial has 3 real roots.

3. x(x+3)(x-6)^2=0

Put each equals zero.

x = 0

x = 3

x = 6 twice

Hence, thus given polynomial has 4 real roots.

4. 3x(x^3-1)^2=0

Put each equals zero.

3x = 0 and  x = 0

(x^3 – 1)² = [(x – 1)(x² + x + 1)]² = (x – 1)²(x² + x + 1)² = 0,

Here, only two roots are real

The quadratic expression do have unreal roots, thus 1 twice are the real roots.

Hence, thus given polynomial has 3 real roots..

5. (x^3-8)(x^4+1)=0

Put each equals zero.

x³ – 8 = x³ – 2³ = (x – 2)(x² + 2x + 4) = 0

There is only one real root i.e, 2, the quadratic expression do have imaginary roots

Check using the discriminant formula

D = b² – 4ac = 2² – 4(1)(4) = 4 – 16 = – 12 < 0.

x⁴ + 1 = 0 has imaginary roots.

Hence, thus given polynomial has 1 real roots..

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x = -1 and y = -13, (-1,-13) is the solution to the system of equation y = 3x - 10 and y = -2x - 15.

Given the system of equation in the question;

To find the solution to the system of equation, replace the occurrence of y in the second equation with y = 3x - 10  and solve for x.

y = -2x - 15

3x - 10 = -2x - 15

Add 10 to both sides

3x - 10 + 10 = -2x - 15 + 10

3x = -2x - 15 + 10

Add 2x to both sides

3x + 2x = -2x + 2x - 15 + 10

3x + 2x = - 15 + 10

Add like terms

5x = -5

x = -5/5

x = -1

Now, to solve for y, replace all occurrence of x with -1 in the first equation and solve for y.

y = 3x - 10

y = 3( -1 ) - 10

y = -3 - 10

y = -13

Therefore, the solution to the system of equation is (-1,-13).

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The equation of the parabola from the vertex is f(x) = 7(x - 3)² + 5

The equation of the function is given as

f(x) = 7x²

Also, we have

Vertex = (3, 5)

The form of the equation is given as

f(x) = a(x - h)² + k

Where

Vertex = (h, k)

This means that

Vertex = (h, k) = (3, 5)

Substitute (h, k) = (3, 5) in the equation f(x) = a(x - h)² + k

So, we have

f(x) = a(x - 3)² + 5

This also means that

f(x) = 7(x - 3)² + 5

The 7 is gotten from f(x) = 7x²

Hence, the equation of the parabola is f(x) = 7(x - 3)² + 5

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The correct inequality symbol that makes the statement true is:

1000 < (6²)³.

The inequality symbols, and their meaning, are presented as follows:

In the context of this problem, the numbers being compared are presented as follows:

1000 and (6²)³.

The power of power property of a number with multiple exponents means that the base is kept while the exponents are multiplied.

The number in which this property is applied in this problem is (6²)³, in which:

Hence the equivalent number is given as follows:

(6²)³ = 6^6 = 6 x 6 x 6 x 6 x 6 x 6 = 46,656

Which is a greater number than 1,000, meaning that 1,000 is less than the number, and the inequality is:

1000 < (6²)³.

The problem is given by the image at the end of the answer.

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Order of greatest y intercept to least y intercept,

1). A linear function has been given as,

   y = [tex]\frac{1}{2}[/tex]x + 4

   Y intercept = 4

2). The graph,

    Y intercept = (2)

3). Graph represented by table

    Y intercept = 1

4). A line passes through two points (-2, -3) and (4, 0)

    Y intercept = -2

It is the total distance from the origin and the intersection of y axis and the formed line. It may be positive, negative or zero.

  From the graph,

    y-intercept = (2)

A line passes through two points (-2, -3) and (4, 0),

Slope of the line = [tex]\frac{y2 - y1}{x2 - x1}[/tex]

                           = [tex]\frac{0-(-3)}{4-(-2)}[/tex]

                           = 1/2

Equation of a line passing through a point (x', y') and slope = m

y - y' = m(x - x')

If the point is (4, 0) and slope = 1/2

y - 0 = 1/2 ( x - 4 )

y = 1/2x - 2

y-intercept of this line = (-2)

A linear function has been given as,

y = [tex]\frac{1}{2}[/tex]x + 4

Comparing it with the slope intercept equation,

y = mx + b

b = y-intercept = 4

From the given table,

For x = 0, f(x) = 1

Therefore, y-intercept = 1

Order of greatest y intercept to least y intercept,

1). A linear function has been given as,

   y = [tex]\frac{1}{2}[/tex]x + 4

Y intercept = 4

2). The graph,

Y intercept = (2)

3). Graph represented by table

Y intercept = 1

4). A line passes through two points (-2, -3) and (4, 0)

Y intercept = -2

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The correct option is  a.) a questionnaire, used as observing the relationship between independent variable as well as a dependent variable is the goal of a quantitative research technique known as employed as.

Quantitative methods place an emphasis on accurate measurements or the statistical, quantitative, or numerical evaluation of information gathered through surveys, polls, and other types of research, as well as the manipulation of statistical data that has already been obtained using computing methods.

Quantitative research involves gathering numerical information and using it to understand a specific event or generalise it across groups of individuals.

Its primary attributes are:

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The rate of change in the account for a week is $157.5.

Annalise has some money in her bank account. She withdraws $22.50 per day from her account for a week. We need to represent the change in the account for the week. The number of days in a week is seven. So, it means that she withdraws money from her bank account daily for seven days. The total amount of money withdrawn from the bank account is the product of the withdrawal amount per day and the total number of days in a week.

A = $22.5*7 = $157.5

Let the initial amount of money in the bank be "$x". The change in the bank balance is $157.5. The current balance is $(x - 157.5).

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The value of m is 36 degrees and the value of n is 27 degrees

Consider the triangle on right side

Two sides of the triangle is equal, therefore it is an isosceles triangle.

One angle of the triangle = 126 degrees

Other two angles of the triangle is equal

The sum of interior angles of the triangle is 180 degrees

Then, the equation will be

126 + n + n = 180

2n + 126 = 180

2n = 180 - 126

2n = 54

n = 54/2

n = 27 degrees

Consider the full triangle

The equation will be

(m +27) + 90 +27 = 180

m + 27 + 90 + 27 = 180

m + 144 = 180

m = 180 - 144

m = 36  degrees

Hence, the value of m is 36 degrees and the value of n is 27 degrees

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The given equation  m<2 = 28⁰ so here in this case option A is correct .

Simplification:

       <1 = <3

<1 = 5x + 8              ………………equation 1.

<3 = 12x – 20         ………………equation 2.

By angle property <1 = <3  [ given ]

and

<1 = <2   [ vertically opposite angles ]

We have some options so we can use it to get answer more quickly:

Put <1=28 and <3=28

And solve it for X.

28 = 5x + 8                     Eq1

20=5x => x=4

28 = 12x - 20                 Eq2

28 + 20 = 12x

48 = 12x

4 = x

X = 4

As <1 = <2 ( vertically opposite angles )

From the first equation  <1 = <2  = 5x + 8 ......( equation 3)

Putting the value of x = 4 in (equation 3)

<2 = 5* 4+ 8

<2=28

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The greatest even integers that the 5 consecutive number has a sum of - 80 is - 12.

Even numbers are those numbers that can be divided into two equal groups or pairs and are exactly divisible by 2.

Therefore, even integers are integers that are even.

There are 5 consecutive even integers with a sum of –80.

let

x = first integers

Therefore,

x + x + 2 + x + 4 + x + 6 + x + 8 = - 80

5x + 20 = - 80

5x = -80 - 20

5x = - 100

divide both sides by 5

x = - 100 / 5

x = -20

Therefore,

greatest integer = - 20 + 8 = - 12

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