Which has a higher reduction potential — silver or iron?

Planet Zoltron takes 32 days to to go once around the Sun.

To find the answer, we need to know about the third law of Kepler.

            = (10 AU/ 1AU)3/2 × 1day

             = 32 days.

Thus, we can conclude that the planet Zoltron has time period of 2 days.

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She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

What is focal length?

The focal length is a measure of how strongly the system converges or diverges light.

A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light.

For a standard rectilinear lens,

FOV = 2 arctan (x/2f)

FOV ∝ 1 / f

where x is the diagonal of the film.

Focal length (f) and field of view (FOV) of a lens are inversely proportional.

From the equation we can say that,

A shorter focal length gives you a wide angle of view which allows more view to fit in the frame.

Hence,

She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

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The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T

Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.

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Answer:

W1 L1 = W2 L2        equation for balancing torques

M1 g L1 = M2 L2 g

Or M2 = M1 * 1.75 / 1.22 = 1.43 M1 = 32.1 kg

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

It is the energy due to the position.

A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:

U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J

A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:

U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J

The increase in the potential energy is:

518 J - 283 J = 235 J ≈ 240 J

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

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A. What can happen to energy in a system is that it can be converted.

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

The energy of a system can be converted from one form to another.

Thus, what can happen to energy in a system is that it can be converted.

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The work required to pump out the liquid is 2.35 MJ.

What is work?

Work can be defined as the scalar product of the force and the displacement.

The formula to calculate the work done W is,

[tex]W=F.d[/tex]

where F is the force and d is the displacement.

Note: It is assumed that the weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].

Break down the vertical tank into parallel disc elements whose thickness is dh and are located at a height h from the ground. The radius of the element at height h is r.

It is given that the height of the tank is 6 m and the base radius is 5 meters. Using these, the ratio of the radius r at height h to the height h by using the triangle similarity criterion is,

[tex]\frac{h}{r}=\frac{6}{5} \\ r=\frac{5h}{6}[/tex]

Using the above value of r, the volume of the element is given by,

[tex]V= \pi r^2dh\\V=\pi (\frac{5h}{6})^2dh\\V= \frac{25\pi h^2}{36} dh[/tex]

The weight of the volume element is the force required.

The weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].

So the weight F of the volume element at height h is given by,

[tex]F=10000 (\frac{25 \pi h^2}{ 36})dh\\F= 6944.44\pi h^2dh[/tex]

At the height h, the difference in the height of the top of the tank and the volume element is (6-h). So the work required to pump out the volume of liquid at height h is given by the integrating the equation,

[tex]W=6944.44\pi\int\limits^6_0 {(6h^2-h^3)} \, dx \\\\W=69.44\pi \left[ 2h^3-\frac{h^4}{4}\right]^6_0\\W=2,.35\times10^6\text{ J}[/tex]

The value of the W obtained is 2.35*10^6 J or 2.35 MJ.

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Answer:

What type of equilibrium? There are more types, lol.

If you want a mechanical equilibrium, then just take in consideration the uniform linear motion. The resultant of the forces is null.

The voltage drop across the 10.0 Ω resistor is c)120V

A voltage drop is an amount the voltage lowers when crossing a component from the negative side to the positive side in a series circuit. If you positioned a multimeter across a resistor, the voltage drop would be the quantity of voltage you are reading.

hence, the voltage drop across the 10.0 Ω resistor = 120 V

correct answer c) 120 V

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The large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.

Lunar Maria are large, dark, basaltic plains on Earth's Moon. It was created by an ancient asteroid impacting the Moon on the far side and triggering some volcanic activity on the opposite side.

These are vast basins containing lava flows that are marked by craters, ridges, faults and straight and immersed valleys called rills. They are waterless. There are about 20 major areas of this type. Most of which include the largest located on the side of the Moon that always faces Earth.

These maria were the result of the melting and eruption of basaltic lava on the lunar surface 3.8 to 2.8 billion years ago. This type of lava was highly fluid under the Moon's weak gravitational field and spread over vast distances.

Thus, the large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.

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The distance traveled by the sprinter in meters is determined as 1.88 m.

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

a = 693 N / 64 kg

a = 10.83 m/s²

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

s = ¹/₂at²

where;

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

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The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34  = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90  = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) =  -19.3 m/s

The horizontal and vertical components of the velocities are given as follows:

1. 35 m/s at  57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34  = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90  = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at  275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) =  -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

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The angular speed of the rod after the impact is 1.49 rad/s

What is angular speed?

The rate of change of angular displacements is known as angular speed.

Angular speed is a scalar measure of the rotating object.

What is Angular momentum?

It is the property of a rotating body given by the product of the moment of inertia and the angular velocity of the rotating object.

Angular momentum is expressed as follows:

L=m*v*r

Here,

mass of beam, M =20 kg

mass of rock, m =0.1 kg

length of the beam, L =2 m

length where rock slides, l = (L / 2), l = 1 m

velocity of rock, v =400 m/s

As here the Torque on which the system is zero implies that the angular momentum is conserved.

Initial angular momentum for rock: I(ri) = m*v*r

Final angular momentum for rock: I(rf) = m*w*r^2

Final angular momentum for beam: I(bf) = 1/3 (M*L^2w)

Now, According to the conservation of momentum:

m*v*r =  m*w*r^2 +  1/3 (ML^2w)

w = m*v*r / ( mr^2 + 1/3 ML^2 )

w = 0.1 *400*1 / ( (0.1 * 1) + 1/3 20* 2^2 )

w = 1.49 rad / s

The angular speed of the rod after the impact is 1.49 rad/s

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b) internal energy drives plate motion

Lithospheric plates are part of a planetary scale thermal convection system. The energy source for plate tectonics is Earth’s internal heat while the forces moving the plates are the “ridge push” and “slab pull” gravity forces.

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.

The motion of tectonic plates is driven by convection in the mantle. Convection: The process of heat transfer from one part of a fluid to another part by the actual movement of the particles of the fluid is called convection. Liquid and gases are heated by the process of convection.

In simple terms, convection is the idea that dense, cold things sink, and buoyant, warm things rise. In the earth the cold sinking things are slabs (subducting plates) and the warm things are plumes, or just rising material from deeper in the mantle.

hence , correct option is b) internal

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The voltage across the ends of the heating element is 125 volts.

Power = 500J/s = 500 Watts. I = 4A

V*I = 500

V = 500/I = 500/4 = 125 Volts.

The difference between two points' electric potentials, also known as electric potential difference, electric potential pressure, or electric tension, is what moves a test charge between the two points in a static electric field. The derived unit for voltage (potential difference) in the International System of Units is called volt. 166 Work per unit charge is stated in SI units as joules per coulomb, with 1 volt equaling 1 joule (of work) for 1 coulomb (of charge). The quantum Hall and Josephson effect was first used to define the volt in the old SI system in 1990. More recently, fundamental physical constants have been included to the definition of the volt in the new SI system.

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   After impact velocity = 14.968 ft/s

Weight and mass of Bullet and wooden block:

Bullet: w = 1oz = 1/16 lb m = 0.001941 lb

wooden block : W = 5lb M = 0.15528 lb

velocity of block and bullet immediately after impact:

Σmv1 + ΣImp = mv2

Resolving vertical component

( m× v₀cos30⁰) + 0 = ( m+M) v'

v' = ( m× v₀cos30⁰)/ (m+M)

v' = 14.968 ft/s

Horizontal and vertical component of the impulse exerted by block on the bullet:

   Here we will apply the principle of impulse and momentum.

 Horizontal component:

          -mv₀ cos30⁰ + RxΔt  =0

                                 RxΔt = mv₀sin30⁰

                                          = 0.001941 × 1400sin30⁰

                                   RxΔt = 1.3587 lb.s

         Vertical component:

                           -mv₀cos30⁰  + RyΔt =  -mv'

                                     RyΔt = m( v₀cos30⁰-v')

                                     RyΔt = 0.001941(1400cos30⁰ - 14.968)

                                              = 2.32 lb.s

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The way to perform the experiment is illustrated below.

Place each straw tightly without deforming the roundness of the straw into the corner of the set square.

Measure the distance from the corner of the set square to where the straw touches the set square using the 30 cm ruler. This will be the radius of each straw.

Multiply this radius by 2 in order to obtain the diameter of each straw.

Sum the diameter of each of the 10 straws.

Divide this sum by 10 to obtain the average value for the diameter of a straw.

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The x-coordinates of the object at each time in a 1 ×1001 row vector named a11 using coordinate.

Coordinates are distances or angles, represented by numbers, that uniquely perceive factors on surfaces of dimensions (second) or in space of 3 dimensions.

Coordinates are hard and fast values that help to expose the exact position of a factor within the coordinated aircraft.  A coordinate aircraft is a 2nd plane that's shaped by the intersection of perpendicular traces known as the x-axis and y-axis.

clear all

close all

alpha=-0.003;

w=0.05;

A=[1-alpha,-w;w,1-alpha];

A_inv=inv(A);

x0=[1;-1];

ans1=[1];

ans2=[-1];

for i=1:1000

x0=A_inv*x0;

ans1(i+1)=x0(1);

ans2(i+1)=x0(2);

end

ans1

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The acceleration lasted for 0.007s.

To find the answer, we need to know about the Newton's equation of motion.

Newton's equations are

V= final velocity, U= initial velocity, a= acceleration, t= time and S = distance

60²-0= 2a×0.2= 0.4a

Thus, we can conclude that the acceleration of the fireshell lasted for 0.007s.

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The answer would be D where and in what arrangement organisms are located.

The time taken for the car to drive directly north is 8.52 seconds.

v = u + at

v = u + a cosθ(t)

v = 17.9 + 2.88cos(137.7)t

v = 17.9 - 2.1t

when the car is directly north, v = 0

0 =  17.9 - 2.1t

2.1t = 17.9

t = 17.9/2.1

t = 8.52 seconds

Thus, the time taken for the car to drive directly north is 8.52 seconds.

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Water bends in the same direction irrespective of the charge of the rod placed near it is because water is dipole- that hydrogen is positively charged and oxygen is negatively charged and thus either of the particle is attracted by the charged rod.

The reason behind it:

As a neutral substance, water has an equal number of positive and negative charges. The negatively charged electrons migrate away from the negatively charged rod and the positively charged protons move toward the rod when the negatively charged rod is placed closer to the water. Water then adheres to the rod. Protons migrate away from the positively charged rod, just as they do when it is moved closer to the water, while electrons flow in its direction. As a result, the water and rod form a relationship.

The partial +ve charge on H is drawn to the -ve charged rod when it is installed, which causes the water stream to bend in the direction of the charged rod.

The partial -ve charge on O is drawn to the +ve rod when it is installed, causing the water stream to bend in the direction of the rod.

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Wave power involves  conversion of mechanical energy to electrical energy.

We know that energy conversion is part of the postulations of the first law of thermodynamics which states that energy can neither be created nor destroyed but can be transformed from one form to another.

Now, the wave power can convert the regular up and down movement of the ocean waves into a source of electricity. This implies that the energy that is taking place here is the conversion of mechanical energy to electrical energy.

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The amount of excess load that can be imposed on the wing of an airplane depends upon the speed of the airplane.

What is meant by wing loading?

Wing loading in aerodynamics is the ratio of the loaded weight of the aircraft and the area of each wing. It is given as:

W_L = W (weight of the aircraft) / S (gross wing area of the airplane)

The more speed an aircraft gains, the more lift is produced by each unit of wing area.

Thus, with a high value of wing loading the aircraft lands and takes-off at higher speeds with low maneuvering control. Generally, Airliners have high wing loading while smaller airplanes have lower wing loading.

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The average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × [tex]10^{-19}[/tex] C

Average current I = Q/t

Where

Substitute all the parameters into the formula

I = 1.6 × [tex]10^{-19}[/tex] C ÷ 2 × [tex]10^{-3}[/tex]

I = 8 × [tex]10^{-17}[/tex] A

Therefore, the average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A

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Work done will be 825 N*m

Given:

mass of crate = 44.0 kg

horizontal force = 150 N

distance moved by crate = 5.50 m

To Find:

Work done

Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

First we want to find the work, it is given by the force applied times the distance moved, so the work is just:

W = Force x displacement

W = 150N*5.50m

W = 825 N*m

So, work done will be 825 N*m

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If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.

Reasoning:

It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.

Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.

Thus the electric force applied on the charge in my hand due to each other is,

[tex]F=\frac{kQq}{r^2}[/tex]

Here k is the Coulomb constant, and r is the distance between the charges.

It is also known that the force on a positive charge due to another positive charge is acted outwards.

Thus, the force on the charge due to the charge on the east is,

[tex]\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}[/tex]

And the force on the charge due to the charge on the north is,

[tex]\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}[/tex]

As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of [tex]45^\circ[/tex] from the north or from the north direction.

Thus the net force is acting in the north-east direction.

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True statements that reflect why infants experience more fluid and electrolyte changes are that dehydration can upset the  balance of electrolytes in an infant or child and the newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin.

As infants are not used to the environment around , they are more sensible towards problems such as Dehydration because of fast metabolism.

Dehydration can upset the  balance of electrolytes in an infant or child. Children are especially vulnerable to dehydration due to their small size and fast metabolism, which causes them to replace water and electrolytes at a faster rate than adults.

Infants are particularly prone to the effects of dehydration because of their greater baseline fluid requirements (due to a higher metabolic rate), higher evaporative losses (due to a higher ratio of surface area to volume), and inability to communicate thirst or seek fluid.

The newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin, insensible water loss (IWL), as well as decreased capacity to concentrate the urine.

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Hydrogen, the element that is by far the most prevalent in the universe, exhibits radio emissions with a wavelength of 21 centimetres.

This makes it practical for using radio waves to explore space objects. An object in space emits radio waves that are more noticeable the more hydrogen it has.

The majority of a disk-shaped galaxy's mass is located on the galactic plane. The galactic poles are shown by directions that are perpendicular to the galactic plane.

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