which of the following equations is a linear equation in one variable?

A. 5x-3=4(x+y)
B. 2a+5b-c=2
C. 3m=8
D. x=2/y+5
​

[tex]\\ \sf\longmapsto 112^2[/tex]

[tex]\\ \sf\longmapsto (100+12)^2[/tex]

[tex]\\ \sf\longmapsto 100^2+2(100)(12)+12^2[/tex]

[tex]\\ \sf\longmapsto 10000+2400+144[/tex]

[tex]\\ \sf\longmapsto 12400+144[/tex]

[tex]\\ \sf\longmapsto 12544[/tex]

112²

(a + b)² = (a² + 2ab + b²)

⇛112²

⇛(100 + 12)²

⇛(100)² + 2 × 100 × 12 + (12)²

⇛10000 + 2400 + 144

⇛12400 + 144

⇛12544

Answer:

Step-by-step explanation:

The first thing you want to do is to factor in any quadratic equation.

So, -10(x^2-25)

Now, we see this is a special case, whenever we see a equation in this case, x^2 - b^2, we factor it to this (x+b)(x-b)

So, -10(x+5)(x-5)

x = -5 and x = 5

Answer:

It’s b. $192,727

Step-by-step explanation

i hope this help

can I get brainly

Answer: -7

Step-by-step explanation:

To find f(-8) look at the f function. Find the y value when x = -8

To find g(4) look at the g function. Find the y value when x = 3

Plug these values into the equation

-1 f(-8) - 4 f(4)

-1 (-5) - 4 (3)

5 - 12 = -7

Answer:

The probability that the sample mean is more than 110 is 0.0384.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the sampling distribution of the sample mean will be approximately normally distributed.  

Then, the mean of the sampling distribution of sample mean is given by:

[tex]\mu_{\bar x}=\mu[/tex]

And the variance of the sampling distribution of sample mean is given by:

[tex]\sigma^{2}_{\bar x}=\frac{\sigma^{2}}{n}[/tex]

The information provided is:

[tex]n=50\\\\\mu=100\\\\\sigma^{2}=1600[/tex]

Since n = 50 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the normal distribution.

The mean variance of the sampling distribution for the sample mean are:

[tex]\mu_{\bar x}=\mu=100\\\\\sigma^{2}_{\bar x}=\frac{\sigma^{2}}{n}=\frac{1600}{50}=32[/tex]

That is, [tex]\bar X\sim N(100, 32)[/tex].

Compute the probability that the sample mean is more than 110 as follows:

[tex]P(\bar X>110)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{110-100}{\sqrt{32}})[/tex]

                   [tex]=P(Z>1.77)\\=1-P(Z<1.77)\\=1-0.96164\\=0.03836\\\approx 0.0384[/tex]

*Use a z-table.

Thus, the probability that the sample mean is more than 110 is 0.0384.

Answer:

4

Step-by-step explanation:

(y+2)²=[(-4)+2]²

=(-4+2)²

=-2²

=4

It looks like the integral is

[tex]\displaystyle \iint_D x^2 (y-x) \,\mathrm dx\,\mathrm dy[/tex]

where D is the set

D = {(x, y) : 0 ≤ x ≤ 1 and x ² ≤ y ≤ √x}

So we have

[tex]\displaystyle \iint_D x^2(y-x)\,\mathrm dx\,\mathrm dy = \int_0^1 \int_{x^2}^{\sqrt x} x^2(y-x)\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \left(\frac{x^2y^2}2-x^3y\right)\bigg|_{y=x^2}^{y=\sqrt x} \\\\ = \int_0^1 \left(\frac{x^3}2-x^{7/2}+x^5-\frac{x^6}2\right)\,\mathrm dx \\\\ = \left(\frac{x^4}8 - \frac{2x^{9/2}}9 + \frac{x^6}6 - \frac{x^7}{14}\right)\bigg|_{x=0}^{x=1} = \frac18-\frac29+\frac16-\frac1{14} = \boxed{-\frac{1}{504}}[/tex]

Answer:

x = 17/5

y = -2/5

Step-by-step explanation:

2x + 2y = 6

3x - 2y = 11

sum both equations results

5x + 0 = 17

x = 17/5

2x + 2y = 6

2*17/5 + 2y = 6

34/5 + 2y = 6

2y = 6 - 34/5

2y = 30/5 - 34/5

2y = -4/5

y = (-4/5)/2

y = -2/5

verify:

3x - 2y = 11

3*17/5 - 2*-2/5 = 11

51/5 + 4/5 = 55/5

51 + 4 = 55

Answer:

= −28.043478261

Step By Step Explanation

Answer From Gauth Math

Answer:

84 beads

Step-by-step explanation:

She had 98 beads and lost all but fourteen. So it would be 98 - 14 which would get you 84 beads that the girl has lost

Answer:

Shawn is correct because two events are independent if the probability of both occurring is equal to the product of the probabilities of the two events.

Step-by-step explanation:

We are given that A represent going to the movies on Friday and let B represent going bowling on Friday night. The P(A) = 0.58 and the P(B) = 0.36. The P(A and B) = 94%.

Now, it is stated that the two events are independent only if the product of the probability of the happening of each event is equal to the probability of occurring of both events.

This means that the two events A and B are independent if;

P(A) [tex]\times[/tex] P(B) = P(A and B)

Here, P(A) = 0.58, P(B) = 0.36, and P(A and B) = 0.94

So, P(A) [tex]\times[/tex] P(B) [tex]\neq[/tex] P(A and B)

      0.58 [tex]\times[/tex] 0.36 [tex]\neq[/tex] 0.94

This shows that event a and event B are not independent.

So, the Shawn statement that both events are not independent because P(A)P(B) ≠ P(A and B) is correct.

Answer:

Shawn is correct

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

the size of the square to be cut out for maximum volume is 1.5695 inches

Step-by-step explanation:

cardboard that measures 8 by 12 inches.

We need to determine What size square should be cut from each corner

We were given given the size of the cardboard.

let us denote the length of the square as 'x'.

Then our length, width and height will be:

Length = 8 − 2x

Width = 12− 2x

Then our Height = x

So now, the volume= length×width ×height

Volume = (8 − 2x) x (12− 2x) x (x)

After calculating volume comes out to be:

V = (96 − 40x + 4x²) (x)

V = 4x³ − 40x² + 96x

Now, we can use differentiation to equate it to zero.

So differentiate it with respect to x, we get

dV/dx = 12x² − 80x + 96

12x² − 80x + 96 = 0

So, after solving this, x comes out to be:

x = 5.097 and x = 1.5695

Looking at it the size of the square cut out cannot be 5.097 because we cannot cut out of both sides of the width, since the width is 5 inches.

Therefore, the size of the square to be cut out for maximum volume is 1.5695 inches.

Answer:

524cm^2

Step-by-step explanation:

Formula for Volume of sphere= 4/3 πr^2

We have,

r=5cm

Now,

Volume(v)=4/3 πr^2 = 4/3π 5^3= 4/3π 125 = 166.666666667π = 523.598775599

Rounding to the nearest tenth,

Volume=524cm^2

Answer:

Amanda's box is in this case, the bigger one. Then subtract the Amanda's by Mary's. The Larger box is 70cm^3 larger then the smaller box.

Step-by-step explanation:

Amanda's box: 13.5*10*10= 1350cm^3

Mary's box: 20*8*8= 1280cm^3

1350-1280=70

The larger box is 70cm^3 larger then the smaller box.

If you have any questions regarding my answer tell me in the comments, i will come answer them. Have a good day.

Monster Truck show. Before the show, Troy got to see

the trucks close up. He noticed that each monster truck tire had a radius of

about 3 feet.

Answer:

C(4,6)

Step-by-step explanation:

the x turns into its opposite when reflected across y same thing for y when reflected across x

Answer:

c. (4, 6)

Step-by-step explanation:

The rule of an reflection about the y-axis is: [tex]A(x,y)\rightarrow A'(-x,y)[/tex]

Apply the rule to  point (-4, 6):

[tex]\frac{(-4,6)\rightarrow\boxed{(4,6)}}{(x,y)\rightarrow(-x,y)}[/tex]

Option C should be the correct answer.

Answer:

x = 4

Step-by-step explanation:

First, we need to get the 3x by itself on the left. To do this, we subtract 5 from both sides. 3x + 5 - 5 = 17 - 5; 3x = 12. Now, to find x, we divide both sides by 3 to get 3x/3=12/3; x = 4

Answer:

Step-by-step explanation:

[tex] \mathsf{3x + 5 = 17}[/tex]

Move constant to R.H.S and change it's sign

⇒[tex] \mathsf{3x = 17 - 5}[/tex]

Subtract 5 from 17

⇒[tex] \mathsf{3x = 12}[/tex]

Divide both sides of the equation by 3

⇒[tex] \mathsf{ \frac{3x}{3} = \frac{12}{3} }[/tex]

Calculate

⇒[tex] \mathsf{x = 4}[/tex]

Hope I helped!

Best regards!

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

Answer:

a) 15

b) 9

c) 2

Step-by-step explanation:

im try it by using trial and error by calculator

Explanation:

I used GeoGebra to determine that the approximate solutions in (x,y) form are

(0.00333, 0)

(9.59682, 3.45925)

These are the locations where the two graphs cross or intersect.

When rounding to the nearest tenth, we end up with (0, 0) and (9.6, 3.5) which is why the answers are D and E.

Be careful to keep in mind that x = 0 is not in the domain of g(x) since log(0) is undefined. So it's fairly misleading to say that (0,0) is an intersection point when it's not even on the graph of g(x). This is one big issue with rounding numbers that we lose crucial information like this.

Answer:

Hello,

x=9.59682

Step-by-step explanation:

Using Excel with the methode of "dichotomie" (divide by 2)

Just modifiy value in A2(start value)  and E1 (precision)

The majority of drivers who will buy used next time bought their current vehicle used. The correct option is B.

Any affiliations, financing, or financial holdings that could be seen as influencing the review's objectivity to give rise to potential bias.

Such elements might consist of, but are not limited to, the following: Employment, professional associations, paid consulting, and participation in groups that support relevant causes.

The given table is:-

Current vehicle      Buy used

Bought new             0.039

Bought Used           0.948

Leased                     0.013

Total                         1.000

In the given table it is observed that the majority of drivers who will buy used next time bought their current vehicle used. The correct option is B.

To know more about statistics follow

https://brainly.com/question/28344445

#SPJ2

Answer:

C. 0

Step-by-step explanation:

Since we are finding f(-4), we use the first function since -4 is less than -2.

f(-4) = (-4) + 4 = 0

Therefore, the answer is C.

Answer:

a

   [tex]P(X < 2500) = 0.02668[/tex]

b

   [tex]P(X < 1500) = 0.00001[/tex]

Step-by-step explanation:

From the question we are told that

     The  population mean  is  [tex]\mu = 3350[/tex]

      The standard deviation is  [tex]\sigma = 440[/tex]

We also told in the question that the birth weight is  approximately Normally distributed

    i.e      [tex]X \ \~ \ N(\mu , \sigma )[/tex]

Given that Low-birth-weight babies weighing less than 2500 grams,then the proportion of babies born full term are low-birth-weight babies is mathematically represented as

       [tex]P(X < 2500) = P(\frac{ X - \mu }{\sigma } < \frac{2500 - \mu}{\sigma } )[/tex]

Generally  

         [tex]\frac{X - \mu}{ \sigma } = Z (The \ standardized \ value \ of \ X )[/tex]

So

      [tex]P(X < 2500) = P(Z < \frac{2500 - \mu}{\sigma } )[/tex]

substituting values

      [tex]P(X < 2500) = P(Z < \frac{2500 - 3350}{440 } )[/tex]

       [tex]P(X < 2500) = P(Z <-1.932 )[/tex]

Now from the standardized normal distribution table(These value can also be obtained from Calculator dot com) the value of

     [tex]P(Z <-1.932 ) = 0.02668[/tex]

=>    [tex]P(X < 2500) = 0.02668[/tex]

Given that  very-low-birth-weight babies (weighing less than 1500 grams,then the  proportion of babies born full term are very-low-birth-weight babies is mathematically represented as

    [tex]P(X < 1500) = P(\frac{ X - \mu }{\sigma } < \frac{1500 - \mu}{\sigma } )[/tex]

    [tex]P(X < 1500) = P(Z < \frac{1500 - \mu}{\sigma } )[/tex]

substituting values

           [tex]P(X < 1500) = P(Z < \frac{1500 - 3350}{440 } )[/tex]

       [tex]P(X < 1500) = P(Z <-4.205 )[/tex]

Now from the standardized normal distribution table(These value can also be obtained from calculator dot com) the value of

     [tex]P(Z <-1.932 ) = 0.00001[/tex]

    [tex]P(X < 1500) = 0.00001[/tex]

[tex]\\ \sf\longmapsto y+124=180[/tex]

[tex]\\ \sf\longmapsto y=180-124[/tex]

[tex]\\ \sf\longmapsto y=56°[/tex]

now using angle sum property

[tex]\\ \sf\longmapsto x+54+125+65=360[/tex]

[tex]\\ \sf\longmapsto x+179+65=360[/tex]

[tex]\\ \sf\longmapsto x+244=360[/tex]

[tex]\\ \sf\longmapsto x=360-244[/tex]

[tex]\\ \sf\longmapsto x=116°[/tex]

Answer:

Step-by-step explanation:

36°

Answer:

$215,892.50

Step-by-step explanation:

This is a problem of compound interest.

In compound interest Amount A for principal p charged at interest r% per annum is given by

A = p(1+r/100)^n

where n is the time period in years.

_____________________________

given

p = $100,000

r = 8%

t = 10 years

A= 100,000( 1+ 8/100)^10

A= 100,000( 1.08)^10

A = $215,892.50

So , you need to pay $215,892.50 in total to debt cleared of debt.

Answer: The population was 2,300,000.

Step-by-step explanation:

Let the population in 1950 be x

11,200,000 = 2,000,000+4x

11,200,000-2,000,000 = 4x

0r, 9,200,000=4x

0r, x = 9,200,000/4

so, x = 2,300,000

Step-by-step explanation:

Putting values

A = - 7(15 + 9)

A = - 7(24)

A = - 168

Answer:

this? hope it helps ........

Answer:

The answer is area=32pi-64 and the perimeter is 8pi

Step-by-step explanation: