Answer: A
Step-by-step explanation:
Each value of x maps onto only one value of y.
The sum of 225 consecutive positive integers only has digits 1 or 0. What is the smallest possible value of the sum?
Answer:
1 +10=11 (since 0 is neither negative or positive the first and second positive integerswith 1 or 0
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either from Rome, Italy or New York, New York:
Maximum Minimum Q1 Q3 IQR Median Mean σ
Rome 16 0 3 13 10 8.5 8 5.4
New York 20 1 4.5 6 1.5 5.5 7.25 5.4
Which of the choices below best describes how to measure the center of this data? (5 points)
Group of answer choices
Both centers are best described with the mean.
Both centers are best described with the median.
The Rome data center is best described by the mean. The New York data center is best described by the median.
The Rome data center is best described by the median. The New York data center is best described by the mean.
It's NOT C "The Rome data center is best described by the mean. The New York data center is best described by the median." already tried, its incorrect.
The best description on measurement of the center of this data is; C. The Rome data center is best described by the mean. The New York data center is best described by the median.
How to find the center of the data?If we make the box and whisker plot of the Rome and New York data, we will see that there will clearly be an outlier in the New York data.
Thus;
Due to the fact that the data set for New York has an outlier and the mean is skewed, it means that we would use the median.
Finally, we see that the Rome data set is symmetrical because it has no outlier, and as such we can use the mean.
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Office procedure note this 39-year-old patient returns to the office today because of a defect on the nail of his left big toe. he was seen three times in the last four months for this problem. this defect is very suspicious, and i felt it best to biopsy a portion of the nail plate and bed. the sample was sent to pathology. i told the patient that he will be called with the results, and then i will decide how to proceed. cpt code(s):
The CPT code that is used here is CPT code 11755.
What is the CPT code 11755?This is the code that is used as the biopsy of the nail bed. The CPT code is used to report this procedure.
Then it would be determined if it is a case of melanoma or lesion that is causing the issues with the individuals nails.
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he correct code for biopsy of the nail bed or nail plate.
If WX= 82 cm, find the length of YZ. (OV = 9cm and OV is perpendicular to YZ)
The length of the measure of YZ is 80cm
Perpendicular linesPerpendicular lines are lines that are at angle 90 degrees to each other. From the given diagram;
WX = 82cm
Required
Length. of YZ
Using the pythagoras theorem
YV = VZ = √41²-9²
YV = VZ = √1600
YV = VZ = 40
Since YZ = YV + VZ
YZ = 40cm + 40cm
YZ= 80cm
Hence the length of the measure of YZ is 80cm
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d all the time and I like the time you
Answer:
Step-by-step explanation:
1a+1b(a+b-c)+1b+1c(b=c-a)+ 1a+1c(c+a-b)
1a+1b-c+1b +1c-a+1a+1c-b
1a+2b-c+a+1c-b
2a+1b+c this is the answer I think lol
Someone help me please
Answer:
[tex]\sqrt{60}[/tex]
Step-by-step explanation:
Use the Pythagorean theorem a^2 + b^2 = c^2
In this case you are given a and c, so set the equation up like
2^2 + b^2 = 8^2
b^2 = 8^2 - 2^2
b =[tex]\sqrt{8^{2} -2^{2} }[/tex]
b =[tex]\sqrt{60}[/tex]
A conjecture and the paragraph proof used to prove the conjecture are shown. Given: angle 2 is congruent to angle 3. Prove: angle 1 and angle 3 are supplementary. A horizontal line. Two rays extend from upper region of the line diagonally down to the left and right and intersect the line forming interior angles labeled as 2 and 3 and an exterior angle labeled as 1. Drag an expression or statement to each box to complete the proof. Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. ∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Response area. Therefore, m∠1+ Response area = 180° by the definition of supplementary. It is given that ∠2≅ Response area, so m∠2=m∠3 by the Response area. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary by the definition of supplementary. angle congruence postulatelinear pair postulatem∠2m∠3∠3∠2
The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.What is the angles about?Using the image attached, one can see that m<1 and m<2 creates a kind of linear pair hence one can say they are both supplementary using the law of LINEAR POSTULATE THEOREM.
Based on the fact that the supplementary angles add up to 180 degrees, therefore:
m<1 + m<2 = 180 - will be equation 1
Since the interior angles m<2 and m<3 are known to be equal based on the CONGRUENCE POSTULATE THEOREM. Therefore
m<2 = m<3 --- will be equation 2
Then place eqn. 2 into eqn. 2
m <1 + m <3 = 180
This connote that m<1 and m<3 are supplementary.
Hence, The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.Learn more about the angle from
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Charmaine's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Charmaine $4.25 per pound, and type B coffee costs $5.40 per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $451.50. How many pounds of type A coffee were used
30 pounds of coffee A and 60 pounds of coffee B used.
According to statement
Type A coffee costs Charmaine $4.25 per pound
Type B coffee costs $5.40 per pound.
Total cost of month on coffee is $451.50
AND
B=2A -(1)
Let's form the equation
4.25A + 5.40B = 451.50
Put equation 1 in it then
4.25A + 5.40*2A = 451.50
15.05A = 451.50
A = 30 pounds then
B = 60 pounds.
So, 30 pounds of coffee A and 60 pounds of coffee B used.
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BRANIEST + 15 POINT QUESTION
Let the missing number x
So, ATQ
[tex] \frac{3}{14} \times x = 6[/tex]
[tex] \frac{14}{3} \times \frac{3}{14} x = 6 \times \frac{14}{3} [/tex]
[tex] \frac{1}{3} \times 3x = \frac{14}{3} \times 6[/tex]
[tex]x = \frac{14}{3} \times 6[/tex]
[tex]x = 14 \times 2[/tex]
[tex]x = 28[/tex]
Therefore, 3/14 of 28 is 6...
Answer:
28
Step-by-step explanation:
Let the number we are looking for = [tex]x[/tex]
∴ [tex]\frac{3}{14}[/tex] of [tex]x[/tex] is 6
⇒ [tex]\frac{3}{14}[/tex] × [tex]x = 6[/tex]
• Divide both sides of equation by [tex]\frac{3}{14}[/tex] :
⇒ [tex]x = 6 \div \frac{3}{14}[/tex]
⇒ [tex]x = 28[/tex]
∴ The missing part is 28.
Which of the following functions has a vertical asymptote at x=2, a horizontal asymptote at f(x)=1, and a root at x=−1?
A. f(x)=3x+2+1
B. f(x)=−3x−2+1
C. f(x)=3x+2−1
D. f(x)=3x−2+1
What is the volume, measured in cubic centimeters, of the box below? Do not
include units in your answer.
5 cm
4 cm
3 cm
Answer:
v =L× b×h
=5× 4×3
=60 cubic centimeter
Simplify. Show work.
3² x 5 + 4 =
Answer:
49
Step-by-step explanation:
[tex]3^{2} *5+4[/tex]
= [tex]9*5+4[/tex] Simplify the exponents.
= [tex]45+4[/tex] Multiplication.
= 49 Addition.
Answer:
49
Step-by-step explanation:
1. Whenever there is an exponent, we solve that first. 3^2 is 9.
2. In an equation, multiplication, and division is first, and since there is no division in the equation, we do the multiplication first. 9 x 5 is 45.
3. We finish by adding 4 to 45, which is 49.
PLEASE HELP!!! the photo has the question and options please help
The equation which expresses the number of bacteria, P, present at any time, t is P(t) = 4(2)^t
EquationNumber of bacteria = PTime = tCheck all options
When t = 1
P(t) = 8(4)^t
= 8(4)¹
= 8(4)
P(t) = 32
Not true
P(t) = 4(2)^t
= 4(2)¹
= 4(2)
= 8
True
P(t) = (2)^t
= (2)¹
= 2
Not true
P(t) = 8(2)^t
= 8(2)¹
= 8(2)
= 16
Not true
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What is the equation of the line through the origin and (-2,3)?
Step-by-step explanation:
[tex]algenbraic[/tex]
x+2/3 - x+1/5 = x-3/4 - 1
Answer:
x = 157/60
Step-by-step explanation:
x + 2/3 - x + 1/5 = x - 3/4 - 1
x - x - x = -2/3 - 1/5 - 3/4 - 1
-60x/60 = -40/60 - 12/60 - 45/60 - 60/0
-60x = -40 - 12 - 45 - 60
-60x = -157
x = -157/-60
x = 157/60
157/60 + 2/3 - 157/60 + 1/5 = 157/60 - 3/4 - 1
2/3 + 1/5 = 157/60 - 3/4 - 1
40/60 + 12/60 = 157-60 - 45/60 - 60/60
40 + 12 = 157 - 45 - 60
52 = 157 - 105
Solve this please!!!
Answers:
i) [tex]\sf (x + 2)(x+ 3)[/tex]
ii) [tex]\sf \left(3x+1\right)\left(3x+2\right)\left(9x^2+9x-16\right)[/tex]
Factorize expression's:
i.
[tex]\sf (x + 1)^2 + 3(x + 1) + 2[/tex]
apply perfect square and distributive method
[tex]\sf (x^2 + 2(x)(1) + 1^2) + 3x + 3 + 2[/tex]
expand
[tex]\sf x^2 + 2x + 1 + 3x + 3 + 2[/tex]
collect like terms
[tex]\sf x^2 + 2x + 3x + 3 + 2 + 1[/tex]
add/subtract like terms
[tex]\sf x^2 + 5x + 6[/tex]
breakdown
[tex]\sf x^2 + 3x + 2x+ 6[/tex]
factor common term
[tex]\sf x(x + 3) + 2(x+ 3)[/tex]
collect into groups
[tex]\sf (x + 2)(x+ 3)[/tex]
ii.
[tex]\sf (9x^2 + 9x - 4)(9x^2 + 9x - 10) - 72[/tex]
breakdown
[tex]\sf (9x^2 + 12x - 3x - 4)(9x^2 + 15x - 6x - 10) - 72[/tex]
factor common term
[tex]\sf (3x(3x + 4) -1( 3x + 4)) ( (3x(3x + 5)- 2(3x +5) )- 72[/tex]
collect like terms
[tex]\sf (3x -1)( 3x + 4) (3x- 2)(3x +5) - 72[/tex]
expand
[tex]\sf 81x^4+162x^3-45x^2-126x-32[/tex]
factor
[tex]\sf \left(3x+1\right)\left(3x+2\right)\left(9x^2+9x-16\right)[/tex]
Answer:
[tex]\textsf{1.} \quad (x+3)(x+2)[/tex]
[tex]\textsf{2.} \quad (3x+1)(3x+2)(9x^2+9x-16)[/tex]
Step-by-step explanation:
Question 1
[tex]\textsf{Given expression}: \quad(x+1)^2+3(x+1)+2[/tex]
[tex]\textsf{Let }u=(x+1) \implies u^2+3u+2[/tex]
[tex]\textsf{To factor }\:\:u^2+3u+2:[/tex]
Rewrite the middle term as u + 2u:
[tex]\implies u^2+u+2u+2[/tex]
Factorize the first two terms and the last two terms separately:
[tex]\implies u(u+1)+2(u+1)[/tex]
Factor out the common term (u+1):
[tex]\implies (u+2)(u+1)[/tex]
Replace [tex]u[/tex] with [tex](x+1)[/tex] :
[tex]\implies (x+1+2)(x+1+1)[/tex]
Simplify:
[tex]\implies (x+3)(x+2)[/tex]
Question 2
[tex]\textsf{Given expression}: \quad (9x^2+9x-4)(9x^2+9x-10)-72[/tex]
Expand:
[tex]\implies 9x^2(9x^2+9x-10)+9x(9x^2+9x-10)-4(9x^2+9x-10)-72[/tex]
[tex]\implies 81x^4+81x^3-90x^2+81x^3+81x^2-90x-36x^2-36x+40-72[/tex]
Collect like terms:
[tex]\implies 81x^4+81x^3+81x^3-90x^2+81x^2-36x^2-90x-36x+40-72[/tex]
Combine like terms:
[tex]\implies 81x^4+162x^3-45x^2-126x-32[/tex]
Use the Factor Theorem:
If f(x) is a polynomial, and f(a) = 0, then (x – a) is a factor of f(x).
[tex]\begin{aligned}\implies f \left(-\dfrac{1}{3}\right) & =81\left(-\dfrac{1}{3}\right)^4+162\left(-\dfrac{1}{3}\right)^3-45\left(-\dfrac{1}{3}\right)^2-126\left(-\dfrac{1}{3}\right)-32\\ & = 1-6-5+42-32\\ & = 0\end{alilgned}[/tex]
Therefore (3x + 1) is a factor.
[tex]\begin{aligned}\implies f \left(-\dfrac{2}{3}\right) & =81\left(-\dfrac{2}{3}\right)^4+162\left(-\dfrac{2}{3}\right)^3-45\left(-\dfrac{2}{3}\right)^2-126\left(-\dfrac{2}{3}\right)-32\\ & = 16-48-20+84-32\\ & = 0\end{alilgned}[/tex]
Therefore (3x + 2) is a factor.
Therefore:
[tex]\implies f(x)=(3x+1)(3x+2)(ax^2+bx+c)[/tex]
Compare the coefficient of x⁴ and the constant to find a and c:
[tex]\implies 3 \cdot 3 \cdot a=81 \implies a=9[/tex]
[tex]\implies 2c=-32 \implies c=-16[/tex]
Therefore:
[tex]\implies f(x)=(3x+1)(3x+2)(9x^2+bx-16)[/tex]
Expand:
[tex]\implies f(x)=81x^4+(81+9b)x^3-(126-9b)x^2-(144-2b)x-32[/tex]
Compare the coefficient of x³ to find b:
[tex]\implies 81+9b=162 \implies b=9[/tex]
Therefore, the fully factorized expression is:
[tex]\implies (3x+1)(3x+2)(9x^2+9x-16)[/tex]
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Loc can mow his entire lawn in 20 minutes; Loc's roommate Reza needs 30 minutes to mow the entire lawn. If Loc starts mowing at 1:00, mows for five minutes and then Reza starts to help with his own mower, at what time will they finish mowing the lawn
Loc and Reza together will finish the entire mowing process on the lawn at 1:14 p.m.
Calculation of total mowing time takenLoc mow the total area in 20 mins.
So, his pace is 1 lawn / 20 minutes or 1/20th of a lawn each minute.
Reza's pace is 1 lawn / 30 minutes, or 1/30th of a lawn each minute because he can mow the grass in that amount of time.
Reza joins Loc after he has been mowing for 5 minutes. He can mow 1/20th of the grass in these 5 minutes, which is 5/20th of the lawn =1/4th lawn
There is currently just
1-1/4=3/4 of the lawn left to complete.
We may construct the following equation by assuming that they mow together for x mins:
1/20x + 1/30x = 3/4 [amount done by Loc + Reza = total amount]
⇒(3x+2x)/60x = 3/4
⇒5x/60 = 3/4
⇒x/12= 3/4
⇒4x=36
⇒x= 9 mins
So, when they collaborate, they can complete the lawn in 9 minutes.
Hence, Loc mows alone for 9+5 mins = 14 mins
Therefore, it is concluded that starting at 1 p.m they finish the mowing at 1:14 p.m.
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Determine S9 of the series where a=6 and r=2
Hi
arithmetic serie mean that to change from a rank to an other, you add "r"
So : if 6 is S1, and 2 is pace,
then you need 8 hops to go from S1 to S9.
so you 'r going to add the reason 8 times.
so : S9 = 6 + 8 * 2 = 6 + 16 = 22
conclusion : S9 = 22
Please someone helpp
Due to length restrictions, we cannot summarize the results of the three parts about the quadratic equations of the form x² + b · x + c = 0. We kindly invite to check the explanation for further details.
How to apply algebra properties to solve quadratic equations of the form x² + b · x + c = 0In this question we have several exercises with quadratic equations of the form x² + b · x + c = 0 and, to be more exactly, quadratic equations with the following characteristics:
x² - (r₁ + r₂) · x + r₁ · r₂ = 0 (1)
Please notice that the first grade coefficient is equal to the inverse of the sum of the two roots and the zero grade coefficient is the product of the two coefficients.
Now we proceed to resolve all the points:
Part I
a) (x + 17) · (x + 1) = x² + 18 · x + 18, r₁ = - 17, r₂ = - 1
b) (x + 5) · (x + 4) = x² + 9 · x + 20, r₁ = - 5, r₂ = - 4
c) (x - 11) · (x - 1) = x² - 12 · x + 11, r₁ = 11, r₂ = 1
d) (x - 18) · (x - 2) = x² - 20 · x + 36, r₁ = 18, r₂ = 2
Part II
a) x² - 12 · x + 27
b) (x + 4) · (x + 8)
c) (x - 5) · (x - 7)
d) (x - 4) · (x - 5)
Part III
a) (x - 18) · (x + 3) = x² - 15 · x - 54
b) (x + 18) · (x + 3) = x² + 21 · x + 54
c) (x + 18) · (x - 3) = x² + 15 · x - 54
d) (x - 18) · (x - 3) = x² - 21 · x + 54
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Which expression does this graph illustrate?
Answer:
D
Step-by-step explanation:
The red line starts with a filled in circle that mean that the number -12 is included. The graph is saying that x can be -12 or any number above -12. The line under the > is telling you that 12 is included.
which situation is most likley to show a constant rate of change
Option B. The situation that would be more likely to show a constant rate of change would be B. The distance traveled by a truck driving at a constant speed compared with time.
How to solve for the rate of changeThis is the factor that is used to determine if there is a decrease or an increase in a given factor.
A good way to d this is by the use of time and speed to compare the distance that is being traveled.
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Complete question
Which situation is most likely to show a constant rate of change?
A. The weight of a child compared with its age in months
B. The distance traveled by a truck driving at a constant speed compared with time
C. The cost of a new car compared with the number of tires it has
D. The outside temperature compared with the time of day
Please help Urgent
1. Explain the steps to use coordinates in calculating the perimeter and area of polygons? Explain your procedure when working with diagonal sides and irregular shapes on the coordinate plane.
2. Explain how the distance formula and slope formula are used to classify various quadrilaterals and triangles.
The way to use the distance formula to classify quadrilateral include:
Use the distance formula to measure the lengths of the sides.Use the slope to check whether the sides are perpendicular and form right angles.Use the slope to check whether the diagonals are perpendicular to eachHow to illustrate the information?The steps to calculate the perimeter and area of a polygon:
Step 1: Plot the given points on the graph.
Step 2: Connect the points and identify the figure.
Step 3: Determine lengths by counting the grid lines.
Step 4: Use a formula to calculate the perimeter and area if one exists.
Step 5: If there are no formulas for a figure, the perimeter can be calculated by summing the lengths of the sides. We might estimate the area without an area formula by counting the number of small squares enclosed.
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Given the graph of the function, f(x) , what is the value of f (-2)?
The value of f(-2) is 0
How to evaluate the function?The graph of the function is added as an attachment
The graph is given as:
y = f(x)
When x =-2. we have
y = f(-2)
From the graph, we have:
x = -2 and y = 0
So, we have
f(-2) = 0
Hence, the value of f(-2) is 0
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PLEASE HELP QUICKLY️️️
Answer:
first option x = 7
Step-by-step explanation:
"x" is the cathetus opposite the angle of 30°
14 is the hypotenuse
use the sine function
[tex]sin30^{0} =\frac{x}{14}[/tex]
[tex]x=14sen30^{0} =14(0.5)=7[/tex]
Hope this helps
Prove the following trigonometric identities
Answer:
Greetings !
check the attachment above☝️ but i haven't done the second question wait a moment. thx
Please help with this
Answer: Circle lines
Step-by-step explanation:
Hopefully the attached image helps, it is a diagram of all the labeled lines on a circle excluding the radius (BG or GE)
NEED HELP PLEASE!!!!!
What is c−1(x) given c(x)=x3−5?
A. c−1(x)= ∛x+5
B. c−1(x)= ∛x+x
C. c−1(x)= ∛x- ∛5
D. c−1(x)= ∛x-5
Answer: A
Step-by-step explanation:
Let c(y)=x.
[tex]\implies x=y^3 -5\\\\x+5=y^3\\\\y=\sqrt[3]{x+5}\\\\c^{-1}(x)=\sqrt[3]{x+5}[/tex]
Use the box-and-whisker plots to determine which statements are true.
The true statements are :
the average monthly temperatures of New Orleans are not as varied as that of Indianapolis.
The median of the average monthly temperatures of New Orleans is equal to the upper quartile of the average monthly temperature of Indianapolis.
What are the true options?
A box plot is used to study the distribution and level of a set of scores. The box plot consists whiskers. The whiskers represents the minimum and maximum scores.
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.
Range for New Orleans = 85 - 50 = 35
Range for Indianapolis = 75 - 25 = 50
Median for New Orleans = 70
Upper quartile for Indianapolis = 70
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The greatest question: what is the square root of nine. i don't know the answer:)
3 is the square root of nine.
The square root of a number is the factor that we can multiply by itself to get that number. The symbol for square root is \sqrt{ } square root of, end square root . Finding the square root of a number is the opposite of squaring a number.
To find the fraction square root, first, find the square root of the numerator and then find the square root of denominator. After finding the square root values, simplify the fraction. For example, √(4/16), can be written as √4/√16.
(3)^2 = 9
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If the clock tower in "Back to the Future" had a big hand length of 3 feet, what would be the length of the arc, in feet, the tip travels from 6:00pm to 6:20pm. Round to the nearest foot.
The length of the arc made by the big hand if the tip travels from 6:00pm to 6:20pm is 0.52 feet
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
The clock reads 12 hours (720). The angle if the tip travels from 6:00pm to 6:20pm (20 minutes) is:
Ф = (20/720) * 360 = 10°
The length of the arc is given as:
Length of arc = (Ф/360) * 2π * length of hand = (10/360) * 2π(3) = 0.52 feet
The length of the arc made by the big hand if the tip travels from 6:00pm to 6:20pm is 0.52 feet
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