Which of the following terms are possible in the domain of a sequence? Select all that apply.

Answer:

53 mph

Step-by-step explanation:

We need to give the answer in terms of miles per hour. This means that we need to find out how many miles Joe needs to travel in one hour. Therefore, this is a ratio problem.

We can set up a proportion where the unknown variable is the number of miles driven in one hour:

[tex]\frac{106}{2} =\frac{x}{1}[/tex]

x is just 106/2, or 53. Therefore, Joe needs to travel 53 mph

Answer:

Step-by-step explanation:

Solution :  

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1)   when : x_1= -1      y_1= 5  

     m= the slope is : (YC - YA)/(XC -XA)

(-1-2)/(0-3) = -3/-3 =1

( parallel to AC means same slope)

an equation in the point-slope form is : y -5 = 1(x+1)

y=x+6

Check the picture below.

part A

since the base of the triangular base is 16, and the altitude "h" splits the base in two equal halves, half that is just 8, so we're looking at a right triangle with a hypotenuse of 17 and a side of 8, thus

[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{17}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{h}\\ \end{cases} \\\\\\ \sqrt{17^2-8^2}=h\implies \sqrt{225}=h\implies \boxed{15=h}[/tex]

part B

well, the prism is simply two triangles and 3 rectangles, le's simply add their areas.

[tex]\stackrel{two~triangles}{2\left[ \cfrac{1}{2}(\stackrel{base}{16})(\stackrel{height}{15}) \right]}~~ + ~~\stackrel{two~rectangles}{2(20)(17)}~~ + ~~\stackrel{one~rectangle}{(20)(16)} \\\\\\ 240~~ + ~~680~~ + ~~320\implies \text{\LARGE 1240}[/tex]

Answer:

Just 1 positive, odd factor

Step-by-step explanation:

48 has many factors. But not many odd factors. Only 3 is odd and bigger than 2 and less than 10.

So, just one odd, positive factor.

By trigonometric functions we find that the measure of angle A is approximately 0.12π radians.

In this question we have a right triangle, of which the length of two sides are known (AB, BC). We can know the measure of angle A by trigonometric functions:

[tex]\tan A = \frac{BC}{AC}[/tex]

[tex]\tan A = \frac{2}{5}[/tex]

A ≈ 0.12π radians

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The upper quartile for NFC is 3 points higher than that of AFC.

A box plot is used to study the distribution and level of a set of scores. The scores are distributed into 4 groups. Each group has a value of 25%

On the box, the third line on the box represents the upper quartile. 75% of the scores represents the upper quartile.

Upper quartile for AFC : 26

Upper quartile for NFC : 23

Difference = 26 - 23 = 3

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Using it's concept, there is a 0.1667 = 16.67% probability of tossing a head and drawing a red marble.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Hence the probability of tossing a head and drawing a red marble is:

[tex]\frac{1}{2} \times \frac{2}{6} = \frac{1}{6} = 0.1667[/tex]

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A confidence interval is an interval estimate of an individual y value, given values of the independent variables.

According to statement

we have to find a interval which give an estimate of an individual y value, given values of the independent variables.

Confidence interval tells that more than just the possible range around the estimate. It also tells about how stable the estimate is. A stable estimate is one that would be close to the same value if the survey were repeated.

So, A confidence interval is an interval estimate of an individual y value, given values of the independent variables.

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In quadrant IV, [tex]\sin(A)[/tex] is negative. So

[tex]\sin^2(A) + \cos^2(A) = 1 \implies \sin(A) = -\sqrt{1-\cos^2(A)} = -\dfrac35 = \boxed{-0.6000}[/tex]

Answer:1+1

Step-by-step explanation:

The tiger population loses 3/5 of its size every 2.94 decades

The given equation is:

[tex]N(t)=710(\frac{8}{125} )^t[/tex]

Find the derivative of the given function

[tex]\frac{dN}{dt} =710(0.064)^tln(0.064)\\\\\frac{dN}{dt} =-1951.7(0.064)^t[/tex]

When the tiger loses 3/5 of its population

dN/dt = 3/5

Solve for t

[tex]\frac{3}{5} =-1951.7(0.064)^t\\\\-0.0003=(0.064)^t[/tex]

Take the natural logarithm of both sides

[tex]ln(-0.0003)=t(ln0.064)\\\\-8.087=-2.75t\\\\t=\frac{-8.087}{-2.75} \\\\t=2.94[/tex]

The tiger population loses 3/5 of its size every 2.94 decades

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Answer:

2

Step-by-step explanation:

• Multiplying two numbers with same bases is the same as adding their powers:

∴ [tex](\frac{4^{\frac{5}{4} } \cdot 4^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]

⇒ [tex](\frac{4^{\frac{5}{4} } ^ + ^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]

⇒ [tex](\frac{4^{\frac{6}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]

• Dividing two numbers with same bases is the same as subtracting their powers:

∴  [tex](\frac{4^{\frac{6}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]

⇒ [tex](4^{{\frac{6}{4} - \frac{1}{2} }})^{\frac{1}{2} }[/tex]

⇒  [tex](4^{1})^{\frac{1}{2} }[/tex]

⇒  [tex]4^{\frac{1}{2}[/tex]

• Raising anything to the power of  [tex]\frac{1}{2}[/tex] is the same as square-rooting it:

∴  [tex]4^{\frac{1}{2}[/tex]

⇒ [tex]\sqrt{4}[/tex]

⇒ 2

The polynomial approximate values are

a. The linear approximating polynomial is p1(x) = 2 - x

b.The quadratic approximating polynomial is  p2(x) = x² - 3*x + 3

c. The approximating polynomial value is p1(0.97) = 1.03; p2(0.97) = 1.0309

According to the statement

we have given that the f(x) = 1/x

And we have to find that polynomial approximate values which are written below

The linear approximating polynomial And quadratic approximating polynomial And approximate the given quantity of polynomials obtained in parts a. and b.

So, the given function is f(x) = 1/x

And

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

Now, we find the linear approximating polynomial

So,

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

And Now, we find the quadratic approximating polynomial

So,

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

And Now, we find the approximating polynomial value

So,

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

So, The polynomial approximate values are

a. The linear approximating polynomial is p1(x) = 2 - x

b.The quadratic approximating polynomial is  p2(x) = x² - 3*x + 3

c. The approximating polynomial value is p1(0.97) = 1.03; p2(0.97) = 1.0309.

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Question:

A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic approximating polynomial for the following function centeredat the given point a. c. Use the polynomials obtained in parts a. and b. to approximate the given quantity.

f(x)=1/x, a=1; approximate 1/0.97

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The 41th term of the arithmetic sequence is 66.

Arithmetic sequences are those that contain these patterns. The difference between successive terms in an arithmetic series is constant. Because the difference between consecutive words is always two, the sequence 3, 5, 7, and 9 is an example of arithmetic.

[tex]a_{n}=a_{1}+(n-1)d[/tex]

[tex]a_n[/tex] =   the nᵗʰ term in the sequence.

[tex]a_1[/tex] =  the first term in the sequence.

d    =   the common difference between terms.

Finding arithmetic sequence for the nth term:

aₙ = a₁ + (n-1)d

d = the common difference

a₇ = a₁ + (7-1)d

34 = 5 + 6d

29 = 6d

d = 29/6

Now ,

Finding the  41st term of the arithmetic sequence.

a₄₁ = a₁ + (n-1)d

   = 5 + (41-1)d

   = 5 + 40d

   = 5 + 40(29/6)

   = (198)* 1/3

  =  66

The 41th term of the arithmetic sequence is 66.

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Answer:

410 Miles

Step-by-step explanation:

Please refer to the photo attached. (Apologies for the legitimately terrible drawing)

The Shortest Distance between any 2 points is the distance thats connects the 2 points directly.

In this case, we can use Pythgoras's Theorem to find AB which is the shortest distance between A and B.

By Pythagoras's Theorem,

[tex] {c}^{2} = {a}^{2} + {b}^{2} \\ {ab}^{2} = {ac}^{2} + {cb}^{2} \\ {ab}^{2} = {90}^{2} + {400}^{2} \\ab = \sqrt{ {90}^{2} + {400}^{2} } \\ = 410 \: miles[/tex]

Answer:

5.4 ft to nearest tenth.

Step-by-step explanation:

We know the adjacent side  of the right triangle  and we need the hypotenuse so we use the cosine:

cos 50 = 3.5/x

x = 3.5 / cos 50

  = 5.445 ft.

No, you will not be dealt this hand exactly 48 ​times. This can be obtained by understanding the concept of probability.

The probability means that out of 100 times nearly 48 times the player is dealt the particular hand.

No, you will not be dealt this hand exactly 48 ​times since 48 times is an approximate value out of 100 times.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: In a certain card​ game, the probability that a player is dealt a particular hand is 0.48. Explain what this probability means. If you play this card game 100​ times, will you be dealt this hand exactly 48 ​times? Why or why​ not?

d² = (y2 - y1)² + (x2 - x1)²

..............

Answer:

-4

Step-by-step explanation:

Slope = y/x

1. y=12 x=-3

  12/-3=-4

2. y=8, x=-2

   8/-2 = -4

3. y=4, x=-1

   4/-1 = -4

4. 0/0 = 0

5. y=-4, x=1

   -4/1 = -4

Hope it helps I had this question last year on Acellus.

Answer:

y = - [tex]\frac{1}{6}[/tex] x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6x - 2 ← is in slope- intercept form

with slope m = 6

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{6}[/tex] , then

y = - [tex]\frac{1}{6}[/tex] x + c ← is the partial equation

to find c substitute (6, - 2 ) into the partial equation

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = - [tex]\frac{1}{6}[/tex] x - 1 ← equation of perpendicular line

Answer:

a ≈ 16.5 cm , b ≈ 23.8 cm

Step-by-step explanation:

using the Law of Sines in Δ ABC

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex]

we require to calculate ∠ C

∠ C = 180° - (42 + 75)° = 180° - 117° = 63°

Then to find a

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{c}{sinC}[/tex] ( substitute values )

[tex]\frac{a}{sin42}[/tex] = [tex]\frac{22}{sin63}[/tex] ( cross- multiply )

a × sin63° = 22 × sin42° ( divide both sides by sin63° )

a = [tex]\frac{22sin42}{sin63}[/tex] ≈ 16.5 cm ( to the nearest tenth )

similarly to find b

[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] ( substitute values )

[tex]\frac{b}{sin75}[/tex] = [tex]\frac{22}{sin63}[/tex] ( cross- multiply )

b × sin63° = 22 × sin75° ( divide both sides by sin63° )

b = [tex]\frac{22sin75}{sin63}[/tex] ≈ 23.8 cm ( to the nearest tenth )

Answer:

Step-by-step explanation:

    [tex]\sf \boxed{\bf\dfrac{a}{Sin \ A}=\dfrac{b}{Sin \ B}=\dfrac{c}{Sin \ C}}[/tex]

Side 'a' faces ∠A.

Side 'b' faces ∠B.

Side 'c' faces ∠C.

We have to find ∠C using angle sum property of triangle.

  ∠C + 75 + 42 = 180

         ∠C +117   = 180

                  ∠C  = 180 - 117

                 ∠C = 63°

[tex]\sf \dfrac{a}{Sin \ 42}= \dfrac{22}{Sin \ 63}\\\\ \dfrac{a}{0.67}=\dfrac{22}{0.89}\\\\[/tex]

   [tex]\sf a = \dfrac{22}{0.89}*0.67\\\\ \boxed{a = 16.56 \ cm }[/tex]

                        [tex]\sf \dfrac{b}{Sin \ B} = \dfrac{c}{Sin \ C}\\\\ \dfrac{b}{Sin \ 75}=\dfrac{22}{Sin 63}\\\\ \dfrac{b}{0.97} =\dfrac{22}{0.89}\\\\[/tex]

                             [tex]\sf b = \dfrac{22}{0.89}*0.97\\\\ \boxed{b =23.98 \ cm }[/tex]

Answer:

240π cm³ (exact)

754 cm³ (approximate)

Step-by-step explanation:

I assume the shape of the cup is a cylinder. The height of the cylinder is 15 cm.

Think of a vertical rectangle that contains the vertical axes of the cylinder.

Two sides of the rectangle are diameters of the bases of the cylinder. The other two side are heights of the cylinder. The pencil is 17 cm long and is a diagonal of this rectangle. We can find the diameter of the base of the cylinder using the Pythagorean theorem.

In a rectangle that is 15 cm long, the diagonal measures 17 cm.

a² + b² = c²

15² + b² = 17²

b = 8

The diameter of the cup is 8 cm.

radius = 8 cm/2 = 4 cm

V = πr²h

V = π(4 cm)²(15 cm) = 240π cm³ (exact)

V = 754 cm³ (approximate)

Answer:

1/36

Step-by-step explanation:

The probability for showing a three the first time is 1/6, and then again is another 1/6, multiply and you get 1/36

The statements that are  true about this study are

This is further explained below.

Generally, a scientific technique is used to create a discovery, test a theory or show an established truth.

In conclusion, The following are accurate claims concerning this study:

Random sampling is used in this investigation. In this investigation, a control group is used. Repeated measurements are employed in this investigation.

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Since there are same number of either side, hence the solution has infinite number of solution

System of equations are equation that consist of two or more equations with unknown variables.

Given the equations

2x - y = 7

2y = 4x - 14

This can also be written as

2x - y = 7

y = 2x - 7

Substitute equation 2 into 1

2x - (2x - 7) = 7

2x-2x+7= 7

7 = 7

Since there are same number of either side, hence the solution has infinite number of solution

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Answer: (8 * x) -3

Step-by-step explanation:

The term product refers to multiplication, so let the unknown number be x and multiply it by 8. Then you can subtract 3 afterwards.

*= multiplication

Answer:

[tex] \large{ \boxed{\tt{2 {x}^{3}y + 7 {y}^{2} x - 3 {x}^{2} - 12y}}}[/tex]

- All you gotta do is writing the polynomial in the descending order of the power of the variable.

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Using proportions, it is found that there are 5 cups of milk in each bowl of chocolate pudding.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The cafeteria used 10 quarts for 8 bowls, hence the number of quarts per bowl is:

10/8 = 1.25

Each quart has 4 cups, hence the number of cups is:

4 x 1.25 = 5 cups.

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The area of the triangle is 557. 7cm²

In order to determine the area of a triangle, we have to know the size of the base and the size of the height

The formula for finding the area of a triangle is given as = half the base multiplied by the height

In mathematical form, it is written as;

Area = 1/ 2 × base × height

From the figure given, we have their lengths to be'

base = 57. 2 m

height = 19. 5 m

Let's substitute the values

Area = 1/ 2 × 57. 2 × 19. 5

Area = 1/ 2 × 1115. 4

Find the ratio

Area = 557. 7 m²

The area of the triangle is 557. 7cm²

Hence, the area of the triangle is 557. 7cm²

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