Answer:
The answer is C. a paved roadExplanation:
Generally, roads are meant to have very rough surfaces to allow for friction between car tyres hence the motion of vehicles.
What is a paved surface?
Paved roads are roads that are covered with a firm surface suitable for travel, like paving stones or concrete or asphalts.
Another good example of a paved road is a small paved courtyard, covered with a hard layer of concrete/cement.
The other two examples sited in this problem are glossy materials with very low surface friction, that is their surfaces are very smooth.
light of a wavelength 600 nm shines on a soap bubble film. For what soap film thickness will destructive interference occur
Answer:
The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
Explanation:
Given;
wavelength of light, λ = 600 nm
The minimum thickness of the soap bubble for destructive interference to occur is given by;
[tex]t = \frac{\lambda/n}{2}\\\\t = \frac{\lambda}{2n}[/tex]
where;
n is refractive index of soap film = 1.33
[tex]t = \frac{\lambda}{2n} \\\\t = \frac{600*10^{-9}}{2(1.33)}\\\\t = 2.2556 *10^{-7} \ m\\\\t = 225.56 *10^{-9} \ m\\\\t = 225.56 \ nm[/tex]
Therefore, the minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
A small uniform disk and a small uniform sphere are released simultaneously at the top of a high inclined plane, and they roll down without slipping. Which one will reach the bottom first?
Answer:
the sphere
Explanation:
From the given information,
A free flow body diagrammatic expression for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane can be seen in the image attached below.
From the diagram;
The Normal force mgsinθ - Friction force F = mass m × acceleration a
Meanwhile; the frictional force
[tex]F = \dfrac{I \alpha }{R}[/tex]
where
[tex]\alpha = \dfrac{a}{R}[/tex] in a rolling motion
Then;
[tex]F = \dfrac{I a }{R^2}[/tex]
∴
The Normal force mgsinθ - F = m × a can be re-written as:
[tex]\mathtt{mg sin \ \theta- \dfrac{Ia}{R^2} = ma}[/tex]
making a the subject of the formula, we have:
[tex]a = (\dfrac{mg \ sin \theta}{m + \dfrac{I}{R^2}})[/tex]
Similarly;
I = mk² in which k is the radius of gyration
∴
replacing I = mk² into the above equation , we have:
[tex]a = (\dfrac{mg \ sin \theta}{m + \dfrac{mk^2}{R^2}})[/tex]
where;
the uniform disk [tex]\dfrac{k^2}{R^2 }= \dfrac{1}{2}[/tex]
the uniform sphere [tex]\dfrac{k^2}{R^2 }= \dfrac{2}{5}[/tex]
∴
[tex]a = \dfrac{2}{3} \ g sin \theta \ for \ the \ uniform \ disk[/tex]
[tex]a = \dfrac{5}{7} \ g sin \theta \ for \ the \ uniform \ sphere[/tex]
We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.
An object is at rest on a table. The gravitational force is 10 N down, and the normal force is 10 N up. What is the net force?
Fnormal
Fgravity
10 N up
OON
10 N down
20 N up
Answer:
0N
Explanation:
When trying to figure out opposing forces, you have to add them together,
10 + -10 = 0,
so your answer is 0N
Answer:the answer is 0 N
Is the sinusoidal pattern on a string longer or shorter when there is a greater propagation velocity?
Answer:
We know that
Velocity= wavelength x frequency
And f= 1/2π√T/u
So we also know that
The frequency of nth harmonic standing wave is
fn=nv/2L
So from the relationships above
We can see that as propagational velocity increases, the frequency increases and the wavelength decreases. So finally we can say that sinusoidal pattern on a string is shorter when there is a greater propagation velocity
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
Answer:
magnitude = 3
unit vector = [tex]\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}[/tex]
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
[tex]u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right][/tex]
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | = [tex]\sqrt{2^2 + (-1)^2 + (-2)^2}[/tex]
| u x v | = [tex]\sqrt{4 + 1 + 4}[/tex]
| u x v | = [tex]\sqrt{9}[/tex]
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û = [tex]\frac{u X v}{|u X v|}[/tex]
u x v = 2i - j - 2k [calculated in (a) above]
|u x v| = 3 [calculated in (a) above]
∴ û = [tex]\frac{2i - j - 2k}{3}[/tex]
∴ û = [tex]\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}[/tex]
Scientist start by asking a question about something what is the initial explanation to that question called
A hypothesis. It is the first step to the scientific method.
What is the direction of the force? Answer with a positive angle measured counterclockwise from the positive x axis.
Answer:
hello the diagram related to your question is missing attached below is the missing diagram
answer : 107.07⁰
Explanation:
The direction of the force can be calculated as below
angle = 180 - ∝ - ∅ ------ 1
∅ = [tex]tan^{-1} b/a[/tex] = tan^-1 ( 0.429 )
∅ = 23.2⁰
∝ can be determined by applying the parallelogram law
∝ = [tex]tan^{-1} ( \frac{R24sin56.4}{f13 + R24cos56.4} )[/tex]
= tan^-1 ( 21.173 / 17.935 )
∝ = 49.73⁰
back to equation 1 direction of force with positive angle
= 180 - 49.73 - 23.2 = 107.07⁰
When discharging a fire extinguisher, it is important to aim: a. On top of the flames b. At the top of the flames c. Anywhere d. At the base of the fire
Answer:
d. At the base of the fire
Explanation:
Most fire extinguisher utilize the non-combustible nature of carbon-dioxide . carbon-dioxide is what is used in fire extinguishers, because it does not support burning. Also, carbon-dioxide is denser than air, allowing it to sink down. Aiming at the bottom of the flame allows the carbon-dioxide to sink down on the base of the flame, covering the base of the fire, and cutting off its supply of oxygen which is vital for combustion.
At what distance will a 80 W lightbulb have the same apparent brightness as a 120 W bulb viewed from a distance of 40 m
Answer:
32.6mm
Explanation:
Using area of a sphere(bulb) = 4πr²
So A is proportional to radius²
So the Energy will be proportional to r²
But 120/80 = 1.5 is the energy factor so
Using
1.5/d² = 1/r²
1.5/40²= 1/r^2
r = √( 40²/ 1.5)
r = 32.6m
A 0.16 pF parallel - plate capacitor is charged to 10 V. Then the battery is disconnected from the capacitor. When 1.00 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by
Answer:
The value is [tex]V_d = 5 \ V[/tex]
Explanation:
From the question we are told that
The capacitance of the capacitor is [tex]C = 0.16 \ pF = 0.16*10^{-12} \ F[/tex]
The voltage is [tex]V = 10\ V[/tex]
The number of electrons present on the negative plate is [tex]N_e = 1.00 *10^{7} \ electrons[/tex]
Generally the charge on the positive plate at 10 Volt is mathematically represented as
[tex]Q_a = C * V[/tex]
=> [tex]Q_a = 0.16*10^{-12} * 10[/tex]
=> [tex]Q_a = 0.16*10^{-11} \ C[/tex]
Now the charge on the plate when the electron where placed is evaluated as
[tex]Q_b = Q_a + ( N_e * e)[/tex]
Where e is the charge on each electron with a value [tex]e = 1.60 *10^{-19} \ C[/tex]
=> [tex]Q_b = 0.16*10^{-11} + (1.0*10^7 * 1.60*10^{-19})[/tex]
=> [tex]Q_b = 3.2 *10^{-12 } \ C[/tex]
Generally the voltage between the two plate is evaluated as
[tex]V_d = \frac{ Q_b - Q_a }{ 2 * C }[/tex]
=> [tex]V_d = \frac{ 3.2*10^{-12} - 0.16*10^{-11}}{2 * 0.16 *10^{-12}}[/tex]
=> [tex]V_d = 5 \ V[/tex]
Suppose that an object in free fall were somehow equipped with a speedometer. By how much would its speed readings increase with each second of fall? Express your answer to two significant figures and include the appropriate units.
What are different ways to describe speed and velocity
Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ____________ not matching the type of stimulus of the receptor.
Answer:
Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ___MODALITY_________ not matching the type of stimulus of the receptos
Explanation:
Because modality of sensation refers to what is perceived after the stimulus is effected eg the pressure modality is effected when the pressure receptors of the skin are stimulated so in this case sound will not elite olfactory sensation because the modality here is sound rather than smell
A passenger train travels 295 miles in the same amount of time it takes a freight train to travel 225 miles. The rate of the passenger train is 14 mph greater than the rate of the freight train. Find the rate of each train.
Answer:
9.3
Explanatin:
Answer:
4.5
Explanation:
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s.A violinist is tuning her instrument to concert A (440 Hz). She plays the note while listening to an electronically generated tone of exactly that frequency and hears a beat of frequency 6.00 Hz, which increases to 7.00 Hz when she tightens her violin string slightly.
(a) What was the frequency of the note played by her violin when she heard the 3-Hz beats?
(b) To get her violin perfectly tuned to concert A, should she tighten or loosen her string from what it was when she heard the 3-Hz beats?
Answer:
A) 443 Hz
B) She has to loosen the string
Explanation:
A) Given;
Beat frequency;f_beat = 3 Hz
Frequency of electronically generated tone; f_e = 440 Hz
We know that formula for beat frequency is given by;
f_beat = |f1 - f2|
Now, applying it to this question, we have;
f_beat = f_v - f_e
Where f_v is frequency of the note played by the violinist
Thus, plugging in the relevant values;
3 = f_v - 440
f_v = 3 + 440
f_v = 443 Hz
B) In the concept of wave travelling in a string, the frequency is directly proportional to the square root of the force acting on the string.
Now, for the violinist to get her violin perfectly tuned to concert A from what it was when she heard the 3-Hz beats, the beat frequency will have to be zero. Which means it has to decrease by 3 Hz. For it to decrease, it means that the force applied has to decrease as we have seen that frequency is directly proportional to the square root of the force acting on the string.
Thus, she would have to loosen the string.
Discuss the characteristics of the waves in the visible portion of the electromagnetic spectrum
Explanation:
The electromagnetic spectrum consists of series of waves that are arranged from longest wavelength to shortest.
In the electromagnetic spectrum, between infrared and ultraviolet, visible light falls.The frequency of visible light is of the order of 10¹⁴ Hz.Its wavelength is about 740 nm.Visible light spectrum is visible to humans. It consists of colors like violet, blue, green, yellow etc.The period of a simple pendulum is 8 s. If the same pendulum experiment is repeated on a plant of g = 1/4 gE, the new period is
Answer:
16 secs.
Explanation:
Data obtained from the question include the following:
Period on earth (T) = 8 secs
Next period (Tn) =?
Next, we shall determine the length of the string. This can be obtained as follow:
Period on earth (T) = 8 secs
Acceleration due to gravity on earth (gE) = 9.8 m/s²
Pi (π) = 3.14
Length of string (L) =?
T = 2π√(L/gE)
8 = 2 × 3.14 ×√(L/9.8)
8 = 6.28 × √(L/9.8)
Divide both side by 6.28
8/6.28 = √(L/9.8)
Take the square of both side
(8/6.28)² = L/9.8
Cross multiply
L = (8/6.28)² × 9.8
L = 15.9 m
Therefore the length of string is 15.9 m
Next, we shall determine the new period of the pendulum as follow:
Length (L) = constant = 15.9 m
Pi (π) = 3.14
Acceleration due to gravity on earth (gE) = 9.8 m/s²
Acceleration due to gravity on the planet (g) = 1/4 gE = 1/4 × 9.8 m/s²
= 2.45 m/s²
New period (Tn) =?
Tn = 2π√(L/g)
Tn = 2 × 3.14 × √(15.9/2.45)
Tn = 6.28 × √(15.9/2.45)
Tn = 16 secs.
Therefore, the new period of the pendulum is 16 secs.
What is the primary reason that astronomers suspect that some jovian moons were captured into their current orbits
Answer:
The summary including its circumstances in question is outlined in the illustrating segment below.
Explanation:
An astronomer seems to be an astronomical specialist who performs his information about the research problem or area elsewhere in Earth's view.A few other moons include "backward" orbits (particularly in comparison to the movement or rotation of another planet), or are favorably committed to the equator of their continent.A car accelerates from 14.0m/s to 21m/s in 6.0s. What was its acceleration?
How far did it travel in this time? Assume constant acceleration.
Answer:
Acceleration (a) = 1.167 m/s²
Distance travel = 105 m (Approx)
Explanation:
Given:
Initial speed (u) = 14 m/s
Final speed (v) = 21 m/s
Time taken (t) = 6 sec
Find:
Acceleration
Distance travel
Computation:
v = u + at
21 = 14 + a(6)
7 = 6a
Acceleration (a) = 1.167 m/s²
S = ut + (1/2)(a)(t²)
S = (14)(6) + (1/2)(1.167)(6²)
S = 84 + 21
S = 105 m (Approx)
Distance travel = 105 m (Approx)
On planet Q the standard unit of volume is called guppi. Space travelers from Earth have determined that one liter = 38.2 guppies. How many guppies are in 150 liters?
Answer:
5730 guppies
Explanation:
1 liter= 38.2 guppies
150 liters= 150×38.2
On planet Q the standard unit of volume is called guppi. Space travelers from Earth have determined that one liter = 38.2 guppies. Guppies in 150 liters is 5730 guppies.
What are units of volume?Volume, which is measured in cubic units, is the 3-dimensional space occupied by matter or encircled by a surface. The cubic meter (m³), a derived unit, is the SI unit of volume. A addition new nickname for the cubic (dm³) is a liter (L).
Given that in the question on planet Q the standard unit of volume is called guppi, the conversion of different volume unit,
1 liter = 38.2 guppies, so
150 litre = 5730 guppies
Guppies in the given 150 liters of volume is 5730 guppies.
To learn more about volume refer to the link:
brainly.com/question/13338592
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Why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?
Answer:
Because the force F is always at 90 degrees to the velocity of the particle.
Explanation:
The factors that determine the path of a particle in a uniform magnetic field depend on
The magnetic flux density
The charge on the particle
The speed of the particle
Why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?
Because the force F is always at 90 degrees to the velocity of the particle.
This can be illustrated by the equation
F = BQVSINØ
The magnetic force is always acting perpendicular to the particle velocity and its direction can be found using the left hand rule.
A sprinter can accelerate with constant acceleration for 4.00 s before reaching top speed. He can run the 100 m dash in 10 s. What is his speed as he crosses the finish line?
Answer:
12.5 m/s
Explanation:
If the avg speed is 10 m/s we assume that the speed is constant and not fluctuating
If VT (Velocity*Time) is equal to speed at the end of the 4 seconds of accel. it is the top speed at the finish line
since the speed is 0 at the beginning of races, we will use V0= 0 m/s
So the avg velocity for those 4 seconds is (VT+V0) /2 = or 1/2 VT (for 40% of the race)
The avg velocity for the last 6 seconds is, of course, VT (for 60% of the race
hence
(1/2VT)(.4) + VT(.6) = 10 m/s
VT = 10/.8 = 12.5 m/s
Two identical guitar strings are prepared such that they have the same length ( 0.62 m ) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the second harmonic. The other string is plucked in a different location, primarily exciting the third harmonic. The resulting sounds give rise to a beat frequency of 324 Hz . What is the wave propagation speed on the guitar strings?
Answer:
The speed is 401.76m/s
Explanation:
To find the fundamental frequency we use
3rd.harmonic - 2nd.harmonic = 324Hz
And we know that
f=v/2L
So v=f2L
v= 324 x 2 x 0.62= 401.76m/s
A cosmic-ray proton in interstellar space has an energy of 10.0 MeV and executes a circular orbit having a radius equal to that of Mercury’s orbit around the Sun (5.80 × 1010m). What is the magnetic field in that region of space?
Answer:
The value is [tex]B = 7.7106 *10^{-12 } \ T[/tex]
Explanation:
From the question we are told that
The energy is [tex]E = 10.0 MeV = 10.0 *10^{6} \ eV = 10.0 *10^{6} * 1.60*10^{-19} = 1.6 *10^{-12} \ J[/tex]
The radius is [tex]R = 5.80 *10^{10} \ m[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{m * v }{q * R }[/tex]
Where m is the mass of proton with value [tex]m = 1.6*10^{-27} \ kg[/tex]
v is the velocity of the proton which is mathematically deduced from the formula for kinetic energy as
[tex]v = \sqrt{ \frac{E }{ 0.5 * m } }[/tex]
Here E is also equivalent to kinetic energy of the proton so
[tex]v = \sqrt{ \frac{1.6 *10^{-12} }{ 0.5 * 1.6*10^{-27} } }[/tex]
[tex]v = 4.47214 *10^{7} \ m/s[/tex]
So
[tex]B = \frac{1.60 *10^{-27} * 4.47214 *10^{7}}{ 1.60 *10^{-19} * 5.80*10^{10}}[/tex]
[tex]B = 7.7106 *10^{-12 } \ T[/tex]
The magnetic field in the region has a magnitude of 7.7×[tex]10^{-12}[/tex] T.
Let's consider the magnetic field in the region be B. Now the proton in the given orbit is in equilibrium under the influence of centripetal force ([tex]F_{c}[/tex]) and magnetic force([tex]F_{b}[/tex]).
[tex]F_{c}[/tex] = [tex]F_{b}[/tex]
m[tex]v^{2}[/tex]/R = qvB
⇒ B = mv/qR
where, m is the mass of proton = 1.6 × [tex]10^{-27}[/tex] kg
q is the charge of proton = 1.6 × [tex]10^{-19}[/tex] C
R is the radius of the orbit = 5.8 × [tex]10^{10}[/tex] m
now we can calculate the velocity of the proton, v, from the energy of the proton given in the question that is E = 10 MeV.
1 MeV = 1.6 × [tex]10^{-19}[/tex] J
v = [tex]\sqrt{\frac{2E}{m} }[/tex]
=[tex]\sqrt{\frac{2*10*10^{6}* 1.6*10^{-19} }{1.6*10^{-27} } }[/tex]
v = 4.47 × [tex]10^{7}[/tex] m/s
now,
B = mv/qR
= [tex]\frac{1.6*10^{-27}*4.47*10^{7} }{1.6*10^{-19}*5.8*10^{10} }[/tex]
B = 7.7 ×[tex]10^{-12}[/tex] T
Learn more about magnetic force :
https://brainly.com/question/25746114
A truck travels due east for a distance of 1.9 km, turns around and goes due west for 9.3 km, and finally turns around again and travels 3.4 km due east.
What is the total distance that the truck travels? What are the magnitude and direction of the truck's displacement?
Answer:
The total distance of the truck is 14.6 km
The magnitude and direction of truck's disaplacement is 4 km east
Explanation:
Distance is the total path covered by the trcuk regardless of the direction since distance is described by magnitude only.
The total distance traveled by the truck is given by;
Total Distance = 1.9 km + 9.3 km + 3.4 km
Total Distance = 14.6 km
Displacement is the change in postion at a time interval. In dispalcement direction is considered.
let eastward motion be positive
let westward motion be negative
Displacement = 1.9km east - 9.3 km west + 3.4 km east
Displacement = -4 km east
Therefore, the magnitude and direction of dispalcement = 4 km east
Below is a car. The car's engine is providing a driving force of 10N. The parachute is creating air resistance of 7N. What is going to happen to the car? Explain.
Answer:
The car is going to slow down to 3N.
Explanation:You have a force going 10N to the left and if you put an opposing force of 7N you get 3N of total force.
100 hectometer =_______ nanometers
Answer:
Hey!
Your answer is 10^12 nanometers!
Explanation:
AKA
1,000,000,000,000 nm
HOPE THIS HELPS!!
An object is continuously changing its velocity by the same rate. What is true
about this object?
a. The object has decreasing acceleration.
b. The object has increasing acceleration.
c. The object has zero acceleration.
d. The object has constant acceleration.
Answer:
d. The object has constant acceleration.
Explanation:
Acceleration is the rate of change of velocity. So if the rate of change is the same at all times, then the acceleration is constant.
A sign is hung between two cables. If the sign weighs 350 N, what is the tension (in N) in each cable?
Answer:
Tension in each cable = 175 N
Explanation:
Given:
Number of cables = 2
Weight of sign board(T) = 350 N
Find:
Tension in each cable
Computation:
We know that,
T1 = T2
So,
T1 + T2 = T
T1 + T2 = 350
T1 + T1 = 350
T1 = 175
Tension in each cable = 175 N
A star has a declination of approximately 45°. Which of these statements is correct about the star?
A) It is 45° above the celestial equator.
B) It is 45° below the celestial equator.
C) It is 45° to the left of the celestial equator.
D) It is 45° to the right of the celestial equator.
The star is approximately 45° above the celestial equator. (A)
"Declination" on the celestial coordinate system is equivalent to latitude on the terrestrial one.