Who might benefit from this claim?

Who Might Benefit From This Claim?

Answers

Answer 1

The correct answer is D. Grocery stores that sell legumes

Explanation:

One of the main points this claim proposes is that metabolism can be improved by consuming legumes, this is expressed in "incorporating legumes such as lentils and chickpeas... boosts metabolism." In this context, if this is proven as true through an argumentative text or speech, it is likely many people want to increase their intake of legumes because a better metabolism has multiple benefits for health. Moreover, increased intake of legumes means an increase in the sale of legumes and higher profits for stores selling legumes. This means the claim might benefit grocery stores that sell legumens (option D.)


Related Questions

A student filled the graduated cylinder up to the 9.6 mL mark, but incorrectly recorded the volume as 10.0 mL. How would this affect the density? Explain.

Answers

Answer:

0.4 ml will be affect the density.

Explanation:

Given that,

A student filled the graduated cylinder up to the 9.6 mL mark.

Recorded volume = 10.0 mL

We know that,

Density :

Density is equal to the mass divided by volume.

In mathematically,

[tex]\rho=\dfrac{m}{V}[/tex]

Where, m = mass

V = volume

Affect the density :

Affect the density is equal to the change in volume.

We need to calculate the affect the density

Using formula of affect the density

[tex]\rho=V'-V[/tex]

Put the value into the formula

[tex]\rho=10.0-9.6[/tex]

[tex]\rho=0.4\ ml[/tex]

Hence, 0.4 ml will be affect the density.

2. Explain what an isotope is and give two important physical properties of isotopes that make them useful in biological research. Define half-life.​

Answers

Answer:

isotope is a variants of a particular chemical element which differ in neutron number, and consequently in nucleon number.All isotopes of a given element have the same number of protons but different number of neutrons in each atom.

The 2 important physical properties of isotope is

1.Melting Points2.Boiling Points

A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool? Enter your answer in scientific notation. The density of water is 1.0 g/mL.

Answers

Given :

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft .

Density of water , [tex]\rho=1\ g/ml=1000\ kg/m^3[/tex] .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

[tex]1\ ft =0.3\ m[/tex]

For ,

[tex]3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m[/tex]

So , volume of pool is :

[tex]V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3[/tex]

We know , density is given by :

[tex]\rho=\dfrac{m}{V}[/tex]

So , [tex]m=\rho V[/tex]

Putting given values in above equation :

[tex]m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg[/tex]

Hence , this is the required solution.

The value of mass in kg is [tex]1.76\times10^{6} \ kg[/tex].

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft  

Covert depth into m from ft.[tex]1ft=0.3m[/tex]

[tex]3.7ft=0.3\times3.7\\=1.11m[/tex]

Volume of pool is as follows:-

[tex]Volume=59.8\times26.6\times1.11\\=1765.65\ m^{3}\\=1765.65\times1000\ L=1765650 L[/tex]

Density:-

It is defined as mass per unit volume.

[tex]Density=\frac{Mass}{Volume}[/tex]

Substitute 1.0 kg/L for density and 1765650 L for volume for the calculation of mass as follows:-

[tex]m=1kg/L \times1765650\ L\\\\=1.76\times10^{6} \ kg[/tex]

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At STP how many liters of NH3 can be produced from the reaction of 2.00 mol of N2 with 2.00 mol of H2

Answers

Answer:

29.9L of NH₃ are produced

Explanation:

The reaction of H2 with N2 to produce NH3 is:

3 H2 + N2 → 2 NH3

For a complete reaction of 2.00 moles of H2 there are required:

2.00 moles H2 * (1 mole N2 / 3.00 moles H2) = 0.667 moles N2

The limiting reactant is hydrogen.

The volume of hydrogen using PV = nRT is (STP: 273.15K; 1atm):

V = nRT / P

V = 2.00mol * 0.082atmL/molK*273.15K / 1atm

V = 44.8L

As we know for the reaction, 3 moles of hydrogen produce 2 moles of NH3.

The moles of H2 produced are:

2mol H2* (2mol NH3 / 3mol H2) = 1.33 moles NH3 are produced

Under pressure and temperature constant (STP) you can apply The Avogadro's law that states:

V₁ / n₁ = V₂ / n₂

Where V is volume and n moles of 1, the first gas and 2, the second gas.

V₁ / n₁ = V₂ / n₂

44.8L / 2.00mol = V₂ / 1.33 moles

V₂ =

29.9L of NH₃ are produced

Which aqueous solution has the highest boiling point?a. 0.20 M NaClb. 0.10 M CaCl2c. 0.1 M Ga2(SO4)3d. 0.2 M C6H12O6

Answers

Answer:

c. 0.1 M Ga₂(SO₄)₃

Explanation:

The boiling point increasing of a solvent due the addition of a solute follows the formula:

ΔT = K*m*i

Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.

That means the option with the higher m*i will be the solution with the highest boiling point:

a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).

m* i = 0.20*2 = 0.4

b. CaCl₂; i = 3. 3 ions.

m*i= 0.10M * 3 = 0.3

c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5

m*i = 0.10M*55 = 0.5

d. C₆H₁₂O₆ has i = 1:

m*i = 0.2M*1 = 0.2

The solution with highest boiling point is:

c. 0.1 M Ga₂(SO₄)₃

Protons have about the same mass as

Answers

Answer:

[tex]\Large \boxed{\mathrm{neutrons}}[/tex]

Explanation:

Protons have about the same mass as neutrons.

Protons have a mass of 1 amu

Neutrons have a mass of 1 amu

Electrons have a mass of 1/1836 amu

Answer:

Protons and neutrons have approximately the same mass,

Explanation:

1.6726219 × 10^-27 kilograms is the mass of protons as well as neutrons

Select the single best answer. When 2-heptyne was treated with aqueous sulfuric acid containing mercury(II) sulfate, two products, each having the molecular formula C7H14O, were obtained in approximately equal amounts. What are these two compounds

Answers

Answer:

heptan-3-one and heptan-2-one

Explanation:

In this case, we must remember what the products of this reaction are. An alkyne in the presence of HgSO4 and H2SO4 will produce a ketone. But, in the triple bond, we have two carbons, therefore the carbonyl group can be placed on any of the carbons of the triple bond.

In figure 1 we have the general reaction. At C = O it can be added to the carbon on the left (red carbon) or the carbon on the right (blue carbon).

Following this logic, for 2-heptyne the carbonyl group can be added to carbon 2 producing heptan-2-one. Similarly, the carbonyl group can be added to carbon 3 producing heptan-3-one. (See figure 2)

g The chemicals above are dissolved in water to make a solution. Which ones will conduct electricity

Answers

Answer:

This question is incomplete

Explanation:

Although, the question above is incomplete, however the correct option can be deduced from the explanation below.

Compounds/chemicals that dissolve in water to conduct electricity are Ionic/electrovalent compounds. Ionic compounds/salts are compounds that are held together by ionic/electrovalent bond. These compounds dissociate in water to form ions; the dissociated ions formed are the carriers of electric charges hence enabling the salt solution conduct electricity. Examples of these electrovalent/ionic compounds include NaCl, CaCl₂, CsF and MgO.

NOTE: Identify the ionic/electrovalent compounds in the options (from the completed question) to get your answer.

When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2

Answers

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

For the reaction2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)ΔH° is -125 kJ/mol and ΔS° is +253 J/K ∙ mol. This reaction is ____.A. spontaneous only at low temperatureB. spontaneous only at high temperatureC. spontaneous at all temperaturesD. nonspontaneous at all temperaturesE. unable to determine without more information

Answers

Answer:

C. spontaneous at all temperatures

Explanation:

The spontaneity of  reaction is determined by the sign of the  gibbs free energy.

A negative sign denotes that the reaction is spontaneous, positive sign means the reaction is not spontaneous.

From the question;

ΔS° = +253 J/K

ΔH° = -125 kJ/mol

ΔG = ΔH°  - TΔS°

From the data given, the condition in which we can obtain a negative value of G, is at any value of T.

For any value of T, G would always be a negative value.

This means the correct option is option C.


Which metal is used to make foils for packaging of food?​

Answers

Explanation:

aluminium metal is used to make foils for packaging of food

aluminum metal is best used for packaging foods

at critical humidity the rate of corrosion is​

Answers

Answer:

Corrosion of carbon steel occurs when the relative humidity of the air is 70% to 80% and the air temperature is above 32 F.

Hope this helps you :)

Which of the following is the best example of one
way carbon progresses through the carbon
cycle?
A. Humans take in carbon dioxide and give off
carbon dioxide through respiration.
B. Marine organisms transform carbohydrates from
the atmosphere into carbon gas.
C. Fungi take in carbohydrates as nutrients and
release oxygen into the atmosphere.
D. Plants take in carbon dioxide and turn it into
carbohydrates during photosynthesis.

Answers

Answer:

D. Plants take in carbon dioxide and turn it into

carbohydrates during photosynthesis.

Explanation:

Which one of these salts will form a neutral solution on dissolving in water? KNO2 NaCN NaCl NH4NO3 FeCl3

Answers

Answer:

NaCl

Explanation:

Salts whose ion cannot hydrolyse form neutral solutions; not having alkaline nor acidic properties.

All the other salts would dissociate to form solution or strong acid ad weak bases or vice versa, which then determines their alkalinity or acidity: all except sodium chloride, NaCl.

I hope this explanation was helpful and clear.

g Write an equation showing what happens when AgNO3 is added, and explain why the equilibrium shifts

Answers

Answer:

[tex]\mathbf{AgNO_3+Cl^- \to AgCl_s + NO^{3-}}[/tex]

Explanation:

The addition of AgNO3 to the system Cl⁻ react with result into the formation a precipitate of AgNO3, as such the reactant concentration decreases.

[tex]\mathbf{AgNO_3+Cl^- \to AgCl_s + NO^{3-}}[/tex]

Suppose the concentration of a given substance is present in an equilibrium system is changed without a change in any of the other conditions, then, by le chatelier's principle, the position of equilibrium will move to decrease the concentration of the added substances.  In order to relieve this constraint, the equilibrium will shift to the right favouring the forward reaction.

The following pairs of aqueous solutions are separated by a semipermeable membrane. In which direction will the solvent flow?a. A = 3.45 M calcium iodide; B = 3.45 M sodium bromideb. A = 5.00 M sucrose; B = 3.00 M potassium nitrate

Answers

Answer:

osmosis is a process where by solvent or fluid molecules flow from low concentration to high concentration.

So in

A.solvent will flow from B to A because

B = 3.45 M sodium bromide is more concentrated than 3.45 M calcium iodide;

b) solvent still flow from B to A because

A = 5.00 M sucrose is less concentrated than B = 3.00 M potassium nitrate

Barry Bonds hit 62 homeruns in one season. Given there are 4 bases and each base is
90 feet apart, how many kilometers did he run?

Answers

Answer:

6.803136 KM

Explanation:

I multiplied 90 by 4 to get 360 feet, or the distance of each homerun. 360 times 62 gave me 22,320.

22,320 converted to KM is 6.803136 Km

you may want to round it up, but I would use the precise answer.

Barry Bonds is a former American baseball player that played in various leagues and seasons. In 62 home runs and 4 bases, he ran around 6.803136 Kilometers.

What is the unitary method?

The unitary method is the mathematical technique to estimate the values of units from a single value by multiplication and division. It uses the cross multiplication application to find the other values.

Given,

Number of bases = 4

Distance between each base = 90 feet apart

Number of home runs in one season = 62

By using the cross multiplication and unitary method the distance can be calculated as:

1 base = 90 feet apart

4 base = X feet

Solving for X as:

X = 90 × 4

= 360 feet

If one homerun = 360 feet

Then, 62 homerun = X feet

X is calculated as:

X = 360 × 62

= 22,320 feet

The units from feet to km are converted as:

1 feet = 0.0003048 km

Then, 22,320 feet = 6.803136 km

Therefore, Barry Bonds ran 6.803136 km.

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A balloon under 1 atm of pressure contains 10.0 g of neon gas. With the temperature kept constant, 15.0 g of xenon gas is added. What happens?

Answers

Answer:

The volume of the ballon expands 1.2 times

Explanation:

The pressure in the ballon will be always the same. And as temperature is also the same the only parameters that change are moles of gas and volume.

The volume is directely proportional to  moles of the gas under pressure and temperature constant (Avogadro's law). That means:

V₁ / n₁ = V₂ / n₂

Where V is volume and n moles of 1, initial statet and 2, final state of the gas

Initial moles of Neon gas (20g/mol) are:

10.0* (1mol / 20g) = 0.5 moles are equal to initial moles that occupies X liters of volume.

As you add 15.0g of Xe (Molar mass: 131g/mol):

15.0g * (1mol / 131g) = 0.11 moles + 0.55 moles = 0.66 moles that are final moles.

Replacing in Avogadro's law:

V₁ / n₁ = V₂ / n₂

X L / 0.55moles = V₂ / 0.66 moles

1.2X L = V₂

That means the volume of the ballon expands 1.2 times

How many dm³ of hydrogen,measured at s.t.p.,would be needed to reduce 47.7g of copper(II) oxide to copper?

A. 4.48
B. 6.72
C. 10.82
D. 13.44​

Answers

Answer:

Option D. 13.44

Explanation:

We'll begin by calculating the number of mole in 47.7g of copper(II) oxide, CuO.

This can be obtained as follow:

Mass of CuO = 47.7 g

Molar mass of CuO = 63.5 + 16 = 79.5 g/mol

Mole of CuO =.?

Mole = mass /Molar mass

Mole of CuO = 47.7/79.5

Mole of CuO = 0.6 mole

Next, we shall write the balanced equation for the reaction. This is given below:

CuO + H2 —> Cu + H2O

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2 to produce 1 mole of Cu and 1 mole of H2O.

Next, we shall determine the number of mole of H2 needed to react completely with 0.6 mole of CuO.

This can be obtained as follow:

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2.

Therefore, 0.6 mole of CuO will also react with 0.6 mole of H2.

Finally, we shall determine the volume occupied by 0.6 mole of H2 at STP.

This can be obtained as follow:

1 mole of H2 occupied 22.4 dm³ at STP.

Therefore, 0.6 mole of H2 will occupy = 0.6 × 22.4 = 13.44 dm³.

Therefore, 13.44 dm³ of H2 is needed for the reaction.

A student determines the volume of a cube to be 4.6 cm?
What is the percent error if the correct volume of the crystal is
4.3 cm??

Answers

Answer:

6.98%

Explanation:

% error= |experimental value - actual value|/actual value × 100

Experimental value= 4.6 cm

Actual value= 4.3 cm

% error = |4.6-4.3|/4.3 × 100

% error = 6.98%

Answer: 7%

Explanation:

The quantity, 1,385 mg is equivalent to in scientific notation

Answers

Answer:

The answer is 1385 x10∧ -3

Explanation:

Scientific notation is a quick way to represent a number using notation in exponential form or powers of base ten.

This notation allows us to express too large or small numbers easily.

For example:

500 is written as 5x10∧2; Where the power 2 represents the number of 0's that follow 5.

0.0093 is written as 9.3x10∧-3; Where the power -3 represents the number of times the comma was moved to the right.

Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical reaction:
S8 + 24F2------ 8S + F6
Round your answer to zero decimal places.J/K

Answers

Answer:

[tex]\Delta _rS\°=-2965.27J/K[/tex]

Explanation:

Hello,

In this case, for the considered reaction, the standard reaction entropy is computed considering the standard entropy of each product and reactant and their stoichiometric coefficients as shown below:

[tex]\Delta _rS\°=8*S\°_{SF_6}-S\°_{S_8}-24*S\°_{F_2}[/tex]

Thus, considering the ALEKS Data tab, we obtain:

[tex]\Delta _rS\°=8*(291.52J/K)-(430.23J/K)-24*(202.8J/K)\\\\\Delta _rS\°=-2965.27J/K[/tex]

Regards.

Why is Hydrogen Peroxide lethal to drink if it is only composed of one more molecule of oxygen than water?

Answers

Answer: Hydrogen peroxide is a clear, odorless, and colorless liquid consisting of hydrogen and oxygen. It’s available in dilutions ranging from 3–90%, some of which are sometimes used as an alternative health remedy.

Advocates suggest that drinking a few drops of hydrogen peroxide diluted in water may help treat a range of illnesses, including diabetes and even some forms of cancer.

However, medical professionals warn against the dangers of this practice.

This article takes a look at the latest evidence to determine whether the benefits of drinking hydrogen peroxide outweigh its potential risks.

Explanation:

If you have ingested small amounts of 3% hydrogen peroxide, call your local poison control helpline for assistance. If you have swallowed larger amounts or higher concentrations, seek immediate medical assistance from an emergency room.

The bottom line

Hydrogen peroxide is touted as an alternative health remedy for a range of health conditions.

However, there’s no scientific evidence that drinking it yields any benefits. Plus, doing so is linked to dangerous side effects, including breathing problems, severe gut damage, and in some cases, death.

For these reasons, drinking any concentration or amount of hydrogen peroxide is not recommended.

What is the cost of 4 oranges, if 6 oranges weigh 2.4 pounds and the price of oranges are
$0.50 per pound?

Answers

Answer:

$.80

Explanation:

2.4 / 6 = 0.4

0.4 lbs per orange

0.4 x 4 = 1.6

4 oranges = 1.6 lbs

1.6 x 0.50 = $0.80

Cost is the price or the amount required to purchase a product by money. The four oranges will cost $0.80 if six oranges weigh 2.4 pounds and $0.50 per pound.

What is the cost?

The cost has been used in commerce and accounts and is defined as the monetary amount required by the person to pay for purchasing the object. The amount of the object can be based on various proportions. The cost of bananas can be estimated by the unitary method.

Given,

Weight of six oranges = 2.4 pounds

Price of oranges per pound = $0.50

At first, the weight of one orange is calculated as:

If 6 oranges = 2.4 pounds

Then, 1 orange = 0.4 pounds per orange

Second, the weight of four oranges is calculated as:

1 orange = 0.4 pounds

4 oranges = 1.6 pounds

Third, the cost of four oranges is calculated as:

1 pound = $0.50

1.6 pounds = $0.80

Therefore, 4 oranges cost $0.80.

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Anatomy+ Chemistry List the 8 common ions in the human body and their charge. Identify each as a cation or anion.

Answers

Answer:

Sodium ions - Na⁺ - cation

Potassium ions - K⁺ cation

Chloride ions - Cl⁻ anion

Magnesium ions - Mg²⁺ cation

Calcium ions - Ca²⁺ cation

Phosphate ions - P³⁻ anion

Iron ions - Fe²⁺ cation

Zinc ions - Zn⁺ cation

Explanation:

Following is a list of 8 common but essential ions in the cells and fluids of human bodies:

1. Sodium ions helps in regulation and control the level of body fluids

2. Potassium ions help regulate cellular functions

3. Calcium ions are essential for building and maintaining strength bones and teeth. and have role in blood clotting, muscle contraction, and the transmission of nerve signals to cells.

4. Chloride ions are the main anions found outside body cells. They acts as counterions

5. Magnesium ions  present in the bones

6. Phosphate ions present in body fluids act as the counterions.

7. Iron

8. Zinc

What is the normality of 500ml
Solution of Sodium hydroxide Containing 30 gm naoh?​

Answers

Answer:

[tex]N=1.5N[/tex]

Explanation:

Hello,

In this case, since normality is defined in terms of the equivalent grams and the volume of the solution:

[tex]N=\frac{eq-g}{V}[/tex]

We need to compute the equivalent grams by considering that the molar mass of NaOH is 40 g/mol and one mole of NaOH contains one equivalent grams due to the presence of one hydroxyl ion only:

[tex]eq-g=30gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1eq-g}{1mol}=0.75eq-g[/tex]

And the volume in liters (0.500 L). Therefore, we obtain:

[tex]N=\frac{0.75eq-g}{0.500L} \\\\N=1.5N[/tex]

Regards.

Which reactant in each of the following pairs is more nucleophilic? Explain.a. -NH2 or NH3b. H20 or CH3CO2-c. BF3 or F-d. (CH3)3P or (CH3)3Ne. I- or Cl-f. -C triple bonded to N or -OCH3

Answers

Answer:

I^- or Cl^-

Explanation:

A nucleophile is any reagent that donates an unshared pair of electrons to form a new covalent bond. Nucleophiles are mostly bases also. Nucleophilicity is a kinetic property, it refers to the rate at which a nucleophile replaces a leaving group from an alkyl halide.

Looking at the options, Cl^- and I^- are the best nucleophiles among the options provided in the question.

3.5 cm in length x 3.2 in height x 0.3cm in with calculate the volume

Answers

Answer:

volume = area×breadth×height

Explanation:

answer is 3.36

g What is the major problem with using Friedel-Crafts alkylation to mono-alkylate an aromatic ring?

Answers

Answer:

Explanation:

Following are the problems to mono-alkylate the aromatic ring .

1 ) The carbocations formed in the process undergo rearrangement when the number of carbon to be added in the alkylation process is more than two .

2 ) The formed monoalkylated product is more reactive than reactant so reaction does not stop after monoalkylation . Dialkylation and tri alkylation product too are simultaneously formed . This can be controlled by using benzene in excess as reactant . Monohalo benzene or nitrobenzene  are  too weak to undergo Friedel craft reaction because of presence of deactivating

group .

What volume (mL) of a 0.3428 M HCl(aq) solution is required to completely neutralize 23.55 mL of a 0.2350 M Ba(OH)2(aq) solution

Answers

Answer:

32.29 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2HCl(aq)+ Ba(OH)2(aq) —> BaCl2(aq) + 2H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid (nA) = 2

Mole ratio of the base (nB) = 1

Next, data were obtained from. This include the following:

Molarity of acid, HCl (Ma) = 0.3428 M

Volume of acid, HCl (Va) =.?

Molarity of base, Ba(OH)2 (Mb) = 0.2350 M

Volume of base, Ba(OH)2 (Vb) = 23.55 mL

Finally, we shall determine the volume of the acid, HCl required for the reaction as follow:

MaVa /MbVb = nA/nB

0.3428 × Va / 0.2350 × 23.55 = 2/1

Cross multiply

0.3428 × Va = 0.2350 × 23.55 × 2

Divide both side by 0.3428

Va = (0.2350 × 23.55 × 2) / 0.3428

Va = 32.29 mL

Therefore, the volume of acid, HCl required for the reaction is 32.29 mL

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They need to raise a total of $1,630. Enter and solve an equation to find how much money they need. Show that your answer is reasonable. Let m represent your variable. In a class full of men and women, 2/9 of the class are women. What is the ratio of men towomen in its simplest form? For each of the following variables, determine whether the variable is categorical or numerical. If the variable is numerical, determine whether the variable is discrete or continuous. In addition, determine the measurement scale a. Number of cellphones in the household b. Whether there is a high-speed Internet connection in the household c. Distance (in miles) from a person's house to the nearest store d. Number of text messages exchanged per month e. Time in hours spent exercising per week a. Number of cellphones in the household is what kind of variable? A. This variable is a categorical variable that is ordinal-scaled. B. This variable is a discrete numerical variable that is interval-scaled. C. This variable is a continuous numerical variable that is interval-scaled. D. This variable is a continuous numerical variable that is ratio-scaled. E. This variable is a categorical variable that is nominal-scaled. F. This variable is a discrete numerical variable that is ratio-scaled. b. Whether there is a high-speed Internet connection in the household is what kind of variable? A. This variable is a discrete numerical variable that is interval-scaled. B. This variable is a continuous numerical variable that is interval-scaled. C. This variable is a categorical variable that is ordinal-scaled. D. This variable is a categorical variable that is nominal-scaled. E. This variable is a continuous numerical variable that is ratio-scaled. F. This variable is a discrete numerical variable that is ratio-scaled. c. Distance (in miles) from a person's house to the nearest store is what kind of variable? A. This variable is a continuous numerical variable that is interval-scaled. B. This variable is a categorical variable that is ordinal-scaled. C. This variable is a categorical variable that is nominal-scaled. D. This variable is a discrete numerical variable that is interval-scaled. E. This variable is a continuous numerical variable that is ratio-scaled. F. This variable is a discrete numerical variable that is ratio-scaled. d. Number of text messages exchanged per month is what kind of variable? A. This variable is a discrete numerical variable that is interval-scaled. B. This variable is a continuous numerical variable that is interval-scaled. C. This variable is a categorical variable that is ordinal-scaled. D. This variable is a continuous numerical variable that is ratio-scaled. E. This variable is a discrete numerical variable that is ratio-scaled. F. This variable is a categorical variable that is nominal-scaled. e. Time in hours spent exercising per week is what kind of variable? A. This variable is a continuous numerical variable that is interval-scaled. B. This variable is a discrete numerical variable that is ratio-scaled. C. This variable is a categorical variable that is ordinal-scaled. D. This variable is a categorical variable that is nominal-scaled. E. This variable is a discrete numerical variable that is interval-scaled. F. This variable is a continuous numerical variable that is ratio-scaled. What is the purpose of the color-coding approach used in staff assessment products (i.e., green - on plan, amber - off plan but okay, etc.)? What are the different forms of energy involved in stretching and releasing a rubber band? What other processes are similar? Why would large-scale damage to your epidermis in danger your body to other harmful environmental factors? How long would it take a hawk to stop if he was flying at 9m/s and decelerated at 3m/s2? Help.................... What is an important first step you can take to prepare for an emergency? The Hebrews (Israelites) were the first civilization to believe what? Which of the following are screen objects used to maintain, view, and print data from a database?A. Form.B. Field.C. Data files.D. Entities. Who is the president of the USA during the Great Depression Write a story that ends with the statement : l had never been so embarrassed in my life. If B is the midpoint of AC, solve for x, and find the lengths of AB, BC, and AC.Please show all work and not just the answers. Which tool encrypts entire drives, rendering them unusable unless one possesses the correct key to unlock the drive?