How many times greater is
6.6 x 10^10
than
3 x 10^7
2.2
22
1000
2200
Answer:
2,200
Step-by-step explanation:
6.6 x 10^10
= 66,000,000,000
3 x 10^7
= 30,000,000
66,000,000,000 ÷ 30,000,000
2,200
Answer:
2200.
Step-by-step explanation:
6.6 / 3 * 10^10/10^7
= 2.2 * 10^3
= 2200
A researcher wishes to see if the average weights of newborn male infants are higher than the
average weights of newborn female infants. She selects a random sample of 12 male infants and
finds the mean weight is 7.70 pounds. She selects a random sample of 9 female infants and finds
that the mean Leight is 7.80 pounds. Assume that the variables are normally distributed and the
population standard deviation is 0.5 for each group.
Using alpha=0.05 to test if the mean weight of the males is higher than the mean weight of the
females, the pvalue of the test is:
Answer:
The p-value is [tex]p-value = 0.62578[/tex]
Step-by-step explanation:
From the question we are told that
The sample size of male infant is [tex]n_1 = 12[/tex]
The sample size of female infant is [tex]n_2= 9[/tex]
The sample mean of male infant is [tex]\= x_1 = 7.70 \ lb[/tex]
The sample mean of female infant is [tex]\= x_2 = 7.80 \ lb[/tex]
The population standard deviation is [tex]\sigma = 0.5[/tex]
The significance level is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu_ 1 = \mu_2[/tex]
The alternative hypothesis is [tex]H_1 : \mu_1 > \mu_2[/tex]
The test statistics is mathematically represented as
[tex]t =\frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma }{n_1} } + \frac{\sigma }{n_2} } }[/tex]
=> [tex]t = \frac{7.70 -7.80}{\sqrt{\frac{0.5 }{12} } + \frac{0.5 }{9} } }[/tex]
=> [tex]t = -0.3207[/tex]
From the z-table the p-value is obtained, the value is
[tex]p-value = P(Z > -0.3207) = 0.62578[/tex]
[tex]p-value = 0.62578[/tex]
if a salesman has a base salary of 35,000 per year makes 5% commission on each sales ,how much must he do in sales to make a total of 75,000 for the year
He must do a 8,00,000 sales to make total of 75000 for the year.
For salesman base salary = 35000, Salary to be atained is 75000. Having commission of 5% on every sales. Sales to be determine so the salesman attained 75000 for year.
In mathematics it deals with numbers of operations according to the statements.
Here, according to the statement.
Let x be sales,
35,000 + 5%x = 75,000
0.05x = 75000-35000
x = 40000/0.05
x = 8,00,000
Thus, he must do a 8,00,000 sales to make total of 75000 for the year
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can some0ne help me?
Answer:
(x - 2)/3
(x - 4)/-5 or (-x + 4)/5
Step-by-step explanation:
this is an inverse function, and to solve an inverse function you would :
swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it
the first question's answer is :
g(x) = 3x + 2
x = 3(g(x)) + 2
x - 2 = 3(g(x))
(x - 2)/3 = g(x)
the second one is:
g(x) = 4 - 5x
x = 4 - 5(g(x))
x - 4 = -5(g(x))
(x-4)/-5 = g(x)
g(x) = 3x + 2
y = 3x + 2
x = 3y + 2
3y = x - 2
y = x/3 - 2/3
inverse g(x) = (x - 2) / 3
g(x) = 4 - 5x
y = 4 - 5x
x = 4 - 5y
5y = 4 - x
y = 4/5 - x/5
inverse g(x) = (4 - x) / 5
Eliminate the parameter for the following set of parametric equations: x= t^2 + 2 y= 4t^2
Answer:
Solution : y = 4x - 8
Step-by-step explanation:
The first thing we want to do is isolate t², rather than t. Why? As you can see when we substitute t² into the second equation, it will be easier than substituting t, as t is present in the form t². So, let's isolate t² in the first equation --- ( 1 )
x = t² + 2,
t² = x - 2
Now let's substitute this value of t² in the second equation --- ( 2 )
y = 4t²,
y = 4(x - 2),
y = 4x - 8 ~ And hence our solution is option c.
2. Place the following values in scientific notation:
2020000 m
C. 0.003020 km
9901000 m/s
d. 0.001100 mm
Answer: a. [tex]2.02\times10^6\ m[/tex]
b. [tex]9.901\times10^6\ m/s[/tex]
c. [tex]3.02\times10 ^{-3}\ km[/tex]
d. [tex]1.1\times10^{-3}\ mm[/tex]
Step-by-step explanation:
Scientific notation is a technique to express a very big or a very small number in the product of a decimal form of number ( between 1 and 10) and powers of 10.
a. [tex]2,020,000 m\ = 2.02\times1,000,000=2.02\times10^6\ m[/tex]
b. [tex]9,901,000\ m/s =9.901\times1000000=9.901\times10^6\ m/s[/tex]
c. [tex]0.003020\ km=\dfrac{3020}{1000000}[/tex]
[tex]=3.02\times10 ^{-3}\ km[/tex]
d. [tex]0.001100\ mm=\dfrac{1100}{1000000}=\dfrac{11}{10000}[/tex]
[tex]1.1\times10^{-3}\ mm[/tex]
A particular country has total states. If the areas states are added and the sum is divided by , the result is square kilometers. Determine whether this result is a statistic or a parameter.
Answer:
Some texts are missing from the question, I found a possible match, and here it is:
A particular country has total of 45 states. If the areas of 35 states are added and the sum is divided by 35, the result is 135,600 square kilometres. Determine whether this result is a statistic or a parameter.
Answer:
The result is a statistic because the data involved are samples.
Step-by-step explanation:
A Parameter is a numerical representation of an entire population. That is they are numbers summarizing data for an entire population. In this case, if all the 45 states were measured, the result would have been a parameter.
On the other hand, statistics are numbers that are subsets (representative portions) of an entire population. Since 35 states were chosen out of 45 states, the average area of the 35 states is a statistic and not a parameter.
if P(x)=1+6x-5x^2 represents the profit in selling x thousand Boombotix speakers, how many speakers should be sold to maximize profit?
Answer:
600
Step-by-step explanation:
[tex]p(x) = 1 + 6x - 5x^2[/tex]
x max = [tex]-b/2a[/tex]
a = -5
b = 6
-6/2(-5) = 6/10 = 3/5 = .6
.6 thousand = 600
600 speakers should be sold.
Alternatively, you can check the vertex of the parabola formed.
Which of the following is not a way of generating random numbers? A. random number tables B. using phone numbers selected at random in a local phone book C. using the internet D. books of random numbers
Answer:
well all of these look like a way so we have to use elimination method
A : random number tables : well it has random numbers so X out
B: PHONE NUMBERS: well phone numbers are random so X out
C: USing the internet : totally X out
D: books of random numbers: X out
so none of the above i guess
The only way that might not be used in generating random numbers is : (B). using phone numbers selected at random in a local phone book
Meaning of random numbersRandom numbers are numbers that occurs randomly without prediction. these numbers are impossible to predict using past values.
Random numbers are important for computer encryption and lotteries.
In conclusion, The only way that might not be used in generating random numbers is using phone numbers selected at random in a local phone book
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Question: The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find the length of the remaining side?
Answer:
The hypotenuse is the longest side in a triangle.
a^2=b^2+c^2.
14^2=9^2+c^2.
c^2=196-81.
c^2=115.
c=√115.
c=10.72~11cm
Consider the following. C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
b Evaluate
Integral of (x+2y^1/2)ds
Answer:
a.
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b.
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
Step-by-step explanation:
Given that:
C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),
Then:
[tex]C_1 = (0,0) \\ \\ C_2 = (1,0) \\ \\ C_3 = (0,1)[/tex]
Also:
[tex]\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }[/tex]
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b Evaluate :
Integral of (x+2y^1/2)ds
[tex]\mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int \limits ^1_{0} \ (t + 0) \sqrt{1} } \\ \\ \mathtt{ \int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\ \mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits 2- t + 2\sqrt{t-1} \ \sqrt{1+1} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} \int \limits^2_1 2- t + 2\sqrt{t-1} \ dt }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2) \end {pmatrix} ^2_1}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ \sqrt{2} }{6} \ (11 )}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ 11 \sqrt{2} }{6}}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 0+2 \sqrt{3-t} \ \sqrt{0+1} }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 2 \sqrt{3-t} \ dt}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits^3_2 \begin {pmatrix} \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}[/tex]
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
look below for the image
Answer:
135.7 yd²
Step-by-step explanation:
Surface area of the cone,
πr²+πrl
= π×3²+π×11.4×3
= 43.2π
= 135.7 yd² (rounded to the nearest tenth)
If (5x+3):(7x+3)=3:4, find the value of x.
[tex]\\ \sf\longmapsto \dfrac{5x+3}{7x+3}=\dfrac{3}{4}[/tex]
[tex]\\ \sf\longmapsto 4(5x+3)=3(7x+3)[/tex]
[tex]\\ \sf\longmapsto 20x+12=21x+9[/tex]
[tex]\\ \sf\longmapsto 12-9=21x-20x[/tex]
[tex]\\ \sf\longmapsto x=3[/tex]
[tex]\large\rm \longrightarrow \: {\purple{ \frac{(5x + 3)}{(7x + 3)} \: = \: \frac{3}{4} }} \\ [/tex]
⇛ Now , Cross Multiplying
[tex]\large\rm \longrightarrow \: {\blue{ 4 \: (5x + 3) \: = \: 3 \: (7x + 3)}}[/tex]
[tex]\large\rm \longrightarrow \: {\red{ 20x \: + \: 3 \: = \: 21 \: + \: 3}}[/tex]
[tex]\large\rm \longrightarrow \: {\orange{ 12 \: - \: 9 \: = \: 21x \: - \: 20x }}[/tex]
[tex]\large\rm \longrightarrow \:{\green{ 3 \: = \: x}}[/tex]
⇛ Hence , the value of x is 3
In an experiment to determine whether there is a systematic difference between the weights obtained with two different mass balances, six specimens were weighed, in grams, on each balance. The following data were obtained:
Specimen A B
1 13.76 13.74
2 12.47 12.45
3 10.09 10.08
4 8.91 8.92
5 13.57 13.54
6 12.74 12.75
Can you conclude that the mean weight differs between the two balances?
i). State the null and alternative hypotheses.
ii). Compute the test statistic.
iii). State a conclusion using the a =0.05 level of significance.
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
6 12.74 12.75 -0.01 0.001
∑ 0.06 0.0173
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.
The equation of the line L is 2y-x=10.Find the coordinates of the point where L intersects the y-axis
Equation:- 2y-x=10
For L to intersects Y axis then X cordinate must be zero
so put value of X as zero (0)
2y=10
So Y cordinate is equal to 5
Cordinate:- (0,5)
which was the last palindromic date?
Answer:
The previous palindrome date in all formats came 909 years ago on 11/11/1111. The next will come in 101 years on 12/12/2121 and after that there will not be another until 03/03/3030.
It depends how you format the date. If you do mm/dd/yyyy format
mm = month
dd = day
yyyy = year
then the last palindromic date was September 10th, 2019 since this would be written as 9/10/2019 in the mm/dd/yyyy format
Taking out the slash symbols, we have the number 9102019 which is the same when we reverse the digits.
The answer will be different if you have the date format as dd/mm/yyyy
The illustration below shows the graph of y as a function of x.
Complete the following sentences based on the graph of the function.
The y-intercept of the graph is the function value y=_____
The smallest positive x-intercept of the graph is located at x=_____
The greatest value of y is y=____ and it occurs when x=____
For x between x and x= 2 π the function value y___ 0
Answer:
below
Step-by-step explanation:
that is the solution above
Find the area of the region enclosed by the curves x=3y^2, x=0, and y=2
Answer:
8
Step-by-step explanation:
Hello,
[tex]x=3y^2<=>y=\sqrt{\dfrac{x}{3}} \ \ for \ x\geq 0[/tex]
And for y = 2, x = 3 * 2 * 2 = 12 so first, let's compute
[tex]\displaystyle \int\limits^{12}_0 {\sqrt{\dfrac{x}{3}}} \, dx =\dfrac{1}{\sqrt{3}} \int\limits^{12}_0 {\sqrt{x}} \, dx\\\\=\dfrac{1}{\sqrt{3}} \left[ \dfrac{2}{3}x^{3/2}\right]_0^{12}\\\\=\dfrac{1}{\sqrt{3}} *\dfrac{2}{3}*12*\sqrt{12}\\\\=\dfrac{2*12*2*\sqrt{3}}{3*\sqrt{3}}\\\\=2*4*2=16[/tex]
The area which is asked is 12*2 - 16 = 24 - 16 = 8
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Using integrals, it is found that the area of the region enclosed by the curves in the interval is of 27 units squared.
In this problem:
The curve is [tex]x = 3y^2[/tex], hence the integral is relative to y.The lower limit is when x = 0, hence [tex]0 = 3y^2 \rightarrow y = 0[/tex].The upper limit is when y = 2.Then, the integral for the area is:
[tex]A = \int_{0}^{2} 3y^2 dy[/tex]
[tex]A = y^3|_{y = 0}^{y = 3}[/tex]
[tex]A = 3^3 - 0^3[/tex]
[tex]A = 27[/tex]
The area of the region enclosed by the curves in the interval is of 27 units squared.
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The manager of a garden shop mixes grass seed that is 60% rye grass with 140 pound of grass seed that is 80% rye grass to make a mixture that is 74% rye grass. How much of the 60% mixture is used?
Answer:
60 pounds
Step-by-step explanation:
Let x = number of pounds of grass seeds A
The number of pounds of grass seed B = 140 pounds
Total pounds of the resulting mixture = (140 + x) pounds
Rye grass A = 60% = 0.6
Rye grass B = 80% = 0.8
Total percent of mixture formed = 74% = 0.74
Hence, we have the equation:
0.6x + 0.8 × 140 = 0.74 ( 140 + x)
0.6x + 112 = 103.6 + 0.74x
Collect like terms
112 - 103.6 = 0.74x - 0.6x
8.4 = 0.14x
x = 60 pounds
Therefore, the quantity of the 60% mixture used is 60 pounds.
The manager of a garden shop mixes grass seed that is 60% rye grass with 140 pound of grass seed that is 80% rye grass to make a mixture that is 74% rye grass. How much of the 60% mixture is used?
15. (x - 3)
If f(x) = 2x2 – 5, find the following.
16.fly-2)
17. f(a+h)-f(a)
Answer:
16. f(y-2) = 2(y-2)²-5
= 2(y²-4y+4)-5
= 2y²-8y+8-5
= 2y²-8y+3
17. f(a+h)-f(a) = 2(a+h)²-5-(2a²-5)
= 2(a²+2ah+h²)-5-2a²+5
= 2a²+4ah+h²-2a²
= h²+4ah
Lauren bought 4 bags of popcorn for $3.00. What is the unit rate per bag of popcorn."?
Answer:
$0.75
Step-by-step explanation:
Given that
Number of bags of popcorn bought = 4
Total money spent = $3.00
To find:
Unit rate per bag of popcorn = ?
i.e. price of one bag of popcorn is to be find out.
Solution:
We can use ratio here to find the rate of one bag of popcorn.
4 bags bought at $3
4 bags : $3
Let us divide both the sides with 4.
[tex]\frac{4}4[/tex] bags : $ [tex]\frac{3}4[/tex]
OR
1 bag bought at $ 0.75
We can alternatively use unitary method.
4 bags are bought at $ 3
1 bag is bought at $ [tex]\frac{3}{4}[/tex]
1 bag is bought at $0.75.
So, unit rate per bag of popcorn is $0.75.
Evaluate [x + 1/y]^m × [x-1/y]^n /[y+1/x]^m [y-1/x]^n
9514 1404 393
Answer:
(x/y)^(m+n)
Step-by-step explanation:
[tex]\displaystyle\frac{\left(x+\frac{1}{y}\right)^m\left(x-\frac{1}{y}\right)^n}{\left(y+\frac{1}{x}\right)^m\left(y-\frac{1}{x}\right)^n}=\left(\frac{x}{y}\right)^m\left(\frac{x}{y}\right)^n\\\\=\boxed{\left(\frac{x}{y}\right)^{m+n}}[/tex]
evaluate the expression
The area of a rectangular garden if 6045 ft2. If the length of the garden is 93 feet, what is its width?
Answer:
65 ft
Step-by-step explanation:
The area of a rectangle is
A = lw
6045 = 93*w
Divide each side by 93
6045/93 = 93w/93
65 =w
Answer:
[tex]\huge \boxed{\mathrm{65 \ feet}}[/tex]
Step-by-step explanation:
The area of a rectangle formula is given as,
[tex]\mathrm{area = length \times width}[/tex]
The area and length are given.
[tex]6045=93 \times w[/tex]
Solve for w.
Divide both sides by 93.
[tex]65=w[/tex]
The width of the rectangular garden is 65 feet.
Simplify the expression 3-8x3-4
Answer:
−8x3−1
Step-by-step explanation:
let's simplify step-by-step.
3−8x3−4
=3+−8x3+−4
Combine Like Terms:
=3+−8x3+−4
=(−8x3)+(3+−4)
=−8x3+−1
Answer:
-1 - (2x^3)^3
Step-by-step explanation:
The equation is:
=> 3 - 8x^3 - 4
=> -1 - 8x^3
=> -1 - (2x^3)^3
Convert the following equation
into standard form.
y = 7 - 7x
[?]x + y = []
Answer:
[tex]y = 7 - 7x \\ y + 7x = 7 \\ 7x + y = 7[/tex]
Answer:
7x + y = 7
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Given
y = 7 - 7x ( add 7x to both sides )
7x + y = 7 ← in standard form
What are the odds IN FAVOR of picking a red marble from a bag of 10 green marbles, 10 yellow marbles, and 5 red marbles?
Answer:
there is a 20% chance of getting a red marble
Step-by-step explanation:
Answer:
there is a 1/5 percent chance or 20%
Step-by-step explanation:
Hope this helps!
What would happen if addition were not associative?
Select all that apply.
A. The sum of 0 and a number would not always result in that number
B. The basic addition facts would not be true.
C. Addends could not be arranged in groups that sum to 10s to make column addition easier.
D. Addends could only be added in order from left to right.
Answer:
B, C, and D........................
35) Like J is represented by the equation 3x-2y=10. Line M is perpendicular to line J at (6,-1) What is the equation of Line M
Answer:
y=-2/3x+3
Step-by-step explanation:
the equation of line J is y=3/2x-5
perpendicular slope would be -2/3
you want it at point (6, -1) so sub the points into y=-2/3x+b
-1=-2/3(6)+b
-1=-4+b
3=b
y=-2/3x+3
I need help please anyone ?????!!!
answer:
2 on the picture is the amplitude