why must the displacement vector of the lighter ball be scaled by the ratio of masses of the two balls?

Answers

Answer 1

If no external force on the Centre of mass remains stationary. In order to do that displacement in lighter body must be more than that of heavier ball.

The sum of the starting momentums of the two bodies when they collide is equal to the sum of their final momentums, according to the law of conservation of momentum.

The experimental system supports the law of conservation of linear momentum when a collision occurs between a heavier ball and a lighter ball in the absence of any other external forces.

The centre of mass does not move due to any external forces. A lighter body must have a greater displacement than a heavier ball in order for that to happen. Changes in an object's position are referred to as displacement. A vector quantity, it has both a direction and a magnitude. An arrow that directs viewers from the starting location to the ending position is used to symbolize it. As an illustration, the position of an object changes if it moves from position A to position B. Displacement is the name for this shift in an object's position.

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magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1550 newtons while magnus pulls the bus a distance of 2.15 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.

Answers

The Work done by tension force on Magnus is

- 3225 Joule .

In the given question we have, one end of rope is tied around magnus waist and other attched to bus and he pulls the bus. The direction of tension force is just work done.

constant force = 1550 Newton

displacement = 2.15 meters

The direction of tension force is opposite to work done due to the tension force is reaction force to force of work done for pulling the bus.

work done by tension = W = - W₀

where W₀is horizontal work done by magnus during pulling.

so, W₀ = Fdcosθ

where , F---> force , d--> displacment and θ ---> angle between force and displacement

As we see whole work done in horizontal direction. So, angle between force and displacement is zero.

put all the vales in above formula we get ,

W₀= 1550× 2.15 cos0 = 1550×2.15 = 3225 Joule

W = - W₀ = - 3,225J

Hence, work done by tension force on Magnus is

- 3,225 Joule.

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A plane flies with an average
velocity of -98.5 m/s for 45.0 s.
What was its displacement?
(Unit = m)
Don't forget: velocities and displacements to
the right are +, to the left are -.

Answers

Answer:-4432.5 m

Explanation:trust

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A speaker, rated at 4V, draws a current of 13A. It is left switched on for 3 seconds. How much electrical work is done on a speaker?

Answers

Answer:

16C

Explanation:

since current=CHARGE/TIME

THEREFORE CHARGE=TIME X CURRENT

=2X8

=16C

9-3 is it possible for a small force to produce a larger impulse on a given object than a large force? explain.

Answers

It is possible for a smaller force with a longer time to be stronger than a larger force with a shorter time since impulse equals force x time.

Is it possible for a small force to produce a larger impulse?Yes, since impulse is defined as the product of the applied force and the applied time (J=Ft J = F t), a smaller force acting over a longer period of time may produce a larger impulse than a larger force acting over a shorter period of time. Force times time equals impulse.In comparison to a bigger force that acts over a much shorter period of time, a tiny force acting over a long period of time can easily produce more impulse (change in momentum). An object's momentum is a function of its mass times its velocity.An item can be propelled at the same speed by a tiny force applied over a long time as it can by a high force applied quickly.

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Projectile motion is a combination of _______________ motion in the horizontal direction, and ________________ motion in the vertical direction.

A. accelerated, accelerated
B. constant, constant
C. accelerated, constant
D. constant, accelerated

Answers

Projectile motion is a combination of constant motion in the horizontal direction, and accelerated motion in the vertical direction. Therefore, the correct answer option is: D. constant, accelerated.

What is projectile motion?

Projectile motion can be defined as a form of motion which is experienced by a physical object (body) that is projected near the surface of planet Earth, while moving along a parabolic (u-shaped curve) path, and under the influence of a gravitational force only.

Based on scientific research and records by scientists such as Galileo, we can infer and logically deduce that the initial horizontal velocity of a physical object undergoing a projectile motion is always equal to its final horizontal velocity.

Additionally, Galileo stated that projectile motion combines constant or uniform motion in the horizontal direction and accelerated motion in the vertical direction.

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What is the normal force acting on a 50kg dog? A)540N b)570N c)490N d)440N

Answers

Answer:

C) 490

Explanation:

Normal force = mass × gravitational acceleration

50kg × 9.8

490 N

Find the acceleration of a 10 kg bucket of water that is lifted with a force of 200 Newtons.

Answers

The acceleration of a 10 kg bucket of water that is lifted with a force of 200 Newtons is 20 N/kg.

The rate at which velocity changes with time, in terms of both speed and direction, is called acceleration.

Acceleration (a)

Mass (m) = 10 kg

Force (F) = 200 N or Newton

∴  a = F / m

=> a = 200 N / 10 kg

=> a = 20 N / kg

So, the acceleration of a 10 kg bucket of water that is lifted with a force of 200 Newtons is 20 N / kg.

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what has more kinetic energy an object of mass 2m moving with speed 3v or an object of mass m moving with speed 4v

Answers

Kinetic energy The height of an object of mass m moving at speed 4v will be greater than that of an object of mass 2m moving at speed 3v. Kinetic energy = 0.5 m v2

A mass of 2 m moving at a speed of 3 v has kinetic energy of 9 m, while a mass of m moving at a speed of 4 v has kinetic energy of 8 m. The ability of an object to move another object is known as its kinetic energy. It is effective for a force to move an object. Furthermore, we are aware that an object in motion can cause a stationary object to move if it collides with it. It can therefore perform a function. The ability of an object to perform work as a result of its motion is how we define kinetic energy.

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at what frequency should a 200-turn, flat coil of cross sectional area of 300.0 cm2 be rotated in a uniform 30.0-mt magnetic field to have a maximum value of the induced emf equal to 8.0 v?

Answers

At 7.1 Hz a 200-turn, flat coil of cross sectional area of 300.0 cm2 be rotated in a uniform 30.0-mt magnetic field to have a maximum value of the induced emf equal to 8.0 v

What is magnetic field?

An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.

Given,

number of turns is N = 200 turns

cross-sectional area is A = 300 cm² = 300 x 10⁻⁴ m²

the magnitude of magnetic field strength is B = 30 x 10⁻³ T

the maximum value of the induced emf is E = 8 V

Now,

Maximum induced emf is, E = NBAω

where,

ω is the angular velocity (ω = 2πf)

Now,

E = NBA2πf

where,

f is minimum frequency

So, f = E / (NBA2π)

f = 8 / (200 x 30 x 10⁻³  x 300 x 10⁻⁴ x 2 x 3.142)

f = 7.073 Hz

f = 7.1 Hz

∴ the minimum frequency of the coil is 7.1 Hz.

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You are skiing and you push off from the top of the hill, giving yourself an initial velocity of 1 m/s. You accelerate down the hill at a rate of 2 m/s/s. What will your speed be after 10 seconds? How far will you have traveled after 10 seconds?

Answers

Using Equations of motion, speed after 10 seconds will be 21 m/s and the distance travelled after 10 seconds will be 110 m.

What are  Equations of motion?

Equations of motion are thought of as the relationships that assist us in relating the physical quantities, such as distance traveled, time spent traveling there, acceleration, and initial and final velocities.

First equation of motion

The velocity-time relation is the name given to the fundamental equation of motion, v = u + at.

Second equation of motion

The position-time relation can be defined as s = ut + 1 / 2at2 in the second equation of motion.

Third equation of motion

v2 = u2+ 2as, the position-velocity relation, is the third equation of motion.

Given,  initial velocity, u = 1 m/s

            acceleration, a = 2 m/s/s

            time = 10 s

Using First equation of motion, we find the speed after 10 seconds.

v = u + at

v = 1 + 2 x10

v = 1 + 20

v = 21 m/s

Using Second equation of motion, we find the distance travelled after 10 seconds,

s = ut + 1 / 2at2

s = 1 x 10 + ( 2 x 10 x 10)/2

s = 10 + 100

s = 110 m.

Hence, after 10 seconds speed will be 21 m/s and distance will be 110 m.

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Using the data collected from the motion detector, the group of students is
able to calculate both initial and final velocities. The initial velocity is
measured when the mass is released, and the final velocity is measured just
as the mass hits the floor. Using these velocities, they calculate the initial and
final kinetic energies. They also calculate the initial gravitational potential
energy by measuring the initial height when the mass is released. The final
gravitational potential energy is taken to be zero at the floor. When they
compare the final (kinetic) energy value to the initial energy value (that is, the
sum of the initial kinetic and gravitational potential energies), which of the
values is greater...
if the assumptions presented in the previous problem are true?
The initial and final energies a
if the assumptions presented in the previous problem are not true?
[ Select ]

Answers

Unless the above assumptions are clear, the initial and final energies are equal.

What is kinetic energy?

Kinetic energy is the form of energy that an object or a particle possess due to its motion. If work, that transfers energy, is done on an object by applying a net force, the object accelerates and thereby gains kinetic energy. Kinetic energy is a property of a moving object or particle and depends on its motion as well as its mass. The type of motion may be translational (or motion along a path from one place to another), rotational, vibrational, or any combination of motions. Translational kinetic energy is one-half the product of its mass (m) and the square of its velocity (v) or 1/2mv².

Given,

Initial and final velocities = v₁ and v₂

Initial kinetic energy = [tex]\frac{1}{2} mv_{1} ^{2}[/tex]

Final kinetic energy = [tex]\frac{1}{2} mv_{2} ^{2}[/tex]

Gravitational potential energy is calculated = mgh

As the assumptions are not clear, this question assumes no air resistance. As a result, no energy is consumed by work.

then

Initial Kinetic Energy = Final Kinetic Energy

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A van accelerates from a velocity of 2 m/s to a velocity of 20 m/s in 12 s.
Calculate the acceleration of the van.

Answers

Answer:

Explanation:

Given:

V₀ = 2 m/s

V = 20 m/s

Δt = 12 s

__________

a - ?

The acceleration of the van:

a = ΔV / Δt = (V - V₀) / Δt

a = (20 - 2) / 12 = 18 / 12 ≈ 1.5 m/s²

Gabe is designing a flashlight that uses a parabolic reflecting mirror and a light source. the shape of the mirror can be modeled by a parabola that opens upward with a diameter of 4 in. and a depth of 1 in. the vertex of the parabola is at the origin. where should gabe place the bulb to ensure a perfect beam of light? (0, 1) (0, 4) (1, 0) (4, 0)

Answers

Gabe should place the bulb to ensure a perfect beam of light at (C) (1,0).

A reflective surface used to gather or project energy like light, sound, or radio waves is known as a parabolic, paraboloid, or paraboloidal reflector, dish, or mirror. Its form is a component of a circular paraboloid or the surface produced by a parabola rotating around its axis.

Suppose the equation of parabolic mirror is Y2 = 4ax

The given data in the problem is x = 1 and y = 2

So the subject value is y2 = 4ax

4 = 4 a (1)

4 = 4a

a = 1

So  x = 1

thus focus is at  (x, y) = (1,0)

Thus option C is the correct answer.

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a 1.92 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 n/m. the object is displaced 5.31 m to the right from its equilibrium position and then released, which initiates simple harmonic motion. what is the magnitude of the force acting on the object 3.72 s after it is released? answer in units of n.

Answers

The magnitude of the force acting on the object of mass 1.92 kg, 3.72 s after it is released is 23.414 N in negative direction.

ω = √ ( k / m )

ω = Angular frequency

k = Force constant

m = Mass

k = 4.77 N / m

m = 1.92 kg

ω = √ 4.77 / 1.92

ω = √ 2.48

ω = 1.58 rad / s

F ( t ) = - m d ω² cos ω t

F ( t ) = Force wrt time

d = Displacement

t = Time

t = 3.72 s

d = 5.31 m

F ( 3.72 ) = - 1.92 * 5.31 * 1.58² cos ( 1.58 * 3.72 )

F ( 3.72 ) = - 25.45 cos 5.88

F ( 3.72 ) = - 23.414 N

Therefore, the magnitude of the force acting on the object is 23.414 N in negative direction.

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what conditions must occur for the two carts to move in different directions after the collision? (assuming that a moving cart collides elastically with a stationary cart).

Answers

As a result of the collision, the cart, which had a velocity of 1, comes to rest. The cart then accelerates with velocity v1 from rest. assuming that a moving cart collision elastically with a stationary cart.

We are aware that both the linear momentum and the kinetic energy are conserved in completely elastic velocity. However, only the kinetic energy of an inelastic impact is conserved. Any situation in which two or more bodies quickly exert forces on one other is referred to be a collision. The scientific definition of the word "collision" makes no reference to the magnitude of the force involved, despite the fact that the most frequent usage of the word relates to instances in which two or more objects clash violently.

The instantaneous speed could be compared to the speed shown by the speedometer.

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.

suppose you have two identical socks that exert a force of 10 n on each other. now you move them so they are three times as far apart as they were originally. (a) calculate the new force between the objects. (b) will this force be attractive or repulsive? please explain

Answers

(a) Since the separation is being tripled the force would go to 1/9 its original value if the charges remained constant because Coulomb's Law is an inverse square law. So, the new force is 10/9 N.

(b) because the pressure remains the equal and it became repulsive, initially, it will remain repulsive. One could also deduce this for the reason that the socks are equal.

Electrostatic repulsion can also be observed, for example, with an electroscope. It's a simple device consisting of a piece of metal sticking out of a glass jar and a thin metal leaf hanging inside. When the outer piece of metal touches the charged body, the Coulomb force causes the sheet to expand.

The repulsive force between oppositely oriented magnets. A compression material that repels the body on both sides. Repulsion is associated with involuntary vomiting such as in response to the ingestion of toxins.

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a 65 kg bungee jumper drops from a 60 ledge. the bungee cord has an unstretched length of 20 m, meaning that for the first 20 m the only force on the jumper is gravity. the bungee cord acts like a linear spring. the jumper comes to rest 0.5 m above the surface of the water. what is the stiffness constant of the cord?

Answers

To find the stiffness constant of the cord, learn gravity and force.

What is gravity?

By means of gravity, a planet or other body pulls objects toward its center. All the planets are maintained in their orbits around the sun by the force of gravity.

What is force?

An object with mass changes its velocity in response to a push or pull. Force is an external agent that has the power to alter a body's resting or moving state. It has a size and a movement.

Enot=Eat start= Ug =mgh

=(65kg)(10m/s²)(60m)

=39,000J

Eat lowest point =Usp+Ug

=1/2K(Δy²)+mgh

=1/2k(39.5m)² + (65kg)(10m/s²)(0.5m)

from conservation of energy, solve to get K= 49.6N/m.

Therefore, the energy function can be written ( for y<40).

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he complex impedance of an electric circuit measures resistance as the real component and reactance as the imaginary component, both measured in ohms. what is the magnitude of impedance of an electric circuit with a resistance of 90 ohms and a reactance of 120 ohms?

Answers

The magnitude of impedance is 1.33 ohms .

What is meant by electric circuit?

Electric circuit: a way for current to travel. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit.

Current flowing from the positive terminal to the negative terminal of the battery is known as an electric circuit. Putting together a circuit A cell or battery, connecting wires, a lightbulb, and a switch make up an electric circuit.

Given .

resistance = 90 ohms

reactance =120 ohms

So magnitude of impedance is 120/90

= 1.33 ohms

therefore the magnitude of impedance is 1.33 ohms

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What is the phase angle between the voltages of the inductor and capacitor in a rlc series circuit?.

Answers

Answer:  at least 180 degrees

three objects are at the top of an inclined plane: a disk, a sphere, and a ring. all of the objects have the same radius and the same mass. which object would finish last in a race down the incline if they are all released from rest? (hint: use conservation of energy methods, and note that at the bottom there is both translational and rotational energy)

Answers

The ring would finish at last in the race down the incline.

Incline is a a plane surface tilted at some angle from the horizontal.

The moment of inertia of the ring = [tex]mr^{2}[/tex]

The moment of inertia of the disc = ( [tex]mr^{2}[/tex] ) / 2

The moment of inertia of the solid sphere = 2( [tex]mr^{2}[/tex] ) / 5

Since the moment of inertia is the resistance to rotational motion, we see that the object with the smallest moment of inertia will reach the bottom first.

The gain in total kinetic energy is equal to the loss in gravitational potential energy, which in turn is the same for all the objects and is equal to 'mgh'

where h is the height of the inclined plane.

So the order of reaching the bottom is Sphere, disc and ring.

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a spherical shell with radius r and uniform surface charge density spins with angular frequency w around the diameter. find the magnetic field

Answers

The magnetic field is [tex]\vec{m}=\frac{Q}{3} R^2 \vec{\omega}[/tex]

How to calculate magnetic field?

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is moving through a magnetic field.

Uniformly charged spherical shell of radius R carries a total charge =Q

Hence it has surface charge density

[tex]\sigma=\frac{Q}{4 \pi R^2}[/tex]

It rotates about its axis with frequency=f

∴ Its angular velocity ω=2πf

Suppose the angular velocity [tex]\vec{\omega}=\omega \hat{z}[/tex]

To find the magnetic moment of spinning shell we can divide

it into infinitesimal charges. Using spherical polar coordinates (ρ,ϕ,θ) with origin at the center of the spherical  shell, we consider infinitesimal area dS of a circular ring of infinitesimal width and of radius r located at a distance R from the origin on the surface of sphere.

Here [tex]\vec{r}=R \sin \theta \hat{r}[/tex] and coordinate ρ=R, is constant for each elemental area.

[tex]d q=\sigma d S=\sigma R^2 \sin \theta d \theta d \phi[/tex]

Current in the ring is given by

[tex]\begin{aligned}&d I=(d q) \times f=\left(\sigma R^2 \sin \theta d \theta d \phi\right) \times \frac{\omega}{2 \pi} \\&\Rightarrow d I=\frac{\omega \sigma R^2 \sin \theta d \theta d \phi}{2 \pi}\end{aligned}[/tex]

Now the magnetic dipole moment of ring is given by the expression in terms of position vector [tex]\vec{r}[/tex]current density [tex]\vec{J}[/tex]

[tex]\begin{aligned}&d \vec{m}=\frac{1}{2} \int_{\text {ring }} \vec{r} \times \vec{J} \\&\Rightarrow d \vec{m}=\frac{1}{2} d I \int_{\text {ring }} \vec{r} \times d \vec{l}\end{aligned}[/tex]

Line integral becomes equal to the circumference of ring

[tex]\therefore d \vec{m}=d I\left(\pi R^2 \sin ^2 \theta\right) \hat{z}[/tex]

Inserting value of dI we get

[tex]\begin{aligned}&d \vec{m}=\frac{\omega \sigma R^2 \sin \theta d \theta d \phi}{2 \pi}\left(\pi R^2 \sin ^2 \theta\right) \hat{z} \\&\Rightarrow d \vec{m}=\frac{\vec{\omega} \sigma R^4 \sin ^3 \theta d \theta d \phi}{2}\end{aligned}[/tex]

Total magnetic moment is integral with respect to both variables within respective limits

[tex]\begin{aligned}&\vec{m}=\frac{\vec{\omega} \sigma R^4}{2} \int_0^\pi \sin ^3 \theta d \theta \int_0^{2 \pi} d \phi \\&\Rightarrow \vec{m}=\frac{\vec{\omega} \sigma R^4}{2} \times \frac{4}{3} \times 2 \pi \\&\Rightarrow \vec{m}=\frac{4}{3} \pi \sigma R^4 \vec{\omega}\end{aligned}[/tex]

Rewriting in terms of charge Q

[tex]\begin{aligned}&\vec{m}=\frac{4}{3} \pi\left(\frac{Q}{4 \pi R^2}\right) R^4 \vec{\omega} \\&\vec{m}=\frac{Q}{3} R^2 \vec{\omega}\end{aligned}[/tex]

The complete question is : A spherical shell of radius R and uniformly charged with charge Q is rotating about its axis with frequency f. Find the magnetic moment of the sphere?

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the lift piston base and the input piston base are at the same height. what input force, , is required to maintain this system in equilibrium?

Answers

Input force = (Output force/Output area) × Input area



By Pascal Law,
     
   Input force / input area = Output force / output area

By re-arranging,

      Input force = (Output force/Output area) × Input area

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Which statement best shows that waves can carry energy?

Sounds can be recorded.
A rainbow shows a spectrum of colors.
You feel vibrations if loud sounds are played.
Light shining through some trees makes shadows.

Answers

The statement that best shows that waves can carry energy is option d: light shining through some trees makes shadows.

What is the most accurate way to define sound waves?

A sound wave is the pattern of disruption brought on by the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid matter). Pressure waves are produced when an object vibrates, such as a ringing phone, and these waves are known as sound waves.

Therefore, note that the energy of a sound wave is transferred through particle contact. A vacuum cannot be traversed by a sound wave. Sound is now a mechanical wave as a result.

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Which of the following objects have kinetic energy?
An elephant walking 1.5 m/s along the ground.
A jet flying across the sky 4,000 m above the ground.
A car traveling 20 m/s along a flat road.
A concrete block sitting on the ground.
An apple on a tree branch 3.0 m above the ground.​

Answers

I think the Answer is A (An elephant walking 1.5 m/s along the ground), and B (A jet flying across the sky 4,000 m above the ground.

Within free market economies, what role does self interest play? What role does competition play?

Answers

Economic activity is driven by self-interest, and competition helps to drive down costs and increase the quality, diversity, and creativity of goods and services.

What kind of activity is self-interested?

Seeking your own personal gain is the definition of self-interest. You attend work in order to earn money to spend on the things you want. You attend school so that after you graduate, you'll be able to find a better career and get more money to spend on the things you desire.

How can self-interest be developed?

Pick some fresh endeavors that promote goodwill in your career, family, and leisure life. Likewise, be adamant in your actions. When appropriate, communicate your thoughts and feelings to others by asking for what you want, declining what you don't want, and saying No to requests. For a while, make it a point to treat yourself to something every day.

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what is the point in the sky directly overhead called? which constellation is closest to this point tonight?

Answers

The answers include the following:

The point in the sky which is directly overhead is called Zenith.The constellation which is closest to this point tonight is Polaris.

What is Constellation?

This is referred to as a group of stars that form a perceived pattern or outline and are usually given names and an example is hydra.

The Zenith as the name implies is known as the overhead point in the sky which is usually hardly seen while the constellation which is closest to this point tonight is Polaris due to the position thereby making it the most appropriate choice.

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how would the gravitational force of star james change if star james contracted to 1/7 of its previous diameter, without osing any of it's matter

Answers

The final gravitational force at the surface of the star is 49 times of the initial gravitational force.

Gravitational force definitions.

The attraction that exists between all masses in the universe, particularly between the mass of the earth and objects that are close to its surface.

Use Newton's gravitational law to find the gravitational force at the surface of a star if the star contracted to one fifth of its previous diameter as follows.

Newton's gravitational law states that the gravitational force between two objects is inversely proportional to the square of their distance and directly proportional to the product of their masses.

[tex]F_g}[/tex] =GMm/r²

In this case, the two objects' masses are M and m, G is the gravitational constant, and r is their separation from one another.

Since mass is constant, the gravitational force at the surface of a star before contraction is,

F₁ =GMm/r₁²

Here, r₁ is initial diameter of the star.

The gravitational force at the surface of a star after the contraction is,

F₂ =GMm/r₂²

Here, r₂ is final diameter of the star.

Compare the equations, we get

F₂/F₁= GMm/r₂²/GMm/r₁²

F₂/F₁=(r₁/r₂)²

F₂ = F₁(r₁/r₂)²

Substitute r₁/7 for r₂ in equation and solve for final gravitational force on the star.

F₂ = F₁(r₁/r₁/7)²

F₂= 49F₁

Therefore, the final gravitational force at the surface of the star is 49 times of the initial gravitational force.

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if a falling ball made a perfectly elastic collision with the floor, would it rebound to its original height? explain.

Answers

When dumped, it would rebound all the way up to the original height.

What occurs when an impact is perfectly elastic?

If there is no kinetic energy lost during contact, the collision is entirely elastic. In an inelastic collision, some of the kinetic energy is converted into another kind of energy during the contact.

The system's overall kinetic energy, which includes the interacting items, remains constant both before and after the impact. A very buoyant ball might serve as an illustration of an elastic collision. If you dropped it, it would return to its original height after bouncing all the way down.

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bird bones have air pockets in them to reduce their weight. this also gives them an average density significantly less than that of the bones of other animals. suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 45.0 g and its apparent mass when submerged is 3.60 g (the bone is watertight). what mass of water is displaced?mass of water displaced:kg what is the volume of the bone?volume of the bone:m3 what is its average density?average density of the bone:kg/m3 question credit: openstax college physics

Answers

a) Mass of displaced water is 41.4 g or 0.0414 kg

b) Volume of the bone is 41.4 mL or 41.4 × 10⁻⁶m³

c) Average density of the bone is 1.09 g/ mL or 0.00109 × 10⁻⁶ Kg /m³

In the given question we have, the weight of some bird bones is measured in air outside of some water and the weight is 45.0 grams and the apparent weight in water is 3.60 grams. Now, we shall find out the weight of the displaced water? So the buoyant force is this difference between the weight of the bones out of the water and in the water, so the weight out of the water times g minus the weight in the water times g and then the g can be factored in and the buoyant force is also equal to the weight of the displaced fluid from Archimedes' principle

i.e., 45 × g - 3.60× g = weight/ mass of displaced water

weight of displaced water = 41.4 × g

g× mass of displaced water = 41.4 ×g

=> mass of displaced water = 41.2 grams

a) Mass of displaced water = 0.0414 Kg

b) the volume of the bones is going to be equal to the volume of water displaced.

We know that the density of water is the mass of water displaced divided by the volume of water. So the volume of water displaced is the weight of the water displaced divided by the density of the water.

Volume of water displaced = 41.4 grams / density of displaced water

density of water displaced = 1 grams / milliliters

So, the density of water is 41.4 milliliters or 41.4 ×10⁻⁶ m³

c) The average density of the bone is the weight of the bone divided by its volume,

Average density of bone = 45 grams / 41.4 mililitres

so it's value is 1.09 grams per milliliter or 0.00109 × 10⁻⁵ m³

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a 40-kg crate is being lowered with a downward acceleration is 2.0 m/s 2 by means of a rope. (a) what is the magnitude of the force exerted by the rope on the crate? (b) what would be the magnitude of the force exerted by the rope if the crate were being raised with an acceleration of 2.0 m/s 2?

Answers

a) Force exerted by the rope on the crate is equal to 312 N.

b) Force exerted by the rope if the crate were being raised with an acceleration of 2.0 m/s² is 472N.

What is force?

In science, a force is a push or a pull in a specific direction. When one object interacts with another object, forces are created.

In physics, arrows are used to represent forces. An arrow pointing in the same direction will indicate the force's direction.

Given,

mass of a crate, m = 40 kg

Acceleration of crate, a = 2 m/s²

a) As carte is falling down, net force exerted by rope on the carte is given by : F = m(g-a)

F = 40(9.8-2)

F = 312 N

∴ required force exerted by the rope on the crate is equal to 312 N.

b)  If the crate was raised with an acceleration of 2.0 m/s², than:

F = m(g+a)

F = 40 (9.8 + 2)

F = 472 N

∴ required force exerted by the rope if the crate were being raised with an acceleration of 2.0 m/s² is 472N.

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